A rugby team spend a number of hours training each week. 35% is spent on fitness and
this lasts for 7 hours and 21 minutes. How long do the team spend training each week?

The formation of molecule can easily be shown by drawing Lewis dot structure. Therefore, SiH\(_3\)⁻ will have  1 lone pair as well as it has a negative formal charge.

Lewis dot structure is a way to represent the valence electron of an element in the form of dot. These are mainly beneficial in understanding the chemical formula of covalent compound.

Si belongs to group 14 of periodic table that is carbon family, so valence electron is 4. One electron is added to this due to one negative charge over the compound. Out of 5 unpaired electron, 3 covalent bond is formed with one electron of hydrogen. Two electron is left over silicon. 1 lone pair as well as it has a negative formal charge.

Therefore, SiH\(_3\)⁻ will have  1 lone pair as well as it has a negative formal charge.

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Answer:

If you are referring to the Precambrian time, the answer is 500 Million Years Ago.

Explanation:

Precambrian time is the time period that started with the formation of Earth and ended about 500 million years ago.

Explanation:

having no strongly marked or positive characteristics or features.

The difference in pressure between methane and an ideal gas under the given conditions is approximately 5.93 atm.

The difference in pressure between methane (using the van der Waals equation) and an ideal gas can be calculated using the formula:

ΔP = [(an²/V²) - (2bn/V)] * (RT/V)

where:

ΔP is the difference in pressure,

a and b are the van der Waals constants for methane (a = 2.300 L^2·atm/mol^2, b = 0.0430 L/mol),

V is the volume of the gas (8.00 L),

R is the ideal gas constant (0.0821 L·atm/(mol·K)),

T is the temperature in Kelvin (23.8 °C + 273.15 = 296.95 K).

Substituting the given values into the formula:

ΔP = [(2.300 L^2·atm/mol^2 * (15.0 mol)^2) / (8.00 L)^2 - (2 * 0.0430 L/mol * 15.0 mol) / 8.00 L] * (0.0821 L·atm/(mol·K) * 296.95 K)

Simplifying the expression gives:

ΔP = [(2.300 * 15.0^2) / 8.00^2 - (2 * 0.0430 * 15.0) / 8.00] * (0.0821 * 296.95)

Calculating this expression will give the difference in pressure between methane and an ideal gas under the given conditions.

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Answer: Gemstones can have various internal structures, and it often depends on the type of gemstone. Some common internal structures found in gemstones include:

Explanation: Crystalline Structure: Many gemstones are made up of a regular, repeating arrangement of atoms, forming a crystalline structure. These crystals can have different shapes, such as cubic (e.g., diamond), hexagonal (e.g., emerald), or orthorhombic (e.g., peridot).

Amorphous Structure: Some gemstones lack a defined crystalline structure and instead have an amorphous arrangement of atoms. One example is opal, which is composed of tiny silica spheres in a random arrangement.

Inclusions: Gemstones may contain inclusions, which are solid materials trapped within the gem during its formation. Inclusions can be crystals, minerals, or other materials that give the gemstone a unique appearance and character. In some cases, specific inclusions are used to identify gemstones.

Cleavage and Fracture: The way a gemstone breaks or cleaves along planes of weakness is also a part of its internal structure. Cleavage refers to the tendency of some gems to break along specific planes, creating smooth surfaces, while fracture refers to irregular breaks in gemstones.

Color Zones and Banding: Some gemstones display variations in color within their internal structure, either in the form of color zones or banding. For instance, agate is a type of chalcedony with colorful banding.

Optical Phenomena: Certain gemstones exhibit unique optical phenomena due to their internal structures. Examples include asterism (the star effect in star sapphires), chatoyancy (the cat's eye effect), and iridescence (play-of-color seen in opals).

It's important to note that the internal structure of a gemstone can significantly impact its appearance, durability, and value. Gemologists and experts often study these structures to identify and classify gemstones correctly.

Answer:

The solute is the substance being dissolved.

The solvent is the substance dissolving the solute.

Therefore, the salt is the solute and the water is the solvent.

Explanation:

The salt is the solute.

The carbonate ion (CO₂³⁻) can be represented by three resonance structures.

Carbonate is a carbon oxoanion. It is a conjugate base of a hydrogencarbonate. ChEBI. Carbonate Ion is a polyatomic ion with formula of CO₃(²⁻).

Here are the three resonance structures for CO₂³⁻:

Structure with double bonds between carbon and two oxygen atoms:

O-C-O

Structure with double bonds between carbon and one oxygen atom, and a single bond with another oxygen atom:

O-C-O

Structure with double bonds between carbon and two oxygen atoms:

O-C-O

In reality, the actual structure of the carbonate ion is a combination or hybrid of these resonance structures, with the negative charge being delocalized over the three oxygen atoms. The image is given below.

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Answer:

indian ocean

Explanation:

Answer:

13.3 mL

Explanation:

To make a 1.00 M solution of HCl from a 15.0 M concentrated solution, we can use the dilution formula:

M1V1 = M2V2

∴ M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

We are given:

M1 = 15.0 M (concentrated HCl solution)

V1 = unknown

M2 = 1.00 M (desired final concentration)

V2 = 200 mL (desired final volume)

Plugging in these values, we get:

15.0 M x V1 = 1.00 M x 200 mL

Simplifying and solving for V1, we get:

V1 = (1.00 M x 200 mL) / 15.0 M

V1 = 13.3 mL (rounded to three significant figures)

Therefore, we need to measure 13.3 mL of concentrated HCl and then add enough water to bring the total volume up to 200 mL to make a 1.00 M solution.

The name of the compound made of magnesium and fluorine is magnesium fluoride and its formula is MgF2. Magnesium fluoride is a white crystalline solid that has a bitter taste and is insoluble in water. Magnesium fluoride is a stable ionic compound with a high melting point.

This compound is the primary source of magnesium and fluoride ions in many industrial and chemical processes. Magnesium fluoride is produced by the reaction between magnesium oxide and hydrogen fluoride.

MgO + 2HF → MgF2 + H2O

In the laboratory, magnesium fluoride is produced by dissolving magnesium hydroxide in hydrofluoric acid.

Mg(OH)2 + 2HF → MgF2 + 2H2O

Magnesium fluoride is used in the production of ceramics and glass as a flux and to increase the resistance of the glass to attack by acids. Magnesium fluoride is also used as an optical coating on lenses and other optical components as it has a low refractive index.

Magnesium fluoride is a white crystalline solid with a bitter taste that is insoluble in water. It is the primary source of magnesium and fluoride ions in many industrial and chemical processes. The formula of magnesium fluoride is MgF2. It is used in the production of ceramics and glass as a flux and to increase the resistance of the glass to attack by acids. Magnesium fluoride is also used as an optical coating on lenses and other optical components as it has a low refractive index.

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Balanced chemical equation:

\(3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ----- > 6 KNO3 (aq) + Ba3(PO4)2(s)\)

What is double-displacement reaction?

In an aqueous solution, a double-displacement reaction takes place when the positive and negative ions of two ionic compounds exchange positions to form two completely different compounds.

Chemical formula for :

Barium nitrate---> Ba(NO3)2  (aq)

Pottasium Phosphate = K3PO4 (aq)

Reaction between these two is a type of double displacement type reaction in which ions are exchanged , forming

Pottasium Nitrate -----> KNO3 (aq)

Barium Phosphate -----> Ba3(PO4)2 (s)

(aq) means the phase is aqueous and (s) means phase is solid or the compound precipitated out .

Now, writing the molecular formula using the above data , we get:

\(Ba(NO3)2 (aq) + K3PO4 (aq) ------ > KNO3 (aq) + Ba3(PO4)2 (s)\)

A equation is called balanced when number of chemical species are same on both sides of the equation .

Here, in product side there are 3 Ba and 2 (PO4) and only 1 Ba and 1 PO4 in reactant side to balance this let's multiply

2 with K3PO4 on reactant side and ,

3 with Ba(NO3)2 on reactant side

The equation thus becomes:

\(3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ------ > KNO3 (aq) + Ba3(PO4)2 (s)\)

Now,

There are 6 K atoms on reactant side to balance this let's multiply 6 with KNO3 in product side by doing so we also balanced NO3.

Consequently, the balanced chemical equation is

3 Ba(NO3)2 (aq) + 2 K3PO4 (aq) ----- > 6 KNO3 (aq)  + Ba3(PO4)2(s)

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Answer:

Its food for cannibals.

Benzophenone dissolves in methanol because it forms intermolecular hydrogen bonds with the methanol molecules.

Methanol is a polar solvent, meaning it has a positive and negative end. Benzophenone is also polar, with the carbonyl group (C=O) being the most polar part of the molecule. The oxygen atom in the carbonyl group has a partial negative charge, and the hydrogen atoms in the methanol molecule have a partial positive charge.

This allows for the formation of intermolecular hydrogen bonds between the benzophenone and methanol molecules. These hydrogen bonds increase the solubility of benzophenone in methanol, allowing it to dissolve.

In summary, benzophenone dissolves in methanol due to the formation of intermolecular hydrogen bonds between the polar molecules.

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Answer:

H20

Explanation:

Answer:

hope it helped you

Explanation:

H2O (u have to write ✍️no 2 below H.

Answer: The answer is C

Answer:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

Explanation:

Hope this helps :)

Answer:

3.57 m

Explanation:

Expressed in the correct number of significant digits, The product of the number 1000 and the measurement 0.00357 m will give us;

1000 × 0.00357 = 3.57 m

The correct number of significant figures is three significant figures as seen in 3.57 m

Butane is the gas that will condense at the lowest pressure.

Condensation is the process through which matter transitions from its initial gaseous state into its final liquid state. For instance, condensation happens when water vapour in the air, which is in its gaseous state, comes into touch with a colder surface and turns into liquid water.

The process of condensation, which is the reverse of evaporation, converts airborne water vapor to liquid water. Because it causes clouds to develop, condensation is essential to the water cycle.

When warm air meets cold surfaces or when your home is too humid, condensation happens. This moisture-rich heated air immediately cools down and releases the water, which condenses into liquid droplets on the chilly surface when it comes into contact with it.

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Answer:

B

Explanation:

The mass of sodium present in 15.0 mL of blood drawn from the patient is 47.2 g.

\(15.0 \, \text{mL} = 15.0 \, \text{mL} / 1000 \, \text{mL/L} = 0.015 \, \text{L}\)

\(\text{Number of moles of sodium in 1 L} = \text{Molarity} \times \text{Volume of solution in L}\)

\(\text{Number of moles of sodium in 1 L} = 137 \, \text{mmol/L} \times 1 \, \text{L} = 137 \, \text{mmol}\)

\(\text{Number of moles of sodium in 0.015 L} = 137 \, \text{mmol/L} \times 0.015 \, \text{L} = 2.055 \, \text{mmol}\)

\(\text{Mass of sodium} = \text{Number of moles} \times \text{Molar mass}\)

\(\text{Mass of sodium} = 2.055 \, \text{mmol} \times 22.99 \, \text{g/mol} = 47.2 \, \text{g}\)

The mass of sodium present in the 15.0 mL of blood drawn from the patient is 47.2 g.

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The approximate power per area emitted by the inside wall of an oven when baking a cake in w/m2 is 6 x 3^4.

Comparing the surface power density of various industrial energy sources is crucial. Geographer Vaclav Smil popularised the idea. In the pertinent literature, the phrase is sometimes abbreviated to "power density," which may cause confusion with similar or homonymous concepts.

The power obtained per square metre of Earth's surface area utilised by a particular energy system, including all supporting infrastructure, manufacturing, fuel mining (if relevant), and decommissioning, is expressed in W/m2. Due to the high power density of fossil fuels and nuclear energy, substantial amounts of electricity may be produced in very small spaces at power plants.

6 x 3^4 (for reference Humans are about 300 K)

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12.4 g N₂O₂

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 1.24 × 10²³ molecules N₂O₂

[Solve] grams N₂O₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of N₂O₂ - 2(14.01) + 2(16.00) = 60.02 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

12.3588 g N₂O₂ ≈ 12.4 g N₂O₂

Rutherford's first slide consisted of a conceptual map of the material, which provided an overview of the key ideas, and internal hyperlinks in the form of an outline.

Rutherford, a physicist known for his groundbreaking work on atomic structure, used slides to present his research findings and concepts. In his first slide, he utilized a conceptual map of the material, which is a visual representation of the key ideas and their relationships within the topic.

The conceptual map likely provided an overview of the main concepts and themes that Rutherford intended to cover in his presentation. It helped the audience understand the structure and organization of the material, providing a roadmap for the subsequent slides.

Additionally, Rutherford incorporated internal hyperlinks in the form of an outline to each slide. These hyperlinks allowed him to navigate seamlessly through the presentation and provided an easy way for the audience to follow along. By clicking on the hyperlinks, the audience could directly access specific slides corresponding to the outlined topics.

This approach enhanced the clarity and organization of Rutherford's presentation, enabling a logical flow of information and facilitating comprehension for the audience.

Rutherford's first slide consisted of a conceptual map of the material, which provided an overview of the key ideas, and internal hyperlinks in the form of an outline. This approach ensured a structured and accessible presentation, allowing Rutherford to effectively convey his research findings and concepts to the audience.

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The only option that is consistent with Avogadro's law is (c) Vn = constant (P, T constant), as it directly relates the volume of a gas to the number of particles present, while maintaining constant pressure and temperature.

Avogadro's law states that equal volumes of gases at the same temperature and pressure contain equal numbers of particles, regardless of their chemical nature or physical properties. This law can be expressed mathematically in a few different ways, but the option that is consistent with Avogadro's law is (c) Vn = constant (P, T constant).
This equation represents Boyle's law and Avogadro's law combined, as it shows that the volume of a gas is directly proportional to the number of particles present (n), while keeping the pressure and temperature constant. In other words, if we increase the number of particles in a gas while maintaining the same pressure and temperature, the volume of the gas will increase proportionally.
Option (a) P/T = constant (V,n constant) represents Charles's law, which states that the volume of a gas is directly proportional to its temperature at constant pressure, while keeping the number of particles constant. Option (b) V/T = constant (P, n constant) represents Gay-Lussac's law, which states that the pressure of a gas is directly proportional to its temperature at constant volume, while keeping the number of particles constant. Option (d) V/n = constant (P, T constant) represents Boyle's law, which states that the volume of a gas is inversely proportional to its pressure at constant temperature, while keeping the number of particles constant.
Therefore, the only option that is consistent with Avogadro's law is (c) Vn = constant (P, T constant), as it directly relates the volume of a gas to the number of particles present, while maintaining constant pressure and temperature.

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