Answers
A matter can be separated into three states.
SolidLiquidGasIn solid state the bonding between atoms is maximum.In liquid state the bonding between atoms is less than solid.In gaseous state the bonding between atoms is minimum2. liquid
3. gas
Related Questions
A car rounding a corner has an acceleration
of 5m/s². If it rounds a corner with twice the
radius at the same speed, what would be its new
acceleration?
Answers
5/4 m/s^{2} would be its new acceleration .
What is centrifugal acceleration ?
The simplest case of circular motion is uniform circular motion, where an object moves in a circular trajectory with constant velocity. Note that the linear velocity of an object in circular motion is constantly changing because, unlike velocity, it is constantly changing direction. From kinematics we know that acceleration is a change in velocity, either in magnitude or direction, or both. Therefore, an object in uniform circular motion will always be accelerated even if the magnitude of its velocity is constant. You can feel this acceleration every time you get in the car while cornering. Keeping the handle steady while turning and moving at a constant speed creates a smooth circular motion. What you will notice is a feeling of skidding (or skidding depending on speed) out of the center of the turn.
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It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left in the game, the Bruins pull the goalie and have him play as a forward in an attempt to tie the game. The Flyers successfully defend their goal for 9 s. With only 1.25 s remaining on the game clock, a Flyer shoots the puck on the ice past the skates and sticks of the other players and toward the Bruins' goal. The puck is 37 m from the goal when it leaves the stick with an initial horizontal velocity of 30 m/s. The shot is perfectly directed toward the empty goal, but the ice slows the puck down at a constant rate of 0.50 m/s2 as it slides toward the goal. None of the Bruins can stop the puck before it reaches the goal.
A. Where is the puck when the game clock reaches zero and the horn sounds to end the game?
B) Do the flyers win the game by 1 or 2 points?
Answers
Answer:
A
\(k = 0.11 \ m \) beyond the goal post
B
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points
Explanation:
From the question we are told that
The amount of time left in the game is \(t = 20 \ s\)
The amount of time the goal was defended is \(t_1 = 9 \ s\)
The time remaining when the shot was made is \(t_2 = 1.25 \ s\)
The distance of the pluck from the goal is \(d = 37 \ m\)
The initial velocity of the pluck is \(u = 30 \ m/s\)
The acceleration of the pluck is \(a = -0.50 \ m/s^2\)
Generally the distance travel at the remaining time is mathematically represented as
\(D = u * t _2 + \frac{1}{2}* a* t_2\)
\(D = 30 * 1.25 - \frac{1}{2}* 0.50* 1.25^2\)
\(D = 37.11 \ m \)
So the position of the pluck when the game clock reaches zero is
\(k = D - d\)
=> \(k = 37.11 - 37\)
=> \(k = 0.11 \ m \) beyond the goal post
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points
How are gases and liquids different from each other? A. Gases can change volume, and liquids cannot. O B. Liquids can change volume, and gases cannot. C. Gases can change shape, and liquids cannot. D. Liquids can change shape, and gases cannot.
Answers
Answer:
A.gasses can change volume, and liquids cannot
Explanation:
if you pour a glass of water you don't have to worry about it expanding such that it overflows. however if you air up a ballon you may notice that it becomes lager the warmer it gets and smaller the cooler it gets
explain the methods to determine specific charge of an electron ?
Answers
The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.
The J. J. Thomson Method
In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$
When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$
The Millikan Oil Drop Method
This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.
The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.
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The methods to determine the specific charge of an electron are :
The J. J. Thomson Method The Millikan Oil Drop Method.How do we describe?In the J. J. Thomson Method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.
When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.
The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.
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Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
Answers
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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The figure below shows a ray of light as it travels from media A to media B.The refractive index of media B to media A is
Answers
Given data:
* The angle of incidence in the medium A is,
\(i=60^{\circ}\)* The angle of refraction in medium B is,
\(r=45^{\circ}\)Solution:
According to the Snell's Law,
\(\begin{gathered} n_A\sin (i)=n_B\sin (r) \\ \frac{n_B}{n_A}=\frac{\sin (i)}{\sin (r)} \end{gathered}\)where n_B is the refractive index of medium B and n_A is the refractive index of medium B,
Substituting the known values,
\(\begin{gathered} \frac{n_B}{n_A}=\frac{\sin (60^{\circ_{}})}{\sin (45^{\circ})} \\ \frac{n_B}{n_A}=\frac{0.866}{0.707} \\ \frac{n_B}{n_A}=1.225 \end{gathered}\)Thus, the ratio of refractive index of medium B to the refractive index of medium A is 1.225.
A Hiker walks 4.5km at 35 degrees north east then turns due south and goes 4.5 km. What is the total displacement
Answers
The total displacement travelled by the hiker who travelled 4.5kms at 35 degrees and 4.5kms towards south is 6.36kms.
What is displacement?Displacement can be defined as the change in position of an object with respect to time. It is a vector quantity, has direction and magnitude both. It is represented as an arrow which points from the starting position to the final position that the object has travelled. For example, an object that moves from A position to B position, then the object's position changes.
The distance travelled by the hiker is 4.5kms towards northeast at 35 degrees and 4.5kms towards south.
The total distance travelled by the hiker = \(\sqrt(4.5)^{2}+ (4.5)^{2}\)
Total distance travelled by the hiker = √(20.25+20.25)
Total Distance= √40.5km
Total distance travelled by the hiker = 6.36kms
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A zebra is running at 80 kmh in front of a lion that is moving with 100 km h. If the zebra is 15 km ahead of lion, how long (in minutes) it
takes for the lion to catch the zebra if their velocities remain unchanged?
Answers
Answer: 45 minutes
Explanation:
hope this helps!
What is the momentum of a photon having the same total energy as an electron with a kinetic energy of 100 keV?
Answers
Answer:
The momentum of the photon is 1.707 x 10⁻²² kg.m/s
Explanation:
Given;
kinetic of electron, K.E = 100 keV = 100,000 eV = 100,000 x 1.6 x 10⁻¹⁹ J = 1.6 x 10⁻¹⁴ J
Kinetic energy is given as;
K.E = ¹/₂mv²
where;
v is speed of the electron
\(K.E = \frac{1}{2}mv^2\\\\mv^2 = 2K.E \\\\v^2 = \frac{2K.E}{m} \\\\v = \sqrt{\frac{2K.E}{m}} \\\\but \ momentum ,P = mv\\\\(v)m = (\sqrt{\frac{2K.E}{m}})m\\\\P_{photon} = (\sqrt{\frac{2K.E}{m_e}})m_e\\\\P_{photon} = (\sqrt{\frac{2\times 1.6\times 10^{-14}}{9.11\times10^{-31}}})(9.11\times 10^{-31})\\\\P_{photon} = 1.707 \times 10^{-22} \ kg.m/s\)
Therefore, the momentum of the photon is 1.707 x 10⁻²² kg.m/s
Is clinical depression associated with eating disorders yes or no
Answers
Yes, a symptom of depression is a loss of appetite, and eating disorders are often developed as a result of an unhealthy coping mechanism with life; therefore, people with depression can get eating disorders and vice versa. They go hand in hand.
The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
Answers
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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QUICK!! What class of leer is shown below?
first class lever
second class lever
third class lever
fourth class lever
Answers
Answer:
3rd class lever
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The class of lever that should be given in the attached image is to be considered the third-class lever.
What is a third-class lever?In a Class Three Lever, the Force should be lies between the Load and the Fulcrum. In the case when the Force is closer to the Load, it should be easier to lift and there is a mechanical advantage.
So based on this, we can say that The class of leer that should be given in the attached image is to be considered as the third-class lever.
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What is the acceleration at 3 seconds?
Please explain your answer. Thank you :]
![What is the acceleration at 3 seconds?Please explain your answer. Thank you :]](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/iMbNnw8dzsff4wknF5hWbCxF72mG0qT1.png)
Answers
Answer:
\(-3 m/s^{2}\)
Explanation:
Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2
Define invariant transformations
Answers
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".
calculate how much heat is released when 500g of platinum is cooled from 250.0K to 240.0K
Answers
m= mass
C= specific heat
AT- change in temperature (final minus initial)
Q=mCA(delta)T
Q=500g(0.133J/g*C)(-10*C)
Q= -655 J
Answer:
Q = 665 J
Explanation:
Given:
m = 500 g = 0.5 kg
T₁ = 250.0 K
T₂ = 240.0 K
c = 133 J / ( kg*⁰K) - Specific heat capacity of platinum
___________
Q - ?
Heat is released:
Q = c*m*( T₁ - T₂) = 133*0.5*(250.0 - 240.0) =
= 133*0.5*10 ≈ 665 J
If the change in entropy dS = dQ / T and that S=f(Q,T) prove that entropy is a state function .
Answers
Answer:
It is because the entropy of a system depends only on its state, just like its internal energy. Or, putting it the other way round, a given state of a system has a particular entropy.
The formula dS = dQ/T only applies to a reversible change, and such a change has only one path, or a few equivalent paths.
You find an old book and decide to estimate the thickness of one of the sheets or leafs. Neglecting the front and back cover, if all the sheets of book are 3 inches thick, and has 1024 marked pages (numbered 1 to 1024), what is the approximate thickness of the sheet in units of mm.
Answers
Explanation:
There are 1024/2 = 512 SHEETS (each is numbered on two sides)
3 inches * 25.4 mm/inch / 512 sheet = .1488 mm per sheet
an airbubble at the bottom of a lake 90 m deep has a volume of 1.5 cm³. what will be the volume just below the surface if atmospheric pressure is equivalent to a height of 10m of water
Answers
The volume of the air bubble just below the surface of the lake would be 0.000015 m³ = 1.5 cm³.
How do we calculate?V₁ = 1.5 cm³
P₁ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
To convert V₁ to m³:
Volume₁ = 1.5 cm³ * (1 m / 100 cm)³ = 0.000015 m³
we then substitute the values into the equation:
Volume ₂ = 0.000015 m³ * (P₂ / (1000 kg/m³ * 9.8 m/s² * 10 m))
Pressure ₂ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
We then substitute the value of P₂ into the equation for Volume 2:
V₂ = 0.000015 m³ * ((1000 kg/m³ * 9.8 m/s² * 10 m) / (1000 kg/m³ * 9.8 m/s² * 10 m))
Volume₂ = 0.000015 m³
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the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
Answers
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the x-component of the ball'sfinal velocity?X-component (m/s)
Answers
According to the problem, the final velocity module is 14.8 m/s and its direction is -47°. To find the x-component, we have to use the following formula
\(v_x=v\cdot\cos \theta\)Using the given information, we have
\(\begin{gathered} v_x=14.8m/s\cdot\cos (-47) \\ v_x\approx10.1m/s \end{gathered}\)Hence, the x-component is 10.1 m/s, approximately.Lab Report
Light
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U4_ Lab_Light_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for each part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect your data.
Type your answer here:
Data and Observations
1. Record your observations in the data tables.
Type your answer here:
Table 1. Angles of Incidence and Angles of Reflection for a Beam of Light Reflected off a Mirror
Angle of incidence (°) Angle of reflection (°)
Table 2. Angles of Incidence and Angles of Refraction for a Beam of Light Refracted through a Glass Lens
Angle of incidence (°) Angle of refraction (°)
Conclusions
1. Draw a diagram (develop a model) that shows what happens to light when it reflects off a mirror. Look for patterns in your data to help you develop your model. Hint: Is the angle of reflection always greater than, less than, or equal to the angle of incidence? Include labels.
Type your answer here:
2. Use your model to predict the angle of reflection of a beam of light reflected off a mirror if the angle of incidence of the beam of light is 40 degrees.
Type your answer here:
3. Draw a diagram (develop a model) that shows what happens to light when it is refracted through a glass lens. Look for patterns in your data to help you develop your model. Hint: Is the angle of refraction always greater than, less than, or equal to the angle of incidence? Include labels.
Type your answer here:
Answers
Answer:
Explanation:
the answer is b
a particle of mass 200gm executes SHM.the restoring force is provided by a spring of force constant 80N/m.the time period of oscillation is?
Answers
Answer:
time period of oscillation is 0.31 seconds
Explanation:
we shall know the formula:
\(T = 2\pi \sqrt{\frac{m}{k} }\) ......where m is mass and k is force constant.
change 200gm into kg, then it will be 0.2 kg
T = 2π√0.2÷80
T = 0.314 seconds
T = 0.31 seconds rounded to 2 decimal places.
4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
Answers
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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Each spring, a crevice in the cliff wall widens and deepens. What is the best explanation for how physical weathering causes the crevice to widen and deepen?
Winds deposit sand into the crevice.
Water freezes and expands in the crevice.
Snow melts and evaporates between the rocks in the crevice.
Air pollution in the area causes a reaction that widens the crevice.
Answers
Answer: water freezes and expands in the crevice
Explanation:
Answer:
Water freezes and expands in the crevice
Explanation:
Prior Knowledge
1. What do a light bulb, a toaster, a radio, and a computer all have in common?
Answers
Answer:
They all have electrical currents
Answer:
They have electronic parts and currents
What has to happen to make new elements?
Answers
Cannon
Mass - M
Marble
Mass m
Note: Figure not drawn to scale.
Students launch identical marbles of mass mm horizontally from a toy cannon of mass MC,
where Mc > mm, as shown above. The cannon can be adjusted to change the launch speed v of
the marble relative to the ground. Each time a marble is launched, the cannon slides backward
before coming to rest. The coefficient of kinetic friction between the cannon and the ground is u
(mu). For each launch, the students vary the launch speed v and record the distance x the cannon
slides backward for each launch speed.
Answers
Answer:
the distance x increases as the student increase the mass of the cannon.
Explanation:
a) From the question ; we get to understand that for each launch, the students use a different mass which is launch at speed v relative to the ground.
This changes in the mass used brought about a change in the momentum at the same speed v ; perhaps an increase in momentum. However; since the conservation of the momentum is considered at each launching.
The momentum of the marble = momentum of the cannon
But since the momentum of the cannon increase ; therefore the same equivalent changes takes place in its kinetic energy . Therefore , the kinetic energy will increase and the distance will also increase in the bid to quench the amount of energy generated. Thus, the distance x increases as the student increase the mass of the cannon.
b)We all know that conservation of the momentum will definitely takes place after launching of the cannon.
Let assume that \(\rho\) is the momentum of the cannon with mass \(M_C\)
The kinetic energy of the canon will be:
\(\frac{\rho ^2 }{2 M_C}\)
Also the frictional force acting on the cannon is :
\(f = \mu mg\)
If the cannon move at an additional distance x; the frictional force acting at this area quench the amount of the energy generated and consume the kinetic energy of the cannon;
So;
\(fx = K.E\)
\(fx = \frac{\rho ^2 }{2 M_C}\)
\(\mu mg x = \frac{\rho ^2 }{2 M_C}\)
\(x = \frac{\rho ^2 }{2 \mu mg M_C}\)
\(x = \frac{m_m^2 V^2 }{2 \mu mg M_C}\)
Thus; it is consistent with the answer in (a) as increase in the mass of the marble will bring about an increase in distance x
The increase in the mass of the marble increase the distance of the cannon.
Momentum:
Momentum of an object is equal to the product of the mass and the velocity of the object.
The kinetic energy of the cannon
\(K_C = \dfrac {\rho^2}{2 M_C}\)
Where,
\(\bold{\rho}\) - momentum of the cannon
Mc - mass
The frictional force on cannon
\(\bold{F_f = \mu mg}\)
Cannon move a distance x,
Hence,
\(\bold {F_f \times x = K_C}\\\\\bold {\mu m g \times x = \dfrac {\rho^2}{2 M_C }}\\\\\bold {x = \dfrac {\rho^2}{2\mu m g M_C }} }\\\\\bold {x = \dfrac {m^2 V^2}{2\mu m g M_C } }\)
Therefore, The increase in the mass of the marble increase the distance of the cannon.
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If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.
Answers
If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.
What is acceleration?The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.
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please help meee please please
Answers
Answer:
I think it's c but don't know for sure
5. What occurs when an enzyme and a substrate interact at an
active site?
a. Activation energy is reduced.
b. The products are bound irreversibly.
c. The enzyme is changed by the reaction.
d. Activation energy is increased.
Answers
Answer:
B
Explanation:
The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex
When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.
What are enzymes?Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.
All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.
Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.
Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.
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