Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = \(\omega=7.27\times 10^{-5} rad/s\)
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :
\(v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s\)
So, the velocity of the satellite is 3.08 km/s.
3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?
Answer:
P = 96 J
Explanation:
Given that,
Weight of the book, W = mg = 8 N
It is placed at a height of 12 m
We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :
E = mgh
mg = Weight
\(E=8\ N\times 12\ m\\E=96\ J\)
So, the potential energy of the book is 96 J.
Please someone answer this quickly!! I'll give 20 points for it, I just need the answers :)
The potential energy of the person mass 95 Kg sitting on top of a slid 3 m high is 2795.85 J
How do i determine the potential energy of the person?The following data were obtained from the question:
Mass of person (m) = 95 KgHeight of slid (h) = 3 mAcceleration due to gravity (g) = 9.81 m/s² Potential energy of person (PE) = ?The potential energy of the person can be obtained as follow:
PE = mgh
Inputting the given parameters, we have:
= 95 × 9.81 × 3
= 2795.85 J
Thus, the potential energy of the person is 2795.85 J
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Which has covalent bonds?
A.) glucose
B.) table salt
C.) steel alloy
D.) Iron oxide - rust
Answer:
A.) glucose
Explanation:
Answer:
A. glucose
Explanation:
pay attention to the lesson
A body was found in the basement of the Underwater Basket Weaving Building at 12:00 noon today, where the temperature is a steady 65 degrees Fahrenheit. When found, the core temperature was 92.7 degrees Fahrenheit. Two hours later, at 2:00 PM, the core temperature had fallen to 88. Assuming that the body temperature was 98.6 at the time of death, use Newton's law of cooling to find the time of death. ROUND TO 2 DECIMAL PLACES. The time of death was about hours before the body was found.
Using Newton's law of cooling, the time of death could have been 2 hours and 7 minutes before the body was found or around 9:53 AM.
According to Newton's Law of Cooling, the change in temperature of a body is proportional to the difference between its own temperature and the temperature of its surroundings. The law is expressed by the formula:
T(t) = T_a + (T_0 - T_a)e^(-kt),
where T(t) is the temperature of the body at time t, T_0 is the initial temperature of the body, T_a is the ambient temperature (in this case, 65 degrees Fahrenheit), and k is a constant of proportionality.
To find the time of death, we need to solve for t in the formula above. We know that at the time of death, the body temperature was 98.6 degrees Fahrenheit, so T_0 = 98.6. We also know that two hours later, the core temperature had fallen to 88 degrees Fahrenheit, so T(2) = 88. Plugging these values into the formula, we get:
88 = 65 + (98.6 - 65)e^(-k*2)
23 = 33.6e^(-2k)
ln(23/33.6) = -2k
0.3257 = k
Now we can solve for t using the formula:
T(t) = 65 + (98.6 - 65)e^(-0.3257t)
We want to find the time when the body temperature was 98.6 degrees Fahrenheit, so we plug that value in for T(t) and solve for t:
98.6 = 65 + (98.6 - 65)e^(-0.3257t)
33.6 = 33.6e^(-0.3257t)
e^(-0.3257t) = 1
t = ln(1)/(-0.3257)
t = 2.12 ≈ 2 hours and 7 minutes
Therefore, the time of death was about 2 hours and 7 minutes before the body was found or at around 9:53 AM.
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A conducting bar moves along a circuit with a
constant velocity. A constant magnetic field is
perpendicular to the bar and circuit. The bar
covers 1.50 m2 of area in 1.00 second. An
EMF of 3.57 V is induced in the circuit. What
is the strength of the magnetic field in Tesla?
[?] T
Answer:
2.38 T
Explanation:
Since the number of coils and the change in time are both 1, I set it up as 3.57=1.50(x) and then solved for x to be 2.38 T.
a 0.25 µf capacitor is connected to a 9.0 v battery. what is the charge on the capacitor?
A 0.25 µF capacitor is connected to a 9.0 V battery. The charge on the capacitor is 2.25 µC. A capacitor's ability to store charge is determined by its capacitance, which is measured in farads (F).
What is the charge on the capacitor?A capacitor is an electrical component that stores electrical energy in an electric field between a pair of conductors. Capacitors of different sizes and types are used in various applications, ranging from smoothing and filtering power supply voltages to storing energy in pulsed lasers.
A capacitor's ability to store charge is determined by its capacitance, which is measured in farads (F). The voltage across the capacitor plates and the capacitance are both proportional to the amount of charge stored on the capacitor.
The formula for calculating the charge on the capacitor is given below: Q = CVWhere Q is the charge, C is the capacitance, and V is the voltage across the capacitor. In this case, the capacitance is 0.25 µF, and the voltage is 9.0 V. Thus, the charge on the capacitor is given by: Q = CV= 0.25 µF × 9.0 V= 2.25 µC
Thus, the charge on the capacitor is 2.25 µC.
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A balloon drifts 140 m toward the west in 45 s; then the wind suddenly changes and the balloon flies 90 m toward the east in the next 25 s. a. What distance did it travel during the first 45 s? b. What distance did it travel during the next 25 s? c. What total distance did it travel? d. What was its average speed during the first 45 s? e. What was its average speed during the next 25 s? f. What was its average speed for the entire trip? g. What was its displacement during the first 45 s? h. What was its displacement during the next 25 s? i. What was its total displacement?
Answer:
Explanation:
Given
1 ) 140 m west in 45 s .
2 ) 90 m east in 25 s .
a )
distance travelled in first 45 s = 140 m
b ) distance travelled in next 25 s = 90 m
c ) Total distance travelled = 140 m + 90 m
= 230 m
d ) average speed in first 45 s
= distance in 45 s 45
= 140 / 45 = 3.11 m /s
e ) average speed in next 25 s
distance in 25 s / 25
= 90 / 25 = 3.6 m /s
f ) average in entire trip
= total distance / total time
= (140 + 90) / ( 25 + 45 )
= 3.28 m /s
g )
displacement in first 45 s = 140 m towards west
h )
displacement in next 25 s = 90 m towards east
i )
total displacement = 140 - 90
= 50 m towards west .
Everywhere on Earth is about 93 million miles away from the sun. What causes days to be warmer on one part of Earth than on another? (1 point)
the rotation of Earth
the speed of Earth in its orbit
the number of cars on the road
the angle at which the sun strikes Earth
a force of 5N and 3N are simultaneously exerted on an object .The direction of the forces can be altered at will.When will these forces have their greatest resultant?
Answer:
When the both the forces are acting in the same direction
Explanation:
Answer:
The resultant of these two forces will be the greatest when the two forces are in the same direction.
Explanation:
Let \(F_1\) and \(F_2\) denote these two forces. The resultant of these two force would be the vector sum \((F_1 + F_2)\).
Refer to the diagram attached. Join the head of \(F_1\) to the tail of \(F_2\). Under this construction, the vector connecting the tail of \(F_1\!\) to the head of \(F_2\!\) (the vector shown with a lighter color) would represent the resultant vector \((F_1 + F_2)\).
Consider the triangle inequality: as long as \(F_1\) and \(F_2\) (the first two sides of the triangle in the diagram) are not parallel to one another, the magnitude of the resultant vector would always be smaller than the sum of the magnitude of \(F_1\!\) and that of \(F_2\!\).
In other words: \(\| F_1 + F_2 \| < \| F_1 \| + \| F_2 \|\).
However, notice that when \(F_1\) and \(F_2\) are in the same direction, the three sides \(F_1\!\), \(F_2\!\), and \((F_1 + F_2)\) are in the same line and no longer form a triangle.
On the other hand, if \(F_1\) and \(F_2\) are opposite to one another, \(\| F_1 + F_2 \| = \| F_1 \| - \| F_2 \|\).
The magnitudes of the two forces, \(\| F_1 \| = 5\; \rm N\) and \(\| F_2 \|= 3\; \rm N\), are fixed. Hence, when the two forces are in the same direction, \(\| F_1 + F_2 \| = \| F_1 \| + \| F_2 \| =8\; \rm N\).
As long as \(F_1\) and \(F_2\) are not in the same line, the triangle inequality ensures that \(\| F_1 + F_2 \| < \| F_1 \| + \| F_2 \| =8\; \rm N\).
Hence, \(8 \rm \; N\) would be the greatest magnitude that the resultant force could achieve. That value is reached when the two forces are in the same direction.
Which type of protist is animal AND plant like?
Answer:
Protists are called plant-like, fungus-like and animal-like because they share some of the characteristics of plants, fungi and animals, even though they belong in a different category: the kingdom Protista.
Explanation:
A 12 kg object has 500 j of kinetic energy. What is it's speed?
Answer: 9.13 m/s
Explanation:
Hi there,
The equation for kinetic energy is
\(KE=\frac{1}{2} mv^2\)
With m representing mass and v representing velocity. Before you start a problem, it is very important to check what units you are working with. Mass should always be in kg and velocity in m/s, so it looks like you are all set.
Start by plugging in the given numbers to their respective spots:
\(500.0=\frac{1}{2} (12.0)v^2\)
From there, you can just solve for velocity. It should be 9.13 m/s. Remember to round to your significant figures and keep units consistent.
Hope this helps!
Flow is steady and inviscid in the image shown. Point (2) is a stagnation point. Between which pairs of points can you use the hydrostatic equation for pressure? Open (5) (4) ) H Choose all that apply. (3) wo R (1) Vj = V P1 = P 1 and 4 1 and 2 1 and 3 3 and 4 2 and 5
The hydrostatic equation for pressure can be used between points that are at the same height and in a fluid at rest. In the image shown, the flow is steady and inviscid, and point (2) is a stagnation point. This means that the fluid is not moving at point (2), and the pressure at this point is equal to the stagnation pressure.
The correct answers are:
-> 1 and 4
-> 1 and 3
The hydrostatic equation for pressure can be used between the following pairs of points:
- 1 and 4: These points are at the same height and in a fluid at rest, so the hydrostatic equation for pressure can be used between them.
- 1 and 3: These points are also at the same height and in a fluid at rest, so the hydrostatic equation for pressure can be used between them.
The hydrostatic equation for pressure cannot be used between the following pairs of points:
- 1 and 2: These points are not at the same height, so the hydrostatic equation for pressure cannot be used between them.
- 3 and 4: These points are not at the same height, so the hydrostatic equation for pressure cannot be used between them.
- 2 and 5: These points are not at the same height, so the hydrostatic equation for pressure cannot be used between them.
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Which two elements have similar characteristics?
Periodic Table
OF The Elements
Calcium(Ca) and barium(Ba) are both earth-alkaline metals with comparable properties to one another: they are solid but reactive, and they have simple properties in water.
What is a periodic table?The periodic table is an organization of all known elements in order of increasing atomic number and repeating chemical characteristics.
They are organized in a tabular format, with a row representing an era and a column representing a group.
Elements are ordered in increasing atomic number order from left to right and top to bottom.
Elements of the same group will have the same valence electron configuration and, as a result, will have comparable chemical characteristics.
Elements in the same period, on the other hand, will have an increasing order of valence electrons.
Ca and Ba are both earth-alkaline metals with comparable properties to one another: they are solid but reactive, and they have simple properties in water.
Hence, the two elements that have similar characteristics will be Ca and Ba
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If a plane traveling down a runway at 75 m/s accelerates at a rate of 8 m/s’over
40 seconds, then what is its final velocity?
Answer:
395 m/s
Explanation:
Initial velocity (u) = 75 m/sAcceleration (a) = 8 m/s²Time taken (t) = 40 secondsBy using the first equation of motion,
❖ v = u + atv denotes final velocityu denotes initial velocitya denotes accelerationt denotes time→ v = 75 + 8(40)
→ v = 75 + 320
→ v = 395
→ Final velocity = 395 m/sA bicycle moves at an initial velocity of 5m/s accelerating constantly at 2.5m/s^2, what would be the displacement of the bicycle after 6.5 seconds?
The displacement of the bicycle is 85.3125m
Displacement of the bicycle may be defined as the change in position of the bicycle. It is a vector quantity so that it has direction and magnitude.
We are given that,
The initial velocity of the bicycle = u = 5m/s
The acceleration of the bicycle is = a = 2.5 m/s²
The time taken by the bicycle = t = 6.5 seconds
Therefore, to get the value of displacement of the bicycle by the equation of motion which is written as,
S = ut + (1/2) at²
Where, S is displacement, u is initial velocity, a is acceleration and t is time taken by the bicycle.
Since , putting the values in above equation then we get,
S = {5m/s × 6.5sec} +{ (1/2) × 2.5m/s² × (6.5 sec)²}
S = 32.5 m + 52.8125m
S = 85.3125m
Therefore, the bicycle would be moves 85.3125m
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What is the missing force?
Answer: -110N
Explanation:
Assign a variable x to the unknown force. The net force was given as +25N, which means the sum of the two forces must equal +25N.
Subtract 135N on both sides
135 + x = 25
x = -110N
The negative sign indicates direction because force is a vector.
A bowling bowl rolls 33m with an average speed of 2.5 m/s how many seconds did the ball roll
Use the principle of superposition (Equation 1.3) to predict the electric field at the point 0.5 meters to the right and 1.5 meters above the 5 nC charge. Express your result both in terms of x and y components, and then in terms of total magnitude and direction.
Answer:
Explanation:
The x component of electric field Ex = k Q / R²
= 9 x 10⁹ x 5 x 10⁻⁹ / .5²
= 180 N .
The y component of electric field Ey = k Q / R²
The y component of electric field Ey
= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²
= 20 N
Total field = \(\sqrt{180^2+20^2}\)
= 181.1 N .
Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111
= 6.33⁰
Patrice has no family history of diseases. Based on her history, what is her doctor MOST likely to tell Patrice?
O A. She should get regular health screenings.
She can avoid all health screenings.
She should visit a psychiatrist regularly.
B.
C.
D. She can avoid all vaccines.
Answer:A
Explanation: because her family doesn’t have any disease
A doctor would likely recommend regular health screenings for Patrice, despite her lack of family disease history. Screenings are universally recommended for early detection and treatment of potential issues. Vaccinations would also not be avoided based on family history alone.
Explanation:Even if Patrice does not have a family history of diseases, her doctor is most likely to tell her that she should get regular health screenings. Having no family history of specific diseases does not mean one is entirely free from the potential of developing health issues. Regular health screenings can help detect potential problems early, when they're easier to treat or manage. These screenings can involve routine physical exams, blood tests, or specific tests like mammograms or colonoscopies, depending upon age, gender, and other factors. Vaccines, similarly, are not decided based on family history, but rather on the possibility of exposure to specific diseases and age-specific recommendations.
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Can someone explains questions 4 and 5 and tell me which of my ans are wrong? please.
The values and the description of the motion of the objects under gravity are as follows;
1. The same
2. A smaller
3. A greater
4. 40 m/s
a. 5 m/s directed down
b. 45 m/s
5. a. Upwards
b. B
c. B
d. 10 m/s²
e. 10 m/s²
f. C
What is gravitational acceleration?Gravitational acceleration is the acceleration due to the force of the Earth's attraction or pull on an object.
1. Compared with X, Y has the same acceleration as they fall
2. Compared with X, Y hits the ground with a smaller speed
3. Compared with X, Y has a greater time of descent
4. Assume g = 10 m/s², and that there is no air resistance. A stone is dropped from rest. What is its speed after 4 seconds.
The speed is given by the equation;
v = u + g•t
The velocity of the stone is therefore;
v = 0 + 10 × 4 = 40
The speed of the stone = 40 m/s
a. The initial speed of the stone u = 25 m/s
Therefore;
v = 25 - 10 × 3 = -5
The speed of the stone after 3 seconds is 5 m/s directed down
b. The initial speed of the stone = 15 m/s
Direction of the stone = Downwards
The speed after 3 seconds is therefore;
v = 15 + 10 × 3 = 45
The speed after 3 seconds is 45 m/s
5. a. The speed of the ball at point A is -30 m/s which is upwards, given that the speed is measured in the downward direction
b. The ball is stationary when the speed is 0, which is at point B.
c. The motion is a projectile motion, of an object moving upwards under gravity. The ball reaches its maximum height when its speed is 0, which is at point B.
d. The acceleration of the ball is due to gravity and it is constant. The acceleration at point C is therefore, 10 m/s²
e. The acceleration at point A is 10 m/s²
f. The point where the ball has the same speed as it did at point A is given by the point that is equidistant as point A from the point B where the speed is 0, which is point C.
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You throw a ball toward a wall with a speed of 25.0 m/s and at an angle of 40.0° above the horizontal. The wall
is 22.0 m horizontally from the release point of the ball.
A. How far above the release point does the ball hit the wall?
B. What are the horizontal and vertical components of the velocity as the ball hits the wall?
PLEASE HELP
Answer:
We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ
0
be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v
x
=v
0
cos40.0°, the time it takes for the ball to hit the wall is
t=
v
x
Δx
=
(25.0m/s)cos40.0
o
22.0m
=1.15s.
(a) The vertical distance is
Δy=(v
0
sinθ
0
)t−
2
1
gt
2
=(25.0m/s)sin40.0
o
(1.15s)−
2
1
(9.80m/s
2
)(1.15s)
2
=12.0m.
(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v
x
=v
0
cos40.0°=19.2m/s.
(c) The vertical component becomes (using Eq. 4-23)
v
y
=v
0
sinθ
0
−gt=(25.0m/s)sin40.0
o
−(9.80m/s
2
)(1.15s)=4.80m/s.
(d) Since v
y
>0 when the ball hits the wall, it has not reached the highest point yet.
Answer:
horizontal component of the velocity of the ball is vx=v0cos40.0°, the time it takes for the ball to hit the wall is
t=Δx/vx=(25.0m/s)cos40.0o22.0m=1.15s.
(a) The vertical distance is
Δy=(v0sinθ0)t−21gt2=(25.0m/s)sin40.0o(1.15s)−21(9.80m/s2)(1.15s)2=12.0m.
(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: vx=v0cos40.0°=19.2m/s.
(c) The vertical component becomes (using Eq. 4-23)
vy=v0sinθ0−gt=(25.0m/s)sin40.0o−(9.80m/s2)(1.15s)=4.80m/s.
(d) Since vy>0 when the ball hits the wall, it has not reached the highest point yet.
Explanation:
For the displacement field u(x,t)=u
i
e
i
with components given below, calculate the full three dimensional strain at the point p=e
1
+2e
2
+10e
3
u
1
=0.1x
1
x
2
u
2
=0.1x
2
+5
u
3
=500
The full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
To calculate the full three-dimensional strain at the point \(p = e_1 + 2e_2 + 10e_3\), we need to find the components of the strain tensor \(\epsilon_m_n\).
The strain tensor εₘₙ can be calculated using the formula:
εₘₙ = (0.5) * (∂uₘ/∂xₙ + ∂uₙ/∂xₘ)
Given the displacement field u(x, t) with components:
u₁ = 0.1x₁x₂
u₂ = 0.1x₂ + 5
u₃ = 500
We can calculate the components of the strain tensor as follows:
\(\epsilon_1_1 = (1/2) * (\delta u_1/\delta x_1 + \delta u_1/\delta x_1)\\= (1/2) * (0.1x_2 + 0)\\= 0.05x_2\)
\(\epsilon_1_2 = (1/2) * (\delta u_1/\delta x_2 + \delta u_2/\delta x_1)\\= 0.05x_1\)
\(\epsilon _1_3 = (1/2) * (\delta u_1/∂x_3 + \delta u_3/\delta x_1)\\= (1/2) * (0 + 0)\\= 0\)
\(\epsilon_2_1 = (1/2) * (\delta u_2/\delta x_1 + \delta u_1/\delta x_2)\\= (1/2) * (0 + 0.1)\\= 0.05\)
ε₂₃ = (1/2) * (∂u₂/∂x₃ + ∂u₃/∂x₂)
= (1/2) * (0 + 0)
= 0
ε₃₁ = (1/2) * (∂u₃/∂x₁ + ∂u₁/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₂ = (1/2) * (∂u₃/∂x₂ + ∂u₂/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₃ = (1/2) * (∂u₃/∂x₃ + ∂u₃/∂x₃)
= (1/2) * (0 + 0)
= 0
Therefore, the full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
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Find the gravitational force between the
Sun and the Earth.
Given Mass of the Sun = 1.99x10³0 kg
Mass of the Earth = 5.98x10²4kg
The average distance between the Earth
and the Sun = 1.5x10¹¹ m.
Answer:
The process is given in the pic.
I have taken the average masses so u substitute the values and solve hope it will help :)❤
example of nuclear fission
Answer:
In nuclear power plants, energetic neutrons are directed into a sample of the isotope uranium-235. ... A common fission reaction produces barium-141 and krypton-92. In this particular reaction, one uranium nucleus breaks into a barium nucleus, a krypton nucleus, and two neutrons
Inelastic collisions do not conserve kinetic energy. Does
this violate the Law of Conservation of Energy?
Answer:
No. Because undefined amounts of energy are also released in deformation of the objects, heat released, etc.
Kieran ran 8 laps of the track in 18 minutes. Jevon ran 6 laps of the track. Who had a greater average speed
Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.
We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.
Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.
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Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. a 2-column table with 4 rows. the first column labeled step has entries 1, 2, 3, 4. the second column labeled command has entries, grip block, lift block 10 centimeters, hold for 20 seconds, release block. during which step does the robotic arm do work on the block? step 1 step 2 step 3 step 4.
Step 2 does the robotic arm do work on the block. Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.
What is a robotic arm?A robotic arm is a type of artificial arm that may be programmed to do tasks similar to those of a human arm.
The arm can be the sum of the mechanism or part of a larger robot. Joints connect the manipulator's linkages, allowing rotational or translational motion.
By following the directions in the table, Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.
The items in the first column labeled step are 1, 2, 3, and 4. Grip block, elevate block 10 cm, hold for 20 seconds, release block are the items in the second column labeled command.
Step 2 does the robotic arm do work on the block.
Hence,step 2 is the correct answer.
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When air rapidly expands, its temperature normally _________.
A) remains the same
B) increases
C) decreases
D) is unaffected
Answer:
B
Explanation:
When air rapidly expands, its temperature normally decreases (C). This can be explained by the principles of thermodynamics and the behavior of gases.
As air expands, the pressure decreases, and the gas molecules have more space to move around. This results in the molecules having less kinetic energy and fewer collisions with each other. As the number of collisions decreases, so does the overall temperature of the gas.
The decrease in temperature during rapid expansion is a natural process called adiabatic cooling. This occurs because the work done by the gas to expand against its surroundings is done at the expense of its internal energy, which results in a temperature drop. This effect can be commonly observed in the atmosphere, where air cools as it rises and expands in lower pressure environments, such as in clouds or near mountain tops.
Understanding how the temperature of air changes during expansion is essential in various applications, including meteorology, engineering, and aviation. In all these fields, the relationship between air expansion and temperature is a crucial factor in understanding the behavior of gases and predicting their properties in different conditions.
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When looking through a linear polarizer at a light source producing randomly polarized light...
A. The light intensity will fluctuate between 100% and 50% as the polarizer is rotated 360°.
B. The light intensity will fluctuate between 100% and 0% (no light) as the polarizer is rotated 360°.
C. The light intensity will fluctuate between 50% and 0% (no light) as the polarizer is rotated 360°.
D. The light intensity will be the same as the original light source and remain constant as the polarizer is rotated 360°.
E. The light intensity will constantly be reduced by 50% as the polarizer is rotated 360°.
When looking through a linear polarizer at a light source producing randomly polarized light the light intensity will fluctuate between 100% and 0% (no light) as the polarizer is rotated 360°.
Therefore the answer is B.
Linear polarizers are used to filter light that is polarized in a particular direction. If the light source is producing randomly polarized light, then the light waves are oriented in many different directions. When the light passes through a linear polarizer, only the light waves that are aligned with the polarizer's axis are transmitted, while the others are absorbed.
As the polarizer is rotated, the transmitted light intensity will decrease until the polarizer's axis is perpendicular to the orientation of the light waves, at which point no light is transmitted. As the polarizer is rotated further, the transmitted light intensity will increase again until it reaches maximum when the polarizer's axis is parallel to the orientation of the light waves. This results in a sinusoidal pattern of light intensity, with a maximum at 100% and a minimum at 0%, as the polarizer is rotated 360°.
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A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?
Answer:
1350N
Explanation:
Given data
mass= 75kg
velocity= 6m/s
distance= 2m
The expression for the applied force is given as
F= mv^2/d
Substitute
F= 75*(6)^2/ 2
F= 75*36/2
F= 2700/2
F= 1350N
Hence the force is 1350N