A sample of employed people was asked whether they had changed jobs in the past two years. The following display from a TI-84 Plus calculator presents a 95% confidence interval for the population proportion who had changed jobs during that time. 1-Propint C. 19525..38253) p=2888888889 n=90 and a) We are % confident that the population proportion is between Do not round. b) The point estimate, p Round to the nearest 5th decimal place. c) The margin of error, m = Round to the nearest 5th decimal place. d) If p = . then 2 = øn= Round to the nearest whole number. e) Use the information calculated to construct a 98% confidence interval for p. We are % confident that the population proportion is between and . Do not round

By using the concept of expectation, it can be calculated that

a) Probability distribution of Y

P(Y = 0)  = 0.63

P(Y = 1) = 0.25

P(Y = 2) = 0.12

b) Mean of Y = 0.49

  Standard deviation of Y = 0.6999

c) Mean of selling price = $4.4

   Standard deviation of selling price = $0.99

What is expectation?

At first it is important to know about probability of an event.

Probability gives us the information about how likely an event is going to occur

Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.

Probability of any event is greater than or equal to zero and less than or equal to 1.

Probability of sure event is 1 and probability of unsure event is 0.

Suppose x is a random variable with the probability function f(x). suppose

\(x_1, x_2, ...., x_n\) are the values corrosponding to the actual occurance of the event and \(p_1, p_2,...., p_n\) be the corrosponding probabilities.

Expectation is given by the formula

\(E(x) = p_1x_1 + p_2x_2 + ... + p_nx_n\)

a)If a fat quarter has more than 2 defects, it cannot be sold and is discarded.

The table for the probability distribution of X is given

P(X \(\leq\) 2) = 0.58 + 0.23 + 0.11 = 0.92

For probability distribution of Y

P(Y = 0) = P(X= 0 | X \(\leq\) 2) = \(\frac{0.58}{0.92}\) = 0.63

P(Y = 1) = P(X= 1 | X \(\leq\) 2) = \(\frac{0.23}{0.92}\) = 0.25

P(Y = 2) = P(X= 2 | X \(\leq\) 2) = \(\frac{0.11}{0.92}\) = 0.12

Mean of Y = 0 \(\times\) 0.63 + 1  \(\times\) 0,25 + 2  \(\times\) 0.12 = 0.49

E(\(Y^2\)) = 0 \(\times\) 0.63 + 1  \(\times\) 0.25 + 4  \(\times\) 0.12 = 0.73

Variance = \(0.73 - 0.49^2\) = 0.4899

Standard deviation = \(\sqrt{0.4899} = 0.6999\)

b) Here, E(G) = 0.40, V(G) = \(0.66^2\)

The fat quarters sell for $5.00 each but are discounted by $1.50 for each defect found.

Selling price = 5 -1.5G

Mean of selling price = 5 - 1.5\(\times\) 0.4 = 5 - 0.6 = $4.4

Variance of selling price = \(5 - 1.5^2 \times 0.66^2\\\) = $0.9801

Standard deviation of selling price = \(\sqrt{0.9801}\) = $0.99

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Complete Question

Company f sells fabrics known as fat quarters, which are rectangles of fabric created by cutting a yard of fabric into four pieces. Occasionally the manufacturing process results in a fabric defect. Let the random variable x represent the number of defects on a fat quarter created by company f. The following table shows the probability distribution of x.

x                   0            1            2     3         4 or more

probability 0.58 0.23 0.11 0.05 0.03

If a fat quarter has more than 2 defects, it cannot be sold and is discarded. Let the random variable Y represent the number of defects on a fat quarter that can be sold by Company F.

(a) Construct the probability distribution of the random variable Y.

(b) Determine the mean and standard deviation of Y. Show your work.

Company G also sells fat quarters. The mean and standard deviation of the number of defects on a fat quarter that can be sold by Company G are 0.40 and 0.66, respectively. The fat quarters sell for $5.00 each but are discounted by $1.50 for each defect found.

(c) What are the mean and standard deviation of the selling price for the fat quarters sold by Company

According to the area of rectangle, the maximum area is given by a 300 × 500 ft rectangle that is being half of a square

The formula to calculate the area of square is written as

A = l x b

where l refers the length and b refers the breadth in rectangle.

Here we have know that if there were no river then the maximum area would be given by a square configuration since increasing the length and decreasing the width of a square by the same value t  will decrease the area by a square with sides of length t.

Here we have to add the river on one side.

As we all know that we need to fence in a rectangle on one side of the river and then here we have imagine an identical rectangle on the other side of the river.

Then the maximum area is given when the two rectangles form a square that is when we have a rectangle twice as long as wide is written as

=> 1500 feet of fence then the rectangle has fenced sides written as 500feet and 300feet.

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The distance bewteen the points (-3,5) and (3,1) in a simple radical form is 2√13.

The distance formula used in finding the distance between two points is expressed as;

d = √( ( x₂ - x₁ )² + ( y₂ - y₁ )² )

From the graph;

Point A: (-3,5)

x₁ = -3

y₁ = 5

Point B: (3,1)

x₂ = 3

y₂ = 1

Plug the given values into the distance formula and simplify.

\(d = \sqrt{( x_2 - x_1)^2 + (y_2 -y_1 )^2} \\\\d = \sqrt{( 3-(-3))^2 + (1 -5)^2} \\\\d = \sqrt{( 3+ 3)^2 + (1 -5)^2} \\\\d = \sqrt{( 6)^2 + (-4)^2} \\\\d = \sqrt{36 + 16} \\\\d = \sqrt{52}\\\\d = 2\sqrt{13}\)

Therefore, the distance between the points is 2√13.

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The value of x is 3.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

TV is a line and U is the midpoint so,

TU = UV

So,

8x + 11 = 12x - 1

Combining like terms.

11 + 1 = 12x - 8x

12 = 4x

Divide 4 into both sides.

12/4 = x

x = 3

Thus,

x is 3.

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To educate a patient on how to judge the appropriate size of a serving of chicken or lean beef, a good estimate of a 3-ounce serving size is a typical deck of cards or the palm of their hand. This will help them make healthy choices and keep track of their portions. So, a good estimate of a 3-ounce serving size is a typical deck of cards or the palm of your hand.

A serving size is a standardized amount of food or drink that is intended to make it easier for people to compare the nutritional content of different products and understand how much they are consuming. A serving size might be listed on a food label or recommended as part of a healthy eating plan or diet.

The recommended serving size for different foods and beverages can vary depending on several factors, including a person's age, sex, and physical activity level, as well as the nutrient content of the food or drink.

For example, a serving of fresh vegetables might be 1 cup, while a serving of meat, poultry, or fish might be 3 ounces. A good estimate of a 3-ounce serving size is a typical deck of cards or the palm of your hand. This can help you make healthy choices and keep track of your portions.

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Answer:

There is no way to predict this because it could take her anywhere from 11 to 66 tries

Answer:

Idisisisos9191929929293938kdidif8c8c8c87c7c7c7c7c

12

Step-by-step explanation:

9+3 =12

pls make me brainiest

Step-by-step explanation:

1 opción:

Del primer 9:

retirar el fósforo de la parte superior de tal manera que este nueve se convierte en 5 y colocarlo en la parte inferior del segundo nueve de tal manera que se convierte en 8:

5 + 3 = 8

2 opción:

en el primer nueve trasladar el fósforo vertical de la parte superior derecha a la parte inferior izquierda de tal manera que este se convierte en 6:

6 + 3 = 9

Del primer nueve retirar el fósforo vertical superior izquierdo de tal manera que este se convierte en 3 y ese fósforo colocarlo de forma vertical en la parte inferior izquierda del 3 y recorrer de este 3 el fósforo vertical superior derecho hacia la izquierda de tal manera que se convierte en 6:

3 + 6 = 9

Answer:

5*5

Step-by-step explanation:

that would be the easy way

Answer:  12.5 square inches

Step-by-step explanation:

The equation for the area of a triangle is A = bh/2

The base and height are both 5, so its 5×5 divided by 2

25/2 = 12.5 or  12  1/2

Area is always square units, so use square inches

The "ramp" is the hypotenuse of the triangle. It's like they want to know how much they need to cover the side.

Answer:

3 - (n - 1) = 1/2(3n - 4)

Step-by-step explanation:

We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.

Let the number be n.

The first part is: three minus the difference of a number and one:

3 - (n - 1)

The second part is: one-half of the difference of three times the same number and four:

1/2(3n - 4)

Now, let us equate the first and second parts:

3 - (n - 1) = 1/2(3n - 4)

PS: I really do not understand the options

Answer:

D) 3 – (n – 1) = left-parenthesis 6 plus 2 right-parenthesis left-parenthesis x plus 4 right parenthesis equals StartFraction one-half EndFraction left-parenthesis x minus 3 right-parenthesis.(3n – 4)



Answer:

5

Step-by-step explanation:

5(a+3)=40

5a+15=40

5a+15-15=40-15

5a=25

a=5

Answer:

4, 3

Step-by-step explanation:

(11x + 34) is congruent to (15x + 18) because they are vertical angles.

11x + 34 = 15x + 18

34 = 4x + 18

16 = 4x

4 = x

Then substitute it into 15x + 18

15(4) + 18 = 78

That angle plus the smaller one make 90 degrees, so

12 = 5y - 3

15 = 5y

3 = y

Approximately 200 entries per hour were being deposited at 5pm, 2400 entries were deposited between noon and 8pm, 800 entries had not yet been processed by midnight, and entries were being processed most quickly at 8pm.

a) At 5pm, the rate at which entries were being deposited can be approximated by taking the difference between the number of entries at that time and the previous time, 4pm. This is (400-200) / (5-4) = 200 entries per hour.

b) The value of the trapezoidal sum can be approximated by taking the average between the upper and lower boundaries of the subintervals and then multiplying by the width of the intervals. In this case, (200+400+600+800)/2 x 4 = 2400 entries. This represents the total number of entries deposited between noon and 8 pm.

c) According to the model, the number of entries that had not yet been processed by midnight is p(8) = 800 entries.

d) According to the model, the entries were being processed most quickly at 8 pm, since it is the time where p(t) is at its maximum of 800 entries per hour.

Approximately 200 entries per hour were being deposited at 5pm, 2400 entries were deposited between noon and 8pm, 800 entries had not yet been processed by midnight, and entries were being processed most quickly at 8pm.

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Answer:

Step-by-step explanation:

x/2 = 20

*2      *2     (2 cancels)

 x = 40

Answer:

x=40

Step-by-step explanation:

A correlation coefficient based on an observational study cannot be used to support a claim of cause and effect. The correct answer is A: never.

Correlation does not imply causation, and while a strong correlation between two variables may suggest that there is a relationship between them, it does not prove that one variable causes the other. Observational studies are particularly susceptible to confounding variables, which can make it difficult or impossible to determine whether a relationship between two variables is causal or not.

To establish causality between two variables, a randomized controlled experiment is required. In a randomized controlled experiment, the experimenter can manipulate the independent variable and observe the effect on the dependent variable, while controlling for other variables that might affect the outcome. By randomly assigning subjects to different treatment groups, the experimenter can ensure that any differences in the outcome between groups are due to the treatment, rather than some other factor.

Therefore, while a correlation coefficient can be a useful tool for describing the relationship between two variables, it cannot be used to establish causality.

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The probability that he misses the train today is 0.135 or 13.5%.

P(Class runs late)=30%=0.30

P(Miss train ∣ Class runs late)=45%=0.45

General multiplication rule:

P(A and B)=P(A)×P(B ∣ A)

Using the general multiplication rule, we then obtain (and using that the student always catches his train if the class ends on time) :-

P( Miss train)=P( Miss train and Class runs late)=P(Class runs late)×P(Miss train ∣ Class runs late)

= 0.30×0.45

= 0.135

= or 13.5%.

So, the the probability that he misses the train today is 0.135 or 13.5%.

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Answer:

62 × (70 + 8) > (70 + 8) × 26

Step-by-step explanation:

62 ×(70 + 8)

62 × 78

4,836

(70 + 8) × 26

78 × 26

2,028

Therefore 4,836 is greater than 2,028

Answer:

\(62\cdot(70+8)>(70+8)\cdot26\)

Step-by-step explanation:

\(62\cdot(70+8)\\62\cdot78\\4836\\\\(70+8)\cdot26\\78\cdot26\\2028\)

Answer: 264 in.

Step-by-step explanation:

To determine the long-run equilibrium for each firm's production of kites, we need to find the level of output where marginal cost (MC) equals marginal revenue (MR). In perfect competition, firms maximize their profit by producing at the level where MC = MR.

Given the marginal cost function MC = 0.02q, we equate it to the marginal revenue, which is equal to the market price (P) in perfect competition. So, we have:

0.02q = P

Now, we need to find the price at which the quantity demanded (QD) equals the quantity supplied (QS) in the market. To do this, we set QD equal to QS:

QD = QS

Substituting the demand function QD = 4000 - 1000P into the equation, we get:

4000 - 1000P = QS

Now, we can solve for the price (P):

4000 - 1000P = 0.02q

Simplifying further:

1000P = 4000 - 0.02q

P = (4000 - 0.02q) / 1000

Now, we can substitute the value of P into the equation for MC to find the level of output (q):

0.02q = P

0.02q = (4000 - 0.02q) / 1000

Solving for q:

0.02q = 4 - 0.00002q

1.00002q = 4

q = 4 / 1.00002

q ≈ 3999.8

In the long-run equilibrium, each firm will produce approximately 3999.8 kites.

The long-run supply curve for kites in perfect competition is horizontal at the minimum average total cost (ATC) of the firms. This is because in the long run, firms have enough time to adjust their inputs and optimize their production processes, leading to production at the lowest possible cost.

a. To find the number of kites sold and the number of firms in the kite industry, we substitute the price (P) into the demand function QD = 4000 - 1000P:

QD = 4000 - 1000P

QD = 4000 - 1000(4000 - 0.02q) / 1000

Simplifying:

QD = 4000 - 4000 + 0.02q

QD = 0.02q

Since q represents the output per firm and we know that each firm produces around 3999.8 kites, we can substitute this value:

QD = 0.02 * 3999.8

QD ≈ 79.996

Approximately 80 kites will be sold. To find the number of firms in the kite industry, we divide the total quantity supplied by the output per firm:

QS = 3999.8

Number of firms = QS / q

Number of firms = 3999.8 / 3999.8

Number of firms = 1

b. In the very short run, when it is impossible to manufacture any more kites than those produced for that week, the price of kites will be determined by the demand and supply conditions. With the demand function QD = 5000 - 500P, we can find the equilibrium price:

QD = QS

5000 - 500P = QS

Substituting the supply quantity from above:

5000 - 500P = 3999.8

Solving for P:

500P = 5000 - 3999.8

A sample distribution with n = 20 and a five-number summary of 2, 4, 6, 8, and 10 can be generated by arranging the values in increasing order as follows: 2, 2, 3, 4, 4, 5, 6, 6, 7, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10.

To construct a sample distribution with a specific five-number summary, we need to determine the arrangement of values within the dataset. The five-number summary consists of the minimum value (2), the first quartile (Q1, 4), the median (Q2, 6), the third quartile (Q3, 8), and the maximum value (10).

Since the dataset has 20 observations, we need to arrange these values in increasing order while ensuring that they match the given five-number summary. In this case, we can start by placing the minimum value of 2 at the beginning of the dataset. Next, we need to include additional values between 2 and 4 to represent the first quartile. We can add two 2's, a 3, and two 4's to achieve this.

Moving forward, we continue adding values to match the remaining quartiles. For Q2, we include values 5 and 6, and for Q3, we include three 8's and four 9's. Finally, we add four 10's to represent the maximum value.

By arranging the values in this manner, we obtain a sample distribution with n = 20 and a five-number summary of 2, 4, 6, 8, and 10.

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Answer:

  6

Step-by-step explanation:

You want the x-coordinate of the midpoint of segment AB with endpoint coordinates A(21, 5) and B(-9, -13).

The midpoint of a line segment has coordinates that are the average of the endpoint coordinates:

  M = (A +B)/2

  M = ((21, 5) +(-9, -13))/2 = (12, -8)/2

  M = (6, -4)

The midpoint of AB is (6, -4).

The x-coordinate of the midpoint is 6.

Answer:

73

Step-by-step explanation:

180-107=73

a)Total material to be excavated: 1,613 cubic yards

b) Number of days to complete the work: 11 days

c) Number of weeks to complete the work: 2 weeks

d) Labor and material cost: $17,600

e) Rate per cubic yard of material removed: $260

a) The volume of the lake:

Area of the lake = 1 acre

Average depth of the lake = 5 feet

Convert the area to square feet: 1 acre = 43,560 square feet

Volume of the lake = Area × Depth = 43,560 cubic feet

Convert the volume to cubic yards: 43,560 / 27 = 1,613 cubic yards

b) The number of days to complete the work:

The contractor can remove 150 cubic yards of material in 1 shift.

Divide the total volume of the lake by the amount removed in a shift: 1,613 / 150 = 10.75 ≈ 11 days

c) The number of weeks to complete the work:

The contractor removes 100 cubic yards of material per day for 2 days of the week.

The contractor removes 150 cubic yards of material per day for the remaining 5 days of the week.

Calculate the total amount of material removed in a week:

(100 × 2) + (150 × 5) = 950 cubic yards

Divide the total volume of the lake by the amount removed in a week:

1,613 / 950 = 1.7 ≈ 2 weeks (rounded to whole number)

d) The labor and material cost:

The cost of the operator and helper per hour is $200.

Calculate the total production:

Amount produced on Mondays and Fridays

=100 cubic yards per day × 2 days = 200 cubic yards

Amount produced on the remaining 5 days

= 150 cubic yards per day × 5 days = 750 cubic yards

Total production in the first week

= 200 + 750 = 950 cubic yards

The total hours worked in the first week:

Hours worked on Mondays and Fridays

= 2 days × 8 hours/day = 16 hours

Hours worked on the remaining 5 days

= 5 days × 8 hours/day = 40 hours

Total hours worked in the first week

= 16 + 40 = 56 hours

The labor and material cost in the first week:

Labor and material cost per hour = $200

Total labor and material cost in the first week

= 56 hours × $200/hour = $11,200

The amount produced in the second week and total hours worked:

Amount produced in the second week = Total volume - Amount produced in the first week

= 1,613 - 950 = 663 cubic yards

Total hours worked in the second week

= 3 days × 8 hours/day + 2 days × 8 hours/day = 32 hours

The labor and material cost in the second week:

Labor and material cost in the second week = Total hours worked in the second week × $200/hour

= 32 hours × $200/hour = $6,400

Total labor and material cost = Labor and material cost in the first week + Labor and material cost in the second week = $11,200 + $6,400 = $17,600

e) The rate per cubic yard of material removed:

A 30% markup is required.

Calculate the markup amount: 30% × $200 = $60

Calculate the rate per cubic yard: $200 + $60 = $260 per cubic yard

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For slope equals to 1/3 the value of k in the line is 3 by slope intercept form.

The increase divided by the run, or the ratio of the rise to the run, is known as the line's slope. In the coordinate plane, it describes the slope of the line. Finding the slope between two separate locations and calculating the slope of a line are related tasks. In general, we require the values of any two separate coordinates of a line in order to determine its slope.

A line's steepness and direction are measured by the line's slope. Without actually using a compass, determining the slope of lines in a coordinate plane can assist in forecasting whether the lines are parallel, perpendicular, or none at all.

Any two different points on a line may be used to compute the slope of any line. The ratio of "vertical change" to "horizontal change" between two different locations on a line is calculated using the slope of a line formula.

The equation of the line :

3y - 5 = 1/9 kx

The slope of line is 1/3

3y - 5 = 1/9k x

by slope intercept form

1/9k = 1/3

k = 3

So, for slope equals to 1/3 the value of k in the line is 3 by slope intercept form.

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Answer:

Emily has 5 apples!!!

Step-by-step explanation:

Ok,

Let the apples Emily has be 'x'

Now,

× + 25= 30

Transpose 25 to RHS

× = 30-25

× = 5

Therefore, Emily has 5 apples :D

Hope it helps!!!

Answer:

No

Step-by-step explanation:

listen to guy above he opened my eyes

Answer:

7

Step-by-step explanation:

Given expression:

The constant is a term that has no variables. Let's verify the terms in the expression to determine which term is the constant.

Determining if 6x³y is a constant:

Determining if 8x² is a constant:

Determining if 5x is a constant:

Determining if 7 is a constant:

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Answer:

7

Step-by-step explanation:

The constant term in an expression is the term without a variable.

The variables in this expression are x and y, so the constant term is 7 as this term does not have a variable.

By using the concept of cryptography, it can be concluded that

A solution that is now widely used to allow two parties to secretly exchange keys is Deffie - Hellman protocol

What is cryptography?

Cryptography refers to secure information and communication techniques derived from mathematical concepts and a set of rule-based calculations called algorithms, to transform messages in ways that are hard to decipher.

This is a concept of Cryptography

Diffie–Hellman key exchange establishes a shared secret between two parties which will be used for secret communication for exchanging data over a public network.

A solution that is now widely used to allow two parties to secretly exchange keys is Diffie - Hellman protocol

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