A plastic pool gets filled up with 10L of water per hour.

a) After 2 hours how much water is in the pool? Write an equation.

b) After how many hours will the pool be 80L?

c) Is part b) linear or nonlinear?

They met 480 meters from the house.

Given that Noah and his grandfather were returning home from a walk, and when they were 800 m away from the house, the grandfather said that he was thirsty, so Noah immediately ran home, got a bottle of water, and ran back to meet his grandfather who never stopped walking at a steady pace, to determine how many meters from the house did they meet if noah ran four times as fast as his grandfather walked, the following calculation must be made:

Therefore, they met 480 meters from the house.

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The question is incomplete. Please see the complete question below

The candy shop made 3 1/18 pounds of chocolate they sold 1 1/4pounds how many pounds of chocolate do they have left

Answer:

15/8

Step-by-step explanation:

The shop made 3 1/8 pound of chocolate

They sold 1 1/4 of chocolates

Hence the number of chocolates left can be calculated as follows

3 1/8-1 1/4

= 25/8-5/4

= 15/8

Suppose z is a function of x and y and tan (√x + y) = e²², we get:`z/t = -12st³ + 12s²t⁴`Therefore, `z/t = -12st³ + 12s²t⁴`.

To find z/x, differentiate z with respect to x and keep y constant. `z/x = dz/dx * dx/dx + dz/dy * dy/dx` (Note that `dx/dx` = 1)Now, `dz/dx = -((√x + y)⁻²)/2√x` by the chain rule. Also, we know that `tan (√x + y) = e²²`.

Therefore, `tan (√x + y)` is a constant. Hence,`dz/dx = 0`.Therefore, `z/x = 0`.To find z/y, differentiate z with respect to y and keep x constant. `z/y = dz/dx * dx/dy + dz/dy * dy/dy` (Note that `dx/dy = 0` as x is a constant)

Differentiating z with respect to y, we get:`dz/dy = 3y²`Therefore,`z/y = 3y²`3. Let z = 2² + y³, x = 2 st and y = s - t². Compute for z/х and z/t

To find z/x, differentiate z with respect to x and keep y constant. `z/x = dz/dx * dx/dx + dz/dy * dy/dx` (Note that `dx/dx` = 1)

Now, `dx/dx = 1` and `dz/dx = 0` because z does not depend on x.

Hence, `z/x = 0`.To find z/t, differentiate z with respect to t and keep x and y constant.` z/t = dz/dt * dt/dt` (Note that `dx/dt = 2s`, `dy/dt = -2t`, `dx/dt` = `2s`)

Differentiating z with respect to t, we get:`dz/dt = 3y² * (-2t)`

Substituting x = 2st and y = s - t², we get: `z/t = 3(s - t²)²(-2t)`

Simplifying, we get: `z/t = -12st³ + 12s²t⁴`

Therefore, `z/t = -12st³ + 12s²t⁴`.

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Answer:

25.65634 squares cm

Step-by-step explanation:

The area of the whole circle is

pi x 7 squared

pix49 =153.93804

the degrees of a circle are 360

 60 is 1/6 of 360

so we need to divide the area by 6

153.93804/6 = 25.65634

The graph of the function f(x) = 32 is attached accordingly.

X  - Intercept - There is no x-intercept since the function is a horizontal line.

Y -Interept - The y-intercept is (0, 32), since the line intersects the y-axis at y = 32.

  Vertical Asymptotes - There are 0    vertical asymptotes,   since t function is defined for all values of x.

Horizontal Asymptotes - There are 0    horizontal   asymptotes, since the function is a horizontal line.

Slant Asymptotes - There are zeroslant asymptotes, since the function is a horizontal line.

Holes - There are zeroholes in the graph, since the function is a horizontal line with no breaks or discontinuities.

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Answer: see below

Step-by-step explanation:

got it right on quiz

Answer:

0.023

Step-by-step explanation:

Answer:

Shakerville 21° warmer

Step-by-step explanation:

-27 + -6 = 21

The maximum number of songs she can download while still remaining within her budget is x <= 21

The given parameters are:

One-time fee = $12.99

Rate = $0.65 per song

Budget = $27

The inequality is then represented as:

One-time fee + Rate * x <= Budget

So, we have:

12.99 + 0.65x <= 27

Subtract 12.99 from both sides

0.65x <= 14.01

Divide both sides by 0.65

x <= 21.55

Round down

x <= 21

Hence, the maximum number of songs she can download while still remaining within her budget is x <= 21

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Answer:

Plato answer.

Answer:

(−3, −2) (−2, −1) (−1, −2) (−1, −4)

Angle of Rotation (CCW)    

90°   (2, −3) (1, −2) (2, −1) (4, −1)

180°  (3, 2) (2, 1)  (1, 2)         (1, 4)

270° (−2, 3) (−1, 2) (−2, 1) (−4, 1)

360° (−3, −2) (−2, −1) (−1, −2) (−1, −4)

The triangle EFG's exterior angle to G is 95.6 degrees.

The exterior angle theorem states that when a triangle's side is extended, the resultant exterior angle formed is equal to the sum of the measures of the two opposite interior angles of the triangle. The theorem can be used to find the measure of an unknown angle in a triangle.

So, Using Exterior angle theorem

We can say that

m∠E = 69.7°+ m∠F = 25.9° = exterior angle to ∠G

So,

exterior angle to ∠G = 69.7+25.9=95.6°

Therefore we can say that the Exterior angle to G of the triangle EFG is 95.6°.

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Answer:

Price of Candle: 12.5

Price Wallflower: 5

Price of Lotion: 8

Step-by-step explanation:

Let cost of a candle = \(x\)

Let cost of a wallflower = \(y\)

Let cost of a lotion = \(z\)

Cost of 4 candles = 4\(x\)

Cost of 5 wallflowers = 5\(y\)

Cost of 6 lotions = 6\(z\)

Cost of 2 candles = 2\(x\)

Cost of 3 wallflowers = 3\(y\)

Cost of 1 lotion = \(z\)

As per question statement:

\(4x+5y+6z=123 .... (1)\\2x+3y+z=48 ...... (2)\\z=2y-2 ..... (3)\)

Using equation (3) in (1) and (2), the equations get reduced to :

\(\Rightarrow 4x+17y = 135 ..... (4)\\\Rightarrow 2x+5y = 50 ..... (5)\)

Multiplying (5) with 2 and subtracting from equation (1):

\(7y = 35\\\Rightarrow y = 5\)

By equation (3):

\(\Rightarrow z =8\)

By equation (4):

\(\Rightarrow x = 12.5\)

Therefore, the answer is:

Price of Candle: 12.5

Price Wallflower: 5

Price of Lotion: 8

Answer:

x>0

Step-by-step explanation:

Answer:

\(( { \frac{4}{7} )}^{2} = \frac{ {4}^{2} }{ {7}^{2} } = \frac{16}{49} \)

Answer: The probability is 1/5

Step-by-step explanation: there are 5 even numbers in between 1 to ten and ten is one of them so it would be 1/5 probability hope this helps! :)

The requried probability that she drew the number 10 is 0.2.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
There are 5 even numbers and 5 odd numbers in the set of integers from 1 to 10. Since Cynthia is bringing a dessert, she must have drawn an even number.

Therefore, the probability that she drew the number 10 is given as,
= 1/5 = 0.2

since there is only 1 even number that is greater than 8 (i.e., 10).

Thus, the probability that she drew the number 10 is 0.2.

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The Euclidean algorithm can be applied to Gaussian integers in the same way it is applied to ordinary integers. In this case, we are given x = 3+2i and y = 2-5i and we need to find q and r such that x = qy + r and d(r) < d(y).

First, we divide x by y to get a quotient and remainder:
x/y = (3+2i)/(2-5i) = (3+2i)(2+5i)/(2-5i)(2+5i) = (16+7i)/29 = 0.551724 + 0.241379i

Since q and r must be Gaussian integers, we round the real and imaginary parts of the quotient to the nearest integer to get q = 1 + 0i = 1.

Next, we multiply q by y and subtract from x to get the remainder:
r = x - qy = (3+2i) - (1)(2-5i) = 1+7i

Finally, we check that d(r) < d(y):
d(r) = 1^2 + 7^2 = 50
d(y) = 2^2 + (-5)^2 = 29

Since d(r) > d(y), we need to adjust our quotient and remainder. We can do this by subtracting 1 from the real part of q and adding y to the remainder:
q = 0 + 0i = 0
r = (1+7i) + (2-5i) = 3+2i

Now, d(r) = 3^2 + 2^2 = 13 < 29 = d(y), so our final answer is q = 0 and r = 3+2i.

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Events M and N are independent events.

It means that the outcome of one event does not affect the outcome of the other event.

The probability of events M and N both occurring is given by

Re-arranging for P(N), we get

Where

P(M and N) = 0.158

P(M) = 0.23

Therefore, the probability P(N) is 0.7

The measures of the angles are ∠1 = 127°, ∠2 = 53°, ∠3 = 127°, ∠4 = 37°, ∠5 = 53°, ∠6 = 90°, ∠7 = 37°, ∠8 = 143°, ∠9 = 37° and ∠10 = 143°

From the question, we have the following parameters that can be used in our computation:

The transversal lines and the other lines

So, we have

∠1 = 180 - 53

Evaluate

∠1 = 127°

Also, we have

∠5 = 53°

By vertical angles, we have

∠2 = 53°

∠3 = 127°

Next, we have

∠4 = 127 - 90°

∠4 = 37°

Solving further, we have

∠6 = 90°

By corresponding angles, we have

∠7 = 37°

∠9 = 180 - 90 - 53°

∠9 = 37°

∠10 = 90 + 53°

∠10 = 143°

∠8 = 143°

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Answer:

≈ 3.9 miles

Step-by-step explanation:

The third angle in the triangle is

180° - (53 + 78)° = 180° - 131° = 49°

Using the Sine rule in the triangle with distance from 2 being x, then

\(\frac{3}{sin49}\) = \(\frac{x}{sin78}\) ( cross- multiply )

x × sin49° = 3 × sin78° ( divide both sides by sin49° )

x = \(\frac{3sin78}{sin49}\) ≈ 3.9 ( to the nearest tenth )

Answer:

Question number 1: Correlation = no. Causation = no.

Question number 2: Correlation = yes. Causation = no.

Question number 3: Correlation = yes. Causation = yes.

Step-by-step explanation:

Happy to help!

Answer:

A) y = -3x -2

Step-by-step explanation:

1. start at point (-1,1)

2. move down 3 (-3) and over to the right 1 (1)

3. that makes your slope -3/1 which is just -3.

4. find your y-intercept: -2

5. using y=mx+b, plug in your numbers and you get

6. y = -3x -2

Hope this helps! Brainliest, please!

fraction form : 8/25

decimal form : 0.32

Answer:

8/25 or if you have to do decimal form it's 0.32

Step-by-step explanation:

Answer:

0.4987

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

So for 80 we have:

z = (80 - 80) / (3)

z = 0

and this value represents 0.5

for 89 we have:

z = (89 - 80) / (3)

z = 3

and this value represents 0.9987

we subtract:

0.9987 - 0.5 = 0.4987

Which means that it represents 49.87%

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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The system of linear inequalities to represent the constraints of this situation is x + y ≥ 200, x ≤ 220, y ≥ 50.

This means that the total number of computers (desktop plus laptops) must be at least 200 (x + y ≥ 200). The company needs no more than 220 desktops (x ≤ 220), and at least 50 laptops (y ≥ 50).

The inequality x + y ≥ 200 represents the total number of computers needed, x ≤ 220 represents the maximum number of desktops needed, and y ≥ 50 represents the minimum number of laptops needed. Together, these inequalities represent the constraints of the situation.

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Different models and methodologies exist, and ongoing research aims to improve our understanding and ability to predict and manage induced seismicity hazards.

Different models and methodologies exist, and ongoing research aims to improve our understanding and ability to predict and manage induced seismicity hazards.

When forecasting induced seismicity hazard, researchers use parameters like rock properties and injection rates to calculate the likelihood and magnitude of induced earthquakes. These parameters are important factors that influence the response of the subsurface to fluid injection or extraction activities, such as hydraulic fracturing (fracking) or fluid disposal in deep wells.

Here are some specific calculations researchers might perform using these parameters:

1. Seismicity Rate: Researchers estimate the rate at which induced earthquakes may occur by analyzing the injection rates of fluids (e.g., water, wastewater, or hydraulic fracturing fluids) into the subsurface.

The higher the injection rate, the greater the likelihood of inducing seismic activity.

2. Magnitude-Frequency Distribution: Researchers analyze the rock properties, including its stress state, fault network, and fault stability, along with the injection rates, to estimate the magnitude and frequency of induced earthquakes.

They use statistical models, such as the Gutenberg-Richter relationship, to predict the distribution of earthquake magnitudes that may occur due to the injection activities.

3. Stress Changes: Injection activities can alter the stress distribution within the subsurface, potentially leading to fault activation or slip.

Researchers assess the rock properties, including the in-situ stress conditions, to calculate the stress changes induced by fluid injection. This information helps determine the potential for fault reactivation and the magnitude of induced seismic events.

4. Seismic Hazard Maps: By combining the above calculations with geologic and geophysical data, researchers can create seismic hazard maps that indicate the areas at higher risk of induced earthquakes.

These maps provide valuable information for regulatory bodies, industry stakeholders, and decision-makers to mitigate potential risks associated with fluid injection or extraction operations.
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The value of x is given as follows:

x = 9.40 cm.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

The parameters for this problem are given as follows:

Applying the cosine, the value of x is obtained as follows:

cos(20º) = x/10

x = 10 x cosine of 20 degrees

x = 9.40 cm.

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