A runner wants to run 10.1 km. her running pace is 8.1 mi/hr. how many minutes must she run?

The Witness Experimenter configure options include a Skip field that misses out on a different number of random numbers for each replication (Option D).

Experimenter configure options are some basic settings of a Witness experiment. These settings influence how the experiment would behave and what output is produced. With the help of configure options, you can set the value of random number streams and skip replication.

The skip value misses out on a different number of random numbers for each replication. As a result, this provides some level of control over the replication. By changing the value of the skip, you can control which random numbers should be missed and which should not be missed. In addition, by using the skip field, you can increase the simulation run speed. As a result, you get better output in less time.

Thus, the correct option is D.

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Answer: ITS T

Explanation:

In a motor, electrical current enters through the brushes. TRUE.

The specific surface area, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, can be calculated to be a total of 9.53 square meters per gram.

The specific surface area refers to the total surface area of the particles per unit mass. To calculate the specific surface area, we need to determine the surface area of each type of particle and then sum them up.

First, we calculate the surface area of sand particles. The average size of sand particles is given as 0.6 mm. Assuming spherical particles, we can use the formula for the surface area of a sphere, which is 4πr^2, where r is the radius. Therefore, the surface area of a sand particle is 4π(0.3 mm)^2.

Next, we calculate the surface area of silt particles. The average size of silt particles is given as 0.005 mm. Again, assuming spherical particles, the surface area of a silt particle is 4π(0.0025 mm)^2.

Finally, we calculate the surface area of clay particles. The average size of clay particles is given as 0.0006 mm. Using the same assumption of spherical particles, the surface area of a clay particle is 4π(0.0003 mm)^2.

Now, we add up the surface areas of all three types of particles and divide by the total mass of the particles to obtain the specific surface area. This calculation yields a specific surface area of approximately 9.53 square meters per gram.

In summary, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, the specific surface area is calculated to be 9.53 square meters per gram.

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The 90% confidence interval for the proportion, with x = 141 and n = 470, is (0.265, 0.335).

To construct a confidence interval, we need to compute the number of successes (x) first. Given that n = 470 and ˆp (p-hat) = 0.3, we can calculate:

x = n * ˆp = 470 * 0.3 = 141

Next, we can use the formula for a confidence interval for a proportion:

CI = ˆp ± z * √((ˆp(1-ˆp))/n)

Here, z represents the z-score corresponding to the desired confidence level. For a 90% confidence interval, the z-score is  1.645.

Substituting the values into the formula:

CI = 0.3 ± 1.645 * √((0.3(1-0.3))/470)

Calculating the expression inside the square root:

√((0.3(1-0.3))/470) ≈ √(0.21/470) ≈ √0.000446

CI = 0.3 ± 1.645 * 0.0211 ≈ 0.3 ± 0.0346

Therefore, the 90% confidence interval for the proportion, with x = 141 and n = 470, is (0.265, 0.335).

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Answer:

Explanation:

If a star is moving toward Earth, it is blue-shifted. Light is an electromagnetic wave that has a range of colors

what force attracts protons inside a nucleus to each other is the residual strong force, also known as the nuclear force. This force is much stronger than the electromagnetic force, which would typically repel positively charged particles like protons.

what force attracts protons inside a nucleus to each other is the residual strong force, also known as the nuclear force. This force is much stronger than the electromagnetic force, which would typically repel positively charged particles like protons. The residual strong force is mediated by the exchange of particles called mesons between protons and neutrons in the nucleus. The weak nuclear force also plays a role in holding the nucleus together, but it is much weaker than the residual strong force.
that the force that attracts protons inside a nucleus to each other is the residual strong force.

The residual strong force, also known as the nuclear force, is responsible for binding protons and neutrons together in the nucleus of an atom. It is a residual effect of the strong nuclear force, which is the force that holds quarks together within protons and neutrons. The residual strong force is stronger than the electrostatic repulsion between protons, allowing the nucleus to remain stable.

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The correct answer is: All of these answers are correct.

All the provided explanations can be plausible reasons for the low adoption of a cookstove intervention in rural Bangladesh. It is important to consider factors such as technology maintenance, regional cooking preferences, and the suitability of the chosen stove for the user's level of education.

All of these factors can significantly impact the acceptance and adoption of a new cooking technology.It would hinder their ability to effectively use and benefit from the intervention.

Considering these factors collectively provides insight into why the adoption rate remained low. Addressing these issues is crucial to improving the acceptance and success of cookstove interventions in rural communities.

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To burn a leaf as quickly as possible using the reading glasses, they should be held at a distance of 0.22 meters (or 22 cm) from the leaf.

The refractive power of the reading glasses is given as 4.5 D, which means that the focal length of the glasses is:

f = 1/p

where p is the refractive power in diopters. Substituting p = 4.5 D, we get:

f = 1/4.5 D = 0.22 m

This means that the glasses will focus sunlight to a point at a distance of 0.22 meters (or 22 cm) from the lens.

To burn a leaf as quickly as possible, we need to position the glasses so that the focused sunlight falls on the leaf. This can be done by holding the glasses at a distance of one focal length from the leaf, which in this case is 0.22 meters (or 22 cm).

So, to burn a leaf as quickly as possible using the reading glasses, they should be held at a distance of 0.22 meters (or 22 cm) from the leaf.

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a) The absolute pressure in the container at this temperature is 5.56 * 10⁴ kPa; b) 0.07 moles of gas has been removed from the container.

a) Calculation of absolute pressure: The formula of absolute pressure is given by the ideal gas law formula i.e PV = nRT; where, P = pressure of gas in Pascal (Pa)V = volume of the gas in liters (L)n = number of molecules of gas, R = Universal gas constant which is equal to 8.314 J/K/mol

T = temperature of gas in Kelvin (K)Hence, P = nRT / V, P = (3 * 10²⁴) * 8.314 * (273+20) / (15 * 1000) P

= 5.56 * 10⁷ Pa

≈ 5.56 * 10⁴ kPa

Therefore, the absolute pressure in the container is 5.56 * 10⁴ kPa.

b) Calculation of moles of gas removed: From the ideal gas law PV = nRT, we have; n = PV / RT

Given that the temperature has changed to 1.5 °C lower while the pressure has reduced by 5%, this means that; P₂ = P₁ - 0.05 P₁ = 0.95 P₁ and T₂ = T₁ - 1.5

= 20 - 1.5

= 18.5 °C.

The new pressure (P₂) is given by; P₂ = (0.95 * 5.56 * 10⁷) Pa

= 5.28 * 10⁷ Pa

The new temperature (T₂) in Kelvin is given by T₂ = 18.5 + 273

= 291.5 K

Using the ideal gas law formula again, the number of moles in the gas at initial conditions is given by; n₁ = P₁V / RT₁

Substituting in the values of P₁, V, R and T₁; n₁ = (5.56 * 10⁷ * 15 * 10⁻³) / (8.314 * 293)

= 0.94 mol

Similarly, the number of moles in the gas after the change in temperature and pressure is given by; n₂ = P₂V / RT₂

Substituting in the values of P₁, V, R and T₂; n₂ = (5.28 * 10⁷ * 15 * 10⁻³) / (8.314 * 291.5)

= 0.87 mol

The amount of gas removed is therefore given by the difference between the number of moles in the gas before and after the change; i.e. moles of gas removed = n₁ - n₂

= 0.94 - 0.87

= 0.07 mol

Therefore, 0.07 moles of gas has been removed from the container.

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Answer:

Acceleration (b) not sure tho

Explanation:

Answer:

2200000 = 2.2E6 min for light from Proxima to reach earth

8.3 min from light sun to reach earth

2.2E6/8.3 = 2.56E5   times for light from Proxima

Proxima is about 256,000 times farther away than the sun

Since the sun is about 93,000,000 = 9.3E7 miles from earth

Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away

Note - the speed of light is

3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given

Answer:

Newton's Third Law of Motion

Explanation:

it explains that forces always come in action-reaction pairs. The Third Law states that for every action force, there is an equal and opposite reaction force

Answer:

newtons third law of motion

Explanation:

newtons third law of motion explains that forces always come in action-reaction pairs

The calculated mathematical expressions are projectile range is gu and height is 7.8 m.

Maximum height velocity equals half of initial height velocity.

Maximum height velocity equals the horizontal component.

V x=2u y=u 2 4u 2 = 23 u.i.e. tan 3 = 60

Projectile range = gu Gu 2sin120 = 3u2/3g= 2 sin2 = gu

The projectile's horizontal displacement determines its range. Since gravity only works vertically, there is no acceleration in this direction. demonstrates the range line. The projectile's range is a function of beginning speed, just like time of flight and maximum height.

We are aware that s=ut+0.5 at 2.

⟹5=25sinθ×2−0.5×g×4

∴sinθ= 2 1

⟹θ=30

o and H=2025si230

=7.8m

After three seconds, a stone that was thrown at an angle of ′′ with the horizontal from a tall building's roof hits the ground. It was back at the projection level two seconds after the projection. Consequently, the building's height is (g=10m/s2)

The projectile can travel as high as h, which is equal to half of this triangle's altitude. = H - 12H, resulting in the desired outcome of h = H/2.

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​

Answer:

800 Newtons.

Explanation:

Work is defined as the force applied to an object multiplied by the distance over which the force is applied. The formula for work is W = F x d.

In this case, the force required to lift the box is equal to the work done divided by the distance.

F = W / d

F = 800 J / 5 m

To convert Joules to newtons, we need to use the relation 1 Joule = 1 Newton x Meter

F = 800 N

So the box weighed 800 Newtons.

Given

mj = 65 kg

mc = 78 kg

voj = 5.75 m/s

after collision

vfj = vfc = 0 m/s

Procedure

The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

The velocity before the collision would be 4.8m/s

Answer:

Total Resistance in circuit is Fourteen Ohms (14 Ω).

Explanation:

How do we know, if the resistors are connected in series, the total resistance is the sum of all the resistors.

(Important: The total resistance can only be added just when the resistors are connected in series)

Then, total resistance (TR ) is the sum of all resistors (T1 + T2, in this case)

TR = T1 + T2

According to problem data, we have:

TR = 8 Ω + 6 Ω

TR = 14 Ω

                                                                              ║Sincerely, ChizuruChan║

Answer:

spread and go up

Explanation:

like water when hot gas when cold ice when warm liquid

Answer:

\(1\times 10^{8} N/C\)

Explanation:

According to the gauss law

As we know that

Electric field is

\(E = -k\frac{q}{r^2}\)

where,

k = column constant = \(9 \times 10 ^{9}\ N. \frac{m^2}{c^2}\)

q = charge

r = distance from the sphere center

For computing the magnitude of e first we have to need to find out the charge outside of sphere which is

\(q = -\frac{Er^2}{k}\)

\(q = -\frac{1 \times 10^{6} \frac{N}{C} (25m)^2}{9 \times 10 ^{9}\ N. \frac{m^2}{c^2}}\)

q = -0.07 C

Now we have to find the electric field

\(E = k\frac{q}{r^2}\)

The r is 2.5m but in question it is given 5m

So,

Electric field is

\(E = 9 \times 10^{9} N . \frac{m^2 \times 0.07 C}{C^2 (2.5 m)^2}\)

\(E = 9 \times 10^{9} N. \frac{m^2 \times 0.07 C} {C^2 (2.5m)^2}\)

\(= 1\times 10^{8} N/C\)

Within an H-II region, hydrogen atoms become ionized by absorbing ultraviolet radiation from a nearby star.

The high-energy photons from the star have enough energy to knock an electron off the hydrogen atom, leaving a positively charged hydrogen ion or proton.

This process is known as photoionization and is the main mechanism for ionizing hydrogen in H-II regions.

The ionized hydrogen then emits its own radiation, creating the characteristic red glow of H-II regions.

While hydrogen atoms can also become ionized by other means, such as absorbing thermal radiation or capturing free electrons, these processes are less common in H-II regions compared to photoionization by ultraviolet radiation from nearby stars.

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In the dry and extremely hot conditions of Southern California during summer, at approximately 1 pm, one would expect to see that the stomata of plants are closed. This is because to avoid excessive water loss through transpiration, plants tend to close their stomata, which are tiny openings on the surface of leaves responsible for gas exchange. Closing the stomata helps to conserve water by reducing the loss of water vapor from the plant's leaves.

Stomata play a crucial role in gas exchange during photosynthesis. However, when plants are exposed to hot and dry conditions, the closure of stomata becomes essential to prevent excessive water loss. By closing their stomata, plants can reduce transpiration and conserve water. Transpiration is the process through which water vapor escapes from the plant through the stomata.

Closing the stomata helps in minimizing water loss by reducing the evaporation of water from the plant's leaves into the surrounding dry air. This is particularly important in drought conditions when water availability is limited. By conserving water, plants can better withstand the dry and hot environment.

While the closure of stomata helps in water conservation, it also has an impact on photosynthesis. When the stomata are closed, the exchange of gases, including carbon dioxide (CO2) for photosynthesis, is restricted. As a result, the rate of photosynthesis decreases. However, in extremely hot and dry conditions, the priority for the plant is to conserve water rather than carry out photosynthesis. Therefore, it is expected that the stomata will be closed to limit water loss, even though this reduces the availability of CO2 for photosynthesis.

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The loudness of a sound is related to the logarithm of the ratio of the measured intensity, 1, to a reference intensity, I. The loudness, L, of a sound, is measured in decibels, dB, and can be determined using the formula L=10log10 (I0I).

Given, The intensity of the sound of a rocket launching = 4500 times that of a jet engine. The loudness of the rocket launching, L = 170 dBNow, we can determine the value of L0 as follows:L = 10 log10 (I0/I)170 = 10 log10 (I0/I) (Equation 1)Therefore, I0/I = antilog (17) (from Equation 1)I0/I = 50,119.41Since the loudness of the rocket launching, L = 170 dB is already given, we can calculate the loudness of the jet engine as follows:L = 10 log10 (I0/I)dB = 10 log10 (I0/I)dB = 10 log10 (50,119.41)dB = 10 (4.700)dB = 47

The intensity of a rocket launching sound is 4500 times that of a jet engine sound, and its loudness is already provided as 170 dB. The loudness of a sound is related to the logarithm of the ratio of the measured intensity to a reference intensity, I.

To calculate the loudness of a jet engine, we can use the formula L = 10 log10 (I0/I).To determine I0/I, we substitute the loudness of the rocket launching, 170 dB, into the formula. We find that I0/I is equal to 50,119.41. We then substitute this value into the formula for the loudness of the jet engine. We find that the loudness of the jet engine is 47 dB. To the nearest decibel, the loudness of the jet engine is 47 dB.

Therefore, the loudness of the jet engine is 47 dB. 150 words to calculate the loudness of a jet engine, we must first determine the intensity of the sound it produces.

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Metals' complex structures account for their high melting and boiling temperatures as well as their conductivity. A metal's characteristics can be changed by adding another substance to it to create an alloy.

Of all the metals, silver has the highest electrical conductivity. In actuality, silver is the standard by which conductivity in all other metals is measured. Silver ranks 100 on a scale of 0 to 100, followed by copper at 97 and gold at 76.

Due to the fact that the atoms in metals form a matrix through which outside electrons can easily travel, metals are efficient conductors of both electricity and heat. They produce a sea of electrons surrounding the positive nuclei of the interacting metal ions rather than orbiting their individual atoms.

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C. When describing motion, a frame of reference is a system of reference points used to determine position and velocities of objects.

A frame of reference is an arbitrary set of axes with reference to which the position or motion of something is described or physical laws are formulated.

Frame of reference serves a valuable purpose, because it enables us to make more accurate measurement of our position, displacement, velocity and the total distance traveled.

Also, a frame of reference consists of an abstract coordinate system and the set of physical reference points that uniquely fix the coordinate system and take measurements within that frame.

In other words, it is a system or base, on which motion of an object is determined.

Thus, when describing motion, a frame of reference is a system of reference points used to determine position and velocities of objects.

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The ranking of the surfaces according to the amount of bending experienced by the wheels at the boundary would be: surface a, surface b, and surface c, with surface a causing the greatest amount of bending and surface c causing the least.

The amount of bending experienced by the wheels at the boundary between different surfaces can be explained by the difference in the coefficients of friction between the surfaces.

When the wheels transition from the concrete sidewalk to the paved driveway (surface a), the coefficient of friction changes abruptly, causing a significant bending of the wheels at the boundary. This is because concrete has a higher coefficient of friction than pavement, which causes the wheels to slow down quickly as they move from the sidewalk to the driveway. The sudden change in speed and direction of motion causes the wheels to bend and deflect from their initial straight-line course.

When the wheels transition from the paved driveway to the grass lawn (surface b), the coefficient of friction decreases even more, causing the wheels to slow down even more slowly. This results in less bending of the wheels at the boundary between the surfaces.

Finally, when the wheels transition from the grass lawn to the close-cropped grass on the golf course putting green (surface c), the coefficient of friction is even lower, causing the wheels to slow down gradually and smoothly. This results in the least amount of bending of the wheels at the boundary between the surfaces.

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Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

Answer:

Remember a few key things:

1.) Oil comes from plants, but also animals

2.) When heat lamps are done or useless, they go to landfills

3.) Things in landfills go back to the environment after a few years or even decades.

4.) Sometimes there are all-natural oils for heat lamps