The value of x is 15.8. (one decimal place)
What is complementary angles?Complementary angles are two angles that add up to a 90-degree angle (a right angle). In other words, if two angles are complementary, the sum of the measures of the angles is 90 degrees. For example, if one angle measures 30 degrees, then its complementary angle measures 60 degrees (since 30 + 60 = 90). Complementary angles are often denoted as "∠A" and "∠B," and they are commonly found in geometry and trigonometry problems.
Two angles are complementary if the sum of the measures is 90°. Therefore, the sum of 2x-9 and 6x-27 must be equal to 90°.
2x-9+6x-27=90
Combine like terms: 8x=126
x=15.8
Therefore, In this case, x is 15.8.
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A dishwasher is priced at $685. There is an 8% sales tax rate. What is the sales tax of the dishwasher in dollars and cents?
Answer:
The tax would be $54.80 !
Step-by-step explanation:
To do the problem you have to cross multiply and divide.
\(\frac{x}{685} = \frac{8}{100}\)
685 x 8 = 5480
5480 / 100 = 54.8
Simplify 5x^2 +x^2+2+x^2+6
Answer:
\(=7x^2+8\)
Step-by-step explanation:
\(5x^2+x^2+2+x^2+6\)
\(=5x^2+x^2+x^2+2+6\)
\(=5x^2+x^2+x^2+8\)
\(=7x^2+8\)
Brainliest?!
A professor of cognitive psychology is interested in the percent accuracy on this memory encoding task among college students. She measures the percent accuracy for 36 randomly selected students. The professor knows that the distribution of scores is normal, but she does not know that the true average percent accuracy on this memory encoding task among college students is 0. 793 percent correct with a standard deviation of 0. 114 percent correct
The expected value of the mean of the 64 randomly selected students, M, is 0.794 percent correct
Since the sample size is relatively large (n=64) and the population standard deviation is known, we can use the Central Limit Theorem to approximate the distribution of sample means as normal with a mean equal to the population mean (µ) and a standard error equal to the population standard deviation divided by the square root of the sample size (σ/√n).
Thus, the expected value of the mean of the 64 randomly selected students, M, is:
E(M) = µ = 0.794 percent correct
Therefore, the expected value of the mean is 0.794 percent correct
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The given question is incomplete, the complete question is:
A professor of cognitive psychology is interested in the percent accuracy on this memory encoding task among college students. She measures the percent accuracy for 64 randomly selected students. The professor knows that the distribution of scores is normal, but she does not know that the true average percent accuracy on this memory encoding task among college students is 0.794 percent correct with a standard deviation of 0.1110 percent correct. The expected value of the mean of the 64 randomly selected students, M, is___ (Note: use mean and/or standard deviation just given to calculate the expected value of M.)
How to find the length of the segment indicated?
Answer:
Step-by-step explanation:
it is 2x
Solve: (4.5 x 10^4)/ (300)
Please and Thank you.
Answer:
150 plz brainliest
Step-by-step explanation:
10^4 = 10000
10000 (4.5) = 45,000
45,000/300 = 150
you are asked to size the diameter of a bolt loaded in shear to the nearest 1/8 inch with a factor of safety of 1.5. you find that bolt diameter that yields this factor of safety is 2.4183 inches. what is the diameter of the bolt you should use (in units of inches to 3 decimal places).
Answer:
2.375 inches
Step-by-step explanation:
Main Steps
1. Identifying important parts of the question
2. Solving the problem
Step 1. - Identifying important parts of the question
In the question, there is some extraneous information. For instance, the question introduces the terms "diameter" and "loaded in shear" and "with a safety factor of 1.5". However, given the information in the problem, and the question asked, it isn't necessary to know that it is "loaded in shear" means, or to know what a diameter is (since everything stays with diameters, and doesn't involve another dimension), and the problem gives the result that will satisfy "a safety factor of 1.5".
Sifting through the problem/question, these are the important parts:
- "to the nearest 1/8 inch" (meaning round to the nearest 1/8th of a unit)
- with "units of inches to 3 decimal places"
- The number to round is "2.4183 inches
Step 2. - Solving the Problem
To round to the nearest 1/8 inch, we can divide the number 2.4183 by 1/8.
\(2.4183 \div(1/8)\)
Recall that dividing by a fraction is the same as multiplying by the reciprocal
\(2.4183 * 8\)
19.3464
So, there are approximately 19, one-eighth-inches in the measurement. (Note that 19.3464 is closer to 19 than it is to 20). To find the final rounded measurement, multiply 19 by 1/8
\(19 * (1/8)\)
2.375 inches
So, the diameter of the bolt that should be used (if rounded to the nearest 1/8 inch, to allow for a factor of safety of 1.5) is 2.375 inches
Raw material purchases: $100,000 percentage of raw material purchases transferred to work in process: 50% direct labor: $200,000 overhead: $300,000 total depreciation: $30,000 which 80% is for inventory production and 20% for sg&a work in process completed: 70% finish goods that is sold: 90% as of december 31, 20xx how much raw materials are left in the balance sheet as of december 31, 20xx how much work-in-process inventory is left in the balance sheet as of december 31, 20xx how much finished goods are left in the balance sheet
As of December 31, 20XX, the balance sheet shows that the ending balance of raw materials is $76,000, the ending balance of work-in-process inventory is $52,600, and the ending balance of finished goods is $52,600.
In order to solve this problem, we need to follow a few steps. The steps are as follows:
1. Calculate the raw material transferred to work in process by multiplying the raw material purchases with the percentage transferred to the work in process.
2. Calculate the cost of goods manufactured (COGM) by adding the costs of raw material transferred to the work in process, direct labor, and overhead, and then subtracting the total depreciation.
3. Calculate the cost of goods sold (COGS) by multiplying the cost of goods manufactured with the percentage of finished goods that is sold.
4. Calculate the ending balance of raw materials by subtracting the COGM from the sum of raw material purchases and the beginning balance of raw materials.
5. Calculate the ending balance of work-in-process inventory by subtracting the COGS from the COGM.
6. Calculate the ending balance of finished goods by subtracting the COGS from the sum of the beginning balance of finished goods and the cost of goods manufactured.
Now, let's use the above method to solve the given problem.
Balance sheet for raw material purchases, transferred to work in process, direct labor, overhead, total depreciation, inventory production, and SG&A are given.
- Raw material purchases: $100,000
- Percentage of raw material purchases transferred to work in process: 50%
- Direct labor: $200,000
- Overhead: $300,000
- Total depreciation: $30,000, of which 80% is for inventory production and 20% for SG&A
- Work in process completed: 70%
- Finished goods that is sold: 90%
As of December 31, 20XX, we need to calculate how much raw materials are left on the balance sheet, how much work-in-process inventory is left on the balance sheet, and how much finished goods are left on the balance sheet. The problem is solved below.
1. Calculate the raw material transferred to work in process:
Raw material transferred to work in process = 50% of $100,000
= 0.50 × $100,000
= $50,000
2. Calculate the cost of goods manufactured (COGM):
Raw material purchases transferred to work in process = $50,000
Direct labor = $200,000
Overhead = $300,000
Total depreciation = $30,000, of which 80% is for inventory production and 20% for SG&A
COGM = ($50,000 + $200,000 + $300,000) - (80% × $30,000)
= $50,000 + $200,000 + $300,000 - $24,000
= $526,000
3. Calculate the cost of goods sold (COGS):
COGS = 90% × $526,000
= 0.90 × $526,000
= $473,400
4. Calculate the ending balance of raw materials:
Beginning balance of raw materials = $0
Raw material purchases = $100,000
Raw material transferred to work in process = $50,000
COGM = $526,000
Ending balance of raw materials = ($100,000 + $0) - $526,000 + $50,000
= $76,000
5. Calculate the ending balance of work-in-process inventory:
Beginning balance of work-in-process inventory = $0
COGM = $526,000
COGS = $473,400
Ending balance of work-in-process inventory = $526,000 - $473,400 + $0
= $52,600
6. Calculate the ending balance of finished goods:
Beginning balance of finished goods = $0
COGM = $526,000
COGS = $473,400
Ending balance of finished goods = ($0 + $526,000) - $473,400
= $52,600
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problem 5 (30 points, each 10 points). in a chemical plant, 24 holding tanks are used for final product storage. four tanks are selected at random and without replacement. suppose that four of the tanks contain material in which the viscosity exceeds the customer requirements. 1. what is the probability that exactly one tank in the sample contains high-viscosity material? 2. what is the probability that at least one tank in the sample contains high-viscosity material? 3. in addition to the four tanks with high-viscosity levels, four different tanks contain material with high impurities. what is the probability that exactly one tank in the sample contains high-viscosity material and exactly one tank in the sample contains material with high impurities?
1. The probability of selecting exactly one tank with high-viscosity material is 0.
2. The probability of selecting at least one tank with high-viscosity material is 1.
3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is 0.25.
1. The probability of selecting exactly one tank with high-viscosity material is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 4, x = 1, and p = 24/24 = 1. Therefore, P(X = 1) = (4C1)1^1(1-1)^4-1 = 0.
2. The probability of selecting at least one tank with high-viscosity material is calculated by the complement rule, P(X > 0) = 1 - P(X = 0). In this case, P(X > 0) = 1 - (4C0)1^0(1-1)^4-0 = 1.
3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 8, x = 2, and p = 24/24 = 1. Therefore, P(X = 2) = (8C2)1^2(1-1)^8-2 = 0.25.
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The dimensions of length 48 inches by width 48 inches by height 84 inches. One Angel Soft MEGA roll has diameter 5 inches, height 4 inches.
What is the volume of the closet space?
What is the volume of one roll of toilet paper?
Use 3.14 for π and round to the nearest whole number
How many rolls of Angel Soft MEGA toilet paper can be fit into the closet space?
2467 rolls of Angel Soft MEGA toilet paper can fit into the Closet space.
The volume of the closet space, we multiply the length, width, and height of the closet. Given that the dimensions of the closet are:
Length = 48 inches
Width = 48 inches
Height = 84 inches
Volume of the closet = Length * Width * Height
Volume = 48 * 48 * 84 = 193,536 cubic inches
The volume of the closet space is 193,536 cubic inches.
To calculate the volume of one roll of toilet paper, we use the formula for the volume of a cylinder. Given that the diameter of the roll is 5 inches and the height is 4 inches, the formula for the volume of a cylinder is:
Volume = π * (radius)^2 * height
The radius of the roll is half the diameter, so the radius is 5/2 = 2.5 inches.
Volume of one roll = 3.14 * (2.5)^2 * 4 = 78.5 cubic inches
The volume of one roll of Angel Soft MEGA toilet paper is 78.5 cubic inches.
the number of rolls that can fit into the closet space, we divide the volume of the closet space by the volume of one roll.
Number of rolls = Volume of closet space / Volume of one roll
Number of rolls = 193,536 / 78.5
Number of rolls ≈ 2467
2467 rolls of Angel Soft MEGA toilet paper can fit into the given closet space.
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Find the missing number so that the equation has infinitely many solutions.
– 2x+18=blank x+18
The missing term in the equation is n = -2
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the equation be represented as A
Now , the value of A is
Substituting the values in the equation , we get
Let the missing term be represented as n
-2x + 18 = nx + 18
Subtracting 18 on both sides of the equation , we get
-2x = nx
Divide by x on both sides of the equation , we get
n = -2
Therefore , the missing term is n = -2
Hence , the equation is n = -2
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9. Janice was creating goodie bags for her party. She has 24 lollipops and 36
pieces of gum. After she bagged the candy, there was the same amount of
contents in each bag. What is the greatest number of bags she can create
with no pieces of candy left over?
Answer:
6
Step-by-step explanation:
24/6 = 4
36/6 = 6
6 bags, 4 lollipops and 6 pieces of gum in each bag.
Answer:
12 bags
Step-by-step explanation:
You would need to find the GCF of both numbers: 12
24*12 = 2
38*12 = 4
12 bags with 2 lollipops and 4 pieces of gum in each
Solve the given differential equation by variation of parameters. x2y'' + xy' − y = ln x
y (x) = ?
The solution to the given differential equation, x²y'' + xy' - y = ln(x), using variation of parameters is: y(x) = C₁x + C₂x ln(x) + x ln²(x)/2,
where C₁ and C₂ are constants.
Determine the differential equation?To solve the differential equation using variation of parameters, we first find the solutions to the homogeneous equation x²y'' + xy' - y = 0. Let's denote these solutions as y₁(x) and y₂(x).
Next, we find the Wronskian W(x) = y₁(x)y₂'(x) - y₁'(x)y₂(x) and calculate the integrating factors u₁(x) = -∫(y₂(x)ln(x))/W(x) dx and u₂(x) = ∫(y₁(x)ln(x))/W(x) dx.
Using these integrating factors, we can determine the particular solution yₚ(x) = -y₁(x)∫(y₂(x)ln(x))/W(x) dx + y₂(x)∫(y₁(x)ln(x))/W(x) dx.
Finally, the general solution is given by y(x) = yₕ(x) + yₚ(x), where yₕ(x) is the general solution to the homogeneous equation.
Solving the homogeneous equation x²y'' + xy' - y = 0 gives the solutions y₁(x) = x and y₂(x) = x ln(x).
After calculating the Wronskian W(x) = x² ln(x), we obtain the integrating factors u₁(x) = -ln(x)/2 and u₂(x) = -x/2.
Plugging these values into the particular solution formula, we find yₚ(x) = C₁x + C₂x ln(x) + x ln²(x)/2.
Hence, the general solution is y(x) = C₁x + C₂x ln(x) + x ln²(x)/2, where C₁ and C₂ are arbitrary constants.
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the mayor of a city randomly chooses 4 of the 20 wards in her city and surveys all the voters in those selected wards.
The sample space is 4845.Therefore, option C is correct.
Given: The mayor of a city randomly chooses 4 of the 20 wards in her city and surveys all the voters in those selected wards.
Solution: We have a sample size of 4 wards out of a total of 20 wards. The mayor has chosen all the voters in those 4 wards. So, the sampling method used here is stratified sampling as the mayor chose the voters of specific 4 wards.
Sample space = Total number of ways to select 4 wards out of 20 wards= C(20,4) = 20!/(4!(20 - 4)!) = 4845
Hence, the sample space is 4845.Therefore, option C is correct.
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how to solve x+23.4=40.7
Answer:
\(x=17.3\)
Step-by-step explanation:
Given the following question:
\(x+23.4=40.7\)
To solve, we need to understand that this is a simple one-step equation and all we have to do to find the answer is subtract 23.4 on both sides.
\(x+23.4=40.7\)
\(23.4-23.4=0\)
\(40.7-23.4=17.3\)
\(x=17.3\)
Hope this helps.
you will build a rectangular sheep pen next to a river. there is no need to build a fence along the river, so you only need to build three sides. you have a total of 420 feet of fence to use. find the dimensions of the pen such that you can enclose the maximum area.
The dimensions of the pens enclosing the largest area are 105 feet x 210 feet.
Let 'w' be the width of the pen and 'l' be the length of the pen (perpendicular to the river). We know there is a 420-foot fence that can be used to build the 3 sides of the enclosure.
2w + l = 420
Maximize the area of the pen given by the formula:
A = lw
You can solve l in terms of w using the equation 2w + l = 420.
l = 420 - 2w
Substituting this formula for l gives:
\(A = w(420 - 2w) = -2w^2 + 420w\)
To find the maximum area, take the derivative of A with respect to w and set it to 0.
dA/dw = -4w + 420 = 0
Solving for w gives:
w = 105
Substituting this value of w into the formula for l yields:
l = 420 - 2w = 210
Therefore, the dimensions of the pens enclosing the largest area are 105 feet x 210 feet.
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does anyone know how to do this by solving with substitution
Answer:
Step-by-step explanation:
Question 1
System of equations is,
y = -6x -------(1)
y = -4x - 2 ---------(2)
Substitute the value of y from equation (1) to equation (2)
-6x = -4x - 2
-6x + 4x = -2
-2x = -2
x = 1
From equation (1)
y = -6(1)
y = -6
Question (2)
System of equations is,
-y = x --------(1)
3x + 5y = 20 ---------(2)
Substitute the value of x from equation (1) to equation (2)
3(-y) + 5y = 20
-3y + 5y = 20
2y = 20
y = 10
From equation (1)
-y = x
x = -10
Question (3)
System of the equations is,
y = -2x - 7 --------(1)
9x - 10y = 12 ----------(2)
Substitute the value of y from equation (1) to equation (2)
9x - 10(-2x - 7) = 12
9x + 20x + 70 = 12
29x = 12 - 70
29x = -58
x = -2
From equation (1)
y = -2(-2) - 7
y = 4 - 7
y = -3
2.5.1 Characterization Theorem
If S is a subset of R that contains at least two points and has the property
(1)
if x, y ES and
then S is an interval.
Proof. There are four cases to consider: (i) S is bounded, (ii) S is bounded above but not below, (iii) S is bounded below but not above, and (iv) S is neither bounded above nor below.
Case (i): Let a = inf S and b = sup S. Then SC[a, b] and we will show that (a, b)C S.
If a < z
Now if a S and b S, then S =[a, b]. (Why?) If a S and b S, then S=(a, b). The other possibilities lead to either S = (a, b) or S = [a, b).
Case (ii): Let b = sup S. Then SC (-[infinity]o, b] and we will show that (-oo, b)C S. For, if z
Cases (iii) and (iv) are left as exercises.
Cases (iii) and (iv) are left as exercises, meaning the proof for those cases is not provided in the given information. To fully establish the Characterization Theorem, the proof for these remaining cases needs to be completed.
Theorem 2.5.1 (Characterization Theorem):
If S is a subset of R that contains at least two points and has the property that if x, y ES and x < y, then (x, y)C S, then S is an interval.Proof.
There are four cases to consider:
(i) S is bounded,
(ii) S is bounded above but not below,
(iii) S is bounded below but not above, and
(iv) S is neither bounded above nor below.
Case (i): Let a = inf S and b = sup S.
Then SC[a, b] and we will show that (a, b)C S. If a < z < b, then there exist x, y
ES such that x < z < y. Since x < y and S has property (1), we have (x, y)C S.
Since zEP(x, y), it follows that zES.
Thus (a, b)C S.
Now if a S and b S, then S =[a, b].
If a S and b S, then S=(a, b).
The other possibilities lead to either S = (a, b) or S = [a, b].
Case (ii): Let b = sup S.
Then SC (-[infinity]o, b] and we will show that (-oo, b)C S. For, if z < b, then there exists y
ES such that z < y < b.
Since b is the least upper bound of S and yES, it follows that y 6S. But then (z, y)C (-oo, b) and (z, y)C S.
Thus (-oo, b)C S. Now if S contains its smallest element a, then S = [a, b]. Otherwise, S=(a, b).
Cases (iii) and (iv) are left as exercises.
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scores on an iq test are normally distributed. the test is designed so that the mean is 100 and standard deviation is 15. (a) what percentage of the population has an iq above 120?
From the normal distribution it is calculated that 9.18% of people has an iq over 120.
Normal distributions are crucial to statistics because they are widely used in the natural and social sciences to represent real-valued regressors with unknown distributions.
Some of their significance can be attributed to the central limit theory. This claim states that, in some cases, the average of many samples (observations) of a stochastic process with limited mean and variance constitutes itself as a random variable, whose distribution merges to a normal distribution as the number of samples increases.Because of this, the distributions of physical values, such as error margins, which are expected to be the sum of many independent events, are frequently near to normal.We have to find P( X > 120 )
Thus find z score for x =120
\(z=\frac{x-\mu}{\sigma}=\frac{120-100}{15}=\frac{20}{15}=1.33\)
Thus we get:
P(X>120) = P(Z>1.33)
P(X>120) = 1 - P(Z<1.33)
P( Z < 2.67) = 0.9082
Thus
P(X>140) = 1 - P(Z<2.67)
P(X>140) = 1 - 0.9082
P(X>140) = 0.0918
Percentage = 9.18%
Therefore 9.18% of people has an iq over 120.
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help me please , for 20 points
Answer:
A
Step-by-step explanation:
First off we can see that there are 46 pencils - and 7 students - so we can divide the two
46/7 is not a whole number, so we need to find a number that can be multiplied by 7, and is right below 46.
If you multiply 7 by 6, you get 42, which is the highest you can get with multiply by 7, which is also below 46.
Now that we know that each student gets 6 pencils, we need to find out how many are left.
We can do 46 (total pencils) minus 42 (pencils given) to get a leftover of 4 pencils, so the answer is A.
In ΔDEF, the measure of ∠F=90°, EF = 2. 3 feet, and FD = 2. 9 feet. Find the measure of ∠D to the nearest tenth of a degree
In ΔDEF, the measure of angle D = 38.4°
Here in triangle DEF the measure of angle F = 90°
This means that ΔDEF is a right triangle and DE is the hypotenuse.
We need to find the measure of angle D.
Consider the tangent of angle D.
tan(D) = opposite side/ adjacent side
tan(D) = EF / FD
Here, EF = 2.3 feet, and FD = 2.9 feet.
So above equation becomes,
tan(D) = 2.3 / 2.9
tan(D) = 0.79310
D = arctan(0.7931)
D = 38.42°
Therefore, the measure of ∠D = 38.4°
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find the unit rate, it’s easy :)
Answer:
Step-by-step explanation:
The graphs of linear functions f ans g are shown on the grid
sketch the curve with the given polar equation. θ = −π/6
We can use the polar equation r = f(θ) to sketch the curve. However, since you have only provided the value of θ as −π/6, we cannot determine the shape of the curve without knowing the equation of the function f(θ).
In order to sketch the curve, we need to plot at least three points on the polar coordinate plane. We can do this by selecting three different values of θ, plugging them into the polar equation, and finding the corresponding values of r. We can then plot these points and connect them to form the curve.
Answer:
1. First, recall that in polar coordinates, a point is represented by (r, θ), where r is the distance from the origin, and θ is the angle measured counter-clockwise from the positive x-axis.
2. In this case, the polar equation is given as θ = -π/6, which means the angle is fixed at -π/6 radians, or -30 degrees.
3. Since r can take any value, this curve is a straight line consisting of all points that are located at a -30-degree angle from the positive x-axis. To visualize this, imagine a ray starting at the origin and rotating -30 degrees in the clockwise direction.
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Parallelogram MATH has side lengths as follows: MA = 20 and AT = 24. Determine the side length of TH:
Answer: 20
Step-by-step explanation: Opposite sides of a parallelogram are congruent
what is the solution of y= -1/3x+5 and 2x-3y=3??
Answer:
1. x = 15
2. y = 2/3x - 1
Step-by-step explanation:
help please quickly and thank you
Answer:
the first one is correct and the second one is where you set them equal to 180 and slove for x and the third one is you set that equal to 180.
Step-by-step explanation:
21) Natalie kicked a soccer ball. The equation ℎ=−162+50 describes the height of the ball t seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?
To find the time until the ball hits the ground, you need to solve the quadratic as the height equals zero.
0 = -16t^2+50t
This gives us a classing quadratic that you can factor or use the quadratic formula to solve.
x = 0, x = 25/8
If you graph this, think of y = 0 as the ground, so when the parabola intersects the x-axis on the right that represents how much time would have passed.
Hope this helps you out! Good luck with your homework! Stay safe and stay healthy.
Combine the like terms to create an equivalent expression.
7+4c+2d+3
Answer:
4c+2d+10
Step-by-step explanation:
7+4c+2d+3
4c+2d+(3+7)
4c+2d+10
Answer: 4c+2d+10
Step-by-step explanation:
At James Middle School, there are 480 students enrolled in
algebra. The chart shows the grade distribution for one algebra class.
Assume that a medical research study found a correlation of -0.73 between consumption of vitamin A and the cancer rate of a particular type of cancer. This could be interpreted to mean:
a. the more vitamin A consumed, the lower a person's chances are of getting this type of cancer
b. the more vitamin A consumed, the higher a person's chances are of getting this type of cancer
c. vitamin A causes this type of cancer
The negative correlation coefficient of -0.73 between consumption of vitamin A and the cancer rate of a particular type of cancer suggests that as vitamin A consumption increases, the cancer rate tends to decrease.
A correlation coefficient measures the strength and direction of the linear relationship between two variables.
In this case, a correlation coefficient of -0.73 indicates a negative correlation between consumption of vitamin A and the cancer rate.
Interpreting this correlation, it can be inferred that there is an inverse relationship between the two variables. As consumption of vitamin A increases, the cancer rate tends to decrease.
However, it is important to note that correlation does not imply causation.
It would be incorrect to conclude that consuming more vitamin A causes this type of cancer. Correlation does not provide information about the direction of causality.
Other factors and confounding variables may be involved in the relationship between vitamin A consumption and cancer rate.
To establish a causal relationship, further research, such as experimental studies or controlled trials, would be necessary. These types of studies can help determine whether there is a causal link between vitamin A consumption and the occurrence of this particular cancer.
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