a point charge q1 = 2.40 uC is held stationary at the origin. A second point charge q2 = -4.30uC moves from the point x= .150 m, y= 0.0 m, to the point x = .250 m, y= 0.0m
a) what is the charge in potential energy of the pair of charges?
b) How much work is done by the electric force on q2​

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

The scientific meaning for temperature is at the heart of thermodynamics. It arises from the Zeroth Law of thermodynamics that states that if two systems are in thermal equilibrium and one of those systems is in thermal equilibrium with a third system, then all three systems are in thermal equilibrium with each other.

Explanation:

Answer:

The double arrow represents thermal equilibrium between systems.

Explanation:

The total pressure of the gasses in the container is 43.64 PSI.

The total pressure of the gas is equal to the sum of the individual partial pressure of the gas.

The total pressure of the gasses in the container is calculated as follows;

P ( tot) = P1 + P2 + P3

where;

The total pressure of the gasses in the container is calculated as;

P ( tot ) = 0.025 PSI + 15 PSI + 28.61 PSI

P ( tot ) = 43.64 PSI

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Answer:

Net torque in positive direction:

Fz = -450 * cos 30 deg * 1.5 = -585 N-M

Fz = 200 * 3.5 = 700 N-M

Net F = 115 N-M

Torque is generally defined as L = R X F

X cross Y = Z     normal coordinate system

Note that Z will be out of the page giving the positive value for the torque.

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

When a ball is dropped from a height, its velocity increases linearly due to gravity.

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Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s

Answer:

Period of motion is approximately 0.5447  seconds

Explanation:

We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)

F = k * x

0.012 kg * 9.8  m/s^2 = k 0.034 m

k = 0.012 kg * 9.8  m/s^2 / (0.034 m)

k = 3.46 N/m

now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

\(T=2\pi\,\sqrt{\frac{m}{k} }\)

which in our case becomes:

\(T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec\)

the calculated answer in micrometer is 9.52 x 10⁻²

Dimensional analysis is the analysis of the relationships between different physical quantities by identifying their base quantities (such as length, mass, time, and electric current) and units of measure (such as miles vs. kilometers, or pounds vs. kilograms) and tracking these dimensions as calculations or comparisons are performed. The conversion of units from one dimensional unit to another is often easier within the metric or SI system than in others, due to the regular 10-base in all units.

9.52x 10⁴

1 m= 10⁶ μm

dimensional analysis = 9.52 x 10⁴ x 10⁻⁶

                                   =9.52 x 10⁻² μm

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All of the above are risks of speeding.

Speeding is a type of aggressive driving behavior. Speeding is more than just breaking the law. The consequences are far-ranging:

Speed also affects your safety even when you are driving at the speed limit but too fast for road conditions, such as during bad weather, when a road is under repair, or in an area at night that isn’t well lit.

Speeding endangers not only the life of the speeder, but all of the people on the road around them, including law enforcement officers. It is a problem we all need to help solve.

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The total volume of the piece of wood is 1.33\(cm^3\).

To calculate the total volume of the piece of wood, we can use the principle of displacement.

1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).

2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.

3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).

4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).

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The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.

The velocity of the third piece is calculated from the principle of conservation of linear momentum.

mu = m₁u₁ + m₂u₂ + m₃u₃

where;

6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y

0 = 6.84 + 3u₃y

u₃y = -6.84/3

u₃y = -2.28 m/s

ΔP = Pf - Pi = J

where;

2640(0.1) = 2(10)cos32 +  1(8)cos(28) + 3u₃x - 6(22)

264 = -108 + 3u₃x

3u₃x = 372

u₃x = 372/3

u₃x = 124 m/s

u₃ = √(124² + 2.28²)

u₃ = 124.02 m/s

tanθ = u₃y/u₃x

tanθ = 2.28/124

tanθ = 0.018

θ = 1.05⁰ (below the horizontal)

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Answer:

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. ... Their movement generates an electric current and causes each electron to act like a microscopic magnet.

Explanation:

Answer:

The limitations of the experiment are those characteristics of design or methodology that impacted or influenced the application or interpretation of the results of your study.

Answer:10

Explanation: Acceleration of car is given by a= v^2/r, v= 50m/s, r= 250m a= 10 m/s^2 2

Answer:

» Image distance :

\({ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\ \)

\({ \tt{ \frac{1}{v} + \frac{1}{10} = \frac{1}{5} }} \\ \\ { \tt{ \frac{1}{v} = \frac{1}{10} }} \\ \\ { \tt{v = 10}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: image \: distance \: is \: 10 \: cm \: \: }}}}}\)

» Magnification :

• Let's derive this formula from the lens formula:

\( { \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\ \)

» Multiply throughout by fv

\({ \tt{fv( \frac{1}{v} + \frac{1}{u} ) = fv( \frac{1}{f} )}} \\ \\ { \tt{ \frac{fv}{v} + \frac{fv}{u} = \frac{fv}{f} }} \\ \\ { \tt{f + f( \frac{v}{u} ) = v}}\)

• But we know that, v/u is M

\({ \tt{f + fM = v}} \\ { \tt{f(1 +M) = v }} \\ { \tt{1 +M = \frac{v}{f} }} \\ \\ { \boxed{ \mathfrak{formular : } \: { \tt{ M = \frac{v}{f} - 1 }}}}\)

\({ \tt{M = \frac{10}{5} - 1 }} \\ \\ { \tt{M = 5 - 1}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: magnification \: is \: 4}}}}}\)

» Nature of Image :

Answer:

Vf = 23 m/s

Explanation:

First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:

s₁ = v₁t₁

where,

s₁ = distance covered by motorcycle 1 = ?

v₁ = speed of motorcycle 1 = 6.5 m/s

t₁ = time = 10 s

Therefore,

s₁ = (6.5 m/s)(10 s)

s₁ = 65 m

Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,

s₂ = s₁ + 50 m

s₂ = 65 m + 50 m

s₂ = 115 m

Now, using second equation of motion for motorcycle 2:

s₂ = Vi t + (1/2)at²

where,

Vi = initial velocity of motorcycle 2 = 0 m/s

Therefore,

115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²

a = 230 m/100 s²

a = 2.3 m/s²

Now, using 1st equation of motion:

Vf = Vi + at

Vf = 0 m/s + (2.3 m/s²)(10 s)

Vf = 23 m/s

The speed of the motorcycle 2 when it passes motorcycle 1 is 23 m/s.

The distance traveled by motorcycle 1 is calculated as follows;

\(x_1 = vt\\\\x_1 = 6.5 \times 10\\\\x_1 = 65 \ m\)

The distance traveled by motorcycle 2 when it passes motorcycle 1 is calculated as follows;

\(x_2 = x + x_1\\\\x_2 = 50 \ m \ + \ 65\ m\\\\x_2 = 115 \ m\)

The constant acceleration of the motorcycle 2 is calculated as;

\(s = u + \frac{1}{2} at^2\\\\s = 0 + \frac{1}{2} at^2\\\\a = \frac{2s}{t^2} \\\\a = \frac{2 \times 115}{10^2} \\\\a = 2.3 \ m/s^2\)

The speed of the motorcycle 2 when it passes motorcycle 1 is calculated as follows;

\(v_f = v_0 + at\\\\v_f = 0 + (2.3)(10)\\\\v_f = 23 \ m/s\)

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The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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Answer:

0.82

Explanation:

constant velocity.means acceleration a = 0, so net force = 0

F - μmg = ma = 0

so μ = F/(mg) = 200/(25*9.8) = 0.82

the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s

the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(1.5g * 13m)

v = sqrt(22.5 * 9.8)

v = sqrt(219.5)

v = 14.8 m/s

(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).

So, we can rearrange the equation to solve for v: v = sqrt(ar)

Plugging in the values, we get: v = sqrt(g * 13m)

v = sqrt(9.8 * 13m)

v = sqrt(127.4)

v = 11.3 m/s

So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.

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The nature of science is an extensive and multifaceted concept that refers to various qualities, including its subject matter, methodology, principles, and theories.

It is a process of systematic inquiry that aims to explain the natural world through empirical observation, testing, and interpretation.

Science is characterized by its openness to criticism, objectivity, and the search for evidence to support or refute hypotheses and theories.

Science is dynamic and continuously evolving, with new discoveries, theories, and innovations that challenge our understanding of the world around us.

The nature of science encompasses several key concepts, including the use of empirical evidence, peer review, and the scientific method.

Empirical evidence refers to observable, measurable, and testable phenomena that can be subjected to scientific inquiry.

Peer review is the process by which scientific findings are evaluated by other experts in the field, ensuring their accuracy and validity.

The scientific method is a structured approach to inquiry that involves formulating hypotheses, testing them through experimentation or observation, and drawing conclusions based on the data collected.

Scientific knowledge is tentative and provisional, meaning that it is subject to change in the light of new evidence or findings.

As a result, science is a self-correcting process that relies on continued experimentation, observation, and testing to refine and expand our understanding of the natural world.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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The physical stimulus of sound is the vibration of air molecules. Sound waves are created by vibrating sources and propagate as compressions and rarefactions through the air. Our ears detect these vibrations and transmit them to the brain for interpretation.

The correct answer is option C.

The physical stimulus of sound is vibrations in air molecules. When a sound is produced, such as by a musical instrument or a person speaking, it sets the air molecules in motion. These vibrating air molecules create disturbances or pressure waves that propagate through the air. The molecules move back and forth, compressing and rarefying the air as the sound wave travels.

Sound waves are considered mechanical waves because they require a medium, such as air, to travel through. The vibrations of the air molecules transmit the energy of the sound wave from its source to our ears.

The process of sound production begins with an object or source that vibrates. For example, when a guitar string is plucked, it vibrates back and forth, displacing the surrounding air molecules. These air molecules then collide with neighboring molecules, transferring the vibrations through the air. The pattern of compressions and rarefactions continues as the sound wave propagates outward from the source.

When sound waves reach our ears, they cause the eardrum to vibrate. The eardrum is a thin membrane that separates the outer ear from the middle ear. The vibrations of the eardrum are transmitted to the middle ear bones, which amplify and transmit the sound vibrations further into the inner ear. In the inner ear, the vibrations are converted into electrical signals by the cochlea and transmitted to the brain for interpretation.

In summary, the physical stimulus of sound is the vibration of air molecules. Sound waves are created by vibrating sources and propagate through the air as compressions and rarefactions. These vibrations are then detected by our ears and processed by our auditory system.

Therefore, among the given options the correct one is option C.

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The question probable may be;

What is the physical stimulus of the sound?

a. Vibrations in space

b. Vibrations in electromagnetic radiation

c. Vibration in air molecules

d. Potential energy in air molecules

Answer:

W = - 3431250 [N]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the initial mechanical energy of a body plus the work done on this body must be equal to the final mechanical energy of the body. We must remember that the mechanical energy of a body is equal to the sum of kinetic energies plus potential energy plus elastic energy.

In this problem, we only have kinetic energy.

\(E_{1}+W_{1-2}=E_{2}\\where:\\E_{1}=E_{pot}+E_{kine}+E_{elas}\\E_{pot} = 0\\E_{elas}=0\\E_{kine}=\frac{1}{2} *m*v^{2}\)

And we have:

m = mass = 1220 [kg]

v = velocity = 75 [m/s]

As the carriage stops the final kinetic energy is zero.

Now replacing:

\(\frac{1}{2} *1220*(75)^{2} +W_{1-2}=0\\W_{1-2}= - 3431250[N]\)

Note: The negative force means that the force has to be carried out by the carriage. That is, no external force acts on the car to stop it.

The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is 20.

To solve this problem, we can use the stars and bars method, which is a combinatorial technique used to count the number of ways to distribute indistinguishable objects into distinguishable containers. In this case, we have four indistinguishable balls and five distinguishable boxes.

The stars and bars method works by representing each ball as a star and using bars to separate the balls into different boxes. For example, if we wanted to distribute two balls into three boxes, we could use the following diagram:

* | * * | *

In this diagram, the first and last bars represent the boundaries of the containers, while the stars represent the balls.

The second bar separates the first two balls from the last ball, indicating that the first two balls are in the first container and the last ball is in the third container.

To distribute four balls into five boxes, we need to use three bars to separate the balls into four groups. We have a total of six spaces to place the bars (including the boundaries), and we need to choose three of them to place the bars.

Therefore, the number of distinct ways to place four indistinguishable balls into five distinguishable boxes is the same as the number of ways to choose three spaces out of six, which is:

6 choose 3 = (6!)/(3!3!) = 20

Therefore, there are 20 distinct ways to place four indistinguishable balls into five distinguishable boxes using the stars and bars method.

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Answer:

K = 3.07 x 10⁷ N/m = 30.7 MN/m

Δx =  2.93 x 10⁻⁶ m = 0.00293 mm

Explanation:

In order to find out the effective spring constant of the straw, we can use the following equation:

K = AE/L

where,

K = Effective Spring Constant = ?

A = Cross-Sectional Area = π(Do - Di)²/4 = π(0.014² - 0.011²)/4 = 9.5 x 10⁻⁵ m²

L = Length of Straw = 21 cm = 0.21 m

E = Young's Modulus = 68 GPa = 68 x 10⁹ Pa

Therefore,

K = (9.5 x 10⁻⁵ m²)(68 x 10⁹ Pa)/(0.21 m)

K = 3.07 x 10⁷ N/m

Now, we find stress to check the elastic limit:

Stress = Force/Area = 90 N/9.5  x10⁻⁵ m²

Stress = 0.95 MPa < Tensile Strength (7 MPa)

Thus, the straw is still in elastic limit and hook's law can be applied:

Δx = F/K = (90 N)/(3.07 x 10⁷ N/m)

Δx =  2.93 x 10⁻⁶ m = 0.00293 mm

Answer:

Refraction is another way that waves interact with matter. ... Waves bend as they enter a new medium because they start traveling at a different speed in the new medium. For example, light travels more slowly in water than in air. This causes it to refract when it passes from air to water or from water to air.

Explanation:

i hope this helps but if it doesnt im rlly srry :p

(a) Current in the upper branch is -0.4 A

(b) Current in the middle branch is 1.6 A

(c) Current in the lower branch is 1.2 A

Kirchhoff's current law states that, at a node, the current entering the circuit is equal to the current leaving the circuit. That means the sum of all currents at the node is zero.

Here,

According to Kirchhoff's current law,

I₁ + I₂ = I₃

Taking the clockwise direction from upper loop,

According to Kirchhoff's voltage law,

2I₁ -10 + 3I₁ - 4I₂ + 20 - I₂ = 0

5I₁ - 5I₂ = -10

I₁ - I₂ = -2

Taking clockwise direction from the lower loop,

According to Kirchhoff's voltage law,

-4I₂ + 20 - I₂ + 2I₂ - 10I₃ = 0

-5I₂ - 10I₃ = -20

Dividing by 5,

I₂ + 2I₃ = 4

So we get three equations,

I₁ + I₂ = I₃                 (1)

I₁ - I₂ = -2                 (2)

I₂ + 2I₃ = 4               (3)

From the above equations,

Adding (2) and (3), we get,

I₂ = 3I₃ - 2

Applying this in  eqn(3),

3I₃ - 2 + 2I₃ = 4

5I₃ = 6

I₃ = 1.2 A

So, I₂ = 3I₃ - 2 =3X 1.2 - 2

I₂ = 1.6 A

I₁ = -2 + I₂ = -2 + 1.6

I₁ = -0.4 A

Hence,

(a) Current in the upper branch is -0.4 A

(b) Current in the middle branch is 1.6 A

(c) Current in the lower branch is 1.2 A

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Answer:

if its winter

Explanation:

then we know it will me cold

Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.

The equations apply in uniformly accelerated straight motion in vertical dimension are

v₁ = v₀ + gt

v₁² = v₀² + 2gh

h = v₀t + ½ gt²

Where

A student standing on the ground throws a ball straight up with

Find the time it takes for the ball to reach the ground!

We use g = 9.8 m/s². See the illustration picture in the attachment!

The ball will go upward and stop at a certain height with v₁ = 0. The time needed is

v₁ = v₀ - gt₁

0 = 13.0 - 9.8t

13.0 = 9.8t

t₁ = 13.0/9.8

t₁ = 1.3 s

The height above the hand when the ball stops is

v₁² = v₀² - 2gh₂

0 = 13.0² - 2(9.8)h₂

13.0² = 2(9.8)h₂

169 = 19.6h₂

h₂ = 8,62 m

The ball stops at a height of

h₃ = h₁ + h₂

h₃ = 2.50 + 8.62

h₃ = 11.12 m

The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is

h₃ = v₁t + ½ gt₂²

11.12 = 0 + ½ (9.8)t₂²

11.12 = 4.9t²

t₂² = 2.27

t₂ ≈ 1.5 s

The time that the ball in the air is

t = t₁ + t₂

t = 1.3 + 1.5

t = 2.8 s

Hence, the ball is in the air for 2.8 seconds.

Your question is incomplete, but most probably your full question was

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).

Learn more about uniformly accelerated straight motion here:

brainly.com/question/2560313

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