a refracting telescope has a magnification m. if the focal length of the objective lens is doubled and the eyepiece focal length is halved, what is the new magnification?

The car's acceleration is 8 m/s².

The car's acceleration can be calculated using the formula:

a = (v_f - v_i) / t

where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken.

In this case, the car starts from rest (v_i = 0) and reaches a final velocity of 32 m/s in 4 seconds. Substituting these values into the formula, we get:

a = (32 m/s - 0 m/s) / 4 s = 8 m/s²

Therefore, the car's acceleration is 8 m/s².

The rate of change of velocity about time is defined as acceleration. Because it is a vector number, it has both magnitude and direction. Meters per second square is the standard measure of acceleration.

When an it em accelerates, its velocity changes in magnitude, direction, or both. A positive acceleration indicates an increase in velocity, whereas a negative acceleration indicates a decrease in velocity. If an object's velocity is steady, its acceleration is zero.

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The magnitude of the force of static friction exerted on the 1.4-kg wooden block resting on a 30° incline can be found using the coefficient of static friction (0.83) and the normal force (mg*cos(30°)). By multiplying the coefficient of static friction by the normal force, we can determine the maximum force of static friction.

Since the block is at rest, the force of static friction will be equal to the maximum force of static friction. Substituting the given values, the magnitude of the force of static friction can be calculated.

To find the magnitude of the force of static friction exerted on the block, we can follow these steps:

Draw a free-body diagram: This will help us identify the forces acting on the wooden block. The forces acting on the block include the force of gravity (mg) directed downward, the normal force (N) perpendicular to the incline, and the force of static friction (fs) acting parallel to the incline.

Resolve forces: Decompose the force of gravity into its components. The component acting parallel to the incline is mgsin(30°), and the component perpendicular to the incline is mgcos(30°).

Determine the normal force: The normal force is equal in magnitude and opposite in direction to the component of gravity perpendicular to the incline. Therefore, N = mg*cos(30°).

Calculate the maximum force of static friction: The maximum force of static friction can be determined using the formula fs(max) = μsN, where μs is the coefficient of static friction. In this case, μs = 0.83 and N = mgcos(30°).

Calculate the magnitude of the force of static friction: Since the block is at rest, the force of static friction will be equal to the maximum force of static friction. Therefore, fs = fs(max) = 0.83*(mg*cos(30°)).

Now, you can substitute the values of mass (m = 1.4 kg) and acceleration due to gravity (g = 9.8 m/s²) into the equation to calculate the magnitude of the force of static friction (fs).

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The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.  As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder.

Answer:

The time the ball is in contact with the club is approximately 0.011063 seconds

Explanation:

The question is with regards to Newton's second law of motion which states that a force is equal to the rate of change of momentum produced

The given parameters are;

The mass of the ball, m = 0.061 kg

The force with which the ball is struck with the golf club, F = 299.4 N

The change in velocity of the ball, Δv = 54.3 m/s

By Newton's second law, we have;

\(F_{net} = \dfrac{\Delta P}{\Delta t} = \dfrac{m \times \Delta v}{\Delta t}\)

Where;

Δt = The time it takes the momentum of the object to change = The time the ball is in contact with the club

Substituting the known values, we get;

\(F_{net} = F =299.4 = \dfrac{0.061 \times 54.3}{\Delta t}\)

\(\therefore \Delta t = \dfrac{0.061 \times 54.3}{299.4} \approx 0.011063\)

The time the ball is in contact with the club = Δt ≈ 0.011063 seconds.

Work done refers to the transfer of energy that occurs when a force is applied to an object and causes it to move over a certain distance in the direction of the force. Work is a scalar quantity and is denoted by the symbol "W." The work done by the racquet on the ball can be calculated using the formula:

Work = Force × Distance × cosθ

In this case, the force applied by the racquet on the ball is equal to the change in momentum of the ball.

To find the change in momentum, we need to calculate the initial and final momentum of the ball.

The initial momentum of the ball can be calculated using the formula:

Initial momentum = mass × initial velocity

Substituting the values given in the question:

Initial momentum = 0.0600 kg × 50.0 m/s

Next, we need to calculate the final momentum of the ball. Since the ball is traveling in the opposite direction after being hit by the racquet, the final velocity would be negative.

Final momentum = mass × final velocity

Substituting the values given in the question:

Final momentum = 0.0600 kg × (-40.0 m/s)

Now we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

Substituting the values:

Change in momentum = (0.0600 kg × (-40.0 m/s)) - (0.0600 kg × 50.0 m/s)

Simplifying the expression:

Change in momentum = -2.4 kg·m/s - 3.0 kg·m/s

Change in momentum = -5.4 kg·m/s

Now we can calculate the work done:

Work = Force × Distance × cosθ

Since the force applied by the racquet is equal to the change in momentum, we can substitute the value:

Work = (-5.4 kg·m/s) × Distance × cosθ

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When you park and your vehicle is facing uphill and there is no curb, your wheels should be turned so that they point towards the side of the road .

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The statement describes the way in which energy moves between a system of reacting substances  is  Molecular collisions transfer thermal energy between the system and its surroundings. Option D

In a chemical reaction, energy is either released or absorbed. This energy is transferred through molecular collisions. In other words, When molecules collide, they exchange energy.

If the reaction is exothermic, meanng it releases heat, the thermal energy is transferred from the system to the surroundings.

If the reaction is endothermic, what this means is that it absorbs heat, thermal energy is transferred from the surroundings to the system.

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The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

answer:

click on the picture, hope it helps

The magnitude of the electric field at that location is is 40  N.C⁻¹.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Given parameters:

Charge of the positive test charge, q =  5.0x10⁻⁶ C.

Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.

Then, electric field at the position, E = F/q

= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.

= 40  N.C⁻¹.

Hence,  the magnitude of the electric field at the location of the test charge is 40  N.C⁻¹.

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The most important factor in the creation of horizontal ocean strata with varying temperatures is variation in the density property of water at different temperatures.

The body of salt water known as the ocean, sometimes known as the sea or the world ocean, is what makes up 97% of the planet's water and covers roughly 70.8% of its surface. A vast body of water that is not part of the world ocean can also be referred to as an ocean. Five main oceanic regions are designated by distinct names: the Pacific (biggest), the Atlantic, the Indian, the Southern (Antarctic), and the Arctic (the smallest). On average, the oceans cover 361,000,000 km2 (139,000,000 sq mi) of the earth. The ocean is the main part of the hydrosphere on Earth, which makes it essential to life as we know it. The ocean affects the carbon cycle, the water cycle, and the climate by serving as a significant heat reservoir.

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Variation in the density of water at various temperatures is the most crucial element in the formation of horizontal ocean start with changing temperatures.

The ocean, often known as the sea or the world ocean, is the body of salt water that makes up 97% of the planet's water and occupies around 70.8% of its surface. The term "ocean" can also apply to a large body of water that is not a part of the global ocean. The Pacific (largest), the Atlantic, the Indian, the Southern (Antarctic), and the Arctic are the five main oceanic regions that are given different names (the smallest). The earth's oceans encircle 361,000,000 km2 (139,000,000 sq mi) on average. Being the primary component of the hydrosphere on Earth, the ocean is crucial to life as we know it. The carbon, water, and climate cycles are all impacted by the ocean.

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After considering the given data we conclude that the AC resistive circuit, the current and voltage are in phase with each other. This projects that the current flowing through the circuit and the voltage applied across the circuit reach their maximum and minimum values at the same time.

This is due to the circuit consists of a pure resistive load, which means that there is no inductance or capacitance in the circuit to cause a phase shift between the current and voltage. Therefore, the phase angle between the voltage and current is zero, and the current is said to be "in phase" with the voltage. This is confirmed by multiple sources, including research materials and articles.
The voltage-to-current ratio in an AC circuit is described by the supply frequency, phase angle, and phase difference. In an AC resistive circuit, the value of the resistor’s resistance stays constant regardless of the supply frequency. The current flowing through the resistance is directly proportional to the voltage across it with this linear relationship in an AC circuit being referred to as Impedance.
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Answer:

yes it does exert a force, it pushes it up

Explanation:

this is called normal force

if it didn't exert a force the book would keep going down

according to newton every force has an equal amd opposite reaction

so the book exerts a force on the table and vice versa

hope this helped

Answer:

Take a magnet and move it over the cup

Explanation:

Since there are metals also in the cup they would be attracted by the magnet leaving the plastic clips only in the cup

Answer:

The North Pole.

Explanation:

According to the Lenz's law of electromagnetic induction, an induced elemagnetic force tends to give rise to the current. In reaction, this current's magnetic field try to oppose any replacement in the magnetic flux.

So,  as per the law of Lenz's electromagnetic induction, when the current passes in a coil in anti-clockwise direction, this will produce the opposite end of the coil in the north pole.

So, the correct answer is north pole.

The final velocity of textbook upon being pushed is 0.64 m/s. Thus, \(v_{f} = 0.64 m/s\).

Given mass of the textbook, m = 1.4 kg

External force applied to push textbook, F = 6.0 N

Frictional force exerted on book, f = 3.0 N

Initial velocity of textbook, u = 0

Since, The external force applied on the object is more than the total limiting friction exerted on book. Hence, the object moves and friction become Kinetic Friction.

Therefore, F-f = ma

6 - 3 = 1.4 * a

\(a= \frac{3}{1.4}\)

\(a = 2.1 m/s^{2}\)

Now, to find final velocity of textbook

\(v^{2} = u^{2} + 2as\)

where v = final velocity

u = initial velocity

a = acceleration

s = distance travelled by textbook

\(v^{2} = 0 + 2*2.1*0.1\)

\(v^{2} = 0.42\)

v = 0.64 m/s

Hence, Final velocity of textbook after crossing 1.0m of distance is 0.64m/s.

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a) To find the speed of the signal in water, we can use the equation:

Speed = Wavelength x Frequency

Where Wavelength is given as 1.5 mm and Frequency is given as 1 x 10^6 Hz.

Speed = 1.5 x 10^-3 m x 10^6 Hz = 1.5 x 10^3 m/s

So the speed of the signal in water is 1.5 x 10^3 m/s

b) To find the period in water, we can use the equation:

Period = 1 / Frequency

Where Frequency is given as 1 x 10^6 Hz

Period = 1 / (1 x 10^6) s = 1 x 10^-6 s = 1 microsecond

So the period of the signal in water is 1 microsecond

c) The speed of sound in air is approximately 343 m/s. Since the frequency of the signal remains constant and the speed of sound in air is different than the speed of sound in water, the wavelength of the signal will also be different. However, since the period is inversely proportional to the frequency and is independent of the medium, the period of the signal in air will be the same as in water, which is 1 microsecond.

Answer:

Its also know as atomic mass its the mass of isotopes.

Explanation:

relative atomic masses of sources in the local environment of the Earth's crust and atmosphere as determined by the atomic weight.

The distance from the dot on the screen in the center of fringe e to the left slit is half a wavelength longer than the distance from the dot to the right slit.

In a double-slit interference setup, when a monochromatic light with a wavelength of 530 nm passes through the slits, it creates an interference pattern on the screen.

In the interference pattern, the bright fringes (constructive interference) occur when the path difference between the two slits is an integer multiple of the wavelength. The dark fringes (destructive interference) occur when the path difference is half an integer multiple of the wavelength.

At the center of the fringe e, it corresponds to a bright fringe, which means the path difference between the two slits is an integer multiple of the wavelength. Since the left and right slits have the same distance from the center of the screen, the path difference between the center of the fringe and the left slit is equal to the path difference between the center of the fringe and the right slit.

Therefore, the distance from the dot on the screen in the center of fringe e to the left slit is half a wavelength longer than the distance from the dot to the right slit.

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Answer:

See below

Explanation:

A ) distance = 1/2 a t^2    <==== when starting from rest

          20    = 1/2 (a) (3.5^2)      shows a = 3.27 m/s^2

B)   Velocity(at 3.5 s)   =   a t   = 3.27 * 3.5 = 11.42 m/s

C)    3.5 seconds      +    80 m / 11.42 m/s = 10.5 s

Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N

Explanation: To calculate the work done we use the formula

W=F.s                               (1)

W= work done

F=  force applied               s= displacement

Given, work done W= 25 joules= 25 J

displacement s= 0.5m

∴From equation (1) we get the force required when work is done and displacement is given, that is

F\(=\frac{W}{s}\)                                (2)

∴Force required \(F=\frac{W}{s}= \frac{25J}{0.5m}=50N\)            

(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)

ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N

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Notice that 40.35 is 5 times the half-life of 8.07 days. So in this time, the starting amount x of the sample was halved 5 times until 25 g of it were left, meaning

x/2⁵ = 25 g

Solve for x :

x = 2⁵ • (25 g) = 800 g

When an electron traveling north reaches an area with a consistent electric field facing north, the electron's speed and direction of motion are altered.

A negatively charged subatomic particle known as an electron can either be free or attached to an atom. In the electron cloud, which is located outside of the atomic nucleus, exist electrons.

An electric field that is oriented northward will exert a force on an electron moving northward through it. The electron will accelerate in the field's direction as a result of this force. The strength of the electric field and the charge of the electron will determine how much the acceleration is.

The electron will continue to receive a constant force and move in a straight line with a constant acceleration in a uniform electric field since the electric field's direction is constant. As the electron passes through the electric field, both its velocity and kinetic energy will increase.

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Answer:

C. 100 NEWTONS

Explanation:

just my brain being ly = brainly is the name so my brian is being ly

The weight of the stone is 10N.

To find the weight of the stone, we need to know about the gravitational force on any object due to earth.

When an object is near the earth surface, its weight is mass × gravitational acceleration (g).

So, the weight of the stone= 1kg × 10 m/s²

                            = 10 N

Thus, we can conclude that the weight of the stone 100 m above a gorge is 10N.

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Answer:

u = 80 cm and v = 80/3 cm

Explanation:

focal length f = +40/2 = 20 cm.

magnification m = v/u = 1/3, thus v = u/3

using 1/u+1/v=1/f gives 1/u=1/(u/3)=20  

So u = 80 cm and v = 80/3 cm

The maximum value that can be taken using the knapsack, given the items' {value, weight} pairs and a knapsack capacity of 20, is 60. Therefore the correct option is A. 60.

To find the maximum value that can be taken using the knapsack, we can apply the concept of the Knapsack Problem. The Knapsack Problem is a classic optimization problem in computer science.

Given the items' {value, weight} pairs and the knapsack capacity of 20, we need to select a combination of items that maximizes the total value while ensuring that the total weight does not exceed the knapsack capacity.

Using a dynamic programming approach, we can construct a table to track the maximum value achievable at each weight and for each item. Starting with an empty knapsack (weight = 0), we iterate through each item and update the table based on whether including the current item would increase the total value.

By considering all possible combinations, we can determine that the maximum value achievable with the given items and knapsack capacity is 60.

Therefore, the correct answer is A. 60.

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-1^10

centi=10 mm and mm=1/10=10^-1 cm

Answer:

Heat of vaporization

Explanation:

When water is at high levels of temperature heat is move as an energy source into the air.    

Answer:

\(\boxed {\boxed {\sf Heat \ of \ vaporization}}\)

Explanation:

There are two options for this answer: heat of fusion or heat of vaporization.

Let's define both of the terms.

Heat of fusion:

Heat of vaporization:

The question asks us which type of heat provides the energy for the phase change of a liquid to a gas. Therefore, the correct answer is heat of vaporization.