The speed of the roller coaster car as shown is 31 m/s
What is the Roller coaster?We know that the roller coaster is the kind of device that we can use to be able to show the conversion of kinetic energy to potential energy. By the use of the roller coaster, we can show that the total mechanical energy in the system is a constant.
As such we have that;
mgh = 1/2mv^2
m = mass of the object
g = acceleration due to gravity
h = height
v = velocity
Hence;
gh= 1/2v^2
v = √2gh
v = √ 2 * 9.8 * 49
v = 31 m/s
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a driver travels 4.25 km in two minutes. if the driver's initial velocity is 20m/s, what is the acceleration
Recall the definition of average velocity:
average v = ∆x / ∆t
The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is
average v = (4250 m) / (120 s) ≈ 35.4 m/s
Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:
average v = (initial v + final v) / 2
Solve for (final v) :
35.4 m/s = (20 m/s + final v)/2
final v ≈ 50.83 m/s
Recall the definition of average acceleration:
average a = ∆v / ∆t
Solve for a :
a = (50.83 m/s - 20 m/s) / (120 s)
a ≈ 0.257 m/s²
A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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A block with mass M = 3 kg is moving on a flat surface with constant speed v1 = 12 m/s. A bullet with mass m = 0,1 kg is shot at an angle α = 20◦ with respect to the direction of the movement of the block. The speed of the bullet is v2 = 400 m/s. At what angle and with what speed does the block move after it is hit by the bullet that remains stuck inside the block? Draw a sketch. How long does it take for the block to stop moving if the friction coefficient between the block and the surface is kt = 0,2?
The speed does the block move after it is hit by the bullet that remains stuck inside the block will be 23.7 m/sec and it takes 12.07 seconds to stop.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Apply the law of conservation of momentum principle;
m₁v₁+m₂v₂cosΘ =(m₁+m₂)V
3 kg × 12 m/s + 0,1 kg × 400 m/s cos 20° = (3+0.1)V
36 + 40 cos 20° = 3.1 V
V=23.7 m/sec
The time it takes to stop when the friction coefficient between the block and the surface is 0.2 is found as;
V = u +at
V = 0+ μgt
23..7=0.2× 9.81 ×t
t=12.07 sec
Hence, it takes 12.07 seconds to stop.
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The magnetic field through a circular loop of radius r = 15 cm varies with time, as shown. The direction of the field is perpendicular to the loop. What is the magnitude of the induced emf, ε1, in millivolts, at time t1 = 1.0ms?
B=0I2R(at centre of loop), B = 0 I 2 R(at centre of loop), where R is the loop's radius, gives the magnetic field strength at the loop's centre.
How does the magnetic field change as the loop's radius increases?The magnetic field strength diminishes with increasing radius. Radius of the loop has an inverse relationship with magnetic field intensity.
With its plane normal to an external field of magnitude 5.0102T, a circular coil with a radius of 10 cm and 16 turns that is carrying a current of 0.75 A is at rest. The coil is unrestricted in its ability to rotate around an axis in a plane perpendicular to the field direction.
Hence, the integral around any circle's diameter that is centred on a wire.
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Describe the movement of an object with negative (-) slope in the negative (-) quadrant of a velocity/time graph:
O constant velocity
O no motion
speeds up
O slows down
Movement of an object with negative (-) slope in the negative (-) quadrant of a velocity/time graph is that the object constantly speeds up.
The slope of velocity-time graph of an object represents the magnitude of acceleration of the object,
Velocity-Time graph can be possible only in two quadrants, either first or fourth, Velocity-time graph is not possible in the third and second quadrant because in these two quadrants, time becomes negative and no such thing as negative time has been discovered till now.
Negative slope means the lines making an angle in clock-wise direction with respect to co-ordinate axes.
Negative Quadrant can only mean the fourth quadrant here, because in first quadrant both velocity and time are positive.
Negative (-) slope in the negative fourth quadrant of a velocity/time graph means, that the velocity of the object is increasing with time but in negative direction.
Because the Velocity is constantly increasing in negative direction, the movement of the object can be said to be speeding up is negative direction.
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What acceleration would a 18 kg box have if we pushed it with a force of 250 N across a surface that
has a coefficient of friction of 0.8?
N
Answer:
\(a=0.08\ m/s^2\)
Explanation:
Given that,
Mass of a box, m = 18 kg
It is pushed with a force of 250 N
The coefficient of friction is 0.8
We need to find the acceleration of the box.
Normal force acting on the box,
N = mg
M = 18 × 10
N = 180 N
The force acting on the force in terms of coefficient of friction is given by :
\(F=\mu mg\\\\\text{or}\\\\ ma=\mu mg\\\\a=\dfrac{\mu }{g}\\\\a=\dfrac{0.8}{10}\\\\a=0.08\ m/s^2\)
So, the acceleration of the box is \(0.08\ m/s^2\)
If there is an outlier on your graph, you should ignore it.
O True
O False
Answer:
false
Explanation:
a car moving with 72 km/hr towards east and another car with 90km/hr towards west find relative of A w.r to B
Answer:
please tell me what does w.r mean ? then I will try to give answer
A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
At which point is there the greatest amount of potential energy?
How much power does motor provides an elevator in a building when the total mass when loaded is 500 kg to a height of 3m in 25 seconds?
Refer to the picture!
(a) The work done by the donkey on the cart is 59,721.9 J.
(b) The work done by the force of gravity on the cart is -48,434.87 J.
(c) The work done on the cart by friction during this time is 11,315.12 J.
What is the work done by the donkey on the cart?(a) The work done by the donkey on the cart is calculated as follows;
Wd = Fd cosθ
where;
F is the applied force by the donkeyd is the displacementθ is the angle of inclinationWd = 375 N x 163 m x cos(12.3)
Wd = 59,721.9 J
(b) The work done by the force of gravity on the cart is calculated as;
Wg = Fg x d x cosθ
Where;
Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacementθ = 90⁰ + 4.03⁰ = 94.03⁰
Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)
Wg = -48,434.87 J
(c) The work done on the cart by friction during this time is calculated as;
Wf = Ff x d x cosθ
where;
Ff is the force of friction;Ff = μmg cosθ
Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)
Ff = 69.59 N
Wf = 69.59 x 163 x cos (4.03)
Wf = 11,315.12 J
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Explain how the energy from the sun is transferred to fossil fuel?
Answer:
Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.
Explanation:
Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.
When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.
(u should paraphrase it)
Bro help me
Explain how an object with a higher temperature can have less thermal energy than an object with a lower temperature. ASAP
The total energy of all the particles makes up thermal energy. This implies that larger objects with slower-moving particles at low temperatures can have more energy than smaller ones with higher temperatures.
What is thermal energy?Thermal energy is the sum of the energies of all the particles. This implies that larger objects at low temperatures can have more energy than smaller ones at higher temperatures due to slower-moving particles.
These molecules and atoms move more quickly when something is heated, providing it with more thermal energy. Compared to cold water, hot water has more thermal energy.
Therefore, molecules and atoms in colder objects move more slowly and have less thermal energy than those in warmer ones. The ability of particles to transfer energy increases with speed.
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9. Which of these is equal to 7nm?
O 0.7m
O
0.007m
O 0.000007m
O 0.000000007m
Answer:
o.o7m bb
Explanation:
Methane and oxygen combine in a synthesis reaction. true or false
Answer:
True.
Explanation:
A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a new compound. Methane (CH4) and oxygen (O2) can combine in a synthesis reaction to form carbon dioxide (CO2) and water (H2O). This reaction is exothermic and is the basis of combustion reactions.
The balanced equation for this reaction is:
CH4 + 2O2 -> CO2 + 2H2O
In this reaction, one methane molecule and two oxygen molecules combine to form one carbon dioxide molecule and two water molecules.
It's worth mentioning that methane is considered a greenhouse gas, and the combustion of methane releases carbon dioxide and water vapor into the air, which contribute to global warming and climate change.
Please help with this question!
Answer: Constant Speed
Explanation:
Object's speed does no(sic) change over its entire distance.
No change in speed means that the object is either at constant speed, or is stationary.
A 0. 16 kg hockey puck initially at rest on the ice requires a 0.157 N of horizontal force to set it in motion. Once the hockey puck is in motion, only a 0.047 N horizontal force is needed to keep it moving at a constant velocity.
a. Find the coefficient of static friction, Ms, between the puck and the ice.
Answer:
Approximately \(0.10\), assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\) and a level surface.
Explanation:
Under the assumption, the normal force between the ice and the hockey puck is equal to the weight of the puck:
\(\begin{aligned}m\, g &= (0.16\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) \\ &\approx 1.57\; {\rm N}\end{aligned}\).
The friction on the puck is considered "static" when as long as the puck is not moving relative to that surface. In this question, the maximum value of this static friction is \(0.157\; {\rm N}\). When the external horizontal force exceeds \(0.157\; {\rm N}\!\), the puck would start moving relative to the ice.
Divide maximum static friction by the normal force to find the coefficient of static friction:
\(\begin{aligned}\mu_{s} &= \frac{(\text{maximum static friction})}{(\text{normal force})} \\ &\approx \frac{0.157\; {\rm N}}{1.57\; {\rm N}} \\ &\approx 0.10\end{aligned}\).
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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A chemical symbol is to an element as a chemical formula is to a(n)
t
1
016 (part 1 of 2) 10.0 points
A neutron in a reactor makes an elastic head-
on collision with the nucleus of an atom ini-
tially at rest.
Assume: The mass of the atomic nucleus is
about 12.7 the mass of the neutron.
What fraction of the neutron's kinetic en-
ergy is transferred to the atomic nucleus?
017 (part 2 of 2) 10.0 points
If the initial kinetic energy of the neutron is
8.28 x 10-13 J, find its final kinetic energy.
Answer in units of J.
018 (part 1 of 2) 10.0 points
(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.0787.
(b) The final kinetic energy of the neutron is 7.63 x 10⁻¹³ J.
What is the final velocity of the atomic nucleus?The final velocity of the atomic nucleus is calculated by applying the principle of conservation of linear momentum as follows;
initial momentum of the neutron = final momentum of the atomic nucleus
m₁u₁ = m₂u₂
where;
m₁ is the mass of the neutronu₁ is the initial velocity of the neutronm₂ is the mass of the atomic nucleusu₂ is the final velocity of the atomic nucleusThe mass of the atomic nucleus = 12.7 m₁
u₂ = m₁u₁ / m₂
u₂ = m₁u₁ / (12.7 m₁)
u₂ = 0.0787u₁
The initial kinetic energy of the neutron is calculated as;
K.Ei = ¹/₂m₁u₁²
The final kinetic energy of the atomic nucleus is calculated as;
K.Ef = ¹/₂m₂u₂²
K.Ef = ¹/₂(12.7 m₁)(0.0787u₁)²
K.Ef = 0.0787 (¹/₂m₁u₁²)
K.Ef = 0.0787 (K.Ei)
The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;
= 0.0787 (K.Ei) / K.Ei
= 0.0787
= 7.87 %
The final kinetic energy of the neutron is calculated as follows;
K.E.f (neutron) = (1 - 0.0787) x (8.28 x 10⁻¹³ J)
K.E.f (neutron) = 7.63 x 10⁻¹³ J
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Maria read on an internet blog that infrared light is dangerous to humans. According to the blog, infrared light exposure is responsivle for a number of detrimental effects in humans. Which of these can actually be caused by exposure to infrared light?
a-overheating
b-skin cancer
c-radiation sickness
d-memory less
Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).
Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.
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an electric field of magnitude 3.54 kn/c is applied along the x axis. calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true
Complete question: Conditions are:
(A) The plane and the yz plane are parallel. You could be presuming that the electric field and rectangular plane are not in the same relative direction.
(b) The plane is perpendicular to the x-y plane. \(N·m^2/C \s\)
(C) The y-axis is contained within the plane, and its normal intersects the x-axis at a 39.0° angle. \(Nm2/C\)
Values of electric flux for different conditions in electric field are (a) 0.861 \(Nm^2/C\), (b) no electric flux and (c) 0.697 \(Nm^2/C\)
The electric flux is the flow of electric field through a surface and is calculated by multiplying the surface area with the component of the electric field that is perpendicular to the surface.
In electric flux of electric field:
(a) If the rectangular plane is parallel to the yz plane, the electric field is perpendicular to the plane and the electric flux will be equal to the surface area multiplied by the electric field. The surface area of the plane is 0.350 m * 0.700 m = 0.245 \(m^2\). Thus, the electric flux = 0.245 \(m^2\)* 3.54 kN/C = 0.861 \(Nm^2/C.\)
(b) If the plane is parallel to the xy plane, the electric field will be parallel to the plane and there will be no electric flux through the plane.
(c) If the plane contains the y axis and its normal makes an angle of 39.0° with the x axis, the component of the electric field perpendicular to the plane will be 3.54 kN/C * cos(39.0°). The electric flux = 0.245 \(m^2\) * 3.54 kN/C * cos(39.0°) = 0.697 \(Nm^2/C\).
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A person holds onto an object for 2 minutes but doesn't move the object. Is work done
on the object?
Answer:
No
Explanation:
A plane traveling 3.1 m/s east encounters wind traveling 4.7 m/s north. The wind current is 18 m wide. Determine the time to cross the wind current.
HELP CHECK ANSWERS ONLY 3 QUESTIONS:
1. If you took your weight first at sea level and then on top of a very tall mountain, you would find that your weight:
a. decreases
b. stays the same **
c. increases
2. Smaller masses experience more gravitational force than bigger masses.
A. True
B. False **
3. An asteroid moves away from our planet. What happens to the gravitational attraction between it and the earth as it zooms away?
a. It decreases. **
b. It increases.
c. It does not change.
d. It becomes zero.
Answer:
answer 1 is A, Answer 2 is A, Answer 3 is c
When an asteroid moves away from our planet the gravitational attraction between it and the earth as it zooms away increases.
What is gravitational force?The term gravitational force is a force that is attractive and acts between any two masses on the earth surface.
If you took your weight first at sea level and then on top of a very tall mountain, you would find that your weight increases.
It is false that Smaller masses experience more gravitational force than bigger masses.
When an asteroid moves away from our planet the gravitational attraction between it and the earth as it zooms away increases.
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In a race, Usain Bolt accelerates at
1.99 m/s2 for the first 60.0 m, then
decelerates at -0.266 m/s2 for the final
40.0 m. What was his final velocity? (Unit = m/s)
Thomas the Train chugs along at 2 m/s. Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s. What is Thomas' acceleration?
The acceleration of Thomas is 0.233 m/s^2.
Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.
Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.
We are to find the acceleration of Thomas.
The formula for acceleration is given as :
acceleration = (final velocity - initial velocity) / time
In the given problem, the initial velocity of Thomas, u = 2 m/s.
The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.
Therefore, the acceleration of Thomas will be given as:
a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2
Thus, the acceleration of Thomas is 0.233 m/s^2.
To summarize, the acceleration of Thomas is 0.233 m/s^2.
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if a bus drives 2km due east,5km 45 degrees north of east, 4km at 30 degrees north of west, then 2km due south. what is the bus's resultant displacement?
The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.
The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.
The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km
The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km
The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.
Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km
The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km
The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east
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what are some possible results of constructive forces on earth's surface
Answer:
what are the choices
Explanation:
Answer:
Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.
Explanation: