A man pushes a 10 kg block on a straight horizontal road by applying


a force of 5 N. As a result, he moves the block a distance of 10 meters


with an acceleration of 0. 2 m/s2. Calculate the work done by the


man on the block during motion.

Answer:

Avion A (10000 meters).

Explanation:

Deje que la altura de los aviones sea A y B respectivamente.

Dados los siguientes datos;

Altura A = 10000 metros

Altura B = 33300 pies

Para encontrar el avión que voló más alto, tendríamos que hacer alguna conversión de unidades.

Conversión:

Metros a centímetros;

1 metro = 100 cm

10000 metros = 100 * 10000 = 1.000.000 centímetros.

Por lo tanto, la altura A en cm = 1,000,000 centímetros

Pies a centímetros;

1 pie = 30,48 centímetros

33300 pies = 33300 * 30,48 = 1014984 centímetros.

Por lo tanto, la altura B en cm = 1014984 centímetros.

De los cálculos anteriores, podemos deducir que el avión A voló más alto.

When high-key lighting is used, characters and figures are clearly lit with bright images. High-key lighting is a lighting technique characterized by a predominance of light tones and minimal shadows.

It involves using an abundance of light sources or high-intensity lighting to evenly illuminate the scene, resulting in a well-lit and cheerful ambiance.

High-key lighting is commonly employed in genres such as comedies, romantic films, and musicals, where a bright and upbeat atmosphere is desired.

By reducing the contrast between light and shadow, high-key lighting creates a sense of openness, positivity, and a visually pleasing aesthetic, allowing the audience to focus on the characters and their expressions without distractions caused by dark or dramatic lighting.

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The observed frequency will be greater than the source’s frequency (option - A) is correct answer.

If the source and observer are moving simultaneously in either case—moving observer or moving source—you'll notice that the frequency increases. The frequency decreases if they are drifting apart. Whether the source is moving or the observer is moving will affect how much the frequency changes.

Although the waves move at the same speed, the frequency that is observed is affected by any relative movement between the source and the observer. The wavelength changes along with the observed frequency. When an observer and a source are moving in the same direction, the frequency rises and the wavelength falls.

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The deposit would contain approximately 4.10 × 10\(^ 32\) kg of iron.

(a) The magnetic moment of an atom is given by the Bohr magneton, μB:

μB = eh/4πm

where e is the electron charge, h is Planck's constant, and m is the mass of the electron.

The magnetic moment of an atom with unpaired electrons is the sum of the magnetic moments of the unpaired electrons. For iron, the number of unpaired electrons can be determined from its electron configuration, which is [Ar]\(3d^6 4s^2\). This means that there are four unpaired electrons per iron atom, since the 3d subshell has a maximum of ten electrons and the 4s subshell has two.

Thus, the number of unpaired electrons that would participate in the magnetization of the iron deposit is:

number of unpaired electrons = (number of iron atoms/m3) x (4 unpaired electrons/iron atom)

=\(8.50 × 10^28 x 4\\= 3.40 × 10^29 unpaired electrons\)

(b) The mass of iron per unit volume of the deposit can be calculated using the density of iron and Avogadro's number:

= (\(4.75 × 10^27 kg/m^3) x [(8.00 × 10^22 A · m^2)/(9.27 × 10^-24 A · m^2/\)magnetic moment of one iron atom)]

= 4.10 × \(10^32\) kg

Therefore, the deposit would contain approximately 4.10 × 10\(10^32\) kg of iron.

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\(\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}} \)

The speed of the ball seven seconds later is 28.6 m/s.

We have the following information;

initial velocity of the ball = 40 m/s

time taken = 7 seconds

Acceleration of the ball = 9.8 m/s^2

Now;

v = u - gt (the ball is moving upwards)

v = 40 - (9.8 * 7)

v = 28.6 m/s

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Answer:

Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.

Explanation:

Hope its helps you ✌️

Explanation:

It is given that,

Object distance from the mirror, u = -30 cm

Focal length of the mirror, f = +15 cm

Size of the object, h = 7.5 cm

We need to find the image distance and the size of the image.

Mirror's formula, \(\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\)

v is image distance

\(\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(15)}-\dfrac{1}{(-30)}\\\\v=10\ cm\)

Let h' is the size of the image. So,

\(\dfrac{h'}{h}=\dfrac{-v}{u}\\\\h'=\dfrac{-vh}{u}\\\\h'=\dfrac{-10\times 7.5}{-30}\\\\h'=2.5\ cm\)

So, the image is located at a distance of 10 cm and the size of the image is 2.5 cm.

(a) The center of mass of the system is 1.26 m.

(b) If the man walks to the right edge of the boat, the center of mass of the system is unchanged, 1.26 m.

(c) After walking to the right edge of the boat, the man has moved 2.53 m from his original location.

(d) After walking to the right edge of the boat, the new location center of the boat is 0.88 m.

(e) The man ends up at 1.26 m.

A man stands at the left end of a uniform boat. The coordinate system is the man's original location as shown in the picture and we assume that there is no friction or drag between the boat and water. The picture is in the attachment.

The man's location is at x₁ = 0.

The center of the boat is at x₂ = L/2 = 1.65 m.

(a) The center of mass of the system would be

x₀ = (m₁x₁ + m₂x₂)/(m₁ + m₂)

x₀ = [51(0) + 168(1.65)]/(51 + 168)

x₀ = 277.2/219

x₀ = 1.26 m

(b) If the man walks to the right edge of the boat, the center of mass of the system would remain the same. This is because there is no friction between the boat and water. So, it would be 1.26 m.

(c) After walking to the right edge of the boat, the illustration of the man's location is shown in the attachment!

x₂ = x₁ - 1.65

The man's location (x₁) is at

x₀ = (m₁x₁ + m₂x₂)/(m₁+m₂)

1.26 = (51x₁ + 168(x₁ - 1.65)/(51+168)

1.26 = (51x₁ + 168x₁ - 277.2)/219

275.94 = 219x₁ - 277.2

553.14 = 219x₁

x₁ = 2.53 m

(d) The new location of the center of the boat is

x₂ = x₁ - 1.65

x₂ = 2.53 - 1.65

x₂ = 0.88 m

(e) If he walks to the very center of the boat, he would end up at the center of mass of system, at 1.26 m. The center of mass is unchanged as explained in point b.

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The law of conservation of mass states that matter cannot be created or destroyed, only changed from one form to another.

The law of conservation of mass is a fundamental principle in chemistry that states that matter cannot be created or destroyed in a closed system.

This means that the total mass of the reactants in a chemical reaction must equal the total mass of the products. In other words, the mass of the substances before the reaction must be equal to the mass of the substances after the reaction.

This law is also sometimes called the law of mass conservation or the law of matter conservation.

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If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.

Matter :

A substance called matter is made up of different kinds of particles, occupies space, and has inertia.

The various types of particles each have a unique mass and size according to the fundamentals of modern physics.

Antimatter :

As the opposite particles of the corresponding particles in "ordinary" matter, the antimatter is defined as matter made up of them.

The two particles' combined mass is entirely converted into energy. The term "matter-antimatter annihilation" refers to this process.

If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.

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Answer:

The first case requires more force to spin de bucket.

Explanation:

As we know, the centripetal force is directly proportional to the mass, the equation is given by:

\(F_{c}=ma_{c}\)

The first case has a quarter more water than the second case, therefore the first case requires more force to spin de bucket.

I hope it helps you!

The displacement of train moves is s = 147.68m.

To calculate the displacement train moves using the formula of equation of motion,

s = 1/2 ( u + v ) t

Where,

s is displacement

u is initial velocity

v is final velocity

t is time

Given data :

u = 4.82 m/s

v = 7.09 m/s

t = 24.8 s

s = ?

Now, putting the values in equation we get,

s = 1/2 (  4.82 m/s + 7.09 m/s ) 24.8 s

s  = 1/2 x 11.91 m/s x 24.8 s

s = 147.68 m

Hence, the displacement of train moves is s = 147.68m.

The fundamental equation of motion in classical mechanics is Newton's second law, which declares that the force F acting on a body is equal to that body's mass m times its center of mass's acceleration a, or F = ma.

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As the turntable spins faster, the penny that is furthest from the turntable's centre will slide first.

Centripetal force increases as the turntable spins faster, exerting more force on the pennies. The centripetal force is proportional to the angular velocity squared and the angle of deflection from the turntable's centre. In other words, the penny that is farther away from the turntable's centre experiences a stronger centripetal force than the penny that is closer to it.

With the centripetal force, the frictional force between the pennies and the turntable likewise grows. Nevertheless, the coefficient of static friction—a feature of the surface where the pennies and turntable are placed—limits the frictional force. For the penny that is nearer to the turntable's centre than for the coin that is farther away, the coefficient of static friction

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The frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

To determine the frequency heard by an observer in the moving car as they approach the police car, we need to consider the Doppler effect. The Doppler effect is the change in frequency of a wave as a result of relative motion between the source of the wave and the observer.

The speed of sound in air is given as 343 m/s.

The velocity of the car approaching the police car is 36 m/s.

The frequency of the siren (relative to the police car) is 500 Hz.

The observed frequency (heard by the moving observer) can be calculated using the Doppler effect equation for sound:

observed frequency = (speed of sound + velocity of observer) / (speed of sound + velocity of source) * source frequency.

Plugging in the given values:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 500 Hz

≈ 1.181 * 500 Hz

≈ 590.5 Hz.

Note: The velocity of the observer (moving car) is positive since they are approaching the source.

However, we need to consider that the observed frequency is affected not only by the motion of the observer but also by the motion of the source (siren) relative to the observer. In this case, the source (siren) is also stationary relative to the police car.

Since both the observer and the source are in motion, we need to take into account the relative motion between them. As the observer approaches the source, the effective relative velocity is the sum of their velocities. In this case, the effective relative velocity is 36 m/s.

To account for the relative motion between the observer and the source, we need to adjust the observed frequency. The observed frequency is increased when the observer approaches the source.

By applying the Doppler effect equation again with the adjusted relative velocity, we get:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 590.5 Hz

≈ 1.181 * 590.5 Hz

≈ 696.5 Hz.

Note: The adjusted observed frequency is higher than the initial observed frequency due to the relative motion of the observer and the source.

Therefore, the frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

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Answer:

Accurate at 99.9999746%

Explanation:

First of all, let's calculate how many seconds we have in a year which has 365 days.

1day = 24 × 60 × 60 seconds = 86400 s

Thus, for 365 days, we have;

86400 × 365 = 31536000 seconds

Now, since 1 year has 31536000 seconds, let's find the ratio of efficiency.

We are told that the watch manufacturer claims that its watches gain or lose no more than 8 seconds in a year. Thus, efficiency is given by;

Efficiency = (8/31536000) × 100% = 0.00002536783 %

Thus, it will be be accurate at;

100% - 0.00002536783% ≈ 99.9999746%

a. To determine the magnitude of the magnetic field at the center of the coil, we can use the formula for the magnetic field produced by a current-carrying coil: B = (μ₀ * N * I) / (2 * R),

where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), N is the number of turns in the coil, I is the current flowing through the coil, and R is the radius of the coil.

Given:

Number of turns (N) = 100

Current (I) = 3.5 A

Diameter (d) = 6.0 mm = 0.006 m

Radius (R) = d / 2 = 0.006 m / 2 = 0.003 m

Plugging these values into the formula, we get:

B = (4π × 10⁻⁷ T·m/A) * (100 turns) * (3.5 A) / (2 * 0.003 m)

B ≈ 0.0739 T

Therefore, the magnitude of the magnetic field at the center of the coil is approximately 0.0739 Tesla.

b. The direction of the force on a positive ion in the water above the center of the coil can be determined using the right-hand rule for magnetic fields. When the current is flowing through the coil in a certain direction, the magnetic field lines around the coil will also follow a specific pattern.

In this case, the current is flowing horizontally through the coils, producing a magnetic field directed downward. The water is flowing eastward above the center of the coil. By applying the right-hand rule, if we point the thumb of our right hand in the direction of the water flow (east), and the fingers in the direction of the magnetic field (downward), the palm will face in the direction of the force experienced by a positive ion. Therefore, the force on a positive ion will be directed south.

c. The magnitude of the force on an ion with a charge +ee can be determined using the formula:

F = q * (v * B) * sin(θ),

where F is the force, q is the charge of the ion (+ee), v is the velocity of the ion (1.5 m/s), B is the magnitude of the magnetic field (0.0739 T), and θ is the angle between the velocity vector and the magnetic field vector.

In this case, the water is flowing eastward, and the magnetic field is directed downward. Therefore, the angle θ between the velocity and magnetic field vectors is 90 degrees, resulting in sin(θ) = 1.

Plugging in the values, we get:

F = (+ee) * (1.5 m/s) * (0.0739 T) * (1)

F = 0.11085 * ee N

Therefore, the magnitude of the force on an ion with a charge +ee is approximately 0.11085 times the elementary charge (ee).

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Answer:

Cytokinesis occurs differently in animal and plant cells. In animal cells, the plasma membrane of the parent cell pinches inward along the cell's equator until two daughter cells form. In plant cells, a cell plate forms along the equator of the parent cell.

Explanation:

Explanation:

The pascal (symbol: Pa) is the SI derived unit of pressure used to quantify internal pressure, stress, Young's modulus and ultimate tensile strength. It is defined as one newton per square metre. It is named after the French polymath Blaise Pascal

Pressure vs. Depth Lab:

Pressure is defined as the force per unit area applied on an object. It is a scalar quantity, which means it only has magnitude and no specific direction.

It is often measured in units of Pascals (Pa), which is equivalent to one Newton of force per square meter of area. Pressure can be caused by the weight of an object, the force applied by a fluid, or the collision of particles with a surface.

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Finding a suitable material for the filament of an incandescent light bulb was one of Thomas Edison's biggest obstacles.

The source of light in an incandescent light bulb is the filament, which is a wire-like structure. It is often constructed of tungsten or another material with a high melting point and good thermal shock resistance. When an electric current is sent through the filament, which is commonly twisted into a coil or loop shape, the filament heats up and starts to generate light.

Thermal radiation causes the filament to produce light. This is the result of the filament's temperature-related electromagnetic radiation output. The filament starts to emit infrared radiation and visible light as it warms up.

The filament's temperature and the kind of material it is constructed of affect the hue of the light it emits.

A glass bulb that has been evacuated or a bulb that has been filled with an inert gas, such as argon or nitrogen, surrounds the filament in an incandescent light bulb. By doing this, you can avoid the filament from burning out or breaking, which would make the lightbulb unusable.

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Answer: 1*10^3 mm^3

That’s it

Answer:

The depth of the object below the surface of the liquid is 0.510 meters.

Explanation:

The hydrostatic pressure (\(P\)), measured in pascals, experimented by the object is directly proportional to density of the fluid (\(\rho\)), measured in kilograms per cubic meter, gravitational acceleration (\(g\)), measured in meters per square second, and depth of the object (\(h\)), measured in meters. That is:

\(P = \rho\cdot g \cdot h\) (1)

If we know that \(P = 4500\,Pa\), \(\rho = 900\,\frac{kg}{m^{3}}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the depth of the object is:

\(h = \frac{P}{\rho\cdot g}\)

\(h = \frac{4500\,Pa}{\left(900\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(h = 0.510\,m\)

The depth of the object below the surface of the liquid is 0.510 meters.

The depth of the object below the liquid's surface will be

"0.510 m".

According to the question,

Object immersed, P = 4500 Pa

Density of liquid, ρ = 900 kg/m³

Acceleration due to gravity, g = 9.8 m/s²

We know the relation,

→ Hydrostatic pressure (P) = ρ.g.h

or,

Depth will be:

→ h = \(\frac{P}{\rho .g}\)

By substituting the values,

     = \(\frac{4500}{900\times 9.8}\)

     = \(\frac{4500}{8820}\)

     = 0.510 m

Thus the above answer is appropriate.  

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Answer:

48

Explanation:

you basically divide 1200 into 25

The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.

This can be defined as the ratio of displacement to the time of a body

To calculate the initial velocity of the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the initial velocity of the car is 11.5 m/s

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Answer:

The object sped up.

The object changed directions.

Explanation:

Just got the question correct.

Answer:

A & D

The object sped up

The object changed direction

Explanation:

:)

Answer:

F1 = G M1 m / x^2       gravitational force on test mass m due to M1

F2 = G M2 m / (R - x)^2       gravitational force on test mass m due to M2

M1 / x^2 = M2 / (R - x)^2

(R - x)^2 / x^2 = M2 / M1

(R - x) / x = (M2 / M1)^1/2     where x is distance from M1 and R is total distance between objects

Check:     x = R / 2 then M1 = M2 as it should

As well as these benefits, reuse eliminates the environmental damage that would have been caused if the item had been disposed of, rather than reused. In contrast, manufacturing a product from raw materials (and, to a lesser extent, recycling) consumes resources, causes pollution and generates wastes.

The net work done on the bale of hay as it is pulled a horizontal distance of 15 m is approximately 560.40 Joules.

Let's break down the problem step by step.

We have an applied force of 140 N at an angle of 28° above the horizontal. First, we need to determine the vertical and horizontal components of this force.

Vertical component:

F_vertical = F * sin(θ) = 140 N * sin(28°) ≈ 65.64 N

Horizontal component:

F_horizontal = F * cos(θ) = 140 N * cos(28°) ≈ 123.11 N

Now, let's consider the forces acting on the bale of hay:

1. Gravitational force (weight): The weight of the bale is given by

W = m * g,

where

m is the mass (35 kg)

g is the acceleration due to gravity (9.8 m/s²). Therefore,

W = 35 kg * 9.8 m/s² = 343 N.

2. Normal force (N): The normal force acts perpendicular to the floor and counteracts the gravitational force. In this case, the normal force is equal to the weight of the bale, which is 343 N.

3. Frictional force (f): The frictional force can be calculated using the formula

f = μ * N,

where

μ is the coefficient of friction (0.25)

N is the normal force (343 N).

Thus, f = 0.25 * 343 N

= 85.75 N.

Next, we need to determine the net work done on the bale of hay as it is pulled horizontally a distance of 15 m. Since the frictional force opposes the applied force, the net work done is equal to the work done by the applied force minus the work done by friction.

Work done by the applied force:

W_applied = F_horizontal * d

= 123.11 N * 15 m

= 1846.65 J

Work done by friction: W_friction = f * d

= 85.75 N * 15 m

= 1286.25 J

Net work done: W_net = W_applied - W_friction

= 1846.65 J - 1286.25 J

= 560.40 J

Therefore, the net work done on the bale of hay as it is pulled a horizontal distance of 15 m is approximately 560.40 Joules.

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