A painter starts with a blank 30 inch by 18 inch piece of rice paper. The painter wants to leave a uniform border x inches wide along the outer edges so that the painting can be framed. Write a polynomial in standard form that represents the area of paper that can be painted

A "required parameter" requires an assigned value for the argument used to call the method, while "optional parameters" do not need to be included in the method call and have a default value assigned to them.

The type of parameter that requires that the argument used to call the method must have an assigned value is a "required parameter".

Required parameters are parameters that must be included in the method call, and the argument passed for the required parameter must have a value assigned to it. If a required parameter is not included in the method call, or if the argument passed for the required parameter does not have a value assigned to it, an error will be thrown.

In contrast, there are also optional parameters, which are parameters that do not need to be included in the method call. If an optional parameter is not included in the method call, the method will use a default value assigned to the parameter.

In many programming languages, the syntax for specifying required and optional parameters in a method or function call is specified using different symbols, such as parentheses or square brackets.

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Answer:

D,  \(10i\sqrt{2}\)

Step-by-step explanation:

Separate -1, 2, and 100 from each other inside the radical. You can take out -1 as i, and 100 as 10. You now have 10i on the outside of the radical and 2 on the inside. Hope this helps.

Answer:

the answer is D.

!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

32.

Step-by-step explanation:

True. A basis of R4 consists of linearly independent vectors that span the entire space R4. Since R4 is a 4-dimensional space, any basis of R4 will contain 4 vectors.

In the vector space R4, the basis is a set of vectors that span the entire space and are linearly independent. Since R4 is a 4-dimensional space, any basis of R4 must contain exactly 4 vectors. This is because 4 linearly independent vectors are required to span all possible combinations of the 4 dimensions in R4.

Therefore, any basis of R4 will consist of 4 elements.

In mathematics, a basis is a set of linearly independent vectors that can be used to represent any vector in a given vector space. The vector space R^4, also known as R4, represents a four-dimensional space. To form a basis for R4, we need a set of vectors that are linearly independent and can span the entire four-dimensional space.

Since R4 is a four-dimensional space, any basis of R4 will contain exactly four vectors. This is because the dimension of a vector space is defined as the maximum number of linearly independent vectors it contains. In the case of R4, the dimension is four, so we need four linearly independent vectors to form a basis that spans the entire space.

By having a basis of four linearly independent vectors, any vector in R4 can be represented as a unique linear combination of those basis vectors. These basis vectors serve as a coordinate system that allows us to describe any point in R4.

It's worth noting that there are infinitely many possible choices for a basis in R4 since there are infinitely many sets of four linearly independent vectors that can span the space.

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The area of the quadrilateral is 176.6 square meters, rounded to one decimal place.

Triangle ABC is approximately 14.1 meters tall.

Triangle ACD is roughly 2.6 meters tall.

We can now calculate the area of triangle ACD:

Area(ACD) = (1/2) * AD * height Area(ACD) = (1/2) * 7.8 * 2.6 Area(ACD) = (1/2) * 7.8 * 2.6

Finally, we may sum the areas of the two triangles to get the quadrilateral's area:

Area(quadrilateral) equals Area(ABC) + Area(ACD).

166.5 + 10.1 = 176.6

The area of the quadrilateral is roughly 176.6 square meters, rounded to one decimal place.

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Answer:

$35.00

Step-by-step explanation:

Add the exacted prices of the five books together.

5.99 + 6.00 + 6.45 + 7.75 + 7.99 = 34.18

The number closest to 34.18 on the list of choices is 35.00.

Have a nice day :)

The chance that at least one of the suits doesn't appear is approximately 0.304 or 30.4%.

(13/52) * (13/51) * (13/50) * (13/49) * (13/48)

1 - (13/52) * (13/51) * (13/50) * (13/49) * (13/48)

1 - (13/52) * (1 - 1/51) * (1 - 2/50) * (1 - 3/49) * (1 - 4/48)

= 1 - (13/52) * (50/51) * (48/50) * (46/49) * (44/48)

= 1 - 0.696

= 0.304

Therefore, the chance that at least one of the suits doesn't appear is approximately 0.304 or 30.4%.

The approach I used to solve the problem of finding the chance that at least one of the suits doesn't appear is a common one that can be used to solve many similar problems in probability theory. Specifically, we can use the complement rule, which states that the probability of an event occurring is equal to 1 minus the probability of the event not occurring.

This approach can be applied to many problems in probability theory, but it may not always be the most efficient or straightforward method. The choice of method will depend on the specific problem and the information provided. Other common methods include using combinations and permutations, conditional probability, and Bayes' theorem.

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Answer:

y = -0.2x + 4.6

Step-by-step explanation:

We can set up a point-slope form to calculate for the equation:

y - y1 = m (x - x1)

Before we plug the coordinate into the formula, we need m, the slope of L, we know that L is perpendicular to the straight line, and the slope of the straight line is 5:

Perpendicular slope form is: opposite reciprocal of m, which is:

-1/5 or -0.2

Now we plug all the numbers into the previous equation:

y - 5 = -0.2 (x + 2)

y = -0.2 (x + 2) + 5

y = -0.2x + -0.4 + 5

y = -0.2x + 4.6

Now this is a slope-intercept form.

Answer:

\(h = \frac{4}{n}\)

Step-by-step explanation:

Isolate the variable by dividing each side by factors that do not contain the variable.

Hence, you get the following answer:

\(h = \frac{4}{n}\)

Basically, we are given the diagonal of the square to be 13.5 feet. We need to find the side length of the square.

The formula that relates diagonal and side length of a square is:

Where

d is the diagonal

s is the side length

We substitute and find our answer:

The side length is about 9.5 feet

Answer choice B

Answer:

it would be -4<x< inf which is B

The expected value of the sum of the 100 pledges is 0.33 x ($10 + $50 + $100) x 100 = $5,000.

The expected value of the sum of the 100 pledges is $5,000. This can be calculated using the standard deviation of the three amounts $10, $50 and $100, which is $37. We can calculate the expected value of each pledge by multiplying the value of each pledge by its probability. For example, the expected value of a $10 pledge is 0.33 x $10 = $3.30. We can do the same for the $50 and $100 pledges. Thus, the expected value of the sum of the 100 pledges is 0.33 x ($10 + $50 + $100) x 100 = $5,000.

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Answer:

https://corbettmaths.files.wordpress.com/2015/03/functions-answers.pdf

Step-by-step explanation:

Sorry if this is not right

The PDF of W = X², if X has an exponential distribution with parameter λ, is equal to fW(w) = (1/2)λ√w × \(e^{(-\lambda \sqrt{w} )}\) for w ≥ 0 and fW(w) = 0 for w < 0.

To find the probability density function (PDF) of the random variable W = X² when X has an exponential distribution with parameter λ,

Apply a transformation to the original PDF.

Let us denote the PDF of X as fX(x) and the PDF of W as fW(w). We want to find fW(w).

To begin, let us express W in terms of X,

W = X²

Now, find the PDF of W, which is the derivative of the cumulative distribution function (CDF) of W.

So, find the CDF of W first.

The CDF of W is ,

FW(w) = P(W ≤ w)

Substituting W = X², we have,

FW(w) = P(X² ≤ w)

To determine the probability of X² being less than or equal to w,

consider that X can take on both positive and negative values.

So,  split the calculation into two cases,

First case,

X ≥ 0

In this case, X² ≤ w implies X ≤ √w, since X is non-negative.

Thus, we have,

FW(w) = P(X² ≤ w) = P(X ≤ √w)

Since X has an exponential distribution, its CDF is given by,

FX(x) = 1 -\(e^{(-\lambda x)}\)  for x ≥ 0

for the case X ≥ 0, we have,

FW(w) = P(X ≤ √w) = FX(√w) = 1 -\(e^{(-\lambda \sqrt{w} )}\)

Second case,

X < 0

X² ≤ w implies X ≤ -√w, since X is negative.

However, for X < 0, X² is always non-negative.

The probability is always 0 in this case.

Combining both cases, we can write the CDF of W as,

FW(w) = 1 - \(e^{(-\lambda \sqrt{w} )}\) for w ≥ 0

FW(w) = 0 for w < 0

Finally, to find the PDF fW(w), we take the derivative of the CDF with respect to w,

fW(w) = d/dw [FW(w)]

Differentiating, we have,

fW(w) = (1/2)λ√w × \(e^{(-\lambda \sqrt{w} )}\) for w ≥ 0

fW(w) = 0 for w < 0

Therefore, the PDF of W = X², when X has an exponential distribution with parameter λ, is given by,

fW(w) = (1/2)λ√w × \(e^{(-\lambda \sqrt{w} )}\) for w ≥ 0

fW(w) = 0 for w < 0

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The above question is incomplete, the complete question is:

If X has an exponential (λ) PDF, what is the PDF of W = X² ?

Using visual interpretation of the plot trend, the scatter plot shows positive correlation.

A positive correlation is depicted by a positive slope or trend line on a scatter plot. The trend of the scatter plot slopes upward which establishes a positive association.

If the slope is otherwise negative, such that the trend line slopes downward, then we have a negative association or relationship.

Therefore, the scatter plot shows positive relationship.

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Answer:

a=2/5

Step-by-step explanation:

1.7((2)/(5))+0.3((2)/(5)) = 0.8=80/100=4/5

Answer:

the answer is a=2/5

Step-by-step explanation:

combine like terms 1.7+0.3=2

get the varliable alone 2/4/5

answer 2/5

The probability offered both jobs is 0.204,offered neither of the two jobs is 0.060,at least one job is 0.976,offered the first job not the second job is 0.136,offered the first job but will be offered the second job is 0.204.

To find the probability that Jennifer will be offered both jobs, we multiply the probabilities of being offered each job since the two job offers are independent. Therefore, 0.340 * 0.600 = 0.204.

The probability that Jennifer will be offered neither of the two jobs is calculated by subtracting the probability of being offered at least one job from 1. Since being offered at least one job is the complement of being offered neither, the probability is 1 - 0.976 = 0.024.

The probability that Jennifer will be offered at least one of the two jobs is found by summing the probabilities of being offered each job and subtracting the probability of being offered neither. Therefore, 0.340 + 0.600 - 0.024 = 0.976.

The probability that Jennifer will be offered the first job but not the second job is obtained by subtracting the probability of being offered both jobs from the probability of being offered the first job. Thus, 0.340 - 0.204 = 0.136.

The probability that Jennifer will not be offered the first job but will be offered the second job is equal to the probability of being offered the second job but not both jobs. Since the two job offers are independent, this probability is the same as the probability of being offered both jobs, which is 0.204.

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Answer:

26

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

6 +6=12

12+3=15

15+2=17

17+4=21

Answer:

It is the distribution of the statistic if we were to draw all possible samples of a given size from the population and calculate the statistic for each sample.

Step-by-step explanation:

The sampling distribution of a statistic refers to the range of all possible sample values of the statistic that could be drawn from the parent population under the specified sampling plan.

In other words, it is the distribution of the statistic if we were to draw all possible samples of a given size from the population and calculate the statistic for each sample.

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Answer:

  cos(x) -csc(x)

Step-by-step explanation:

It is helpful to know the relations between the trig functions:

  \(\cot{x}=\dfrac{\cos{x}}{\sin{x}}\\\\\sec{x}=\dfrac{1}{\cos{x}}\\\\\csc{x}=\dfrac{1}{\sin{x}}\)

__

Then the given expression can be simplified as follows:

  \(\cot{x}(\sin{x}-\sec{x})=\dfrac{\cos{x}}{\sin{x}}\left(\sin{x}-\dfrac{1}{\cos{x}}\right)=\cos{x}-\dfrac{1}{\sin{x}}\\\\=\boxed{\cos{x}-\csc{x}}\)

Answer:

17:55

Step-by-step explanation:

What time did the plane leave London City airport?

speed = distance/time

time = distance/speed

time = 256 miles / 192 mph

time = 1.333 hours = 1 1/3 hours = 1 hour 20 minutes

The plane flew for 1 hour and 20 minutes.

19:15 - 1:20 =

(Borrow 1 hour from 19 leaving 18. Convert the borrowed hour to 60 minutes and add to 15 minutes making it 75 minutes.)

= 18:75 - 1:20

= 17:55

Answer:

Step-by-step explanation:

Remark

a is one part of the cosine function. It is termed the adjacent side. The given number (12) is the hypotenuse of a right triangle. The reference angle is given as 25. You have all you need to solve for a

Givens

<B = 25o

AB = 12

a = a

Equation

Cos(B) = adjacent side / hypotenuse

Solution

Cos(25) = adjacent side / 12               Multiply both sides by 12

12*cos(25) = adjacent side

cos(25) = 0.90631

12*0.906331 = adjacent side

10.87 = adjacent side

Answer

a = 10.9

Answer:

AA, AD, AC, AB (or flipped)

BB, BD, BC, BA (or flipped)

CD, CA, CB, CC (or flipped)

DA, DC, DD, DB (or flipped)

Step-by-step explanation:

The average radius of the Crab Nebula in the year 2019 was 4.56 x 107 R_(sun).

As per the given question, the average velocity of the Crab Nebula is 1,500 km/s, and it has been expanding since the year 1054. We are supposed to find the average radius in the year 2019.

To find the average radius in the year 2019, we need to find out the time period between 1054 and 2019.

Time difference, t = 2019 - 1054= 965 years

Then we need to convert this time into seconds.

Since 1 year = 365 days and 1 day = 24 hours and 1 hour = 3600 seconds,965 years = 965 x 365 x 24 x 3600 seconds = 3.04 x 1010 seconds

Now we can use the formula:

v = d/t

Where v is velocity, d is distance, and t is time distance of the crab nebula is the radius of the crab nebula, and the time is 3.04 x 1010 seconds.

v = 1500 km/s

Let r be the average radius of the Crab Nebula in the year 2019.

r = v x t = 1500 km/s x 3.04 x 1010 seconds = 4.56 x 1013 km = 4.56 x 107 R_(sun)

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Approximately 21 pH values would have to be included in each sample to estimate the difference between the mean acidity for rainfalls at the two different locations to the nearest 0.2 pH, with probability near 0.90.

What is the standard error?

Standard error is a measure of the variability or uncertainty of a statistic. It is the standard deviation of the sampling distribution of a statistic, and it estimates how much the sample statistic may vary from the true population parameter due to random sampling error.

To estimate the difference between the mean acidity for rainfalls at two different locations, we can use the formula for the standard error of the difference between means:

\(SE = \sqrt{[(s1^2 / n1) + (s2^2 / n2)]}\)

where s1 and s2 are the sample standard deviations, n1 and n2 are the sample sizes, and SE is the standard error of the difference between means.

We want our estimate to be correct to the nearest 0.2 pH, with probability near 0.90. This means we want to find the sample size n that will give us a margin of error of 0.2 pH with a confidence level of 90%.

We can use the following formula to find the sample size:

\(n = [(z*\sigma / E)^2]\)

where z is the z-score for the desired confidence level (0.90), σ is the population standard deviation (0.35), and E is the margin of error (0.2).

First, we need to find the z-score for a 90% confidence level. This can be found using a standard normal distribution table or calculator. For a 90% confidence level, the z-score is approximately 1.645.

Substituting these values into the formula, we get:

n = [(1.645*0.35 / 0.2)^2]

= 20.95

Rounding up to the nearest whole number, we get a sample size of n = 21 for each sample.

Therefore, approximately 21 pH values would have to be included in each sample to estimate the difference between the mean acidity for rainfalls at the two different locations to the nearest 0.2 pH, with probability near 0.90.

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● 3x^2 - 10 = 0

Add 10 to both sides

● 3x^2 - 10 + 10 = 10

● 3x^2 = 10

Divide both sides by 3

● 3x^2/3 = 10/3

● x^2 = 10/3

● x = √( 10/3 ) or x = - √( 10/3 )

● √(10/3) + (-√(10/3)) = 0

● √(10/3) × -√(10/3) = -10/3