A plane accelerates from rest at a constant rate of 5. 00 m/s^2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the time to needed to take off?.

Answer:east

Explanation:Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.

Answer:

it rises east and moves west through out the day and sets west

The correct answer is option 4: A1, B2, C2

A1: The force of friction acting on the ladder is given by:

f_friction = µ * N

where µ is the coefficient of static friction and N is the normal force acting on the ladder, which is equal to the gravitational force acting on the ladder.

B2: The gravitational force acting on the ladder can be expressed as:

f_gravity = m * g

where m is the mass of the ladder and g is the acceleration due to gravity.

C2: The component of the gravitational force acting parallel to the wall can be expressed as:

f_parallel = f_gravity * sin(θ)

where θ is the angle between the ladder and the wall.

The ladder will remain stationary as long as the force of friction acting on it is equal to or greater than the component of the gravitational force acting parallel to the wall. Setting these two forces equal to each other, we get:

f_friction = f_parallel

µ * N = m * g * sin(θ)

The smallest angle θ for which the ladder remains stationary is given by:

sin(θ) = µ * N / (m * g)

θ = sin^-1 (µ * N / (m * g))

Note that the value of µ * N / (m * g) must be less than or equal to 1 for the ladder to remain stationary.

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Answer:

Gamma rays is used for nuclear power and for medical treatment

Answer:

it decrease by 9 times

Explanation:

If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

Answer:

α = 60 degr

Explanation:

To find the magnitude and direction of the resultant force, we can use the law of cosines and the law of sines:

Magnitude:

Let's call the forces A = 10N and B = 20N. The angle between them is 60 degrees. The magnitude of the resultant force R can be found using the formula:

R² = A² + B² - 2AB cosθ

where θ is the angle between the forces. Substituting the values we get:

R² = (10N)² + (20N)² - 2(10N)(20N) cos(60)

R² = 100N² + 400N² - 200N²

R² = 300N²

Taking the square root of both sides, we get:

R = sqrt(300N²) = 10 sqrt(3) N

Therefore, the magnitude of the resultant force is 10 sqrt(3) N.

Direction:

The direction of the resultant force can be found using the law of sines. Let's call the angle between the resultant force and the 10N force α, and the angle between the resultant force and the 20N force β. Then we have:

sin α / R = sin β / B

Substituting the values we get:

sin α / (10 sqrt(3) N) = sin 60 / 20N

Simplifying, we get:

sin α = (10 sqrt(3) N / 20N) sin 60

sin α = sqrt(3) / 2

Taking the inverse sine of both sides, we get:

α = 60 degrees

Therefore, the direction of the resultant force is 60 degrees from the 10N force

The element (A) F (fluorine) doesn't have similar chemical properties to neon (Ne).

The noble gases comprise a group of the periodic table, consisting of six chemical elements: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). The noble gases are the chemical elements that are the least reactive.

They are the lightest and have the smallest atomic radii of any element in their respective periods. Their non-reactivity makes them very useful in a wide range of applications. They are used in lighting, cryogenics, as pressurized gases for spacecraft propulsion, and in the semiconductor industry. The noble gases are located in the last column of the periodic table. The number of electrons in their outermost shell (the valence shell) is the same as the group number.

For example, helium and neon have two valence electrons, and argon has eight. Fluorine, represented by F on the periodic table, is a chemical element with the atomic number 9. It is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. As a member of the halogen group, it is a highly reactive element. Therefore, the option (A) F (fluorine) is not a noble gas and doesn't have similar chemical properties to neon (Ne).

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Answer:

they are gas giants. they are much much more bigger then terrestrial

The final temperature of the gas given the data from the question is 1527 °C

The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

V / 300 = 6V / T₂

Cross multiply

V × T₂ = 300 × 6V

Divide both side by V

T₂ = (300 × 6V) / V

T₂ = 1800 K

Subtract 273 from 1800 K to express in degree celsius

T₂ = 1800 – 273

T₂ = 1527 °C

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Answer: 8.75 km/hr

Explanation:

Concept to know

Average speed: total distance/total time

-------------------------------------------------------

 total distance/total time

=(12.2+19.3)/(1.4+2.2) ⇔ add the numbers of two time running together

=31.5/3.6 ⇔ simplify

=8.75 km/hr

Hope this helps!! :)

Please let me know if you have any question

Answer: the poles

Explanation:

Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.

Most crashes occur at intersections because of the following reason:

1) Drivers fail to search and identify a safe path of the travel when approaching an intersection.

2) Drivers don't identify or understand the risks.

3) Drivers fail tp develop good driving habits to effectively manage the risks.

Thus, Most crashes occur at intersections because all of the above reason. Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.

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The thermal energy will be transferred from the air to the surface. Hence, the answer is false.

Thermal energy can be transferred from higher temperatures to lower temperatures. It is obey the second law of thermodynamics

"At a very microscopic level, it simply says that if you have a system that is isolated, any natural process in that system progresses in the direction of increasing disorder, or entropy, of the system."

It means that heat energy transferred from the higher temperature and the lower temperature states will absorb heat energy from the surrounding. The thermal energy will be transferred through conduction, convection, or radiation.

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The kinetic energy of a he2 ion released from rest and accelerated through a potential difference of 2.5 is 4.32J.

In material science, the motor energy of an article is the energy that it has because of its movement. It is characterized as the need might have arisen to speed up a body of a given mass from rest to its expressed speed. Having acquired this energy during its speed increase, the body keeps up with this dynamic energy except if its speed changes. A similar measure of work is finished by the body while decelerating from its ongoing pace to a condition of rest. At the point when work is finished on an item, energy is moved, and the article moves with another steady speed. We call the energy that is moved motor energy, and it relies upon the mass and speed accomplished. Active energy of an item is the proportion of the work an article can do by uprightness of its movement.

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A ball is dropped out of a helicopter. If its final velocity at time t is vf, then its final velocity at time 0.5t is 0.5 vf.

The equation of motion for vertical motion is given by:

v = u + g . t

Where:

v = final velocity

u = initial velocity

t = time period

g = acceleration due to gravity

In the given problem, the ball experienced a free-fall motion. The initial velocity is zero.

The final velocity at time t is given by:

v = vf

Hence,

v = g . t

From the above equation, the final velocity is directly proportional to t

Let vs = the velocity at time 0.5 t.

Therefore,

vf : vs = t :  0.5t

vf : vs = 1 : 0.5

Hence, vs = 0.5 vf

The final velocity at time 0.5t is equal to 0.5 vf.

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Based on the relationship between power and time, the time required is 10.67 seconds

Force produced by the car = mass × acceleration

Force produced by the car engine = 30 kW = 3000 kW

mass of car = 800 Kg

acceleration of car = changein velocity / time

acceleration = 110 - 70/t = 40/t

3000 = 800 × 40/t

t = 32000/3000

time, t = 10.67 seconds

Therefore, the time required is 10.67 seconds

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The   AMPLITUDE  of a wave is the maximum distance that the particles in a medium move from their rest position as the wave passes.

The velocity with which the electrons drift in the silver wire is approximately 1.58 x 10^-4 m/s.

To find the velocity with which electrons drift in a silver wire, we can use the formula:

I = nAvq

where:

I is the current (in amperes),

n is the number of free electrons per unit volume (in m^3),

A is the cross-sectional area of the wire (in m^2),

v is the drift velocity of electrons (in m/s), and

q is the charge of an electron (approximately 1.6 x 10^-19 C).

Given:

I = 5.0 A (current)

n = 5.8 x 10^28 m^-3 (number of free electrons per m^3)

A = πr^2 = π(0.002 m)^2 (cross-sectional area)

q = 1.6 x 10^-19 C (charge of an electron)

First, we calculate the cross-sectional area of the wire:

A = π(0.002 m)^2 = 1.2566 x 10^-5 m^2

Next, we rearrange the formula and solve for v:

v = I / (nAq)

v = 5.0 A / (5.8 x 10^28 m^-3 * 1.2566 x 10^-5 m^2 * 1.6 x 10^-19 C)

v ≈ 1.58 x 10^-4 m/s

Therefore, the velocity with which the electrons drift in the silver wire is approximately 1.58 x 10^-4 m/s.

The drift velocity represents the average velocity at which the electrons move in the wire under the influence of an electric field. It is relatively small due to frequent collisions with lattice ions and other electrons within the wire.

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Answer:

a

Explanation:

cause her hand is straight and she followed the direction it sould be correctly unless I am messing something

Answer:

the work done in raising the load is 24,750 J

Explanation:

Given;

load lifted by the crane with a force, F = 2750 N

height through which the load was raised, h = 9.0 m

The work done by the crane in raising the load is calculated as;

W =  F x h

W = 2750 x 9

W = 24,750 J

Therefore, the work done by the crane in raising the load is 24,750 J

The nurse should administer approximately 1.075 ml of atropine subcutaneously (SC) based on the physician's order and the concentration of the vial.

To calculate the amount of atropine to be administered, we first need to convert the physician's order from grains (gr) to milligrams (mg).

1/150 gr can be converted to milligrams by multiplying it by the conversion factor of 64.79891. Thus, 1/150 gr is approximately 0.43 mg.

The atropine vial is labeled as 0.4 mg/ml, which means there is 0.4 mg of atropine in 1 ml of solution.

To determine the volume to be administered, we divide the required dose (0.43 mg) by the concentration of the vial (0.4 mg/ml):

0.43 mg / 0.4 mg/ml = 1.075 ml

Therefore, the nurse should administer approximately 1.075 ml of atropine subcutaneously (SC) based on the physician's order and the concentration of the vial.

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The mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.

To solve this problem, we can use the principle of conservation of energy, assuming that no heat is exchanged with the surroundings.

We'll use the equation:

Q_neon + Q_container = 0,

where Q_neon represents the heat gained or lost by the neon gas and Q_container represents the heat gained or lost by the container.

The heat gained or lost by a substance can be calculated using the equation:

Q = mcΔT,

where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Let's calculate the heat gained or lost by the neon gas:

Q_neon = m_neon × c_neon × ΔT_neon,

where m_neon is the mass of the neon gas and c_neon is its specific heat capacity.

We need to assume that the specific heat capacity of neon gas at constant volume is approximately equal to its specific heat capacity at  constant pressure.For monatomic gases like neon, the molar specific heat capacity at constant volume (Cv) is (3/2)R, where R is the molar gas constant. The molar specific heat capacity at constant pressure (Cp) is (5/2)R.

Since we have the molar mass of neon, we can calculate the molar gas constant (R) as follows:

R = 8.314 J/(mol·K).

The mass of neon gas can be determined using its molar mass (M) and the number of moles (n):

m_neon = n × M.

The number of moles can be obtained from the ideal gas law:

PV = nRT,

where P is the pressure, V is the volume, T is the temperature, and R is the molar gas constant.

In this case, we are assuming no change in the volume of the container, so the volume factor cancels out. Therefore, we don't need to consider the volume in our calculations.

Now let's calculate the heat gained or lost by the container:

Q_container = m_container × c_container × ΔT_container,

where m_container is the mass of the container and c_container is its specific heat capacity.

Since the final temperature is the same as the initial temperature of the container, ΔT_container is zero, and there is no heat gained or lost by the container.

Returning to the conservation of energy equation:

Q_neon + Q_container = 0,

we have:

Q_neon + 0 = 0,

Q_neon = 0.

Since Q_neon is zero, it means that no heat is gained or lost by the neon gas. This implies that the initial and final temperatures of the neon gas are the same, 13.0°C.

Now, let's calculate the mass of the neon gas:

m_neon = n × M,

where n is the number of moles.

To find the number of moles, we can use the ideal gas law:

PV = nRT,

where P is the pressure and R is the molar gas constant.

Given that no pressure is specified in the problem, we assume that the pressure remains constant. Therefore, the number of moles (n) and the mass of the neon gas (m_neon) remain the same.

In conclusion, the mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.

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The two equal-mass objects will stick together and move as one object after the completely inelastic collision.

In an inelastic collision, the two objects involved stick together and move as a single object after the collision. Since the objects have equal masses and are moving towards each other at equal speeds, their momenta will be equal and opposite before the collision.

During the collision, the objects come into contact and exert forces on each other. These internal forces cause the objects to deform and redistribute their velocities. However, due to the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision.

Since the initial momenta of the objects are equal and opposite, the final momentum of the combined object will also be zero. This means the objects will stick together and move as one object after the collision, with a common velocity. This scenario is known as a completely inelastic collision.

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Scientists believe that light is made of streams of particles, called photons, because of their observed behavior. In certain experiments, such as the photoelectric effect, it was found that light behaves more like a particle than a wave. For example, light can knock electrons out of atoms, which would require a particle-like behavior. Additionally, the energy of each photon is directly proportional to its frequency, which is a characteristic of particles. The behavior of light in other experiments, such as the double-slit experiment, can also be explained by the wave-like behavior of photons. Therefore, scientists have concluded that light has both particle and wave-like properties, known as wave-particle duality.

While this answer may provide helpful information for your assignment, it is important to remember that using it verbatim could be seen as plagiarism. To avoid this, it is best to use your own words and properly cite any sources used. This will ensure that you are giving credit to the original author and presenting your own unique perspective on the topic.

~~~Harsha~~~

Answer:

The number of freely moving neutrons decreases over time.

Explanation:

During a fission reaction, the total number of protons remains the same. In other words, the charge is conserved. It is the neutron number that decreases during a fission reaction.

Therefore, 'The number of freely moving neutrons decreases over time' is the correct answer.

Answer:

Answer: Because it at rest indefinitely without any external force acting upon it. Newton's first law also applies when the rocket is gliding through space with no external forces on it, it will travel in a straight line at a constant speed forever

Explanation:

Explanation:

extension(x) = 0.02m When the P.E is 10J.

extension(x)= 0.04m PE?.

P.E is proportional to Extension²

P.E/x² = P.E"/x"²

10/(0.02)² = P.E/(0.04)²

P.E= 10x(0.04)²/(0.02)²

P.E= 40J

As the number of resistors in a series circuit increases, the overall resistance increases.

A series circuit is a current pathway that lets electrons flow to one or more resistors.

In series circuit, the current flowing in each circuit component is the same, while the voltage across the circuit components are differnt.

The equivalent resistance of a series curict is obtained by adding all the inididual resistance of the circuit.

Re = R1 + R2 + R3

where;

So in a series circuit, as the number of resistance increases, the overall resistance or equivalent resistance increases.

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The expression for q(t) is q(t) = exp(cet - dtrct + C₁), in terms of e, r, t, and c.

To integrate both sides of the equation dq(t)q(t) - ce = -dtrc and obtain an expression for q(t) in terms of e, r, t, and c, follow these steps,

1. Rewrite the equation as: (dq(t)/q(t)) - (ce) = -dtrc
2. Integrate both sides with respect to t:
  ∫[(1/q(t))dq(t) - ce dt] = ∫[-dtrc dt]
3. Perform the integration:
  ln|q(t)| - cet = -dtrct + C₁ (where C₁ is the constant of integration)
4. Isolate ln|q(t)|:
  ln|q(t)| = cet - dtrct + C₁
5. Take the exponential of both sides to solve for q(t):
  q(t) = exp(cet - dtrct + C₁)

In terms of e, r, t, and c, the expression for q(t) is therefore q(t) = exp(cet - dtrct + C1).

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a) When an identical resistor is added in series with the first resistor and the cell, the current through the resistors will remain the same as A amps.

When an identical resistor is added in series with the first resistor and the cell, the current through the resistors will remain the same as A amps.

This is because in a series circuit, the same current flows through each component. The total resistance of the circuit increases when a resistor is added in series, but the voltage across the resistors remains the same as the voltage across the cell.

According to Ohm's law, V = IR, where V is voltage, I is current, and R is resistance.

Since the voltage is constant and the resistance has increased, the current through the resistors must remain the same to satisfy Ohm's law. Therefore, the current through the second resistor will also be A amps.

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Answer:

a = v^2 / R     centripetal acceleration of car

If a exceeds g then the car would leave the road

v = (a R)^1/2 = (9.80 * 45)^1/2 = 21 m/s

The speed must not exceed 21 m/s

Note (60 mph = 26.8 m/s)

The maximum speed that the car can have without flying off the road at the top of the hill is approximately 30.2 m/s.

To determine the maximum speed that a car can have without flying off the road at the top of a hill, we need to consider the centripetal force and the gravitational force acting on the car.

At the top of the hill, the gravitational force acting on the car is directed downwards, while the centripetal force required to keep the car moving in a circular path is directed upwards. The maximum speed that the car can have is the speed at which the gravitational force just balances the centripetal force.

The centripetal force required to keep the car moving in a circle of radius 45 m is given by:

\(F_c = mv^2/r\)

where m is the mass of the car, v is its speed, and r is the radius of the circle.

The gravitational force acting on the car is given by:

\(F_g = mg\)

where g is the acceleration due to gravity and m is the mass of the car.

For the car to remain on the road at the top of the hill, the centripetal force must be equal to the gravitational force, so:

\(F_c = F_g\)

\(mv^2/r = mg\)

Simplifying this expression gives:

\(v^2 = rg\\v = \sqrt{rg}\)

Substituting the values of r and g gives:

\(v = \sqrt{45 m * 9.81 m/s^2} v = 30.2 m/s\)

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