a sample of a gas has volume 78.5ml at 318.15 K.. What Volume at will the sample occupy at
273. 15 K when the pressure is held constant?
Use charles Law formula of volume. ​

The temperature of sample gas that fills a 0.725L container is 576K which initially is collected in a 0.4L container at a temperature of 318K.

Given the volume of a sample gas (V1) = 0.4L

The temperature of gas (T1) = 45°C = 273 + 45 = 318K

The volume of container that fills gas (V2) = 0.725L

The temperature of gas at volume V2 = T2

We know that from ideal gas laws, the volume of gas and temperature are directly related to each other where its equation is: PV = nRT

If we assume the pressure is constant, then,

From the above equation we can say that:

V1/T1 = V2/T2

0.4/318 = 0.725/T2

T2 = 576.315K

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The percent ionization of an acidic solution can be calculated from the H+ concentration. the percent ionization of the monoprotic acid of 0.141 M is 18.23 %.

Percent ionization of an acidic solution is the percent of H+ ions in the solution. Thus, mathematically, it is the ratio of H+ ion concentration to the concentration of solution multiplied by 100.

Let HA be the monoprotic acid when it ionizes, forming equal concentration of H+ and A- let it be x. Thus ionization  constant can be written as follows:

Ka = [x]² /[HA]

0.00469 =[x]²/[0.141 M]

   [X] = 0.025. = [H+]

Percentage ionization  = (0.025 M / 0.141 M)× 100

                                      = 18.23 %

Therefore percentage ionization of the acid is 18.23%.

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The net force of the runner, given the data from the question is 280 N

From the question given above, the following data were obtained:

The net force of the runner can be obtained as illustrated below:

Net force = Exerting force - resistance force

Net force = 325 - 45

Net force = 280 N

From the calculation made above, we can conclude that the runner's net force is 280 N

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The net force of the runner would be 280 N.

Hope this helps! Also, if you need help with the other questions regarding this assignment, feel free to check out the study set I made on Quizlet. Thanks and good luck!

Quizlet - "Unit 6: Lesson 2 Newton's First Law QC"

h t t p s : / / q u i z l e t. c o m / 7 3 7 7 5 9 5 5 5 / u n i t - 6 - l e s s o n - 2 - n e w t o n s - f i r s t - l a w - f l a s h - c a r d s / ? n e w

Answer:

highest concentration

C. 10M hcl

Answer: the powdered juice dissolves

Explanation: powdered juice is completely dissolved in water making it present in all the water

Answer:

Kc = [B₃]²/[A₂]³  = 0.40

Explanation:

3A₂ ⇄ 2B₃  

Given at equilibrium =>  [A₂] =2.5 and [B₃] = 2.5

Kc = [B₃]²/[A₂]³ = (2.5)²/(2.5)³ = (2.5)⁻¹ = 0.40

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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The completed sentence is given as follows:

As more solvent is added, more dissolves. As some of the solute particles collide with the solid surface, it rejoins the solid crystal.

When maximum solubility is reached, particles are returning to the solid form at the same rate at which they are going into the solution.

Saltwater: Salt: Solvent
Water: Solute

Saltwater- Mixture - Uniform - but, no definite shape. Salt dissolves in water. Salt is best described as a solute.
Soluble: Dissolving

Aqueous Solutions: solutions in which water is the solvent. Water: the universal solvent.

Water is known as the "universal solvent" because it dissolves more compounds than any other liquid. This is critical for all living things on the planet.

It implies that water transports vital chemicals, minerals, and nutrients everywhere it travels, whether through the air, the earth, or our bodies.

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Answer:

methane

Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp

Considering the definition of enthalpy of reaction, the enthalpy change for the reaction is 650 kJ.

The enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.

In this case you want to calculate the enthalpy change of:

5 H₂SO₄ → 5 SO₃ + 5 H₂O

You know the following reaction, with his corresponding enthalpie:

SO₃ + H₂O → H₂SO₄     ΔH = –130 kJ

To obtain the enthalpy of the desired chemical reaction you need 5 moles of H₂SO₄ on reactant side. The given equation has 1 mole of H₂SO₄ on the product side, soit is necessary to locate it on the reactant side (invert it) and multiply it by 5.

When an equation is inverted, the sign of delta H also changes. And since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

In summary, you know that the enthalpy change is 650 kJ.

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Answer:

Answer: He should add a single dot below the symbol to correct the electron dot diagram of an aluminium atom.

Explanation: Electron dot structures are the structures in which valence electrons around an atom are shown. The electrons are represented as dots in these structures.

Aluminium is the 13th element of the periodic table.

Electronic configuration of Aluminium is given by:

Valence electrons of aluminium = 3

In the given image, 2 valence electrons are shown and total number of valence electrons are 3. So, in order to correct the diagram, he should add a single electron below the symbol.

Explanation:

yes giuve me brainliest

Answer:

The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.

for eg, mixture of sand and sugar.

hope it helps..

Taking into account the definition of sensible heat, the specific heat of metal is 0.7036 J/gC.

When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat.

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 41.2 g× (32.8 °C - 99 °C)

For water: Qwater= 4.186 J/gC× 58.5 g× (32.8 °C - 25 °C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the metal gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 41.2 g× (32.8 °C - 99 °C)= 4.186 J/gC× 58.5 g× (32.8 °C - 25 °C)

Solving:

Specific heat of metal× 2727.44 gC= 1919.0718 J

Specific heat of metal= 1919.0718 J÷ 2727.44 gC

Specific heat of metal= 0.7036 J/gC

Finally, the specific heat in this case is 0.7036 J/gC.

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For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer:

Explanation:

Safety: The rate of energy release determines how quickly and explosively the energy is released. In the case of the stick of dynamite, the rapid and instantaneous release of energy can cause a violent explosion. On the other hand, the controlled release of energy from gasoline allows for safer and more manageable energy output, reducing the risk of accidents and minimizing potential harm.

Efficiency: The rate at which energy is output affects the efficiency of a system. In many practical applications, such as engines or power generation, it is desirable to convert energy into useful work as efficiently as possible. Controlling the rate of energy release allows for a more efficient conversion of energy, minimizing waste and maximizing the desired output.

Control and Functionality: Different systems require energy to be released at specific rates to perform their intended functions. For example, in an internal combustion engine, the controlled and timed release of energy from fuel allows for the synchronized movement of engine components, resulting in the desired mechanical work. Controlling the rate of energy output ensures that a system operates effectively and performs its intended function.

Environmental Impact: The rate at which energy is output can also impact the environment. In processes that release energy too rapidly or uncontrollably, such as certain combustion reactions or explosions, there can be significant environmental consequences, including air pollution, damage to ecosystems, and the release of harmful byproducts. Controlling the rate of energy release allows for better management and mitigation of these environmental impacts.

Overall, the rate at which energy is output from a system is crucial for safety, efficiency, control, functionality, and environmental considerations. By regulating and optimizing the rate of energy release, we can ensure that energy is utilized effectively and responsibly in various applications.

The units that the answer to the calculation has is grams SO₂.

The correct option is A.

The unit of the answer in the calculation is determined from the data given for the calculation.

The data given for the calculation is:

0.41 L SO₂ / 1 *  1 mol SO₂ / 22.4 L SO₂ *  64.1 g SO₂ / 1 mol SO₂

The unit of liters will cancel out in the first multiplication.

0.41 L SO₂ / 1 *  1 mol SO₂ / 22.4 L SO₂  = 0.018 mol SO₂

The unit of mol will cancel out in the second multiplication

0.018 mol SO₂ * 64.1 g SO₂ / 1 mol SO₂ = 1.152 grams SO₂.

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Answer:

Yes

Explanation:

The temperature of the reaction mixture rises as energy is released in an exothermic process. The temperature drops when energy is absorbed in an endothermic reaction. Placing a thermometer in the reaction mixture will allow you to track temperature changes.

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:

0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP

Explanation:

The balanced chemical equation for the decomposition of KNO3 is:

2 KNO3 (s) → 2 KNO2 (s) + O2 (g)

From this equation, we can see that 2 moles of KNO3 produce 1 mole of O2. Therefore, we need to calculate the number of moles of KNO3 we have and use the mole ratio to find the number of moles of O2 produced.

First, we need to convert the mass of KNO3 given to moles:

moles of KNO3 = mass of KNO3 / molar mass of KNO3

The molar mass of KNO3 is 101.1 g/mol (39.1 g/mol for K, 14.0 g/mol for N, and 3 x 16.0 g/mol for 3 O atoms), so we have:

moles of KNO3 = 3.25 g / 101.1 g/mol = 0.0321 mol

Now we can use the mole ratio from the balanced equation to find the number of moles of O2 produced:

moles of O2 = 0.5 x moles of KNO3

moles of O2 = 0.5 x 0.0321 mol = 0.01605 mol

Finally, we can convert the number of moles of O2 to volume at STP using the ideal gas law:

V(O2) = n x RT/P = (0.01605 mol)(0.0821 L·atm/(mol·K) x 273.15 K)/(1 atm) = 0.359 L

Therefore, 0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP.

Answer:

tendría que ser 10.?e :

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

The weight of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.

However,

the number of moles of CoCl₂ must be calculated using the following formula:

no of moles = 0.5L × 1M

no of moles = 0.5moles

Molar mass of CoCl₂ = 99g/mol

mass of CoCl₂  = 0.5 × 99

mass of CoCl₂  = 49.5g

Hence, the weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

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The new rate constant is 1.5 * 10^6  M-1s-1 .

In this case we know that we have to use the Arrhenius equation to find the rate constant at two different temperatures by the use of the formula;

ln(k2/k1) = -Ea/R(1/T2 - 1/T1)

k2 = Rate constant at  436 K

k1 = Rate constant at 249 K

T1 = initial temperature

T2  = final temperature

R = Gas constant

Ea = activation energy

Hence;

ln(k2/1.60 × 10^2) = -38 * 10^3/8.314(1/436 - 1/249)

ln(k2/1.60 × 10^2) =  -38 * 10^3/8.314(0.002 - 0.004)

ln(k2/1.60 × 10^2) =  9.14

k2/1.60 × 10^2 = e^ 9.14

k2 = e^ 9.14 * 1.60 × 10^2

k2 = 1.5 * 10^6  M-1s-1

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Answer:

Electrical light energy, heat energy,

Explanation:

Electrical light energy, heat energy, etc. Chemical energy can be converted to electrical energy. Thermal energy can be converted to heat energy. Nuclear energy can be converted to light energy and heat energy.

Average atomic mass of newly discovered element X is 166

What is average atomic mass?

It is calculated by adding the masses of the element's isotopes each multiplied by its natural abundance on Earth

Given data

 Isotope                Mass              % abundance

   15                          71                       71.007

   21                          75                      74.996

   64                          77                       77.112

Contribution made by each isotope by multiplying natural abundance with mass

Average atomic mass

     =  (71 × 71.007 + 75 × 74.996 + 77 × 77.112) / 100

     = 166

Therefore average atomic mass is 166

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Empirical formula of Carbon dioxide :

To determine the concentration of H2SO4, we can use the concept of molarity (M) and the equation:

M1V1 = M2V2

where:

M1 = concentration of NaOH (in this case, 1.90 M)

V1 = volume of NaOH used (in this case, 38.70 cm^3)

M2 = concentration of H2SO4 (what we're trying to find)

V2 = volume of H2SO4 used (in this case, 10.30 cm^3)

Rearranging the equation, we have:

M2 = (M1 * V1) / V2

Substituting the given values:

M2 = (1.90 M * 38.70 cm^3) / 10.30 cm^3

M2 ≈ 7.12 M

Therefore, the concentration of H2SO4 is approximately 7.12 M.

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Answer:

1 and 2 are identical

Explanation:

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