In a perfectly elastic collision, mass, mechanical energy, and momentum are conserved.
In a perfectly elastic collision, two objects collide and then separate without any loss of kinetic energy. This means that the total mechanical energy of the system remains constant before and after the collision. The conservation of mechanical energy implies that no energy is lost to other forms, such as heat or sound, during the collision.
Additionally, the law of conservation of momentum holds true in a perfectly elastic collision. Momentum, which is the product of an object's mass and velocity, is conserved before and after the collision. This means that the total momentum of the system remains constant, even though the individual objects involved in the collision may experience changes in their velocities.
Lastly, the conservation of mass is another important aspect of a perfectly elastic collision. The total mass of the system, which includes all the objects involved in the collision, remains constant throughout the collision. This principle holds true as long as there is no external force acting on the system that could change the mass.
In conclusion, a perfectly elastic collision conserves mass, mechanical energy, and momentum. These principles are fundamental to understanding the behavior of objects interacting through collisions, and they provide valuable insights into the dynamics of physical systems.
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what factors go into decisions about changing what materials should be used when building a products
Answer:
you need to consider the use for the product, how brittle the materials are, how they react to certain things, the cost of the materials, the durability and flexibility of the materials, and how easy to obtain the materials are as well as how they would work and how they would hold
As a general rule, women __________.
A. are more flexible than men
B. are less flexible than men
C. are as flexible than men
D. are flexible in different ways than men
Answer:
a
Explanation:
An electron moves perpendicular to a sunspot at a speed of 7.8 * 10 6 m/s. A magnetic force of 3.7 * 10 -13 N is exerted on the electron. What is the magnitude of the magnetic field emitted by the sunspot
The magnitude of the magnetic field emitted by the sunspot is approximately 2.95 x 10⁻⁴ Tesla.
To determine the magnitude of the magnetic field emitted by the sunspot, we can use the formula for the magnetic force on a charged particle:
F = q * v * B * sin(θ)
where F is the magnetic force (3.7 x 10⁻¹³ N), q is the charge of the electron (1.6 x 10⁻¹⁹ C), v is the speed of the electron (7.8 x 10⁶ m/s), B is the magnitude of the magnetic field, and θ is the angle between the velocity and the magnetic field. Since the electron moves perpendicular to the sunspot, θ = 90°, and sin(θ) = 1.
Now we can rearrange the formula to solve for B:
B = F / (q * v * sin(θ))
Substitute the given values:
B = (3.7 x 10⁻¹³ N) / (1.6 x 10⁻¹⁹ C * 7.8 x 10⁶ m/s * 1)
B ≈ 2.95 x 10⁻⁴ T
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TRUE or FALSE
Organs are composed of multiple tissue types.
Answer:
TRUE
Explanation:
Organs are made of two or more tissue types to allow them to function.
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A 1 kg object is located at a distance of 1.0 x 103 m from the center of a larger
object whose mass is 2.0 x 1020 kg.
a. What is the size of the force acting on the smaller object?
The force = 1.334 x 10⁴ N
Further explanationGravity is a force that arises because of the attraction between objects with mass.
The magnitude of this attraction is proportional to the mass of the object.
The greater the mass of the object, the greater the gravitational force
Relationships can both be stated in
Newton's Gravity Law:
\(\rm F=G.\dfrac{m_1.m_2}{r^2}\)
with F = gravitational force, N
G = gravitational constant, 6.67 x 10⁻¹¹ Nm²/kg²
m1, m2 = mass of object, kg
r = distance between two objects. m
m₁= 1 kg
m₂=2 x 10²⁰ kg
r = 1 x 10³ m
The force acting on the smaller object=The force acting on the larger object(Newton's Third Law)
\(\tt F=6.67\times 10^{-11}\dfrac{1\times 2.10^{20}}{(1\times 10^3)^2}\\\\F=1.334\times 10^4~N\)
Arthur puts new batteries in his flashlight before leaving the house. Until the batteries die, it draws 0.25 A of current, allowing a total of 6,812 C of charge to. flow in the circuit. How long will Arthur be able to use the flashlight before the batteries'energy is depleted?
Given,
The current, I=0.25 A
The total charge flowing in the circuit is q=6812 C.
The electric current can be defined as the time rate of flow of the charges.
Thus, the electric current is given by,
\(I=\frac{q}{t}\)Where t is the time duration.
\(\begin{gathered} 0.25=\frac{6812}{t} \\ t=\frac{6812}{0.25} \\ =27248\text{ s} \end{gathered}\)Thus the batteries will fry out after 27248 s
what’s the relationship between height and potential energy?
Answer:
the higher up an object is, the more potential energy it has
Explanation:
1) An astronaut has a mass of 40Kg. Calculate his weight on earth if Gravity (g) = 10m/s^2.
2) The same astronaut goes to the International Space Station. Here the gravitational pull is equal to .5 m/s^2. Calculate his weight.
3) Our astronaut friend is assigned to study a neutron star. He travels to the surface using a special suit. Here the gravitational force is terrible at 150m/s^2 What is the astronaut’s weight?
Answer:
The formula is W=mg.
1.) W=40×10=400.
2.)W=40×5=200.
3.)W=40×150=6000.
130 An object, initially at rest, is dropped from a height of 12.0m. The change in gravitational potential
energy when it falls to the ground is 565J.
The frictional forces are negligible
mgh
What is its speed when it hits the ground?
A
4.71 m/s
B
15.5m/s
C 47.1 m/s
D 240 m/s
The speed when it hits the ground is option (B) 15.5 m/s.
To determine the speed of the object when it hits the ground, we can use the principle of conservation of energy. The initial potential energy of the object is converted into kinetic energy as it falls.
The change in gravitational potential energy is given as ΔPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
We know that ΔPE = 565 J, and the height h = 12.0 m.
Since the object is initially at rest, its initial kinetic energy is zero.
The total mechanical energy (sum of potential and kinetic energy) is conserved, so:
ΔPE = ΔKE
mgh = (1/2)mv^2
Here, m cancels out, giving:
gh = (1/2)v^2
Substituting the known values:
(9.8 m/s^2)(12.0 m) = (1/2)v^2
117.6 = (1/2)v^2
Dividing both sides by (1/2):
235.2 = v^2
Taking the square root of both sides:
v ≈ 15.33 m/s
Therefore, the speed of the object when it hits the ground is approximately 15.33 m/s.
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Phosphorus atoms are to be diffused into a silicon wafer using both predeposition and drive-in heat treatments; the background concentration of P in this silicon material is known to be 7.5 x 10^19 atoms/m^3. The predeposition treatment is to be conducted at 950 degree C for 50 minutes; the surface concentration of P is to be maintained at a constant level of 2.0 x 10^26 atoms/m^3. Drive-in diffusion will be carried out at 1200 degree C for a period of 3.0 h. For the diffusion of P in Si, values of Qd and D0 are 3.40 eV/atom and 1.1 x 10^4 m^2/s, respectively.
Required:
Determine the value of xj for the drive-in diffusion treatment.
The diffusion of phosphorus atoms into a silicon wafer involves a predeposition treatment at 950°C for 50 minutes, surface concentration of P at 2.0 x 10^26 atoms/m^3, followed by a drive-in diffusion at 1200°C for 3.0 hours.
To calculate the depth of diffusion (x) during the predeposition and drive-in treatments, we can use the equation:
x = sqrt((4 * D * t) / π)
where x is the depth of diffusion, D is the diffusion coefficient, and t is the time.
Predeposition Treatment:
Given:
Temperature (T) = 1223 K
Time (t) = 3000 seconds
Surface concentration (Cs) = 2.0 x 10^26 atoms/m^3
According to the diffusion coefficient (D) formula:
D =( D0 * exp(-Q d / (k * T)))
where D0 is the pre-exponential factor, Qd is the activation energy, and k is the Boltzmann constant (8.617 x 10^-5 eV/K).
Substituting the values and calculating D:
D = (1.1 x 10^4 m^2/s) * exp(-3.40 eV / (8.617 x 10^-5 eV/K * 1223 K))
D ≈ 3.32 x 10^-4 m^2/s
Now, substitute the values into the depth of diffusion formula:
x = sqrt((4 * D * t) / π)
x = sqrt((4 * (3.32 x 10^-4 m^2/s) * 3000 s) / π)
x ≈ 0.029 m or 29 mm
Therefore, during the predeposition treatment, the depth of diffusion is approximately 29 mm.
Drive-In Diffusion:
Given:
Temperature (T) = 1200°C = 1473 K
Time (t) = 3.0 hours = 3.0 * 60 * 60 = 10800 seconds
Using the same diffusion coefficient (D) calculated earlier, we can calculate the depth of diffusion (x) during the drive-in treatment:
x = sqrt((4 * D * t) / π)
x = sqrt((4 * (3.32 x 10^-4 m^2/s) * 10800 s) / π)
x ≈ 0.135 m or 135 mm
Therefore, during the drive-in diffusion, the depth of diffusion is approximately 135 mm.
During the predeposition treatment, the depth of diffusion of phosphorus (P) atoms into the silicon (Si) wafer is approximately 29 mm. During the drive-in diffusion, the depth of diffusion is approximately 135 mm. These calculations are based on the given diffusion parameters and treatment conditions.
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How is the total energy in an isolated system is a conserved quantity
An isolated system is completely isolated from its surroundings and no transfer of energy or mass is possible between the system and surroundings.
The law of conservation of energy or the first law of thermodynamics states that the energy can neither be created nor be destroyed, but it can be transformed from one form to another. In other words, the total energy of an isolated system is always conserved.
For example, when you are driving a car or a motorcycle, the chemical energy that was stored either in the fuel or in the battery is getting converted into mechanical energy. Similarly, when an explosion happens, the chemical energy of the fuel is converted into light energy and heat energy.
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A certain lever system is only 30% efficient. The following changes are considered:
change 1: Use a stiffer lever to reduce energy lost bending the lever.
change 2: Make a longer lever that will require less force.
Which change would make the lever more efficient?
Change 1 would make the lever more efficient because less energy would be lost.
Change 2 would make the lever more efficient because this would make it easier to lift.
Change 1 would make the lever more efficient because this would make it easier to lift.
Change 2 would make the lever more efficient because less energy would be lost.
Answer: Change 2 would make the lever more efficient because this would make it easier to lift.
Explanation:
The considered change is: Make a longer lever that will require less force because it would make the lever more efficient because this would make it easier to lift.
What is lever?A beam is pivoted at a fixed fulcrum, to form a simple machine known as a lever. A body that can rotate about a point on itself is called a lever.
The lever is classified into three types based on where the fulcrum, weight, and effort are located. Additionally, leverage is a systemic mechanical advantage.
One of the six simple devices that Renaissance scientists identified. Leverage is the ability to increase an input force into a bigger output force through the use of a lever. The mechanical advantage of the lever is determined by the ratio of output force to input force.
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A light year is approximately 9. 5 trillion km long. 'barnard's star' is 6 light years away from earth. Calculate how many trillions of kilometres this is.
Using the theories of light year, we got that 57.0 trillion km is 'Barnard's star' away from earth.
Light is the fastest-moving stuff in the our universe. It actually travels at 186,000 miles per second (300,000 km/sec). And thus a light-year is about 5.88 trillion miles (9.46 trillion kilometers).
We know very well that ,
1 light year=9.5 trillion km
Therefore,6 light year=6×9.5 trillion km
=>6 light year=57.0 trillion km.
Hence, if a light year is approximately 9. 5 trillion km long, 'Barnard's star' is 6 light years away from earth which is equivalent to 57 trillion of kilometres
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8. The diagram below shows a hot air balloon rising. Propane gas tanks are seen at
the bottom of the balloon
What energy transformations occur when propane gas is used to lift the balloon?
A.thermal-> Chemical-> light
B. Chemical-> mechanical->
Thermal
C. Chemical-> mechanical-> thermal
D. Mechanical-> light-> Chemical
Answer:
C. Chemical-> mechanical-> thermal
Explanation:
The energy conversion for the propane, that is, energy transformations that occur when propane gas is used to lift the balloon will be:
Chemical energy converting to mechanical energy which later converted to thermal energy
The correct option is therefore Chemical-> mechanical-> thermal which is option C
What is the cost of operating a 40 W light bulb for a year, if the cost of electricity is $0.10 per kWh
Answer:
$480 a year
Explanation:
Ocean swells are an example of waves. In the Waves Gizmo, you will observe wave motion on a model of a spring. The hand can move the spring up and down or back and forth.
To begin, check that the Type of wave is Transverse, Amplitude is 20. 0 cm, Frequency is 0. 75 Hz, Tension is 3. 0 N, and Density is 1. 0 kg/m. (Note: In this Gizmo, "density" refers to the linear mass density, or mass per unit length. It is measured in units of kilograms per meter. )
1. Click Play (). How would you describe the motion of a transverse wave? Click Pause (). Notice the crests (high points) and troughs (low points) of the wave.
2. Click Reset (). Choose the Longitudinal wave and increase the Amplitude to 20. 0 cm. Click Play. How would you describe the motion of a longitudinal wave? Click Pause. Notice the compressions in the wave where the coils of the spring model are close together and the rarefactions where the coils are spread apart
When we Click Play() the motion of a transverse wave is from left to right and when we Click Reset() the motion of a wave and hand both is left to right.
Wave motion is the regular and orderly movement of disturbances, or departures from equilibrium or rest, from one location to another. The most well-known waves are surface waves on water, but waves can also be seen in sound waves, light waves, and subatomic particle movements.
When we Click Play() the motion of a transverse wave will be from left to right but the movement of particles will be up and down and in conclusion the wave moves left and right and the hands move up and down.
Now, when we Click Reset() and choose the Longitudinal wave and increase the Amplitude to 20. 0 cm. and then Click Play the motion of the longitudinal wave and the hand both is left to right.
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Give me an example of heterogeneous mixture
Answer:
oil and water
Explanation:
solve for x, x=2.7(35)+1/2(-9.7)*35^2
The answer is:
-5846.75
Kyle and Jenny both have pet rabbits. They wanted to see who had the fastest rabbit, so they each recorded data at their homes and brought it's the results. Kyle rabbit went a total of 40 m in a time of one minute and 20 seconds. Jenny's rabbit went 30 m in one minute and 30 seconds. What was the velocity of Kyle's rabbit? What was the velocity of jennies rabbit? Whose rabbit was the fastest?
Answer:
v_kyle = 0.5 m/s
v_jennies = 0.333 m/s
Kyle's Rabbit was the fastest
Explanation:
For the velocity of Kyle's Rabbit:
d = distance covered = 40 m
t = time taken = (1 min)(60s/1 min) + 20 s = 80 s
\(v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}\)
v_kyle = 0.5 m/s
For the velocity of Jennies Rabbit:
d = distance covered = 30 m
t = time taken = (1 min)(60s/1 min) + 30 s = 90 s
\(v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}\)
v_jennies = 0.333 m/s
It is clear from the results that:
Kyle's Rabbit was the fastest
An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?
Answer:
8.89 m/s
Explanation:
rate = distance/time
40m/4.5 sec = 8.8888889 m/s
PLEASE HELPPP
Force: Adding vectors (find resultant force)
50N north plus 50N west Plus 50N north west
Placing ice on a sprained ankle this is an example of conduction, convection, radiation?
A satellite is 1200 k above the earth (radius = 6400 k); it completes one revolution in 90min. what is the linear speed?
A satellite is 1200 k above the earth (radius = 6400 k); it completes one revolution in 90min. what is the linear speed?
530.58 (1200+6400)*pi*2/90
What is linear speed?The measurement of a moving object's actual distance traveled is called linear speed. Linear speed is the rate of motion of an object along a straight line. In plain English, it is the distance traveled along a linear path in the allotted amount of time.
A pseudovector used in physics to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves. The right-hand rule is a common way to specify the direction of angular velocity.
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The foot of a 60 kg sprinter is on the ground for 0.40 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?
We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.
To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.
Mass of the sprinter,
m = 60 kgTime the sprinter's foot is on the ground,
t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,
v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:
v = final velocity of the sprinter, which is 2.0 m/s
u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s
Substituting these values, we get:2.0
= 0 + a(0.40)Simplifying, we get:
2.0 = 0.4a
Dividing both sides by 0.4, we get:
a = 5 m/s² Substituting the values, we get:
F = 60 × 5F = 300 N
Therefore, the magnitude of the friction force is 300 N.
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According to Coulomb's law, what happens to the attraction of two oppositely charged objects as their distance of separation increases?
(a) increases (b) decreases
(c) remains uncharged (d) cannot be determined
Answer:
Option B. Decreases
Explanation:
Coulomb's law states that:
F = Kq₁q₂ / r²
Where:
F => is the force of attraction between two charges
K => is the electrical constant.
q₁ and q₂ => are the two charges
r => is the distance apart.
From the formula:
F = Kq₁q₂ / r²
The force of attraction (F) is inversely proportional to the square of their separating distance (r).
This implies that as the distance between them increase, the force of attraction between the two charges will decrease and as the distance between two charges decrease, the force of attraction between them will increase.
Considering the question given above and the illustration given above, the force of attraction will decrease as their distance of separation increases.
Option B gives the right answer to the question.
The amount of potential energy (PE) an object has depends on the object's _____________. *
height
motion
velocity
Joules
The amount of kinetic energy (KE) an object has depends on the object's _____________ *
height
motion
acceleration due to gravity
Joules
magnesium plus iron sulphate
Answer:
what is the ❓❓❓⁉️⁉️⁉️⁉️
if an object has a smaller density than water, will the object stay fully submerged, partly submerged, or rise completely out of the water when it is released underwater
If an object has a smaller density than water, it will partially submerge in water. This is because of Archimedes' principle, which states that an object will float in a fluid if its weight is less than or equal to the weight of the fluid displaced by the object.
If the object's density is less than that of water, it will displace a volume of water that weighs more than the object, causing it to float partially.
The extent to which the object will submerge depends on the difference between its density and that of water. If the difference is small, the object will float only slightly below the surface of the water. On the other hand, if the object's density is much less than that of water, it will float high above the surface of the water, partially submerged.
It is worth noting that an object with a density that is much less than that of water will eventually rise to the surface of the water. This is because the buoyant force acting on the object increases as the object rises, eventually exceeding the object's weight and causing it to float to the surface.
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if the order quantity doubles, what happens to the frequency of orders (i.s., the number of orders submitted per unit of time)?
If the order quantity doubles, the frequency of orders, or the number of orders submitted per unit of time, is likely to decrease because when the order quantity doubles, it means that more products are being ordered in each order
If the order quantity doubles, the frequency of orders, or the number of orders submitted per unit of time, is likely to decrease. This is because when the order quantity doubles, it means that more products are being ordered in each order, resulting in fewer orders required to fulfill the same demand.
When the order quantity increases, it implies that larger batches of products are being produced or purchased. This reduces the need for frequent ordering since a single order can cover a larger quantity of items, meeting the demand for a longer duration. As a result, the frequency of orders decreases because fewer orders are needed to maintain inventory levels.
Reducing the frequency of orders can bring several benefits to businesses. It can lead to cost savings by reducing order processing costs, administrative tasks, and transportation expenses associated with each order. Additionally, it can optimize inventory management by allowing for more efficient production planning and reducing stockouts.
However, it's important to note that the relationship between order quantity and order frequency may also depend on factors such as demand variability, lead times, and storage capacity. It is crucial for businesses to strike a balance between order quantity and frequency to ensure optimal inventory management and customer satisfaction,
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Which of the following employs a 160-bit hash?
A. MD5
B. SHA-1
C. SHA-2
D. NTLM
B. SHA-1 employs a 160-bit hash.
Hash functions are mathematical algorithms that take input data and produce a fixed-length output called a hash or digest. The hash is unique to the input data, which means that even a small change to the input data will result in a completely different hash. Hash functions are widely used in cryptography, digital signatures, and data integrity checks.
MD5 is a widely used hash function that produces a 128-bit hash. However, MD5 is now considered insecure and has been deprecated due to security vulnerabilities that have been discovered.
SHA-1 is another widely used hash function that produces a 160-bit hash. However, like MD5, SHA-1 is now considered insecure and has been deprecated.
SHA-2 is a family of hash functions that includes SHA-224, SHA-256, SHA-384, and SHA-512. These hash functions produce hashes that range from 224 to 512 bits in length and are considered more secure than MD5 and SHA-1.
NTLM is a hashing algorithm used for password authentication in Windows NT and later versions of Windows. NTLM uses a variety of hash functions, including MD4, MD5, and SHA-1, depending on the version of Windows being used. However, like MD5 and SHA-1, NTLM is now considered insecure and has been deprecated in favor of more secure authentication protocols such as Kerberos.
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