Answer:
11.67 lbs
Explanation:
5. Which set of coefficients will balance this chemical
equation?
_C2H4(g) +
O2(g) → 2CO2(g) + 2H2O(g)
A. 1.2
B. 1.3
C. 2.3
D. 2.5
Answer: The answer is B 1,3
a buffer contains equal amounts of a weak acid and conjugate base and has a ph of 5.25. how will the concentration of conjugate base in the buffer change after the addition of a small amount of strong base?
The concentration of conjugate base in the buffer change after the addition of a small amount of strong base The concentration of conjugate base will increase. HA+BOH ⇒ H2O +AB
Buffer capacity refers to the amount of added acid or base that can be neutralized by a buffer. This is determined by the concentration of the conjugate acid and conjugate base. As these concentrations increase, the buffering capacity increases. A buffer is a solution that can withstand changes in pH due to the addition of acidic or basic components.
Can neutralize small amounts of added acids or bases and keep the pH of the solution relatively stable. When a strong base is added to a buffer the hydroxide ions are consumed by the weak acid, forming water, and consumed by the weak conjugate base of the acid. The number of weak acids decreases and the number of conjugate bases increases.
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A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?
Answer:
The answer is
2.7 g/mLExplanation:
The density of a substance can be found by using the formula
\(Density = \frac{mass}{volume} \)
From the question
mass of aluminum = 40.5 g
volume = 15.0 mL
The density is
\(Density = \frac{40.5}{15} \)
We have the final answer as
2.7 g/mLHope this helps you
Any ions with a charge (3+ ) has?
Answer:
protons
Explanation:
Convert 145 m/s to km/hour. using dimensional analysis.
Answer:
522 Kilometers per Hour
Explanation:
Hi there! :)
Answer:
\(\huge\boxed{522 km/hour}\)
\(\text{Express 145 m/s as a fraction:} \frac{145m}{s}\)
\(\text}Convert to km/hour by multiplying by the equivalents in terms of meters and seconds to cancel out the units}\)
\(\frac{145m}{sec} * \frac{3600 sec}{1 hour} * \frac{1 km}{1000 m} = \\\\\text {Cross out similar units and multiply the coefficients:}\\\\\frac{145 * 3600 * 1km}{1 * 1hour * 1000} = \frac{522000km}{1000hour}= 522 km/s.\)
Hydrolysis of which covalent bonds in atp releases a considerable amount of energy?
There is a significant quantity of energy released during the hydrolysis of the covalent bonds in ATP.
Phosphate-phosphate bond hydrolysis occurs during the breakdown of an ATP molecule, which releases a significant amount of energy.
How is ATP hydrolysis defined?
Adenosine triphosphate (ATP) contains highly energetic phosphoanhydride bonds that, when broken, such as occurs in muscles, release chemical energy through a catabolic reaction process called ATP hydrolysis.Nitrogen-carbon double bonds, phosphate-phosphate bonds, carbon-hydrogen bonds, and hydrogen bonds are all found in an ATP molecule.
Phosphate-phosphate bond hydrolysis occurs during the breakdown of an ATP molecule, which releases a significant amount of energy.
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What is used for mixing a small amount of chemicals together?
a thin solid glass rod that is used in chemistry to combine substances. A stirring rod often has rounded ends and is about the length of a long straw.
What use serves the stirring rod?A crucial component of lab apparatus for mixing chemicals and liquids for reactions is a long, thin stirring rod. Stirring rods are made of solid plastic, glass, or steel and are non-abrasive, chemically inert, and chemically resistant.
What is the name of the glass stirring rod?Glass rod, also known as a stirring rod, stir rod, or solid glass rod, is frequently made of quartz and borosilicate glass. Its diameter and length can be modified to meet your needs.
Does filtration employ stirring rods?When the liquid transfer procedure is paused, use a stirring rod to direct the liquid flow into the funnel and stop small amounts of liquid from dribbling down the beaker's outside.
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Identify the four ways you can increase the strength of an electromagnet.
Answer:
wrapping the coil around a piece of iron (such as an iron nail)
adding more turns to the coil.
increasing the current flowing through the coil.
I forget the last one
Explanation:
Tighten the wire coils. The more times the wire coils in a given length of solenoid, the stronger the electromagnetic field will be. For instance, if your copper wire is coiled 100 times around a 2-inch iron nail, try to push the coils closer together and wrap the wire a few more times around the nail.
Explanation:
the hybridization of the nitrogen atom in the cation nh2 is: quizlet
the hybridization of the nitrogen atom in NH2 is sp2.
The hybridization of the nitrogen atom in the cation NH2 can be explained by considering the valence electrons of nitrogen. Nitrogen has five valence electrons, and in NH2, one of these electrons is used to form a bond with the hydrogen atom, leaving four electrons.
To determine the hybridization of the nitrogen atom in the NH2+ cation, follow these steps:
1. Identify the nitrogen atom's valence electrons. Nitrogen has 5 valence electrons.
2. Add the number of hydrogen atoms bonded to nitrogen (2 in this case).
3. Add any extra electrons due to the charge. Since it's a positive cation (NH2+), we need to subtract one electron.
Now, the total number of electrons in the valence shell is 5 (from nitrogen) + 2 (from the hydrogens) - 1 (from the positive charge) = 6 electrons.
4. Divide the total number of electrons by 2 to get the electron pairs: 6 electrons ÷ 2 = 3 electron pairs.
5. Determine the hybridization based on the number of electron pairs. In this case, there are 3 electron pairs:
- 2 pairs are used for bonding with the hydrogen atoms.
- 1 pair is a lone pair on the nitrogen atom.
The hybridization that corresponds to 3 electron pairs is sp2. Therefore, the hybridization of the nitrogen atom in the NH2+ cation is sp2.
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What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?
A. AG = 2700 kJ/mol
B. AG = -36 kJ/mol
C. AG = 0 kJ/mol
D. AG = 18 kJ/mol
Answer:
ΔG = 18KJ/mol
Explanation:
Given data:
ΔG = ?
ΔS = 0.09 Kj/mol.K
ΔH = 27 KJ/mol
Temperature = 100 K
Solution:
Formula:
ΔG = ΔH - TΔS
ΔS = entropy
ΔH = enthalpy
by putting values,
ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)
ΔG = 27 KJ/mol - 9 KJ/mol
ΔG = 18KJ/mol
what will be the result of the reaction
(CH3COO)2+redP +Cl2
Answer:
(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl
Explanation:
This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.
What is the total number of O atoms in 6 formula units of hydroxyapetite, Ca10(PO4)6(OH)2, present in tooth enamel?
We need to count the number of oxygen atoms present in each component of the formula and then multiply by the appropriate coefficients.
In hydroxyapatite (Ca10(PO4)6(OH)2), we have:
6 formula units, which means we have 6 copies of each component.Breaking down the formula, we find:
Each Ca10 unit does not contain any oxygen atoms.Each PO4 unit contains 4 oxygen atoms.The OH unit contains 1 oxygen atom.So, for each formula unit:
We have 6 PO4 units, resulting in 6 x 4 = 24 oxygen atoms.We have 2 OH units, resulting in 2 x 1 = 2 oxygen atoms.Adding the oxygen atoms from each component:
24 oxygen atoms (from PO4 units) + 2 oxygen atoms (from OH units) = 26 oxygen atoms per formula unit.
Now, multiplying by the 6 formula units:
26 oxygen atoms x 6 formula units = 156 oxygen atoms.
Therefore, in 6 formula units of hydroxyapatite, there are a total of 156 oxygen atoms present.
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A student shines a light on a piece of transparent glass. Which of the following diagrams accurately shows the path of the light? Responses A Image with alt text: B Image with alt text: C Image with alt text: D
Glass is a transparent material as it allows light to pass through.
Why is glass transparent?The question is incomplete as the images that have been referred to here are not shown and as such I will just consider glass as a transparent material.
Glass, which is primarily made of silicon dioxide with a few impurities, is more properly classified as a supercooled liquid than as a solid. It is translucent because there are no internal grain boundaries.
The photon instead moves through unhindered. The glass is translucent as a result.
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Answer:
b
Explanation:
b
Please Help me!!!!! please
Answer:
6
Explanation:
Subscript are written at the bottom right side of the symbol of atoms. In given reaction we can see carbon subscript is 6 on right side of chemical equation.
C₆H₁₄
C = 6
Chemical equation:
C₆H₁₄(g) + O₂(g) → CO₂(g) + H₂O(g)
Balance chemical equation:
2C₆H₁₄(g) + 19O₂(g) → 12CO₂(g) + 14H₂O(g)
The given reaction is burning of hexane. When hexane burn in the presence of oxygen it produced carbon dioxide and water.
The reaction also follow the law of conservation of mass. There are equal number of atoms of each element on both side of equation.
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
A beam of light has a wavelength of 280 nanometers. What is the frequency of the light? Show all work!
A beam of light has a wavelength of 280 nanometers. The frequency of the light is 1.07 × 10¹⁵ Hz.
the information in the question is given as :
wavelength of beam of light = 280 nm
the relation between the frequency and the wavelength is given as :
F = c / λ
where,
F = frequency of the light
c = speed of light
λ = wavelength of light
speed of light , c is = 3 × 10⁸ m/s
substituting all the value in the formula for the frequency, we get:
F = c / λ
F = 3 × 10⁸ / 280 × 10⁻⁹
F = 0.0107 × 10¹⁷ Hz
F = 1.07 × 10¹⁵ Hz
Thus, A beam of light has a wavelength of 280 nanometers. The frequency of the light is 1.07 × 10¹⁵ Hz.
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List two things that should not be in the lab.
Answer:
a) Food and Drinks
b) Ball
Explanation:
8. Convert 161 millimeters into meters.
There are 1000 millimeters in a meter. To convert 161 millimeters to meters, we need to divide by 1000:
161 millimeters ÷ 1000 = 0.161 meters
Therefore, 161 millimeters is equal to 0.161 meters.
An electric current is produced when ______________________ move continuously batteries magnets electric charges wires
Answer:
electric charges.
Explanation:
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction.
An electron can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.
An electric current is produced when electric charges (electrons) move continuously and it's measured in Amperes through the use of an ammeter.
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
\( V = IR\)
Where;
V represents voltage measured in voltage.
I represents current measured in amperes.
R represents resistance measured in ohms.
A thin film of acetone (n = 1.25) coats a thick glass plate (n = 1.50). White light is incident normal to the film. In the reflections, fully destructive interference occurs at 530 nm and fully constructive interference at 583 nm. Calculate the thickness of the acetone film.
The thickness of the acetone film is approximately 79.5 nm.
When light waves reflect off a thin film, interference can occur between the waves that reflect from the top and bottom of the film. This interference depends on the thickness of the film, the indices of refraction of the film and the surrounding media, and the wavelength of the light.
Let the thickness of the acetone film be denoted by t, and let the wavelength of the light be denoted by λ. The phase shift between the waves that reflect from the top and bottom of the film is given by:
Δφ = 2πnt/λ
where n is the index of refraction of the acetone film. For fully destructive interference, the phase shift must be an odd multiple of π:
Δφ = (2n + 1)π
Substituting the given values for n and λ at 530 nm, we have:
(2.5) (530 x \(10^{-9\) m) = (2t)
Simplifying this equation, we get:
t = 265 nm
Similarly, for fully constructive interference at 583 nm, we have:
(2.5) (583 x \(10^{-9\) m) = (2t) + λ/2
Substituting the value of t from the previous calculation, we can solve for λ/2 and then for t:
λ/2 = (2.5) (583 x \(10^{-9\) m) - (2t) = 159 x \(10^{-9\) m
t = (159 x \(10^{-9\) m)/2 = 79.5 nm
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Problem24. How many grams of \( 5 \% \) salt solution should be added to 500 grams of a \( 20 \% \) salt solution to make a \( 15 \% \) salt solution?
Given that the initial amount of a 20% salt solution is 500 grams, we need to determine the amount 'x' of a 5% salt solution to be added.
Using the formula for mixing solutions, "Initial amount of salt + Additional amount of salt = Final amount of salt," we can calculate 'x'.
The initial amount of salt in the 500 grams of 20% solution is 20% of 500g, which equals 100g.
The additional amount of salt can be determined by considering the concentration of salt in the 5% solution.
For every 100 milliliters (ml) of the 5% solution, there are 5 grams of salt.
Therefore, in 1 liter (1000 ml) or 1000 grams of the 5% solution, there are 5 grams of salt. Consequently, in 'x' grams of the 5% salt solution, the amount of salt present is (5/100) × x grams or x/20 grams.
Setting up the equation, the final amount of salt is given by 100g + x/20g, which should equal (3/20) × 500g (since the final amount is 75g).
Simplifying the equation, we have x/20 + 100 = 75, leading to x/20 = 75 - 100, x/20 = -25, and x = -25 × 20 = -500.
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how to find oxidation number
The oxidation number of the atom is the number that will represents the total number of the electrons lost or the gained by it.
The oxidation number of the atom is the number that will represents the total number of the electrons lost or the gained by it. The free element has an oxidation number that is equal to zero. For the monoatomic ions, the oxidation number will always be has the same value as the charge related to the ion.
The hydrogen atom (H) will exhibits an oxidation state of the +1. The Oxygen has the oxidation of the -2 in most of the compounds. All the alkali metals that have the oxidation state of the +1 in the alkali compounds.
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What is the electric configuration for phosphorus?
Not every earthquake has a(n) ______, but every earthquake has _____that occur in _____ the mainshock.
1.
Aftershock
Foreshock <------
2.
Aftershock <-------
Foreshock
3.
Places far away from
The Same place as <------
Am i right?
Not every earthquake has a(n) Foreshock, but every earthquake has an Aftershock that occurs in the Same place as the mainshock.
What is an earthquake?
An earthquake is defined as a natural disaster in which there are tectonic plates that are present on the earth's crust collides with each other.
An Earthquake can be minor as well as natural depending upon the frequency it causes the damage. Earthquake is the Shaking of Earth and was much destruction of the economy and manpower.
Surroundings are being disturbed like trees will fall, and buildings will collapse which will cause damage to the economy as well as to human life.
Foreshock is the before shop which happens before the earthquake and aftershock is the other socks that happen after the earthquake
Thus, the correct options are 1. Foreshock, 2. Aftershock, 3. The Same place as.
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i am begging anyone to help me with this! (all tutors i've asked said they can't solve it but i need someone to help me out) - i can get the first little bit of it so maybe we can work through it together?
First, we need to calculate how much energy we will get from this combustion.
Assuming the combustion is complete, we have the octane reacting with O₂ to form only water and CO₂, so:
\(C_8H_{18}+O_2\to CO_2+H_2O\)We need to balance the reaction. Carbon only appear on two parts, so, we can start by it:
\(C_8H_{18}+O_2\to8CO_2+H_2O\)Now, we balance the hydrogen:
\(C_8H_{18}+O_2\to8CO_2+9H_2O\)And in the end, the oxygen:
\(C_8H_{18}+\frac{25}{2}O_2\to8CO_2+9H_2O\)We can multiply all coefficients by 2 to get integer ones:
\(2C_8H_{18}+25O_2\to16CO_2+18H_2O\)Now, we need to use the enthalpies of formation to get the enthalpy of reaction of this reaction.
The enthalpy of reaction can be calculated by adding the enthalpies of formation of the products multiplied by their stoichiometric coefficients and substracting the sum of enthalpies of formation of the reactants multiplied by their stoichiometric coefficients.
For the reactants, we have (the enthalpy of formation of pure compounds is zero, which is the case for O₂):
\(\begin{gathered} \Delta H\mleft\lbrace reactants\mright\rbrace=2\cdot\Delta H\mleft\lbrace C_8H_{18}\mright\rbrace+25\cdot\Delta H\mleft\lbrace O_2\mright\rbrace \\ \Delta H\lbrace reactants\rbrace=2\cdot(-250.1kJ)+25\cdot0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ+0kJ \\ \Delta H\lbrace reactants\rbrace=-500.2kJ \end{gathered}\)For the products, we have:
\(\begin{gathered} \Delta H_{}\mleft\lbrace product\mright\rbrace=16\cdot\Delta H\lbrace CO_2\rbrace+18\cdot\Delta H\lbrace H_2O\rbrace \\ \Delta H_{}\lbrace product\rbrace=16\cdot(-393.5kJ)+18\cdot(-285.5kJ) \\ \Delta H_{}\lbrace product\rbrace=-6296kJ-5139kJ \\ \Delta H_{}\lbrace product\rbrace=-11435kJ \end{gathered}\)Now, we substract the rectants from the produtcs:
\(\begin{gathered} \Delta H_r=\Delta H_{}\lbrace product\rbrace-\Delta H\lbrace reactants\rbrace \\ \Delta H_r=-11435kJ-(-500.2kJ) \\ \Delta H_r=-10934.8kJ \end{gathered}\)Now, this enthalpy of reaction is for 2 moles of C₈H₁₈, so for 1 mol of C₈H₁₈ we have half this value:
\(\Delta H_c=\frac{1}{2}\Delta H_r=\frac{1}{2}\cdot(-10934.8kJ)=-5467.4kJ\)Now, we have 100 g of C₈H₁₈, and its molar weight is approximately 114.22852 g/mol, so the number of moles in 100 g of C₈H₁₈ is:
\(\begin{gathered} M_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{n_{C_8H_{18}}} \\ n_{C_8H_{18}}=\frac{m_{C_8H_{18}}}{M_{C_8H_{18}}}=\frac{100g}{114.22852g/mol}\approx0.875438mol \end{gathered}\)Since we have approximately 0.875438 mol, and 1 mol releases -5467.4kJ when combusted, we have:
\(Q=-5467.4kJ/mol\cdot0.875438mol\approx-4786.37kJ\)Now, for the other part, we need to calculate how much heat it is necessary to melt a mass, m.
First, we have to heat the ice to 0 °C, so:
\(\begin{gathered} Q_1=m\cdot2.010J/g.\degree C\cdot(0-(-10))\degree C \\ Q_1=m\cdot2.010J/g\cdot10 \\ Q_1=m\cdot20.10J/g \end{gathered}\)Then, we need to melt all this mass, so we use the latent heat now:
\(Q_2=n\cdot6.03kJ/mol\)Converting mass to number of moles of water we have:
\(\begin{gathered} M=\frac{m}{n} \\ n=\frac{m}{M}=\frac{m}{18.01528g/mol} \end{gathered}\)So:
\(Q_2=\frac{m}{18.01528g/mol}_{}\cdot6.03kJ/mol\approx m\cdot0.334716kJ/g\)Adding them, we have a total heat of:
\(\begin{gathered} Q_T=m\cdot20.10J/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.02010kJ/g+m\cdot0.334716kJ/g \\ Q_T=m\cdot0.354816kJ/g \end{gathered}\)Since we have a heat of 4786.37 kJ form the combustion, we input that to get the mass (the negative sign is removed because it only means that the heat is released from the reaction, but now it is absorbed by the ice):
\(\begin{gathered} 4786.37kJ=m\cdot0.354816kJ/g \\ m=\frac{4786.37kJ}{0.354816kJ/g}\approx13489g\approx13.5\operatorname{kg} \end{gathered}\)Since we have a total of 20kg of ice, we can clculate the percent using it:
\(P=\frac{13.5\operatorname{kg}}{20\operatorname{kg}}=0.675=67.5\%\)a solution contains 1.569 mg of coso4 (155.0 g/mol) per milliliter. calculate a. the volume of 0.007840 m edta needed to titrate a 25.00 ml aliquot of this solution. b. the volume of 0.009275 m zn2 needed to titrate the excess reagent after addition of 50.00 ml of 0.007840 m edta to a 25 ml aliquot of this solution
Volume of EDTA needed is \(32.28ml\) and Volume of \(Zn^{+2}\) needed to titrate the excess reagent is \(14.9796ml\).
Titration-a procedure or method for calculating the concentration of a dissolved substance using the least amount of reagent at a certain concentration needed to get a specific result when combined with a known volume of the test solution.
concentration refers to the amount of a substance in a defined space. Another definition is that concentration is the ratio of solute in a solution to either solvent or total solution.
Concentration of \(Co^{+2}\)=\((\frac{1.569\times10^{-3} }{155} )\times(\frac{1000}{1} )=0.0101226M\)
\(M_{1}V_{1} =M_{2}V_{2}\)\(V_{1}=\frac{0.0101226M\times25ml}{0.007840M}\)
\(V_{1}=32.2786ml\)
Volume of EDTA needed is\(32.28ml\)
millimoles of EDTA taken = \(0.007840M\times 50.00ml = 0.392mmol\)millimoles of \(CO^{+2}\) in the sample is \(0.0101226M\times25.00ml = 0.25306mmol\)
millimoles of EDTA(excess)=\(0.392 - 0.25306 = 0.138935mmol\)= millimoles of \(Zn^{+2}\) reacted
Volume of \(Zn^{+2}\) needed = \(\frac{0.138835mmol}{0.009275M } = 14.9796\:ml\)
Volume of \(Zn^{+2}\) needed to titrate the excess reagent\(=14.9796ml\)
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1,3-cyclopentadiene. how many molecular orbitals are bonding molecular orbitals?
The number of bonding molecular orbitals among the molecular orbitals of 1,3-cyclopentadiene is 5.
The 1,3-cyclopentadiene molecule is composed of 5 carbon atoms and 8 hydrogen atoms. Each carbon atom has 4 valence electrons, and each hydrogen atom has 1 valence electron. Therefore, the total number of valence electrons in the molecule is (5 x 4) + (8 x 1) = 28.
Molecular orbitals are formed when atomic orbitals combine. In 1,3-cyclopentadiene, there are 5 atomic orbitals from the 5 carbon atoms and 8 atomic orbitals from the 8 hydrogen atoms, for a total of 13 atomic orbitals. These 13 atomic orbitals combine to form 13 molecular orbitals.
Of these 13 molecular orbitals, 5 are bonding molecular orbitals, 5 are antibonding molecular orbitals, and 3 are nonbonding molecular orbitals. The bonding molecular orbitals are lower in energy than the antibonding molecular orbitals and are therefore filled with electrons first. The 5 bonding molecular orbitals are filled with a total of 10 electrons, leaving 18 electrons to fill the remaining 8 molecular orbitals.
Therefore, the 1,3-cyclopentadiene molecule has a total of 5 bonding molecular orbitals.
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is nh3 strong or weak?
Ammonia (NH₃) is a weak base.
When dissolved in water, ammonia reacts with water molecules to form ammonium ions (NH₄⁺) and hydroxide ions (OH⁻), according to the following equation:
NH₃ + H₂O ⇌ NH₄⁺ + OH⁻
Ammonia only partially dissociates in water, which means that it produces relatively few hydroxide ions compared to a strong base like sodium hydroxide (NaOH). Therefore, ammonia is considered a weak base.
The strength of a base is determined by its ability to donate hydroxide ions (OH⁻) in water, which is quantified by the base dissociation constant (Kb). The Kb value for ammonia is relatively low (1.8 x 10⁻⁵), compared to strong bases like sodium hydroxide (Kb value of 1.0 x 10¹⁴).
Overall, ammonia can still react with acids to form salts and water, but its reactivity is much weaker than that of a strong base.
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an experimental plot of ln(k) vs. 1/t is obtained in lab for a reaction. the slope of the best-fit line for the graph is -2905 k. what is the value of the activation energy for the reaction in kj/mol?
Multiplying the slope (-2905 k) by the gas constant (0.008314 kJ/mol K) gives the activation energy: 24.1 kJ/mol.
The slant of the best-fit line for the diagram of ln(k) versus 1/T is equivalent to - Ea/R, where Ea is the actuation energy for the response, R is the gas consistent, and T is the temperature in Kelvin. To decide the actuation energy, we really want to improve this condition to address for Ea.
Ea = - slant x R
We realize that the slant of the best-fit line is - 2905 K, and R is 8.314 J/(mol·K). In any case, the slant should be changed over completely to units of J/(mol·K) by duplicating by 1000, since we need the actuation energy in units of kJ/mol. Accordingly:
Ea = - (- 2905 K x 8.314 J/(mol·K)) x (1/1000 kJ/J)
Ea = 24.1 kJ/mol
The initiation energy for the response is 24.1 kJ/mol. This worth addresses the base energy expected for the reactants to defeat the energy hindrance and structure items. The higher the initiation energy, the more slow the response rate, as well as the other way around.
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what is the transformation efficiency of e coli hb101 when using the claciu chloride
The transformation efficiency of E. coli HB101 using calcium chloride can vary depending on the experimental conditions and the protocol used.
However, transformation efficiency is a measure of how many bacterial cells take up the foreign DNA and become genetically transformed, usually reported as the number of transformants per microgram of DNA. To calculate the transformation efficiency of E. coli HB101 using calcium chloride, follow the 5 steps:
1. Perform a transformation experiment using E. coli HB101 and calcium chloride. This usually involves treating the bacterial cells with calcium chloride to make them more permeable to foreign DNA, then exposing them to the DNA of interest.
2. Plate the transformed cells on selective agar plates that will allow only the transformed cells to grow.
3. Count the number of transformant colonies that appear on the selective agar plates after a suitable incubation period.
4. Determine the amount of DNA (in micrograms) used in the transformation experiment.
5. Calculate the transformation efficiency by dividing the number of transformant colonies by the amount of DNA used.
The result will be in the unit of transformants per microgram of DNA. Keep in mind that the transformation efficiency can be influenced by factors such as the quality and concentration of the DNA, the bacterial strain, and the specific experimental conditions. Therefore, the transformation efficiency for E. coli HB101 using calcium chloride may differ between experiments and laboratories.
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How many grams of sodium hydroxide (NaOH) do you need to make 6.5 L of 1.0M solution?
260grams
Explanations:The formula for calculating the moles of NaOH is expressed as
\(\begin{gathered} moles=molarity\times volume \\ moles\text{ of NaOH}=1.0M\times6.5L \\ moles\text{ of NaOH}=6.5moles \end{gathered}\)Determine the required mass of NaOH
\(\begin{gathered} Mass\text{ of NaOH}=moles\times molar\text{ mass} \\ Mass\text{ of NaOH}=6.5\cancel{moles}\times\frac{40g}{\cancel{mole}} \\ Mass\text{ of NaOH}=260grams \end{gathered}\)Hence the grams of sodium hydroxide (NaOH) you need to make 6.5 L of 1.0M solution is 260grams