The resulting test statistic will indicate how many standard errors the sample mean is away from the hypothesized mean. A larger absolute value of the test statistic suggests stronger evidence against the null hypothesis.
To find the test statistic, we can use the formula for the t-statistic:
t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))
In this case, the hypothesized mean is 7 hours, the sample mean is 6.01 hours, the sample standard deviation is 8.96 hours, and the sample size is 617.
Substituting these values into the formula, we get:
t = (6.01 - 7) / (8.96 / sqrt(617))
Calculating this expression will give us the test statistic.t = (6.01 - 7) / (8.96 / sqrt(617))
Calculating the numerator:
(6.01 - 7) = -0.99
Calculating the denominator:
(8.96 / sqrt(617)) ≈ 0.360
Therefore, the test statistic (t) is approximately:
t ≈ -0.99 / 0.360 = -2.75
The test statistic is -2.75.
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Aiden invested $43,000 in an account paying an interest rate of 9 1/4 % compounded monthly. Hailey invested $43,000 in an account paying an interest rate of 8 7/8% compounded continuously. To the nearest dollar, how much money would Aiden have in his account when Hailey's money has doubled in value?
first off let's change the mixed fractions to improper fractions, and let's Hailey's account first.
\(\stackrel{mixed}{9\frac{1}{4}}\implies \cfrac{9\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{37}{4}} ~\hfill \stackrel{mixed}{8\frac{7}{8}}\implies \cfrac{8\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{71}{8}} \\\\[-0.35em] ~\dotfill\)
\(~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &\stackrel{43000(2)}{\$86000}\\ P=\textit{original amount deposited}\dotfill & \$43000\\ r=rate\to \frac{71}{8}\%\to \frac{~~ \frac{71}{8}~~}{100}\dotfill &0.08875\\ t=years \end{cases} \\\\\\ 86000=43000e^{0.08875\cdot t}\implies \cfrac{86000}{43000}=e^{0.08875t}\implies 2=e^{0.08875t}\)
\(\ln(2)=\ln(e^{0.08875t})\implies \log_e(2)=\log_e(e^{0.08875t})\implies \ln(2)=0.08875t \\\\\\ \cfrac{\ln(2)}{0.08875}=t\implies 7.81\approx t\)
ok, now we know how long it takes for Hailey's money to double, how much money does Aiden have by then?
\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$43000\\ r=rate\to \frac{37}{4}\%\to \frac{~~ \frac{37}{4}~~}{100}\dotfill &0.0925\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &\frac{\ln(2)}{0.08875} \end{cases}\)
\(A=43000\left(1+\frac{0.0925}{12}\right)^{12\cdot \frac{\ln(2)}{0.08875}}\implies A=43000\left( \frac{4837}{4800} \right)^{\frac{12\ln(2)}{0.08875}}\implies \boxed{A\approx 88311}\)
notice, in Hailey's amount we used the logarithmic value for "t", just to avoid any rounding issues.
help please asap . please explain your answer
Answer:
y = -6x + 2
Step-by-step explanation:
Slope intercept form: y = mx + b
m is the slope
b is the y-intercept
The line pictured goes down 6 for each 1 it moves to the right, slope is rise over run, in this case, -6/1 or just -6
The y-intercept is the point that the function crosses the y-axis, in this case 2
Plug those in to get:
y = -6x + 2
the life of light bulbs is distributed normally. the variance of the lifetime is 625 and the mean lifetime of a bulb is 520 hours. find the probability of a bulb lasting for at most 549 hours. round your answer to four decimal places.
Light bulbs is normally distributed with a variance of 625 and a mean lifetime of 520 hours, we need to calculate the cumulative probability up to 549 hours. The answer will be rounded to four decimal places.
Given a normally distributed lifetime with a mean of 520 hours and a variance of 625, we can determine the standard deviation (σ) by taking the square root of the variance, which gives us σ = √625 = 25.
To find the probability of a bulb lasting for at most 549 hours, we need to calculate the area under the normal distribution curve up to 549 hours. This can be done by evaluating the cumulative distribution function (CDF) of the normal distribution at the value 549, using the mean (520) and standard deviation (25).
The CDF will give us the probability that a bulb lasts up to a certain point. Rounding the result to four decimal places will provide the desired precision.
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The problem involves using normal distribution to find the probability of a given outcome. Using the Z-score, we can determine that the probability of a light bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%
Explanation:Given the mean (µ) of the lifetime of a bulb is 520 hours. Also, the variance (σ²) is given as 625. Thus, the standard deviation (σ) is the square root of the variance, which is 25.
To find the probability of a bulb lasting for at most 549 hours, we first calculate the Z score. The Z-score formula is given as follows: Z = (X - µ) / σ, where X is the number of hours, which is 549. So substitute the given values into the formula. Z = (549 - 520) / 25, the Z value is 1.16.
We then look up the Z-table to find the probability associated with this Z-score (1.16), which is approximately 0.8770. Therefore, the probability of a bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%.
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Amir solved the following equation. describe the first mistake he made.
2x-2=14
-2 -2
2x =12
2. 2
X=6
Answer:
he faked too much
Step-by-step explanation:
Jazmine can run 4 5/6 miles in 2/3 of an hour. How many miles can she run in 1 hour?
Answer: she can run \(6\dfrac54\) mile sin 1 hour.
Step-by-step explanation:
Given : Distance run by Jasmine in \(\dfrac23\) of an hour = \(4\dfrac56\text{ miles}=\dfrac{24+5}{6}\text{ miles}\)
\(=\dfrac{29}{6}\) miles
Distance run by Jasmine in 1 hour = \(\dfrac{29}{6}\times\dfrac{3}{2}=\dfrac{29}{4}\) miles.
\(=6\dfrac{5}{4}\) miles.
Hence, she can run \(6\dfrac54\) mile sin 1 hour.
Northside Middle School spent $1187.50 on
95 math books. How much did each book
cost?
Answer:
Each book cost $12.50 dollars.
Step-by-step explanation:
1,187.50 / 95 = 12.50
An automobile dealer finds that the total monthly revenue from the sale of x automobiles of a certain model is Rx= 10,000x³/²/2+√x
Find the marginal revenue MR(x)=R′(x)
Find MR(9).
1. Total revenue formula: Rx = 10,000x^(3/2)/(2+√x). 2. Marginal revenue formula: MR(x) = R′(x). 3. MR(9) calculation.
To find the marginal revenue (MR) and evaluate MR(9), we first need to understand the total revenue formula and how to calculate the derivative of this formula.
1. Total revenue formula (Rx):
The total monthly revenue from the sale of x automobiles of a certain model is given by:
Rx = 10,000x^(3/2)/(2+√x)
2. Marginal revenue formula (MR):
The marginal revenue (MR) is calculated by taking the derivative of the total revenue formula, Rx.
3. MR(9) calculation:
To find MR(9), we substitute x = 9 into the derivative formula of Rx.
Now, let's calculate the MR(9) step by step:
Step 1: Find the derivative of Rx:
To find the derivative, we need to apply the power rule and chain rule.
The derivative of Rx with respect to x is given by:
R′(x) = (d/dx) [10,000x^(3/2)/(2+√x)]
Step 2: Simplify the derivative:
To simplify the derivative, we can use the quotient rule and the power rule.
R′(x) = [10,000 * ((2+√x) * (3/2) * x^(1/2)) - (10,000 * x^(3/2) * (1/2) * (√x))] / (2+√x)^2
Simplifying further:
R′(x) = [15,000x^(3/2) + 5,000x - 10,000x^(3/2)√x] / (2+√x)^2
Step 3: Calculate MR(9):
Substitute x = 9 into the derivative formula.
MR(9) = [15,000(9)^(3/2) + 5,000(9) - 10,000(9)^(3/2)√9] / (2+√9)^2
Simplifying:
MR(9) = [15,000(27) + 5,000(9) - 10,000(27)√9] / (2+3)^2
MR(9) = [405,000 + 45,000 - 270,000] / 25
MR(9) = 180,000 / 25
MR(9) = 7200
Therefore, MR(9) = 7200.
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The sum of two numbers is 103. The smaller number is eleven less than the larger
number. What is the smaller number?
Answer:
The answer is 57 and 46
Step-by-step explanation:
I'll send a screenshot of the problem. I'd really like an answer, please do your best!
Answer:
a). $(725 - 22t)
b). $99
Step-by-step explanation:
Expense account of the school has balance after 't' weeks = $(450 - 70t)
And fundraising account has the balance = $(275 + 48t)
a). Total amount in both the accounts after 't' weeks
= $(450 - 70t) + $(275 + 48t)
= $(450 + 275) + $(-70t + 48t)
= $(725 - 22t)
b). Total amount after 8 weeks
= $(725 - 22×8)
= $(275 - 176)
= $99
The price of a train ticket to London from Lanchester in 1995 is £30 1996 is £40 1997 is £50 2000 is £60 Use simple index and calculate price index for the ticket for these four years with base year 2000.
The price index for a train ticket from Lanchester to London, using the base year 2000, can be calculated by dividing the price in each year by the price in the base year and multiplying by 100. The price index for 1995 is 50, for 1996 is 66.67, for 1997 is 83.33, and for 2000 (the base year) is 100.
To calculate the price index for a train ticket from Lanchester to London, we need to compare the prices in different years to a base year, which in this case is 2000. The formula for calculating the price index is (Price in Year / Price in Base Year) x 100.
For the year 1995, the price of the ticket is £30. Dividing this price by the price in the base year (2000), which is £60, gives us 0.5. Multiplying this by 100 gives a price index of 50.
For 1996, the ticket price is £40. Dividing by the base year price (£60) gives us 0.6667. Multiplying by 100 gives a price index of approximately 66.67.
Similarly, for 1997, the price index is 83.33, as the ticket price of £50 divided by the base year price (£60) gives us 0.8333 when multiplied by 100.
Lastly, for the base year 2000, the price index is 100, as it is the reference point and used as the denominator in the formula.
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According to the sliding filament model, which of these gets shorter during muscle contraction? (choose all that apply)
The required result of the sliding filament model given below.
What is the sliding filament model?The mechanism by which muscles contract is described by the sliding filament model. Actin and myosin myofilaments move over one another as a result of a cycle of repeated occurrences, constricting the sarcomere and creating tension in the muscle.
The A band is the middle, darkly pigmented area of the sarcomere that runs the entire length of the thick filaments. The portion of the thin filaments that cross over the thick filaments is also included. The I band is formed by the remaining thin filaments within the sarcomere but not by any thick filaments. Each A band has a narrow region in the middle called the H zone, which is made up entirely of dense filaments.
Myosin heads pull the thin filaments in the direction of the M line during muscle contraction. Because of this, the thin filaments glide inward, allowing their ends to overlap and connect at the sarcomere's core. The I band and H zone become smaller as a result.
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12(y+2 =6(2y+4 is that infinite,one or no solution
Answer:
one solution
Step-by-step explanation:
just did the same edge
Answer:
one solution
Step-by-step explanation:
12y+24=12y+28
12+12=24
28-24=4
24÷4=6
Thank you
Which of the following expressions has a result of zero????
0/(-4)
6/0
-11 + 11
0 . (-7)
-8 - (-8)
Answer:
A, C, D, E
Step-by-step explanation:
You want to identify the expressions that have a value of 0 among these:
0/(-4)6/0-11 + 110 · (-7)-8 - (-8)Zero product ruleA product is zero if and only if one of the factors is zero. That is the case for the expressions ...
0/(-4)0 · (-7)Additive inverseThe sum of a number and its additive inverse is zero. Another way to say this is that the difference between a number and itself is zero. That is the case for the expressions ...
-11 +11-8 -(-8)Help on all parts pls step by step preferably
Applying the inscribed angle theorem, we have:
a. x = 55° b. x = 60° c. x = 92° d. x = 84°
How to Apply the Central Angle Theorem and the Inscribed Angle Theorem?These theorem states that:
Inscribed angle measure = 1/2(central angle) or measure of intercepted arc.
Intercepted arc measure = central angle measure.
Therefore, we have:
a. x = 180 - 35 - 90 [tangent theorem]
x = 55°
b. x = 1/2(120) [inscribed angle theorem]
x = 60°
c. x = 2(46) [inscribed angle theorem]
x = 92°
d. m(FE) = 2(42) = 84°
m(EB) = 180 - FE = 180 - 84
m(EB) = 96°
m(AB) = 180 - m(EB) = 180 - 96
m(AB) = 84°
x = m(AB) = 84° [central angle theorem]
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Find angle x giving your answer to one decimal place
The value of angle x in decimal place is 57.8°.
What is decimal place?A decimal number's digits are assigned a place value according to a chart that displays decimal place values. A digit in a number's place value is, as far as we are aware, its numerical value. The correct placement of each digit in a decimal number is therefore determined using decimal place value charts, just like with other place value diagrams. In this chart, the place values of the digits before and after the decimal point are shown.
Draw the altitude of the triangle
We know that
sinθ = Opposite / Hypotenuse
sin 38° = y/11
y = 11 sin 38°
y = 6.77
sin(x) = y/8
sin(x) = 6.77/8
sin(x) = 0.84625
sin(x) = 57.8°
Thus, the value of angle x in decimal place is 57.8°.
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Solve for x. 9^x = sqrt 729 A.)1/4 B.)1/3 C.)3/4 D.)3/2 please help this is urgent!!!
Answer:
D
Step-by-step explanation:
Using the law of radicals/ exponents
\(\sqrt{a^{3} }\) ⇔ \(a^{\frac{3}{2} }\)
Consider the right side
\(\sqrt{729}\) = \(\sqrt{9^{3} }\) = \(9^{\frac{3}{2} }\)
Thus
\(9^{x}\) = \(9^{\frac{3}{2} }\)
Since the bases on both sides are equal, equate the exponents, so
x = \(\frac{3}{2}\) → D
Does anyone know how to solve this?
(2x^2)-6x+9 can be written in the form (a(x-b)^2)+c where a b c can be written as integers or fractions in their simplest form.
a) work out the values of a b c
b) using your answer to part a), solve (2x^2)-6x+9=12.5. give any fractions or surds in your answers in their simplest forms.
Answer:
it needs to be written step by step
Please help me with this geometry question. Answer should be entered like this (answer, answer) thank you
Answer:
Q is the point (3, 4).
Step-by-step explanation:
The formulae for the coordinates of a point (h, k) which divides a line joining the points (x1, y1) and (x2, y2) in the ratio m : n is:
h = (mx2 + nx1) / (m + n), k = (my2 + my1)/(m+n)
Now we have S = (x1, y1) = (-2, -6) and T = (x2, y2) = (5, 8) and
m = 5 and n = 2.
So here, for point Q:
h = (5*5) + 2*-2)/(2+5)
= 21/7
= 3.
k = (5*8 + (-6*2) / 7
= 28/7
= 4.
What is 1 1/6 plus 2 3/8 (by the way show work)
Answer:
\frac{170}{48}
Step-by-step explanation:
1\(\frac{1}{6}\) = \(\frac{7}{6}\)
2\(\frac{3}{8}\) = \(\frac{19}{8}\)
in order to add these fractions, we need the denominators to be same. We can multiply 6 and 8 to get 48.
In doing this, we need to multiply the numerators by the respective numbers also.
So, 7 (8) = 56 and 19 (6) = 114.
Add:
\(\frac{56}{48}\) + \(\frac{114}{48}\) = \(\frac{170}{48}\)
PLSSS HELP!!
Which equation could have been used to create this graph?
y = x + 4
y = 2x
y = 4x
y = x + 2
2|x|-9 translate 6 units up
The translation of the function 2 | x | - 9 when translated 6 units up gives the function as 2 | x | - 3.
We are given a function:
2 | x | - 9.
A function from a set X to a set Y assigns to each element of X exactly one element of Y.
We are asked to translate the function 6 units up.
This means that we have to add 6 units to the function.
A function has been “translated” when it has been moved in a way that does not change its shape or rotate it in any way.
So, we get that:
f(x) = 2 | x | - 9 + 6
f(x) = 2 | x | - 3
Therefore, the translation of the function 2 | x | - 9 when translated 6 units up gives the function as 2 | x | - 3.
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A biologist monitors the growth of molds to better understand how they spread. She begins with a culture of 50 molds in a container that can hold 1,000 cultures. Which model represents this scenario?
Answer:
D. y = StartFraction 1,000 Over 1 + 19 e Superscript negative 0.6 t Baseline EndFraction
Step-by-step explanation:
edge 2020
the coeffiecient for 6m + 7 is
m
Answer:
The coefficient of 6m is 6
Step-by-step explanation:
Blake is going to invest in an account paying an interest rate of 5. 7% compounded daily. How much would Blake need to invest, to the nearest hundred dollars, for the value of the account to reach $76,000 in 17 years
Blake needs to invest $50,300, to the nearest hundred dollars, for the value of the amount to reach $76,000 in 17 years.
In order to reach a value of $76,000 in 17 years, Blake needs to calculate the future value of his investment. To do this, he needs to take his initial investment amount, the interest rate, and the number of compounding periods. In this case, the initial investment amount is unknown, the interest rate is 5.7% compounded daily, and the number of compounding periods would be 17 years x 365 days, or 6205 days. Using the formula FV = PV(1 + r/n)^nt, Blake can calculate the future value of his investment. Plugging in the known values, we can calculate the initial investment amount to be $50,300, to the nearest hundred dollars. This means that Blake needs to invest $50,300 in an account paying an interest rate of 5.7% compounded daily, in order to have the account reach a value of $76,000 in 17 years.
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Use Sin Cos Tan to find the indicated angle
Fill in the blank so that the ordered pair is a solution of y=9x - 9.
( ), 63
Answer:
(8, 63)
Step-by-step explanation:
The ordered pair is a solution to the equation when substituting the values for x and y make the equation a true statement.
If we let x represent the first number of the ordered pair, it will be a solution when ...
63 = 9x -9
7 = x -1 . . . . . . . divide by 9
8 = x . . . . . . . add 1
The blank gets filled with 8, so the ordered pair is (8, 63).
What is the missing number in the sequence 1, 5, 10, 16, 23, 31,__?
Answer:
40 I think, if I wrong sorry
Step-by-step explanation:
Solve for x. x = -x
not possible
0
1
-1
Two firms producing identical products engage in price competition. Cost of firm 1 is $20 per unit produced and cost of firm 2 is $15 per unit produced. There are no fixed costs. Firms produce only after they learn the quantity demanded. Each firm can choose any real number in the interval [15,25] as its price.
For tie-breaking we will assume that if both firms set the same price, all consumers purchase from firm 2.
The payoff/profit function of firm 1 is:
(p1 - 20)(100 - p1) if p1 is less than or equal to p2,
0 if p1 is greater than p2
The payoff/profit function of firm 2 is:
(p2 - 15)(100 - p2) if p2 is less than p1,
0 if p2 is greater than or equal to p1
Given all of this information, solve the following parts of the problem:
a) is p1 = 20, p2 = 19.50 a Nash Equilibrium?
b) is there a Nash Equilibrium in which Firm 2 makes a positive profit?
c) How many strategies does player 1 have?
d) is p1 = 15, p2 = 15 a Nash Equilibrium?
e) is p1 = 21, p2 = 21 a Nash Equilibrium?
a) No, p1 = 20, p2 = 19.50 is not a Nash Equilibrium.
b) Yes, there is a Nash Equilibrium in which Firm 2 makes a positive profit.
c) Player 1 has infinitely many strategies.
d) Yes, p1 = 15, p2 = 15 is a Nash Equilibrium.
e) No, p1 = 21, p2 = 21 is not a Nash Equilibrium.
What is Nash Equilibrium?Nash Equilibrium is a state of a strategic game where no player has an incentive to deviate from his or her chosen strategy after considering the strategies of other players. A game has more than one Nash equilibrium if players are unable to agree on a cooperative strategy to play.
Finding Nash Equilibrium
a) Is p1 = 20, p2 = 19.50 a Nash Equilibrium?No. Firm 1 has an incentive to decrease the price to 19.49, thus breaking the tie in its favour. So p1=20, p2=19.5 is not a Nash equilibrium.b) Is there a Nash Equilibrium in which Firm 2 makes a positive profit?Yes. There are several equilibria in which Firm 2 makes a positive profit. One such equilibrium is when both firms charge the same price of 15, at which both firms earn a profit of 375.c) How many strategies does player 1 have?Player 1 has infinitely many strategies to choose from as they can choose any real number in the interval [15,25] as their price.d) Is p1 = 15, p2 = 15 a Nash Equilibrium?Yes. This is a Nash Equilibrium because neither firm has an incentive to change their strategy as they are earning non-zero profits. Both firms earn a profit of 375.e) Is p1 = 21, p2 = 21 Nash Equilibrium?No. If Firm 1 changes its price to 20.99, its profit increases from 405 to 407.99. Therefore, p1=21 and p2=21 is not a Nash Equilibrium.Learn more about Nash equilibrium at
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Which of the following equations represent exponential growth functions? Choose all that apply.
a) f (x)=4^x
b) f (x)=(1/4)^-x
c) f (x)=(2/3)^x
d) f (x)= (2.3)^x
e) f (x)=(.8)^x
Option:-
a) f(x) = 4^x is applicable
b) f(x) ={ (1/4)^-x = 4^x }is applicable
c.) f(x) = (2/3)^x is not applicable
d.) f(x) = (2.3)^x is applicable
e.) f(x) = (.8)^x is not applicable
Options (a), (b) and (d) are exponential growth functions.
What is Exponential function?An exponential decay is in the form:
y = abˣ
where y, x are variables, a is the initial value of y and b is the multiplier which is less than 1.
By the Exponential decay form,
An exponential decay is in the form: y = abˣ
(a) f (x)=4ˣ is applicable as 4>1
(b) f (x)=(1/4)⁻ˣ is applicable as (1/4)-1=4>1
(c) f (x)=(2/3)ˣ is not applicable because 2/3<1
d) f (x)= (2.3)ˣ is applicable as 2.3>1
e) f (x)=(.8)ˣ is not applicable, 0.8<1.
So options (a), (b) and (d) are applicable for exponential growth functions.
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