When a student carefully hangs a 450 g mass from the free end then the length of the spring now is 18.7 cm. So, the correct option is a.
We can use Hooke's law to solve this problem. Hooke's law states that the force required to extend or compress a spring by some distance is proportional to that distance. Mathematically, this can be expressed as:
F = -kx
where F is the force applied to the spring, x is the distance the spring is compressed or stretched from its equilibrium position, and k is the spring constant. The negative sign indicates that the force is opposite in direction to the displacement. To apply this equation, we can follow these steps:
1. Convert the mass to force using F = mg.
F = (0.45 kg) x (9.8 m/s²)F = 4.41 N2.
Apply Hooke's law to find the distance the spring is stretched.
F = -kx
4.41 N = -(340 N/m)x
-4.41 N / 340 N/m = x
x = -0.013 metre cube.
Add the equilibrium length of the spring to find the final length of the spring.
x_final = x_initial + x = 0.200 m - 0.013 m
= 0.187 m
= 18.7 cm.
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Question 7 of 10
Which event is an example of melting?
A. People see their breath on a cold winter day.
B. Dew forms on the leaves of a tree.
C. Frost forms on a blade of grass.
O D. An ice cube forms a small puddle on the counter.
A race car speeds up with an acceleration of 10 m/s2 for 21 s. If its final velocity is 210 m/s, find its initial velocity.
Answer:
answer is 0m/ sec
please follow me.
A secant-secant angle intercepts arcs that are 3/5 and 3/8 of the circle. if a chord-chord angle and its vertical angle intercept the same arc, what is the measure of the chord-chord angle?
The measure of the chord-chord angle is 175.5.
What is a chord in a circle?A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.
What is an angle in math?An angle is a figure created by two rays or lines that have the same termination in plane geometry. The Latin word "angulus," which meaning "corner," is where the term "angle" originates. The common terminal of the two rays—known as the vertex—is referred to as an angle's sides.
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The job of a nucleolus is to build ribosomes.
True or False
Answer:
true
Explanation:
Answer: the job of the nucleus is to actually combine into complete ribosomes not make them .
Explanation: ribosomes make protein . so the nucleuses job is to make protein .
if the environmental lapse rate (elr) of the atmosphere surrounding a rising parcel of air is greater than the dar (i.e. >10co/1000m), then:
If the environmental lapse rate (ELR) of the atmosphere surrounding a rising parcel of air is greater than the dry adiabatic rate (DAR) of 10°C/1000m, certain conditions and phenomena can be inferred.
When the ELR is steeper than the DAR, it indicates a condition of instability in the atmosphere.
This means that the surrounding air cools at a faster rate than a rising parcel of air would if it were undergoing adiabatic cooling.
As a result, the parcel of air becomes warmer compared to its surroundings, making it less dense and causing it to continue rising.
The steep ELR exceeding the DAR signifies an environment conducive to the development of convective processes such as thunderstorms, cumulus clouds, and other forms of unstable atmospheric phenomena.
The increased lapse rate creates an environment where the parcel of air continues to rise and can reach higher altitudes, potentially leading to the formation of significant weather events and atmospheric instability.
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When steam condenses
a. it changes from the gas phase to the liquid phase.
b. it gives off heat.
c. molecules move closer together.
d. all of the above occur.
Answer:
all of the above?
Explanation:
I think that is
When a wave strikes and object and bounces off . ( example echo)
A. Medium
B. Refraction
C.Reflection
D. Interference
Answer:
C. reflection
Explanation:
reflection occurs when a wave strikes an object and bounces off of it
When a wave strikes an object and bounces off, it is called reflection.
Hence, the correct option is C.
This is similar to what happens when sound waves strike a surface and bounce back, resulting in an echo.
Reflection occurs when a wave encounters a boundary or an obstacle and changes direction, returning back into the medium it came from.
The angle of incidence (the angle at which the wave strikes the surface) is equal to the angle of reflection (the angle at which the wave bounces off the surface).
Therefore, When a wave strikes an object and bounces off, it is called reflection.
Hence, the correct option is C.
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a stone is thrown straight upward and at the top of its path is velocity is momentarily zero what is its acceleration at that point
When a stone is thrown straight upward and at the top of its path, its velocity is momentarily zero. The acceleration at that point is equal to the acceleration due to gravity, which is approximately 9.81 m/s².
Why is the acceleration at the top of its path due to gravity? The acceleration of the stone is due to gravity because gravity is the only force acting on it at that point. As the stone moves upward, gravity slows it down until it comes to a complete stop at the top of its path. At that point, the stone changes direction and begins to fall back to the ground under the influence of gravity. Therefore, the acceleration at the top of its path is equal to the acceleration due to gravity.
What is the formula for acceleration due to gravity?
The formula for acceleration due to gravity is: a = GM/r²
Where: a = acceleration due to gravity, G = gravitational constant, M = mass of the object attracting the stone (in this case, the mass of the Earth), r = distance between the stone and the center of the Earth (radius of the Earth in this case)
However, in most cases, we can use the average value of acceleration due to gravity, which is 9.81 m/s². This is because the acceleration due to gravity is almost constant at the surface of the Earth.
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What does the force of gravity do for us?
Answer:
Earth's gravity is what keeps you on the ground and what makes things fall. Anything that has mass also has gravity. Objects with more mass have more gravity.
Explanation:
Suppose the tilt of Earth's equator relative to its orbit were 30 ° instead of 23.5°. At what latitudes would the Arctic and Antarctic Circles be located?
_____ degrees latitude
The new position of the Arctic and Antarctic Circles would be located at 30° North and 30° South, respectively.
If the tilt of Earth's equator relative to its orbit were 30° instead of 23.5°, the location of the Arctic and Antarctic Circles would be affected. The Arctic Circle is defined as the latitude above which the sun does not set on the summer solstice and does not rise on the winter solstice. The same applies to the Antarctic Circle but in the Southern Hemisphere.
Currently, the Arctic Circle is located at 66.5° North and the Antarctic Circle is located at 66.5° South. If the tilt of Earth's equator relative to its orbit were 30°, the position of the Arctic and Antarctic Circles would be closer to the equator.
To determine the new position of the Arctic and Antarctic Circles, we can use the following formula:
θ = 90° - ϕ
where θ is the angle between the axis of rotation and the line perpendicular to the plane of the ecliptic, and ϕ is the tilt of the Earth's axis relative to the plane of the ecliptic.
If the tilt were 30°, then θ would be:
θ = 90° - 30° = 60°
Therefore, the new latitude of the Arctic and Antarctic Circles would be:
ϕ = 90° - 60° = 30°
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The new position of the Arctic and Antarctic Circles would be located at 30° North and 30° South, respectively.
If the tilt of Earth's equator relative to its orbit were 30° instead of 23.5°, the location of the Arctic and Antarctic Circles would be affected. The Arctic Circle is defined as the latitude above which the sun does not set on the summer solstice and does not rise on the winter solstice. The same applies to the Antarctic Circle but in the Southern Hemisphere.
Currently, the Arctic Circle is located at 66.5° North and the Antarctic Circle is located at 66.5° South. If the tilt of Earth's equator relative to its orbit were 30°, the position of the Arctic and Antarctic Circles would be closer to the equator.
To determine the new position of the Arctic and Antarctic Circles, we can use the following formula:
θ = 90° - ϕ
where θ is the angle between the axis of rotation and the line perpendicular to the plane of the ecliptic, and ϕ is the tilt of the Earth's axis relative to the plane of the ecliptic.
If the tilt were 30°, then θ would be:
θ = 90° - 30° = 60°
Therefore, the new latitude of the Arctic and Antarctic Circles would be:
ϕ = 90° - 60° = 30°
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2.2 Represent and Reason Blocks 1 and 2 are suspended from the ends of a light string hung over two very light pulleys. If blocks 1 and 2 are of equal mass predict what will happen if they are released from the same vertical position. From different positions
The equal mass of blocks are released from the same vertical position does not produce tension whereas, released from different position causes acceleration due to tension developed in the string.
Does a string's tension produce any results?An internal force is responsible for the string's tension. Due to the fact that it has no impact on the system, it need not be taken into account. If the string were extensible, it would be necessary to account for this force, for example by incorporating the elastic potential energy the string contains.
What does a pulley block mean?Several pulleys or sheaves installed on a single frame make up a block. Tackle is a grouping of blocks with a rope woven through the pulleys. Reeving is the process of threading cables or ropes through obstacles, and a threaded block and tackle is referred to as "rove."
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Can you somebody answer this question for me please?
Answer:
The answer is B - the bending of rock layers happens due to stress, and this process is called folding. Faults are when it looks broken/displaced
because the direction of earth's motion around the sun continually changes during the year, the apparent position of a star in the sky moves in a small loop, known as the aberration of starlight. in order to better understand this phenomenon, it is sometimes helpful to use visual analogies. in these visual analogies, the car is analogous to the earth, and the rainfall is analogous to starlight. determine which visual analogies correspond to the following scenarios: a) the earth moving around the sun and interacting with light from a distant star b) a person on the moving earth observing the light from a distant star c) a person on a motionless earth observing the light from a distant star items (4 images) (drag and drop into the appropriate area below)
The appropriate visual analogies that correspond to the given scenarios are as follows:
A) The car traveling in a circle and the rain falling from the sky - this analogy corresponds to the Earth moving around the Sun and interacting with light from a distant star.
B) The car traveling in a straight line and the rain falling from the sky - this analogy corresponds to a person on the moving Earth observing the light from a distant star.
C) The car is stationary and the rain falls from the sky - this analogy corresponds to a person on a motionless Earth observing the light from a distant star.
What is a star?
As we know that the direction of the earth's motion around the sun continually changes during the year, and the apparent position of a star in the sky moves in a small loop, known as the aberration of starlight. Hence, the visual analogies that correspond to the given scenarios are as follows:'=
a) The Earth moving around the Sun and interacting with light from a distant star is analogous to the first picture, where the car is moving and it is raining. This visual analogy explains that when the Earth moves around the Sun and interacts with light from a distant star, it results in a small loop of light in the sky.
b) A person on the moving Earth observing the light from a distant star is analogous to the second picture, where a person is sitting inside the moving car and looking at the rain. This visual analogy explains that when a person is on the moving Earth and observes the light from a distant star, it creates an illusion in the sky.
c) A person on a motionless Earth observing the light from a distant star is analogous to the third picture, where a person is standing outside the car and looking at the rain. This visual analogy explains that when a person is on a motionless Earth and observes the light from a distant star, it appears as if the star is moving in a small loop in the sky.
Therefore, the appropriate visual analogies that correspond to the given scenarios are as follows: Image 1: The Earth moving around the Sun and interacting with light from a distant star image 2: A person on the moving Earth observing the light from a distant star image 3: A person on a motionless Earth observing the light from a distant star.
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50 POINTS!
Look at the HR diagram below with four stars labeled. The HR diagram is shown with absolute brightness on the vertical axis and surface temperature in degree Celsius on the horizontal axis. The dwarf stars are plotted along a slant from coordinates 30,000 and negative 3 to 10,000 and negative 4. The main sequence stars are plotted along a slant from coordinates 20,000 and negative 2 to 2,000 and negative 6. The giants are plotted horizontally from coordinates 5,000 and 2 to 2,000 and 3. The supergiants are plotted horizontally from coordinates 7,500 and 4 to 2,500 and 4. Four stars are plotted: A is at 20,000, negative 4, B is at 2,500, negative 4, C is at 5,000, 2, and D is at 6,000, 4. Which statement is correct about Star A and Star C? They have the same color because they are neighboring stars. They have the same brightness because they are neighboring stars. They have different colors because they have different temperatures. They have different brightness because they are the same size.
The correct statement is that "They have different colors because they have different temperatures."
What are supergiant stars?
The most massive and brightest stars are known as supergiants. Supergiant stars range in temperature from roughly 3,400 kelvin to over 20,000 kelvin, whereas their absolute visual magnitudes range from 3 to 8.
In light of this, we may say that supermassive stars are a particular form of a star with an absolute brightness of about 3 and a surface temperature of about 20,000 °C.
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3. Calculate the speed for a car that went a distance of 155 kilometers in 3 hours
Answer:This is an explanation
for 150 km its all ik i tried hard ty
Explanation:The car covers 150 km in 3 hours or 3*60 = 180 minutes.
So in 12 min the car will cover (12/180)*150 = 10 km.
Answer:
The average speed would be the distance covered divided by the time. In this case, (130 km)/(2 hours) = 65 km/hour. Note that you didn't ask for the average speed, just the speed
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
m ahead. The ranger, who is driving at 11.4 m/s, immediately applies the brakes and
slows down with an acceleration of 3.80 m/s2. How much distance is required for the
ranger's vehicle to come to rest? Only enter the number, not the units.
Answer:
17.1
Explanation:
The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m
The initial speed with which the ranger was driving, u = 11.4 m/s
The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)
The distance required for the ranger to come to rest, s = Required
The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;
v² = u² + 2·a·s
∴ s = (v² - u²)/(2·a)
Where;
v = The final velocity = 0 m/s (the vehicle comes to rest (stops))
Plugging in the values for 'v', 'u', and 'a', gives;
s = (0² - 11.4²)/(2 × -3.8) = 17.1
The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).
what is the approximate depth of the ocean floor at point a? at point c?
I have to get it done right now.. it is pass due
Answer:
3,688 meters (12,100 feet)
Explanation:
he deepest part of the ocean is called the Challenger Deep and is located beneath the western Pacific Ocean in the southern end of the Mariana Trench, which runs several hundred kilometers southwest of the U.S. territorial island
If I apply an acceleration for (2.440x10^0) seconds of (5.68x10^0) m/s2 when I hav an initial velocity of +(3.5200x10^0) m/s, what final velocity do I have?
The final velocity is approximately 1.74272 × 10¹ m/s.
To find the final velocity, we can use the kinematic equation:
v = u + at,
where
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.
Given:
Initial velocity (u) = + 3.5200 × 10 m/s
Acceleration (a) = 5.68 × 10 m/s²
Time (t) = 2.440 × 10 seconds
Substituting these values into the equation, we have:
v = 3.5200 × 10 m/s + 5.68 × 10 m/s² × 2.440 × 10 seconds.
v = (3.5200 + 5.68 × 2.440) × 10 m/s.
v = (3.5200 + 13.9072) × 10 m/s.
v = 17.4272 × 10 m/s.
v = 1.74272 × 10¹ m/s.
Therefore, the final velocity is approximately 1.74272 × 10¹ m/s.
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HELP THIS IS DUE TODAY who ever answers first (correctly and gives explanation will get brainly)
How much power does a cordless phone use if it draws 0.50 A of current at 6.0 V?
i need it in watts so please write it in forms of Watt
Answer:
3.0 W
I actually had this question before BUT I have no clue how to explain it. I haven't done this in so long. I apologize but that is the correct answer.
Answer:3.0 W
Explanation:
P=VI
P= (6.0 V) (5.0 A)
P= 3.0 W
What is so unique about the mirrors of telescopes such as the Keck Observatory, Gran Telescopio Canaries, and the soon-to-be-built Giant Magellan Telescope?
The mirrors of the Keck Observatory, Gran Telescopio Canarias, and the Giant Magellan Telescope are all segmented, meaning they are made of multiple individual mirrors that together form a larger mirror.
New giant telescopesThe mirrors of telescopes such as the Keck Observatory, Gran Telescopio Canarias, and the soon-to-be-built Giant Magellan Telescope are unique because they are made up of segmented mirrors. The shape of the mirror created by these individual mirrors allows them to collect more light than traditional telescope mirrors, allowing for higher resolution and greater accuracy.
These segmented mirrors are also unique because they can be adjusted to change the shape of the overall mirror. This allows for the correction of distortions caused by the Earth's atmosphere and provides clearer, more accurate images.
The Keck Observatory, for example, uses 36 hexagonal segmented mirrors to create a single 10-meter mirror. The Gran Telescopio Canarias uses 36 segmented mirrors to create a 10.4-meter mirror. The Giant Magellan Telescope, which is currently under construction, will use seven 8.4-meter mirrors to create a single 24.5-meter mirror.
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a = 5 m/s2, F = 100 N. m = ?
Answer:
20 kg
Explanation:
F = ma
m - mass in kilograms
a = acceleration
F = force
A kid walks 500 m North and then 300 m south.
a. What is the distance of his walk?
b. What is the displacement of his walk?
Explanation:
for the walking distance it did not matter in what direction the kid walked.
a. the distance of the walk is 500 + 300 = 800 m
b. the kid ended up 500-300=200 m north of the original point.
In a student-designed experiment, a 4 kg bowling ball is pushed with a broom using an applied force of 10 N. If the friction force on the bowling ball is 1 N, what will be the acceleration of the ball?
Answer:
a = 2.25 m/s^2
Explanation:
The solution is in the image. Also, knowing this picture is from a Schoology assessment page, if this is a test, try to solve the question yourself before asking for help. Also, specify which part you need help on.
During the formation of the Solar System, smaller particles in the solar nebula combined to form planetesimals, some of which provided the building blocks for planets. The majority of planetesimals did not become planets, however, and some of them remain in the Solar System today as debris left over from the time of planet formation. Asteroids are a special class of planetesimals that orbit around the Sun. Study the distribution of known asteroids shown in this figure, and choose all of the statements below that match your observations. Choose one or more: A. All of the asteroids exist in a region between Jupiter and Mars B. Some asteroids cross Earth's orbit as they orbit around the Sun C. The majority of asteroids exist in a region between Jupiter and MarsD. Asteroids have been discovered as tar out as PlutoE. There are dumps of asteroids that existat particular spots in Jupiter's orbit IF The majority of asteroldsedstinside of Mars orbit EG Asteroids are randomly distributed throughout the Solar System
Some meteorites cross Solar system as they revolve around the Sun, while others form clusters at certain locations in Jupiter's orbit. The bulk of asteroids are located in the space between Jupiter the Mars.
Where are the asteroids?Half way between Venus and Mars' orbits, the Solar System's asteroid belt seems to be a torus-shaped zone. It comprises a large number of asteroids or minor planets, which are rocky bodies with variable shapes and sizes that are significantly smaller than planets.
What factors lead to asteroids?Asteroids are remains of the solar system's creation, which occurred around billion years ago. Early on, Jupiter's creation prevented additional planetary bodies from growing in the space between Asteroid belts, leading the small particles that did exist to collide with one another and disintegrate into the asteroids we know today.
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A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?
(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.
(2) The velocity of the center of mass at position 2.
(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.
The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.
(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.
Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.
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if the bill is vetoed
Answer:
Explanation:
A vote is maybe a vote
Two charged particles are a distance of 1.82 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.14 nC.
The magnitude of the electric force is(F) \(79.07\times 10^{-9}\) N and the electric force between the charges is repulsive.
How can we calculate the magnitude of the electric force?To calculate the magnitude of the electric force that one particle exerts on the other, we are using the formula,
\(F=k\frac{q_{1} q_{2} }{r^{2} }\)
Here we are given,
\(q_1\)= Charge of the first particle= 7.03nC = \(7.03\times 10^{-9}\) C.
\(q_2\)=Charge of the second particle = 4.14nC= \(4.14\times 10^{-9}\) C.
r= The distance between two charges=1.82m.
k= Constant of proportionality= \(\frac{1}{4\pi \epsilon}\)=\(9\times 10^{9} Nm^{2} /C^{2}\)
Now we put the known values in the above equation, we get
\(F=k\frac{q_{1} q_{2} }{r^{2} }\)
Or,\(F=9\times 10^{9} \times \frac{7.03\times 10^{-9}\times 4.14\times 10^{-9} }{(1.82)^{2} }\)
Or, F= \(79.07\times 10^{-9}\) N.
From the above calculation we can conclude that the magnitude of the electric force(F) is \(79.07\times 10^{-9}\) N.
Charges \(q_1\) and \(q_2\) is \(79.07\times 10^{-9}\) C and \(4.14\times 10^{-9}\)C respectively, Both charges are positive and have same polarity. The force between the same charges is repulsive.
Thus, we can conclude that, the electric force between the charges is repulsive.
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Disclaimer: The question was given incomplete in the portal. Here is the complete question.
Question: Two charged particles are a distance of 1.82 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.14 nC.
What is the magnitude of the electric force that one particle exerts on the other?Is the force attractive or repulsive?Observa a tu alrededor y escribe el nombre de diez objetos que se encuentren en movimiento, Luego escribe el de otros diez que pienses que se encuentran en reposo. ¿Qué criterio tuviste en cuenta para considerar que están en reposo?
Answer:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
Explanation:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
There are four coils of wire being used as electromagnets. They all have the same size and are made up of the same material but have a different number of loops. Which coil will produce a magnetic field with the maximum strength when the same amount of current passes through all coils?a coil having 10 loopsa coil having 25 loopsa coil having 30 loopsa coil having 45 loops
Answer:
A coil having 45 loops
Explanation:
The strength of an electromagnet is proportional to the number of loops. So, when we have more loops, we will get mor strength. It means that the coil that will produce a magnetic field with the maximum strenght is a coil having 45 loops because 45 is the greatest number in the list.
A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final speed of 25 m/s?
Answer:
\(\Large \boxed{\mathrm{5.67 \ seconds }}\)
Explanation:
\(\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}\)
\(\displaystyle A \ = \ \frac{V_f - V_i }{t}\)
\(\displaystyle 3 \ = \ \frac{25 - 8 }{t}\)
\(\displaystyle 3 \ = \ \frac{17 }{t}\)
\(\displaystyle t \ = \ \frac{17 }{3} \approx 5.67\)