A sample of 3.62 moles of diphosphorous trioxide is
reacted with 6.31 moles of water to produce
phosphorous acid. Using the balanced equation
below, predict which is the limiting reactant and the
maximum amount in moles of phosphorous acid that
can be produced.
P2O3 + 3H₂O → 2H3PO3
A. water, 8.42 moles
B. water, 4.21 moles
C. diphosphorus trioxide, 7.22 moles
D. diphosphorus trioxide, 3.75 moles

Answer:

\(\fbox{Law -Based \: on \: laws \: of \: thermodynamic}\)

Explanation:

At constant pressure Thermal energy always moves from a greater energy level to a lesser energy level, laws of thermodynamics prove that.

Nature always likes to attain equilibrium either it's movement of heat energy or flow of water from higher region to lower region. The first and second law of thermodynamics are profe of that, the first law says that the total energy of universe is Constant. Energy can not be destroyed it always changes from one form to another, by work and heat. The second law explains why thermal energy moves from a greater energy level to a lesser energy level, it deals with the change in entropy of a system and surrounding and states heat flows from hot environment to cold environment.

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

the particles of matter are arranged in different ways for the different states

Explanation:

because solid liquid and gas all three matters have different states for example the particles in a solid are closely packEd and form of movement is vibration

1,3 diiodo propane is formed when oxetane is heated at reflux.

Reflux is defined as the process which involves heating the chemical reaction for a specific amount of time, while continually cooling the vapor produced back into liquid form, using a condenser. The vapors that are produced above the reaction continually undergo condensation, returning to the flask as a condensate.

Oxetane is a stable carbon compound which shows characteristic properties when reacted with conc. acids. When oxetane reacts with HI it gets reduced to form 1,3 diiodo propane which is also an organic compound.

Therefore, when oxetane is heated in excess amount of concentrated HI, the product formed is 1,3 diiodo propane.

The reaction is given in the image attached below.

The given question is incomplete and the completed question is given below.

Draw the structural formula(s) for the organic product(s) formed when the following compound (OXETANE) is heated at reflux in an excess of concentrated (HI) .

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According to the question, the density of the object is 0.831 g/mL.

Density may be defined as a type of physical property that significantly involves the measurement of quantity or mass per unit of volume in a particular substance.

Density is further characterized as the ratio of mass per unit volume. The unit of density can be expressed in g/cm³ or kg/m³.

According to the question, the mass of an object is = 3.40 oz.

Convert ounce into grams:

1 ounce = 28.35 grams.

3.40 ounces = 3 × 28.35 = 96.38 g.

The volume of an object = 0.1159 L. =  115.9 mL.

Now, the formula for calculating density = \(\frac{mass}{volume}\)

= 96.38/115.9 = 0.831 g/mL.

Therefore, the density of the object is 0.831 g/mL.

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Answer:

Most aren't able to take in carbon dioxide gas from the air or produce any oxygen.

Explanation:

science bro

The diatomic gas ( X2 ) is N₂ dinitrogen.

Dinitrogen is a chemical compound fashioned from the covalent bonding of two nitrogen atoms. it's far a colorless, odorless gas at room temperature and pressure, which makes up about seventy-eight % of the Earth's environment.

Diatomic gas is a chemical compound formed from the covalent bonding of two nitrogen atoms. it's miles drab, odorless gasoline at room temperature and stress, which makes up about seventy eight % of the Earth's surroundings.

Volume = 6.4 L

Pressure = 1.3 atm

Temperature = 25 C = 298 K

R = 0.08206 L.atm/mol.K

P * V = n * R * T

1.3 atm * 6.4 L = n * 0.08206 L.atm/mol.K * 298 K

n = 0.34 moles

difference of mass is the mass of gas = 9.5 g

Molar mass = Mass / No. of moles = 9.5 g / 0.34 moles = 27.9 g/mol

diatomic gas with molar mass 28 g/mol is N2

Hence the diatomic molecule is N2      

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306.178 liters is the volume of O2 at STP, required for the complete combustion of 125g octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and H20

To calculate the volume of \(O_{2}\) required for the complete combustion of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\) at STP (Standard Temperature and Pressure), we need to consider the stoichiometry of the balanced chemical equation.

The balanced equation for the combustion of octane is:

\(C_{8}H_{18}\) + 12.5\(O_{2}\) -> 8\(CO_{2}\) + 9\(H_{2}O\)

From the equation, we can see that 1 mole of octane requires 12.5 moles of \(O_{2}\) to completely combust. The molar mass of octane (\(C_{3}H_{18}\)) is approximately 114.22 g/mol.

To calculate the moles of octane, we divide the given mass by the molar mass:

Moles of octane = 125 g / 114.22 g/mol ≈ 1.093 mol

Since the molar ratio between octane and \(O_{2}\) is 1:12.5, the moles of \(O_{2}\)required can be calculated as:

Moles of \(O_{2}\) = 1.093 mol * 12.5 ≈ 13.663 mol

Now, we can use the ideal gas law, PV = nRT, to calculate the volume of \(O_{2}\) at STP. At STP, the temperature is 273 K, and the pressure is 1 atm.

Using the molar volume of an ideal gas at STP (22.4 L/mol), the volume of \(O_{2}\) required is:

Volume of \(O_{2}\) = Moles of \(O_{2}\) * Molar volume = 13.663 mol * 22.4 L/mol ≈ 306.178 L

Therefore, approximately 306.178 liters of \(O_{2}\) at STP would be required for the complete combustion of 125 grams of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\)

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Answer: The compound is \(Fe_2(SO_4)_3\)

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

A. 1 mole of \(Al(NO_3)_3\) weighs = 26.98(1)+14.01(3)+15.99(9) =212.99 g/mol

B. 1 mole of \(C_3H_8\) weighs = 12.01(3)+1.007(8) = 44.1 g/mol

C. 1 mole of \(Fe_2(SO_4)_3\) weighs = 55.84(2)+32.06(3)+15.99(12) = 399.91 g/mol

D. 1 mole of \(CaCl_2\) weighs = 40.07(1)+35.5(2)= 110.98 g/mol

Thus the compound is \(Fe_2(SO_4)_3\)

It is not stated what the molar absorptivity of Cu2+ at 780 nm with a 1 cm route length is. Depending on the particular solution and circumstances, the molar absorptivity value changes.

A species' molar absorptivity determines how much of a specific wavelength of radiation it can absorb. A species is stimulated from its ground state to a more energetic excited state as electromagnetic radiation is absorbed.

What about the variable (often called a) in the Beer's law equation? The sample's molar absorptivity, commonly referred to as the extinction coefficient, is expressed as. It is a special physical constant of the sample's chemistry that has to do with its capacity to absorb light of a particular wavelength.

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Answer:

\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L} \\ }\)

where

n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question.

N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules

\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)

We have the final answer as.

Answer:

I believe b, dynamic equilibrium

Explanation:

Answer:

She say that im cool

I'm like "yeah thats true"

I believe in G-O-D

Dont believe in T-H-O-T

Explanation:

Answer:

rolling in the deep

Explanation:

The structural feature according to increasing energy difference between the ground state and excited state electrons is given as (i) conjugated polyene (ii) conjugated diene (iii) isolated diene.

Generally, chemical energy is defined as the energy which is stored in the bonds of chemical compounds (molecules and atoms). Chemical energy is released in the chemical reaction and mostly produces heat as a by-product which is known as an exothermic reaction.

The ground state of an electron is defined as the energy level that it usually occupies, is the state of lowest energy for that electron. There is also a maximum energy present that each electron can have and still be part of its atom.

Generally, the excited state describes an atom, ion or molecule with an electron in a higher than normal energy level than its ground state.

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Answer:

Your answer would be C.

Explanation:

Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.

Gamma particles has no mass or charge.

Gamma radiations is a kind of radiations, which are emitted during a nuclear reaction. Gamma radiations are emitted in the form of photons of energy, they did not carry any particles like alpha, beta and proton. So, because of not carrying any particle this radiations have no mass and as it is on the form of energy they also do not carry any charge.

Hence, the particles which has no mass or charge is gamma.

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Explanation:

tgggghhhhijyyhhjjjjjjjj

population is the number of species living in a given area if this is regarding biology or earth studies :)

A total of 1.5 moles of ammonia (NH₃) could be produced.

To react with 56.0 g of N₂, 6.000 moles of H₂ gas are required.

A. We need to balance the chemical equation first:

N₂ + 3H₂ → 2NH₃

From the balanced equation, we can see that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

Therefore, if 0.75 moles of N₂ are reacted with enough hydrogen gas, we can calculate the moles of NH₃ produced using the mole ratio:

0.75 moles N₂ × (2 moles NH₃ / 1 mole N₂) = 1.5 moles NH₃

Therefore, 1.5 moles of NH₃ can be produced.

B. We can use the molar mass of N₂ to convert 56.0 g of N₂ to moles:

56.0 g N₂ × (1 mole N₂ / 28.02 g) = 2.000 mole N₂

From the balanced equation, we know that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

Therefore, the moles of H₂ required can be calculated using the mole ratio:

2.000 mole N₂ × (3 mole H₂ / 1 mole N₂) = 6.000 mole H₂

Therefore, 6.000 moles of H₂ are needed to react with 56.0 g of N₂.

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Answer:

Security

Explanation:

A wireless network consists of good connection with fast speed, convenience, and reliability. Security is a major problem with wireless connection as someone can get your information by joining the same connection as you.

a. Titration Curve:

On the x-axis, label it as "Volume of HCl added (mL)"

On the y-axis, label it as "pH"

b. Equivalence Point:

The equivalence point is the point in the titration where the moles of acid (HCl) added are stoichiometrically equivalent to the moles of base (unknown base) present initially. In the given data, the equivalence point can be estimated to be around 25.0 mL of HCl added. This is where the pH drops dramatically from 7.88 to 5.28, indicating the neutralization of the base.

c. Calculation of Kb Value:

To determine the Kb value, we need to find the pOH at half-neutralization, where half the volume of the equivalent point has been reached. In this case, the half-neutralization volume is 12.5 mL (half of 25 mL).

From the data, we can observe that at 12.5 mL of HCl added, the pH is 9.26.

pOH = 14 - pH = 14 - 9.26 = 4.74

pOH = -log[OH-]

[OH-] = 10^(-pOH)

[OH-] = 10^(-4.74)

To find [OH-] in moles per liter (M), we need to convert mL to L.

[OH-] = 10^(-4.74) mol/L

Now, since we know that at the equivalence point, the concentration of the acid (HCl) is 0.10 M, we can use the stoichiometry of the reaction to determine the concentration of the base (unknown base).

From the balanced equation:

HCl + OH- → H2O + Cl-

1 mole of HCl reacts with 1 mole of OH-

0.10 M (HCl) = [OH-] M (unknown base)

Therefore, Kb = [OH-][unknown base] / [base]

Kb = (10^(-4.74) mol/L)(0.10 M) / (0.10 M - 10^(-4.74) M)

Simplify and calculate Kb.

c. Selection of Indicator:

Based on the given pKa ranges of the indicators, the indicator phenolphthalein (pKa range: 8.3 - 10.0) would be appropriate for this titration. The reason is that the pH at the equivalence point is expected to be around 7, which is well within the range of phenolphthalein's color change. Bromophenol Blue and Methyl Red have lower pKa values and would not be suitable for indicating the equivalence point in this particular titration.

d. Calculation of Molarity and % Ionization of the Weak Base Solution:

To calculate the molarity of the weak base solution, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

At the half-neutralization point, [A-] = [HA], and the pH is 9.26.

9.26 = pKa + log([A-]/[HA])

The pKa can be determined using the pOH at half-neutralization:

pKa = 14 - pOH = 14 - 4.74 = 9.26

9.26 = 9.26 + log([A-]/[HA])

log([A-]/[HA]) = 0

[A-]/[HA] = 10^0 = 1

Since [A-] = [HA], the concentration of the weak base (before titration) is equal to the concentration of its conjugate acid.

Therefore, the molarity of the weak base solution is 0.10 M.

To calculate the % ionization of the weak base, we can use the formula:

% Ionization = ([A-]/[HA]) × 100

% Ionization = (1/0.10) × 100

% Ionization = 1000%

Note: The % ionization may exceed 100% in cases where the concentration of the conjugate acid is very small compared to the concentration of the weak base.

1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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The compound shown has the IUPAC name O Macmillan Learning. -3-ethyl-2,2-dimethyl-hexane Incorrect.

Explanation and response: Because it implies that there's methyl groups on carbons number one and sixth of the parent carbon chain, the name — appears-dimethylhexane is incorrect. Because the name "hexane" implies that a parent atom chain only has six molecules long, the methyl groups are located at the ends of every molecule.

Hexane, commonly referred to as sextane, is an organic compound that belongs to the alkane class. They are acyclic branched as well unbranched hydrocarbons with the standard structure CnH2n+2, and thus entirely composed of hydrogen and saturated oxygen atoms. Hexane is a colorless, clear liquid.

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To convert grams (g) of a substance to moles (mol), you need to divide the mass by the molar mass of the substance.

The molar mass of Be(NO2)2 can be calculated by adding the molar masses of its constituent atoms, which are:

The molar mass of Be: 9.01 g/mol

The molar mass of N: 14.01 g/mol

The molar mass of O: 16.00 g/mol (there are two oxygen atoms in the nitrite ion, NO2-)

So the molar mass of Be(NO2)2 is:

9.01 g/mol (Be) + 2(14.01 g/mol (N) + 2(16.00 g/mol (O)) = 9.01 g/mol + 28.02 g/mol + 32.00 g/mol = 69.03 g/mol

Now we can use this molar mass to convert 11.9 g of Be(NO2)2 to moles:

moles = mass/molar mass

moles = 11.9 g / 69.03 g/mol

moles ≈ 0.1727 mol

Therefore, 11.9 g of Be(NO2)2 is equivalent to approximately 0.1727 moles.

Answer:

The metal will feel hot.

Explanation:

Metals are known for their high thermal conductivity. If one part of the metal feels hot, the other will as well.

_______________________________________________________

This piece of metal has been exposed to the sun, and will feel hot after a certain amount of time. By the statement above, the unexposed part will feel hot as well.

Hope that helps!

Answer:

C

Explanation:

I had this question and C is the right answer

One idea that Dalton taught about atoms was that all atoms of one type were identical in mass and properties.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

3.25 moles

Explanation:

From the equation,   2 moles of Al results in one mole of Al2(so4)3

    6.5 / 2 = 3.25