Answer:
4.04 seconds
Explanation:
Context before solving:In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.
From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.
For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.
To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.
Solving for initial velocity:The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.
Time in the air (projectile motion):
\($t=\frac{2v_isin\theta}{g}\) where g = gravitation acceleration = 9.8 m/s²Solve for \(v_i\) by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.
\($2.00=\frac{2v_isin(30)}{20.0}\)Multiply sin(30) and 2 together.
\($2=\frac{v_i}{20}\)Multiply 20 to both sides of the equation.
\($40=v_i\) \(v_i=40\)Finding the vertical component:Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.
Vertical component:
\((v_i)_y=v_i \times sin\theta\) \((v_i)_y=(40) \times sin(30)\)\((v_i)_y=20\)The vertical component of the velocity vector is 20 m/s.
Finding additional seconds after 2.00 s:Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables \(v_f\), \(v_i\), \(a\), and \(t\).
\(v_f=v_i + at\)Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.
\((v_f)_y=(v_i)_y+a_yt\)The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).
We are trying to solve for time t. Substitute the known values into the equation.
\(0=(20)+(-9.8)t\)Subtract 20 from both sides of the equation.
\(-20=-9.8t\)Divide both sides of the equation by -9.8.
\(2.040816327=t\) \(t=2.04\ \text{seconds}\) Finding total time to reach max height:Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.
\(2.00+2.04=4.04 \ \text{seconds}\)The time that the rocket takes to reach its maximum height is 4.04 seconds.
Answer:
4.04 second is your answer hope it help you........
the speed of an object increases by 30 m/s in 10 seconds. what is its acceleration?
Answer:
3m/s^2
Explanation:
acceleration=velocity/time
acceleration= 30/10=3m/s^2
The following table was given to Candoe by her teacher. She couldn't find answer to some questions. Help her in completing the table.
Layer name Horizon name
1. Organic layer 1. Horizon O
2. Top soil 2. Horizon A
3. Sub soil 3. Horizon B
4. Weathered rock particles 4. Horizon C
5. Bed rock 5. Horizon R
Here is the completed soil horizon table:
Layer name Horizon name
Organic layer 1. Horizon O
Top soil 2. Horizon A
Sub soil 3. Horizon B
4.Weathered rock particles 4. Horizon C
Bed rock 5. Horizon R
The soil horizon names are:
O horizon: This is the organic layer consisting of accumulating plant litter and decomposing organic matter.
A horizon: This is the top soil consisting of mineral material mixed with organic matter. It has the highest concentration of organic matter.
B horizon: This is the subsoil consisting of predominantly mineral material. It has less organic matter than the A horizon.
C horizon: This consists of weathered bedrock with accumulated mineral material. It contains few organic materials.
R horizon: This is the unweathered bedrock material beneath the soil layers.
So each soil layer is named according to its composition and properties using horizon names from O to R
Provide a claim, evidence and reasoning.
The wavelength can be directly read off from the graph as the number of crests or trough and that helps me to determine the wave energy since the energy is inversely related to wavelength.
Can the wavelength be seen directly from the wave graph?The wave graph clearly shows the wavelength of a wave. The space between two successive wave peaks or troughs is known as the wavelength. It is commonly measured in meters or equivalent units of length and is denoted by the sign (lambda).
The wavelength can be calculated from a wave graph by measuring the separation between two adjacent peaks or troughs.
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Light travels through space at a speed of 3.0 x 108 m/s. A space probe is
traveling toward Earth at 2.5 * 108 m/s when one of its spotlights is turned
on. What speed would an observer on Earth measure for the light from the
spotlight?
O A. 2.5 * 108 m/s
O B. 3.0 x 108 m/s
O c. 5.5 x 108 m/s
O D. 0.5 x 108 m/s
Explanation:
The answer is (B). The speed of light is the same for all observers regardless of their motion relative to the light source.
The speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
The given data in the problem is;
The speed of light is, \(\rm C =3 \times 10^8\ m/sec\)
All frames of reference have the same speed of light in a vacuum. Therefore the speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
Hence option B is correct.
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Find the unit tangent vector t(t) at the point with the given value of the parameter t. r(t) = 8 t i 2t2 j 2t k, t = 1
The unit tangent vector t(1) at t = 1 is (8 i + 4 j + 2 k) / (2 √(21)).
To find the unit tangent vector, we need to take the derivative of the position vector r(t) with respect to t, and then normalize the resulting vector.
Given: r(t) = 8t i + 2t² j + 2t k, t = 1
First, let's find the derivative of r(t) with respect to t.
r'(t) = 8 i + (4t) j + 2 k
Now, substitute t = 1 into r'(t) to find the derivative at t = 1.
r'(1) = 8 i + (4 * 1) j + 2 k
= 8 i + 4 j + 2 k
Next, to find the unit tangent vector t(t), we need to normalize r'(1) by dividing it by its magnitude.
The magnitude of a vector is found using the formula: ||v|| = √(v1² + v2² + v3²)
Let's calculate the magnitude of r'(1):
||r'(1)|| = √((8)² + (4)² + (2)²)
= √(64 + 16 + 4)
= √(84)
= 2 √(21)
Finally, to find the unit tangent vector t(t), we divide r'(1) by its magnitude:
t(1) = r'(1) / ||r'(1)||
= (8 i + 4 j + 2 k) / (2 √(21))
Therefore, the unit tangent vector t(1) at t = 1 is (8 i + 4 j + 2 k) / (2 √(21)).
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(378-21) Conductors larger than that for which the wireway is designed shall be permitted to be installed in any wireway.(True/False)
false. According to NEC 378.21, conductors larger than the maximum size permitted by the wireway shall not be installed in the wireway.
This is because conductors that are too large can cause overheating and damage to the wireway, as well as potentially create a fire hazard.According to NEC 378.21, conductors larger than the maximum size permitted by the wireway shall not be installed in the wireway It is important to follow the manufacturer's instructions and guidelines for wireway installation and ensure that the conductors being installed are within the maximum size limits specified. Additionally, it is important to consider the ampacity and temperature ratings of the conductors to ensure they are appropriate for the intended application. Conductors that are too small may also create a hazard by overheating and causing a fire. Therefore, it is essential to choose the appropriate conductor size and follow all applicable codes and standards to ensure safe and reliable electrical installations.
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Wheel and Axle
Give reasons for the following.
a. Handles of metal cutters are made long.
b. String roller is an example of wheel and axle.
c. Winding roads are made on slopes.
d. A shovel is the third class lever.
e. Wedge is called a simple machine.
37
Answer:Handles of metal cutters are made long.
Explanation:
The gas-phase reaction between nitrogen and oxygen was carried out in a device designed to maintain constant pressure. There are two cylinders of equal volume with a reaction arrow between them. The cylinder on the left has two molecules of O 2 and two molecules of N 2. The cylinder on the right has four molecules of N O. A constant pressure is applied to both cylinders Write the balanced chemical equation for the reaction between nitrogen oxygen. Include physical states.
Answer:
2N₂(g) + 2O₂(g) ----> 2NO(g)
Explanation:
Gaseous nitrogen and gaseous oxygen reacts in a molar volume ratio of 1 : 1 to produce nitrogen (ii) oxide.
In the reaction, two molecules of nitrogen gas combines with two molecules of oxygen gas in the cylinder to form two molecules of nitrogen (ii) oxide. The equation of the reaction is given below:
2N₂(g) + 2O₂(g) ----> 2NO(g)
Nitrogen (ii) oxide is formed naturally during lightning bolts. The heat released the lightning flashes causes the nitrogen and oxygen in air to combine to form nitrogen (ii) oxide. The nitrogen (ii) oxide formed however, quickly reacts with more oxygen to form nitrogen(ii) oxide.
Nitrogen (ii) oxide is a colorless, poisonous gas. It is slightly denser than air and almost insoluble in water. it is also neutral to litmus.
The balanced chemical equation for the reaction between nitrogen and oxygen is:
2N₂(g) + 2O₂(g) —> 4NO(g)
The equation between nitrogen and oxygen can be written as follow:
N₂(g) + O₂(g) —> NO(g)
The above equation can be balance as illustrated below:
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before NO as shown below:
N₂(g) + O₂(g) —> 2NO(g)
Multiply the equation by 2, we have:
2N₂(g) + 2O₂(g) —> 4NO(g)The equation is balanced!
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g A person is on a swing tied to a long rope. When she swings back and forth, it takes 12 s to complete one back and forth motion no matter the distance from one side to the other. 9. Why does it always take 12 s and how long is the rope
The motion of a swing is a periodic motion, that means it takes one period for a back and forth motion, which is constant. Here it is 12s, so it will take 12s for a back and forth motion, no matter the distance. The length of the rope in the given case is 11.8m
What is periodic motion?
The motion of a swing is a periodic motion that goes back and forth. The time it takes to complete one back and forth motion is called the period. In this case, the period of the swing is 12 s, which means it takes 12 s to swing from one side to the other and back again, no matter the distance.
The length of the rope affects the distance the swing travels, but not the period of the motion. This is because the period only depends on the gravitational force acting on the swing and the length of the rope, not on the distance traveled.
To determine the length of the rope, we need to know the distance the swing travels in one back and forth motion. Let's assume that the swing travels a distance of 4 meters from one side to the other. This means that the total distance traveled in one back and forth motion is 8 meters.
The period of the motion is given by the formula T=2π√(L/g), where T is the period, L is the length of the rope, and g is the acceleration due to gravity. We know that T=12 s and g=9.81 m/s². Substituting these values into the formula, we get:
12=2π√(L/9.81)
Squaring both sides and rearranging, we get:
L=(12/π)²×9.81/4
L=11.8 meters (approximately)
Therefore, the length of the rope is approximately 11.8 meters.
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PLEAS HELPM ME FASTTT MARKING PERIOD IS ABOUT TO END.
Most areas have two high and two low tides each day, this is called ___________.
Question 2 options:
gravity
semi-diurnal
low tide
Answer:
the answer is semidiurnal
Answer:
I think it is semi-diurnal :)
Hope this helps!!
Have a great day!!
Please rate and mark brainliest!!
A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
9.1 × 10–5 m/s
1.3 × 10–4 m/s
7.6 × 103 m/s
1.1 × 104 m/s
Answer:
the correct answer is D
Explanation:
A 60 watt light bulb runs for 5 seconds. How much energy does
it use?
Iwill need to use more force to stopa
O Lighter mass
O Heavier mass
Answer:
a heavier mass
Explanation:
cords of connective tissue that connect MUSCLES TO BONES
Answer:
Tendon
Explanation:
Tendons are a type of connective tissue that attach muscle to bone. Hope this helps! :)
How much work is done by an engine to accelerate an
800 kg vehicle from 10 m/s to 20 m/s?
We are unable to directly determine the work performed by the engine because the distance over which the force acts is unknown.
What work is involved in accelerating an 800 kg automobile from 5 meters per second to 10 meters per second?This indicates that the effort expended to increase the car's speed will be equivalent to the change in kinetic energy of the vehicle. Thus, 30 kJ of effort must be performed.
What is the recipe for getting stuff done?The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.
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The table summarizes the known values for a completely elastic collision. Given the information, what is the mass of ball 2?
Therefore, the mass of ball 2 is approximately 24.7 kg.
What is collision?A collision is an event that occurs when two or more objects come into contact with each other in a way that alters their motion. In physics, collisions are studied in terms of the conservation of momentum and the conservation of kinetic energy. In an elastic collision, the total kinetic energy of the system is conserved, and the objects bounce off each other without any loss of energy. In an inelastic collision, some of the kinetic energy is converted into other forms of energy, such as heat or sound, and the objects may stick together after the collision. Collisions can be categorized into two types: head-on collisions and oblique collisions. In a head-on collision, the objects approach each other directly from opposite directions, while in an oblique collision, the objects approach each other at an angle. Collisions are an important concept in physics and have applications in fields such as engineering, transportation, and sports. Understanding the principles of collisions can help us design safer cars, improve the performance of athletic equipment, and develop new technologies for space exploration.
Here,
We can use the conservation of momentum and the conservation of kinetic energy to solve for the mass of ball 2 in the completely elastic collision. Using the conservation of momentum:
m1v1i + m2v2i = m1v1f + m2v2f
Substituting the known values:
(6.7 kg)(2.0 m/s) + m2(-5.0 m/s) = (6.7 kg)(-6.18 m/s) + m2(0.83 m/s)
Simplifying and solving for m2:
(13.4 - 33.9) kg·m/s = -44.006 kg·m/s + 0.83 m2
-20.5 kg·m/s = 0.83 m2
m2 = (-20.5 kg·m/s) / (0.83 m/s)
m2 ≈ 24.7 kg
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After rubbing the hair on your head with a balloon, you determine there are 2.4 x 1018 electrons on your head. What is the charge, in coulombs (C), of your head?
Answer:
q = 0.384 C
Explanation:
The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:
\(q = ne\)
where,
q = total charge on head = ?
n = total no. of electrons on the head = 2.4 x 10¹⁸
e = charge on 1 electron = 1.6 x 10⁻¹⁹ C
Therefore,
\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)
q = 0.384 C
1. Defibrillator machines are used to deliver an electric shock to the human heart in order to resuscitate an otherwise non-
beating heart. It is estimated that a current as low as 18 mA through the heart is required to resuscitate. Using 200,000 £2
as the overall resistance, determine the output voltage required of a defibrillating device.
The output voltage required of a defibrillating device will be 1700 V.
What is ohm’s law?Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
Given data;
I = 17 mA=17×10⁻³ A
R = 1×10⁵ ohm
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law
V=IR
V =17×10⁻³ A× 1×10⁵ ohm
V = 17 × 10²
V = 1700 V
Hence,the output voltage required of a defibrillating device will be 1700 V
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Choose whether the statements below are true or false
Answer:
1. false 2.true 3. true
Explanation:
there was more scientific method and more ways to solve
the hypothesis show the experiment design
what will be the final kinetic energy if the velocity of a body is halved keeping mass constant
Answer:
Kinetic energy of the body
\(K.E = \frac{1}{2}mv {}^{2}\)
So, K.E∝ v²
If speed of the body is halved, its kinetic energy is reduced by a factor of 4.
A ball is thrown straight up in the air with a velocity of 12 m/s. Find the maximum height the ball reaches.
Show your work
Answer:
7.35 m
Explanation:
We can solve with kinematics or with energy.
Using kinematics, given:
v₀ = 12 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (12 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 7.35 m
Using energy instead:
PE = KE
mgh = ½ mv²
gh = ½ v²
h = v² / (2g)
h = (12 m/s)² / (2 × 9.8 m/s²)
h = 7.35 m
A car goes from 0 to 26.8 m/s in 6.2 s. What is the average acceleration of the car?
Answer:
0 - 60 mph = 0 - 26.8 m/s = 0 - 96.6 km/h; 0 - 100 km/h = 0 - 27.8 m/s = 0 - 62.1 mph.
Explanation:
give to examples of electrical energy being transformed into light?
Answer:
A lightbulb is connected to an outlet that has a source of electricity. The electrical energy is converted into light energy to allow the bulb to glow.
Explanation: Lightning is a discharge of static electricity. The lightning bolt lights up the sky.
If an object experienced an impulse when a large force was applied what does that indicate about the length of time the force was applied
how many grams is 1dg?
Answer:
Oh, I didn't know if u meant decigram or decagram! So for decagram there would be 10 grams and deci gram is 0.1 grams. Hope this helps!!
Explanation:
Answer:
Hey there!
There are 10 grams in one decagram.
Let me know if this helps :)
A small metal sphere has a mass of 0.19 gg and a charge of -23.0 nCnC. It is 10.0 cmcm directly above an identical sphere that has the same charge. This lower sphere is fixed and cannot move. If the upper sphere is released, it will begin to fall.What is the magnitude of its initial acceleration?
Answer:
a = -7.29 m / s²
Explanation:
For this exercise we must use Newton's second law,
F -W = m a
Force is electrical force
F = k q₁ q₂ / r²
k q₁ q₂ / r² -mg = m a
indicate that the charge of the two spheres is equal
q₁ = q₂ = q
a = (k q² / r² - m g) / m
a = k q² / m r² - g
Let's reduce the magnitudes to the SI system
m = 0.19 g (1kg / 1000 g) = 1.9 10⁻⁴ kg
q1 = q2 = q = -23.0 nC (1C / 10⁹ nC) = -23.0 10⁻⁹ C
r = 10.0 cm (1m / 100cm) = 0.1000 m
let's calculate
a = 9 10⁹ (23.0 10⁻⁹)² / (0.1000² 1.9 10⁻⁴) - 9.8
a = -7.29 m / s²
The negative sign indicates that the direction of this acceleration is downward
The original pressure of a gas was 2.5 atmospheres. When the pressure was decreased to 1.7 atmospheres, the volume increased to 850 mL. What was the original volume? Make sure that you show your work and use the proper units.
Taking into account the Boyle's law, the original pressure of a gas was 2.5 atmospheres and the original volume was 578 mL.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. This is because when the volume decreases, the distance that the particles have to travel is less and therefore more shocks occur in each unit of time, that is, the pressure increases.
Mathematically, if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:
P×V= k
where:
P is the pressure.V is the volume.k is a constant.Being an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁= P₂×V₂
Original volumeIn this case, you know:
P₁= 2.5 atmV₁= ?P₂= 1.7 atmV₂= 850 mLReplacing in Boyle's law:
2.5 atm ×V₁= 1.7 atm ×850 mL
Solving:
V₁= (1.7 atm ×850 mL)÷ 2.5 atm
V₁= 578 mL
The original volume was 578 mL.
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3. A 20 N force pushes a cart. That cart accelerates at a rate of 10 m/s/s. What will the acceleration of the
cart be if the MASS is doubled?
Answer:
5m/s
Explanation:
M = f/a
M = 20/10
M = 2Kg
If mass is is doubled, (4kg), the acceleration will be one half of its original value if the force applied is the same (20N) .
a = f/m
a = 20/4
a = 5m/s
If a ball is kept on a table then there is gravity acting on it as well as a normal reaction force by the table on the ball. But as both the forces are being exerted on the same object i.e. the ball, then it cannot be called a- action reaction pair under Newton's third law of motion because it requires the forces acting on two different bodies.
So, if it is not an action reaction pair, then how is any force being exerted by the table on the ball? Also, is the ball applying any force on the table?
Yes, you are correct that a ball placed on a table is not an example of Newton's Third Law action-reaction pair because the two forces are being applied to the same object. The normal reaction force from the table on the ball is an example of a contact force.
This contact force is generated because the table and the ball are in contact with each other, and the table is exerting an outward force on the ball. At the same time, the ball is also exerting an inward force on the table, resulting in a normal reaction force from the table.
This is the force which is preventing the ball from falling through the table.
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Consider two spinning tops with different radii. Both have the same linear instantaneous velocities at their edges. Which top has a smaller angular velocity? the top with the smaller radius because the radius of curvature is inversely proportional to the angular velocity the top with the smaller radius because the radius of curvature is directly proportional to the angular velocity the top with the larger radius because the radius of curvature is inversely proportional to the angular velocity The top with the larger radius because the radius of curvature is directly proportional to the angular velocity
Answer:
the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity
Explanation:
Angular and linear velocity are related
v = w r
w = v / r
Therefore, if the linear velocity of the two is the same, the one with the smaller radius has the higher angular velocity.
When reviewing the answers, the correct one is:
the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity
The top that has a smaller angular velocity is D. the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.
It should be noted that the top that has a higher angular velocity will be the top with the smaller radius because the radius of curvature is inversely proportional to the angular velocity
On the other hand, since the two spinning tops have different radii while both have the same linear instantaneous velocities at their edges, then the top that has a smaller angular velocity is the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.
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