Answer:
A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes
Explanation:
Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.
The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.
As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.
The potential energy is the energy due to the position of a body.
Earthquakes occur along large cracks (faults) at or near the boundary between two tectonic plates. Why do some faults generate earthquakes while others move peacefully?
which of the following statements describes a perfectly inelastic collision
Answer: An ice hockey player picks up a trophy as he slides past it.
Two pool balls colliding precisely inelastically and rebounding off one another is an example. So, the correct option is A.
What is an Inelastic collision?Inelastic collisions are those in which the total kinetic energy is lower after the impact than it was before. The stick is travelling quickly in the direction of the ball before to the contact. The stick comes to a stop following the accident. It transfers some of its kinetic energy to the cue ball, which rolls forward.
The type of collision mentioned in the given example is known as an inelastic collision is one in which the system's momentum is preserved but its kinetic energy is not. In a ballistic pendulum, an example of an inelastic collision. Dropped ball of clay is another illustration of an inelastic collision.
Thus, the correct option is A.
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Your question is incomplete, most probably the complete question is:
Which of the following statements describes a perfectly inelastic collision?
A. Two billiard balls bounce off of each other,
B. A car crashes into a tree and rebounds in the other direction,
C. A wad of chewing gum is thrown and sticks to a moving truck,
D. Two ice skaters hit each other and fall over in opposite directions,
If the grasses have 100 units of energy, how much can be passed to the grasshoppers?
=Matt (m = 80 kg) and Trey (m= 90 kg) slide across an ice skating rink and collidewith each other. Before the collision, Matt was moving 3 m/s to the east and Treywas moving 2 m/s to the west. After the collision, Matt is moving 1.5 m/s to thewest. What is the total momentum of the system after the collision
The total momentum after collision = 60 kgm/s
Explanation:\(\begin{gathered} \text{Mass of Matt, m}_m=\text{ 80kg} \\ \text{Mass of Trey, m}_t=\text{ 90 kg} \end{gathered}\)Before the collision:
Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west
\(\begin{gathered} \text{Initial speed of Matt, u}_m=\text{ 3m/s} \\ \text{Initial speed of Trey, u}_t=\text{ -2m/s (Since it is an opposite direction)} \end{gathered}\)According to the principle of momentum conservation:
The total momentum before collision = The total momentum after collision
\(\begin{gathered} \text{Total momentum before collision = m}_mu_m+m_tu_t \\ \text{Total momentum before collision = 80(3) + 90(-2)} \\ \text{Total momentum before collision = 240 - 180} \\ \text{Total momentum before collision = 60 kgm/s} \end{gathered}\)Since the total momentum before collision = Total momentum after collision
The total momentum after collision = 60 kgm/s
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
As a galaxy evolves and becomes more massive, what is most likely to happen?
Answer:
Explanation:
The most likely thing that would happen is that the galaxies continue becoming more and more massive, eventually becoming part of a galaxy cluster. These are massive but cluttered parts of the universe that hold many galaxies extremely close to one another. This also leads to galaxies colliding with one another, although when this happens they usually seem to pass right through each other as if they were ghosts. This is simply due to their sheer size and distance between their bodies of mass.
Answer:
It will merge with other galaxies
Explanation:
Pearson Connexus 2023
68. What is the trend of atomic size
on the periodic table?
Answer:
slowly decreases from left to right over the duration of the element.
An appeal of a state appellate court ruling can next be made to:
• A. a state trial court.
• B. the state supreme court.
• C. the U.S. Supreme Court.
• D. a U.S. Court of Appeals.
The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.
Why is Supreme renowned?In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.
Why is Supreme so expensive?Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.
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Would you rather know how you die or know when you die?
Answer:
I guess how cause then I could posibbly prevent it from happening it or if say I die from a protest and I saw a protest I could just be like well im gonna die today. Hbu?
Explanation:
Which type of wall would make the best soundproofing for room?
A.
1.0 centimeter thick glass
OB.
two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them
C.
two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them
OD.
1.0 centimeter thick steel
Among the options given, the choice that would make the best soundproofing for a room is option C: two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them.
Soundproofing is achieved by reducing the transmission of sound waves from one side of the wall to the other. In this case, the combination of two layers of glass with a vacuum between them helps to reduce sound transmission effectively.
Glass is a denser material compared to air or vacuum, so it naturally provides some sound insulation. Adding an extra layer of glass creates a barrier that helps to further dampen sound vibrations. The vacuum between the glass layers acts as an additional sound barrier, as sound waves have difficulty propagating through a vacuum due to the absence of a medium for transmission.
On the other hand, a single layer of 1.0 centimeter thick glass (option A) or two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them (option B) would provide some sound reduction but not as effective as the combination of glass layers with a vacuum in option C.
1.0 centimeter thick steel (option D) would have high density and mass, which could help with sound insulation to some extent. However, steel can still transmit vibrations and might not be as effective as the combination of glass layers with a vacuum in option C for soundproofing a room.
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Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?
The speed of the ball rebounding from the plate is approximately 13.2 m/s.
According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.
The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.
The speed of the ball rebounding can be calculated using the formula:
(1/2)mv²= (1/2)mv_0²
where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).
Solving for v, we get:
v = sqrt(v_0² - (2F/m))
where F is the maximum force exerted on the force plate (1900 N).
Plugging in the values, we get:
v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s
Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.
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A car battery has a rating of 170 ampere-hours. This rating is one indication of the total charge that the battery can provide to a circuit before failing. (a) What is the total charge (in coulombs) that this battery can provide
Answer:
612000 C
Explanation:
Current, I, is given as the rate of flow of charge, that is:
I = Δq / Δt
where q = electric charge
t = time taken
This implies that:
Δq = I * Δt
The battery rating is 170 Ampere-hours, therefore:
Δq = 170 * 1 hour
But 1 hour = 3600 seconds;
=> Δq = 170 * 3600 = 612000 C
The total charge that the battery can provide is 612000 C.
A weightlifter curls a 25 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ .
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Energy burn by the weightlifter = potential energy
Potential energy = mgh
Potential energy = 25.(9.8)(0.50)
Potential energy = 122.5 Joule.
Assume 25% of efficiency so energy burn = 122.5*25/100
energy burn = 30.625 joule
Number of times = 1260/30.625
Number of times = 42 times.
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
A 6 kg mass going 4 m/s is slowed to 3 m/s by a 2 N force for how much distance did the force act?
Given data:
* The mass of the object is m = 6 kg.
* The initial velocity of the object is u = 4m/s.
* The final velocity of the object is v = 3 m/s.
* The force acting on the object is F = 2 N.
Solution:
According to Newton's second law, the force acting on the object in terms of the acceleration of the object is,
\(F=ma\)Substituting the known values,
\(\begin{gathered} 2=6\times a \\ a=\frac{2}{6} \\ a=0.33ms^{-2} \end{gathered}\)As the acceleration is decreasing the velocity, thus, the value of acceleration is,
\(a=-0.33ms^{-2}\)By the kinematics equation, the distance traveled by the object in terms of the acceleration, initial velocity, and final velocity is,
\(v^2-u^2=2aS\)where S is the distance traveled by the object,
Substituting the known values,
\(\begin{gathered} 3^2-4^2=2\times(-0.33)\times S \\ 9-16=-0.66\times S \\ -7=-0.66\times S \\ S=\frac{-7}{-0.66} \end{gathered}\)By simplifying,
\(\begin{gathered} S=\frac{7}{0.66} \\ S=10.6\text{ m} \end{gathered}\)Thus, the distance for which force act to change the velocity from 4 m/s to 3 m/s is 10.6 meters.
A drum is struck first with little energy. The drum is then struck with a lot of energy. Which sound will be louder? Why?
Answer:
The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it
Explanation:
The ACE towing company tows a disabled 1050-kg automobile off the road ata constant speed. If the tow line makes an angle of 10.0° with the vertical asshown, what is the tension in the line supporting the car?
Answer:
10,448.74 N
Explanation:
First, we know that the mass of the car is 1050 kg and the tow line makes an angle of 10.0° with the vertical and we want to know the tension in the line, so
The given
m = 1050 kg
θ = 10.0°
g = 9.8 m/s²
The unknown
T = ?
To write the formula, we need to draw a free body diagram as follows
They are moving at a constant speed, so there is no acceleration and the sum of the forces is equal to 0.
In the vertical direction, we have the following equation
\(\begin{gathered} T\cos\theta-mg=0 \\ T\cos\theta=mg \\ T=\frac{mg}{cos\theta} \end{gathered}\)Therefore, the formula is
\(T=\frac{mg}{cos\theta}\)Replacing the values, we get
\(T=\frac{(1050kg)(9.8\text{ m/s}^2)}{cos(10)}=10448.74\text{ N}\)So, the answer is 10448.74 N
A 2 m tall barrel is closed on top except for a thin pipe extending 8 m up from the top. When the barrel is filled with water up to the base of the pipe (2 m deep), the water pressure on the bottom of the barrel is 20 KPa. What is the pressure on the bottom when water is added to fill the pipe to its top?
Pressure on the bottom when water is added to fill the pipe to its top is 180kPA.
In the first scenario, the atmospheric pressure is:
In the second scenario, h = 8m + 1 m. Therefore, the pressure at the bottom of the barrel is:
What is hydrostatic pressure meaning?
Hydrostatic pressure refers to the pressure that any fluid in a confined space exerts. If the fluid is in a container, there will be some pressure on the wall of that container.
What is hydrostatic pressure used for?
Hydrostatic pressure is one reason (along with the lack of oxygen) why it's not safe for humans to travel unprotected in space. You rely on hydrostatic pressure to keep your lungs at the right inflation and to keep the water in your body from vaporizing.
How is hydrostatic pressure calculated?
The pressure in a liquid at a given depth is called hydrostatic pressure. This can be calculated using the hydrostatic equation:
P = rho * g * d, where P is the pressure, rho is the density of the liquid, g is gravity (9.8 m/s^2) and d is the depth (or height) of the liquid.
Thus, the pressure on the bottom when water is added to fill the pipe to its top is 180kPa.
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Question 2 of 15
When the source of a sound is moving, its speed increases.
A. True
B. False
What did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
Yes the answer is A.) A Nucleus
Explanation:
I took the test
Rutherford’s model of the atom included a nucleus that Thomson’s model did not have, therefore the correct option is A
What are atomic models?There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.
There are many types of atomic models proposed in past based on their individual assumptions and the experimentations
There are mainly five most widely accepted atomic models
John Dalton's atomic model which based on the assumption that all the entities of the universe are made up of the fundamental particle that is an atom.
J.J. Thomson's model: Plum Pudding model explains the arrangement of subatomic particles by taking the example of plum pudding in which positive charge is distributed uniformly throughout and the negative charge particles are sprinkled on it in a random fashion.
Rutherford's model explained the existence of a nucleus inside the atom by using the alpha particle bombardment experiment on a thin sheet of gold.
Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.
Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model also known as the Quantum Model.
Rutherford’s model of the atom included a nucleus that Thomson’s model did not have, therefore the correct option is A
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How much force required to displace a body through 50cm by doing 25J work on it.
Answer:
50 N
Explanation:
W = Fd
F = W/d
first convert cm → m: 50 cm x 1 m/cm = 0.50 m
F = (25 J) / (0.50 m) = 50 N
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
Newton's Laws and Dynamics Unit Test
Imaging a text-book laying on table. According to Newtons third law which correct free-body diagram shows the force of the
table on the text-book?
↓
Diagram A
O Diagram A
O Diagram D
O Diagram C
O Diagram B
Diagram B
Diagram C
Diagram D
(1 point)
The diagram that shows the correct free-body diagram shows the force of the table on the text-book is diagram C.
What is the Newton law?We know that the idea of dynamics is based on the Newton laws. Note that the study of motion while we take into cognizance the reason for the motion is what we have called dynamics in this context.
We must recall that in accordance with the Newton third law, it is known that action and reaction are equal and opposite. This implies that when we exert a force an object, the object would also exert a similar force on the surface. The both forces are equal in magnitude but are exactly opposite in direction.
We can now see that in the diagram C, the forces of action and reaction that are acting on the book are exactly balanced as it lies on the table and this is in accordance with the Newton third law.
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5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 3.04 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answer:
\(F=2.84*10^{-26}N\) & -y direction
\(F=2.84*10^{-26}N\) & +y direction
Explanation:
From the question we are told that:
Speed of electron \(V_e=3.83 * 10^5 m/s\) +x direction
Earths magnetic field \(B_e=3.04 * 10^-^8\) +z direction
a)
Generally the equation for magnetic force \(F_m\) is mathematically given by
\(F=q(V_e*B_e)\)
where
\(q=1.6*10^{-19}c\\\=i*\=z=-\=j\)
\(F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(F=-2.84*10^{-26}N \=j\)
Magnitude & Direction
\(F=2.84*10^{-26}N\) -y direction
b)
Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by
\(\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(\=F'=-2.84*10^{-26}N \=j\)
Magnitude & Direction
\(F=2.84*10^{-26}N\) & +y direction
A 54.3 kg block is placed on an inclined plane that is 42.4 degrees from the horizontal. What is the acceleration of the block? Ignore friction
Given:
The mass of the block, m=54.3 kg
The angle of inclination, θ=42.4°
To find:
The accleration of the block.
Explanation:
The free-body diagram:
Referring to the diagram, N is the normal force, g is the acceleration due to gravity.
The only force acting on the block in the horizontal direction is the horizontal component of gravity.
Thus the net force on the block is given by,
\(\begin{gathered} ma=mgsin\theta \\ \Rightarrow a=gsin\theta \end{gathered}\)Where a is the acceleration of the block.
On substituting the known values,
\(\begin{gathered} a=9.8\times sin42.4\degree \\ =6.61\text{ m/s}^2 \end{gathered}\)Final answer:
The acceleration of the block is 6.61 m/s²
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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A 25 MGD surface water drinking plant has four circular clarifiers (aka sedimentation basin), operated in parallel with each basin receiving equal flow, that all have a diameter of 16 meters and are 3 m deep. Assume that all particles entering the clarifiers have the same particle density of 1.2 mg/mL and the average water temperature is 20 oC with an average viscosity of 1 g/(m*s) and an average density of 998.2 kg/m3.
1. What is the diameter of the smallest particles (in mm) that can be removed by these clarifiers?
2. If the each of the four clarifiers is to be rectangular in shape with a length to width ratio of 5:1, what is the minimum width that each clarifier can be (in meters)?
Answer:
can y
Explanation:
jj
The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
What is the equation for the settling velocity of a particle?The equation for the settling velocity of a particle:
V_s = (2/9) * (ρ_p - ρ_w) * g * r^2 / η
where V_s is the settling velocity, ρ_p is the particle density, ρ_w is the water density, g is the acceleration due to gravity, r is the particle radius, and η is the water viscosity.
1. We can rearrange the equation to solve for the particle radius:
r = [9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
We want to find the particle diameter, which is twice the radius, so we can substitute 2r for d in the following equation:
d = 2r = 2[9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
To remove the smallest particles, we want to use the smallest settling velocity possible, which corresponds to a particle just barely settling to the bottom of the clarifier. Therefore, we can set V_s equal to the minimum settling velocity required for particles to be removed:
V_s = Q / (A * X)
where Q is the flow rate (25 MGD), A is the surface area of one clarifier (πr^2), and X is the overflow rate, which is the flow rate per unit area of the clarifier. A typical overflow rate for a sedimentation basin is 600-1200 gallons per day per square foot (gpd/ft^2), or 2.5-5 m^3/day/m^2. We will use the lower end of this range, 2.5 m^3/day/m^2.
Substituting in the values for Q, A, and X, we get:
V_s = (25 MGD) / (π(8 m)^2 * 2.5 m^3/day/m^2) = 0.00159 m/s
Now we can substitute the values for η, ρ_p, ρ_w, g, and V_s into the equation for the particle diameter:
d = 2[9(1 g/(m*s))(0.00159 m/s) / (2(1200 kg/m^3 - 998.2 kg/m^3)(9.81 m/s^2))]^(1/2) = 0.0257 mm
So, the smallest particles that can be removed by these clarifiers have a diameter of approximately 0.0257 mm.
2. To find the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1, we can use the same overflow rate and flow rate as before, and we can assume a depth of 3 m. The surface area of one clarifier must still be the same as before, so we can use the equation for the surface area of a rectangle:
A = L * W
where L is the length and W is the width.
Substituting in the values for Q, X, and A, we get:
W = (25 MGD) / (5 * 24 hr/day * 60 min/hr * 60 s/min * 2.5 m^3/day/m^2 * 5 * L)
Simplifying, we get:
W = 0.023 L
So, the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
Therefore, The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and a rectangular clarifier's minimum width is 0.023 times the length when the length-to-width ratio is 5:1.
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What is the force on a 1,000 kg elevator that is falling freely at
25 m/s?
Explanation:
Force=mass*acceleration
Mass=1000kg
Acceleration=25m/s
F=1000*25
F=25000N