A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds.
Determine the acceleration of the car and the distance traveled.

Answer:

potential energy

the name comes from the fact that the ruler has "potential" to act

Explanation:

Explanation:

The deformation of the ruler creates a force in the opposite direction, known as a restoring force.

I'm not sure if it's correct...

1. The average speed of Luis over the 60 s is 1.33 m/s

2. The average velocity of Luis over the 60 s is zero.  

1. The average speed can be calculated with the following equation:

\( S = \frac{d}{t} \)

Where:

d: is the total distance traveled

t: is the total time = 60 s

The total distance can be calculated by the sum of the distance traveled to the truck (40 m) and the distance traveled to his home (the same 40 m), as follows:

\( d = 40 m + 40 m = 80 m \)

So, the average speed is:

\( S = \frac{d}{t} = \frac{80 m}{60 s} = 1.33 m/s \)

Hence, Luis's average speed over the 60 s is 1.33 m/s.

2. Now, the average velocity is a vector given by:

\(v = \frac{\Delta x}{\Delta t} = \frac{x_{f} - x_{i}}{t}\)

Where:

\(x_{f}\): is the final distance traveled (the way to his home) = 40 m

\(x_{i}\): is the initial distance traveled (the way to his truck) = 40 m

Δt: is the total time = t = 60 s

Given that Luis in his journey, returns to the same starting point (his house), the total displacement is zero, and so the average velocity is also zero:                              

\(v = \frac{x_{f} - x_{i}}{t} = \frac{40 m - 40 m}{60 s} = 0\)

Therefore, Luis's average velocity over the 60 s is zero.  

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As shown in the figure below, Luis rushes 40 m toward his truck. He notices he forgot his shoes and returns back to his house. His total travel time is 60 s.

Answer:

What is Luis’s average velocity over the 60 s period?

Answer: 0 m/s

What is Luis’s average speed over the 60 s period?

Answer: 1.33  m/s

Answer:12

Explanation:

Sending the SIGTSTP signal will halt or suspend a running process. kill -TSTP 342; is the command.

What is linux machine?

The local system's distinctive machine ID, which is specified at installation or boot, is stored in the /etc/machine-id file. The machine ID is a single, 32-character, lowercase, hexadecimal ID that ends with a newline. This is equivalent to a 16-byte/128-bit value when decoded from hexadecimal.

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After 20 rounds of amplification through the polymerase chain reaction (PCR), the number of copies of the amplified region should theoretically be \(2^{20\), which is 1,048,576.

This is because PCR is an exponential process where each round of amplification doubles the number of copies of the target DNA region. Therefore, the number of copies after 1 round of amplification is 2, after 2 rounds it is 4, after 3 rounds it is 8, and so on.

To calculate the number of copies after 20 rounds of amplification, we use the formula 2^n, where n is the number of amplification cycles. In this case, n = 20, so \(2^{20\) = 1,048,576 copies.

It is important to note that this is a theoretical maximum and assumes 100% efficiency in each round of amplification. In reality, there may be some loss of DNA during the PCR process, and other factors such as contamination or suboptimal reaction conditions can also affect the final yield. Therefore, the actual number of copies obtained may be slightly lower than the theoretical maximum.

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The pressure at point B is 622.5 kPa.

Based on the information provided, we can determine the velocity of the water through the 40-mm-diameter elbow using the formula Q = Av, where Q is the volumetric flow rate (0.012 m³/s), A is the cross-sectional area of the elbow (πr², where r is the radius of the elbow), and v is the velocity of the water.

We can rearrange the formula to solve for v:

v = Q / A

The radius of the elbow can be determined by dividing the diameter by 2:

r = 40 mm / 2 = 20 mm = 0.02 m

The cross-sectional area of the elbow can then be calculated using the formula A = πr²:

A = π(0.02 m)² = 0.00126 m²

Substituting these values into the formula for velocity:

v = 0.012 m³/s / 0.00126 m² = 9.52 m/s

Now that we know the velocity of the water, we can use Bernoulli's equation to determine the pressure at point B:

P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂

Where P₁ is the pressure at point A (170 kPa), ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s2), h₁ and h₂ are the heights of points A and B above a reference level (we can assume they are the same), and P₂ is the pressure at point B (what we want to find).

Rearranging the equation and substituting in the known values:

P₂ = P₁ + 0.5ρ(v₁² - v₂²)

P₂ = 170 kPa + 0.5(1000 kg/m³)(9.522 - 02) = 170 kPa + 452.5 kPa

P₂ = 622.5 kPa

Therefore, the pressure at point B is 622.5 kPa.

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Triangle is a polygon with 3 sides. The record of the letters in your triangle from left to right is EGFBIHDCA.

A triangle is a polygon with 3 sides. Also, It has three vertices.

As the example is given to us, ABCDEFGHI is the record of the letters that are when seen from top to bottom, therefore, if we rotate the triangle such that the left side of the triangle is on the upper side, then the triangle we will get is given below as attached below.

Therefore, the record of the letters in your triangle from left to right will now be "EGFBIHDCA" from the former arrangement which was "ABCDEFGHI".

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The power output is  0.0975 MW

The efficiency of a fission power plant refers to the percentage of the energy released during nuclear fission that is converted into usable electrical energy. The efficiency of a fission power plant depends on various factors, such as the design of the reactor, the type of fuel used, and the efficiency of the power conversion system.

Efficiency = Power output/ Power input * 100/1

39 = x/0.25 * 100

39/100 * 0.25

= 0.0975 MW

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F=m*a

T = 142N

Work = Force x distance

distance = 6.1 M

Force = 142 x cos 37 = 113.4 N

W= 113.4N x 6.1M = 691.78 J

Answer:

\(\huge\boxed{\sf F = 3.33* 10 ^{11} \ N}\)

Explanation:

Given Data:

\(\sf Mass \ of \ the \ dam =m= 3.4 * 10^{10} kg\\\\Mass \ of \ Earth = M_{e} = 5.98 * 10^{24} kg\\\\Radius \ of \ Earth = r_{e} = 6.38*10^6 m\\\\Gravitational \ Constant = G = 6.67 * 10 ^{-11} Nm^2 / kg^2\)

Required:

Force of gravity = F =?

Formula:

\(\sf F = G\frac{mM_{e}}{r^2}\)

Solution:

\(\sf F = (6.67*10^{-11})\frac{(3.4*10^{10}* 5.98 * 10^{24})}{(6.38*10^6)^2} \\\\F = \frac{135.6* 10 ^{-11+10+24}}{40.7 * 10 ^{12}} \\\\F = \frac{135.6 * 10^{23}}{40.7*10^{12}} \\\\F = 3.33 * 10 ^{23-12}\\\\F = 3.33* 10 ^{11} \ N\\\\\rule[225]{225}{2}\)

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The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.

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Answer:

15 units NE

Explanation:

Assuming the coordinate plane is a compass with N being the positive y-axis, we can use the Pythagorean theorem to find the magnitude of the vector. Since the vector is going up by 12 and right by 9 at the same time, it should form a diagonal line, aka the hypotenuse of a triangle. This triangle has both of its leg units as 12, and 9. Pythagorean theorem states that a^2 + b^2 = c^2, that is both of their legs squared is the hypotenuse of the triangle squared. 12^2 + 9^2 = c^2. c = 15. Now that we know the magnitude, let's go back to the quadrants as the compass. Since both units are positive, the vector goes in the positive direction on both sides, which is Quadrant 1. North and East would be the appropriate say for the vector's direction, thus the vector's direction will be 15 units North East.

The charge of the particle in this situation is positive. When a charged particle is immersed in a uniform magnetic field, it experiences a force known as the Lorentz force, which is given by the equation:

F = q(v × B)

Where F is the Lorentz force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.

In this case, the particle is moving along a circular path in the counter-clockwise direction, which means that the force acting on the particle is directed towards the center of the circle. This force is known as the centripetal force, and it is given by the equation:

F = mv^2/r

Where m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circle.

Since the Lorentz force and the centripetal force are equal in magnitude and opposite in direction, we can equate the two equations to get:

q(v × B) = mv^2/r

Rearranging the equation and solving for q gives:

q = mv^2/(rB)

Since the particle is moving in the counter-clockwise direction, the velocity vector v is directed tangentially to the circle, and the magnetic field vector B is directed out of the page. The cross product of these two vectors is directed towards the center of the circle, which means that the charge of the particle must be positive in order for the Lorentz force to be directed towards the center of the circle.

Therefore, the charge of the particle in this situation is positive.

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The current passing through a series combination of resistors does not change as it goes through each successive resistor.

In a series combination of resistors, the current passing through the circuit remains the same throughout the circuit. This is known as Kirchhoff's Current Law, which states that the total current entering a junction is equal to the total current leaving the junction.

When the current passes through each resistor in the series, the resistance of each resistor impedes the flow of the current. This means that the voltage across each resistor is different, but the current flowing through each resistor remains the same.

In other words, the current does not change as it goes through each successive resistor in the combination, but the voltage across each resistor changes proportionally to its resistance. The total voltage across the series combination of resistors is equal to the sum of the voltage drops across each individual resistor.

The relationship between current, voltage, and resistance is described by Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.

Instead, the voltage across each resistor changes proportionally to its resistance, and the total voltage across the series combination of resistors is equal to the sum of the voltage drops across each individual resistor.

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Answer:

a = \(-\frac{25}{27}\) m/s²

Explanation:

Acceleration (a) = (final velocity - initial velocity) ÷ (final time - initial time) =  \(\frac{v_{f} - v_{i} }{t_{f} - t_{i} }\)

Converting the speed from km/h to m/s;

100 km = 100000m

1hr = 3600s

∴ 100km/hr ⇄ \(\frac{100000 m}{3600 s}\) = \(\frac{250}{9} m/s\)

Acceleration = \(\frac{0 - 250/9}{30}\) = \(-\frac{250}{9 * 30} = -\frac{25}{27}\) m/s²

i.e deceleration = \(\frac{25}{27}\) m/s²

Answer:

It is B most likely

Explanation:

Answer:

Each ribbon = 10 inches

Explanation:

Each yard = 36 inches

4 2/3 * 36 = 168 inches      now cut off 8 inches

   160 inches

now make 16 ribbons     160 / 16 = 10 inches

Answer:

I feel it's important to be civilly engaged in my community because it gives me a sense of placement and home in my own community. It also allows me to feel that my voice is being heard and not ignored.

In conclusion, the hole with a diameter of 35.0 mm drilled in the wall of the oven emits approximately 32.8 W of power.

The power emitted by a hole in the wall of an oven can be calculated using the Stefan-Boltzmann law. This law states that the power emitted by a black body is proportional to the fourth power of its temperature.
To calculate the power emitted by the hole, we need to consider it as a black body and assume it is in thermal equilibrium with the oven.
Given that the temperature of the oven is constant at 1065.0 K and the hole has a diameter of 35.0 mm, we can calculate the surface area of the hole using the formula for the area of a circle.
Area = π * (radius)^2
The radius of the hole is half of the diameter, so the radius would be 35.0 mm / 2 = 17.5 mm = 0.0175 m.
Using this radius, we can calculate the area of the hole:
Area = π * (0.0175 m)^2 = 0.000962 m^2
Now, we can calculate the power emitted by the hole using the Stefan-Boltzmann law:
Power = σ * Area * (Temperature)^4
Where σ is the Stefan-Boltzmann constant, which is approximately equal to 5.67 x 10^-8 W/(m^2*K^4).
Plugging in the values, we get:
Power = (5.67 x 10^-8 W/(m^2*K^4)) * (0.000962 m^2) * (1065.0 K)^4
Calculating this, the power emitted by the hole is approximately 32.8 W.
In conclusion, the hole with a diameter of 35.0 mm drilled in the wall of the oven emits approximately 32.8 W of power.

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(A) The solution X is unsaturated

(B) The solution Y should contain 2.9 g solute in 1000 mL solution.

(C) The percentage by mass of the solute is 40%

(A) The type of solution X is determined as follows;

The maximum amount of solute that can dissolve in solution  X  =  29 g/Liter

The amount of solute in solution X = 2.9 g/Liter

This solution is unsaturated because the amount of solute present is less than the maximum the solution can take.

(B) The amount solute and volume in the solution Y is calculated as follows;

The solubility = 2.9 g/Liter

\(solubility = \frac{2.9 \ g}{L} \times \frac{L}{ mL \times 1000} = \frac{2.9 \ g}{1000mL}\)

Thus, the solution should contain 2.9 g solute in 1000 mL solution.

(C) The percentage by mass of the solute is calculated as;

\(mass \ \% = \frac{20 \ g}{50 \ g} \times 100 \% = 40 \%\)

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Answer:

Before stopping, the van travels 42.5 m

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

\(v_f=v_o+at\qquad\qquad [1]\)

The distance traveled by the object is given by:

\(\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]\)

The van slows down uniformly from v0=17 m/s to vf=0 m/s in t=5 s. The acceleration can be calculated by solving [1] for a:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

\(\displaystyle a=\frac{0-17}{5}=-3.4\ m/s^2\)

The distance covered is:

\(\displaystyle x=17\cdot 5+\frac{(-3.4)\cdot 5^2}{2}\)

\(\displaystyle x=85-42.5=42.5\)

Before stopping, the van travels 42.5 m

The correct prescription for the eyeglasses is 2.11 diopters.

To get the correct prescription for the eyeglasses, we need to first calculate the refractive power needed.

We can use the formula:

Refractive power = 1 / focal length (in meters)

We know that with the contact lenses, the man can read books held no closer than 0.290 m from his eyes.

This means the focal length of the lenses is:

Focal length = 0.290 m

So, the refractive power of the contact lenses is:

Refractive power = 1 / 0.290 m = 3.45 diopters

Now, we need to adjust the refractive power for the new distance between the eyeglasses and his eyes (0.030 m).

We can use the formula:

Adjusted refractive power = original refractive power + (original refractive power x distance change)

Distance change = (new distance - old distance) / old distance

Distance change = (0.030 m - 0.290 m) / 0.290 m = -0.8966

So, the adjusted refractive power for the eyeglasses is:

Adjusted refractive power = 3.45 diopters + (3.45 diopters x -0.8966) = 2.11 diopters

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a) The successful tackle constitutes a perfectly inelastic collision due to significant deformation and kinetic energy is not conserved.(b) The velocity of the players immediately after the tackle is 2.88 m/s.(c)  The mechanical energy that disappears as a result of the collision is 785. 8 J.(d) The missing energy may be converted into sound, heat, or some other form of energy due to the impact and deformation of the players' bodies and equipment. The missing energy is typically dissipated and not recoverable as kinetic energy of the system.

(a) The successful tackle constitutes a perfectly inelastic collision because the two players stick together and move as a single unit after the collision. In a perfectly inelastic collision, the colliding objects combine and move together with a common final velocity. This occurs when there is significant deformation, and kinetic energy is not conserved.

(b) To calculate the velocity of the players immediately after the tackle, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

So, if we call the W-E axis our X-axis (being the direction towards east as the positive one) , and to the S-N axis our Y -axis (being the northward direction the positive one)

Dividing both sides:

sin θ / cos θ = tan θ = 1.54 / 2.43 = 0.634

⇒ arc tan (0.634) = 32.3º

Replacing in (1) we have:

v_(f) = 2.43 m/s / cos 32.3º = 2.43 m/s / 0.845 = 2.88 m/s

(c) To determine the mechanical energy that disappears as a result of the collision, we can calculate the initial kinetic energy and the final kinetic energy and find the difference.

Before the collision:

K₀ = 1/2×m₁×v₁₀² + 1/2 m₂×v₂₀²

= 1/2×( ( 90.0) kg×(5.0)²(m/s)² + (95.0)kg×(3.0)(m/s)²) = 1,553 J

After the collision:

K_(f) = 1/2 ×(m₁+ 767.2 J m₂)×vf² = 1/2×185 kg×(2.88)²(m/s)²= 767.2 J

The mechanical energy lost during the collision is just the difference between the final and initial kinetic energy:

ΔK = K_(f) - K₀ = 767.2 - 1,553 J = -785.8 J

So, the magnitude of the energy lost during the collision is 785.8 J.

(d) The missing energy in a perfectly inelastic collision is generally converted into other forms, such as thermal energy or deformation energy. In this case, it may be converted into sound, heat, or some other form of energy due to the impact and deformation of the players' bodies and equipment. The missing energy is typically dissipated and not recoverable as kinetic energy of the system.

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A differential amplifier is an electronic device that amplifies the voltage difference between two input signals while rejecting any common-mode voltage. It is commonly used in applications where the accurate amplification of small signals is required, such as in operational amplifiers, audio amplifiers, and instrumentation amplifiers.

There are different kinds of differential amplifiers, including:

1. Single-Ended Differential Amplifier: This type of differential amplifier has one input signal and one reference signal. It amplifies the voltage difference between the input signal and the reference signal, rejecting any common-mode voltage.

2. Fully Differential Amplifier: In this type of differential amplifier, both the positive and negative inputs are differential signals. It amplifies the voltage difference between the two inputs while rejecting any common-mode voltage. It is commonly used in applications where precise amplification of differential signals is required.

3. Instrumentation Amplifier: An instrumentation amplifier is a differential amplifier that provides high input impedance, high common-mode rejection, and adjustable gain. It is commonly used in applications where accurate amplification of small differential signals is needed, such as in medical instruments and data acquisition systems.

Now, let's draw the circuits for these differential amplifiers:

1. Single-Ended Differential Amplifier:
```
    Vcc
     |
     R1
     |
Vin1--|\
     |  > Amplifier
Vin2--|/
     |
     R2
     |
   GND
```

2. Fully Differential Amplifier:
```
    Vcc
     |
     R1
     |
Vin+--|\
     |  > Amplifier
Vin--|/
     |
     R2
     |
   GND
```

3. Instrumentation Amplifier:
```
    Vcc
     |
     R1
     |
Vin1--|\
     |  > Amplifier
Vin2--|/
     |
     R2
     |
     |
     R3
     |
     |\
     | > Amplifier
     |/
     |
     R4
     |
   GND
```

In these circuit diagrams, Vin1 and Vin2 represent the input signals, and Vcc represents the power supply voltage. R1, R2, R3, and R4 are resistors used to set the gain and provide input impedance to the amplifier. The exact values of these resistors and other components may vary depending on the specific application and desired amplification characteristics.

I hope this explanation helps! Let me know if you have any further questions.

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One Newton is equivalent to 1 kg*m/s². This means that a force of one Newton will cause a mass of one kilogram to accelerate at a rate of one meter per second squared.

The unit of Newton is commonly used in physics to measure force. It is named after Sir Isaac Newton, who made significant contributions to the field of physics. Newton's laws of motion are fundamental principles that govern the behavior of objects in motion, and the unit of Newton is used to quantify the force required to cause an object to move or change its motion. Understanding the concept of force and its measurement is essential in various fields, including engineering, mechanics, and physics. In conclusion, one Newton is equivalent to 1 kg*m/s², and this unit is widely used to measure force.

The angle between the resultant and the larger force is 60 degree if resultant force value is value 9.1 Newtons. We know that resultant force of one newton  given by the superposition principle which uses a formula Resultant force =√((F₁)² + (F₂)² + 2 ˣ F₁ ˣ F₂ ˣ cosθ) Superposition principle of electric force to find the resultant power, all accuses are thought about independently of that specific charge as though any remaining charges are missing. Along these lines, for each charge, the power on that specific charge is to be found out. Then the vector amount of the multitude of forces gives the resultant forces on that charge.

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Answer:

Psychiatrists are medical doctors, psychologists are not. Psychiatrists prescribe medication, psychologists can't. Psychiatrists diagnose illness, manage treatment and provide a range of therapies for complex and serious mental illness. Psychologists focus on providing psychotherapy (talk therapy) to help patients.

Explanation:

Answer:

Psychiatrists are medical doctors, psychologists are not. Psychiatrists prescribe medication, psychologists can't. Psychiatrists diagnose illness, manage treatment and provide a range of therapies for complex and serious mental illness. Psychologists focus on providing psychotherapy (talk therapy) to help patients.

Explanation:

Answer:

Explanation:

speed = distance / time

          = 15 meters / 3 seconds

          = 5 meter / sec.

Answer:5/sec

Explanation:

Therefore, it will take the second sheet approximately 4.63 s to reach the same angular velocity.

With a few calculations and some fundamental conceptual understanding, one can easily determine the ultimate velocity. By dividing the amount of time it took the object to move a certain distance by the overall distance, one can calculate the object's initial velocity.

For a thin rectangular sheet rotating about a plane perpendicular to one of its edges, the moment of inertia is given by:

\(I = (1/12)M(L^2 + W^2)\)

Since both sheets have the same torque causing them to rotate, the torque is the same for both sheets. The first sheet's moment of inertia is:

\(I1 = (1/12)M(0.3^2 + 0.5^2) = 0.0125M\)

The angular acceleration for the first sheet is:

α1 = τ/I1

ω1 = α1t1

Solving for α1, we get:

α1 = ω1/t1

Substituting this into the equation for angular acceleration and solving for ω1, we get:

ω1 = (τ/I1)t1

Similarly, for the second sheet, the moment of inertia is:

\(I2 = (1/12)M(0.5^2 + 0.3^2) = 0.0125M\)

The angular acceleration for the second sheet is:

α2 = τ/I2

ω2 = α2t2

Substituting in the equation for angular acceleration and solving for t2, we get:

t2 = ω2/α2

To find ω2, we can use the fact that the torque is the same for both sheets:

τ = I1α1 = I2α2

Substituting in the expressions for I1, I2, α1, and α2, we get:

\(τ = (1/12)M(0.3^2 + 0.5^2)(ω1/t1) = (1/12)M(0.5^2 + 0.3^2)(ω2/t2)\)

Canceling out the mass and torque, and solving for ω2, we get:

\(ω2 = (0.3^2 + 0.5^2)/(0.5^2 + 0.3^2)(ω1)t1\)

Substituting this into the equation for t2, we get:

\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(t1)\)

Plugging in the values for t1 (8.0 s), we get:

\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(8.0 s)\)

≈ 4.63 s

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