A powerful bolt of lightning can carry a current of 230 kA. part a) Treating a lightning bolt as a long, thin wire, calculate the magnitude of the magnetic field produced by such a bolt of lightning at a distance of 33m . part b) If two such bolts strike simultaneously at a distance of 33m from each other, what is the magnetic force per meter exerted by one bolt on the other?

Answer: an object in motion stays in motion unless acted upon by an unbalanced force

Explanation: this is Newton’s first law of motion, which states that an object, whether in a moving or resting state, will continue to stay in that state unless there is an unbalanced force that changes that state. For a moving object, an example would be friction worth the ground. For a resting object, an example would be the force of a push.

Answer: ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

Hi there!

Using Newton's Second Law:
\(F = ma\)

F = Net Force (60 N)
m = mass (30 kg)
a = acceleration (m/s²)

Solve for acceleration given the other values.

\(60 = 30a\\\\a = \frac{60}{30} = \boxed{2 \frac{m}{s^2}}\)

If the net force increases (while the mass is held constant), the acceleration will INCREASE.

If the mass of the object increases (while the net force is held constant), then the acceleration will DECREASE.

The relationship between the angles of incidence and refraction when a light ray passes across the boundary between two media with differing refractive indices is described by Snell-Descartes law.

Snell's law

n₁sinθ₁ = n₂sinθ₂

In the following equation, n1 and n2 stand for the refractive indices of the two media. θ₁ for angle of incidence (the angle between the incident ray and the normal to the boundary), and θ₂ for angle of refraction (the angle between the refracted ray and the normal to the boundary). Sometimes referred to as Snell-Descartes law, in its mathematical form.

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Answer:

Explained below.

Explanation:

Newton's first law of motion states that an object will continue in its present state of rest or continue with constant speed in a straight line except it is acted upon by an external force.

For every object in motion or at rest there is a force of friction that tries to resist its motion or prevent it from moving with constant velocity.

Now, to push it from rest you will need to apply a force large enough to overcome its static friction. Now, after that initial motion, smaller forces will have to be applied to overcome what is called sliding friction that prevents the crate from sliding which will affect the constant velocity.

Answer:

43.58 m

Explanation:

If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees

Using trigonometry ratio

Sin 5 = opposite/hypothenus

Where the hypothenus = 500m

Opposite = height h

Sin 5 = h/500

Cross multiply

500 × sin 5 = h

h = 500 × 0.08715

h = 43.58m

Therefore, the height above the starting point is equal to 43.58m

( True )  Mercury is the closest planet to the sun and has a unique orbit that takes about 88 Earth days to complete one revolution around the sun. Due to its proximity to the sun, the planet's rotation is also influenced by the sun's gravitational pull, causing it to have a slower rotation rate compared to its revolution.

A sidereal day is the time it takes for a planet to complete one rotation on its axis, relative to the fixed stars. For Mercury, one sidereal day is approximately 58.6 Earth days long.

Therefore, if two Mercury years (which is equal to two revolutions around the sun) are the same length as three sidereal days, it means that each Mercury year is approximately 1.5 sidereal days long, which is true. This can be calculated as follows:

2 Mercury years = 2 x 88 Earth days = 176 Earth days
3 sidereal days = 3 x 58.6 Earth days = 175.8 Earth days

Hence, the statement is true.

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The orange was at a height of 3.26 m above the ground.

The third equation of motion is

v² - u² = 2aS

Given is an orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground.

We can write -

[v] = 8 m/s

[a] = 9.8 m/s²

[u] = 0 m/s

Using third equation of motion, we get -

v² - u² = 2aS

64 - 0 = 2 x 9.8 x S

64 = 19.6 x S

S = 3.26 m

Therefore, the orange was at a height of 3.26 m above the ground.

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\( \blue{ \star}\)Magnetic Energy :

\( \blue{ \star}\)Gravitational Energy :

\( \blue{ \star}\)Nuclear Energy :

\( \blue{ \star}\)Thermal energy :

Answer:

a=f/p

Explanation:

p=f/a

f=p×a

this all

To accurately determine the superhero's position relative to the man at the end of the displacement, more information about the superhero's initial position and movement is required

If a man observes a superhero through a window located 30.0 m below the top of the building, the superhero's position (in m) relative to the man at the end of the displacement would depend on various factors such as the distance of the superhero's initial position from the man, the direction of the superhero's movement, and the duration of the displacement. If the superhero is moving horizontally, then their position relative to the man at the end of the displacement would be the same as their initial position, as the vertical displacement would not affect their horizontal position.

However, if the superhero is moving vertically, then their position relative to the man would change depending on the direction of their displacement.For example, if the superhero is moving upwards, then their position relative to the man would be higher than their initial position, as they would have covered a greater vertical distance. On the other hand, if the superhero is moving downwards, then their position relative to the man would be lower than their initial position.In both cases, the signs of the displacement components would be opposite, as the superhero is moving in a different direction relative to the man's position. The magnitude of the displacement would depend on the superhero's speed and the duration of the displacement.
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The event that had the greatest impact in astronomical history during this time period was the launch of Apollo 16.

The research of astronomy during the time period of 1970 - 1990 are given below as;

Date                                                   Event

1. 15 June 1974               Black Brant VC sounding rocket from White Sands.

2. 14 May 1973              Launch of Skylab, the USA's first space station

3. 26 July 1971                Launch of Apollo 15

Astronomy is a branch of science that deals with celestial bodies and their relationship with each other.

From the information given about astronomy, between the time period 1970 - 1990 as it was on the 26th of December, 1974 that the Soviet space station Salyut-4 was launched.

The event that had the greatest impact in astronomical history during this time period was the launch of Apollo 16.

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If an airplane is loaded with the Center of Gravity (CG) aft of the rear CG limit, it could increase the likelihood of inadvertent overstress and make it more difficult to flare for landing.

The Center of Gravity (CG) of an aircraft plays a crucial role in its stability and control. If the CG is located aft of the rear CG limit, it can have adverse effects on the airplane's performance. Firstly, it increases the likelihood of inadvertent overstress. When the CG is too far aft, the aircraft becomes less stable, making it more susceptible to sudden pitch changes and possible structural damage due to excessive loads. Secondly, having the CG aft of the rear limit makes it more difficult to flare for landing. Flaring is the process of raising the nose of the aircraft just before touchdown to reduce the rate of descent. With an aft CG, the aircraft's pitch control authority decreases, making it harder to perform a smooth flare and potentially leading to a harder landing. The location of the CG alone does not directly affect an aircraft's ability to recover from these situations.

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Answer:

D

Explanation:

LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL

COHETE.

\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N

The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.

The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.

The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.

net force = thrust force + weight

vertical component of net force = thrust force * cos(angle)

vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.

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Answer:

The ground pushes back on your feet with equal force

Explanation:

When you walk across the ground and push on it with your feet, the ground pushes back on your feet with an equal and opposite force.

This interpretation and knowledge is gotten from Newton's third law of motion.

It states that "action and reaction force are equal and opposite in nature".

Answer:

the answer is the second one: the ground pushes back on your feet with equal force

Explanation:

Answer:

Before sled starts to move it has a potential energy due to the elevation...and then that potential energy converted to kinetic energy due to presence of a velocity...the sled will continue to move if their is no resesive force...but however friction force is presence that cause the sled to stop....

Answer:

True

Explanation:

The Gravitational potential energy is given by:

G = mgh

m = mass of body ; g = acceleration due to gravity ; h = height

G for a ball of mass 10kg ; height of 20 meters above the ground

G = 10kg * 9.8m/s² * 20m = 1960 kgm²/s²

G for a ball of mass 1000kg at height, 0 meters :

G = 1000 * 9.8 * 0 = 0

1960 > 0

Hence, Gravitational potential energy for 10kg ball at height 20m is greater Thammfor a 1000kg ball on the ground.

Explanation:

given information

vi= 4m.s^-1

vf= 14m.s^-1

a- unknown (constant)

️t = 3s

substitute the given information onto equations of motion:

The temperature in a classroom is usually around room temperature, which typically ranges from 68-72°F (20-22°C). This means that the temperature is closest to 50°C.

Temperature is a measure of the average kinetic energy of the particles in a system. It is a physical quantity that indicates how hot or cold something is. Temperature is typically measured in units of degrees Celsius (°C) or kelvin (K). Temperature can be affected by many environmental factors, such as air pressure, radiation levels, humidity, and altitude. Heat and cold are also related to temperature, with heat being the result of increased temperature and cold being the result of decreased temperature. Temperature affects many physical and chemical processes, and is an important factor to consider when studying the behavior of matter.

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The number of the grains of salt that would be in the total mass of the sand is determined as  1.67 x 10⁶ gains.

The number of grains of salt is calculated by dividing the total mass of the sand by the mass of a single grain of salt.

Mathematically, the formula for the number of grains of salt is given as ;

1 grain of salt ----------> 0.06 mg

? grain of salt ------------> 100 g

For the mass of a grain of salt is around 0.06 mg, the number of grains that will be found in 100 grams of sand is calculated as follows;

number of grains of salt = ( mass of the sand ) / ( mass of a single grain of salt )

number of grains of salt = ( 100 g ) / ( 0.06 x 10⁻³ g )

number of grains of salt = 1.67 x 10⁶ gains

Thus, the number of the grains of salt found in the mass of the sand is a function of total mass of the sand and the mass of a single grain of salt.

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There are several revisions that Renaldo and Nasreen could make to increase the number of paper clips their electromagnet picks up:

1. Increase the number of turns of wire around the nail: By increasing the number of turns of wire around the nail, Renaldo and Nasreen can increase the strength of the electromagnet.

2. Use a thicker wire: Using a thicker wire will increase the amount of electrical current that can flow through the wire, which will increase the strength of the electromagnet.

3. Use a stronger battery: Using a stronger battery (such as a 9-volt instead of a 1.5-volt battery) will increase the amount of electrical current flowing through the wire, which will increase the strength of the electromagnet.

4. Use a ferromagnetic material for the core: Using a ferromagnetic material, such as iron or steel, for the core of the electromagnet will increase its strength.

5. Increase the length of the wire: Increasing the length of the wire will allow more electrical current to flow through it, which will increase the strength of the electromagnet.

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The energy of a photon with a wavelength of 590 nm is \(3.36 * 10^-19\)

The energy of a photon can be calculated using the equation:

E = hc/λ

where E is the energy of the photon, h is Planck's constant \((6.626 * 10^-34 J.s)\), c is the speed of light\((3.00 * 10^8 m/s)\), and λ is the wavelength of the photon in meters.

To convert 590 nm (nanometers) to meters, we can use the conversion factor:

\(1 nm = 1 * 10^-9 m\)

So, \(590 nm = 590 * 10^-9 m\)

Plugging these values into the equation, we get:

E = \((6.626 * 10^-34 J.s * 3.00 * 10^8 m/s) / (590 * 10^-9 m)\)

E = \(3.36 * 10^-19 J\)

Therefore, the energy of a photon with a wavelength of 590 nm is \(3.36 * 10^-19\)

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Answer:

They would attract one another

Explanation:

The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other negatively charged objects and neutral objects attract each other.

The ball's weight will be precisely balanced by the electric field is E = 12.25 x 10³ N/C = 12.25 KN/C

The electrostatic force caused by the electric field must be equal to the weight of the body or charge in order to balance the object's weight. Therefore,

Weight = Electrostatic Force

E q = mg

where,

Electric field = (E) =?

5 x 103 kg is the mass of the charge, or m.

g = 9.8 m/s2 is the acceleration caused by gravity.

Q equals the charge's magnitude, which is 4 C (4 x 106 C).

Therefore,

E(4 x 10⁻⁶ C) = (5 x 10⁻³ kg)(9.8 m/s²)

E = 0.049 N/4 x 10⁻⁶ C

E = 12.25 x 10³ N/C = 12.25 KN/C

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Answer:

The x-direction and y-direction refer are used to refer to the location of an object as well as to the components of the motion of the object in a two dimensional space

Explanation:

In physics, in the analysis of the motion of an object in two dimensional space, the relative location of the object is specified using the measured distances in the x-direction from the y-axes and y-direction from the x-axes

In order to accurately specify the motion of the object, information regarding the component of the motion of the object in the x-direction and the component in the y-direction are required

The net force acting on the sled if the tension force in the rope is 260 N and the total weight of the sled is 470N is

θ = 30°

Tension, T = 260 N

Weight, W = 470 N

Weight, W = Normal force, N = 470 N

Resolving T into its horizontal and vertical components,

\(T_{x}\) = T cos θ

\(T_{y}\) = T sin θ

Since velocity is constant, acceleration will be zero.

∑ \(F_{x}\) = 0

\(T_{x}\) - \(F_{k}\) = 0

T cos θ = \(F_{k}\)

\(F_{k}\) = 260 * cos 30°

Frictional force, \(F_{k}\) = 226.2 N

Net force, F = T - \(F_{k}\)

F = 260 - 226.2

F = 33.8 N

Therefore, the net force acting on the sled is 33.8 N

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The net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.

To determine the net work required to change the particle's velocity from moving left at 27 m/s to moving right at 47 m/s, we can use the work-energy principle.

The work-energy principle states that the net work done on an object is equal to the change in its kinetic energy.

The kinetic energy of a particle is given by the equation:

KE = (1/2) * m * v^2

where m is the mass of the particle and v is its velocity.

Let's calculate the initial kinetic energy (KE_initial) and final kinetic energy (KE_final) of the particle.

Given:

Mass of the particle (m) = 41 g = 0.041 kg

Initial velocity (v_initial) = -27 m/s (negative sign indicates motion to the left)

Final velocity (v_final) = 47 m/s

Calculate the initial kinetic energy:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 0.041 * (-27)^2

= 0.5 * 0.041 * 729

= 14.9575 J

Calculate the final kinetic energy:

KE_final = (1/2) * m * v_final^2

= (1/2) * 0.041 * 47^2

= 0.5 * 0.041 * 2209

= 45.0595 J

Calculate the net work done:

Net work = KE_final - KE_initial

= 45.0595 - 14.9575

= 30.102 J

Therefore, the net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.

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Answer:

Clarification Statement: Examples of behaviors that affect the probability of animal reproduction could include nest building to protect young from cold, herding of animals to protect young from predators, and vocalization of animals and colorful plumage to attract mates for breeding.

Explanation:Animals have adapted a variety of courtship and mating behaviors to increase the probability of finding a mate. For example, the males of many bird species gyrate their feathers or perform special dances to attract a female.

Answer:

Examples of behaviors that affect the probability of animal reproduction could include nest building to protect young from cold, herding of animals to protect young from predators, and vocalization of animals and colorful plumage to attract mates for breeding.

Explanation:

(a) The charge of the ion is determined as 2.76 x 10⁻¹³C.

(b) The potential difference between the oil droplet’s starting point and end point is 16.28 V.

The charge of the ion is calculated as follows;

W = Fdsinθ

F = W/dsinθ

F = (3.9 × 10⁻¹²)/(0.022 x sin120)

F = 2.046 x 10⁻¹⁰ N

E = F/q

q = F/E

q = (2.046 x 10⁻¹⁰)/(740)

q = 2.76 x 10⁻¹³C

E = V/d

V = Ed

V = 740 x 0.022

V = 16.28 V

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