The strength of the electric field is strongest when the lines are close together and weakest when they are far apart.
What is the magnitude of the electric field?The electric field is the region of space around an electrically charged particle or object where the charge body feels force. Examples: -Electric fields are created by charges and their configurations, such as capacitors and battery cells.
The force per charge applied to the test charge can be used to determine the electric field's strength. Its definition gives birth to the common metric units for electric field strength.
It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. With a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
Therefore, The units of an electric field would be force units divided by charge units, as an electric field is defined as a force per charge.
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Which of the following is not an accurate measurement of mass?
O grams
0 kilograms
O pounds
0 kilometer
Houston Astro's pitcher Framber Valdez throws a45.0 m/sfast ball to a Philly's batter, who hits it straight back to the pitcher at35 m/sbefore its caught and the out is called. The mass of a baseball is 145 grams. a. Calculate the initial momentum of the baseball (before it is hit). b. Calculate the final momentum of the baseball (after it is hit). c. The impulse given to the ball by the bat. d. The max force exerted on the ball from the bat, using the graph provided.
Given, Mass of base ball = 0.14 kg
speed before it made the contact with the ball (V i) = 42 m/s
speed after batter hit the ball(V f) = - 48 m/s
a) impulse = change in momentum
=
=
= -12.6 Kg m/s
b) Magnitude of impulse = 12.6 Kg m/
Force =
=
Force = 2520 N
The impulse given to the ball by the bat is, 2520 N.
Impulse is the essential of a pressure, F, over the time c programming language, t, for which it acts. For the reason that pressure is a vector quantity, impulse is likewise a vector quantity. Impulse carried out to an item produces an equivalent vector exchange in its linear momentum, also within the resultant path.
Calculation
Given, Mass of baseball = 0.14 kg
speed before it made the contact with the ball (V i) = 42 m/s
speed after batter hit the ball(V f) = - 48 m/s
a) impulse = change in momentum
= -12.6 Kg m/s
b) Magnitude of impulse = 12.6 Kg m/
Force = 2520 N
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Modeling physical phenomena: You are studying the motion of bugs flying in a room. The bugs do not appear to interact with each other although they are flying slightly upwards due to a ventilation vent near the ceiling. If you treat (or model) the bugs as particles, consider the following: a) (2 pts) Do the bugs behave like an ideal or real gas? Explain your answer. b) (2 pts) Can you use the MB distribution from #2 to calculate the average bug speed? Explain your answer.
The bugs in this scenario behave more like an ideal gas due to their lack of interaction with each other. However, the MB distribution cannot be directly applied to calculate the average bug speed because the bugs are subject to external forces that are not accounted for in the distribution.
a) The bugs in this scenario behave more like an ideal gas rather than a real gas. An ideal gas is a theoretical model that assumes gas particles do not interact with each other and occupy negligible volume. In the given situation, the bugs do not appear to interact with each other, indicating a lack of significant intermolecular forces or collisions. This suggests that the bugs can be treated as independent particles, similar to the assumptions made in the kinetic theory of gases for ideal gases.
Real gases, on the other hand, exhibit non-negligible intermolecular forces and interactions, causing deviations from the ideal gas behavior. These interactions can result in changes in volume and pressure, which are not observed in the described behavior of the bugs.
b) No, the Maxwell-Boltzmann (MB) distribution cannot be directly used to calculate the average bug speed in this scenario. The MB distribution describes the distribution of speeds for a system of ideal gas particles in thermal equilibrium. It assumes that the particles are subject to random thermal motion and obey the principles of kinetic theory.
However, the bugs in the given scenario are not behaving in a manner consistent with thermal equilibrium or the assumptions of the MB distribution. The upward motion of the bugs due to the ventilation vent indicates the presence of an external force acting on them, which is not accounted for in the MB distribution. Therefore, using the MB distribution to calculate the average bug speed would not accurately represent the actual behavior of the bugs in this specific situation.
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How was it possible for the bike and the semi-truck to have the same
momentum?
Answers/
1-One had more mass and greater velocity
2-The situation is not possible
3-One had less mass but greater velocity
4-One had less mass and less velocity
momentum depends on mass (m) and velocity (v) of object
momentum (p) = m × v
we can get the same value of momentum (m) by different pair values of m and v, for example if a truch has more mass and less velocity and the bike has less mass but more velocity then there must be a case when their momentum is same.
correct answer
3-) One had less mass but greater velocity
if a star has a luminosity of 1026 watts and is 1016m distant from us, what would we measure its brightness to be?
The brightness of a star is determined by its luminosity and its distance from us. If a star has a luminosity of 1026 watts and is 1016 m distant from us, then we would measure its brightness to be 2.23 x \(10^{-7}\) watts per square meter.
To calculate the brightness of a star, the luminosity needs to be divided by 4πr², where r is the distance of the star from us in meters.
In this case, the luminosity is 1026 watts and the distance is 1016m, so the brightness would be calculated as follows:
1026/4πx1016² = 2.23 x \(10^{-7}\) watts per square meter.
In conclusion, the brightness of the star with a luminosity of 1026 watts and a distance of 1016m from us would be measured to be 2.23 x \(10^{-7}\) watts per square meter.
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Bibek went to the swimming pool. he saw the pool to be shallower and is redy to jump into the swimmingpool . is it proper for him to jump? if not why ?
Answer:
A swimming pool appears shallower than it really is due to the phenomenon of REFRACTION. Due to refraction, from rarer medium( Air ) to denser medium ( water ), the pool looks shallower
Explanation:
the light turns green the driver steps on the gas and the car accelerates from rest
Your body has a tendency to lurch backward when the automobile accelerates and exerts power in a forward direction.
By accelerates, what do you mean?Acceleration is the rate at which direction and speed of velocity vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the velocity is constant, transportation on a circle accelerates because of direction is always shifting.
Briefing:The force and the related momentum always flow in the same direction, according to Newton's second law.
However, not all forces and accelerations act inside the direction of motion.
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The projectile launcher shown below will give the object on the right an initial horizontal speed of 5.9 m/s. While the other object will be dropped with no initial speed. The objects are initially 179 cm above the ground and separated by 142 cm. What will be the difference in the landing locations of the two objects?
Answer:
104.3 cm or 179.7
Explanation:
First find time that it takes for the object to hit the ground
\(\sqrt{(2H)/g} -> \sqrt{(2 x 179)/ 9.8} = 6.04s\\\)*
Then find xf of projectile \(xf= 5.9(6.04) = 37.7\\\\\)
not 100% sure if the projectile is going away from the object or towards it but you either do 142- 37.7 or 142+37.7
hope that helps
"217 cm" would be the difference throughout the landing locations of the two objects.
Given:
Initial horizontal speed,
v = 5.9 m/sHeight,
h = 179 cmBy applying equation of motion, we get
→ \(S = ut+\frac{1}{2}at^2\)
By substituting the values, we get
→ \(179\times 10^{-2}=0+\frac{1}{2}\times 9.8\times t^2\)
→ \(3.58= 9.8t^2\)
\(t^2 =\frac{3.58}{9.8}\)
\(t = \sqrt{0.36531}\)
\(= 0.61 \ s\)
now,
The horizontal distance travelled by the first particle will be:
→ \(d = v\times t\)
\(= 5.9\times 0.61\)
\(= 3.59 \ m\)
or,
\(= 359 \ cm\)
hence,
The distance between particle will be:
= \(d -142\)
= \(359-142\)
= \(217 \ cm\)
Thus the above approach is right.
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For the common drain amplifier below, C1 and C2 are very large DC-blocking capacitors to decouple AC input from DC biases. They can be treated as short circuit for AC signals. Assume that the DC power supply voltage VDD is properly chosen so that M1 is in saturation region and the small-signal parameters of M1 are found to be gm = 150 mS, ro = 20 kΩ, Cgs = 50 pF, Cgd = 1.5 pF.
(a) Draw the small-signal equivalent circuit.
(b) Calculate the mid-band voltage gain Av = vout/vin.
(c) Calculate the -3dB bandwidth using the open-circuit time constant (OCTC) method.
The common drain amplifier has a mid-band voltage gain of approximately -1.5 and a -3dB bandwidth of around 1.06 MHz.
(a) The small-signal equivalent circuit for the common drain (CD) amplifier can be represented as follows:
+-----------------+
| |
Vin ----+--| |
| | |
Rg | |
| | |
+--| |
| M1 |
| (N-channel) |
| |
| D |
+--| G |
| | S |
| | |
| |
| Cgs |
| |
+-----------------+
| |
Vout |
| |
+-----------------+
Here, Vin is the input voltage, Vout is the output voltage, Rg is the gate resistor, and M1 represents the N-channel MOSFET with its source (S), gate (G), and drain (D) terminals. Cgs represents the gate-source capacitance, which is connected in parallel with M1.
(b) The mid-band voltage gain (Av) can be calculated using the formula:
Av = -gm * (ro || RD)
Where gm is the transconductance parameter of M1 and ro is the output resistance of M1 in parallel with the load resistance RD.
Given gm = 150 mS and ro = 20 kΩ, let's assume the load resistance RD is also 20 kΩ:
Av = -150 mS * (20 kΩ || 20 kΩ)
= -150 mS * 10 kΩ
= -1.5
Therefore, the mid-band voltage gain (Av) is approximately -1.5.
(c) The -3dB bandwidth can be determined using the open-circuit time constant (OCTC) method. The OCTC method considers the dominant pole in the frequency response of the amplifier. In this case, the dominant pole is determined by the output resistance (ro) and the output capacitance (Cgd) of M1.
The -3dB bandwidth (BW) can be calculated using the formula:
BW = 1 / (2 * π * (ro || RD) * Cgd)
Given ro = 20 kΩ and Cgd = 1.5 pF, let's assume the load resistance RD is still 20 kΩ:
BW = 1 / (2 * π * (20 kΩ || 20 kΩ) * 1.5 pF)
= 1 / (2 * π * 10 kΩ * 1.5 pF)
≈ 1.06 MHz
Therefore, the -3dB bandwidth of the common drain amplifier is approximately 1.06 MHz.
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Explain how you would apply any five pricing techniques to attract customers
Answer:
Explanation:
1. DECOY PRICING
This occurs when customers make a purchase they must often choose between products with different prices and attributes.
This method of pricing is meant to influence the consumer's purchasing decision and maximise the sales of one particular product. The seller will offer at least three products; two of the products will have a similar or equal price. The two products with the similar prices should be the most expensive ones, and one of the two should be less attractive than the other.
2. LOSS LEADER
This is when a product is sold at a low price (often without profit) in order to stimulate other profitable sales or to attract new customers.
The main is that it will help the business to expand their market share as a whole. It's common practice when first entering a market as it introduces new customers to a service or product in the hope of building a customer base and securing future
3.ODD PRICING
This is a method of psychological pricing a product. Prices ending in 9, 95, 97, 99 are sometimes called “charm prices” and in this type of pricing, the seller fixes a price where the last digits are odd numbers. This is intended to give the buyer no room for manœuvering or for bargaining as the price appears to be less - a product priced at £9.99 will seems much cheaper than one priced at £10.00
4. PRICE DISCRIMINATION
The purpose of price discrimination is to capture the market's consumer surplus and generate the most revenue possible for a product. Identical goods or services are sold at different prices from the same provider to different segments of the market. Industries that commonly use price discrimination include the travel industry, pharmaceuticals and textbook publishers.
5. PRODUCT BUNDLE PRICING
Using this method, sellers will combine several products in the same package. It also serves to move old stock. Blu-ray and videogames are often sold using the bundle approach once they reach the end of their product life cycle. This technique is used at auctions where one attractive item may be included in a lot with a box of less interesting things. Buyers must bid for the entire lot. It’s a good way of moving slow selling products, and in a way is another form of promotional pricing.
1. Vector A, having magnitude 2.5 m, pointing 37° south of east and vector B having
magnitude 3.5 m, pointing 20° north of east are added. What is the magnitude of the
resultant vector?
a. 1.0 m
b. 5.3 m
c. 5.9 m
d. 6.0 m
The resulting vector has a magnitude of roughly 5.9 m.
What is the formula for resultant vectors?When two or more vectors are added while adhering to the vector addition rules, the resultant vector is the resultant vector. When two vectors are supplied as R1 and R2, the resulting vector is given as R=R1+R2. This holds true not just for forces but also for every vector.
Let's first break down vector A into its constituent parts. It intersects the positive x-axis at an angle of 90° - 37° = 53°. The x-component of A is thus:
Ax = A cos(53°) = 2.5 cos(53°) ≈ 1.62 m
And the y-component of A is:
Ay = A sin(53°) = 2.5 sin(53°) ≈ 1.95 m
Let's now break down vector B into its component parts. It intersects the positive x-axis at a 20° angle. As a result, B's x-component is:
Bx = B cos(20°) = 3.5 cos(20°) ≈ 3.31 m
And the y-component of B is:
By = B sin(20°) = 3.5 sin(20°) ≈ 1.20 m
The vector sum of A and B is the resulting vector R. Using the Pythagorean theorem, we can determine the size of R:
|R| = sqrt(Rx² + Ry²)
where Rx and Ry are, respectively, R's x- and y-components. We combine the corresponding x- and y-components of A and B to yield Rx and Ry:
Rx = Ax + Bx ≈ 4.93 m
Ry = Ay + By ≈ 3.15 m
Now, we can find the magnitude of R:
|R| = sqrt(Rx² + Ry²) ≈ sqrt((4.93 m)² + (3.15 m)²) ≈ 5.85 m
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Suppose an 18-wheel truck and trailer has a mass of 30,000 kg and is traveling with a speed of 24.5 m/s . If the driver slams on his brakes and begins to skid, what would the stopping distance be if the coefficient of kinetic friction between the truck's tires and the pavement is 0.50 ?
Answer:
it's A
Explanation:
two identical 2.0 kg blocks are stacked as shown in figure p5.71. the bottom block is free to slide on a frictionless surface. the coefficient of static friction between the blocks is 0.35. what is the maximum horizontal force that can be applied to the lower block without the upper block slipping?
Answer:
F2 = M2 g μ force that can be applied to upper block without slipping
M2 a = M2 g μ
a = g μ maximum acceleration of upper block with no slipping
F1 = (M1 + M2) a force applied to lower block
F1 = 4 kg * 9.80 m/s^2 * .35 = 13.7 N
An ideal gas is enclosed in a piston-cylinder apparatus with the piston being freely movable. Given that LaTeX: \DeltaΔE is positive and LaTeX: \DeltaΔH is negative following a process, ____ the system absorbs heat and expands during the process. the system absorbs heat and contracts during the process. the system loses heat and expands during the process. the system loses heat and contracts during the process. the system loses heat but neither expands nor contracts during the process.
Clear question is;
An ideal gas is enclosed in a piston-cylinder apparatus with the piston being freely movable. Given that ΔE is positive and ΔH is negative following a process,
pick one
A) the system absorbs heat and expands during the process.
B) the system absorbs heat and contracts during the process.
C) the system loses heat and expands during the process.
D) the system loses heat and contracts during the process.
E) the system loses heat but neither expands nor contracts during the process.
Answer:
Option A is correct.
Explanation:
In thermodynamics, when the change in energy which is ΔE of a system is positive, it means that the system is undergoing an endothermic process. An endothermic process is simply one where heat is absorbed from the surroundings
Now, when change in enthalpy which is ΔH is negative, it means that it's an exothermic reaction. Exothermic means it releases heat to the surroundings. This means work is positive because the system does work on the surroundings. Thus it will expand.
So the correct answer is;
heat is absorbed from the surroundings and will expand during the process.
4. Marcia consumes 8.4 X 10.J (2000 food calories) of energy per day while maintaining a constant weight.
What is the average power she produces in a day? 97 Watts
Answer:
8.40 is your answer.
Explanation:
The average power she produces in a day be 97.22 Watts.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Marcia consumes total amount of energy per day = 2000 calories = 8.4 × 10⁶ joule.
1 day = 24 × 60 × 60 second = 86400 second
So, average power she produces in a day = energy/time
= 8.4 × 10⁶ joule/86400 second
= 97.22 Watts
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3. a frictionless pulley has the shape of a uniform solid disk of mass 2.5 kg and radius 20.0 cm. a 1.5-kg stone is attached to a massless wire that is wrapped around the rim of the pulley, as shown. the system is then released from rest. as always, show details of your calculation. a. how far (in m)must the stone fall so that the pulley has 4.5 j of kinetic energy? b. what percent of the total kinetic energy of the system does the pulley have at that point?
a. To calculate the distance the stone must fall, we need to use the formula KE = ½ mv², where m is the mass of the object and v is the velocity of the object. First, calculate the total kinetic energy of the system:
\(KEtotal = ½ mPulley x v² + ½ mStone x v² = ½ (2.5 kg)(4.5 J) + ½ (1.5 kg)(4.5 J) = 6.75 J\)
We then rearrange the equation to solve for v²: v² = 2 x KE / m = (2 x 6.75 J) / (1.5 kg) = 9 J/kg.Next, we need to calculate the velocity of the stone, vStone, which is equal to the square root of the above equation: vStone = √(9 J/kg) = 3 m/s
Finally, we need to use the equation s = vt, where s is the distance the stone falls, v is the velocity of the stone, and t is the time it takes for the stone to fall. We rearrange the equation to solve for t: t = s / v = 4.5 m / 3 m/s = 1.5 s Therefore, the stone must fall a distance of 4.5 m in order for the pulley to have 4.5 J of kinetic energy.
b. To calculate the percent of the total kinetic energy of the system that the pulley has, we need to use the equation: Percent of total KE = KEpulley/KEtotal x 100%. KEpulley = ½ mPulley x v² = ½ (2.5 kg)(4.5 J) = 4.5 J
Therefore, the percent of the total kinetic energy that the pulley has is 4.5 J/6.75 J x 100% = 66.67%.
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During its first year of operations, silverman company paid $10,740 for direct materials and $11,300 for production workers' wages. lease payments and utilities on the production facilities amounted to $10,300 while general, selling, and administrative expenses totaled $3,200. the company produced 7,700 units and sold 4,800 units at a price of $6.70 a unit. what is silverman's cost of goods sold for the year
Silverman Company's cost of goods sold for the year is $17,328.
To calculate Silverman Company's cost of goods sold for the year, we need to add up all the costs directly associated with producing and selling the 4,800 units sold during the year.
First, we need to calculate the total cost of direct materials and production workers' wages, which is $10,740 + $11,300 = $22,040.
Next, we need to add the lease payments, utilities, and general, selling, and administrative expenses, which is $10,300 + $3,200 = $13,500.
To calculate the total cost of goods sold, we need to divide the total cost by the number of units produced, which is 7,700 units.
Therefore, the cost of goods sold for Silverman Company for the year is:
($22,040 + $13,500) / 7,700 units = $3.61 per unit
Since the company sold 4,800 units during the year, the total cost of goods sold is:
$3.61 per unit x 4,800 units = $17,328
Therefore, Silverman Company's cost of goods sold for the year is $17,328.
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what are two reasons communication is important in scientific research
Answer:
It allows them to write better and more comprehensible research papers. As well as being able to communicate the relevance and impact of their ideas and discoveries.
Explanation:
a 3.5 kg block is pushed along a horizontal floor by a force : f of magnitude 15 n at an angle ???? 40° with the horizontal (fig. 6-19). the coefficient of ki- netic friction between the block and the floor is 0.25. calculate the magnitudes of (a) the frictional force on the block from the floor and (b) the block’s acceleration.
The frictional force is 11 N and the block’s acceleration is 0.14 m/s².
What is the coefficient of friction?It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction, the lower the friction between the surfaces, and the higher coefficient of friction the higher the friction force between them.
For part (a):
Taking x component:
F(x) = F cosθ
Taking y component:
F(y) = -F sinθ
Applying Newton’s second law to the y-axis:
F(N) = 15 sin40 + (3.5)(9.8)
F(N) = 44 N
coefficient U = 0.25
f(k) = 11 N
For part (b):
Applying Newton’s second law to the x-axis:
a = ((15) cos40 - 11)/3.5
a = 0.14 m/s²
Thus, the frictional force is 11 N and the block’s acceleration is 0.14 m/s².
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If a rock falls from a cliff, at what point are its kinetic energy and its potential energy the same? Ignore air resistance.
Answer:
The gravitational potential energy it had from being above the ground is converted to kinetic energy as the rock falls. As kinetic energy increases, the velocity of the rock will also increase.
Explanation:
69) The molecular weight of nitrogen, N2, is 28 g/mol. What is the rms speed of nitrogen molecules in a cooler at 8.0°C? The Boltzmann constant is 1.38 × 10-23 J/K and NA = 6.022 × 1023 molecules/mol.
A) 450 m/s
B) 500 m/s
C) 550 m/s
D) 600 m/s
E) 650 m/s
The rms speed of nitrogen molecules in a cooler at 8.0°C is approximately 517 m/s (option B).
What is Molecular Weight?
Molecular weight is the sum of the atomic weights (in atomic mass units) of all the atoms in a molecule. It is also known as the molecular mass. The molecular weight is used to calculate various properties of the substance, such as its density, boiling point, and melting point.
First, we need to convert the temperature to kelvin:
T = 8.0°C + 273.15 = 281.15 K
The root-mean-square (rms) speed of gas molecules can be calculated using the formula:
v_rms = sqrt((3 * k_b * T) / m)
where k_b is the Boltzmann constant, T is the temperature in kelvin, and m is the mass of a single molecule.
For nitrogen gas (N2), the molecular weight is 28 g/mol or 0.028 kg/mol. Therefore, the mass of a single nitrogen molecule is:
m = (0.028 kg/mol) / NA = 4.65 × 10^-26 kg
where NA is Avogadro's number.
Now, we can substitute the values into the formula:
v_rms = sqrt((3 * 1.38 × 10^-23 J/K * 281.15 K) / 4.65 × 10^-26 kg)
v_rms = 517 m/s
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It was found that ice cream sales decrease significantly as the temperature outside decreases; a very strong relationship was found. What is the most likely correlation coefficient from this hypothetical study
Answer:
Value closest to 1
Explanation:
It is described from the scenario above that ice cream sales decreases as the outside temperature increases, hence showing a strong relationship between both variables (icream sales and temperature). The correlation Coefficient is a metric used in regression modeling to depict the strength of relationship between two variables, (The dependent and independent variables). Correlation Coefficient ranges from (-1 to +1). With values close to 1 or - 1. Also the positive and negative signs are used to show the type of relationship between the variables. If an increase in variable A leads to a decrease in variable B, then we have negative correlation (-) ; while an increase or decrease in both variables depicts a positive correlation. The most likely correlation Coefficient for the study above will be a positive value which is close to 1 since the relationship is described as strong.
2kg of water at 30 C is poured into a 1kg copper beaker at 20 C.
What will the temperature of the water and copper beaker be together?
The temperature of the water and copper beaker be together is 29.6⁰C.
What is the equilibrium temperature of both substance?
The final temperature or equilibrium temperature of the water and copper beaker is calculated by applying the principle of conservation of energy.
Heat lost by the water = Heat gained by the copper beaker
mcΔθ (water) = mcΔθ (copper)
where;
m is massc is specific heat capacityΔθ is change in temperaturem₁c₁(T₁ - T) = m₂c₂(T - T₂)
where;
T₁ is the initial temperature of waterT₂ is the initial temperature of copper beakerT is the equilibrium temperatureSpecific heat capacity of copper, c₂ = 389 J/kgK
Specific heat capacity of water , c₁ = 4200 J/kgK
(2)(4200)(30 - T) = (1)(389)(T - 20)
252,000 - 8400T = 389T - 7780
259,780 = 8789T
T = 259,780 /8789
T = 29.6⁰C
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What would happen to the magnetic field if she connects the battery in the opposite direction? the field would stop. the field would get stronger. the field would reverse its poles. the field would get weaker.
When the battery is connected in the opposite direction : ( C ) The field would reverse its poles.
Effect of reverse battery connection on electric fieldIn an electrical experiment, when the battery used is connected in opposite directions, the electric field would reverse its poles. because the poles of the battery is reversed the electric field will also be reversed in response.
Hence we can conclude that When the battery is connected in the opposite direction : ( C ) The field would reverse its poles.
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Answer:
The answer is c ez
Explanation:
The full moon is opposite the sun in the sky, and rises as the sun sets. what is the approximate angular separation of the sun and the full moon?
The approximate angular separation of the sun and the full moon is 180°
The full moon is opposite the sun in the sky, and rises as the sun sets is may be understand as ,the Moon can be seen in the day light sky at any phase except for the new moon, when it's invisible to us, and full moon, when it's below the horizon during the day. The crescent through quarter phases are high in the sky during the day, but the daytime gibbous phases can be glimpsed only just before the Sun sets
In the crescent phase, the lit-up part of the Moon increases from 0.1% to 49.9%. is growing, while crescent refers to the curved sickle shape.
The gibbous moon is the phase of moon in that appears more than half lighted but less than full.
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A 2.2 kW electric iron operates normally on a voltage of 220 V.
Fill in the blank.
The current in the iron when it is operating normally is _____ A.
Answer:
Current equals Power divided by Voltage (I=P/V), Power equals Current times Voltage (P=VxI), and Voltage equals Power divided by Current (V=P/I).
P = V I
2.2*10³ = 220 * I
I = 10 amps
A car accelerates from 0 to 72 km/hr in 8 seconds. What is the car's acceleration?
Explanation:
Vi = 0 m/s
Vf = 72 km/hr = (72×5)/18 = 20 m/s
t = 8 s
Vf = Vi + a×t
20 = 8a
a = 2.5 m/s^2
Answer:
Initial Velocity (u) = o m/s
Final Velocity (V) =(72*1000)/1*60*60 m/s
= 20m/s
time (t) =8 sec
Acceleration(a)= v-u /t
=(20-0)/8
=2.5 m/s^2
this is the answer i just did the problem
why is the lifetime in the atmosphere be a problem if cfs are no longer being produced
Answer:CFCs and halons cause chemical reactions that break down ozone molecules, reducing ozone's ultraviolet radiation-absorbing capacity
Explanation:
A horizontal net force F is exerted on an object at rest. The object starts at x= 0 m and has a speed of 4.0 m/s after moving 6.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
what is the mass of the object?
A horizontal net force f is exerted on a 4.0 kg object at rest. The object starts at x = 0 m and travels 6.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the velocity of the object?
Answer: 6.7 m/s
To understand decay in terms of half-life and to solve radioactive dating problems.Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:N(t)=N0e−λt,where λ is known as the decay constant. Note that at t=0, N(t)=N0, the original number of unstable nuclei. N(t) decreases exponentially with time, and as tapproaches infinity, the number of unstable nuclei that remain approaches zero.Part (E) Suppose that an Egyptian farmer claims to have discovered a linen burial cloth used during Egypt's Middle Kingdom some 4000 years ago. Careful analysis shows that the cloth contains 80% of the 14C that it is estimated to have originally contained. How old is the cloth? (years)
The age of the cloth material is obtained from the calculation as 1843 years .
What is the half life?We know that the half life of a radioactive isotope refers to the time that is taken for only half of the number of the original radioactive isotopes that are present to remain in the sample.
We can be able to obtain the age of the cloth by looking at the amount of the radioactive carbon -14 that is still left in the sample. How do we do that? We have to turn to a formula that says;
0.693/\(t_{\frac{1}{2} }\) = 2.303/tlog (Ao/A)
\(t_{\frac{1}{2} }\) = half life of the material
t = age of the material
Ao = amount initially present
A = Amount present at time t
Then we have;
0.693/5730 = 2.303/tlog (Ao/0.8Ao)
1.21 * 10^-4 = 0.223/t
t = 0.223/1.21 * 10^-4
t = 1843 years
Learn more about carbon -14:https://brainly.com/question/4206267
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