A man having a weight of 176 lb attempts to hold himself using one of the two methods shown. Determine the total force he must exert on bar AB in each case and the normal reaction he exerts on the platform at C. The platform has a weight of 31 lb. (Figure 1) Determine the total force the man must exert on bar AB using the first method. Express your answer to three significant figures and include the appropriate units Determine the normal reaction the man exerts on the platform at C using the first method. Express your answer to three significant figures and include the appropriate units. Determine the total force the man must exert on bar AB using the second method. Express your answer to three significant figures and include the appropriate units.

When air undergoes adiabatic expansion, the process is governed by the equation PV^γ = constant, where γ is the ratio of specific heats. In this case, the value of γ for air is 1.4. We are given that one pound of air undergoes an adiabatic expansion from 200 psia to 50 psia, with an initial volume of 4 ft3/lbm and PV^1.4 = constant.

Let's calculate the final volume of the air using the initial and final pressures and the initial volume. Using the formula P1V1^γ = P2V2^γ and substituting the given values, we have: 200(4)^1.4 = 50(V2)^1.4V2 = (200(4)^1.4 / 50)^(1/1.4)V2 = 11.14 ft^3/lbmThe work done by the air is given by the equation W = ∆E + Q, where ∆E is the change in internal energy and Q is the heat added to or removed from the system. Since the process is adiabatic (Q = 0), the work done is equal to the change in internal energy. Let's calculate the work done:W = ∆E = C_v (T2 - T1)where C_v is the specific heat at constant volume, and T1 and T2 are the initial and final temperatures, respectively. The specific heat at constant volume for air is 0.1715 Btu/lbm·R. Let's calculate the final temperature of the air using the initial and final pressures and volumes and the equation P1V1^γ/T1 = P2V2^γ/T2.200(4)^1.4/T1 = 50(11.14)^1.4/T2T2 = T1 * (P2V2^γ / P1V1^γ)T2 = 1183.3 RLet's substitute the values into the equation for work done to get:W = C_v (T2 - T1)W = 0.1715 Btu/lbm·R (1183.3 R - 527.7 R)W = 0.1715 Btu/lbm·R (655.6 R)W = 112.3 Btu/lbmThe change in internal energy is also 112.3 Btu/lbm, since Q = 0. The change in temperature is T2 - T1 = 1183.3 R - 527.7 R = 655.6 R.Answer: The work done by the air is 112.3 Btu/lbm, and the change in internal energy and temperature of the gas are also 112.3 Btu/lbm and 655.6 R, respectively.

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a) Cash Flow Diagram:

```

           |------> $3 billion ------>|

           |                          |

           |------> $2 billion ------>|

           |                          |

$1.25 billion |------> $1.25 billion -->|

  per quarter|       per quarter       |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

           |                          |

           |       ... (repeated)     |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

```

b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.

c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.

d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.

e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.

To analyze the cash flow associated with the Gulf of Mexico Oil Spill, we can create a cash flow diagram. Each arrow represents a cash flow, and the time periods are indicated below each arrow. The diagram shows the cash inflows and outflows over time.

a) Cash Flow Diagram:

```

           |------> $3 billion ------>|

           |                          |

           |------> $2 billion ------>|

           |                          |

$1.25 billion |------> $1.25 billion -->|

  per quarter|       per quarter       |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

           |                          |

           |       ... (repeated)     |

           |                          |

           |------> $1.25 billion -->|

           |       per quarter       |

```

b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.

c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.

d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.

e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.

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Answer:

Flow rate = 118.8 gpm, discharge pressure= 331.5 psig, shaft power = 26.3 hp and Efficiency = 87.5%.

Explanation:

Without mincing words, let us dive straight into the solution to the question above. So, the following parameters or data are given in the question above:

gpm = 80 gpm, shaft power = 8hp, and the pressure of  150 psig.

The flow rate =[ 80 × 1500] ÷ 100g = 118.9 gpm.

Hence, the discharge pressure = 150 × [ 1500/100]² = 331.5 psig.

Also, the required shaft power = 8 × [ 1500/100]³ = 26.3 hp.

The last part that is the efficiency can be calculated as given below:

Efficiency = [ 80 × 0.00223 × 144 × 150 ] ÷ [550 × 8 ] = 0.875 = 87.5%.

I'd say number 4, number 3 looks like an exhaust valve

Rayshawn leaves his car at Taylor's Auto Service center for an oil change. When the service is complete, he is obligated to pay the Auto Service for the work done. This type of contract is best characterized as an express contract.

An express contract is a type of agreement that is explicitly stated in words, whether written or oral. This agreement is created when two or more parties agree to the terms of the contract and express their willingness to enter into a contract. In an express contract, there is a clear agreement between the parties involved. The following are the characteristics of an express contract:It is a written or oral contract. It is a contract in which both parties have mutually agreed on specific terms and conditions. It is a contract in which the agreement is clear and concise, with no ambiguity in its language or meaning. In conclusion, an express contract is a type of agreement that is explicitly stated in words, whether written or oral. When two or more parties agree to the terms of the contract and express their willingness to enter into a contract, an express contract is formed. In the given case, Rayshawn leaves his car at Taylor's Auto Service center for an oil change. When the service is complete, he is obligated to pay the Auto Service for the work done. This type of contract is best characterized as an express contract.

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Answer:

The answer is "Both A and B" are right

Explanation:

During the previous twenty years car producers have made significant advances in planning vehicle structures that give more noteworthy tenant insurance in planar accidents (Lund and Nolan 2003). Be that as it may, there has been little agreement with respect to the significance of rooftop strength in rollover crashes, just as the best strategy for surveying that strength. In 2006 one-fourth of lethally harmed traveler vehicle tenants were associated with crashes where vehicle rollover was considered the most hurtful occasion (Protection Establishment for Expressway Wellbeing, 2007). Numerous lethally harmed tenants in rollovers are unbelted, and some are totally or mostly launched out from the vehicle (Deutermann 2002).

There is difference concerning how underlying changes could influence launch hazard or the danger of injury for inhabitants who stay in the vehicle, paying little mind to belt use.

Answer:A Only

Explanation:

I Took the test

Ared discovered behavior on one computer that certainly appears to be a virus. However, using three separate antivirus programs, he finds that none can detect the file because the computer has a zero-day exploit which is a cyberattack.

A zero-day exploit is a terrifying cyberattack. This attack targets a software vulnerability that is unknown to the software vendor and even to an antivirus vendor. In this cyberattack the attacker spots and targets the software vulnerability before any parties interested in mitigating it and quickly creates an exploit, and uses it for an attack on a computer.

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Answer:

it's answer B. I took the test

Answer:

B is correct I believe

Answer:

car a is moving faster than the car b

Answer:

B: Car A and car B are moving in opposite directions.

C: Car A is moving faster than car B.

E: Car A and car B are moving toward each other until they cross over.

Explanation:

I just did the assignment on EDGE2020 and it's 200% correct!  

Also, heart and rate if you found this answer helpful!! :) (P.S It makes me feel good to know I helped someone today!!)  :)  

You can read about it here https://www.cornellcollege.edu/information-technology/policies/technology-policies/limitations-of-laptops.shtml

Answer:

a) 397.89 ohm

b) attached below

c) 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

d)  0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Explanation:

A) Find the appropriate resistor

c = 0.01 uf

fc = 40 kHz

cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)

from the above equation  R = \(\frac{1}{2\pi foC}\)  = 397.89 ohm

B) sketch of the circuit  is attached

C) The gain of the filter at the cutoff frequency

fc = 40 kHz,  

C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) =  -j 397.89

Vout = Vin * ( R / R- C )

Vout = Vin * ( 397.89 / (397.89 - j 397.89))

Vout = \(\frac{1}{\sqrt{2} }\)  Vin ∠45⁰

therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

D) Gain of filter at 55 kHz

c = 0.01 uF =  \(\frac{-J}{2\pi foC }\) =  -j 289.373 ohms

Vout = Vin * \(\frac{R}{R-C}\)  

        = Vin * ( 397.89 / ( 397.89 - j 289.373))

Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰

therefore gain in ratio = 0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

The required diameter of a steel transmission shaft 10 m in length and of yield strength 350 mpa is 0.02795m

What is steel?

Steel is an iron alloy that contains a few tenths of a percent carbon to increase its strength and fracture resistance when compared to other types of iron. Many additional elements could exist or be added. Stainless steels that are corrosion- and oxidation-resistant often require an additional 11% chromium. Steel's high tensile strength and low cost make it useful in constructions, infrastructure, tools, ships, trains, automobiles, machinery, electrical appliances, armament, and rockets. The foundation metal of steel is iron.

Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter

factor of safety = 1.5

length of shaft = 10 meters

material yield strength = 350 MPa

Torque = 500 N.m

The required shaft diameter = 0.02795 m

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If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity.

Closing the throttle, turning off the fuel pump, setting the mixture control to idle cutoff, and simply cranking the engine is the most reliable hot start method I've found.

If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity. If you are unable to climb, close both throttles and land straight ahead.

The typical practice for the majority of aircraft would be to abandon takeoff if an engine failed during takeoff. In small aircraft, the pilot should turn the throttles down to idle, activate the speed brakes (if provided), and apply the brakes as needed if the engine fails before VR (Rotation Speed).

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Answer:

The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg

Explanation:

The given parameters are;

The mass of the block A= 58 kg

The coefficient of static friction between the block and the surface, \(\mu _s\) = 0.300

The coefficient of static friction between the rope and the fixed peg, B \(\mu _B\) = 0.310

Let T represent the tension in the rope

Therefore, when the rope is static, T = The normal reaction at the peg, B, \(N_B\)

The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°

The length of the rope = √(0.4² + 0.3²) = 0.5

∴ sin(θ) = 3/5 = 0.6

cos(θ) = 4/5 = 0.8

The vertical component of the tension in the rope = T × sin(θ) = 0.6·T

The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T

The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T

The block will start to move when we have;

The horizontal component of the tension in the rope = The friction force

∴ 0.8·T = 170.52 - 0.18·T

0.8·T + 0.18·T = 170.52

0.98·T = 170.52

T = 170.52/0.98 = 174

Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B \(N_B\)

The frictional force at the peg, \(F_B\) = \(\mu _B\) × \(N_B\) = 0.310 × 174 N = 53.94 N

The weight of the mass, \(m_c\), \(W_c\) = The frictional force at the peg, \(F_B\)  + The tension in the rope

∴ The weight of the mass, \(m_c\), \(W_c\) = 53.94 N + 174 N = 227.94 N

Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;

m = W/g

Where;

g = 9.8 m/s²

∴ \(m_c\) = \(W_c\)/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.

The greatest mass, that the weight C can have such that block A does not move = \(m_c\) ≈ 23.259 kg.

The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

Power is the energy transferred per unit time.

Torque is find out by

P = 2πNT/60

10000 = 2π x 2000 x T / 60

T =47.74 N.m

The gear ratio Ne / Ns =4/1

Ns =2000/4 = 500

Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
where d₁ = 30mm = 0.03 m

           d₀ = 30 +(2x 4) = 38mm =0.038 m

Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

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An effective STEM lesson should be designed with clear learning objectives that align with the relevant STEM standards. The lesson should engage students in hands-on, inquiry-based activities that challenge them to think critically, creatively, and analytically. It is crucial that the activities are relevant and captivating to students, igniting their curiosity and interest.

Here are 3 ideas :

1. Design a Rube Goldberg Machine: Students build a complex chain reaction machine using everyday materials.

2. Solar-Powered Car Challenge: Students design and build a car powered by solar energy to maximize distance traveled.

3. Data Analysis with COVID-19: Students analyze real-world data related to the COVID-19 pandemic to develop critical thinking and data analysis skills.

Answer:

The statement is true

Explanation:

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will: a) increase during a climb.

A ram air input can be defined as an air intake system which is designed and developed to use the dynamic air pressure that is created due to vehicular motion, or ram pressure, in order to increase the static air pressure within the intake manifold of an internal combustion engine of an automobile.

This ultimately implies that, a ram air input allows a greater mass-flow of air through the engine of an automobile, thereby, increasing the engine's power.

In conclusion, indicated airspeed will increase during a climb when both the ram air input and drain hole of the pitot system become blocked.

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Complete Question:

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will

a) increase during a climb

b) decrease during a climb

c) remain constant regardless of altitude change

Answer:D

Explanation:

All the options given regarding the hazard communication standard are correct except option D "prepare and post a list of employees who handle hazardous and toxic substances in the workplace".

The main requirements of employers that use hazardous chemicals are:

• ensure that chemicals are properly labelled.

• provide safety data sheets.

• train employees.

• create a written hazard communication program.

It should be noted that preparing and posting a list of employees who handle hazardous and toxic substances in the workplace is incorrect.

Therefore, the correct option is D.

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a) Here, VL = 9v, IL = 50mA, Ir = 50mA for the network of RL= 180 ohms.

b) If RL = 470 ohms, then VL = 10v, IL = 21.276mA, Ir = 45.45mA

c) The value of RL that will establish maximum power conditions for the            Zener diode, R\(_{L_{(max)}}\) = 1.83 kΩ

d) The minimum value of RL to ensure that the Zener diode is in the "on" state R\(_{L_{(min)}}\) = 220 Ω

A Zener diode is a particular kind of diode made to consistently permit current to flow "backwards" (with inverted polarity) when a specific reverse voltage, called the Zener voltage, is reached.

A wide range of Zener voltages, some of which are even variable, are used in the manufacture of Zener diodes. The reverse conduction occurs in some Zener diodes with sharp,  highly dopped p - n junctions and low Zener voltages; in these cases, the Zener effect, named after Clarence Zener, is caused by electron quantum tunneling in the small gap between the p and n regions.

Avalanche breakdown also occurs during the operation of diodes with higher Zener voltages, which have a more gradual junction.

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Given that the monthly electrical usage equals the national US household average of 948 kWh, let's calculate how many panels are required to provide that amount of energy.  

We will then draw a conclusion based on our calculation. For a 140 W panel, the number of panels required can be determined using the following formula: Number of panels = Total Energy Needed / Energy per panel / Number of sun hours.

2 panels Now, let's calculate the total cost for each type of panel. For the 140 W panel, the total cost would be the cost of one panel times the number of panels required. Total cost for 140 W panel = Number of panels x cost per panel.

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Answer:

Hello There!!

Explanation:

The answer is territorial.

hope this helps,have a great day!!

~Pinky~

\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)

The county is normally the state's largest political and Territorial unit.

Answer:

1. Operates machines that cut through rocks underground so natural resources can be harvested: Mine-cutting and channeling operator

2. Studies and manages natural resources to protect the environment: Conservation Scientist

3. Manages forests for conservation, human enjoyment, and harvesting: Forster

4. Inspects, measures, and classifies logs based on quality: Log grader or scaler

5. Operates machinery to cut down trees and move logs: Logging equipment Operator

Explanation:

Conservation Scientist – studies and manages natural resources to protect the environment and support human uses of natural resources

Forester – manages forests for conservation, human enjoyment, and tree harvesting

Mine Cutting and Channeling Machine Operator – operates machinery in underground mines that bring natural resources up to the surface for human use

Logging Equipment Operator – operates logging machinery, such as tractors or bulldozers

Log Grader or Scaler – inspects, measures, and classifies logs based on their quality

The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.

Conservation Scientist deals with the studies and manages natural resources to protect the environment and support human uses of natural resources

Forester deals with forests for conservation, human enjoyment, and tree harvesting

Mine Cutting and Channeling Machine Operator are the operates machinery in underground mines that bring natural resources up to the surface for human use

Logging Equipment Operator are the operates logging machinery, such as tractors or bulldozers

Log Grader or Scaler deals with the inspects, measures, and classifies logs based on their quality.

The careers that match the given descriptions are; Conservation Scientist, Forester , Mine Cutting and Channeling Machine Operator ,and Logging Equipment Operator.

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According to ASME Boiler and Pressure Code, water columns are required on all steam boilers.

The purpose of a water column is to provide a visual indication of the water level in the boiler. This is important because if the water level in the boiler gets too low, it can cause damage to the boiler and be a safety hazard.

The ASME Boiler and Pressure Code sets safety standards for boilers and pressure vessels, and it requires water columns to be installed on all steam boilers. The water column typically consists of a vertical pipe with a valve at the bottom and a glass sight gauge at the top, which allows the operator to visually check the water level.

Additionally, some states and municipalities may have their own regulations regarding water columns and boiler safety, so it's important to be familiar with the relevant codes and standards in your area.

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