a neutral solution does not contain any h3o or oh- a basic solution does not contain h3o an acidic solution has [h3o⁺] > [oh⁻] none of the these are true. a neutral solution contains [h2o] = [h3o⁺]

62.1 g Al

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

2.30 mol Al

Step 2: Identify Conversions

[PT] Molar Mass of Al - 26.98 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

62.054 g Al ≈ 62.1 g Al

The pOH of the solution is 6.38 (Option B).

1. First, calculate the pH of the solution. The pH is the negative logarithm of the H₃O⁺ concentration. Use the formula:
  pH = -log[H₃O⁺]

2. Plug in the given H₃O⁺ concentration:
  pH = -log(2.4 × 10^-8)

3. Calculate the pH:
  pH ≈ 7.62

4. Next, calculate the pOH using the relationship between pH and pOH at 25°C:
  pH + pOH = 14

5. Solve for pOH:
  pOH = 14 - pH

6. Plug in the calculated pH:
  pOH = 14 - 7.62

7. Calculate the pOH:
  pOH ≈ 6.38

To know more about pOH:

https://brainly.com/question/12407500

#SPJ11

The corn starch and water will stay separated and eventually sit in the glass as layers. This is due to the 2 fluids having different densities far enough from one another that the fluids do not mix.

Answer:

Cornstarch and water mixed acts both like a solid and a liquid.

Explanation:

Cornstarch and water is a suspension mixture with a solid dispersed into a liquid. When you press the mixture quickly, the starch molecules close together. This causes the water to get trapped between the starch chains and create a semi-rigid structure.

Answer:

the sun beams down on the pool and heats it up top to bottom the deeper the colder

If glucose (C6H12O6) is the solute, it will not dissociate in water. The main reason for this is that glucose is a nonionic molecule, which means it does not form ions when dissolved in water. Instead, glucose molecules stay intact and do not break apart into smaller charged particles like ions.

When a substance dissolves in water, it can either dissociate or remain undissociated. Dissociation occurs when a substance breaks apart into ions in solution. For example, when table salt (NaCl) dissolves in water, it dissociates into sodium ions (Na+) and chloride ions (Cl-). In this case, the solute (salt) undergoes dissociation.

However, in the case of glucose, there is no dissociation. Glucose is a covalent compound, meaning its molecules are held together by covalent bonds where electrons are shared between atoms. These covalent bonds are relatively strong, so glucose molecules do not easily break apart in water. Instead, they remain as intact glucose molecules.

To know more about that glucose visit:

https://brainly.com/question/1478186

#SPJ11

Glucose, due to its hydrophilic nature, dissolves in water. However, unlike ionic compounds, it does not disassociate into ions, but rather its molecules disperse uniformly in the water.

The student's question asks: If glucose (C6H12O6) was the solute, would it disassociate in water? To address this query, let us first understand some principles. Water, known as the 'universal solvent', readily dissolves ionic compounds and polar covalent compounds due to its polar nature with regions of positive and negative charge.

Molecules like glucose contain regions of hydrogen-oxygen polar bonds, making them hydrophilic, or 'water-loving'. When glucose is dissolved in water, its molecules become widely distributed among those of water. However, unlike ionic compounds such as salt, glucose (a covalent compound) does not ionize or disassociate into separate ions when dissolved. Instead, individual molecules of glucose disperse evenly in the water.

So, while glucose does dissolve in water due to its hydrophilic nature, it does not technically disassociate like ionic compounds. It's important to note that this solubility in water is crucial for the body, which makes use of such solutions for various chemical reactions and processes.

https://brainly.com/question/35937728

#SPJ12

Answer:

B

Explanation:

building blocks for creating proteins

Answer:

Explanation:To calculate the mass of each portion of the liquid, we need to subtract the mass of the empty beaker from the mass of the beaker with the liquid after each transfer.

Mass of first portion of liquid = 27.4850 g - 26.4750 g = 1.0100 g

Mass of second portion of liquid = 28.5000 g - 27.4850 g = 1.0150 g

Mass of third portion of liquid = 29.5160 g - 28.5000 g = 1.0160 g

To calculate the mean mass of a portion of the liquid, we need to take the average of the masses of the three portions of the liquid.

Mean mass of a portion of the liquid = (1.0100 g + 1.0150 g + 1.0160 g)/3 = 1.0133 g

Therefore, the mass of each portion of the liquid is 1.0100 g, 1.0150 g, and 1.0160 g, and the mean mass of a portion of the liquid is 1.0133 g.

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

For more question on energy

https://brainly.com/question/29339318

#SPJ8

To calculate the dilution factor needed to achieve a final concentration of 11.2% (w/v) from a starting concentration of 14M KOH, we need to use the following formula. Dilution factor Starting concentration Final concentration. To do this, we need to know the density of the solution. Let s assume the density is 1 g ml.

Dilution factor Starting concentration Final concentration. First, we need to convert 11.2% (w/v) to molarity. To do this, we need to know the density of the solution. Let's assume the density is 1 g/mL.11.2% (w/v) = 11.2 g KOH / 100 mL solution Molar mass of KOH = 56.11 g/mol11.2 g KOH / 56.11 g/mol = 0.1996 mol KOH0.1996 mol KOH / 1 L solution = 0.1996 M KOH Now we can calculate the dilution factor. Dilution factor = (14 M KOH / 0.1996 M KOH) = 70.14Therefore, you need to dilute the 14 M KOH solution by a factor of 70.14 to get a final concentration of 11.2% (w/v).

learn more about dilution factor here

https://brainly.com/question/28841707

#SPJ11

Answer:

150million km

Explanation:

hope it helps

The pressure of the gas if ethylene is supplied by a 51.6 l tank is 51.1355atm

The final pressure of the gas can be calculated by using the formula given by Boyle's law,

      P1V1 = P2V2

What is Boyle's law?

    Boyle's law relates the compression and expansion of gas at a constant temperature. It states that, At constant temperature the pressure exerted by a gas is inversely proportional to the volume of the given mass of gas.

      P1V1 = P2V2

where,

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure and

V2 is the final volume.

Initial volume V1= 4122.8L

Initial pressure P1= 0.64atm

Final volume V2= 51.6L

Final pressure P2= ?

   0.64*4122.8= P2*51.6

   P2= 2638.592/51.6

   P2= 51.1355atm

Hence the final pressure of the gas is 51.1355atm

Learn more about Boyle's law on

https://brainly.com/question/1696010

#SPJ1

Explanation:

it helps in when the kidney has used the needful nutrients been taken then the unwanted waste product it sends it to the nervous system then the nervous system passes the waste product to the bladder in form of urine

Answer:

5.59 L

Points earned on this question: 4

Explanation:

took the test

The new volume of the sample of gas when the temperature is increased from 298 K to 333 K is 5.59 L

Charles' law states as follow:

V₁ / T₁ = V₂ / T₂

Where

From the question given above, the following data were obtained

V₁ / T₁ = V₂ / T₂

5 / 298 = V₂ / 333

Cross multiply

298 × V₂ = 5 × 333

Divide both side by 298

V₂ = (5 × 333) / 298

V₂ = 5.59 L

Learn more about gas laws:

https://brainly.com/question/6844441

The mass of HI should be present in 0.200l of solution to obtain a solution with pH value's,

(a) pH value is 1.20 the mass is 1.08g

(b) pH value is 1.75 the mass is 0.0066g

(c) pH value is 2.85 the mass is 0.00012g

To solve this problem, we must determine the concentration of H+ ions in the solution using the pH of the solution and the dissociation constant of HI. The concentration of HI and the mass of HI required to make the solution may then be calculated.

The dissociation reaction for HI is:

HI(aq) ↔ H+(aq) + I-(aq)

The dissociation constant, Ka, for this reaction, is:

Ka = [H+][I-]/[HI]

This formula may be simplified by assuming that the starting concentration of HI is equal to the concentration of I- produced, which is equal to the concentration of H+ produced due to the reaction's 1:1 stoichiometry. This results in:

Ka = [H+]^2/[HI]

Solving for [H+], we get:

[H+] = sqrt(Ka*[HI])

Taking the negative log of both sides gives us the pH of the solution:

pH = -log[H+] = -log(sqrt(Ka*[HI]))

pH= -0.5*log(Ka) - 0.5*log([HI])

Rearranging this equation, we get:

[HI] = 10^(-(pH + 0.5*log(Ka)))/V

where V is the volume of the solution.

Now we can calculate the mass of HI required for each pH:

(a) For pH = 1.20:

Ka for HI is 1.3 x 10^-10. Substituting this value into the equation above, we get:

[HI] = 10^(-(1.20 + 0.5*log(1.3 x 10^-10)))/0.200L ≈ 0.0042 M

The mass of HI required is:

mass = concentration x volume x molar mass

     = 0.0042 mol/L x 0.200 L x 127.91 g/mol

     ≈ 1.08 g

Therefore, approximately 1.08 grams of HI is required to prepare a solution with a pH of 1.20.

(b) For pH = 1.75:

[HI] = 10^(-(1.75 + 0.5*log(1.3 x 10^-10)))/0.200L ≈ 0.00026 M

mass = 0.00026 mol/L x 0.200 L x 127.91 g/mol ≈ 0.0066 g

Therefore, approximately 0.0066 grams of HI is required to prepare a solution with a pH of 1.75.

(c) For pH = 2.85:

[HI] = 10^(-(2.85 + 0.5*log(1.3 x 10^-10)))/0.200L ≈ 0.0000047 M

mass = 0.0000047 mol/L x 0.200 L x 127.91 g/mol ≈ 0.00012 g

Therefore, approximately 0.00012 grams of HI is required to prepare a solution with a pH of 2.85.

Learn more about Dissociation Reaction:

https://brainly.com/question/29411272

#SPJ4

Answer:

it is a infectiousr bacterial disease characterized by the growth of nodules(tubercles) in tissues especially the lungs

In the balanced equation for the reaction\(MnO_{4}^-(aq) + Fe_{2} ^+(aq) -- > Mn_{2}^+(aq) + Fe_{3}^+(aq)\) in basic aqueous solution, the coefficient for OH−(aq) is 4.

To balance the given equation in basic aqueous solution, we need to ensure that the number of atoms of each element is equal on both sides of the equation and that the overall charge is balanced. Here's how the equation is balanced:

First, we balance the atoms other than hydrogen and oxygen. The equation becomes:

\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)\)

Next, we balance the oxygen atoms by adding water molecules (H2O):

\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)+4H_{2}O(l)\)

Now, we balance the hydrogen atoms by adding OH−(aq) ions:

\(MnO_{4}^-(aq) + 5Fe_{2} ^+(aq)+8H_{2}O(l) -- > Mn_{2}^+(aq) +5 Fe_{3}^+(aq)+4H_{2}O(l)+4OH^-(aq)\)

Therefore, in the balanced equation, the coefficient for OH−(aq) is 4. This balances the hydrogen atoms and ensures that the equation is balanced in basic aqueous solution.

Learn more about aqueous solution here:

https://brainly.com/question/1382478

#SPJ11

The correct answer is 0.15.

We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.

These quantities might be converted to moles by applying the following formula:

amount= mass/ relative atomic mass

Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.

0.05X + x'O2 = 0.15CO2 + 0.2H2O

This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:

1 x + x O2 = 3 co2 + 4 H2O

The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.

Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.

There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.

This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).

To learn more about number of moles of carbon dioxide refer the link:

https://brainly.com/question/12723070

#SPJ9

9 g of beryllium (Be) and 4 g of Helium (He) have the same number of particles.

If you have 9 g of beryllium (Be) and 4 g of Helium (He), what do both have in common?

The density of Be is 1.84 g/mL. The volume of 9 g of Be is:

\(9g \times \frac{1mL}{1.84g} = 4.9 mL\)

The density of He is 0.18 g/L. The volume of 4 g of He is:

\(4 g \times \frac{1L}{0.18g} = 22 L\)

The molar mass of Be is 9 g/mol and the molar mass of He is 4 g/mol. Then, we have 1 mole of each one (6.02 × 10²³ particles)

The molecular weight of Be is 9 amu and the molecular weight of He is 4 amu.

9 g of beryllium (Be) and 4 g of Helium (He) have the same number of particles.

You can learn more about moles here: https://brainly.com/question/20486415

A gas initially at 21.63 degrees Celsius and 0.87 atm is compressed to a pressure of 2.59 atm. To determine the resulting temperature is approximately 603.21 degrees Celsius we need to apply the ideal gas law equation

According to the ideal gas law, the relationship between pressure (P), volume (V), temperature (T), and the number of moles of gas (n) is given by the equation PV = nRT, where R is the ideal gas constant.

To find the resulting temperature, we can rearrange the ideal gas law equation as follows: T = (P₂ * T₁) / P₁, where T₁ is the initial temperature and P₁ and P₂ are the initial and final pressures, respectively.

Substituting the given values, the initial temperature T₁ is 21.63 degrees Celsius (or 294.78 Kelvin) and the initial pressure P₁ is 0.87 atm. The final pressure P₂ is 2.59 atm. By plugging these values into the equation, we can calculate the resulting temperature T₂.

Using the equation T₂ = (2.59 atm * 294.78 K) / 0.87 atm, we find the resulting temperature T₂ to be approximately 876.21 Kelvin (or 603.21 degrees Celsius).

Therefore, when the gas is compressed to a pressure of 2.59 atm, the resulting temperature is approximately 603.21 degrees Celsius.

Learn more about ideal gas law

brainly.com/question/30458409

#SPJ11

Answer:

The mole and atonmicity of both the gases are different, the number of atoms is not same.

Explanation:

The number of atoms in a molecule (compound) depends on mole number and atomicity.

↬ Mole of 100 g H₂ = 100g ÷ 2u = 50 mole

∴Number of atoms in 100 g H₂

= 2 x 50 x 6.022 × 10²³

= 6.022 x 10²⁴ atoms

↬ Mole of 100 g He = 100g ÷ 4u = 25 mole

∴ Number of atoms in 100 g He

= 1 × 25 × 6.022 × 10²³

= 150.55 × 10²³

= 1.5055 x 10²⁵ atoms

Thus, The mole and atonmicity of both the gases are different, the number of atoms is not same.

-TheUnknownScientist 72

This problem is providing us with the pKa of phenol and its initial concentration. It is asking for the percent ionization it exhibits in water. At the end, the answer turns out to be 0.00405 %.

In chemistry, when acids and bases dissolve in water, they undergo ionization, a process whereby they split into a cation and an anion. In this case, since phenol has a pKa of 9.89, one can write the following ionization reaction:

\(C_6H_5OH(aq)+H_2O\rightleftharpoons C_6H_5O^-(aq)+H_3O^+(aq)\)

And the equilibrium constant can be written as:

\(K=\frac{[C_6H_5O^-][H_3O^+]}{[C_6H_5OH]} =\frac{x^2}{0.0786} =10^{-9.89}\\\\1.29x10^{-10}=\frac{x^2}{0.0786}\)

Which can be solved for x with:

\(x=\sqrt{1.29x10^{-10}*0.0786} \\\\x=3.19x10^{-6}M\)

Finally, the percent ionization:

\(\%ioniz=\frac{3.18x10^{-6}M}{0.0786M}*100\%\\ \\\%ioniz=0.00405\%\)

Learn more about percent ionization: https://brainly.com/question/9173942

Based on the given information and the densities provided in the table, the unknown element in the alloy is most likely Beryllium. option(a)

To identify the unknown element in the alloy, we need to compare the density of the alloy with the densities of the elements listed in the table.

The density of the alloy can be calculated using the given information. We know that 10.0 grams of the alloy has a volume of 4.20 cm³. Density is defined as mass divided by volume, so we can calculate the density of the alloy as:

Density = Mass / Volume = 10.0 g / 4.20 cm³ ≈ 2.38 g/cm³

Now, we compare the calculated density of the alloy (2.38 g/cm³) with the densities listed in the table. From the given options, the closest density is that of aluminum, which is 2.70 g/cm³. The alloy's density is lower than the density of aluminum, which means it must contain an element with a lower density than aluminum.

The unknown element in the alloy is most likely Beryllium (option A) with a density of 1.85 g/cm³. The combination of 62% aluminum and 38% beryllium in the alloy would result in a density close to the calculated value of 2.38 g/cm³. option(a)

For such more questions on densities

https://brainly.com/question/1749900

#SPJ8

Molarity can be defined as the moles of solute in a liter of solution. The molarity of the salt solution is \(\rm \bold{3.99\;\times\;10^{-4}\;M}\).

The moles are the mass of substance with respect to the molar mass. The moles and volume relationship can be expressed in terms of molarity.

The molarity can be expressed as:

\(\rm Molarity=\dfrac{Moles}{Volume}\)

The given solution has,

Substituting the values for molarity as:

\(\rm Molarity=\dfrac{5.99\;\times\;10^{-6}}{1.50\;\times\;10^-^2\;L}\\ Molarity=3.99\;\times\;10^{-4}\;M\)

The molarity of the solution is \(\rm \bold{3.99\;\times\;10^{-4}\;M}\). Thus, option C  is correct.

Learn more about molarity, here:

https://brainly.com/question/12127540

Answer:

Option C is correct

Explanation:

EDGE 2022

The calculated molar ratio of iron to oxygen in BIFs is 1.452.

Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.

To calculate the mass of oxygen contained within BIFs, we'll use the given information:

Total mass of the modern atmosphere = 5.01×10¹⁸ kg

Percentage of oxygen in the modern atmosphere = 21%

Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg

Percentage of oxygen contained in BIFs = 6.6% (given)

Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg

Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.

To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:

Molecular mass of O₂ = 0.032 kg/mole

Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)

= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles

Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.

Next, let's calculate the mass of iron in BIFs:

Total mass of BIFs = 5.0×10¹⁷ kg

Percentage of iron in BIFs = 35%

Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg

To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:

Atomic mass of iron = 0.0558 kg/mole

Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)

= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles

Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.

Finally, let's calculate the molar ratio of iron to oxygen in BIFs:

Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)

= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)

≈ 1.452

To know more about modern atmosphere

https://brainly.com/question/2508257

#SPJ11

Answer:

Li3N

Explanation:

Li+N2=Li3N.........................

Answer:

4 Li(s)+O2(g) → 2 Li2O(s)

Explanation:

its right

A revival of classical concern in and respect for the seen in Donatello's David. The free-standing classical figure antiquity Donatello's David. The sculpture exhibits an eroticism that is typical of its era.

Being the first free-standing statue constructed since antiquity and the first freestanding standing bronze sculpture cast during the Renaissance, Donatello's David was immensely ground breaking when it was created.

The detailed substance of Donatello's sculpture of David, which had no other aesthetic or practical function other than to display his sculpting abilities, was what he saw as the sculpture's uniqueness. David and the skull of the enormous Goliath make up the majority of a book's material.

To know more about Donatello's David visit:

https://brainly.com/question/28039234

#SPJ4

Answer:

multitide of uses (drinking, cleaning, cooking, transportation). Without water we would not survive. -Lead atoms bond together and they make up the lead that we use as a pencil. -Copper atoms, aluminum atoms, nickel atoms, etc., all make up metal which is used for a variety of things in everyday life.

Explanation:

Answer:

101.62 grams of water is given o when 62.1 g of propane burns.

Explanation:

Propane gas (C₃H₈) burns with oxygen gas and products carbon dioxide gas and liquid water. The balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry, the following amounts of moles of each compound participate in the reaction:

Being the molar mass of each compound:

By stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 44 grams of propane produces 72 grams of water, 62.1 grams of propane how much mass of water does it produce?

\(mass of water=\frac{62.1 grams of propane*72 grams of water}{44 grams of propane}\)

mass of water= 101.62 grams

101.62 grams of water is given o when 62.1 g of propane burns.

Answer:

1 mole is equal to 6.022x10²³

Answer:

2.979 mol

Explanation:

mass of NaF=14+19

                    =33g

33g of NaF is the mass of 1 mol

98.3g of NaF is the mass of (98.3/33)*1=2.979 mol