a person travels by car from one city to another. she drives for 27.6 min at 62.7 km/h, 9.6 min at 115 km/h, 46.1 min at 45.2 km/h, and spends 12.3 min along the way eating lunch and buying gas.

Answer:

Gravitational force increases as the masses of the objects increase and decreases as the distance between the objects increases. Balanced forces acting on an object cause no change in the motion of the object. When unbalanced forces act on an object, the sum of the forces is not equal to zero.

Explanation:

put it in your own words

Answer:

(i) The volume of the cylindrical beaker is given by:

V = A x h = (25 cm^2) x (10 cm) = 250 cm^3

The mass of the oil in the beaker is given by:

m_oil = density x volume = (0.8 g/cm^3) x (250 cm^3) = 200 g

The total mass of the beaker and oil is therefore:

m_total = m_beaker + m_oil = 50 kg + 0.2 kg = 50.2 kg

(ii) The volume of the aluminum is given by:

V_aluminum = m_aluminum / density = 66 g / (2.2 g/cm^3) = 30 cm^3

When the aluminum is lowered into the beaker, it displaces an equal volume of oil. Therefore, the volume of oil that overflows is 30 cm^3.

(iii) The final mass of the beaker and its contents is the sum of the mass of the beaker, the mass of the oil remaining in the beaker, and the mass of the aluminum:

m_final = m_beaker + m_oil + m_aluminum = 50 kg + 0.17 kg + 0.066 kg = 50.24 kg

To calculate the mass of the remaining oil, we need to subtract the volume of aluminum from the volume of the beaker and multiply by the density of the oil:

V_remaining_oil = (A x h) - V_aluminum = (25 cm^2 x 10 cm) - 30 cm^3 = 220 cm^3

m_remaining_oil = density x V_remaining_oil = 0.8 g/cm^3 x 220 cm^3 = 176 g

Therefore, the final mass of the beaker and its contents after the overflow liquid has been wiped off is 50.24 kg, and there is 176 g of oil remaining in the beaker

The output voltage of a real battery decreases when a large current is drawn out of it due to the internal resistance causing voltage drop.

When a real battery with internal resistance is connected to a load and a large current is drawn from it, the internal resistance causes a voltage drop within the battery. This voltage drop reduces the effective output voltage of the battery that reaches the load. As a result, the output voltage of the battery decreases compared to its no-load voltage.

The internal resistance dissipates some of the energy as heat, leading to a decrease in the available voltage for the load. This phenomenon is known as "voltage sag" or "voltage drop" and is a characteristic of real batteries with internal resistance. It is important to consider the internal resistance when designing circuits or using batteries to ensure proper voltage regulation and performance.

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The difference between the natural fibers and synthetic fibers is like synthetic fibers are produced using chemicals while, natural fibers are derived from plants and animals and are appreciated in the textile business for several factors.

The fibers that come from natural sources are known as natural fibers. The origins can range from zoological to botanical components. In other words, natural fibers are those that are obtained from plants and animals in their natural state. Wool, silk, hemp, cotton, and linen are a few examples of fabrics that naturally breathe.

Synthetic fibers are produced through a sequence of chemical processes, as their name suggests. These fibers are produced using a variety of chemical compounds rather than being derived from natural sources.

The creation of tiny molecules known as polymers is the process used to create synthetic, artificial, or man-made fibers. In most cases, raw materials and chemical compounds are used to extract polymers. Nylon, polyester, acrylic, and more are a few examples.

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(a) The time required to reduce the paratrooper's speed to 5.25 m/s², assuming the acceleration is constant, can be found using the formula `v = u + at`, where `v` is the final velocity, `u` is the initial velocity, `a` is the acceleration, and `t` is the time taken.

Initially, the paratrooper is falling downward at a speed of 30.3 m/s, and after the parachute opens, the upward acceleration is 69 m/s². Therefore, the net acceleration is given by:

Net acceleration = upward acceleration - downward acceleration= 69 - 9.81= 59.19 m/s²

The time taken to reduce the speed to 5.25 m/s can be found by substituting the values into the above formula as shown below:5.25 = 30.3 + 59.19t⇒ t = (5.25 - 30.3)/59.19≈ -0.421 s

Since the time can't be negative, the above estimate is invalid.

(b) The distance fallen during the time interval can be found using the formula `s = ut + 1/2 at²`. If the acceleration is not constant, an easy estimate can be obtained by taking the average of the initial and final speeds, and multiplying by the time taken, which is approximately the same as the actual distance fallen.

The average speed is given by:(30.3 + 5.25)/2 = 17.78 m/s

Therefore, the approximate distance fallen is:s ≈ ut = 17.78 × t

(a), the time taken to reduce the speed to 5.25 m/s is approximately -0.421 s, which can be disregarded since time can't be negative.

Therefore, the actual time taken is:5.25 = 30.3 + at⇒ t = (5.25 - 30.3)/a= 1.435 sSubstituting this into the above formula, the actual distance fallen is:s = 17.78 × 1.435≈ 25.50 m

Therefore, the paratrooper falls a distance of approximately 25.50 m during this time interval.

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The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.

The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).

1. Substitute the income constraint into Michael's utility function:

\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)

  s.t. \(Y = p_1q_1 + p_2q_2\)

  We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:

 \(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)

  By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).

2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:

\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)

Simplifying and solving for \(q_1\):

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

3. Similarly, we can derive a similar expression for his optimal \(q_2\):

\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).

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Answer:

The car must move at 2 m/s to have a Ke of 2,000 Joules.

Explanation:

Mark me pls

Answer:

The ball hit with 12N

Explanation:

Just took the quiz and got it right

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

A falling object accelerates from -10.00 to-30.00m/s, it takes approximately 2.04 seconds for the falling object to accelerate from -10.00 m/s to -30.00 m/s.

To determine the time it takes for a falling object to accelerate from one velocity to another:

v = u + at

Here, it is given that:

Initial velocity (u) = -10.00 m/s

Final velocity (v) = -30.00 m/s

Since the object is falling, we can assume that the acceleration (a) is due to gravity and is approximately -9.8 m/s² (negative because it's directed downwards).

Substituting the values into the equation:

-30.00 = -10.00 + (-9.8)t

Simplifying the equation:

-30.00 + 10.00 = -9.8t

-20.00 = -9.8t

Dividing both sides by -9.8:

t = -20.00 ÷ -9.8

t ≈ 2.04 seconds

Thus, it takes approximately 2.04 seconds for the falling object to accelerate from -10.00 m/s to -30.00 m/s.

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Answer:

1st: Radiation

2nd: Conduction

3rd: Convection

Explanation:

I actually learned this before in school. Yay

Answer:

23.59 for the average pls give brainliest sis

Answer: 23.59

HOPE THIS HELPS :D

The λmax of S157C at pH 4.5 is greater than at pH 10 due to the proposed bonding of deprotonated C157 with Y63 at pH 10.

At pH 4.5, the side chain of C157 is protonated, which means that it carries a positive charge. This protonated form of C157 is less likely to form a bond with Y63, resulting in a higher λmax value.

On the other hand, at pH 10, the side chain of C157 is deprotonated, meaning it loses a proton and becomes uncharged. In this state, the deprotonated C157 is more likely to form a bond with Y63. This bonding affects the electronic environment and results in a lower λmax value compared to the value at pH 4.5.

In summary, the proposed bonding of deprotonated C157 with Y63 at pH 10 accounts for the observation that the λmax of S157C at pH 4.5 is greater than at pH 10 because the bonding alters the electronic environment, leading to a lower λmax value at the higher p H.

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When an atom loss one electron completely to another atom with the consequent formation of electrostatic charges is referred as an ionic bond.

Ionic bonds are bonds that occur due to the handover of electrons to form positive ions and negative ions whose electron configuration is the same as that of the noble gases. Positive ions and negative ions are bound by an electrostatic force.

The resulting compounds are called ionic compounds. One example that we often encounter everyday is table salt. Well, the chemical formula for table salt is NaCl (Sodium chloride). In solid NaCl there is a bond between Na+ ions and Cl- ions by electrostatic forces, so it is called an ionic bond.

In ionic bonds, there is a transfer of electrons from one atom to another. Due to the movement of electrons, the atom that gains electrons becomes negatively charged, while the atom that loses electrons will be positively charged.

If an atom gains electrons, the atom becomes a negative ion, also known as an anion. Meanwhile, if an atom loses electrons, then the atom becomes a positive ion or cation.

Due to the difference in charge between ions (positive ions and negative ions), positive and negative ions will attract each other by electrostatic forces. This incident is the basis of ionic bonding.

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The crew aboard a small sailboat should be briefed to follow specific instructions when their boat is being towed.

When a small sailboat is being towed, the crew should adhere to the following instructions:

Secure all loose items: The crew should secure any loose items on the boat to prevent them from shifting or falling overboard during the towing process. This includes stowing equipment, sails, and personal belongings in appropriate storage spaces.

Maintain communication: The crew should establish clear communication with the towing vessel to ensure a smooth towing operation. They should follow the instructions given by the towing crew and relay any concerns or issues promptly.

Stay alert and ready to assist: While being towed, the crew should remain vigilant and ready to assist if needed. They should be prepared to help with maneuvers, follow the towing vessel's directions, and be mindful of potential hazards in the water.

By following these guidelines, the crew of a small sailboat can contribute to a safe and successful towing operation, minimizing risks and ensuring a smooth journey.

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Answer:

B.

Explanation:

Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.

Answer:

answer is B

Explanation:

The volume and molarity of the KHP solution, and the volume of NaOH solution used to titrate it, we can determine the molarity of NaOH solution as follow:

What is a titration?

Titration is a procedure for determining the concentration of a substance (the analyte) in a solution by adding a carefully measured volume of a reagent of known concentration (the titrant) until the reaction of the analyte with the titrant is complete. The point at which the reaction is complete is known as the equivalence point.

Let's solve the problem provided: The molarity of KHP solution,

M₁ = 0.256 mol/LVolume of KHP solution,

V₁ = 15.00 ml = 0.01500 L

Volume of NaOH solution, V₂ = 20.75 ml = 0.02075 L

From the chemical equation:

KHC₈H₄O₄ + NaOH → NaKC₈H₄O₄ + H₂O

Molar ratio between KHP and NaOH is 1:1

Moles of KHP in 15.00 ml of solution:

moles KHP = Molarity * Volume

= 0.256 mol/L * 0.01500 L = 0.00384 mol

Moles of NaOH used to react with 0.00384 mol of KHP:

moles NaOH = moles KHP = 0.00384 mol

Molarity of NaOH solution:

M₂Molarity = Moles of solute / Volume of solutionM₂

= moles NaOH / Volume of NaOH

= 0.00384 mol / 0.02075 L

= 0.1846 mol/L

Therefore, the molarity of the unknown NaOH solution is 0.1846 M.

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The mass of the blood denoted is 501.6 g.

The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.

density = mass/volume

mass = density x volume

The given parameters include;

The mass of the blood is calculated as follows;

mass = 1.06 g/mL x 473.176 mL

mass = 501.6 g

Thus, the mass of the blood is calculated from the formula of density.

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The complete question is below

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.

The radius of the turn can be calculated using the centripetal acceleration formula:a_c = v^2 / rwhere a_c is the centripetal acceleration, v is the velocity of the falcon, and r is the radius of the turn.

We know that the centripetal acceleration of the falcon is 1.5 times the free-fall acceleration, which is approximately 9.8 m/s^2. Therefore, the centripetal acceleration of the falcon is:a_c = 1.5 * 9.8 = 14.7 m/s^2We also know that the velocity of the falcon is 30 m/s. Substituting these values into the centripetal acceleration formula, we get:14.7 = 30^2 / rSolving for r, we get:r = 591.8 meters (approx.)Therefore, the radius of the turn is approximately 591.8 meters.Explanation:When a falcon makes a tight circular turn, it needs to generate a centripetal force to keep it moving in a circular path. The centripetal force is generated by the centripetal acceleration, which is directed towards the center of the circle.The centripetal acceleration depends on the velocity of the falcon and the radius of the turn. The faster the falcon is flying or the tighter the turn, the greater the centripetal acceleration required.In this problem, we are given the velocity of the falcon and the centripetal acceleration it can generate. We can use the centripetal acceleration formula to find the radius of the turn.The radius of the turn tells us how tight the turn is. A smaller radius means a tighter turn, which requires a greater centripetal acceleration. In this case, the falcon is able to generate a centripetal acceleration 1.5 times the free-fall acceleration, which is quite impressive and allows it to make tight turns while hunting its prey.

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According to the solving  the phase angle required for the third wave to maximize the amplitude of the new resultant wave is 0° or 2.

To maximize the amplitude of the new resultant wave, the third wave's phase angle should be such that it is in phase with the resultant wave obtained from the first two waves, y1 (x, t) and y2 (x, t).

Thus, we need the third wave to have a phase difference of 0° or 2° with the resultant wave obtained from the first two waves.

Given waves:  

y1(x, t) = (4.60 mm)

sin (2px – 400pt)

y2(x, t) = (5.60 mm)

sin (2 px – 400 pt + 0.80 p rad).

(a) The amplitude of the resultant wave is given as:

A = √[A1² + A2² + 2A1A2cos(ΔΦ)]

Where, A1 = Amplitude of wave y1(x, t)

A2 = Amplitude of wave y2(x, t)ΔΦ

= Phase difference between two waves y1(x, t) and y2(x, t)

Amplitude A = √[(4.60 mm)² + (5.60 mm)² + 2(4.60 mm)(5.60 mm)cos(0.80π)]

≈ 8.88 mm

(b) The phase angle of the resultant wave relative to wave 1 is given by:

tan = (A2 sin ΔΦ) / (A1 + A2 cos ΔΦ)

Where, A1 = Amplitude of wave y1(x, t)

A2 = Amplitude of wave y2(x, t)ΔΦ

= Phase difference between two waves y1(x, t) and y2(x, t)

Phase angle Φ = tan⁻¹[(5.60 mm) sin(0.80π)] / [(4.60 mm) + (5.60 mm) cos(0.80π)]

≈ 18.6°

(c) Let the amplitude of the third wave be A3 = 5.00 mm.

Therefore, the phase angle required for the third wave to maximize the amplitude of the new resultant wave is 0° or 2.

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Answer:

19.89×10^-26Jm

Explanation:

The Energy of a photon is given as;

E = h×c/λ

Where h is Plank's constant.

c is speed of light

λ is the wavelength.

By multiplying both sides of the equation to λ

E × λ = h×c/λ × λ

E × λ = h×c

= 6.63×10^-34× 3×10^8

= 19.89×10^-26Jm

No, the kinetic energy of the electron will not change.

The electron receives no work from the magnetic force. In actuality, the magnetic force's work is provided by:

where F is the magnetic force, d is the electron's displacement, and is the angle between the force's direction and the electron's motion.

However, because the magnetic pull is always perpendicular to the charged particle's direction and velocity, there is no work done.

The work-energy theorem states that the change in an electron's kinetic energy is equal to the work that has been done on it; therefore, because there has been no work done, the electron's kinetic energy has not changed.

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A randomly chosen bag triggers the alarm, the probability that it contains a forbidden item can be calculated using Bayes' theorem. The probability is approximately 80.56%.

To determine the probability that a bag contains a forbidden item given that it triggers the alarm, we can use Bayes' theorem. Let's denote event A as "bag contains a forbidden item" and event B as "bag triggers the alarm." We are given that the probability of event A is 5% (0.05) and the probability of event B given A is 98% (0.98). Additionally, the probability of event B given not A (i.e., the alarm being triggered by a bag without a forbidden item) is 8% (0.08). Using these probabilities, we can apply Bayes' theorem:

\(P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|not A) * P(not A))\)

Substituting the given values, we get:

\(P(A|B) = (0.98 * 0.05) / (0.98 * 0.05 + 0.08 * 0.95) = 0.8056\)

Therefore, the probability that a bag contains a forbidden item, given that it triggers the alarm, is approximately 80.56%.

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Among the given options, natural gas is considered a nonrenewable energy source. Nonrenewable energy sources are those that cannot be replenished or regenerated at a rate that matches their consumption.

Natural gas is formed from the remains of ancient plants and animals that were buried and subjected to heat and pressure over millions of years. Once extracted and used, natural gas is depleted and cannot be easily replaced within a human lifetime.

On the other hand, solar power, wind power, and geothermal energy are considered renewable energy sources. Solar power harnesses the energy from the sun using photovoltaic panels, while wind power utilizes the kinetic energy of wind to generate electricity. Geothermal energy taps into the heat from the Earth's core. These renewable sources are considered sustainable as they are continuously available and do not deplete with usage. They offer a cleaner and more environmentally friendly alternative to nonrenewable energy sources like natural gas, which contribute to carbon emissions and climate change.

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A) By using the sensors to measure the estimated electric field at 2 m is 0.25 N/C.

B) The estimated electric field at 3 m is 0.1111 N/C.

A) By using the sensors to measure the estimated electric field at 2 m:

(Electric field at 1 m) ÷ (Electric field at 2 m)

= \((1 m)^{2}\) ÷ \((2 m)^{2}\)

Simplifying the equation:

1 ÷ (Electric field at 2 m) = 1 ÷ 4

Electric field at 2 m = 1 ÷ (1/4)

= 4 N/C

B) To calculate the estimated electric field at 3 m:

(Electric field at 1 m) ÷ (Electric field at 3 m)

= \((1 m)^{2}\) ÷ \((3 m)^{2}\)

Simplifying the equation:

1 ÷ (Electric field at 3 m) = 1 ÷ 9

Electric field at 3 m = 1 ÷ (1/9)

= 9 N/C

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Answer:

orange it is lol

Explanation:

Answer:

HELP ORANGE DOESNT LOOK LIKE A WORD ANYMORE

Explanation:

Answer:

Explanation:

A compass always (or usually always) points to the magnetic north. If you came in from the south east and got lost, it will point north and you can adjust the way you travel by going 90 off of where the compass points. Keep walking on that line until you hit a place that you recognize and there is no more need for the compass.

Answer: The first thing you have to do is locate east on your compass housing. Turn your compass until you see that east lines up directly with your direction of travel arrow. Quite simply, that is the direction you want to walk. You can do this for any direction.

Explanation:

(a) The power output of the sprinter is 1,540 W (watts) or approximately 2.06 hp (horsepower).

To calculate the power output, we can use the equation:

\(\[ \text{Power} = \frac{1}{2} \cdot \frac{{\text{mass} \cdot \text{velocity}^2}}{{\text{time}}} \]\)

Given:

mass (m) = 70.0 kg

velocity (v) = 10.0 m/s

time (t) = 3.00 s

Plugging in the values:

\(\[ \text{Power} = \frac{1}{2} \cdot 70.0 \, \text{kg} \cdot (10.0 \, \text{m/s})^2 / 3.00 \, \text{s} \]\)

Power ≈ 1,540 W

To convert the power to horsepower:

1 horsepower (hp) = 745.7 W

Power ≈ 1,540 W / 745.7 ≈ 2.06 hp

(b) No, a well-trained athlete would not be able to sustain this level of power output for long periods of time.

Sprinting requires a high amount of power output, which is a combination of strength and speed. The power output calculated in part (a) indicates the energy output per unit of time.

However, sprinting at this level of power continuously for long periods would be extremely demanding and exhausting for the athlete's muscles and cardiovascular system.

Long-duration activities, such as endurance running, rely on a lower power output sustained over a longer time. Endurance athletes have a higher aerobic capacity, which enables them to produce energy more efficiently over extended periods.

Sprinting, on the other hand, is characterized by short bursts of intense effort.

Therefore, while a well-trained athlete may be able to achieve a high-power output during a sprint, it is not sustainable for long periods due to the rapid fatigue it induces.

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