a satellite of mass 210 kg is placed into earth orbit at a height of 900 km above the surface.

Answer: D (Wave 4, Wave 3, Wave 1, Wave 2)

The arrangement of these waves in order of increasing frequency is;Wave 4, Wave 3, Wave 1, Wave 2.

A wave is a disturbance along a medium that transfers energy. We have to note that waves are shown in the manner that is depicted by the images shown in the question.

Now, the arrangement of these waves in order of increasing frequency is;Wave 4, Wave 3, Wave 1, Wave 2.

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The magnitude of the impulse imparted to the golf ball can be determined using the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum it undergoes.

The momentum of an object can be calculated by multiplying its mass by its velocity.

Given:

Mass of the golf ball (m) = 0.050 kg

Initial velocity of the golf ball (u) = 0 m/s (since it starts from rest)

Final velocity of the golf ball (v) = 70.0 m/s

The change in momentum (Δp) can be calculated as:

Δp = m * (v - u)

Substituting the given values:

Δp = 0.050 kg * (70.0 m/s - 0 m/s)

Δp = 0.050 kg * 70.0 m/s

Δp = 3.50 kg·m/s

Therefore, the magnitude of the impulse imparted to the golf ball is 3.50 kg·m/s.

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The magnitude of the impulse imparted to the golf ball is 3.5 N·s.

Impulse is defined as the change in momentum of an object. The magnitude of impulse can be calculated using the formula:

Impulse = Δp = m * Δv

Where:

Δp is the change in momentum,

m is the mass of the golf ball, and

Δv is the change in velocity.

Given:

Mass of the golf ball, m = 0.050 kg

Initial velocity, v₁ = 0 m/s (assuming the ball was at rest initially)

Final velocity, v₂ = 70.0 m/s

The change in velocity is Δv = v₂ - v₁ = 70.0 m/s - 0 m/s = 70.0 m/s.

Substituting the values into the formula, we get:

Impulse = m * Δv = 0.050 kg * 70.0 m/s = 3.5 N·s.

Therefore, the magnitude of the impulse imparted to the golf ball is 3.5 N·s.

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Answer:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

When a rock is transported from the moon to the earth, both mass and weight are changed.

Explanation:

The reason why both mass and weight are changed when a rock is transported from the moon to the earth is that the gravitational field on the surface of the earth is stronger than that on the surface of the moon.

This means that the rock's mass, which is the measure of the amount of matter that an object contains, will remain the same.

However, the rock's weight, which is the force with which an object is attracted to the earth due to gravity, will be different since the gravitational pull on the moon is much weaker than that on the earth. This implies that when the rock is transported from the moon to the earth, it will experience a higher gravitational force which will cause it to weigh more compared to when it was on the moon.

Therefore, both mass and weight will change when a rock is transported from the moon to the earth.

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The force f (in n) the person is exerting on the mower is 18 n.

The force of friction opposing the motion refers to the force that acts in the opposite direction to the motion of an object and makes it harder to move.

According to the given statement, the force of friction opposing the motion is equal to the force f (in N) the person is exerting on the mower.

This indicates that the person's pushing force must be equal to the force of friction opposing the motion for the mower to move at a constant speed.

Using the above information, we can calculate the force f (in N) that the person is exerting on the mower as 18 n since it is equal to the force of friction opposing the motion.

Therefore, the person must push with a force f (in N) of 18 n to overcome the friction and maintain a constant speed for the mower.

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Therefore:

Answer:

1600W

Answer:

      k = \(\frac{g \ m_1}{L}\)

Explanation:

In this exercise the two cases presented are a simple harmonic motion, with angular velocity

spring - mass                                      w² = k / m₁

simple pendulum (string- mass m₂)  w² = g / L

angular velocity and period are related

              w = 2π/ T

since they indicate that the two periods are equal, the angular velocities are also equal, therefore we can equal the two equations

             \(\frac{k}{m1} = \frac{g}{L}\)

             k = \(\frac{g \ m_1}{L}\)

When, the wavelength of a 4. 40 × 102 Hz sound in fresh water will be 3. 30 m. Then, the speed of sound in fresh water is approximately 1452 m/s.

To determine the speed of sound in water, we can use the relationship between frequency, wavelength, and the speed of sound. The formula is;

speed of sound = frequency × wavelength

Given;

Frequency (f) = 4.40 × 10² Hz

Wavelength (λ) = 3.30 m

By substituting the given values into the formula, we can calculate the speed of sound in water;

Speed of sound = 4.40 × 10² Hz × 3.30 m

When we multiply the frequency by the wavelength, we obtain the speed of sound.

Calculating the product, we get;

Speed of sound = 1452 m/s

Therefore, the speed of sound in fresh water will be approximately 1452. m/s.

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Answer:

i believe its B

Explanation:

im taking physics and thats the only thing that makes sense to me haha

hope this is right and helps <3

Answer:

It's B: a constant force that acts on objects that rub together

Explanation:

The energy absorbed outdoor copper sculpture heats up during the day q = 1.79 x 10⁵ J.

To find energy using formula,

q = mcΔT

where,

q is energy

m is mass

c is specific heat

ΔT is change in temperature

Given,

m = 7.8 kg

c = 390 J/kg

T₁ =  28°C

T₂ = 87°C

To find ΔT,

ΔT = T₂ - T₁

ΔT = 87° - 28°

ΔT = 59°C

Now, putting values,

q = mcΔT

q = 7.8 kg x 390 J/kg x 59

q = 1.79 x 10⁵ J

The best materials for sculpture are copper and copper alloys for a variety of reasons. They offer countless artistic possibilities because they can be molded into any desired shape. Copper components can be mechanically joined or assembled by bolting or bonded by welding, enabling works of enormous size.

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(a) The formula for mass is given by;

Density = mass/volumeρ = m/V

mass = ρV

Where ρ is the density, m is the mass, and V is the volume.

So, if the material of both the child's ball and the adult ball is the same, then the mass of both balls depends on the volume of the ball.

Volume of the child's ball is half of that of the adult ball.

r_child = 0.5 * r_adult

Volume of child's ball = (4/3) * π * r_child³

Volume of adult ball = (4/3) * π * r_adult³

Therefore, the volume of the child's ball is;

V_child = (4/3) * π * (0.5 * r_adult)³V_child = (1/3) * π * r_adult³

Volume of the adult ball is;V_adult = (4/3) * π * r_adult³

Therefore, the mass of the child's ball is;

m_child = ρ * V_childm_adult = ρ * V_adult

Since the density is the same for both balls,

m_child/m_adult = V_child/V_adultm_child/m_adult = (1/3) * π *

r_adult³ / (4/3) * π * r_adult³m_child/m_adult = (1/3) / (4/3)m_child/m_adult = 1/4

The mass of the child's ball is reduced by a factor of 1/4 compared to the adult ball.

(b) Rotational Inertia of a ball;

Rotational inertia, I of a solid sphere is given by;

I = (2/5) * m * r²

Where m is the mass of the sphere, and r is the radius.

So, for a child's ball, I_child = (2/5) * m_child * r_child²I_adult = (2/5) * m_adult * r_adult²

Let's substitute the values found above;

m_child/m_adult = 1/4r_child = 0.5 * r_adultI_child = (2/5) * m_child * (0.5 * r_adult)²I_adult = (2/5) * m_adult *

r_adult²I_child/I_adult = m_child/m_adult * r_child²/r_adult²I_child/I_adult = (1/4) * (0.5)²I_child/I_adult = 1/16

The rotational inertia of the child's ball is reduced by a factor of 1/16 compared to the adult ball.

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The ratio of f1/f2 is slightly greater than 3.

Sources of light are objects or phenomena that emit light, a form of electromagnetic radiation visible to the human eye. Some familiar natural light sources include the sun, stars, lightning, and fireflies.

Sources of light can be categorized as either incandescent or luminescent. Incandescent sources produce light through heat, such as the glowing filament in an incandescent light bulb. In contrast, luminescent sources produce light through a chemical or physical process, such as a fluorescent light bulb or a neon sign.

f1 = (c + v(observer)) / (c - v(observer))

f2 = (c - v(observer)) / (c + v(observer))

Dividing the two equations, we get:

f1 / f2 = (c + v(observer)) / (c - v(observer)) * (c + v(observer)) / (c - v(observer))

the ratio of f1/f2 can be expressed in terms of the extremes of v(observer)and v(observer)as:

f1 / f2 = (c + v(observer)) / (c - v(observer)) * (c + v(observer)) / (c - v(observer))

= (c + v(observer)) / (c - v(observer)) * (c + c/2) / (c - c/2) (using v(source) = c/2 and -c/2)

= (3c + 2v(observer)) / (c - 2v(observer))

Since v(observer) is much smaller than c, we can approximate this as:

f1 / f2 ≈ (3c + 2v(observer)) / c

Thus, the ratio of f1/f2 is slightly greater than 3.

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The bond angle in a compound is the angle formed between two bonds in the compound. It is affected by the geometry, electron cloud and the size of atoms.

Bond angle is the distance between two chemical bonds in a compound. Bond angle is affected by the electrostatic force of repulsion and attraction. Hence, the presence of lone pairs and bond pair are the main factors affecting the bond angle.

If there are lone pairs, the repulsion between two  lone pairs is greater than that between a lone pair and bond pair which in turn greater than that between two bond pairs.

Hence, the electron clouds will align themselves to minimize the repulsion. Thus, the geometry and bond angle may vary from what we predicted based on hybridization.

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Your question is incomplete. But your complete question probably was:

What is bond angle? What do you think are the factors that might affect the magnitude of this angle?

Answer:

Cathode: The positive electrode of a cell. Cell: A single encased electrochemical unit (one positive and one negative electrode) which exhibits a voltage differential across its two terminals.

Answer:

Cell

Explanation:

A cell is a single encased electrochemical unit (one positive and one negative electrode) which exhibits a voltage differential across its two terminals.

Answer:

S = V0 t + 1/2 a t^2      net distance traveled

5.2 = a/2 * 25

a = 10.4 / 25 = ,416 m / s^2

F = m * a

m = F / a = 24 / .416 = 57.7 N

Answer:

c) tension ........ ........

Answer:

gravity

Explanation:

because it cannot be move across if there is present gravity force

Answer:

.

The common velocity of the two bodies after the collision is 2.7 m/s.

This can be calculated using the equation of conservation of momentum:

m1v1 + m2v2 = (m1 + m2)v

where m1 is the mass of the first body (12 kg), v1 is the velocity of the first body (4.2 m/s), m2 is the mass of the second body (18 kg), v2 is the velocity of the second body (0 m/s), and v is the common velocity of the two bodies after the collision.

Substituting the given values into the equation, we get:

12(4.2) + 18(0) = (12 + 18)v

Solving for v, we get:

v = 2.7 m/s

In order to help Scarlett retrieve her toy train from the lake, the wooden fishing rod can be modified or adapted by Attaching a magnet, Adding a hook or grappling device, and Using a net or scoop.

Attaching a magnet: Scarlett can attach a strong magnet to the end of the fishing rod. Since the train contains parts made of steel, the magnet will be attracted to the metallic components. By carefully maneuvering the magnet with the fishing rod, Scarlett can potentially attract and retrieve the train from the water.

Adding a hook or grappling device: Scarlett can affix a hook or grappling mechanism to the fishing rod. By casting the hook near the location where the train fell into the lake and skillfully maneuvering the rod, she can attempt to hook onto the train or one of its parts. With a successful hook, she can slowly reel in the train and bring it back to shore.

Using a net or scoop: If the toy train is floating on the surface of the lake or near the shallow edges, Scarlett can attach a net or scoop to the end of the fishing rod. By carefully positioning the net or scoop around the train, she can scoop it up and safely retrieve it without causing any damage.

It's important to note that the success of these modifications will depend on factors such as the depth of the lake, the accessibility of the train, and the size and weight of the fishing rod. Additionally, adult supervision or assistance may be necessary to ensure safety, especially if the lake is deep or poses any hazards.

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The star's (u-b) color can be calculated by taking the logarithm base 2.80 of the ratio of the brightness measured using the u filter to the brightness measured using the b filter.

Logarithm is the type or capacity to which a base should be raised to yield a given number. Communicated numerically, x is the logarithm of n to the base b if bx = n, in which case one composes x = logb n. For instance, 23 = 8; Consequently, 3 is the logarithm of base 2 divided by 8, or 3 = log2 8.

The quotient's log is the difference between the logs. There is no way to simplify the log of a difference. The log coefficient is not the same as an exponent on the log. The exponent can only be transformed into the coefficient when the argument is extended to a power.

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Answer:

The energy associated with an object's motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy.

Explanation:

is the energy stored in moving objects. As the object moves faster, more energy is stored.

called MOVEMENT energy

After the second collision:

Given:

Mass of car B (\(\(m_B\)\)) = 1350 kg

Mass of truck C (\(\(m_C\)\)) = 5400 kg

Velocity of truck C (\(\(v_C\)\)) = -8 km/h (to the left)

Convert \(\(v_C\)\) to m/s:

\(\[ v_C = -8 \, \text{km/h} \\\\= -8 \times \frac{1000}{3600} \, \text{m/s}\\\\ \approx -2.222 \, \text{m/s} \]\)

Total initial momentum

\(\(m_B \cdot v_B + m_C \cdot v_C \\\\= 1350 \cdot 0 + 5400 \cdot (-2.222)\\\\ \approx -12000 \, \text{kg m/s} \)\)

Second Collision (Perfectly Elastic):

Given:

Mass of car A (\(\(m_A\)\)) = 1350 kg

Mass of car B (\(\(m_B\)\)) = 1350 kg

For the second collision, we use conservation of momentum and conservation of kinetic energy:

1. Conservation of momentum:

\(\(m_A \cdot v_A + m_B \cdot v_B \\\\= -12000 \, \text{kg m/s}\)\)

2. Conservation of kinetic energy:

\(\(\frac{1}{2} m_A v_A^2 + \frac{1}{2} m_B v_B^2 \\\\=\frac{1}{2} m_C v_C^2\)\)

Now, solve these equations to find \(\(v_A\)\) and \(\(v_B\)\).

Using the provided equations, we find:

\(\[ v_A = -v_B \]\)

\(\[ v_A = \dfrac{-12000 \, \text{kg m/s} - 5400 \cdot (-2.222)^2}{1350}\\\\ \approx -6.74 \, \text{m/s} \]\)

Convert \(\(v_A\)\) and \(\(v_B\)\) back to km/h:

\(\[ v_A \approx -24.27 \, \text{km/h} \]\)

\(\[ v_B \approx 24.27 \, \text{km/h} \]\)

The velocity of truck C after the second collision will be the negative of its velocity before the first collision:

\(\[ v_C = -(-2.222) \approx 2.222 \, \text{m/s} \]\)

Convert \(\(v_C\)\) to km/h:

\(\[ v_C \approx 7.998 \, \text{km/h} \]\)

Thus, the velocity of truck C is 7.992 km/h.

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Answer:

program explanation

Explanation:

program explanation

The set of activities having a long-term aim should be a program.

A program refers to a set of instructions that a computer follows in order to perform a specific task. At the time When you program a computer, you provide it a set of instructions to make it able to perform a particular task.

So here the program should be considered.

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A toy elevator is raised from the ground floor to the second floor in 20 seconds. The power needed using 1000 J of work, is 50 W,  the calculation is like   1000J of work / 20 seconds = 50W.

Power is measured in Watts (W) which is a unit of energy per time. This means that when you divide the total energy (1000J) by time (20 seconds) it will give you the power (50W). In other words, power is the rate at which energy is expended over a given period of time. The higher the power, the faster the elevator will go. In this case, 1000J of work divided by 20 seconds gives you a power of 50W, which is enough to move the elevator from the ground floor to the second floor in 20 seconds.

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Average number of team members who reached their goal per day = 4.2

Number of team members that reached their goals on Monday = 5

Number of team members that reached their goals on Tuesday = 4

Number of team members that reached their goals on Wednesday = 2

Number of team members that reached their goals on Thursday = 7

Number of team members that reached their goals on Friday = 3

Total number of team members that reached their goals = 5 + 4 + 2 + 7 + 3

Total number of team members that reached their goals = 21

Average number of team members who reached their goal per day = 21/5

Average number of team members who reached their goal per day = 4.2

Answer:

Yes

Explanation:

If the detector absorbs photons, the power that emit light by the emitter is 9.3 x 10⁸ watts.

A light detector (your eye) has an area = 1. 95×10⁻⁶ m²

percentage of absorbing the incident light =  75% = 0.75

The detector faces an isotropic source,  from the source = 3. 40 m

rate of absorption = 3. 950 s⁻¹

then, rate of absorption is given as :

Rabs = 0.75 x (Aabs  x Remit)/4πr²

Remit = (Rabs x 4πr²)/ (0.75 x Aabs )

Remit = 3.92 x 10⁸ photons / sec

The energy of the photon is given as :

energy = hc/λ

E = hc/λ

E = (6.6 x 10⁻³⁴ x 3 x 10⁸) / 5 x 10⁻⁹

E = 2.38 eV.

To calculate the power we use :

P = E x Remit

P = 2.38 x 3.92 x 10⁸

P = 9.3 x 10⁸ Watts.

If the detector absorbs photons, the power that emit light by the emitter is 9.3 x 10⁸ watts.

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Answer:

The current flowing through the circuit and resistors.

Answer:

The last one

Explanation:

The cat goes from the tree branch (top) to the ground (bottom)

(a) The impulse experienced by the ball when thrown against the wall is 1.8 N.s.

(b) The average force exerted by the ball on the wall is 180 N j

Given that,

Mass of the ball  is = 300 g = 0.3 kg

According to impulse-momentum theorem, we can write,

J = Δp = m Δv = Favg Δt

Velocity vector is written as v₁ = v₁ cosθ i - v₁ sinθ j

v₂ = v₂ cosθ i + v₂ sinθ j

Now, impulse components are calculated as,

Jx = m (v 2x - v 1x) = 0.3 (5.19 - 5.19) = 0

Jy = m ( v 2y - v 1y) = 0.3 (3 + 3) = 1.8 N.s

Now, J = √( Jx² + Jy²) = √( 0² + 1.8²) = 1.8 N.s

Magnitude of average force,

J = Favg Δt

Favg = J/Δt = 1.8/(10× 10⁻³) = 1.8× 10² N j= 180 N j

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