A proton (q=+e) and an alpha particle (q=+2e) are accelerated by the same voltac V. Part A Which gains the greater kinetic energy? The proton gains the greater kinetic energy. The alpha particle gains the greater kinetic energy. They gain the same kinetic energy. By what factor? Express your answer using one significant figure.

Explanation:

Using Cosine rule, we have 5² = 3² + 4² - 2(3)(4)(cosx).

=> cosx = 0, x = 90°.

Answer:

0.13 km/s²

Explanation:

Convert hours to seconds

1 hour = 60 seconds (60) = 3600 seconds

\(\frac{190}{3600}\) = 0.052778

\(\frac{0.052778}{4s}\) = 0.013195

0.13 km/s^2 (Round the three decimals)

The acceleration of a roller coaster that goes from 0 to 190 km/h in 4 seconds is 0.13 km/s².

It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.

It is given that:

Predict the acceleration of a roller coaster that goes from 0 to 190km/h in 4 seconds.

As we know from the unit conversion:

1 hour = 60 minutes

60 minutes = 3600 seconds

190km/h in km/s

= 190/3600

= 0.0527

The acceleration of a roller coaster = (v2 - v1)/t

The acceleration of a roller coaster = (0.0527 - 0)/4

The acceleration of a roller coaster = 0.13 km/s²

Thus, the acceleration of a roller coaster that goes from 0 to 190 km/h in 4 seconds is 0.13 km/s².

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Answer:

The final translational seed at the bottom of the ramp is approximately 4.84 m/s

Explanation:

The given parameters are;

The radius of the sphere, R = 2.50 cm

The mass of the sphere, m = 4.75 kg

The translational speed at the top of the inclined plane, v = 3.00 m/s

The length of the inclined plane, l = 2.75 m

The angle at which the plane is tilted, θ = 22.0°

We have;

\(K_i\) + \(U_i\) = \(K_f\) + \(U_f\)

K = (1/2)×m×v²×(1 + I/(m·r²))

I = (2/5)·m·r²

K =  (1/2)×m×v²×(1 + 2/5) = 7/10 × m×v²

U = m·g·h

h = l×sin(θ)

h = 2.75×sin(22.0°)

∴ 7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) = 7/10 × 4.75×\(v_f\)² + 0

7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) ≈ 77.93

∴ 77.93 ≈ 7/10 × 4.75×\(v_f\)²

\(v_f\)² = 77.93/(7/10 × 4.75)

\(v_f\) ≈ √(77.93/(7/10 × 4.75)) ≈ 4.84

The final translational seed at the bottom of the ramp, \(v_f\) ≈ 4.84 m/s.

Therefore, even though Europa has a diameter that is only one-fourth that of Earth, her ocean may hold twice the amount of water as Earth's seas do.The immense and unfathomably depths ocean of Europa is regarded as the best area to look for life outside of Earth.

As a result of the liquid water's close proximity to the silicate mantle, Europe is one of the finest options for habitability.The amount of radiation that strikes the moons from Jupiter is a crucial component in determining whether or not they are habitable.

Europa would need to contain the necessary chemical components for life's chemistry in order to be potentially habitable.These include the frequently occurring elements carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur, which are thought to have been present on Europa at the time it originated.

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The angle of contact between the lining and the drum is 22 degrees (approximate).

Given data:

Torque = 13,000 in-Ibf

Width of drum (w) = 2 inches

Radius of drum (r) = 10 inches

Maximum pressure between lining and drum = 100 psi

Coefficient of friction (μ) = 0.25Formula used:

Torque = (P × r) / μ = (P × w × r) / 2

Here, P = maximum pressure between lining and drum

We know that, Torque = (P × w × r) / 2So, P = (2 × Torque) / (w × r)Putting the given values, we get,

P = (2 × 13000) / (2 × 10)P = 650 psi

Now, torque can also be written as,

Torque = P × μ × r × (180 / π)

From this equation, we can find the angle of contact (θ).

θ = 180 × Torque / (π × P × r² × μ)

Putting the given values, we get,

θ = 180 × 13000 / (π × 650 × 10² × 0.25)θ

= 21.98 degrees

≈ 22 degrees

Therefore, the angle of contact between the lining and the drum is 22 degrees (approximate).

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Answer:

a) The mass of the skateboard is 18.4 kg.

b) The student would have to jump with a velocity of 7.85 m/s to have a final speed of 6.05 m/s.

Explanation:

a) The problem states that a 47 kg student runs down the sidewalk and jumps with a horizontal speed of 4.33 m/s onto a stationary skateboard. After the student jumps onto the skateboard, the student and skateboard move down the sidewalk with a speed of 4.08 m/s. We need to find the mass of the skateboard.

To solve this problem, we can use the principle of conservation of momentum, which says that the total momentum of a system remains constant when there are no external forces acting on it. We can write the equation as:

(m_student * v_student) + (m_skateboard * 0) = (m_student + m_skateboard) * v_final

where m_student is the mass of the student, v_student is the velocity of the student before jumping onto the skateboard, m_skateboard is the mass of the skateboard, and v_final is the final velocity of the student and skateboard after the jump.

Since the skateboard is initially at rest, its velocity is zero. We can simplify the equation as:

(m_student * v_student) = (m_student + m_skateboard) * v_final

Substituting the given values, we get:

(47 kg * 4.33 m/s) = (47 kg + m_skateboard) * 4.08 m/s

Solving for m_skateboard, we get:

m_skateboard = 18.4 kg

Therefore, the mass of the skateboard is 18.4 kg.

b) The problem asks how fast the student would have to jump to have a final speed of 6.05 m/s.

To solve this problem, we can again use the principle of conservation of momentum. The equation would be the same as before:

(m_student * v_student) + (m_skateboard * 0) = (m_student + m_skateboard) * v_final

where v_final is the final velocity of the student and skateboard, and we need to find v_student, the velocity of the student before jumping onto the skateboard.

We can rearrange the equation as:

v_student = (m_student + m_skateboard) * v_final / m_student

Substituting the given values, we get:

v_student = (47 kg + 18.4 kg) * 6.05 m/s / 47 kg

Simplifying, we get:

v_student = 7.85 m/s

Therefore, the student would have to jump with a velocity of 7.85 m/s to have a final speed of 6.05 m/s.

Answer:

Air steel water

Explanation:

The language of the given pushdown automaton (PDA) can be described as follows:

The PDA has a stack alphabet consisting of symbols 'a', 'b', 'z', '6', '1', '۸', '2', '9', '0', 'x', 'y'. 'z' represents the stack end symbol.

The transitions of the pushdown automaton (PDA) are as follows:

Thus, the language accepted by this PDA is characterized by a sequence of 'a's followed by a sequence of 'b's, where the number of 'b's is three times the number of 'a's, and each 'b' is followed by a corresponding sequence of '90', '91', '92', 'a', 'b', 'b', 'b', '1', 'b', 'b', '1', and ending with '1'.

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Answer: b

Explanation: just did it

Based on the information, B. The temperature is not rising because the heat is being used to break the connections between the molecules.

The average kinetic energy of its molecules directly relates to the temperature of a material, not the potency of the intermolecular bonds between them.

By heating up a substance, it causes the kinetic energy of its molecules to grow, which makes them vibrate and move what much faster than before. Though this increased motion can disrupt said intermolecular bonds, it does not take heat energy from them in order to destroy them. Instead, that heat energy is taken in by the particles, transforming it into kinetic energy.

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The electrostatic force between an electron and a proton separated by 27.0 × 10⁻⁹ is 3.1 × 10⁻¹³ Newtons.

The electrostatic force exists between two charges placed at a distance. The magnitude of electrostatic force depends on the magnitude of each charge and the distance between them. When two positive charges or two negative charges are brought together, then the two charges repel each other.

F = (Ke q₁q₂)/ r²

where, F is the electrostatic force,

Ke is the Coulombs constant = 8.987 × 10⁹ N. m². C⁻²

q₁ is the charge of an electron = -1.602 × 10⁻¹⁹ C

q₂ is the charge of a proton = 1.602 × 10⁻¹⁹ C

r is the distance between the two charges = 27.0 × 10⁻⁹

F = (8.987 × 10⁹)(1.602 × 10⁻¹⁹)(1.602 × 10⁻¹⁹)/ (27.0 × 10⁻⁹)²

F = 8.987 × 10⁹ × 2.566 × 10⁻³⁸/ 729 × 10⁻¹⁸

F = 23.060 × 10⁻²⁹/ 729 × 10⁻¹⁸

F = 0.031 × 10⁻¹¹

F = 3.1 × 10⁻¹³ N

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ANSWER

10 Hz

EXPLANATION

Given:

• The wavelength of a periodic wave, λ = 1.6 m

• Its speed, v = 16 m/s

Find:

• The wave frequency, f

The frequency of a wave is given by the quotient between the wave's speed and its wavelength,

Replace the known values and solve,

Hence, the frequency of the wave is 10 Hz.

At -6 Degree Celsius the two materials (copper wire and iron wire) have the same resistance.

Given data:

Temperature is, T' =  20.0ºC.

Resistance of copper wire is, R = 0.500 Ω .

Resistance of iron wire is, R' = 0.525 Ω.

The resistance of a wire is known to change with temperature.

Resistance has proportional effect due to temperature as resistance increase with increasing the temperature. So, the relation is given as,

\(R''=R (1+\alpha(T-T')\)

Here, T is the final temperature and \(\alpha\) is the temperature coefficient.

For Copper,\(\alpha\) is 0.004021 and for Iron,it is 0.005671.

Then,

 For Copper wire,

\(R''=0.500 \times (1+0.004041(T-20)) ........................(1)\)

  For Iron wire,

\(R''=0.525 \times(1+0.005671(T-20)).......................(2)\)

For same resistance,compare equations (1) and (2) as,

\(0.500 \times (1+0.004041(T-20))=0.525 \times(1+0.005671(T-20))\)

\(0.500+(2.02\times 10^{-3})T-0.040=0.525+(2.97\times 10^{-3})T-0.059\)

\(-6\times 10^{-3} =9.5\times 10^{-4} \times T\)

\(T=-6.31 $$ ^\circ C $$\)

Thus,we can conclude that at \(-6 $$ ^\circ C $$\) the two materials have the same resistance.

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COMPLETE QUESTION

A copper wire has a resistance of 0.500 Ω at 20.0ºC , and an iron wire has a resistance of 0.525 Ω at the same temperature. At what temperature are their resistances equal?

The required initial speed v₀ of the bullet when the velocity and mass of the bullet are specified is calculated to be 20.04 m/s.

The height that the block has ascended to is what counts, not the cord's tension.

When it reaches its peak, it will be moving at a pace of zero and therefore have no kinetic energy. It will, however, be more energetically prospective than it was initially.

ΔEp = (m₁ + m₂) g h

The kinetic energy of the projectile was used to lift the block that had the bullet embedded in it.

Ec = 1/2 m₂ v₀²

Due to the bullet's complete conversion of its kinetic energy into potential energy, these two energies are identical. Therefore,

(m₁ + m₂) g h = 1/2 m₂ v₀²

To find out v₀,

v₀ = √[2(m₁ + m₂)gh/m₂]

It is given that, m₁ = 0.8 kg

m₂ = 20g = 20/1000 = 0.02 kg

Height h = 0.5 m

v₀ = √[2(m₁ + m₂)gh/m₂] = √[2(0.8 + 0.02)9.8(0.5)/0.02] = 20.04 m/s

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Answer:

The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure. Note that the fixed points are defined using common physical phenomena so that they can be easily reproduced.

Answer:

Steam point

Explanation:

The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.

Answer:nah u took my points I take urs

Explanation:

Answer:

I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.

When calculating work done by forces, the work of an internal force does not have to be considered because internal forces act in equal but opposite collinear pairs.

Internal forces are forces that act between different parts of the same object or system. These forces can cause deformation or changes in the shape of the object, but they do not contribute to the net work done on the object as a whole. This is because internal forces occur in equal but opposite pairs, meaning that the work done by one internal force is canceled out by the work done by its counterpart. As a result, when calculating the work done by external forces on an object or system, the work of internal forces is not considered since they do not contribute to the overall net work. The focus is on the external forces that interact with the object or system from its surroundings. Therefore, option B) the forces act in equal but opposite collinear pairs is the correct explanation for why the work of internal forces does not have to be considered.

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The angular frequency of the torsional oscillations of the disk is approximately 2.26 rad/s. We can use the formula: Angular frequency (ω) = √(Torsion constant / Rotational inertia)

To find the angular frequency of the torsional oscillations of the disk hanging from a wire, we can use the formula:

Angular frequency (ω) = √(Torsion constant / Rotational inertia)

Given that the rotational inertia (I) of the disk is 450 kg·m² and the torsion constant (k) of the wire is 2300 N·m/rad, we can substitute these values into the formula:

ω = √(2300 N·m/rad / 450 kg·m²)

Simplifying the expression, we get:

ω = √(5.111 rad²/s²)

Calculating the square root, we find:

ω ≈ 2.26 rad/s

Therefore, the angular frequency of the torsional oscillations of the disk is approximately 2.26 rad/s.

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Option A. The presence of air bubbles results in a decrease in the actual volume of gas, we know R is proportional to Volume, actually,​ we should get low values of R . So here we get more value of R . This is erroneously high.

Volume is a measure of occupied 3-dimensional area. it's far often quantified numerically through the use of SI-derived units or via various imperial or US commonplace devices. The definition of the period is interrelated with the extent.

Volume is described as the gap occupied in the boundaries of an object in three-dimensional space. it is also referred to as the capability of the object.

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Answer:

= 24.76m

= 2476 cm

Explanation:

18 meters from point of origin = 18m north 90 degrees?

17 meters from point of origin = 17m west 0 degrees?

                                                                                                        _

If these routes are one after the other then we get a triangle  |

18 side and 17 side

This means we need to do Pythagoras Theorem.

18^2 + 17^2 = c^2

sqrt 324 + sqrt 289 =  c^2

c^2 = sqrt 613 = 24.7588368

= 24.76m

Answer:

2) same size, same distance away from the mirror

Explanation:

The image formed by a plane mirror has the same size and it is at the same distance of the object. It is also reversed from left to right. So, the size and position of an image formed by a plane mirror are

2) same size, the same distance away from the mirror

Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

Answer:

A, I think, hope this helps!

Answer:

i think d because some people are talented even though they are suffering

Answer:

1. 59 Ω

2. 3 Ω

3. 0.625 kΩ

Explanation:

1. The total resistance in a series circuit is equal to the sum of the resistance.

\(R_T=R_1+R_2+R_3...\\R_T=20+19+20\\R_T=59\)

Therefore, the total resistance in the first circuit is 59 Ω.

2. The total resistance in a parallel circuit is equal to the sum of the reciprocals of the resistance.

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{6.0} +\frac{1}{12} +\frac{1}{36}+\frac{1}{18} \\\frac{1}{R_T} = \frac{1}{3} \\R_T=3\)

Therefore, the total resistance in the second circuit is 3 Ω.

3. This is another parallel circuit, so we use the same equation from above:

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{10} +\frac{1}{2} +\frac{1}{1} ...\\\frac{1}{R_T} =1.6\\R_T=\frac{1}{1.6}\)

Therefore, the total resistance in the third circuit is \(\frac{1}{1.6}\) kΩ, or 0.625 kΩ.

I hope this helps!

Answer:

Road safety can be drastically increased if all the drivers on the road were considerate. For eg, if a person is driving slow then one should be considerate enough to wait till he gives side. Also if a person is not confident and driving slow then he should be considerate enough to drive in the slow lane.

Explanation:

safety rules on the road?

Important Traffic Rules To Follow To Ensure Safety While Driving

Always wear a seatbelt. ...

Avoid distractions. ...

Do not cross the speed limits. ...

Service your car regularly. ...

Follow traffic signals. ...

Maintain lane discipline. ...

Be careful during bad weather. ...

Maintain a safe distance.

v = λf. Any electromagnetic wave traveling across empty space will travel at the speed of light, which is 3*108 m/s.As long as f = c, electromagnetic waves can be of any wavelength or frequency.

An E&M wave's direction of propagation can be determined by pointing the right hand's fingers in the direction of the field, curling them in the direction of magnetic field, then pointing the thumb in that direction.

In vacuum, all electromagnetic waves move at the same speed.About 300 million metres every sec (3.0 x 108 m/s) is what is known as the speed of light.

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As the released bar magnet approaches the coil, the falling magnet induces a counter clockwise current in the coil.The direction of the induced current in the coil is counter-clockwise.

A magnetic field exists when there is a change in magnetic flux. The change in magnetic flux is due to the relative motion between the bar magnet and the coil. The bar magnet produces a magnetic field as it falls towards the coil. The change in magnetic flux is proportional to the rate of change of the magnetic field.

Faraday's law of electromagnetic induction states that when a magnetic field that varies with time is passed through a coil, an electromotive force (EMF) is induced in it. When the magnet is dropped through the coil, the magnetic field through the coil varies, inducing an EMF in it. The EMF causes an induced current to flow through the coil. The direction of the induced current is counter-clockwise.

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