A reversible reaction is said to be in equilibrium when
A)
all reactions stop leaving some reactant unused.
B)
the reaction goes to completion and no reactants are left.
9)
the rate of the backward reaction equals the rate of the forward reaction.
D)
the reaction rate of the backward reaction becomes larger than the rate of
the forward reaction.

Answer:

D

Explanation:

Answer:

D

Explanation:

1000 mL = 1 L

so

1000 × 4.6 = 4600

Answer:

20ml

Explanation:

using the formula;C1V1=C2V2

2.5×V1=0.2×250

2.5V1= 50

V1=50/2.5

V1=20L

Option D.  Investigation 4, represents the statement from which investigation is an example of repetition.

Each is a repeated run of your combination of things and stages. Repetition does the replica runs consecutively even as replication does more than one run but throughout identical but special experimental runs. The investigation is a radical search for data, particularly the ones which are hidden or need to be sorted out in a complicated state of affairs. The intention of the research is commonly to decide how or why something befell.

Experimental investigations contain a procedure in which a "honest test" is designed and variables are actively manipulated, managed, and measured which allows you to collect proof to aid or refute a causal courting.

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Disclaimer:- your question is incomplete, please see below for the complete question.

The molar mass of the gas, given that 3.25 g of the gas occupied 2.56 L is 30.66g/mol

To obtain the molar mass of the gas, we shall first obtain the number of mole of the gas. This can be obtained as follow:

PV = nRT

0.95 × 2.56 = n × 0.0821 × 280

Divide both sides by (0.0821 × 280)

n = (0.95 × 2.56) / (0.0821 × 280)

n = 0.106 mole

Haven obtain the mole of the gas, we shall determine the molar mass of the gas as follow:

Molar mass = mass / mole

Molar mass of gas = 3.25 / 0.106

Molar mass of gas = 30.66g/mol

Thus, the molar mass of the gas is 30.66g/mol

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To make a crucible for melting sodium (Na), metals that would be most suitable for that purpose are inert metals or metals like alumina.

inert metals are those metals that do not react with other highly reactive metals or in the atmosphere due to the absence of one free electron in the outermost orbital.

The sodium metal is kept in the crucible of the inert metal like alumina because sodium has one free electron in the outer shell and catches fire as come into the contact with the air.

Therefore, to make a crucible for melting sodium (Na), metals that would be most suitable for that purpose are inert metals or metals like alumina.

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Answer: 205000000 microliter

Hope this helps!

Answer:

2.05 x 10⁸ uL

205000000 uL

Explanation:

Step 1: Find the conversion

1 liter (L) = 1 x 10⁶ microliters (uL)

Step 2: Set up dimensional analysis

\(205 L(\frac{1(10)^6uL}{1L} )\)

Step 3: Multiply and cancel out units

Liters and Liter cancel out.

We are left with uL

205(1 x 10⁶) = 2.05 x 10⁸ uL or 205000000 uL

The concentration of A and B after 80 s  if the initial concentration of ab is 0.260 m, and the reaction mixture initially contains no products is 0.0091 M.

To find the concentrations of A and B after 80 s, we must write the kinetic data is given as follows for the reaction:

AB ⟶ A + B

Initial rate of the reaction is 1.62 x 10⁻³ mol/L/s

Order of reaction for AB is first order (n = 1). Now, using the first-order rate equation, the concentration of AB at time t, [AB]t can be calculated as follows:

ln [AB]0/[AB]t = k

tHere, [AB]0 is the initial concentration of AB, [AB]t is the concentration of AB at time t, k is the rate constant, and t is the time interval.

To determine the rate constant, we can use the initial rate of reaction.

Initial rate, ri = k[AB]n

Here, n is the order of reaction.

So, k = ri/[AB]n

Substituting the given values:

ri = 1.62 x 10⁻³ mol/L/s[AB]0

= 0.260 mk = ri/[AB]n

= 1.62 x 10⁻³ mol/L/s / (0.260 m)1

= 6.23 s-1

Now, we can use the rate constant to determine the concentration of AB at 80 seconds:

ln [AB]0/[AB]80 = kt

Here, k = 6.23 s-1, [AB]0 = 0.260 m, and t = 80 s.

Substituting the values:

ln (0.260 m)/[AB]80

= (6.23 s-1) (80 s)[AB]80

= [AB]0 e-kt

= (0.260 m) e-(6.23 s-1) (80 s)

= 0.0091 m

Now, since the stoichiometry of the reaction is 1:1, the concentration of A and B will be equal to each other. Therefore, [A]80 = [B]80 = 0.0091 m.

Thus, the final concentrations of A and B are 0.0091 M after 80 seconds.

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Answer:

A balanced equation is a chemical equation where there are equal numbers of atoms of each element on both sides of the equation.

A chemical equation that has a equal amount of each

each element on the left and right sides

When you get into a car that has been sitting in the sun for a while, there are several noticeable things that may occur. Here are some of the common observations:

1. Heat: One of the first things you'll notice is the intense heat inside the car. This is because the sun's rays have been absorbed by the car's exterior and trapped inside, creating a greenhouse effect. The temperature inside the car can become significantly higher than the temperature outside.

2. Hot Surfaces: The surfaces inside the car, such as the seats, dashboard, steering wheel, and metal parts, can become extremely hot to the touch. This is due to the absorption of heat from the sun. It's important to be cautious and avoid direct contact with these hot surfaces to prevent burns or discomfort.

3. Odor: The interior of the car may have a distinct smell when it has been sitting in the sun for a while. This is often referred to as the "hot car smell." It is caused by the combination of materials, such as upholstery, plastic, and carpet, heating up and emitting a specific odor.

4. Fading or Discoloration: Prolonged exposure to sunlight can cause fading or discoloration of materials inside the car. For example, the upholstery, dashboard, and other surfaces may gradually lose their original color and become faded or discolored over time.

5. Glare: When you first enter a car that has been sitting in the sun, you may notice a strong glare from the sunlight reflecting off the windshield and other glass surfaces. This glare can make it difficult to see clearly and may require the use of sunglasses or adjusting the sun visors to minimize the brightness.

It's important to note that these observations may vary depending on factors such as the intensity of the sunlight, the duration the car has been in the sun, and the materials used in the car's interior. Regular maintenance and taking precautions, such as using sunshades or parking in shaded areas, can help minimize some of these effects.

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The approximate volume of a 0.120 M solution that contains 10.0 g of copper(II) sulfate, CuSO4 is 522.14mL.

Volume = no. of moles ÷ molarity

The no. of moles of CuSO4 = 10g ÷ 159.61g/mol = 0.063mol

Volume = 0.063 ÷ 0.120

Volume = 0.522L

Volume in milliliters = 522.14mL

Therefore, the approximate volume of a 0.120 M solution that contains 10.0 g of copper(II) sulfate, CuSO4 is 522.14mL.

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Answer:

An exact number is a value that is known with complete certainty. Like for Examples of exact numbers are counted numbers of objects or certain unit conversions. For example, there are exactly 3 feet in 1 yard. There are exactly 12 eggs in a dozen. A class may contain exactly 25 students.

Explanation:

Hope this helps.

Have a good night ma´am/sir.

Be safe!

Answer:

Explanation:

False but I could be wrong but I’m pretty sure.

Answer:

False.

Explanation:

 An ion has an imbalanced number of protons and electrons. Hope this helps! =)

Answer:

(c) only solute present

Explanation:

In chemistry, the mole fraction, denoted by X, refers to the number of moles of a substance in a compound/mixture divided by the total number of substances in the same compound or mixture.

In this case, we can say that mole fraction represents the number of solutes to the number of solutes and solvent in the solution i.e. X = nA/nA + nB

Where; nA = number of solutes

nB = number of solvent

X = mole fraction.

Based on this analogy, When the mole fraction of solute is 1, there is only solute present. That is; X = 1 / 1 + 0

X = 1/1 = 1.

The reaction of 5.50 g of carbon with excess o2 yields 13.7 g of co2. The percent yield of this reaction is  58.75%

To find the percentage yield of 5.50 grams of ethyl butyrate:

Percentage yield= (actual yield/Theoretical yield)*100

so we find Theoretical yield

Butanoic acid has a molecular weight of 88 g/mol.

Ethyl butyrate's atomic weight (molecular weight) is 116 g/mol.

The 7.10 grammes of butanoic acid are completely consumed by the chemical process because we are anticipating a yield of 100 percent.

Therefore, we would calculate the amount of butanoic acid used in moles:

Number of moles= mass/molar mass

Number of moles =7.10/88

                             =0.0807moles

The amount of ethyl butyrate that would result from this chemical reaction would then be calculated:

Ethyl butyrate is equal to 1 mole of butanoic acid.

Ethyl butyrate is equal to 0.0807 moles of butanoic acid.

Mass= Number of molar mass* mass

        =0.0807*13.7

        9.361grams

so percentage yield=  (actual yield/Theoretical yield)*100

                                =(5.50/9.361)*100

                                =58.75%

Percent yield = 58.75%

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Answer:

Fatty Acids

A lipid is an organic compound such as fat or oil. Organisms use lipids to store energy, but lipids have other important roles as well. Lipids consist of repeating units called fatty acids. Fatty acids are organic compounds that have the general formula CH3(CH2)nCOOH" role="presentation" style="display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 17.6px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">CH3(CH2)nCOOHCH3(CH2)nCOOH, where n" role="presentation" style="display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 17.6px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">nn usually ranges from 2 to 28 and is always an even number. There are two types of fatty acids: saturated fatty acids and unsaturated fatty acids.

Saturated Fatty Acids

In saturated fatty acids, carbon atoms are bonded to as many hydrogen atoms as possible. This causes the molecules to form straight chains, as shown in the figure below. The straight chains can be packed together very tightly, allowing them to store energy in a compact form. This explains why saturated fatty acids are solids at room temperature. Animals use saturated fatty acids to store energy.

Figure 14.2.1" role="presentation" style="display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 16px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">14.2.114.2.1: Structures of saturated and unsaturated fatty acids.

Unsaturated Fatty Acids

In unsaturated fatty acids, some carbon atoms are not bonded to as many hydrogen atoms as possible due to the presence of one or more double bonds in the carbon chain. Instead, they are bonded to other groups of atoms. Wherever carbon binds with these other groups of atoms, it causes chains to bend (see figure above). The bent chains cannot be packed together very tightly, so unsaturated fatty acids are liquids at room temperature. Plants use unsaturated fatty acids to store energy.

Figure 14.2.2" role="presentation" style="display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 16px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">14.2.214.2.2: Saturated fatty acids have only single bonds while monounsaturated fats have one double bond and polyunsaturated fats have more than one double bond.

Lipids and Diet

Unsaturated fat is generally considered to be healthier because it contains fewer calories than an equivalent amount of saturated fat. Additionally, high consumption of saturated fats is linked to an increased risk of cardiovascular disease. Some examples of foods with high concentrations of saturated fats include butter, cheese, lard, and some fatty meats. Foods with higher concentrations of unsaturated fats include nuts, avocado, and vegetable oils such as canola oil and olive oil.

Fructose is a simple carbohydrate sugar, while triglycerides are the lipids or the fats of the body. Thus, option C is accurate.

Triglycerides are lipids of the body that are formed of fatty acids and glycerols. It makes the body fat of the animals and of the plants. They are stored in cells for future use and provide energy when needed.

Fructose is a monomer that is the simplest carbohydrate sugar and is generally found in sugarcane, honey, watermelon, grapes, apples, etc.

Therefore, option C. fructose is sugar and triglyceride is fat is correct.

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Carbon monoxide (CO) primarily enters the body through inhalation. When carbon-based fuels such as gasoline, coal, natural gas, or wood are burned, they can produce carbon monoxide gas. Breathing in air that contains carbon monoxide allows the gas to enter the respiratory system.

Once inhaled, carbon monoxide enters the bloodstream through the lungs. It has a high affinity for hemoglobin, the protein in red blood cells responsible for carrying oxygen. Carbon monoxide binds to hemoglobin more readily than oxygen, forming carboxyhemoglobin. This prevents oxygen from binding effectively to hemoglobin and reduces the oxygen-carrying capacity of the blood.

From the bloodstream, carbon monoxide is distributed throughout the body, affecting various organs and tissues. It can cross the blood-brain barrier and bind to the hemoglobin in brain cells, leading to oxygen deprivation and potential neurological damage. Carbon monoxide can also impact the cardiovascular system, impairing the delivery of oxygen to vital organs.

It is important to note that carbon monoxide can enter the body through other routes as well, although to a lesser extent. Ingesting or absorbing carbon monoxide is possible but less common compared to inhalation. Inhalation of carbon monoxide is the primary and most significant route of entry.

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If a person has the values for an object's density and volume, they can calculate the object's mass. Hence option B) is correct.

If a person has the values for an object's density and volume, they can calculate the object's mass. Density is defined as the mass per unit volume of an object. Mathematically, density is calculated by dividing the mass of an object by its volume. Rearranging the equation, we find that mass is equal to the product of density and volume. Therefore, if the density and volume of an object are known, multiplying them together will yield the object's mass. The other options mentioned in the question are not directly calculated using density and volume. The object's size is a broader term that encompasses various dimensions and may not be specifically derived from density and volume alone. The shape the object forms in a container and the amount of space the object takes up are influenced by both the object's mass and its dimensions, which are not solely determined by density and volume. Therefore option B) is correct.

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Answer:

c. side chain

Explanation:

c. side chain. The variable part of an amino acid, which is the unique chemical structure that distinguishes one amino acid from another, is the side chain (also known as R-group).

The side chain, commonly referred to as the R-group, is the variable component of an amino acid and the particular chemical structure that sets one amino acid apart from the others. Each amino acid shares the same fundamental structure, which consists of a core alpha carbon atom bound to a hydrogen atom, an amino group (NH₂), an acid group (COOH), and an amino group (NH₂). The particular collection of atoms connected to the core carbon is known as the side chain, and it differs amongst various amino acids. The amino acid's distinct characteristics and roles in protein synthesis and biological processes are determined by the side chain's make-up and structure.

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Answer:

Li3N

Explanation:

Li+N2=Li3N.........................

Answer:

4 Li(s)+O2(g) → 2 Li2O(s)

Explanation:

its right

Initially, there are approximately 29.38 moles of oxygen gas in the tank. approximately 12.85 moles of oxygen were released from the tank.

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas.

First, let's convert the given temperatures to Kelvin by adding 273 to the Celsius temperatures:

Initial temperature (T1) = 23°C + 273 = 296 K

Final temperature (T2) = 18°C + 273 = 291 K

We'll use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Finding the initial number of moles:

Using the given information, we have:

Initial pressure (P1) = 20.2 atm

Initial volume (V1) = 35 L

Initial temperature (T1) = 296 K

Using the ideal gas law, we can solve for the initial number of moles (n1):

P1V1 = n1RT1

n1 = (P1V1) / (RT1)

= (20.2 atm * 35 L) / (0.0821 L·atm/mol·K * 296 K)

≈ 29.38 moles

Therefore, initially, there are approximately 29.38 moles of oxygen gas in the tank.

Finding the final number of moles:

Using the given information, we have:

Final pressure (P2) = 12.5 atm

Final temperature (T2) = 291 K

Using the ideal gas law, we can solve for the final number of moles (n2):

P2V1 = n2RT2

n2 = (P2V1) / (RT2)

= (12.5 atm * 35 L) / (0.0821 L·atm/mol·K * 291 K)

≈ 16.53 moles

Therefore, after the release of some oxygen gas, there are approximately 16.53 moles of O₂ remaining in the tank.

Finding the moles of oxygen released:

The moles of oxygen released can be calculated by subtracting the final number of moles (n2) from the initial number of moles (n1):

Moles released = n1 - n2

≈ 29.38 moles - 16.53 moles

≈ 12.85 moles

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Answer:nucleus protons nuetrons electrons

Explanation:

The smallest partical into which an element can be divied and still be the smallest element

.( A basic unit o f matter)

Answer:

Nucleus, electrons, and protons

Explanation:

Multiple experiments and results accumulated over the years. Dalton is credited through his ray cathode tube experiments, and Rutherford's Gold Foil experiment led to the discovery of the positively charged nucleus and protons. His student Chadwick continued his studies and discovered the neutron.

Answer:

Explanation: 30 min

Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, to improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

(a) Direct expansion systems are those in which the refrigerant in the evaporator evaporates directly into the space to be cooled or frozen. The evaporator superheat is used to make sure that only vapor and no liquid is carried over into the suction line and compressor. Superheating is required for the following reasons :

(b) Forced draft and induced draft evaporators differ in the way air is introduced into them. In an induced draft evaporator, a fan or blower is positioned at the top of the evaporator, and air is drawn through the evaporator from the top. In a forced draft evaporator, air is propelled through the evaporator by a fan or blower that is located at the bottom of the evaporator. Forced draft evaporators are frequently used in direct expansion systems because they allow for better control of the air temperature. Because the air is directed upward through the evaporator and out of the top, an induced draft evaporator is less effective at keeping the air at a uniform temperature throughout the evaporator.

(c) (i) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant.

(ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant.

(iii) H2O is not classified as a refrigerant.

(d) The function of hydrogen gas in an absorption refrigeration system (NH3/H2O/H2) is to increase the heat of reaction between ammonia and water.

The pressure of hydrogen gas in the evaporator of an absorption refrigeration system can be determined using the formula, Pa/Pb = (Ta/Tb)^(deltaS/R),

where Pa = partial pressure of hydrogen in the evaporator, Ta = evaporating temperature, Tb = condensing temperature, Pb = partial pressure of hydrogen in the absorber, deltaS = entropy change between the absorber and evaporator, R = gas constant.

Substituting the given values, Ta = −2.0 ∘C = 271 K ; Tb = 38.0 ∘C = 311 K ; Pb = atmospheric pressure = 1 atm ;

deltaS = 4.7 kJ/kg K ; R = 8.314 kJ/mol K

we get, Pa/1 atm = (271/311)^(4.7/8.314)

Pa = 0.021 atm or 1.6 mmHg

Therefore, the partial pressure of hydrogen in the evaporator is 1.6 mmHg.

Thus, Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, o improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

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Answer:

They will have the same ear shape since their proteins connect in the same ways to determine ear shape.

Explanation:

I majored in Chemistry

Answer:

They will have the same ear shape since their proteins connect in the same ways to determine ear shape.

Explanation:

When performing a presumptive blood test with Hemastix, the reason why it necessary to test an unstained area close to the bloodstain under examination as a control is that the likelihood that there is presence of blood, and thus need confirmatory test in lab to know if it is actually blood.

Hemastix reagent strips were initially created for the purpose of detecting blood in urine. It has been determined that this quick and simple test is useful as a presumptive test for the presence of blood.

Note that the presence of a chemical in a sample can be determined or confirmed using a presumptive test, which is a qualitative study. These decisions are typically made following a chemical reaction that results in the production of a certain color. A false positive occurs when a different chemical reacts similarly and yields the desired outcome.

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The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the

Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.

James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.

This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.

Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.

Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.

In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.

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Answer:

C) creating a relationship between mass and volume

g/L

g or gram is mass

L or Litres is for volume

Answer:

synthesis reaction

Explanation:

A + X --> AX

Answer:

Combustion reaction

Explanation: