A pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s, therefore the pig is __________during the next 2 seconds.
Question 7 options:
moving faster in the negative direction
moving faster in the positive direction
moving slower in the positive direction
moving slower in the in the negative direction
Answers
Answer:
Moving slower in the negative direction.
Explanation:
This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.
Related Questions
During heavy lifting, a disk between spinal vertebrae is subjected to a 5000-N compressional force. (a) What pressure is created, assuming that the disk has a uniform circular cross section 2.00 cm in radius? (b) What deformation is produced if the disk is 0.800 cm thick and has a Young's modulus of 1.5×109 N/m2?
Answers
Answer:
\(3978873.58\ \text{Pa}\)
\(0.00002122\ \text{m}\)
Explanation:
F = Force = 5000 N
r = Radius of circular cross section = 2 cm
l = Length of disk = 0.8 cm
A = Area = \(\pi r^2\)
Y = Young's modulus = \(1.5\times 10^9\ \text{N/m}^2\)
Pressure is given by
\(P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{5000}{\pi (2\times 10^{-2})^2}\\\Rightarrow P=3978873.58\ \text{Pa}\)
The pressure on the cross section is \(3978873.58\ \text{Pa}\)
The change in length of the cross section is given by
\(\Delta L=\dfrac{PL}{Y}\\\Rightarrow \Delta L=\dfrac{3978873.58\times 0.8\times 10^{-2}}{1.5\times 10^9}\\\Rightarrow \Delta L=0.00002122\ \text{m}\)
The deformation produced is \(0.00002122\ \text{m}\)
Somebody please help it’s urgent!!!!
In the tug of war game, none of the teams won. What can you conclude about the forces of the two teams ? Write all the evidence to support your answer.
Answers
Answer:
Explanation:
We can conclude that the forces of the two teams are equal and opposite and hence they cancel each other. Therefore none of the teams won as the rope did not move.
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An airplane has a maximum airspeed velocity of 140 mph South. If the wind is 60 mph West, what is the resultant velocity (groundspeed) and direction of the airplane?
Answers
Answer:
R∠ is 152,3 ∠ 246,8
Explanation:
We need to add (vectorially) these two velocities. We can choose the coordinates system just that speed of the airplane is the negative part of the y-axis, and negative region of the x-axis, for wind speed, according to
this, the module of the resultant velocity R is:
R =√ (60)² + (140)²
R = √( 3600) + ( 19600)
R =√ 23200
R = 152,315 mph
The tangent of the angle (α ) between R and the y-axis is:
tan α = 60/140
tan α = 0,4286
From tangent tables, we get arctan 0.4286
α = 23,2⁰
Then R∠ is 152,3 ∠ 246,8
Answer:
R∠ is 152,3 ∠ 246,8
Which energy change is caused by an endothermic chemical reaction?
Answers
Endothermic reactions are chemical processes that generate products by absorbing heat energy from the environment around the reactants.
Provide four examples of what an exothermic reaction is.One of the greatest illustrations of an exothermic reaction is the exploding of a firecracker, which emits a loud bang along with light and heat. Lighting a candle is an ongoing process in which the wax serves as fuel and sustainably produces a flame.
What class 10 example does exothermic and endothermic provide?Exothermic reactions are those that release heat energy through chemical processes. C(g)+O2(g)+CO2(g)+Heat Energy is an example. Endothermic reactions are the ones that involve the absorption of heat energy. For instance, CaO+CO2Heat CaCO3.
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Dharna is said to be concentration it is true or false
Answers
dharna is said to be concentration.. it is true
what are the difference between a planetary fly by and a planter orbit insertion. list 6 thing for each, find the answer for NASA.gov
Answers
Answer:
Explanation:
Planetary Flyby:
The spacecraft does not go into orbit around the planet; instead, it uses the planet's gravity to change its speed and direction.
The spacecraft's closest approach to the planet is usually brief, ranging from a few minutes to a few hours.
The spacecraft is able to capture images and data during the brief encounter with the planet.
The spacecraft's trajectory can be adjusted to perform multiple flybys of different planets or moons.
The spacecraft does not require a large amount of fuel to perform a flyby, making it a cost-effective option for exploration.
Flybys are useful for studying a planet's atmosphere, magnetic field, and gravitational field.
Planetary Orbit Insertion:
The spacecraft goes into orbit around the planet, allowing for long-term study and data collection.
The spacecraft's orbit can be adjusted to achieve different scientific objectives, such as mapping the planet's surface or studying its atmosphere.
The spacecraft must have enough fuel to slow down and enter orbit, making it a more expensive option than a flyby.
The spacecraft's orbit can be stable or elliptical, depending on the scientific objectives and mission requirements.
The spacecraft may require several trajectory adjustments to achieve the desired orbit.
Orbit insertion allows for more detailed and comprehensive study of a planet's geology, climate, and magnetic field.
8. What is the difference between mechanical waves and
electromagnetic waves?
Answers
Identify the different types of costs that must be identified and quantified to do aggregate planning. (Check all that apply.) -Inventory holding cost
- Subcontracting cost
- Regular production cost
- Hiring cost
- Backorder/lost sales cost
- Overtime cost
- Firing/layoff cost
Answers
The four relevant costs related to the aggregate production planning involves:
inventory holding costs,Regular production costOvertime costBackorder/lost sales cost.What is aggregate planning?Aggregate planning is a method for creating a comprehensive manufacturing plan that ensures continuous production at a facility. Aggregate production planning is typically applied over a three to eighteen-month period. It is the activity of matching output supply with demand over a medium time span using information derived from inventory levels.
This ultimately implies that aggregate planning is a strategic technique used by organizations to make an aggregate plan for their manufacturing (production) process ahead of time, in order to have an idea of the level of goods to be produced and what resources are required so that the total cost of production is kept to a bare minimum.
Production and inventory costs are the two major cost categories required as inputs for aggregate planning. Production costs include regular and overtime labor costs, costs of subcontracting production, costs of changing capacity by hiring or laying off workers, and costs of increasing or decreasing machine capacity.
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A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.
Answers
Answer:
her initial frequency is 445 Hz
Explanation:
Given;
initial beat frequency, \(F_B\) = 5
observed frequency, F = 440 Hz
let the initial frequency = F₁
F₁ = F ± 5 Hz
F₁ = 440 Hz ± 5 Hz
F₁ = 435 or 445 Hz
This result obtained shows that her initial frequency can either be 435 Hz or 445 Hz
The last beat frequency will be used to determine the actual initial frequency.
F = v/λ
Frequency (F) is inversely proportional to wavelength. That is an increase in length will cause a proportional decrease in frequency.
This shows that the final frequency is smaller than the initial frequency because of the increase in length.
Initial frequency - frequency of tuning fork = 5 beat frequency
Reduced initial frequency - frequency of tuning fork = 3 beat frequency
Initial frequency = 5Hz + 440 Hz = 445 Hz
Final frequency (Reduced initial frequency) = 440 + 3 = 443 Hz
Check: 445 Hz - 440 Hz = 5 Hz
443 Hz - 440 Hz = 3 Hz
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Explosion
1) Two swimmers are floating on a raft that is motionless. One swimmer has a mass of 50 kg and
the other at 80 kg. They both push off the raft at the same time. The 80 kg swimmer moves
away at 3 m/s. What velocity does the 50 kg swimmer move away with?
M1 = 50 kg v1' =____ M2 = 80 kg v2' = 3 m/s
Equation: 0= m1 (v1') + m2 (v2')
Elastic
2) Two hockey players are skating towards each other. A 90 kg player traveling at 6 m/s
rams into a 60 kg player moving at 2 m/s. After the collision, the 90 kg player slows to 4
m/s but is still traveling in the same direction. What is the velocity of the 60 kg player?
Equation: m1 (v1) + m2 (v2) = m1 (v1') + m2 (v2')
v2 = -2 m/s
M1 = 90 kg
v1 = 6 m/s M2 = 60 kg
V1' = 4 m/s
v2' =___
Answers
We can use the conservation of momentum to solve both problems:
Conservation of momentum:
0 = m1(v1') + m2(v2')
where m1 = 50 kg, v2' = 3 m/s, and m2 = 80 kg. We can solve for v1' to get:
v1' = -(m2/m1) v2'
v1' = -(80 kg/50 kg) (3 m/s) = -4.8 m/s
Therefore, the 50 kg swimmer moves away from the raft with a velocity of -4.8 m/s.
Conservation of momentum:
m1(v1) + m2(v2) = m1(v1') + m2(v2')
where m1 = 90 kg, v1 = 6 m/s, m2 = 60 kg, and v1' = 4 m/s. We can solve for v2 to get:
v2 = (m1v1 + m2v2 - m1v1') / m2
v2 = (90 kg)(6 m/s) + (60 kg)(2 m/s) - (90 kg)(4 m/s) / 60 kg
v2 = -1 m/s
Therefore, the velocity of the 60 kg player after the collision is -1 m/s, which means they are moving in the opposite direction to the 90 kg player.
A rotating flywheel has moment of inertia 18.0 kg⋅m^2 for an axis along the axle about which the wheel is rotating. Initially the flywheel has 30.0 J of kinetic energy. It is slowing down with an angular acceleration of magnitude 0.200 rev/s^2.
How long does it take for the rotational kinetic energy to become half its initial value, so it is 15.0 J?
Express your answer to three significant figures and include the appropriate units.
Answers
Answer:
The rotational kinetic energy takes 0.430 seconds to become half its initial value.
Explanation:
By the Principle of Energy Conservation and the Work-Energy Theorem we know that flywheel slow down due to the action of non-conservative forces (i.e. friction), the energy losses are equal to the change in the rotational kinetic energy. That is:
\(\Delta E = K_{1}-K_{2}\) (1)
Where:
\(\Delta E\) - Energy losses, measured in joules.
\(K_{1}\), \(K_{2}\) - Initial and final rotational kinetic energies, measured in joules.
By definition of rotational kinetic energy, we expand the equation above:
\(\Delta E = \frac{1}{2}\cdot I\cdot (\omega_{1}^{2}-\omega_{2}^{2})\) (2)
Where:
\(I\) - Moment of inertia of the flywheel, measured in kilograms per square meter.
\(\omega_{1}\), \(\omega_{2}\) - Initial and final angular speed, measured in radians per second.
If we know that \(K_{1} = 30\,J\), \(K_{2} = 15\,J\) and \(I = 18\,kg\cdot m^{2}\), then the initial angular speed is:
\(K_{1} = \frac{1}{2}\cdot I \cdot \omega_{1}^{2}\) (3)
\(\omega_{1}=\sqrt{\frac{2\cdot K_{1}}{I} }\)
\(\omega_{1} = \sqrt{\frac{2\cdot (30\,J)}{18\,kg\cdot m^{2}} }\)
\(\omega_{1} \approx 1.825\,\frac{rad}{s}\)
\(\omega_{1}\approx 0.291\,\frac{rev}{s}\)
\(K_{2} = \frac{1}{2}\cdot I \cdot \omega_{2}^{2}\) (4)
\(\omega_{2}=\sqrt{\frac{2\cdot K_{2}}{I} }\)
\(\omega_{2} = \sqrt{\frac{2\cdot (15\,J)}{18\,kg\cdot m^{2}} }\)
\(\omega_{2} \approx 1.291\,\frac{rad}{s}\)
\(\omega_{2} \approx 0.205\,\frac{rev}{s}\)
Under the assumption that flywheel is decelerating uniformly, we get that the time taken for the flywheel to slowdown is:
\(t = \frac{\omega_{2}-\omega_{1}}{\alpha}\) (5)
If we know that \(\omega_{1}\approx 0.291\,\frac{rev}{s}\), \(\omega_{2} \approx 0.205\,\frac{rev}{s}\) and \(\alpha = -0.200\,\frac{rev}{s^{2}}\), then the time needed is:
\(t = \frac{0.205\,\frac{rev}{s}-0.291\,\frac{rev}{s}}{-0.200\,\frac{rev}{s^{2}} }\)
\(t = 0.43\,s\)
The rotational kinetic energy takes 0.430 seconds to become half its initial value.
The time taken for the rotational kinetic energy to become half its initial value is 0.426 seconds.
Given the data in the question;
Moment of inertia of the wheel; \(I = 18.0kg.m^2\)Initial kinetic energy; \(K_1 = 30.0J\)Final kinetic energy; \(K_2 = 15.0J\)Since it is slowing down, angular acceleration becomes negative
Angular acceleration; \(a_a = -0.200 rev/s^2 = -1.2566 rad/s^2\)First we need to determine initial and final angular velocity. From the expression for Rotational kinetic energy:
\(K_R = \frac{1}{2}Iw^2\)
Where ω is the angular velocity and I is the moment of inertia around the axis of rotation.
We substitute our given values into the equation
\(K_{R1} = \frac{1}{2}Iw_1^2\\\\ 30J = \frac{1}{2} * 18.0kg.m^2 * w_1^2\\\\30kg.m^2/s^2 = \frac{1}{2} * 18.0kg.m^2 * w_1^2\\\\30kg.m^2/s^2 = 9.0kg.m^2 * w_1^2\\\\w_1^2 = \frac{30kg.m^2/s^2}{9.0kg.m^2}\\\\ w_1^2 = \frac{30kg.m^2/s^2}{9.0kg.m^2}\\\\ w_1 = \sqrt{\frac{30kg.m^2/s^2}{9.0kg.m^2}} \\\\w_1 = 1.8257 rad/s\)
\(K_{R2} = \frac{1}{2}Iw_2^2\\\\15.0J = \frac{1}{2} * 18.0kg.m^2 * w_2^2\\\\15.0kg.m^2/s^2 = \frac{1}{2} * 18.0kg.m^2 * w_2^2\\\\15.0kg.m^2/s^2 = 9.0kg.m^2 * w_2^2\\\\w_2 = \sqrt{\frac{15.0kg.m^2/s^2}{9.0kg.m^2} } \\\\w_2 = 1.29099 rad/s\)
Now, From the equation of rotational motion:
\(w_2 = w_1 + a_at\)
Where \(w_2\) is the final angular velocity, \(w_1\) is the initial angular velocity, \(a_a\) is the angular acceleration and \(t\) is the time taken.
We substitute our values into the equation and solve for "t"
\(1.29099rad/s = 1.8257rad/s + [ - 1.2566rad/s^2\ *\ t ]\\\\1.29099rad/s - 1.8257rad/s = - 1.2566rad/s^2\ *\ t \\\\-0.53471rad/s = - 1.2566rad/s^2\ *\ t \\\\t = \frac{-0.53471rad/s}{- 1.2566rad/s^2}\\\\t = 0.4255s\\\\t = 0.426s\)
Therefore, the time taken for the rotational kinetic energy to become half its initial value is 0.426 seconds.
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A projectile is fired at an upward angle of 55.0 ∘ from the top of a 155 m cliff with a speed of 165 m/s .
a)What will be its speed when it strikes the ground below? (Use conservation of energy and neglect air resistance.)
Answers
A projectile is fired at an upward angle and the speed of the object when it strikes the ground below will be 434.5 m/s.
What is Projectile motion?A projectile is an object or particle that is thrown toward the surface of the Earth and moves along a curved route only under the influence of gravity. Galileo demonstrated that this curving path was a parabola, but in the unique situation where it is hurled straight up, it may also be a straight line.
According to the question,
\(h=v_0_yt+1/2gt^2\)
-155 m = (165 × sin 55°)t - 0.5(9.8)t²
-155 = 135.16t - 4.9 t²
4.9 t² - 135.16t - 155 = 0
t = 27.5 seconds.
Now, the speed of the object when it strikes the ground will be,
\(v_f=v_i+gt\)
= 165 + (9.8)(27.5)
\(v_f\) = 434.5 m/s.
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A Cambra pouce car traveling at 28 m/s slow
at a rate of at 3.6 m/s every second find.
a) The time taken for the police car to come to Stop?
Answers
Answer:
t = 7.8 seconds
Explanation:
Given that,
The initial speed of the car, u = 28 m/s
Acceleration of the car, a = 3.6 m/s²
We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.
\(v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s\)
So, the required time is 7.8 seconds.
1. When an unbalanced force acts on an object,
O the object remains at rest
the weight of the object decreases.
O the object's motion changes.
the inertia of the object increases.
Answers
If the average kinetic energy of the molecules in an ideal gas initially at 18°C doubles, what is the final temperature of the gas?a.)9°Cb.)504°C c.)309°Cd.)36°C
Answers
ANSWER
c. 309°C
EXPLANATION
The average kinetic energy of the molecules in an ideal gas is proportional to the temperature of the gas,
\(KE=k\cdot T\)Where the temperature is measured in Kelvin.
For this problem it is not necessary to specify what is the value of k, we just need to know that it is a constant.
So, if the kinetic energy doubles, so does the temperature (in Kelvin).
The initial temperature of the gas is,
\(T_i=18\degree C+273=291\text{ }K\)If the temperature doubles,
\(T_f=2T_i=2\cdot291K=582K\)In degrees Celsius this is,
\(T_f=582K-273=309\degree C\)Hence, the final temperature of the gas is 309°C.
How can you describe the motion of an object in a race?
Answers
According to the graph below, which of the statements about these cars must be true? A) The speed of car C is greater than the speed of car D. B) At time t = 10 s, both cars have the same velocity. C) The cars meet at time t = 10 s. D) Both cars have the same acceleration. E) The magnitude of the acceleration of car C is less than the magnitude of the acceleration of car D.
Answers
According to the graph below, the statements about these cars must be true are :
At time t = 10 s, both cars have the same velocityThe cars meet at time t = 10 soptions B and C are correct
What is velocity?Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
There are some similarities between velocity and speed and they include:
Both are physical quantities, so both can be measured and quantified. Both the terms (speed and velocity) are associated with moving body only; not with static body. Both have same unit of measurementVelocity (v) is known as a vector quantity that measures displacement (or change in position, Δs) over the change in time.
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The graph is attached below:
If you react 33.0 grams of Ca how many moles of CaSO4 is produced?Ca + H2SO4 → CaSO4 + H2
Answers
0.825 moles of CaSO₄ is produced
Explanation:The given equation of reaction is:
\(Ca+H_2SO_4\rightarrow CaSO_4+H_2\)Mass of Ca = 33.0 g
Molar mass of Ca = 40 g/mol
Number of moles of Ca = Mass/Molar Mass
Number of moles of Ca = 33/40
Number of moles of Ca = 0.825 moles
From the equation:
1 mole of ca produced 1 mole of CaSO₄
0.825 moles of Ca will produce 0.825 moles of CaSO₄
Therefore, 0.825 moles of CaSO₄ is produced
This diagram shows a baseball’s motion.
A baseball is shown at 5 positions along an arc from left to right. A is far left and C is center, with B halfway between A and C. E is far right with D halfway between C and E.
Which statement is best supported by the diagram?
Kinetic energy becomes potential energy between points R and S.
Maximum potential energy is at point P.
Maximum potential energy is at point R.
Potential energy becomes kinetic energy between points P and Q.
Answers
Answer:
c
Explanation:
Maximum potential energy is at point R is best supported by the diagram. Therefore, the correct option is option C among all the given options.
What is motion?In physics, motion is a function of a body's position or orientation over time. Translation is defined as movement across a line or even a curve. Rotation is a motion that modifies a body's orientation. In all scenarios, the acceleration and directed speed of every point on the body are equal (time rate of change of velocity).
Every movement has a frame of reference to which it is related. A body isn't in motion when it is said to be at rest; rather, it is being characterized in relation to a reference frame that's also moving with the body. Maximum potential energy is at point R is best supported by the diagram.
Therefore, the correct option is option C.
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5. A tennis player hits a ball when it is at a height of 1.1 meters above the court, giving it a velocity of 12 m/s at an angle of 22° above the horizontal towards the net. The net is 1.81 meters high and stands 2.6 meters from the player.
a) Show that the ball will just pass over the net.
b) Find when and where the ball hits the ground.
Answers
According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).
How to determine if the ball will clear the net?To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.
How to find when and where the ball hits the ground?To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.
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17. This is used to produce a rough sketch with thick and dark ink to make the figure of an image more distinct. A. shading B. Painting C. Outlining D. Sketching
Answers
I need help on this science homework I forgot on what to do through number 4-7 including a,b,c,d, and e.
Answers
Answer:
\(\begin{gathered} (a)\Rightarrow v=2ms^{-1} \\ (b)\Rightarrow v=1ms^{-1} \\ (c)\Rightarrow v=6.67ms^{-1}_{} \\ (d)\Rightarrow v=1.2ms^{-1} \\ (e)\Rightarrow v=0ms^{-1} \end{gathered}\)Explanation: We need to calculate the speed on intervals a b c d and e, the speed can be calculated with the following formula:
\(v=\frac{\Delta S}{\Delta t}\Rightarrow(1)\)(a) 0-5 seconds Interval:
\(\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(10m-0m)}{(5s-0s)}=\frac{10m}{5s}=2ms^{-1} \\ v=2ms^{-1} \end{gathered}\)(b) 5-15 seconds Interval:
\(\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(20m-10m)}{(15s-5s)}=\frac{10m}{10s}=1ms^{-1} \\ v=1ms^{-1} \end{gathered}\)(c) 15-18 seconds Interval:
\(\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-20m)}{(18s-15s)}=\frac{20m}{3s}=6.67ms^{-1} \\ v=6.67ms^{-1} \end{gathered}\)(d) 18-23 seconds Interval:
\(\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(46m-40m)}{(23s-18s)}=\frac{6m}{5s}=1.2ms^{-1} \\ v=1.2ms^{-1} \end{gathered}\)(e) 23-25 seconds Intervals:
\(\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-40m)}{(25s-23s)}=\frac{0m}{2s}=0ms^{-1} \\ v=0ms^{-1} \end{gathered}\)
In the context of energy transfers with hot and cold reservoirs, the sign convention is that _______________.
Answers
Answer:
Qc>0; Qh>0
Explanation:
In the context of energy transfers with hot and cold reservoirs, the sign convention is QC > 0; QH < 0.
What is energy transfer?The conversion of one form of energy into another, or the movement of energy from one place to another is known as energy transfer.
Given that there are two energy reservoirs. Heat and work sign convention is:
If the heat is adding to the system then it is considered positive and if heat is going out from the system then it is considered negative. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.As, heat is going out that from the hot reservoir ,it is taken as negative- QH < 0.
As heat is coming inside the cold reservoir that is why it is taken as positive - QC > 0.
Therefore, QC > 0 and QH < 0 is the correct answer.
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6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
Answers
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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Use the simulation to complete the activity.
Force and Motion Basics (select Acceleration)
In one or two sentences make a hypothesis about whether or not it is easier to start the box moving than to keep it moving on a rough surface. Then, explain how the simulation can be used to prove the
hypothesis
(2 points)
I'll mark brainliest to whoever gives me the right answer first
Answers
Answer:
The acceleration is directly proportional to the net force; the net force equals mass times acceleration; the acceleration in the same direction as the net force; an acceleration is produced by a net force
Force is related to acceleration through the equation F=ma. “F” stands for force, “m” stands for mass and “a” stands for acceleration. Force is a push or pull that an object can exert on other objects. Acceleration is the rate of change of an object's speed.
Explanation:
An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answers
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.
Answers
The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.
What is Force?Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = m(vf - vi)
Δ P = 1300 (0 - 11)
Δ P = -1.43 × 10⁴ kg.m/s
The impulse is equal to the change in momentum of the car
I = -1.43 × 10⁴ kg.m/s
Magnitude of the force experienced by Kara
I = F × t
where, I is impulse acting on the car
t is time
- 1.43 × 10⁴ = F × 0.14
F = -1.021 × 10⁵ N
Negative sign represents the direction of the force.
Learn more about Force here:
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Your question is incomplete, most probably the complete question is:
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.
a. Determine the momentum change of Kara's car.
b. Determine the impulse experienced by Kara's car.
c. Determine the magnitude of the force experienced by Kara's car.
An object is traveling with a constant speed of 35 m/s. How long does it take to cover 770 m?
Answers
Answer:
22 s
Explanation:
time = distance / velocity
We know that distance = 770 m and velocity = 35 m/s.
t = d / v
t = 770 m / 35 m/s
t = 22 s
It takes 22 seconds to cover 770 m. Hope this helps, thank you !!
can anyone help me put this sentence into a scientific grammar ig : I had to put the blocks on the weigher, and wright down how much they weigh. I had to put the blocks next to the ruler to measure the height.
Answers
Answer:
I had to put the blocks on the weigher, and write down how much they weigh. I had to put the blocks next to the ruler to measure the height.
Explanation:
u would change wright to write because wright can be a name and if u change it to write that would be correct because u are actually writing something down. so it would be right because u are writing something down
state and explain law of conservation of momentum with example
Answers
Answer:
The law of conservation of momentum states that provided there is no exterior force or in an isolated system the total linear momentum of two colliding bodies remains the same or is conserved
An example is if two bodies collide
in this case, the sum of the two momenta before collision is equal to their sum after collision. What momentum one particle loses, the other gains. So the algebraic sum is equal