A paint can has a radius of 2.7 inches and a height of 9 inches. If the company wants to create a label to go around the can, how much paper will they need? Round to the nearest hundredth.

9 minutes is the new standard time for the navigator iii.

What is statistics and example?

If a process improvement has changed the mean observed time for element 6 to 1.50 minutes, then

Element            1    2            3         4             5          6  

Mean obs. Time(t) 1.11   3.1    0.895  1.283333 1.565 1.5  

Normal time       1.0545  1.395 0.93975 1.283333 1.33025 1.65   Sum

Standard time   1.240588 1.641176 1.105588  1.509804 1.565 1.941176

   Sum    9.003333

New standard time = 9 minutes

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The cube root function that tells the side lengths of the​ container, x, in inches for a given​ cost, C is x = (C^(1/3))^3.

We can use the formula for the volume of a cube, which is V = x^3, where x is the side length of the cube. If the cost of producing one cube-shaped container is C dollars, then the cost of producing one unit of volume is C/V = C/x^3 dollars per cubic inch. Solving for x, we get:

x = (C/V)^(1/3)

Substituting V = x^3, we get:

x = (C/x^3)^(1/3)

Simplifying, we get:

x = (C^(1/3)) / (x^(1/3))

Multiplying both sides by x^(1/3), we get:

x^(2/3) = C^(1/3)

Taking the cube of both sides, we finally get:

x = (C^(1/3))^3

Therefore, the cube root function for a given cost, C, is x = (C^(1/3))^3.

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All the solutions are,

⇒ LSA = 80.4π yards²

⇒ LSA = 321.6π yards²

⇒ V = 2786.2 yards³

⇒ SA = 186.5 inhces²

Now, We can simplify as;

1) Slant Height = 13.4 yards

Diameter = 12 yards

Hence, Radius = 6 yards

Since, Lateral surface area of cone is,

⇒ LSA = πrl

⇒ LSA = π × 6 × 13.4

⇒ LSA = 80.4π yards²

2) Slant Height = 26.8 yards

Hence, Radius = 12 yards

Since, Lateral surface area of cone is,

⇒ LSA = πrl

⇒ LSA = π × 12 × 26.8

⇒ LSA = 321.6π yards²

3) Height = 22 yards

Diameter = 22 yards

Hence, Radius = 11 yards

Since, Volume of cone is,

⇒ V = πr²h/3

⇒ V = π × 11² × 22 / 3

⇒ V = 2786.2 yards³

4) Surface area of pyramid is,

SA = (8 x 7) + 1/2 x (2 x (8 + 7) x 8.7

SA = 56 + 15 x 8.7

SA = 186.5 inhces²

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complete question:

attached

Work Shown:

n(A only) = number of items inside set A only

n(A only) = 12

n(A and B) = 16

n(B only) = 20

n(A or B) = n(A only) + n(A and B) + n(B only)

n(A or B) = 12 + 16 + 20

n(A or B) = 48

n(Total) = n(A only) + n(A and B) + n(B only) + n(Not A, not B)

n(Total) = 12+16+20+24

n(Total) = 72

P(A or B) = n(A or B)/n(Total)

P(A or B) = 48/72

P(A or B) = 0.67 approximately

Yes, this is right. theta is angle C.

In Euclidean geometry, an angle is made up of two rays that share a terminal and are referred to as the angle's sides and vertices, respectively. Angles can be formed by two rays in the plane where they are placed. Additionally, when two planes overlap, angles are created. Dihedral angles are what they are called. When two straight lines or rays intersect at a single point, an angle is created. The vertex of an angle is the location where two points converge.

Here, angle is formed at C, A and B, but here B is 90 and the angle sign is given at C.

So, theta is angle C.

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Answer:

7x+8y=32 is the standard form

Answer:

7x + 8y = 32

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C  are integers )

Given

y = - \(\frac{7x}{8}\) + 4 ( multiply through by 8 to clear the fraction )

8y = - 7x + 32 ( add 7x to both sides )

7x + 8y = 32 ← in standard form

Step-by-step explanation:

D.

subtracting the smallest value of the lower half of the data set from the biggest value of the lowest half of the data set

The lower quartile of a set of data is calculated by subtracting the smallest value of the lower half of the data set from the biggest value of the lowest half of the data set.

"A quartile is a statistical term that describes a division of observations into four defined intervals based on the values of the data and how they compare to the entire set of observations.

Just like the median divides the data into half so that 50% of the measurement lies below the median and 50% lies above it, the quartile breaks down the data into quarters so that 25% of the measurements are less than the lower quartile, 50% are less than the median, and 75% are less than the upper quartile."

From the definition it is clear that,

lower quartile of a set of data is calculated by :

subtracting the smallest value of the lower half of the data set from the biggest value of the lowest half of the data set.

Hence, D is the correct option.

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A 40 gram sample of a substance that’s used for drug research has a k-value of 0.1472. The substance's half-life, in days, is approximately 4.7 days.

The half-life of a substance is the time it takes for half of the substance to decay or undergo a transformation. The half-life can be determined using the formula:

t = (0.693 / k)

where t is the half-life and k is the decay constant.

In this case, we are given that the sample has a k-value of 0.1472. We can use this value to calculate the half-life.

t = (0.693 / 0.1472) ≈ 4.7 days

Therefore, the substance's half-life, rounded to the nearest tenth, is approximately 4.7 days.

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128 is the answer.

Explanation: If only 2 sprouted out of 10, that would mean only 20% sprouts on average, so you just divide 640 by 20%, otherwise expressed as 640/20%. The quotient is 128, which is therefore the answer.

Please mark me as brainiest. Wasn't very hard but I would appreciate it!

128 is da answer!!! Hope I helped

–8 + 4(c–9) –5 + 6c + 2c

= –8 + 4c – 36 – 5 + 6c + 2c

= 4c + 6c + 2c – 8 –35 –5

= 12c – 49

The probability that the flight would be delayed when it is raining = 0.79

Given that

the probability that it will rain is 0. 15

the probability that the flight will be delayed is 0. 11.

the probability that it will not rain and the flight will leave on time is 0. 75.

from the above

we can say that

the probability that the flight would be delayed when it is raining = 0.15 + 0.75 - 0.11

= 0.9- 0.11

= 0.79

The probability that the flight would be delayed when it is raining = 0.79

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Answer:

  θ = {π/6, 5π/6} +2kπ . . . . for any integer k

Step-by-step explanation:

Multiplying by the product of the denominators, we can simplify this to ...

  sin(θ)² +(1+cos(θ))² = 4sin(θ)(1+cos(θ))

  sin(θ)² +1 +2cos(θ) +cos(θ)² = 4sin(θ)+4sin(θ)cos(θ)

  2 +2cos(θ) = 2sin(θ)(2 +2cos(θ)) . . . . show similar factors

  2(2sin(θ) -1)(1 +cos(θ)) = 0 . . . . subtract left side, complete the factoring

These factors are zero when ...

  2sin(θ) -1 = 0   ⇒   sin(θ) = 1/2   ⇒   θ = π/6, 5π/6

  1 +cos(θ) = 0 . . . . . extraneous solution; makes equation undefined

__

Solutions are periodic with period 2π, so the complete solution set is ...

 θ = {π/6, 5π/6} +2kπ . . . . for any integer k

Answer:

x=2

Step-by-step explanation:

3x+4=10

subtract four on both sides, you will get 3x=6, divide by three on both sides, x=2

The required volume of the given sphere is 904.32 cm³.

A sphere is a geometrical object that resembles a two-dimensional circle in three dimensions.

In three-dimensional space, a sphere is a collection of points that are all located at the same distance from a single point.

The radius of the sphere is denoted by the letter r, and the specified point represents its center.

All of the points on a circle are equally spaced apart from the center along a plane, but all of the points on a sphere are equally spaced apart from the center along any of the axes.

So, we must ascertain the sphere's volume. With a radius of 6 cm, we have:

V = 4/3 π r^3

V = 4/3 x 3.14 x 6^3

V = 4/3 x 3.14 x 216

V = 904.32  

Therefore, the required volume of the given sphere is 904.32 cm³.

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Complete question:

Find the volume of the sphere.

Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and round your final answer to the nearest hundredth.

Answer:

-1

Step-by-step explanation:

Using rise over run for the two points

4 - 0/ -1 - 3 = -1

Answer:

We found 2 coordinates

1. ( 0 ,3)

2.(3,0)

Now slope = tan theta = 3/3 = 1

Answer is 1

Mark it as brainlist answer

Step-by-step explanation:

The absolute value difference between the distance from Roger's home and Sue's house is 14 miles.

The absolute value difference refers to the distance of two numeric values stated in absolute terms with regard to whether the result is positive or negative.

On a number line, the absolute value difference is the distance between 2 numbers calculated using the formula x - y.

Let the mall be at Point 0.

Distance from Point 0 to Roger's home = x

Distance from Roger's to Sue's home = y

Distance from Point 0 to Roger's home = 8 miles due east

Distance from Point 0 to Sue's home = 6 miles due west

The absolute value difference from Point 0 to Roger's = 8

The absolute value difference from Roger's to Sue's = -6

The total absolute value difference between Roger's and Sue's = 14 (8 - -6).

Thus, we can absolutely conclude that Roger and Sue live 14 miles apart.

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When the pile is 22 feet high, the height of the pile changes to 20/1089π.

Given (dV)/(dt) = 20, h = 22 feet , dh /dt =?

The volume of cone is V = 1/3 * pi * r ^ 2 * h

d=3h

2r = 3h

r = (3h)/2

V = 1/3 * pi * r ^ 2 * h

= 1/3 * pi * ((3h)/2) ^ 2 * h

= 1/3 * pi((9 * H ^ 2 )/4) * h

= (9pi)/12 * h ^ 3

Differentiate w.r.to t

(dV)/(dt) = (3pi)/4 * (3h * h^ 2) * (dh)/(dt)

(dV)/(dt) = (9pi)/4 * (h ^ 2) * (dh)/(dt)

(dV)/(dt)=20, h=22 feet

20 = (9pi)/4 * (22 ^ 2) * (dh)/(dt)

(dh)/(dt) = 80/ (9pi * (22^ 2))

h^ t = 20/ 1089 *pi   ft / min

Therefore, The height of the pile changing when the pile is 22 feet high is 20/1089π

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We are given a piecewise-defined function g and are required to find g(−2), g(0), and g(5).The:g(−2)= −1/3, g(0)= 1, and g(5)= −3/14.:We will find g(−2), g(0), and g(5) one by one,Let us begin with g(−2):

According to the given function,

When x ≤ −2,g(x) = 2When x = −2,g(x) = undefined

When −2 < x < 1,g(x) = 1 / (x − 1)2When x = 1,g(x) = undefined

When 1 < x < 2,g(x) = 1 / (x − 1)2When x ≥ 2,g(x) = −2 / (x + 2)For g(−2),

we use the function value when x ≤ −2,So g(−2) = 2 / 1 = 2

Now, we calculate g(0):When x ≤ −2,g(x) = 2

When −2 < x < 1,g(x) = 1 / (x − 1)2When x = 1,g(x) = undefined

When 1 < x < 2,g(x) = 1 / (x − 1)2

When x ≥ 2,g(x) = −2 / (x + 2)

For g(0), we use the function value

when −2 < x < 1,So g(0) = 1 / (0 − 1)2 = 1 / 1 = 1

Finally, we find g(5):When x ≤ −2,g(x) = 2

When −2 < x < 1,g(x) = 1 / (x − 1)2

When x = 1,g(x) = undefined

When 1 < x < 2,g(x) = 1 / (x − 1)2

When x ≥ 2,g(x) = −2 / (x + 2)For g(5),

we use the function value when x ≥ 2,So g(5) = −2 / (5 + 2) = −2 / 7

Hence, we get g(−2) = −1/3, g(0) = 1, and g(5) = −3/14.

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The order of the quantity from least to the greatest will be π²/8 < √2  < √3 < π²/4 and the order of quantities, as in the numeric labels, is 2341.

A number is a mathematical entity that can be used to count, measure, or name things. For an example, 1, 2, 56 etc. are the numbers.

We have a quantity shown in the table with label 1 to 4

π²/4 = 2.467 → 1

π²/8 = 1.2337→ 2

√2 = 1.4142 → 3

√3 = 1.7320 → 4

The order of the quantity from  least to the greatest will be:

π²/8 < √2  < √3 < π²/4

The order of quantities, as in the numeric labels:

= 2341

Thus, the order of the quantity from least to the greatest will be π²/8 < √2  < √3 < π²/4 and the order of quantities, as in the numeric labels, is 2341.

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The mean of x is 7.7 minutes, and the standard deviation of x is 0.525 minutes and the shape of the sampling distribution of the sample mean is approximately normal.

The mean of the sampling distribution of the sample mean is the same as the population mean.

Given that the population mean is 7.7 minutes, the mean of x is also 7.7 minutes.

The standard deviation of the sampling distribution of the sample mean (also known as the standard error) can be calculated using the formula: standard deviation of x = population standard deviation / √n.

where n is the sample size.

Te population standard deviation is 2.1 minutes, and the sample size is 16.

Substituting these values into the formula:

standard deviation of x = 2.1 / √16

standard deviation of x = 2.1 / 4

standard deviation of x = 0.525 minutes

Therefore, the mean of x is 7.7 minutes, and the standard deviation of x is 0.525 minutes and the shape of the sampling distribution of the sample mean is approximately normal.

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Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

\(\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1\)

We take left hand side of the given equation and solve it,

\(\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}\)

Since, abc = 1,

\(\frac{1}{c}=ab\) and c = \(\frac{1}{ab}\)

By substituting these values in the expression,

\(\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}\)

                                       \(=\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}\)

                                       \(=\frac{1+b+ab}{1+b+ab}\)

                                       \(=1\)

Which equal to the right hand side of the equation.

Hence, \(\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1\)

The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .

The charge at which anything happens is referred to as the velocity at which it happens.

The required details for mean rate :

(a) H0: µ = 21.62

Ha: µ ≠ 21.62

(b) t = -1.231

p-value = 0.2253

(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.

(d) H0: µ = 21.62

Ha: µ ≠ 21.62

t = -1.231

check statistic ≥ 2.020

Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.

The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.

The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.

The crucial values for t at this level of significance are t=2.019.

Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.

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Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.

Joanne's health insurance plan with a $1000 deductible, 80% coinsurance, and a $5000 out-of-pocket cap requires her to pay for her medical expenses until she reaches the deductible.

After reaching the deductible, she is responsible for 20% of the covered expenses, up to the out-of-pocket cap. The plan pays the remaining percentage of covered expenses.

To calculate how much the plan pays for Joanne's July losses, we need to consider her deductible, coinsurance, and out-of-pocket cap.

In March, Joanne incurs $1000 in covered medical expenses.

Since this amount is equal to her deductible, she is responsible for paying the full amount out of pocket.

In July, Joanne incurs $3000 in covered expenses. Since she has already met her deductible, the coinsurance comes into play.

According to the plan's coinsurance rate of 80%,

Joanne is responsible for 20% of the covered expenses.

Therefore, Joanne is responsible for paying 20% of $3000, which is $600.

The plan will pay the remaining 80% of the covered expenses, which is $2400.

In December, Joanne incurs $30,000 in covered expenses. Since she has already met her deductible and reached her out-of-pocket cap, the plan pays 100% of the covered expenses.

Therefore, the plan will pay the full $30,000 for her December losses.

To summarize, Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.

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By considering the given information that angles 21 and 23 are supplementary and analyzing the properties of supplementary angles and parallel lines, we have proven that segment HI is parallel to segment JK.

To prove that segment HI is parallel to segment JK based on the given information that angles 21 and 23 are supplementary, we can utilize the properties of supplementary angles and parallel lines.

First, let's examine the given figure and information.

We have a capital letter A with serifs, where segment HI represents one of the serifs, and segment JK represents a horizontal line within the letter A.

To begin the proof, we'll make use of the fact that angles 21 and 23 are supplementary.

Supplementary angles are defined as two angles whose measures sum up to 180 degrees.

We can observe that angle 21 is an interior angle of triangle AHI, and angle 23 is an interior angle of triangle AJK.

Since angles 21 and 23 are supplementary, their sum is equal to 180 degrees.

Now, let's assume that segments HI and JK are not parallel.

In this case, if we extend lines HA and JA, they will eventually intersect at point P.

Since the angles formed at the point of intersection are supplementary (angle 21 + angle 23 = 180 degrees), it would imply that angle 21 and angle PJK, as well as angle 23 and angle PHI, are also supplementary.

However, this leads to a contradiction. In the original figure, we can observe that angle 21 and angle PJK do not form a supplementary pair since angle PJK is a right angle (90 degrees) in the letter A.

Therefore, our assumption that segments HI and JK are not parallel must be incorrect.

Consequently, we can conclude that segment HI is indeed parallel to segment JK.

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Answer:

70

Step-by-step explanation:

The equation are x = y + 50  and 5x + 2y = 950

Firstly, let x represent the number of adult tickets sold and let y represent the number of student tickets sold.

Since there was 50 more adult tickets sold compared to student tickets, hence this statement can be represented by the equation:

x = y + 50 (1)

Also, they collected a total of $950. Each adult ticket was $5 while female ticket was $2, hence:

5x + 2y = 950     (2)

5(y + 50) + 2y = 950

y = 100

x = 100 + 50

x = 150

Solving equations 1 and 2 simultaneously gives y = 100 and x = 150

Therefore they was 150 adult tickets and 100 student tickets

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Ocean needs a tarp that is approximately 34 feet in size (rounded to the nearest foot) to cover the top of the frame.

To find the size of the tarp needed to cover the top of the frame, we can use trigonometry. Given the angle of the tent as 22.6º and the base length of 24 feet, we can find the length of the tarp using the tangent function.

The tangent of an angle is defined as the ratio of the length of the opposite side to the length of the adjacent side. In this case, the opposite side represents the height of the tent, and the adjacent side represents half the base length.

Let's calculate the height of the tent first:

Height = tan(angle) * (base / 2)

Height = tan(22.6º) * (24 / 2)

Height = 0.414 * 12

Height ≈ 4.968 feet (rounded to the nearest thousandth)

The tarp needed to cover the top of the frame should have a size equal to the base length plus twice the height. Let's calculate it:

Tarp size = base + 2 * height

Tarp size = 24 + 2 * 4.968

Tarp size = 24 + 9.936

Tarp size ≈ 33.936 feet (rounded to the nearest thousandth)

Therefore, Ocean needs a tarp that is approximately 34 feet in size (rounded to the nearest foot) to cover the top of the frame.

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Answer:

k > 8

Step-by-step explanation:

Step 1: We know in order for a quadratic equation to have 2 distinct solutions the discriminant has to be positive

Important formula: Discriminant = \(b^{2}-4ac\)

Step 2: Input information into discriminant

\(b^{2}-4ac\) > 0

\(k^{2}-4(2)(8)\) > 0

\(k^{2}-64\) > 0

\(k^{2}\) > 64

\(\sqrt{ k^{2}}>\sqrt{64}\)

k > 8

Therefore in order for the equation to have 2 distinct solutions is to have k > 8

(b²-4ac) > 0

where Z is an integer

(-k)²-4(2)(8) > 0

k²-64 > 0

k²>64

k>8

Therefore the sum of all values of k is infinite

Answer:

17

Step-by-step explanation:

6 x 2 = 12 so 12 + 5 = 17

Dylan would have to pay $17.

For such questions it is best to form an expression.

The parking fee has a fixed cost of $5.

It also has a cost per hour of $2.

This means that if a person spends t hours at the parking lot, they will have to pay $2 per hour for those t hours.

Expression = 2 x t = 2t

Whole expression including the fixed amount is:

5 + 2t

If Dylan parked for 6 hours therefore, he would pay:

= 5 + 2 t

= 5 + 2 x 6

= $17

Dylan would therefore have to pay $17 if he left his car for 6 hours.

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