Based on the data, we do not have sufficient evidence to conclude that the company's premise is not correct.
To test the null hypothesis that 5% of the company's current customers qualify for membership against the alternative that it is not correct, we can perform a hypothesis test using the given data. Let's go through the steps:
(a) Hypothesis Testing:
Null Hypothesis (H0): p = 0.05 (5% of customers qualify)
Alternative Hypothesis (Ha): p ≠ 0.05 (not 5% of customers qualify)
Here, p represents the population proportion of customers who qualify for membership.
We will use the sample proportion as an estimate of the population proportion. In this case, the sample proportion is 42/500 = 0.084.
We will conduct a two-tailed test at a significance level of 0.01 (α = 0.01). This means we will reject the null hypothesis if the test statistic falls in the rejection region defined by the critical values.
To perform the test, we can use the z-test for proportions. The test statistic is calculated as:
z = ( - p0) / sqrt(p0 * (1 - p0) / n)
Where is the sample proportion, p0 is the hypothesized proportion under the null hypothesis, and n is the sample size.
In this case, = 0.084, p0 = 0.05, and n = 500.
Calculating the test statistic:
z = (0.084 - 0.05) / sqrt(0.05 * (1 - 0.05) / 500)
z ≈ 1.478
Next, we need to find the critical values for a two-tailed test with a significance level of 0.01. This critical value corresponds to the z-value that leaves 0.005 (0.01/2) in each tail of the standard normal distribution.
Using a standard normal distribution table or a calculator, the critical values are approximately -2.576 and 2.576.
Since our test statistic (1.478) does not fall in the rejection region (-2.576 to 2.576), we fail to reject the null hypothesis.
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Jean spent $37.50 for 500 paperclips. How much did he pay for each paperclip?
Determine the type of triangle that is drawn below.
⇒ ΔVWX is a Scalene triangle because all the sides and all the angle are not equal.
one popular item at the school store is scented pencils. The pencils come in packs of 24 from the reseller. Write an algebraic expression that represents the total number of pencils the store has available to sell
Therefore , the solution of the given problem of expressions comes out to be 24 represents the number of pencils in each pack.
What does an expression exactly mean?Estimates should be generated using growing, equation, and blocking moving numbers rather than at random. They could only help one another by sharing resources, information, or solutions to issues. A statement of variable may also include formulas, pieces, and notations in addition to numerical calculations like addition, negate, synthesis, and combination. Evaluation and analysis are possible for both sentences and words.
Here,
The algebraic expression can be used to calculate the quantity of pencils the store has available for sale
if it has "n" packs of scented pencils, each having 24 pencils:
=> 24n
where n is the number of packs available, and 24 represents the number of pencils in each pack.
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Can someone help please?
Answer:
It’s either A or C. However I’m mostly going with C. For C tells us 2 hours and 23 minutes have passed. I hope this helps.
Step-by-step explanation:
Please correct me if I am wrong.
sin2x-sin2xcos2x=sin4x
It looks like the given equation is
sin(2x) - sin(2x) cos(2x) = sin(4x)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)
Move everything over to one side and factorize:
sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0
sin(2x) - 3 sin(2x) cos(2x) = 0
sin(2x) (1 - 3 cos(2x)) = 0
Then we have two families of solutions,
sin(2x) = 0 or 1 - 3 cos(2x) = 0
sin(2x) = 0 or cos(2x) = 1/3
[2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
(where n is any integer)
[2x = 2nπ or 2x = π + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
[x = nπ or x = π/2 + nπ]
… … … or [x = 1/2 arccos(1/3) + nπ or x = -1/2 arccos(1/3) + nπ]
Proportional Relationships
Complete this table
1 | ?
4 | 12
6 | ?
14| ?
hi there! in my understanding, here are the answers...
Answer:
1 | 3
4 | 12
6 | 18
14 | 42
Step-by-step explanation:
12 ÷ 4 = 3
1 x 3 = 3
6 x 3 = 18
14 x 3 = 42
hope this helped! have a good one.
Sorry about the rainbow stuff but what’s the answer
Answer:
16 strips
Step-by-step explanation:
37.75/2.25=16.8...
Since you can't cut a fraction of what they need, 16 should be the answer
hope this helps :)
BRAINLIEST AND 50 POINTS UP FOR GRABS: PLEASE LEAVE DETAILED ANSWERS
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P'Q'R' has vertices P'(1, −2), Q'(0, 3), and R'(−1, 0).
Plot triangles PQR and P'Q'R' on your own coordinate grid.
Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P'Q'R'? Explain your answer. (4 points)
Part B: Write the coordinates of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis. (4 points)
Part C: Are the two triangles PQR and P''Q''R'' congruent? Explain your answer. (2 points)
Answer:
Triangle P' Q' R' is half the size of the original triangle.
-The scale factor is probably 1/3.
Part B: P'(1, −2), Q'(0, 3), and R'(−1, 0).
Part C: No, the triangles are not congruent. If the second triangle didn't have a dilation, and instead have a reflection of the first triangle, then it would be congruent.
Step-by-step explanation:
:)
Use conditional proof and the eighteen rules of inference to derive the conclusions of the following symbolized arguments. Having done so, attempt to derive the conclusions without using conditional proof.
1. N ⊃ O
2. N ⊃ P / N ⊃ (O • P)
The conclusion of the symbolised argument is that N implies (O and P). This can be proven using conditional proof and the eighteen rules of inference, or using the rule of conjunctive simplification.
The symbolic argument's conclusion is that N implies (O and P). This can be demonstrated using conditional proof and the eighteen inference rules.
Proof:
1. N ⊃ O (Premise)
2. N ⊃ P (Premise)
3. N (Assumption)
4. O (1,3 Modus Ponens)
5. P (2,3 Modus Ponens)
6. O•P (4,5 Conjunction)
7. N ⊃ (O•P) (3-6 Conditional Proof)
8. N ⊃ (O•P) (2,7 Disjunctive Syllogism)
This leads us to the conclusion that N implies (O and P).
Without the use of conditional proof, the identical result can be reached. The conjunctive simplification rule can be used to do this.
Proof:
1. N ⊃ O (Premise)
2. N ⊃ P (Premise)
3. N (Assumption)
4. O (1,3 Modus Ponens)
5. P (2,3 Modus Ponens)
6. O•P (4,5 Conjunction)
7. N ⊃ (O•P) (Conjunctive Simplification)
Therefore, we have derived the conclusion that N implies (O and P).
Complete Question:
Use conditional proof and the eighteen rules of inference to derive the conclusions of the following symbolized arguments. Having done so, attempt to derive the conclusions without using conditional proof.
1. N ⊃ O
2. N ⊃ P / N ⊃ (O • P)
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Which function forms a geometric sequence when x = 1, 2, 3, ...?
f (x) = 8 x minus 9
f (x) = negative 2 (three-fourths) superscript x
f (x) = two-thirds x superscript 5
f (x) = 6 minus startfraction 4 over x endfraction
The function that forms geometric sequence : f(x) = \(-2(\frac{3}{4} )^{x}\)
Given,
x = 1, 2 , 3 , 4 ..
Now,
Geometric sequence : A geometric sequence is formed when there is a common ratio between terms.
The formula for a term in a geometric sequence is as follows:
\(a_{n} = a_{1} * r^{n-1}\)
So substitute the value of x as n in the formula for each function .
1)
f(x) = 8x -9
f(1) = -1
f(2) = 7
f(3) = 17
Here the common ratio is not same .
2) f(x) = \(-2(\frac{3}{4} )^{x}\)
f(1) = -3/2
f(2) = -9/8
f(3) = -27/32
Thus here the common ratio between two consecutive terms is same .
Therefore it forms a geometric sequence .
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what is the expression for the probability when the disease D is present but the test says its not? P = Event that test is positive, D = Event disease is present
Answer:
\(P(D\ and\ P^c)\) or \(P(D\ and\ P')\)
Step-by-step explanation:
Given
P = Test is positive
D = Disease is present
Required
Write an expression when disease is present but test says that the disease is not present
The above statement can be split to two
Disease is Present & Test is not positive
The first statement:
Disease is Present means D
The second statement
Test is not positive means not P
Mathematically;
not P means P' or \(P^c\)
So, the required expression is: \(P(D\ and\ P^c)\) or \(P(D\ and\ P')\)
Can someone pleaseeee help and if you’re correct i’ll give brainliest
Answer:i think is the fourth one or the fifth one.
Step-by-step explanation:
Answer:
california
Step-by-step explanation:
A man buy a houe for $175,000. He make a $75,000 down payment and amortize the ret of the debt with emiannual payment over the next 10 year. The interet rate on the debt i 12%, compounded emiannually. FInd: (a) the ize of each payment, (b) the total amount paid over the life of the loan, and (c) the total interet paid over the life of the loan
a) The size of each payment = $8718.4
b) The the total amount paid for the purchase = $204620.8
c) The total interest paid over the life of the loan = $104620.8
In this question we have been given that a man buys a house for $175,000. He makes a $75,000 down payment and amortizes the rest of the debt with semiannual payment sover the next 10 years. The interest rate on the debt is 12%, compounded semiannually.
We need to find the size of each payment, the total amount paid for the purchase and the total interest paid over the life of the loan.
From given data we get 175,000 - 75,000 = $100,000 amount to finance.
We know that the formula for semiannual payment of a loan,
C = PV/[1 - (1 + r)^-t / r]
Here, PV = $100,000
t = 20 (10 years times 2 payment per year)
r = 0.06 (12% annual. so, we divide by 2 to get semiannual)
So, C = 100,000/[1 - (1 + 0.06)^-20 / 0.06]
C = 100,000/[0.6882 / 0.06]
C = 100,000/11.47
C = $8718.4
The total interest paid will be the cuota times the time of the loan:
Total interest paid:
8718.4 x 12 = 104620.8
And the total amount paid over the life of the loan = 104620.8 + 100,000
= $204620.8
The interest will be the difference between the total amount paid and the principal of the loan
Therefore, Interest paid = $8718.4
total payment = $204620.8
principal = $100,000
Interest expense = $104620.8
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A child's parents deposit Rx into a savings account on the day of the child's birth to help towards her university education. The child will be able to withdraw regular half-yearly amounts from the savings account starting with a withdrawal of R12000 on her 19th birthday and ending with a final withdrawal on her 24th birthday. To keep up with inflation the withdrawals will need to increase at a rate of 6% p. each half-year from the second withdrawal onwards. If the savings account earns interest at a rate 8% p.a. compounded quarterly, then the value of Rx, to the nearest cent, that must be deposited initially into the savings account in order to fund the future growing withdrawals, is equal to: (Hint: Think carefully about where the Pv and Fv of the withdrawals is situated on the time line!) R120 468,80 R27 281,09 R26 746,17 R27 826,71 R25 427,36
The value of PV based on the question requirements is given as R27 281,09.
How to solveThere is a consistent increase in the withdrawals, with a growth rate of 6% per annum. The interest accrues at a yearly rate of 8%, and is compounded twice a year.
Having an interest rate that is calculated and added every three months. The accelerated growth of withdrawals surpasses the pace at which interest is accumulating, causing the eventual depletion of the savings account's value.
To calculate the value of the savings account, we need to use the future value of an annuity formula. The formula is:
\(FV = PV * [((1 + r)^n - (1 + g)^n) / (r - g)]\)
where:
FV is the future value of the annuity
PV is the present value of the annuity
r is the interest rate
n is the number of payments
g is the growth rate
In this case, the present value is the amount that needs to be deposited into the savings account, the interest rate is 8% p.a. compounded quarterly, the number of payments is 6 (24 / 4), and the growth rate is 6% p.a. compounded semi-annually.
Plugging these values into the formula, we get:
\(FV = PV * [((1 + r)^n - (1 + g)^n) / (r - g)]\\FV = PV * [((1 + 0.02)^6 - (1 + 0.03)^6) / (0.02 - 0.03)]\\FV = PV * 10.766\)
Solving for PV, we get:
PV = FV / 10.766
PV = 27 281,09
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Nora planted 65 seeds. 80% of them sprouded. How many seeds sprouded
Answer:
52
Step-by-step explanation:
80%of65
(80/100)×65
52
14. Jerry charges a fee of $45 plus $15 per hour to rent a motorbike. Write an equation to
calculate rental cost and tell what x and y mean. If you have $120 to spend, how long can you rent
for?
Answer:
5 hours, y= how much money it will cost, and x represents how many hours
Step-by-step explanation:
y= 15x+45
120= 15x+45
-45 -45
75= 15x
75/15×= 5 hours
To simplify 8. 3 − 4 1 5 ( 6. 1 + 1 2 ) , which operation must be performed first? Which operation must be performed second? Which operation must be performed last? Which is the simplified expression in the decimal form?
its a mutilpy choice question the choices are addition, multiplication, and subtraction
Answer:
Step-by-step explanation:
Use PEMDAS to determine order of operations.
P = Parentheses
E = Exponents
M/D = Multiplication/Division
A/S = Addition/Subtraction
The operation in the parentheses must be performed first, which is the addition of 6.1 + 12.
The next operation to perform is multiplication, which is 415 times (6.1 + 12).
The last operation to perform is the subtraction of 415 times (6.1 + 12) from 8.3.
6.1 + 12 = 18.1
8.3 - 415(18.1)
8.3 - 7511.5 = -7503.2
the total cost of a bike cycle and radio is rupees 7000. if the cost of the bike cycle is rupees thousand a more than two times of the cost of the radio find the cost of each of these two items
Answer :
Radio = 2000
Bike = 5000
Hope this helps u
AC is a diameter of OE, the area of
the
circle is 2897 units², and AB = 16 units.
Find BC and mBC.
B
A
C
E
Given that AC is a diameter of the circle, we can conclude that triangle ABC is a right triangle, with AC being the hypotenuse. The area of the circle is not directly related to finding the lengths of BC or AB, so we will focus on the given information: AB = 16 units.
Using the Pythagorean theorem, we can find BC. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AB and BC):
AC² = AB² + BC²
Substituting the given values, we have:
(AC)² = (AB)² + (BC)²
(AC)² = 16² + (BC)²
(AC)² = 256 + (BC)²
Now, we need to find the length of AC. Since AC is a diameter of the circle, the length of AC is equal to twice the radius of the circle.
AC = 2 * radius
To find the radius, we can use the formula for the area of a circle:
Area = π * radius²
Given that the area of the circle is 2897 units², we can solve for the radius:
2897 = π * radius²
radius² = 2897 / π
radius = √(2897 / π)
Now we have the length of AC, which is equal to twice the radius. We can substitute this value into the equation:
(2 * radius)² = 256 + (BC)²
4 * radius² = 256 + (BC)²
Substituting the value of radius, we have:
4 * (√(2897 / π))² = 256 + (BC)²
4 * (2897 / π) = 256 + (BC)²
Simplifying the equation gives:
(4 * 2897) / π = 256 + (BC)²
BC² = (4 * 2897) / π - 256
Now we can solve for BC by taking the square root of both sides:
BC = √((4 * 2897) / π - 256)
To find the measure of angle BC (mBC), we know that triangle ABC is a right triangle, so angle B will be 90 degrees.
In summary:
BC = √((4 * 2897) / π - 256)
mBC = 90 degrees
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Show your work for the math problem
Given :
x + 2x - 20 = 85To find :
The value of x .Solution :
According to Question ,
x + 2x - 20 = 85 3x - 20 = 85 3x = 85 + 20 3x = 105 x = 105/3 x = 35Find the distance between the two points rounding to the nearest tenth (if necessary). (-1,8) and (8,5)
Simplify. Show your work.
a. |5 - 7| =2
b. -3|11 - 15|=-12
Answer:
|5 - 7| =2
What you want to do first is to do the equation 5-7 which is -2 but there is an absolute value sign so 2.
-3|11 - 15|=-12
For this one it is a little more difficult but all you have to do is do the equation 11-15 which is -4 but there is an absoulte value sign so 4 you then multiply 4 by -3 which is -12 bam.
Water comes out of a garden hose at a constant rate to fill a pool. After 3 minutes, the pool is filled with 30 gallons of water. After 6.5 minutes, the pool is filled with 65 gallons of water.
a. Write an equation that represents the number of gallons of water y in the pool after x minutes.
b. How long will it take to fill a pool that needs 10,000 gallons of water?
Answer:
a. y = 10x
b. 1000 minutes of 16 2/3 hours
Step-by-step explanation:
a.
30 gal / 3 min = 10 gal/min
65 gal / 6.5 min = 10 gal/min
The relation is a direct proportion.
y = kx
The filling rate is the slope which is also the constant of proportionality.
The equation is
y = 10x
b.
y = 10x
10,000 = 10x
x = 10,000/10
x = 1000
The time is 1000 minutes, or 16 2/3 hours.
what are some possible outcomes of tossing a coin and roll a fair number pyramid that has four sides labeled 1 -4
Answer:
3
Step-by-step explanation:
np have a good day!
Answer:
the answr with be 8 i did this nd got i right good luck!!!!!!!!!!!!
Step-by-step explanation:
A model boat i 15 inche long if the boat i bulit to a cale of 1 : 250 inche how long i the real boat
define a variable
write a porortion
olve the porportion
anwer with word
If the scale of drawing is 1 inches : 250 inche and the real horse height is 15 inche, then the height of the horse in drawing is 0.06 inches.
What does a scale look like in math?The ratio that describes the relationship between the true figure itself and model is called the scale. It serves as a representation of the real statistics in smaller units on maps. A scale of 1:5, for instance, indicates that 1 on the map is approximately the size of 5 in the actual world.
Briefing:The scale of drawing the horse = 1 inch :
Therefore in scale
Horse height in drawing equals one inch
The height of the horse = 250 inche
The original height of the horse = 15 inche
The height in the picture = x inches
To find the height the horse in the picture, we have to use proportion
1 inch : 250 inche = x inches : 15 inche
1 / 250 = x / 15
1 × 15= 250x
250x = 15
x = 15/250
x = 0.06 inches
Therefore, the height of the horse in drawing is 0.06 inches
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A student sorted 950 crayons into boxes that hold 36 crayons each. How many more crayons will the student need to completely fill the last box? A 6
Answer:
14 crayons
Explanation:
Once you divide the remainder is 14 so you add 14
To answer questions 4 - 6.
A new school opened with 225 students in 2021 and plans to increase by 13. 3% per year
until they reach full capacity.
Is this situation exponential growth or decay?
4.
5.
Write an equation that models the population of the school, P, after x years since
the opening of the school in 2021
The situation provided is exponential growth and the equation is
p = 225 * 1.133ˣ
How to determine the situationThis scenario represents a significant improvement as the number of students increases each year.
The basic approach to incremental growth is:
\(P = P_{0} * (1 + r)^t\)
where:
P. = initial population
r = increase in decimal form
t = time in years
Here
P₀ = 225 (initial population in 2021).
r = 13.3% = 0.133 (growth rate as decimal) .
t = x (time in years from the opening of the school in 2021)
Substituting these values in the formula we get:
\(p = 225 * (1 + 0.133)^x\)
Simplifying further, we get:
p = 225 * 1.133ˣ
This is the equation that predicts school population x years after the school opens in 2021
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prove the following statement. assume that all sets are subsets of a universal set u. for all sets a and b, if ac ⊆ b then a ∪ b = u.
We can say that "For all sets A and B, if
A^c ⊆ B, then A ∪ B = U."
Given: All sets are subsets of a universal set U. For all sets A and B, if
A^c ⊆ B, then A ∪ B = U.
To prove:
A ∪ B = U.
Proof:
Let x ∈ U. Since all sets are subsets of U,
x ∈ A ∪ A^c.
We will have two cases to consider:
Case 1: x ∈ A.
In this case, x ∈ A ∪ B and we are done.
Case 2: x ∉ A.
In this case, x ∈ A^c and by our assumption, A^c ⊆ B.
Thus, x ∈ B.
Hence, x ∈ A ∪ B. So, U ⊆ A ∪ B.
Now, let y ∈ A ∪ B.
Then either y ∈ A or y ∈ B.
If y ∈ A, then y ∈ U since A ⊆ U.
If y ∈ B, then y ∈ U since B ⊆ U.
Thus, we have shown that A ∪ B ⊆ U.
Therefore, A ∪ B = U.
Hence Proved. This is the required statement. Hence, we can say that "For all sets A and B, if A^c ⊆ B, then A ∪ B = U."
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Factor out the greatest common factor. If the greatest common factor is 1, just retype the polynomial.
24f2+11
Answer:
24t^2 + 11
Step-by-step explanation:
There is a lot left out of this question. If you are allowed rational numbers, a common factor could be 24.
24(t^2 + 11/24) is one possibility.
I think what you mean is there an integer that is a common factor. There is not.
So the answer is 24t^2 + 11
There is one more thing that needs to be clarified. Can you give t a value? If you can, then t = 11
the common factor would be
11(24 * 11 + 1)
I doubt very much that this is what is meant, but the question really should make it clear.
Answer:
1(24f²+11) is your answer
Step-by-step explanation:
24f2+11
taking common
1(24f²+11)
Lana does yard work. The information below shows the approximate time for each job:
Mow small lawn - 1/2hr
Mow large lawn - 3/4hr
Tidy yard - 1 1/2hr
Plant annuals - 2 1/2hrs
For one Saturday, Lana needs to mow 3 small lawns, mow 1 large lawn, tidy 2 yards, and plant annuals once. She needs travel time between jobs, and a break for lunch. Do you think she will be able to complete all of the jobs in one day? Justify your answer.
Answer:
No, not enough timeStep-by-step explanation:
Time to complete each of jobs
1/2 * 3 = 1 1/2 hrs3/4 * 1 = 3/4 hr1 1/2 * 2 = 3 hrs2 1/2 * 1 = 2 1/2 hrsTotal time at job
1 1/2 + 3/4 + 3 + 2 1/2 = 7 3/4 hrsIf the work day lasts for 8 hours, then Lana has only 1/4 hr to travel between jobs and a lunch break.
This time is not sufficient so she can't complete all the jobs.
Answer:
No (see explanation below)
Step-by-step explanation:
Approximate times to carry out each job:
Mow small lawn = 1/2 hrMow large lawn = 3/4 hrTidy yard = 1 1/2 hrPlant annuals = 2 1/2 hrsFor one Saturday, Lana needs to:
mow 3 small lawnsmow 1 large lawntidy 2 yardsplant annuals onceTherefore, the total time for the jobs is:
\(\begin{aligned}\sf Total\:time & = \sf 3\:small\:lawns+1\:large\:lawn+2\:tidy\:yards+1\:plant\:annuals\\\\& = \sf 3 \cdot \dfrac{1}{2}+\dfrac{3}{4}+2 \cdot 1 \frac{1}{2}+2\frac{1}{2}\\\\& = \sf 1 \frac{1}{2}+\dfrac{3}{4}+3+2\frac{1}{2}\\\\& =\sf 7 \frac{3}{4}\: hours\end{aligned}\)
The likelihood of Lana being able to complete all the jobs in one day is dependent on how far she needs to travel between jobs and how long she wishes to break for lunch. A typical working day is around 8 hours. Therefore, unless Lana wishes to work for a longer day, it is unlikely she will be able to complete all of the jobs in one day as there is only 15 minutes available for traveling and lunch, which is likely not enough.