A quarter and a penny are tossed. Then an 8-sided die is rolled. How many possible outcomes are there?

Answer:

y=4x+1

Step-by-step explanation:

I took this math class ik the answer

Answer:

18 sides

Step-by-step explanation:

I'm not sure what the question is, but this is what I think the question is.

"An interior angle of a regular polygon measures 160 degrees. How many sides does the polygon have?"

The sum of the measures of the interior angles of a polygon of n sides is

(n - 2)180

If the polygon is a regular polygon, then the measure of each interior angle is

(n - 2)180/n

Here, we are told an interior angle measures 160 deg.

(n - 2)180/n = 160

(n - 2)180 = 160n

(n - 2)18 = 16n

(n - 2)9 = 8n

9n - 18 = 8n

n = 18

Answer: 18 sides

Using differentials, the maximum error in the viscosity of a fluid moving through a tube can be estimated to be approximately 8.07e-3 Pa s given the tube's length, radius, pressure, and flow rate, along with their respective uncertainties.

We can use the formula for the differential of a function of several variables to estimate the maximum error in the viscosity η:

dη ≈ ∂η/∂r * dr + ∂η/∂p * dp + ∂η/∂v * dv

where ∂η/∂r, ∂η/∂p, and ∂η/∂v are the partial derivatives of η with respect to r, p, and v, respectively. We can calculate these partial derivatives as follows:

∂η/∂r = π/2 * p * r^3 / v

∂η/∂p = π/8 * r^4 / v

∂η/∂v = -π/8 * p * r^4 / v^2

Plugging in the given values and their uncertainties, we get:

dr = 0.00025 meters

dp = 2000 pascals

dv = 0.375e-9 m^3 per unit time

r = 0.003 meters

p = 2e5 pascals

v = 0.375e-9 m^3 per unit time

∂η/∂r ≈ (π/2) * (2.0e5) * (0.003)^3 / (0.375e-9) ≈ 3.84e-3 Pa s/m

∂η/∂p ≈ (π/8) * (0.003)^4 / (0.375e-9) ≈ 4.26e8 Pa s^2/m^4

∂η/∂v ≈ -(π/8) * (2.0e5) * (0.003)^4 / (0.375e-9)^2 ≈ -2.06e-21 Pa s^2/m^4

Now we can plug these values into the formula for dη:

dη ≈ (3.84e-3 * 0.00025) + (4.26e8 * 2000) + (-2.06e-21 * 0.375e-9)

≈ 8.07e-3 Pa s

Therefore, the maximum error in the viscosity η is approximately 8.07e-3 Pa s.

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Answer:

q = $0.05

e = $0.5

Step-by-step explanation:

13q = 0.65 equation 1

5q + 7e = $3.75   equation 2

in equation 1, divide both sides of the equation by 13

q = 0.65 / 13 = 0.05

Substitute for the value of q in equation 2

5(0.05) + 7e = 3.75

0.25 + 7e = 3.75

collect like terms

3,75 - 0.25 = 7e

3.5 = 7e

e = 0.5

The scientist first operated the time-travel machine in the year 7.

To determine the year the scientist first operated the time-travel machine, we need to work backward from the given end point of 2023.

Since he ended up in 2023, we know that after going back 2000 years, the scientist was in the year 23. Going back even further, we subtract three years to account for the initial forward jump. This takes us to the year 20.

From there, we need to find the year when the scientist made the jump forward by two times the current year. To do this, we divide 20 by 2, resulting in 10. This means that the scientist made the jump forward in the year 10.

Finally, to determine the year when he first operated the time-travel machine, we subtract three more years from 10, which gives us the year 7.

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Answer:

2. ($2)(3 lb) = $6 Round and then multiply

Correct question :

If the perimeters of each shape are equal, which equation can be used to find the value of x? A triangle with base x + 2, height x, and side length x + 4. A rectangle with length of x + 3 and width of one-half x. (x + 4) + x + (x + 2) = one-half x + (x + 3) (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3) 2 (x) + 2 (x + 2) = 2 (one-half x) + 2 (x + 3) x + (x + 2) + (x + 4) = 2 (x + 3 and one-half)

Answer: (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3)

Step-by-step explanation:

Given the following :

A triangle with base x + 2, height x, and side length x + 4 - - - -

b = x + 2 ; a = x ; c = x + 4

Perimeter (P) of a triangle :

P = a + b + c

P =( x + 2) + x + (x + 4) - - - (1)

A rectangle with length of x + 3 and width of one-half x

l = x + 3 ; w = 1/2 x

Perimeter of a rectangle (P) = 2(l+w)

P = 2(x+3) + 2(1/2x)

If perimeter of each same are the same ; then;

(1) = (2)

(x + 2) + x + (x + 4) = 2(x+3) + 2(1/2x)

Answer:

B

Step-by-step explanation:

Answer:

D BOTTOM RIGHT

Step-by-step explanation:

Answer:

18:12

simplified 3:2

this is the answer to your problem

The ration between boys and girls are -  18:12

when simplified-  3:2

The sequence 200, 40, 8, ... is a geometric sequence. Let's define the geometric sequence before we explain why the above sequence is geometric. In a geometric sequence, each term is multiplied by the same common ratio to obtain the next term.

A geometric sequence can be represented by the formula a, ar, ar^2, ar^3, ... , where a is the first term, r is the common ratio, and ar, ar^2, ar^3, ... are the successive terms. The common ratio can be calculated using any two consecutive terms in the sequence.To determine if a sequence is geometric or not, we need to check whether the ratio of successive terms is the same. In the given sequence, 200 is the first term, 40 is the second term, and 8 is the third term.

So, the common ratio is =0.2Similarly, the ratio between 40 and 8 is Therefore, the ratio of successive terms is 0.2, which is constant. Hence, the given sequence is a geometric sequence.

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The equation |2x - 3| - m = m has three solution .

What is equation ?

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal."

Equations are mathematical expressions that have two algebraic expressions on either side of an equals (=) sign. The expressions on the left and right are shown to be equal to one another, demonstrating this relationship.

When two expressions are joined by an equal sign, a mathematical statement is called an equation. An equation is something like 3x - 5 = 16. By solving for x, we discover that x equals 7, which is the value for the variable.

|2x-3|-m=m

|2x-3|=m+m

2x-3=|2m|

2x-3=2m            or          2x-3=-2m

x=(2m+3)/2        or       x= -(2m+3)/2

and

2x-3=0

x=3/2

so, there is 3 solutions

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Answer:

Lashawn used 15, $0.50 stamps, 21, $0.35 stamps, and 8, $0.02 stamps to mail the package

Step-by-step explanation:

The given parameters are;

The number of stamps Lashawn used to mail the small package = 44

The price of the combination of 44 stamp = $15.01

The price categories of the stamps are $0.50, $0.35, and $0.02

The number of $0.35 stamps = 2 × The number of $0.50 stamps - 9

Let, x represent the number of $0.50 stamps Lashawn used to mail the package

We have;

The number of $0.50 stamps Lashawn used to mail the package = x

The number of $0.35 stamps = 2 × x - 9 = 2·x - 9

The number of $0.35 stamps = 2·x - 9

The number of $0.02 stamps = 44 - x - (2·x - 9) = 44 - x - 2·x + 9 = 53 - 3·x

The number of $0.02 stamps = 53 - 3·x

Which gives;

0.5 × x + 0.35 × (2·x - 9) + 0.02 × (53 - 3·x) = 15.01

0.5·x + 0.7·x - 3.15 + 1.06 - 0.06·x = 15.01

1.14·x - 2.09 = 15.01

1.14·x = 15.01 + 2.09 = 17.1

x = 17.1/1.14 = 15

x = 15

The number of $0.50 stamps Lashawn used to mail the package = x = 15 stamps

The number of $0.50 stamps Lashawn used = 15 stamps

The number of $0.35 stamps Lashawn used = 2·x - 9 = 2 × 15 - 9 = 21 stamps

The number of $0.02 stamps Lashawn used = 53 - 3·x = 53 - 3 × 15 = 8 stamps.

Answer:

  C.  142°

Step-by-step explanation:

You want the angle between vectors u=3i+√3j and v=-2i-5j.

There are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:

  u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest

You can find the angles of the vectors individually, and subtract those:

  u = |u|∠α

  v = |v|∠β

  θ = α - β

When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:

  \(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)

This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.

A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.

__

Additional comment

The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.

The dot-product relation will work with 3D vectors as well as 2D vectors.

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The score of the top 2.5% of the applicants would be at least 610.

To find the score of the top 2.5% of the applicants, we need to use the z-score formula:

z = (x - μ) / σ

where x is the score we want to find, μ is the mean (460), σ is the standard deviation (80), and z is the z-score corresponding to the area under the normal curve to the right of x.

We want to find the z-score such that the area to the right of z is 0.025 (since we're looking for the top 2.5%). Using a table or calculator, we find that the z-score corresponding to an area of 0.025 to the right is approximately 1.96.

So,

1.96 = (x - 460) / 80

Solving for x, we get:

x = 1.96 * 80 + 460 = 610.8

Rounding to the nearest integer, we get 610. Therefore, the score of the top 2.5% of the applicants would be at least 610.

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Answer:

Multiply both sides by 99

Step-by-step explanation:

k = 4257

Answer:

I guess it would help you

The statement describes the incidence measure of occurrence, which refers to the number of new cases of a disease or condition that occur in a defined population over a specific period of time.

This statement describes the incidence rate of flu among students living in Dunedin hostels.
The incidence rate is a measure of occurrence that calculates the number of new cases (in this case, students getting sick with the flu) in a specific population (150 students in Dunedin hostels) over a specific time period (3 months). This rate helps us understand the frequency at which the flu is affecting this particular group of students

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In order to know if a triangle is a right triangle on a coordinate plane, you can find the lengths of all three sides of the triangle using the distance formula and apply the Pythagorean theorem.

Find the lengths of the three sides of the triangle using the distance formula.

Once you have the lengths of the sides, check if any of the three sides satisfy the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In other words, if a² + b² = c², where c is the longest side, then the triangle is a right triangle.

If one of the sides satisfies the Pythagorean theorem, then the triangle is a right triangle.

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Answer:

nonlinear

Step-by-step explanation:

The graph doesn't have a constant rate of change (notice how it is flat for a while), and it is therefore nonlinear.

Answer:

nonlinear and constant

Step-by-step explanation:

not sure if this is multi choice but its nonlinear and constant.

Answer:

use desmos to graph it

Step-by-step explanation:

heres a picture

Answer: the answer is inside the triangle

Answer:

The value of the investment V(t) after t years is $562.43

Step-by-step explanation:

Here, we are interested in calculating the balance V(t) after 3 years given the information in the question.

We are to use the given formula.

From the question;

V(t) = ?

P= $500

t = 3 years

r = 4% = 4/100 = 0.04

n = 1

Substituting these values into the formula, we have ;

V(t) = 500( 1 + 0.04/1)^(3)

V(t) = 500(1.04)^3

V(t) = 562.432

The position value, r(t) is equals to the (t³/6)k + 2j and velocity value, v(t) is equals to ( t²/2 )k + 4i , for a(t) = tk, v(0) = 4i, r(0) = 2j.

Acceleration is defined as the rate of change of the velocity of an object with respect to time. Accelerations are vector quanty.

a = dv/dt

We have the following informations are available,

Initial velocity, v(0) = 4i

Initial position, r(0) = 2j

Acceleration at any time "t",

a(t) = tk

we have to determine the value of v(t) and r(t).

As we know, a(t) = dv(t)/dt = tk

integrating the above equation ,

v(t) = ∫tk dt = ( t²/2 )k + c

at t = 0 , v(0) = 0 + c = 4i ( since, v(0) = 4i

=> c = 4i

So, v(t) = ( t²/2 )k + 4i

Also, velocity is calculated by derivative of postion (r) with respect to time.

=> v(t) = dr(t) /dt

=> r(t) = ∫ v(t) dt

=> r(t) = ∫ ( t²/2 )k dt

integrating value of the right hand side,

r(t) = ( t³/2×3 )k +d

= (t³/6)k + d

At t = 0, r(0) = (0/6)k + d

=> r(0) = d = 2j

so, r(t) = (t³/6)k + 2j

Hence, the required position and velocity are

(t³/6)k + 2j and ( t²/2 )k + 4i.

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Therefore, In the figure, a∥b  angle m∠7 = 34° .

An angle is a figure in Euclidean geometry made up of two rays that share a vertex, or common terminus, and are referred to as the sides of the angle. Angles of two rays lie in the plane containing the rays. Angles can also result from the intersection of two planes. Dihedral angles are the name given to them.

Here,

Given that a and b are parallel lines,

∠3 and ∠7  are corresponding angles and congruent

m∠3 = 34°

thus ,m∠7 =m∠3 = 34°

so, m∠7 = 34°

Therefore, In the figure, a∥b  m∠7 = 34° .

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Answer:

A

Step-by-step explanation:

at least are key words for   \(\geq\) symbol

Area is L x W and since you have W its basically:

\(33x\geq 165\)

False. The frequency polygon and the histogram are two different ways to represent data, and they have distinct characteristics.

A frequency polygon is a line graph that displays the distribution of a quantitative variable. It shows the frequency of each value or class interval on the horizontal axis and the corresponding frequencies on the vertical axis. The points on the graph are connected to form a line, which gives a visual representation of the data distribution.

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Answer:

Step-by-step explanation: