A pushing force of 7 N to the right is applied to a book on a table. A frictional force of 3 N is applied in the opposite
direction. In which direction will the book move? (1 point)
O The book will move to the left.
O The book will move to the right
O More information is needed.
O The book will stay stationary.

Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

53.5gram.

Explanation

Explanation: number of moles = number of molecule ÷ avogadro's number. => moles = 6.022 × 10²³ ÷ 6.022 × 10²³ = 1 mole. mass of 1 mole of NH4Cl = 1 × molar mass.

Answer:

oxygen, silicon, iron, calcium, sodium

Explanation:

these are all found in space rocks known as meteorites. hope this helps :)

Answer:

3.75 g/mL

Explanation:

Density can be calculated using the following formula:

Density = mass (g) / volume (mL)

You have been given the mass of the mineral sample (75 g). To find the volume, you need to determine the amount of space that the sample takes up when it is placed in the water. This can be done by subtracting the initial water volume from the final water volume.

Volume = Final - Initial

Volume = 40 mL - 20 mL

Volume = 20 mL

Now, you can calculate the density of the mineral sample.

Density = mass / volume

Density = 75 g / 20 mL

Density = 3.75 g/mL

Answer:

Explanation:

Givens

The volume is the tricky part of this question. You are using the graduated cylinder to measure volume. The rise in the reading of the graduated cylinder = the volume of the sample.

Volume = 40 mL - 20 mL = 20 mL

Mass = 75 grams

Formula

Density = mass / volume

Solution

Density = 75 / 20 = 3.75

Answer

Density = 3.75

Cations are formed through lose of electrons and thus, possess positive charge. Cations has smaller ionic radius than the neutral atom, because, they have are fewer  electrons and thus experience more nuclear attractive pull.

Cations are charged particles or ions formed by the lose of electrons from the neutral atom. Atoms acquires positive charge when they lose electrons and acquire negative charge by gaining electrons  and the negative ions are called anions.

For example, Na metal loses one electrons to form the cation Na+. Similarly Mg loses two electrons, to form Mg²⁺  ion. When these atoms loses electrons, the outermost shell can be emptied and the atomic radius shrinks to the penultimate shell.

Similarly, as the number of electrons reduces, the screening of electron from neighboring electrons reduces results in greater nuclear attractive pull and thereby the atomic radius shrinks to smaller than the neutral atom.

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The resulting pH of the solution is 1.74(approx).

To solve this problem, we need to use the concept of acid-base equilibrium and the pH scale. The addition of sulfuric acid will increase the concentration of H+ ions in the solution, which will shift the equilibrium of the \(H_2S\)/HS- system. We can use the following equation to calculate the pH of the resulting solution:

Ka = [H+][HS-]/\(H_2S\)]

where Ka is the acid dissociation constant for \(H_2S\), [\(H_2S\)], [HS-], and [H+] are the concentrations of the \(H_2S\), HS-, and H+ ions, respectively.

First, we need to calculate the initial concentrations of\(H_2S\) and HS- in the solution:

[\(H_2S\)] = 0.505 M

[HS-] = 0.505 M

Next, we need to calculate the amount of H+ ions added to the solution by 1 mL of concentrated sulfuric acid. To do this, we can use the following equation:

[H+] = (n/V) = (18.4 mol/L) x (1x\(10^{-3}\) L) = 1.84 x\(10^{-2}\)mol

where n is the amount of sulfuric acid added in moles, V is the volume of the solution in liters, and 18.4 mol/L is the concentration of the sulfuric acid.

Now, we can calculate the new concentrations of \(H_2S\), HS-, and H+ ions in the solution:

[\(H_2S\)] = [\(H_2S\)]0 - [H+] = 0.505 - 1.84x\(10^{-2}\)= 0.486 M

[HS-] = [HS-]0 + [H+] = 0.505 + 1.84x\(10^{-2}\) = 0.524 M

[H+] = 1.84 x \(10^{-2}\)M

Finally, we can use the equation for Ka to calculate the pH of the resulting solution:

Ka = 1.1 x \(10^{-7}\)

[H+] x [HS-]/[\(H_2S\)] = Ka

pH = -log[H+]

Substituting the values, we get:

(1.84 x \(10^{-2}\)) x (0.524)/(0.486) = 1.98 x \(10^{-2}\)

pH = -log(1.98 x \(10^{-2}\)) = 1.74(approx)

Therefore, the resulting pH of the solution is 1.74(approx)

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B is metamorphism

A is Cementation

The main processes in the rock cycle are:

Weathering: This is the physical or chemical breakdown of rocks into smaller fragments by natural forces such as wind, water, and ice. Weathering can occur through mechanical weathering (e.g. freeze-thaw cycles, abrasion, and root action) or chemical weathering (e.g. oxidation, hydrolysis, and carbonation).

Erosion: This is the process by which weathered materials are transported and removed from their original location by agents such as water, wind, or ice.

Deposition: This is the process by which sediments or rocks are laid down or deposited in a new location after being transported by erosion.

Compaction: This is the process by which sediments are squeezed and packed together by the weight of overlying sediments, which causes them to become more tightly packed and solid.

Cementation: This is the process by which minerals in the groundwater (e.g. silica, calcite, or iron oxide) precipitate out of solution and bind the sediments together into solid rock.

Metamorphism: This is the process by which rocks are subjected to high temperatures, pressures, and chemical reactions that change their physical or chemical properties, resulting in the formation of metamorphic rocks.

Melting and solidification: This is the process by which rocks are melted by high temperatures, and then cooled and solidified to form igneous rocks.

By undergoing these processes, rocks can be transformed from one type to another over time, in a cyclical process that repeats itself over millions of years.

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First, we have to remember what a mass percentage means (in this particular case):

It is the amount of each element in a compound, and it is calculated as follows:

The addition of the different mass percentages is equal to 100%.

In this case, we have the percentage of one of the elements of the compound, we can make the respective subtraction:

Then, the answer is that the iodine mass percentage is 86.4%

Answer:

The correct answer is chemical change because both a color change and a solid formation were observed, which provide strong evidence of a new substance.

A physical change is a change in the state of a substance, such as a change from a solid to a liquid or a change from a liquid to a gas. A chemical change is a change in the composition of a substance, such as the formation of a new substance.

When potassium iodide and lead nitrate are mixed, a yellow precipitate forms. This precipitate is a new substance that was not present before the two substances were mixed. Therefore, the change that occurs when potassium iodide and lead nitrate are mixed is a chemical change.

The other answers are incorrect.

* Answer 1 is incorrect because the observation of a solid forming is not evidence of a state change. A state change is a change in the physical state of a substance, such as a change from a solid to a liquid or a change from a liquid to a gas. The formation of a precipitate is not a state change, but rather a chemical change.

* Answer 2 is incorrect because the color change of the mixture is evidence of a chemical change. When two substances are mixed and a new substance is formed, the new substance may have a different color than the original substances.

* Answer 3 is incorrect because the statement "two substances were mixed, which always results in the formation of a new substance" is not always true. For example, if you mix two different types of liquids, you may not get a new substance. Instead, you may just get a mixture of the two liquids.

The reaction between potassium iodide and lead nitrate results in a chemical change because a color change and solid formation, indicative of a new substance, are observed.

When potassium iodide and lead nitrate are mixed, there is a chemical change that takes place. This is because both a color change and a solid formation were observed, which provide strong evidence of a new substance. In this reaction, two new compounds are formed - lead iodide and potassium nitrate - which is a clear indication of a chemical change. This process is not easily reversible, further supporting it being a chemical change.

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We have our solute = NaCl

We need to find the percent of this solution, given as % (w/v)

% w/v: X grams of solute ------ 100 mL of solution

40 g are diluted in 0.5 mL, therefore:

40 g NaCl ------- 0.5 mL

X ------- 100 mL

X =

The significant figures correspond to the digits that are part of a number, the digits equal to zero that are at the beginning and at the end of a number are not counted, but those that are in the middle must be counted. Let's see some examples to understand better:

We also see in the last example a number written in scientific notation. The power of 10 and its exponent are not counted as digits, so it only has one significant figure.

Moles can be converted to liters by the use of the stoichiometry of the reaction and the gas laws.

To convert moles to liters, you need to use the Ideal Gas Law. The Ideal Gas Law states that the number of moles of a gas is proportional to its volume at a given temperature and pressure. The equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

By rearranging the equation, you can find the volume of a gas in liters when the number of moles is known:

V = nRT / P

Since the volume is in liters, the number of moles can be converted to liters by multiplying it by the volume.

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This problem is providing the mass of gummy bears which are assumed to contain 13 g of sucrose, which undergoes combustion and produces -214.3kJ of heat according to the following:

In chemistry, when a fuel undergoes combustion, a reaction with oxygen, it produces carbon dioxide and water in a complete combustion. In such a way, with the given reaction, we can write the heat of reaction as -11,286 kJ per mole of reaction:

\(\Delta H=-11,286\frac{kJ}{mol\ rxn}\)

Which means that if we need the total heat released by 13 g of sucrose, one must apply the following dimensional analysis including this fuel's molar mass (342.3 g/mol):

\(Q=-11,286\frac{kJ}{mol\ rxn}*\frac{1mol\ rxn}{2molC_1_2H_2_2O_1_1}*13gC_1_2H_2_2O_1_1 *\frac{1molC_1_2H_2_2O_1_1}{342.3gC_1_2H_2_2O_1_1} \\\\Q=-214.3kJ\)

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Answer:

B. Chemically reactive

Explanation:

A Chemically reactive element is an element that is likely to combine with another element to form new substances

The reactivity of the element depends on the number of electrons in the outermost energy level and even the distance of the outermost energy level from the nucleus.  From the periodic table, Fluorine is the most reactive non-metal while francium is the most chemically reactive metal

Transverse and longitudinal waves are the two types of waves. Whereas longitudinal waves are similar to those of sound, consisting of alternating compressions and rarefactions in a medium, transverse waves are like those on water, with their surface moving up and down.

Which four types of waves are there?

We are aware that the transfer of energy is connected to waves. Physics studies a wide variety of waves. Certain waves can travel through a material medium, but other waves cannot.

What types of waves are there?

The way that mechanical waves move determines their classification. Surface waves, longitudinal waves, and transverse waves are all types of mechanical waves that move through a medium.

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Answer:

5H2 + 4NO = 2N2 +4H2O + H2

Explanation:

Reactants:

Five molecules that contains two hydrogen = 5H2

Four molecules that contains one nitrogen and one oxygen = 4NO

Products:

Two molecules that contains two nitrogen = 2N2

Four molecules that contains one oxygen and two hydrogen = H2O

One molecules that contains two hydrogen = 1H2 or H2

The balanced chemical equation for the reaction will be: 5 H₂ + 4 NO → 2 N₂ + 4 H₂O + H₂, and there is no limiting reactant in this reaction.

To write the balanced chemical equation for the reaction, let's first identify the reactants and products based on the information provided:

Reactants:

5 molecules contain 2 white spheres (Hydrogen): 5 H₂

4 molecules contain 1 red (Oxygen) and 1 blue (Nitrogen) sphere: 4 NO

Products:

2 molecules contain 2 blue spheres (Nitrogen): 2 N₂

4 molecules contain 1 red (Oxygen) and 2 white (Hydrogen) spheres: 4 H₂O

1 molecule contains 2 white spheres (Hydrogen): 1 H₂

Now, let's write the balanced chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation:

Reactants: 5 H₂ + 4 NO

Products: 2 N₂ + 4 H₂O + 1 H₂

The balanced chemical equation for the reaction is:

5 H₂ + 4 NO → 2 N₂ + 4 H₂O + H₂

Now, let's determine the limiting reactant:

From the balanced equation, we can see that the stoichiometric ratio between H₂ and NO is 5:4. This means that for every 5 molecules of H₂, we need 4 molecules of NO for the reaction to proceed completely.

Since we have 5 molecules of H₂ and 4 molecules of NO, both reactants are present in the exact stoichiometric ratio required for the reaction. Therefore, neither H₂ nor NO is in excess, and both will be fully consumed during the reaction. As a result, there is no limiting reactant in this reaction.

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--The given question is incomplete, the complete question is

"Oxygen is represented by a red sphere. Nitrogen is represented by a blue sphere. Hydrogen is represented by a white sphere. In the reactants there are five molecules that contain two white spheres and four molecules that contains one red and one blue sphere. In the products there are two molecules that contain two blue spheres, four molecules that contain one red and two white spheres, and one molecule that contains two white spheres. What is the chemical formula for the limiting reactant in the reaction shown? chemical formula: Write the balanced chemical equation for the reaction, using lowest whole-number coefficients."--

Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.

Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.

Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.

By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

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Answer:

eight electrons

Explanation:

Most of the elements important in biology need eight electrons in their outermost shell in order to be stable, and this rule of thumb is known as the octet rule. Some atoms can be stable with an octet even though their balance she'll is the 3n shell, which can hold up to 18 electrons.

Answer:

100.052 degrees C

Explanation:

It has been experimentally proven that the addition of solute to water will result in boiling point elevation due to the presence of more molecules. The boiling point elevation refers to the tendency of a solvent's boiling point to increase when an impurity (a solute) is added.

The formula of boiling point elevation is

\(\Delta T_{b} \ = \ K_{b} \times m\), where m is the molality defined as the number of moles of solute per kilograms of solvent and \(K_{b}\) is the molal boiling point elevation constant.

Given that the molal boiling point elevation constant of water is 0.512 \(^{\circ}\mathrm{C}{m}^{-1}\),

\(\Delta T_{b} \ = 0.512 \ ^{\circ}\mathrm{C}m^{-1} \times \displaystyle\frac{14.2 \ \mathrm{g}}{213 \ \mathrm{g \ mol^{-1} \ \times \ 0.655 \ kg \ (H_{2}O)}} \\ \\ \Delta T_{b} \ = \ 0.052 \ ^{\circ}\mathrm{C}\)

To evaluate the boiling point of the aluminium nitrate solution,

\(T_{b} \ (\mathrm{solution}) \ = \ T_{b} (\mathrm{H_{2}O}) \ + \ \Delta T_{b} \\ \\ \-\hspace{2.06cm} = \ 100^{\circ}\mathrm{C} \ + \ 0.052^{\circ}\mathrm{C} \\ \\ \-\hspace{2.06cm} = 100.052^{\circ}\mathrm{C}\)

The final temperature of the solution is  20 °C.

Given that :

volume of HNO₃ = 0.33 L

molarity = 0.500 M

no. of moles HNO₃ = 0.33 × 0.500

                     = 0.165 mol

moles of Ba(OH)₂ = 0.33 × 0.250

                             = 0.082 mol

Q = ΔH × n

Q = - 52600 J/mol × 0.165 mol

Q = - 8679 J

total volume = 330 mL +330 mL = 660 mL

Density = mass / volume

mass = 1 g/mL × 660 mL

mass = 660 g/mL

now, the change in temperature can be calculated by following formula :

Q = mc ( ΔT )

Q = mc ( T2 - T1 )

- 8679 = 660× 4.184 ( T2 - 18.46 °C)

T2 = 20 °C

Thus, A quantity of 3.30 × 10² mL of 0.500 M HNO3 is mixed with 3.30 × 10² mL of 0.250 M Ba(OH)₂ in a constant-pressure calorimeter of negligible heat capacity. The initial temperature of both solutions is the same at 18.46°C. The heat of neutralization when 1.00 mol of HNO₃ reacts with 0.500 mol Ba(OH)₂ is −56.2 kJ/mol. Assume that the densities and specific heats of the solution are the same as for water (1.00 g/mL and 4.184 J/g · °C, respectively).  the final temperature of the solution is 20 °C.

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The volume of hydrogen gas produced in the reaction of 73 grams of zinc and 73 grams of hydrochloric acid (under normal conditions) is approximately 22.4 liters.

To calculate the volume of hydrogen gas produced in the reaction of zinc and hydrochloric acid, we need to use the principles of stoichiometry and the ideal gas law.

First, let's write the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):

Zn + 2HCl →\(ZnCl_2\)+ H2

From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. To determine the number of moles of zinc and hydrochloric acid, we need to convert the given masses into moles.

The molar mass of zinc (Zn) is approximately 65.38 g/mol, so 73 grams of zinc is equal to:

73 g Zn * (1 mol Zn / 65.38 g Zn) ≈ 1.116 mol Zn

Similarly, the molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol, so 73 grams of HCl is equal to:

73 g HCl * (1 mol HCl / 36.46 g HCl) ≈ 2.002 mol HCl

According to the balanced equation, the reaction produces one mole of hydrogen gas for every two moles of hydrochloric acid. Therefore, since we have 2.002 moles of HCl, we expect to produce half that amount, or approximately 1.001 moles of hydrogen gas.

To calculate the volume of hydrogen gas, we can use the ideal gas law, which states:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. In this case, we assume the reaction is conducted under normal conditions, which means a pressure of 1 atmosphere and a temperature of 273.15 Kelvin.

Rearranging the equation to solve for V, we have:

V = nRT / P

Substituting the values, we get:

V = (1.001 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K) / (1 atm) ≈ 22.4 L

Therefore, the volume of hydrogen gas produced in the reaction is approximately 22.4 liters.

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Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

spinning

Explanation:

Answer:

e) ⁵²Cr

Explanation:

The general form of alpha decay is as follows:

\(\boxed{ ^A_ZX \ \ \rightarrow \ \ ^{A - 4} _{Z - 2} \ Y \ \ + \ \ ^4_2 \alpha}\).

From this, we can see that during alpha decay, the mass number decreases by 4 and the atomic number decreases by 2.

Therefore, we need to find a nucleus that has 4 more nucleons (i.e., a mass number that is 4 more) than that of Ti-48, which is 48 + 4 = 52.

The only option with a nuclear number of 52  is ⁵²Cr, and therefore, Ti-48 is produced by the alpha decay of ⁵²Cr.

If 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C, the molar mass of the gas is 112 g/mol

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Volume = 21.5L

Pressure = 140 kPa

Temperature = 318 K

Using ideal gas equation, PV = nRT

                            140 × 21.5 = n × 8.314 × 318

                                      n = 1.138 moles

Mass = moles × molar mass

Molar mass = 128 ÷ 1.138

= 112 g/mol

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Answer:

Option F 6 will be the answer.

PPE should be worn in the presence of chemical hazards to protect the individual from potential harm. Its usage should be dictated by the presence of the hazard, not by memory or peer action.

You should wear Personal Protective Equipment (PPE) to protect yourself from chemical hazards whenever chemical hazards are present (Option B). PPE is designed to protect you from harmful exposure and injuries. The use of PPE must be based on the hazard presented, not simply when remembered or when others are using it. Hence, whenever you are dealing with chemical hazards, it's crucial to wear the appropriate PPE, which could include items such as gloves, eye protection, protective clothing, and respirators.

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