Answer:
there is nothing there
Explanation:
i don't see. anything
A 25.0-gram sample of magnesium oxide contains 10.8 grams of magnesium. What is the
percent of oxygen by mass in this compound?
(2 points)
a. 89.2 %
C. 43.2%
b. 14.2 %
d. 56.8 %
Answer: b. 14.2%
Explanation: I'm not sure if it's correct but I did it this way. Since we have a 25.0 gram of magnesium oxide by the name of it we should know that the 25.0 gram is composed of magnesium and oxygen. It tells us that we have 10.8 grams of magnesium. Therefore we can subtract 25.0- 10.8 = 14.2 so our answer would be 14.2% of oxygen.
Mercury has a density of 13.6 g/mL. What is the volume occupied by 112.0 grams of mercury?
Answer:
The answer is 8.24 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question
mass = 112 g
density of mercury = 13.6 g/mL
We have
\(volume = \frac{112}{13.6} \\ = 8.23529411...\)
We have the final answer as
8.24 mLHope this helps you
Helium is an example
of a gas because
A. helium does not take the shape of its
container.
B. helium particles are very randomly spaced
and moving freely.
C. helium particles are electrically charged.
D. helium cannot change its size or shape to fit
its container
Answer:
B
Explanation:
The particles move freely
identify NaOH (aq) + HNO3(aq) → NaNO3(aq) + H2O(1)
Answer:
this is called acid base reaction
Which would have a stronger attraction to the nucleus, the outer electrons of a carbon atom, or the outer electrons of an oxygen atom? Why?
Answer: Outer electrons because they revolve around the nucleus and can be multiple more than one
Explanation:
Hope it helps you you
what evidence have you discovered to explain how the structure of compounds determens the properties of the compounds
All of the properties such as ice floating on water, while most solids would sink when placed in its liquid are all due to the structure of the compounds.
The structure of the compounds includes the bonding angle, the type of bonds, the size of the molecule, the interactions between the molecules etc. Slight changes in the chemical structure and affect the properties if the compound.
Isomeric compounds with the same chemical formula but different structures can have different melting and boiling point and differ in reactivity and flammability.
Another common change in isomers are with the double bonds. A double bond can be in the cis formation or in the trans formation, and this will affect its properties as trans isomers will be having high melting point than the cis isomer.
Thus, structure of compounds do determine the properties of the compounds.
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Is Cl2 chlorine, dichlorine or dichloride?
Answer:
Cl² is dichlorine
Explanation:
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what will be the coefficient of o2 in the completed and balanced version of the following redox reaction: no−3 h2o2→no o2
In the completed and balanced equation, the coefficient of O₂ is 2.
To balance the redox reaction: NO₃⁻ + H₂O₂ → NO + O₂, we'll follow the steps for balancing redox reactions:
1. Assign oxidation numbers to each element:
NO₃⁻: N has an oxidation number of +5, and O has an oxidation number of -2.
H₂O₂: H has an oxidation number of +1, and O has an oxidation number of -1.
NO: N has an oxidation number of +2, and O has an oxidation number of -2.
O₂: O has an oxidation number of 0.
2. Identify the elements undergoing oxidation and reduction:
In this case, nitrogen (N) is undergoing reduction, and oxygen (O) is undergoing oxidation.
3. Write the two separate half-reactions, one for oxidation and one for reduction:
Reduction half-reaction: NO₃⁻ → NO
Oxidation half-reaction: H₂O₂ → O₂
4. Balance the atoms other than oxygen and hydrogen in each half-reaction:
Reduction half-reaction: 2NO₃⁻ → 2NO
Oxidation half-reaction: 2H₂O₂ → O₂
5. Balance the oxygen atoms by adding water molecules (H₂O) to the side that needs more oxygen:
Reduction half-reaction: 2NO₃⁻ → 2NO + 3H₂O
Oxidation half-reaction: 2H₂O₂ → O₂ + 2H₂O
6. Balance the hydrogen atoms by adding H⁺ ions to the side that needs more hydrogen:
Reduction half-reaction: 2NO₃⁻ + 10H⁺ → 2NO + 3H₂O
Oxidation half-reaction: 2H₂O₂ → O₂ + 2H₂O
7. Balance the charges by adding electrons (e⁻) to the side that needs more negative charge:
Reduction half-reaction: 2NO₃⁻ + 10H⁺ + 8e⁻ → 2NO + 3H₂O
Oxidation half-reaction: 2H₂O₂ → O₂ + 4H⁺ + 4e⁻
8. Multiply the half-reactions by appropriate coefficients to equalize the number of electrons transferred:
Reduction half-reaction: 2NO₃⁻ + 10H⁺ + 8e⁻ → 2NO + 3H₂O
Oxidation half-reaction: 4H₂O₂ → 2O₂ + 8H⁺ + 8e⁻
9. Add the two half-reactions together and cancel out the electrons:
2NO₃⁻ + 10H⁺ + 8H₂O₂ → 2NO + 3H₂O + 2O₂ + 8H⁺ + 8e⁻
10. Simplify the equation by removing the spectator ions and simplifying the coefficients:
2NO₃⁻ + 8H₂O₂ → 2NO + 3H₂O + 2O₂
In the completed and balanced equation, the coefficient of O₂ is 2.
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Clarity of signal
Analog
And
Digital
I just need these two questions and I’m done will give 28 points. Its for science
Which of the following is an example of a consumer? Tree Sun Rabbit Mushroom
Answer:
rabbit
Explanation:
Answer:
rabbit
Explanation:
the rabbit is the consumer because the sun "produces" the tree and mushroom, the rabbit comes along and eats the mushroom which was produced by the sun.
You are trying to generate hydrogen gas
(H₂) by reacting calcium with water
according to the reaction
Ca (s) + 2 H₂O (I) à Ca(OH)2 (aq) +
H₂ (9)
Carrying the reaction out at which
temperature will result in the quickest
production of H₂ gas?
OA. 0°C
OB. 4 °C
OC. 25 °C
O D. 100 °C
The quickest production of H₂ gas can be achieved by carrying out the reaction at a temperature near the boiling point of water which is 100° Celsius.
How will the boiling point of water increases the rate of reaction?For the quickest production of H₂ gas, the reaction should be done at a higher temperature. This is because as temperature increases, the kinetic energy of the particles increases, leading to higher reaction rate. As the reaction rate increases, it leads to an increased rate of H₂ gas production. Therefore, the reaction should be done at a higher temperature to achieve quicker production of H₂ gas which is the boiling point of water.
What is reaction rate?The rate at which reactants change into products is known as the rate of reaction or reaction rate. It goes without saying that the rate at which chemical reactions take place varies greatly. While certain chemical reactions occur almost instantly, others typically take time to achieve their final equilibrium.
For instance, because it happens quickly, wood burning has a high reaction rate, whereas iron rusting has a low reaction rate because it happens gradually.
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PLSSS HELPPPPPPPPPPPPPP I WILL MARK BRAINLIESTTTT!! you will save my lifeeeeeeeeeeeeeeeeeee
What is the independent and dependent variable in Electrolysis of water experiment
Electrolysis of water
Use a U-tube with electrodes at each end, connected to a battery. Fill the U-tube with water. Turning on the battery, observe the results at each electrode. Next, test for hydrogen and oxygen gas produced at each end of the tube.
Seawater containing 3.50 wt% salt passes through a series of 10 evaporators. Roughly equal quantities of water are vaporized in each of the 10 units and then condensed and combined to obtain a product stream of fresh water. The brine leaving each evaporator but the tenth is fed to the next evaporator. The brine leaving the tenth evaporator contains 5.00 wt% salt.
(a) Draw a flowchart of the process showing the first, fourth, and tenth evaporators. Label all the streams entering and leaving these three evaporators.
(b) Write in order the set of equations you would solve to determine the fractional yield of fresh water from the process (kg H2O recovered/kg H2O in process feed) and the weight percent of salt in the solution leaving the fourth evaporator. Each equation you write should contain no more than one previously undetermined variable. In each equation, circle the variable for which you would solve. Do not do the calculations.
(c) Solve the equations derived in Part (b) for the two specified quantities.
The fractional yield of fresh water from the process is determined by solving a set of equations. The weight percent of salt in the solution leaving the fourth evaporator can also be determined using these equations.
(a) Flowchart of the process:
In the first evaporator, seawater containing 3.50 wt% salt enters and produces vaporized water with the same salt concentration. The vaporized water is condensed, and the resulting brine, still containing 3.50 wt% salt, is fed to the second evaporator. This process continues until the tenth evaporator, where the brine leaving has a salt concentration of 5.00 wt%. The product stream of fresh water is obtained by condensing and combining the vaporized water from each evaporator.
(b) Set of equations:
To determine the fractional yield of fresh water from the process and the weight percent of salt in the solution leaving the fourth evaporator, the following equations can be solved:
Equation 1: x1 = (1 - 0.035) [Variable to solve: x1]
Equation 2: x2 = (1 - 0.035) * x1 [Variable to solve: x2]
Equation 3: x3 = (1 - 0.035) * x2 [Variable to solve: x3]
Equation 4: x4 = (1 - 0.035) * x3 [Variable to solve: x4]
Equation 5: x4 = (1 - 0.050) * x10 [Variable to solve: x10]
In these equations, x1, x2, x3, and x4 represent the fractional yield of fresh water from the first, second, third, and fourth evaporators, respectively. x10 represents the fractional yield of fresh water from the tenth evaporator.
(c) Solution:
To solve the equations derived in part (b), we need to find the values of x1, x2, x3, x4, and x10. These values can be obtained by substituting the known values of salt concentrations and solving the equations simultaneously. Once the values are determined, the fractional yield of fresh water from the process and the weight percent of salt in the solution leaving the fourth evaporator can be calculated.
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which one of the following is different from the others A .HCl B. HF C. HBr D. HI
Answer:
D.HI
Explanation:
because this is the most different
does the entropy of the system increase, decrease, or stay the same for each of the following conditions.
Drag the appropriate items to their respective bins.
Equal volumes of ethanol and water are mixed to form a solution The temperature of the system increases. The volume of a gas increases.
The entropy of the system increases for all of the three given conditions: equal volumes of ethanol and water are mixed to form a solution, the temperature of the system increases and the volume of a gas increases.
Equal volumes of ethanol and water are mixed to form a solution: Entropy increases.The system's entropy increases due to the randomness of the molecules, which is more in the solution than in the separate liquids. When mixing a solution, the solvent molecules spread out and mix with the solute molecules, resulting in a more disordered system. The entropy of the system is greater when there is more disorder.
The temperature of the system increases: Entropy increases.As the temperature of the system increases, the molecular motion also increases. When molecular motion is elevated, the disorderliness or entropy of the system also rises.
The volume of a gas increases: Entropy increases.The entropy of a gas increases as the volume expands since the molecules have more freedom to move around. The gas molecules are more disordered, and the entropy of the system is greater as a result.
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4 ethyl 2 isopropylhexanal
The structure of 4 ethyl 2 isopropylhexanal is:
\(CH_{3} - CH_{2}(C_{2}H_{5} ) - CH_{2} - CH(CH(O)) - CH_{3}\)
What is stereochemistry?
Stereochemistry, a subdiscipline of chemistry, involves the study of the relative spatial arrangements and manipulations of the atoms that make up the structure of molecules. The study of stereochemistry focuses on the relationships between stereoisomers. Stereoisomers, by definition, have the same arrangement (constitution) of the atoms bonded to the molecular formula, but differ in their structural formula (the three-dimensional orientation of the atoms in space). Therefore, it is also called 3D chemistry. The prefix "stereo" means "three-dimensionality".
Stereochemistry covers the entire spectrum of organic, inorganic, biological, physical and especially supramolecular chemistry. Stereochemistry includes methods for determining and describing these relationships. The effect these relationships have on the physical or biological properties of the molecule in question, and how these relationships affect the reactivity of the molecule in question (dynamic stereochemistry).
Hence, the structure of 4 ethyl 2 isopropylhexanal is:
\(CH_{3} - CH_{2}(C_{2}H_{5} ) - CH_{2} - CH(CH(O)) - CH_{3}\)
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draw the molecule by placing atoms on the grid and connecting them with bonds. use square brackets to denote the overall charge. include all lone pairs of electrons. clo3- clo4- no3- so3
ClO3-: The chlorine atom carries a single negative charge.
ClO4-: The chlorine atom carries a single negative charge.
NO3-:The nitrogen atom does not carry any charge, and the molecule as a whole carries a single negative charge.
Certainly! Here are the drawings of the molecules you requested:
1. ClO3-
O
|
Cl - O
|
O [-
2. ClO4-
O
|
Cl - O
|
O
|
O [-
3. NO3-
O
||
N - O
|
O [-
4. SO3
O
||
S - O
||
O
Please note that for SO3, it does not carry any charge (neutral molecule), as requested.
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State two properties of a base
Answer:
Bases are bitter to taste a bitter taste is characteristic of all bases. Bases may or may not be soluble in water Bases that can dissolve in water are called alkalis.Explanation:
The equilibrium concentrations for the reaction between SO2 and O2 to form SO3 at a certain temperature are given in the table below. Determine the equilibrium constant and whether the reaction favors reactants, products, or neither at this temperature.
Answer:
Option B. K = 1.3×10⁴, product favored
Explanation:
Data obtained from the question include:
O2(g) + 2SO2(g) <==> 2SO3(g)
Concentration of O2, [O2] = 0.024 M
Concentration of SO2, [SO2] = 0.015 M
Concentration of SO3, [SO3] = 0.26 M
Equilibrium constant, K =..?
The equilibrium constant, K is simply defined as the ratio of the concentration of products raised to their coefficient to the concentration of the reactants raised to their coefficient.
The equilibrium constant for the above reaction can be written as
K = [SO3]² / [O2] [SO2]²
Inputing the values of [SO3], [O2] and [SO2] the equilibrium constant, K is:
K = [SO3]² / [O2] [SO2]²
K = 0.26² / 0.024 × 0.015²
K = 1.3×10⁴
Therefore, the equilibrium constant K is 1.3×10⁴.
Since the value of the equilibrium constant, K is large and positive, therefore, the reaction favours the product.
Use Table B in your Student Guide to answer the questions about ion concentrations.
A solution with a pH = 13 has approximately how many moles of OH– ions per liter?
0.1
How many moles of H+ would this same solution have per liter?
0.000000000000.1
⇒ 0.0000000000001
(Use the decimal form of your answer.)
A different solution with an H+ concentration of 1.0 × 10–4 would have a pH =
4
.
1. The amount of OH¯ present in the solution is 0.1 mol/L
2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L
3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4
1. How to determine the amount of OH¯ in the solutionWe'll begin by obtaining the pOH of the solution
pH = 13pOH =?pH + pOH = 14
13 + pOH = 14
Collect like terms
pOH = 14 - 13
pOH = 1
Finally, we can determine the OH¯
pOH = 1OH¯ =?pOH = –Log [OH¯]
1 = –Log [OH¯]
Multiply through by –1
–1 = Log [OH¯]
Take the anti-log of –1
[OH¯] = anti-log of (–1)
[OH¯] = 0.1 mol/L
2. How to determine the amount of H⁺pH = 13H⁺ =?pH = –Log [H⁺]
13 = –Log [OH¯]
Multiply through by –1
–13 = Log [H⁺]
Take the anti-log of –13
[H⁺] = anti-log of (–13)
[H⁺] = 0.0000000000001 mol/L
3. How to determine the pHH⁺ = 1×10⁻⁴ mol/LpH =?pH = –Log [H⁺]
pH = –Log 1×10⁻⁴
pH = 4
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Consider the chemical equation. 2h2 o2 right arrow. 2h2o what is the percent yield of h2o if 87.0 g of h2o is produced by combining 95.0 g of o2 and 11.0 g of h2? use percent yield equals startfraction actual yield over theoretical yield endfraction times 100.. 56.5% 59.0% 88.5% 99.7%
The percent yield of H₂O, if 87.0 g of H₂O is produced by combining 95.0 g of O₂ and 11.0 g of H₂ is 87.87%.
How do we calculate mass from moles?Mass of any substance will be calculated by using their moles as:
n = W/M, where
W = given or required mass
M = molar mass
Moles of 95g of Oxygen (O₂) = 95g / 32g/mol = 2.96 moles
Moles of 11g of hydrogen (H₂) = 11g / 2g/mol = 5.5 moles
Given chemical reaction is:
2H₂ + O₂ → 2H₂O
From the stoichiometry of the reaction, it is clear that:
1 moles of O₂ = reacts with 2 moles of H₂
2.96 moles of O₂ = reacts with 2×2.96=5.92 moles of H₂
Here hydrogen is the limiting reagent as it has lower moles and formation of water depends on this only.
2 moles of H₂ = produces 2 moles of water
5.5 moles of H₂ = produces 5.5 moles of water
Mass of 5.5 moles of water will be calculated as:
W = (5.5mol)(18g/mol) = 99g
Given theoretical yield of water = 87g
% yield of water will be calculated as:
% yield = (87 / 99)×100 = 87.87%
Hence required value is 87.87%.
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Answer:
D
Explanation:
Consider a two step synthetic sequence to generate the chiral cyclopropane. provide the alkyne starting material a, intermediate organic product b, and identify the reagents.
The formed cyclopropane has cis stereochemistry.
Chiral cyclopropane rings are important pharmacophores in pharmaceutical drugs and bioactive natural products, so libraries of these building blocks are an important resource for drug research and development campaigns.
A synthesis is a set of two or even more reactions that are designed to produce a specific end product. A synthetic step is a single reaction that has to be carried out independently of the other reactions in a synthesis.
The number of steps inside a synthetic sequence equals the number of reactions that need to be performed separately, i.e. the number of reactions that comprise the sequence.
By stereospecific addi-tion of singlet carbenes, cis cyclopropane could be synthesized from cis alkene. Using a Lindlar catalyst, cis alkene could be synthesized from alkynes.
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how an eruption of a volcano
9. which of the following compounds will undergo a gas-evolving reaction in an aqueous solution? a) ch3cooh b) hf c) hcl d) h2so4 e) h2co3
Among the given compounds, the compound that will undergo a gas-evolving reaction in an aqueous solution is:
e) H2CO3 (carbonic acid)
Carbonic acid (H2CO3) can undergo a gas-evolving reaction in an aqueous solution through a process called decarboxylation. When carbonic acid is heated or subjected to certain conditions, it decomposes to release carbon dioxide (CO2) gas. This gas evolution can be observed as bubbles forming in the solution.
The other compounds listed, including acetic acid (CH3COOH), hydrofluoric acid (HF), hydrochloric acid (HCl), and sulfuric acid (H2SO4), do not undergo gas-evolving reactions under typical aqueous conditions. They may exhibit other chemical reactions but do not release gases as a product in water.
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How does the Nervous System control the
Circulatory System?
How does heat transfer by radiation different from the heat transfer by conduction or convection
The major difference between heat transfer by conduction and convection and heat transfer by radiation is that heat transfer by conduction and radiation requires a material medium, while heat transfer by radiation is done by electromagnetic waves and doesn't require a medium.
Heat or thermal energy is the energy generated when atoms or molecules move in a variety of directions (translational, rotational and vibrational). The three methods of heat transfer are convection, conduction and radiation. Conduction only occurs between solid objects in contact, convection occurs within a fluid, and radiation occurs through electromagnetic waves.
Unlike conduction and convection, radiation doesn't require a material medium before heat is transferred, as electromagnetic radiations don't require a material medium to propagate. Heat is transferred by radiation through infrared rays. Other differences include:
Conduction and convection are slow, while radiation is fast, as infrared rays travel at the speed of light.Radiation can be reflected using mirrors, while conduction and convection cannot.Learn more about radiation here:
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You are experimenting with blood samples and you place a drop of RBCs into a solution of 300 millimoles of CaCl2. What effect does this have on the RBCs?A.) The RBCs would shrink.B.) No effect on RBCs. This is an isotonic soution and there would be no net movement of water.C.) The RBCs would swell and burst.
The drop of RBCs placed in the 300 millimolar solution of CaCl2 would cause the RBCs to shrink. The answer is A) The RBCs would shrink.
This is because the solution is hypertonic, meaning it has a higher solute concentration than the RBCs. As a result, water will move out of the RBCs to try to equalize the concentration of solutes on both sides of the membrane. This will cause the RBCs to shrink in size as they lose water. The Ca2+ ions in the solution can also interact with the negatively charged phospholipid heads in the RBC membrane, causing the membrane to become more rigid and less flexible, further contributing to the shrinkage of the RBCs.
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Select the element with the most negative electron affinity (i.e, accepts an electron most readily):
The electron affinity of an element is the amount of energy released when an isolated gaseous atom accepts an electron to form a negative ion. The more negative the electron affinity, the more readily an element accepts an electron.
Among the given options, the element with the most negative electron affinity is chlorine (Cl), which is not included in the options. However, bromine (Br) is a halogen that is located directly below chlorine in the periodic table, and therefore has a similar electron affinity.
Bromine has an electron affinity of -324.6 kJ/mol, which is the highest among the given options. This means that bromine accepts an electron most readily compared to the other elements listed.
Tin (Sn), Barium (Ba), and Lithium (Li) have electron affinities of -107.3 kJ/mol, -13.95 kJ/mol, and -60.1 kJ/mol respectively, which are all less negative than bromine's electron affinity. Therefore, the element with the most negative electron affinity among the given options is Br (Bromine).
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Complete question
Select the element with the most negative electron affinity (i.e, accepts an electron most readily):
A)Br
B)Sn
C)Ba
D)Li
How can you differentiate Hydrogen and carbon dioxide gases. (by flame)
The presence of hydrogen would be indicated by a pale blue flame that is nearly invisible in broad daylight, but the presence of carbon dioxide would be indicated by the flame going out.
Why do carbon dioxide and hydrogen gas flames differ from one another?A flame ignited by hydrogen gas emits a barely perceptible pale blue flame under normal lighting conditions. This is due to the flame that hydrogen gas produces mostly emitting light in the ultraviolet spectrum, which is invisible to the human eye.
On the other side, a flame is put out when carbon dioxide gas is added to it. This is because carbon dioxide is a gas that does not support burning and is not flammable.
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Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O. Determine its empirical formula.
Answer:
the empirical formula is \(H_2NO_2\)
Explanation:
The empirical formula is
The following information is given
It contains 29.17 mass percentage of N
4.20 mass percentage of H
And, 66.63 mass percentage of 0
Now based on the above information, the empirical formula is \(H_2NO_2\)
hence, the same is to be considered and relevant too
Considering the definition of empirical formula, the empirical formula is H₂N₁O₂= H₂NO₂
The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers small as possible.
Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O.
Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 29.17 grams of N, 4.20 grams of H and 66.63 grams of O.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
N:\(\frac{29.17 grams}{14 \frac{grams}{mole} }\)= 2.08 molesH:\(\frac{4.20 grams}{1 \frac{grams}{mole} }\)= 4.20 molesO:\(\frac{66.63 grams}{16 \frac{grams}{mole} }\)= 4.16 molesThe empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
N:\(\frac{2.08 moles}{2.08 moles}\)= 1H:\(\frac{4.20 moles}{2.08 moles}\)= 2.02 ≅ 2O:\(\frac{4.16 moles}{2.08 moles}\)= 2Therefore the H: N: O mole ratio is 2: 1: 2
Finally, the empirical formula is H₂N₁O₂= H₂NO₂
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