A pole, 6 m long, lies along the x-axis with one end at the origin. A rope is attached to the other end (point A), which runs to a point on the wall (point B), given by the coordinates (0,-1,2) in meters. Also at point A, there is a force given by F = 400 i - 200 j + 500 k (in N). Determine the projected component of this force (in N) acting along the rope AB.

Answers

Answer 1

Answer:

The value  is \( |P| =  187.4 \ N\)

Explanation:

From the question we are told that

   The length of the first rope is  L  =  6 m

    The first rope lie on the x-axis

   The end point of the first rope is  A  

   Now the vector of  A will be \(\vec {OA}=  6i\)

   The point of the second rope on the wall is  B

   The coordinate for the point of the second rope on the wall is  (0,-1,2)

   The vector of B will be  \(\vec {OB} =  -j+2k\)

Now the coordinate of rope AB is mathematically represented as

    \(\vec {AB} =  \vec{OB} -\vec{OA}\)

=>   \(\vec {AB} =  -j+2k -6i\)

=>   \(\vec {AB} =  -6i -j+2k \)

Generally the magnitude of the rope AB is mathematically evaluated as

       \(|\vec{AB}| = \sqrt{(-6^2) +(-1)^2 + (2)^2}\)

       \(|\vec{AB}| = \sqrt{41} \ m \)

Generally the unit vector rope AB is mathematically evaluated as

       \(\vec r = \frac{\vec {AB}}{|\vec{AB}|}\)

=>     \(\vec r =  \frac{1}{\sqrt{41} } * [-6i -j+ 2k]\)

From the question we are told that there is a force acting at point A and the force is  

    \(F = 400 i - 200 j + 500 k\)

Generally the projected component of this force (in N) acting along the rope AB is mathematically represented as

         \( P =  \vec F \cdot  \vec r\)

=>      \(  P  = 400 i - 200 j + 500 k  \ * \  \frac{1}{\sqrt{41} } * [-6i -j+ 2k]\)

Note ( i . i = 1  ) , (j . j  = 1) , (k . k  = 1)

So    \(P =  \frac{1}{\sqrt{41} } [-400 * 6 + 200 * 1 + 500 *2]\)

=>   \(P =  -187.4 \ N\)

So the magnitude of the projected component of this force (in N) acting along the rope AB is  

    \( |P| =  187.4 \ N\)

       

   


Related Questions

A block has two strings attached to it on opposite ends. One string has a force of 5 N,

the other string a force of 15 N. The block is accelerating at 1 m/s2 on a horizontal surface.

A) What is the mass of the block if the friction force is 3 N?


B) What is the coefficient of friction?

Answers

Answer:

A) 7kg

B) 0.044

Explanation:

a) Accordimg to Newton's second law

\sum F = ma

Fm - Ff = ma

Fm is moving force =15-5 = 10N

Ff is fictional force = 3N

m is the mass = ?

a Is the acceleration = 1m/s²

Substitute

10-3 = 1m

7 = m

Hence the mass of the body is 7kg

b) coefficient of friction is expressed as;

n = Ff/R

R is the reaction = mg

n =Ff/mg

Substitute

n = 3/7(9.8)

n = 3/68.6

n = 0.044

Hence the coefficient of friction is 0.044

Data:
AB = 20cm
BC = 30cm
CD is vertical
All members are massless except for BC that has uniform linear density = 1kg/m
Question:
Calculate the moment M applied to the disc that holds the system in equilibrium

Data:AB = 20cmBC = 30cmCD is verticalAll members are massless except for BC that has uniform linear density

Answers

The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Which of the following is a Nobel gas?
Ba2+
OA
OB. Ci
Kr
Ос.
Ca
D.

Answers

Answer:

Kr

Explanation:

the element that is in group 18 is noble gasses. the elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

A ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?

Answers

"a ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?"

I know acceleration would be -9.8 m/s^2 (to assume free fall), the initial velocity would be 20, and that the final position would be 10, but I don't know how to find the max height to then use to find the final velocity.

Just set this up as a quadratic function. I assume that we start from a height of zero, since you don't say.
h(t) = 20t - 4.9t^2
Now, you want to solve
20t - 4.9t^2 = 10
t = 0.583, 3.498
Since v=20-9.8t, that would make
v(3.498) = 20-9.8*3.498 = -14.28

You don't need to find the max height for this problem, but that occurs when v=0. So, h(2) = 20.4

Anyways goodluck!

Archaeological samples are often dated by radiocarbon dating. The half-life of carbon-14 is 5,700 years.
After how many half-lives will the sample have only 1/64 as much carbon-14 as it originally contained?

How much time will have passed?


If the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), you cannot assume that every daughter you see is the result of carbon-14 decay. If you did make this assumption, would you overestimate or underestimate the age of the sample?

Answers

There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.

What is the half life?

The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.

Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.

If we  the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the  age of the sample.

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What factors would create an ideal circuit?

Answers

An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.

The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:

1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.

2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.

3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.

4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.

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A car travels up a hill at a constant speed of 35 km/h and returns down the hill at a constant speed of 69 km/h. Calculate the average
speed for the round trip.

Answers

(PLEASE GIVE BRIANLIEST)

The average speed is not equal to the sum of the speeds divided by 2 because the car takes different times to cover the distance while going up and coming down the hill.

The average speed can be calculated as the total distance covered divided by the total time taken. As the speeds are constant, we can use the formula:

distance = speed * time

Let the distance traveled be "d". The time taken to go up the hill is "t1" and the time taken to come down is "t2".

d = 35 * t1 = 69 * t2

The total time taken for the round trip is t1 + t2.

The average speed is given by:

average speed = d / (t1 + t2) = d / (d/35 + d/69)

So the average speed can be calculated as follows:

average speed = d / (d/35 + d/69) = d * (35 + 69) / (35 * 69) = 104 / 2445 = 8 / 205 km/h

the answer is b, i got it right on edge :)

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

Answers

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.

what is a blue moon​

Answers

.
a phenomenon whereby the moon appears bluish owing to smoke or dust particles in the atmosphere

A frictionless plane is 10.0 m long and inclined at 36.0°. A sled starts at the bottom with an initial speed of 6.00 m/s up the incline. When the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed Vi. Both sleds reach the bottom of the incline at the same moment.
(a) Determine the distance that the first sled traveled up the incline. m
(b) Determine the initial speed of the second sled. m/s

Use the equation for the position of the second sled as a function of time to find the speed that makes it reach the bottom of the slope in the same time that the first sled takes to slide back down.

Answers

If a frictionless plane is 10.0 m long and inclined at 36.0°.

The sled traveled  8.17 m up the incline.The initial speed of the second sled is about  5.68 m/s

How to find the initial speed?

We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:

KE = (1/2)mv^2

where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:

mgh = (1/2)mv^2

where h is the height that the sled has traveled up the incline. Solving for h, we get:

h = (v^2)/(2g)

where g is the acceleration due to gravity. Using the given values, we have:

h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m

So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.

b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:

PE = mgh

where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:

KE = (1/2)mv^2

where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

v = sqrt(2gh)

Using the given values, we have:

v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s

So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.

The position of the sled as a function of time is given by:

y = -0.5gt^2 + Vi*t + h

where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:

0 = -0.5gt^2 + Vi*t + h

t = (Vi ± sqrt(Vi^2 - 2gh)) / g

Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:

t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s

0 = -0.5gt^2 + Vi*t + h

Vi = (h - 0.5gt^2) / t

Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s

Vi = 5.68 m/s

So the initial speed of the second sled is about  5.68 m/s

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1.)Enrico is doing a test to find the kinetic energy of a bullet right after it is shot. He has designed an experiment with a large block of 2 -kg. When he shoots the gun vertically, the bullet penetrates the block and both bullet and block lifts upward 8.0 mm. In case the mass of the bullet is 15 g. what is the kinetic energy of the bullet just before it hits the block (2 pts). (Neglect the air resistance and assume the gravitation acceleration to be 10 m/s2 ) 2) On a boting summer afternoon. Ronaldo is playing outside and shoots a ball of mass 2 kg horizontally with a speed of 8.0 m/s toward a green cart. The mass of the green cart is 15 kg and it rolls at a speed of 1.0 m/s along a horizontal path with no friction. The ball gets stuck in the card. a) What is the velocity of the cart after the ball strikes it? (0.5pts) b) What are the initial and final kinetic energies of the sytem? Is the energy conserved in this collision process? (1 pts) c) What type of collision process is it

Answers

a) The velocity of the cart after the ball strikes is 0.74 m/s

b)The initial and final kinetic energies of the sytem respectively is 68 J &  5.1 J .

c)This collision process is an inelastic collision.

1) The kinetic energy of the bullet just before it hits the block can be found using the following formula:KE = 0.5mv²

Where KE is the kinetic energy, m is the mass of the bullet, and v is the velocity of the bullet just before it hits the block.

Since the bullet and block lift upward 8.0 mm, we can use the following formula to find the velocity of the bullet and block just after impact:v = √(2gh)

Where v is the velocity, g is the acceleration due to gravity (10 m/s²), and h is the height the block is lifted (8.0 mm = 0.008 m).v = √(2 × 10 × 0.008) ≈ 0.4 m/s

Since the mass of the bullet is 15 g = 0.015 kg and the mass of the block is 2 kg, the momentum of the system is conserved just before and after impact.

m_bullet v_bullet = (mbullet + mblock)vf0.015 kg × vbullet = (0.015 kg + 2 kg) × 0.4 m/svbullet ≈ 10.6 m/s

Now we can find the kinetic energy of the bullet just before impact:KE = 0.5 × 0.015 kg × (10.6 m/s)² ≈ 0.89 J2) a) After the ball strikes the cart, both objects will move with a common velocity. We can use the law of conservation of momentum to find this velocity:mi × vi + mb × vb = (mi + mb) × vwhere mi and vi are the mass and velocity of the ball, mb and vb are the mass and velocity of the cart, and v is the common velocity after impact.Since the ball gets stuck in the cart, we know that vb = 0.

Plugging in the given values, we get:2 kg × 8.0 m/s + 15 kg × 1.0 m/s = (2 kg + 15 kg) × vv ≈ 0.74 m/s

b) The initial kinetic energy of the system is the sum of the kinetic energies of the ball and cart:KEi = 0.5 × 2 kg × (8.0 m/s)² + 0.5 × 15 kg × (1.0 m/s)² ≈ 68 J

The final kinetic energy of the system is the kinetic energy of the moving cart after the ball strikes it:KEf = 0.5 × (2 kg + 15 kg) × (0.74 m/s)² ≈ 5.1 J

The total energy of the system is conserved, as there are no external forces acting on the system.

c) This collision process is an inelastic collision, as the ball and cart stick together after impact and move with a common velocity. In an inelastic collision, kinetic energy is not conserved but momentum is conserved.

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What type of wave has crests and troughs?

Answers

Answer:

tidal wave

Explanation:

An 1800-W toaster, a 1400-W electric frying pan, and a 55-W lamp are plugged into the same outlet in a 15-A, 120-V circuit. (The three devices are in parallel when plugged into the same socket.)

a. Will this combination blow the 15-A fuse?
b. What current is drawn by each device?

Answers

Being in parallel each device will have an equal voltage drop of 120 V

A. Yes the combination will blow the fuse. See part B for the total current.

B. Toaster = 1800W / 120V = 15A

   Frying Pan = 1400W / 120V = 11.67A

  Lamp = 55W / 120V = 0.458A

Total amps = 15 + 11.67 + 0.458 = 27.128 Amps

27.128A is greater than 15A so the fuse will blow.

Which of the following statements are true of an object moving in a circle at a constant speed? Include all that apply.a) Because the speed is constant, the acceleration is zero.b) If the net force acting upon the object is suddenly reduced to zero, then the object would suddenly depart from its circular path and travel tangent to the circle.c)The object experiences a force which has a component directed parallel to the direction of motion.d)Inertia causes objects to move in a circle.e)The acceleration and the net force vector are directed perpendicular to each other.f)There can be a force pushing outwards on the object as long as the net force in inwards.g)The acceleration of the object is directed tangent to the circle.

Answers

ANSWER:

b) and f)

STEP-BY-STEP EXPLANATION:

To determine the answer we analyze option by option as follows:

a) Because the speed is constant, the acceleration is zero:

Acceleration happens when there is a change in velocity. Since the direction of the velocity vector is changing, there is an acceleration, an inward acceleration.

Therefore this is false.

b) If the net force acting upon the object is suddenly reduced to zero, then the object would suddenly depart from its circular path and travel tangent to the circle.

We have that if the net force is 0 N, then the moving object will maintain its state of motion and at the instant, the net force becomes 0 N, the object is moving tangent to the circle.

So this option is true

c) The object experiences a force which has a component directed parallel to the direction of motion.

We have that if the movement is circular at a constant speed, the net force is perpendicular to the direction of movement and this means that there is no component parallel or antiparallel to the direction of movement.

Therefore, this option is false.

d) Inertia causes objects to move in a circle.

The centripetal force that causes circular motion.

So this option is false

e) The acceleration and the net force vector are directed perpendicular to each other.

Acceleration and net force are always directed in the same direction. But in this case, they are directed inwards; this happens to be perpendicular to the tangential velocity vector.

So this option is false

f) There can be a force pushing outwards on the object as long as the net force in inwards.

An object moving in a circle must have a net internal force. And it may be the case where individual external forces are overcome by an individual internal force.

That is to say that this option is true

g) The acceleration of the object is directed tangent to the circle. We have that the acceleration is directed inwards; only the velocity is directed tangent to the circle.

So this option is false.

This means that the only true options are b) and f)


If an object is placed 15cm in of front of a concave mirror of radius Curvature 20cm. Determine the position of the image formed

Answers

The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

Given that,

Object distance, u = -15 cm

The radius of curvature of the concave mirror, R = 20 cm

Focal length, f = R/2 = -10 cm (negative for concave mirror)

Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :

\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)

\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)

\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)

\($v=-30 \mathrm{~cm}$\)

So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

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Which of Mendel principles would apply to mating two organisms that have two different alleles for three different traits

Answers

Answer:

Law of independent assortment

Explanation:

This is because law of independent assortment state that alleles of two or more genes when two organisms mate will be inherited or pass down to gametes which are in one way or the other independent of each other or each of the alleles. Therefore parent can have up to three different traits and the alleles can be inherited by the gametes.

Answer:

three different traits

Explanation:

just because it is.

B. On a separate sheet of paper, describe the different ways of generating electric power. ​

B. On a separate sheet of paper, describe the different ways of generating electric power.

Answers

Answer:

These all different sources of energy add to the store of electrical power that is then sent out to different locations via high powered lines. It is the energy from the sun that is harnessed using a range of technologies such as solar heating, solar architecture, photovoltaics, and artificial photosynthesis.

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A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?

Answers

The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Electrostatic attraction

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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Within the living area of the colony, what atmospheric gases must be present on Venus?

Answers

Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.

What gases are present in Venus' atmosphere?

The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.

What gases are found in Mars' and Venus' atmospheres?

For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.

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A miniature quadcopter is located at
xi = −1.75 m
and
yi = 2.70 m
at
t = 0
and moves with an average velocity having components
vav, x = 1.70 m/s
and
vav, y = −2.50 m/s.
What are the x-coordinate and y-coordinate (in m) of the quadcopter's position at
t = 2.10 s?

Answers

A miniature quadcopter is located at xi = −1.75 m and yi = 2.70 m at t = 0, so the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

What is the quadcopter's position?

   

The equation that is used here is the kinematic equations to find the position of the quadcopter at time t,

x = xi + vav, x × t

y = yi + vav, y × t

Substituting the given values, one can get:

x = -1.75 m + 1.70 m/s × 2.10 s = -0.185 m

y = 2.70 m - 2.50 m/s × 2.10 s = -3.175 m

Hence, the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

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PLEASE HELP ASAP!
A machine has an efficiency of 70%. What happens to the other 30% of the work?

Answers

Answer:

The other 30% is lost from friction.

Explanation:

       friction 30% ---> |O| <------ 70% work

A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

What is work done by machine?

In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.

Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

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PLEASE HELP!!! WILL GIVE 30 POINTS!! HAS TO BE CORRECT!


The picture below shows a solar event in the sun's atmosphere.


Which of these events is most likely to occur as a result of the solar event pictured above?


Disruption to electricity power grid

Less aurora activity at the poles

The sun's photosphere would be blocked

The sun's magnetic effect would decrease

PLEASE HELP!!! WILL GIVE 30 POINTS!! HAS TO BE CORRECT!The picture below shows a solar event in the sun's

Answers

Answer:

the answer is A . Disruption to electricity power grid :)

Explanation:

You preform an experiment to measure the speed of a car overtime. the data are shown in the table below. What graph shows the data from this experiment?

You preform an experiment to measure the speed of a car overtime. the data are shown in the table below.

Answers

Answer:

C

Explanation:

Check for coordinates of the VT graph in C part. The information matches with the table.

What is a lower fixed point in physics​

Answers

In physics, a lower fixed point refers to the minimum temperature at which a particular substance or system can reach and below which it cannot be cooled further.

It is a fundamental concept in the study of thermodynamics, specifically in relation to phase transitions and the behavior of substances at low temperatures.

The lower fixed point is often associated with the concept of absolute zero, which is the lowest possible temperature in the Kelvin scale (-273.15 degrees Celsius or -459.67 degrees Fahrenheit).

At absolute zero, particles in a substance possess the minimum amount of energy and their motion ceases, resulting in the absence of thermal energy.

The lower fixed point serves as a reference point for temperature scales, such as the International Temperature Scale of 1990 (ITS-90), which defines temperature measurements based on fixed points like the melting point of certain substances and the triple point of water.

These fixed points provide reproducible and well-defined temperature values for calibration and measurement purposes.

Understanding the lower fixed point is crucial for various scientific and technological applications, such as cryogenics, superconductivity, and the study of quantum phenomena at extremely low temperatures.

By pushing the boundaries of cooling techniques, researchers aim to approach the lower fixed point and explore the fascinating properties and behaviors of matter at such extreme conditions.

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HELP PLZ
A baseball player hits a pop-up. The ball was hit when it was 3 feet off the ground with an initial
upward velocity of 80 ft/s. How long will it take for the ball to reach a height of 10 feet off the
ground, on the way down?

Answers

Answer:

Explanation:

Use the equation

\(h(t)=-16t^2+v_0t+h_0\)

where h(t) is the height after a certain amount of time goes by, v0t is the initial upwards velocity, and h0 is the initial height of the projectile. For us:

h(t) = 10

v0t = 80

h0 = 3 and filling in:

\(10=-16t^2+80t+3\) and get everything on one side to factor:

\(0=-16t^2+80t-7\)

This factors to

t = .09 sec and 4.9 sec. Let's interpret this.

The time of .09 is when the ball reached 10 feet on the way up, and

the time of 4.9 is when the ball reached 10 feet on the way back down. That's the height we need, 4.9 seconds.

A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)

Answers

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

A 24.0kg dog running at a speed of 3.0 m/s jumps onto a stationary skateboard that has a mass of 3.6 kg. How long will it take a force with a magnitude of 9.0N to stop the skateboard and dog?
Given: ?
Unknown: ?
Solve and show your work

Answers

The time will take a skateboard and dog with force 9N to stop the skateboard and dog is 8 seconds.

The force is defined as the push or pull of an object. The force equals the mass and acceleration of the object obtained from Newton's second law. Acceleration defines the change in velocity by the time taken. The force is defined as the rate of change of momentum and time. Momentum is defined as the product of mass and velocity and the unit of momentum is Kg.m/s.

From the given,

mass of dog (m) = 24 kg

The initial speed of dog (u) = 3 m/s

mass of skateboard and dog = 3 + 24 = 27 kg.

The final speed of dog (v) = 0 m/s

Force = 9N

time =?

F = dp/dt, rate of change of momentum and time.

F(dt) = dp

dt = (dp)/F

    =(Pf - Pi)/F

Pf is the final momentum and Pi is the initial momentum.

Pi = m×v = 24×3 = 72 kg.m/s²

Pf = m×v = 27×0 =0 kg.m/s²

dt = (0-72)/9

   = 8s

Thus, the time taken to stop the skateboard and dog is 8s.

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To measure the potential drop across a resistor, a voltmeter is connected in parallel with a resistor. Is this true or false?

Answers

To measure the voltage of a resistor, we have to connect a voltmeter in parallel, while an ammeter is connected in series. The reason for this is because the voltage in parallel resistors is actually equivalent, that is, the voltage passing through each resistor is the same when they are in parallel.

Therefore, the statement is true.

what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2​

Answers

The pressure of a tank of uniform cross-sectional area 4.0m2 when the tank is filled with water at a depth of 6m is 58800 Pa.

Pressure calculation

To find the pressure in the tank, we can use the formula for pressure:

Pressure = density x gravity x height

Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 6 m

Thus:

Pressure = 1000 kg/m³ x 9.8 m/s² x 6 m

Pressure = 58800 kg/(m·s²)

Since the unit of pressure is Pascal (Pa), which is equivalent to kg/(m·s²), the pressure in the tank is:

Pressure = 58800 Pa

Therefore, the pressure in the tank when it is filled with water to a depth of 6 m is 58800 Pascal.

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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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