A pitot tube on an airplane flying at standard sea level reads 26kpa. What is the velocity of the airplane (in m/s)?

Answer:

an apple because its gaining speed as it falls

Explanation:

Answer:

a) The initial momentum of the ball is 22.5 kg·m/s

b) The magnitude of the momentum imparted by the ball is 30 kg·m/s

Explanation:

The question is based on change in momentum

The mass of the ball, m = 0.75 kg

The velocity with which the ball is thrown against the wall, u = 30 m/s

The time duration it takes while the ball is in contact with the wall, Δt = 0.05 sec

The velocity of the ball as it bounce back, v = -10 m/s (The ball moves in the opposite direction)

a) The initial momentum of the ball, \(P_{Initial}\) = m × u = 0.75 kg × 30 m/s = 22.5 kg·m/s

b) The final momentum of the ball, \(P_{Final}\) = m × v = 0.75 kg × (-10 m/s) = -7.5 kg·m/s

The momentum imparted by the ball, ΔP = The final momentum - The initial momentum

∴ ΔP = \(P_{Final}\) - \(P_{Initial}\)  =  -7.5 kg·m/s - 22.5 kg·m/s = -30 kg·m/s

The magnitude of the momentum imparted by the ball, \(\left | \Delta P \right |\) = 30 kg·m/s

Answer:

your mama

Explanation:

because i said so

Answer:

1164m

Explanation:

speed=distance/time, therefore Distance=speed*time.

Now that we have our equation, we plug in the variables, as we do not need to convert our units.

12*97= 1164 m

Answer:

they will increase why because they go from warm cold warm meaning they have to adapt back to the previous location

Explanation:

Answer: mechanical waves are caused by the disturbance of vibration in matter, whether solid, gas, liquid, or plasma.

Explanation:

The answer is infrared.

di ko Alam baka Nanay mo

The angular acceleration of the wheel at t = 2.0 s is d^2θ/dt^2 = -24 rad/s^2 (option b). This is obtained by taking the second derivative of the angular position function with respect to time.

Given: θ = 3.0 - 2.0t^3

Taking the first derivative of θ with respect to time:

dθ/dt = -6.0t^2

Taking the second derivative of θ with respect to time:

d^2θ/dt^2 = -12.0t

Plugging in t = 2.0 s:

d^2θ/dt^2 = -12.0(2.0) = -24 rad/s^2

Therefore, the angular acceleration of the wheel at t = 2.0 s is -24 rad/s^2.

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Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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The factor that is essential to the initial formation of galaxies, for either of the theories describing galaxy evolution is gravity. Galaxies are formed by the gravitational interaction between dark matter and the baryonic matter present in the universe.

A galaxy is a large group of stars, dust, and gas bound together by gravity. It is the basic unit of observation in astronomy and one of the most important structures in the universe.Galaxies are classified into three primary types: elliptical, spiral, and irregular.

Each type is defined by its shape, which is determined by the pattern of its stars' orbits. The Milky Way, our galaxy, is a barred spiral galaxy.In conclusion, gravity is the most crucial factor in the formation of galaxies, according to both theories of galaxy evolution.

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Answer:

a. Walking burns up more energy.

b. 1740 kJ

c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.

Explanation:

a. We know energy W = Pt where P = power and t = time.

Now for walking, t = d/v where d = distance = 5.00 km and v = speed = 3.00 km/hr and P = 290 W

So, t = d/v = 5.00 km/3.00 km/hr = 5/3 hr = 5/3 × 3600 s = 6000 s

W = Pt = 290 W × 6000 s = 1740000 = 1740 kJ

Now for running, t = d/v where d = distance = 5.00 km and v = speed = 10.00 km/hr

So, t = d/v = 5.00 km/10.00 km/hr = 0.5 hr = 0.5 × 3600 s = 1800 s and P = 700 W

W = Pt = 700 W × 1800 s = 1260000 = 1260 kJ

Since walking burns up 1740 kJ and running burns up 1260 kJ, walking burns up more energy.

b. It burns up 1740 kJ

c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.

Answer:

A) 80 N

Explanation:

The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.

The Coulomb force if the same particles are separated by a distance of 6 meters is 222.221 N.

Coulomb force is also known as electrostatic force is the force of attraction or repulsion of particles or objects because of their electric charge. It is given by the formula,

\(F = k \dfrac{q_1q_2}{r^2}\)

Where

F = electric force

k = Coulomb constant = 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻²

\(q_1, q_2\) = charges

r = distance of separation

We know that the distance between the two particles is 12 meters while the force between the two particles is 20N, therefore, the Coulombs force can be written as,

\(F = k \dfrac{q_1q_2}{r^2}\\\\20 = k \dfrac{q_1q_2}{20^2}\\\\k {q_1q_2} = 20 \times 20^2\\\\k {q_1q_2} = 8000\)

Now, if the distance between the two particles is reduced to 6, the force will be,

\(F = k \dfrac{q_1q_2}{r^2}\\\\F = \dfrac{8000}{6^2}\\\\F = 222.221\rm\ N\)

Hence, the Coulomb force if the same particles are separated by a distance of 6 meters is 222.221 N.

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Answer:

A change in velocity is either a change in an object's speed or its direction. When a moving object changes direction, its velocity changes and it is accelerating.

Explanation:

Answer: arrange systematically in groups; separate according to type, class, etc.

Explanation:

i hooked this up btw

An electric field is a region around a charged particle where other charges experience an electric force. In the case of a -5.0 x 10^-5 C point charge, it is a negatively charged particle.

To draw the electric field lines around this point charge, start by placing the charge at the center of your diagram. Since the charge is negative, the electric field lines will point towards the charge, indicating the direction of the force on a positive test charge placed in the field. Draw arrows on the field lines to show this direction. The lines should be evenly spaced and radiate inwards towards the point charge.Equipotential lines represent regions where the electric potential is constant. These lines are always perpendicular to the electric field lines. To draw two equipotential lines, draw curved lines around the point charge, making sure they are perpendicular to the electric field lines. The spacing between the equipotential lines will vary based on the strength of the electric field, with closer lines indicating a stronger field.

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GPS and satellite imagery used to measure glacier speed. Underwater challenges in measuring mid-ocean ridge spreading rate.

To gauge the speed of a glacial mass, researchers could utilize a blend of GPS recipients and satellite symbolism. GPS recipients can follow the development of markers put on the ice sheet's surface after some time, while satellite symbolism can give a more extensive perspective on the icy mass' general development.

This information can be utilized to work out the icy mass' normal speed throughout a year.One extra test researchers face in estimating the spreading rate at a mid-sea edge contrasted with estimating the speed of an ice sheet is the trouble of working in a submerged climate.

It tends to be trying to convey instruments and gather information at the ocean bottom, and the sea climate can be brutal and flighty. Furthermore, the mid-sea edge framework is continually changing, so estimations should be assumed control over an extensive stretch of time to precisely decide the spreading rate.

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To determine the magnitude and direction of the magnetic field produced by a current-carrying wire in Investigation 1, you can use Ampère's Law and the right-hand rule. Ampère's Law relates the magnetic field around a closed loop to the electric current passing through that loop.

In the case of a straight wire, the magnetic field forms concentric circles around the wire, with the field's strength decreasing as you move farther from the wire.

To calculate the magnitude of the magnetic field, you can use the formula B = (μ₀ * I) / (2 * π * r), where B represents the magnetic field strength, μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), I is the current through the wire, and r is the distance from the wire to the point where the magnetic field is being measured.

For determining the direction of the magnetic field, you can use the right-hand rule. If you point your thumb in the direction of the current and curl your fingers, your fingers will wrap around the wire in the direction of the magnetic field. This means that if the current flows upward, the magnetic field will rotate clockwise around the wire when viewed from above.

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The vertical curvature (radius of curvature) of the road is approximately 1370.6 meters. To solve this problem, we can follow these steps:

Step 1: Identify the given information

- Speed of the car (v) = 45 m/s

- Apparent weight increase = 15%

Step 2: Calculate the increase in gravitational force

Since the occupants' apparent weight is 15% higher,

the additional force acting on them can be calculated as 0.15 times the gravitational force (g), which is approximately 9.81 m/s^2.

- Additional force = 0.15 * 9.81 m/s² = 1.4715 m/s²

Step 3: Determine the centripetal acceleration
The additional force acting on the occupants is due to the centripetal acceleration (a_c) caused by the curvature of the road.

The centripetal acceleration can be calculated using the formula:

- a_c = v² / r, where r is the radius of curvature of the road.

Step 4: Calculate the radius of curvature

Rearrange the centripetal acceleration formula to find the radius of curvature

(r):- r = v² / a_c

Step 5: Substitute the values and calculate r

- r = (45 m/s)² / 1.4715 m/s²

- r ≈ 1370.6 meters

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Answer:

The two main reasons that your results might not match up each time are uncontrolled conditions and experimental error.

The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.

To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.

Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.

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Answer:

2 and one-third, negative 4 and three-fourths

Step-by-step explanation:

the solution is the point at which the system of equations are equal to each other, meaning where they intersect

The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.

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Answer: nebular hypothesis

Explanation:

I think atoms and molecules in matter are always in motion because of kinetic energy.

Answer:

in motion.

Explanation:

In chemistry, we often explain the states of matter in terms of the kinetic molecular theory (KMT). The word kinetic refers to motion and the kinetic molecular theory suggests that atoms and molecules are always in motion. The energy associated with this motion is termed kinetic energy.

Point out the following about solids: The particles (atoms or molecules) are attracted to each other. The particles (atoms or molecules) vibrate but do not move past one another. The solid retains its shape.

They are not always in motion. They are always in motion if and only if the temperature of the surroundings is greater than absolute zero ( 0 K ).

Not only are molecules really small but they are in constant motion. The motion is called “thermal motion” because it's caused by temperature. Increase the temperature around them and the molecules move faster.

Answer: mass

The mass of a person is constant, weight is a force that is influenced by gravity.

The time needed for the elevator to lift the load is approximately 4.31 seconds.

Power is simply the amount of energy transferred per unit time.

It is expressed as;

P = W / t

Where P is power, W is work done and t is time.

Given the data in the question;

Plug the given values into the above formula and solve for t

P = W / t

P = W / t

t = W / P

t = 56000J / 13000J/s

t = 4.31 s

Therefore, the required time is 4.31 seconds.

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Answer:

Metals are elements that forms positive ions by losing one or more electrons in a chemical reaction

Explanation:

The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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Test 4 illustrates a balanced net force as both the forces acting in opposite directions are equal in magnitude.

Net force is zero in image depicted by test 4. Thus, the forces acting in opposite direction, upward and downward, can be considered as balance forces. Equal in size and directed oppositely, balanced forces are those. One definition of equilibrium is a state of balanced forces. When the forces are in balance, there is no change in direction.

While balanced forces can keep an object at rest or moving at a constant speed, unequal forces can cause objects to accelerate. We are brought back to remember the condition of weight in order to comprehend this as :

F = ma,

where the magnitude of Force is equal to the product of the mass and the acceleration due to gravity.

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