Answer:
c. 80%
Explanation:
Given;
load raised by the machine, L = 360 N
distance through which the load was raised, d = 0.2 m
effort applied, E = 50 N
distance moved by the effort, e = 1.8 m
The efficiency of the machine is calculated as follows;
\(Efficiency = \frac{ 0utput \ work }{1nput \ work} \times 100\% \\\\Efficiency = \frac{Load \ \times \ distance \ moved \ by \ load }{Efort \ \times \ distance \ moved \ by \ effort} \times 100\%\\\\Efficiency = \frac{360 \times 0.2}{50 \times 1.8} \times 100\%\\\\Efficiency =80\%\)
Therefore, the efficiency of the machine is 80%
1. Why are the outer planets called “gas planets?”
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Explanation:
i hope this helps :)
Ram has power of 550 watt. What does it mean?
which of these correctly compares the masses of different objects in the universe?
A moon has more mass than the planet it circles and less mass than a star.
Do planets have a greater mass than stars?
By this definition, "stars" must be larger than planets in terms of mass. The size of a white dwarf would be comparable to that of a moon or small planet, but its mass would be approximately 200–1300 times that of Jupiter. Even more extreme are neutron stars, which are about the size of an asteroid but have a mass of several thousand Jupiters.
Why is the weight of the same object different on different planets Class 7?
The weight of an object is determined by its mass and the gravitational force that it experiences. The separation between two objects affects how strong gravity is. Because of this, an object weights differently on many planets.
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A child easily pushes an empty shopping cart around the store. As the cart fills, the child has to exert more force to keep the shopping moving and keep up with his mom. Which law is best supported by this example?
A. Newton's First Law
B. Newton's Second Law
C. Newton's Third Law
D. The law of definite proportions
Answer:
B Newton's second law
Explanation:
An empty grocery cart is easier to move because there is less mass in an empty cart compared to a full cart. Newton's second law state that an object's acceleration depends on the mass of the object and the force applied.
Can we track the movement of energy in nature
In the first activity, Vehicle 2 has a greater acceleration than Vehicle 1, but has a less forceful engine. How can this be? Explain in terms of your equation.
Answer:
This can be explained by the equation Force=Mass x Acceleration. Vehicle 2 has a higher acceleration than Vehicle 1, which means it accelerates quicker. However, this increased acceleration is achieved by a less forceful engine. This is possible because Vehicle 2 has a lower mass than Vehicle 1, meaning the same force applied to Vehicle 2 results in greater acceleration. Therefore, Vehicle 2 has a greater acceleration than Vehicle 1 but has a less forceful engine.
Someone help me please! will give brainliest
The force of gravity on a person on earth is greater than the force of gravity on a person on the moon. Therefore, an astronaut on the moon will...
Select one:
a. have more mass.
b. have less mass.
c. have the same mass.
d. have no mass.
the same mass.
they will be lighter on the moon (weight) but they're mass with still stay the same.
tell if this is right, hope it helps <3
An electric bell is kept under a bell jar in which a vacuum has been created. slowly air is introduced in to the jar. what will happen to the sound of the electric bell? a. it will increase until it reaches its maximum. b. it will decrease until it stops. c. it will not change. d. it will increase and decrease periodically. e. it will decrease exponentially.
Answer:
a) it will increase until it reaches its maximum
Sound requires a medium (air in this case) in order to propagate because it is a "compressional" wave as opposed to light which is a "transverse" wave and does not need a medium present for propagation.
What force will cause a displacement of 2m, while doing a work of 50J
Using the work done relation, the value of force is 25 Newton.
When a force is applied along a displacement, "work" in physics refers to the energy that is transported to or away from an object. The following situations include work: relocating a table. a door being pulled and pushed. Walking. raising a stone.
The work W that a force F traveling across a distance x exerts on an object is calculated using the formula W=Fs. If the object is moving in the opposite direction from how we expect it to, we add a minus sign.
Work done is equal to displacement times force.
50J = force × 2
f=50/2
Force = 25 Newton.
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a coin falls faster than feather on earth
Answer: true
Explanation: A coin falls faster than a feather on earth because the coin has more mass than the feather so gravity pulls harder on the coin than the feather.
Answer:
Because the feather has more AIR RESISTANCE FORCE than the coin....in a vacuum they would fall at the same rate (no air to provide resistance)
Explanation:
At the gym, a man pulls a bar on a machine that works the muscles of the upper back. It takes him 0. 5 seconds to raise 30
kilograms of weights a vertical distance of 0. 5 meters.
Which of these exerts the same power output? (Estimate g as 10 m/s2. )
A) lifting 25 kilograms a distance of 2. 4 meters in 2. 0 seconds
B) lifting 45 kilograms a distance of 2. 4 meters in 3. 0 seconds
C) leg pressing 45 kilograms a distance of 0. 5 meters in 0. 5 seconds.
D) bench pressing 30 ligrograms a distance of 0. 5 meter in 1. 5 seconds.
Pleaseeeeeee help me
The power output of the man pulling the bar can be calculated as follows:
Power = Work / Time
The work done by the man is equal to the force he exerts multiplied by the distance he moves the weights:
Work = Force x Distance
The force he exerts is equal to the weight of the weights he is lifting:
Force = Weight x g
where g is the acceleration due to gravity, which is approximately 10 m/s^2.
Plugging in the given values, we get:
Force = 30 kg x 10 m/s^2 = 300 N
Work = Force x Distance = 300 N x 0.5 m = 150 J
Power = Work / Time = 150 J / 0.5 s = 300 W
Now we can check which of the other options exerts the same power output:
Option A:
Force = 25 kg x 10 m/s^2 = 250 N
Work = Force x Distance = 250 N x 2.4 m = 600 J
Power = Work / Time = 600 J / 2.0 s = 300 W
Option B:
Force = 45 kg x 10 m/s^2 = 450 N
Work = Force x Distance = 450 N x 2.4 m = 1080 J
Power = Work / Time = 1080 J / 3.0 s = 360 W
Option C:
Force = 45 kg x 10 m/s^2 = 450 N
Work = Force x Distance = 450 N x 0.5 m = 225 J
Power = Work / Time = 225 J / 0.5 s = 450 W
Option D:
Force = 30 kg x 10 m/s^2 = 300 N
Work = Force x Distance = 300 N x 0.5 m = 150 J
Power = Work / Time = 150 J / 1.5 s = 100 W
Therefore, options A and B exert the same power output as the man pulling the bar, while options C and D do not.
5) Calculate the moment caused by a 2 kg mass placed at a distance of 0.5 m to the left of the pivot. Is this
moment clockwise, or anti-clockwise? (2 marks)
The moment caused by the 2 kg mass placed at a distance of 0.5 m to the left of the pivot is 1 kg m. This moment is anticlockwise.
What is moment ?Moment is a physical parameter equal to the product of the distance or displacement and another physical quantity such as mass, force etc.
For a mass of 2 kg and distance of 0.5 m the moment is :
moment = mass × distance
= 2 × 0.5 = 1 kg m
If we are taking the moment of force, then it the product of the distance and force acting on the body is taken.
force = mg
F = 2 kg × 9.8 m/s² = 19.6 N
then moment of force = 19.6 N × 0.5 m = 9.8 N
The moment from left to right in direction is anticlockwise.
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A proton moves at 2.50 x 10^6 m/s horizontally at a right angle to a magnetic field. What is the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally
The strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is 0.0414 T.
Understanding Magnetic FieldTo balance the weight of the proton and keep it moving horizontally, we need to apply a magnetic field with a strength equal to the gravitational force acting on the proton.
The force experienced by a charged particle moving in a magnetic field is given by the formula:
F = q * v * B
where:
F is the magnetic force,
q is the charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.
The weight of the proton is given by the formula:
Weight = mass * acceleration due to gravity
Since the proton is moving horizontally, the gravitational force is balanced by the magnetic force. Therefore:
F = Weight
q * v * B = mass * acceleration due to gravity
Given the following constants:
charge of a proton (q) = 1.6 x 10⁻¹⁹ C,
mass of a proton (mass) = 1.67 x 10⁻²⁷ kg
acceleration due to gravity (g) = 9.8 m/s².
Substituting the known values into the equation, we can solve for the magnetic field strength (B):
B = (mass * gravitational acceleration) / (q * v)
B = (1.67 x 10⁻²⁷ kg * 9.8 m/s²) / (1.6 x 10⁻¹⁹ C * 2.50 x 10⁶ m/s)
B = 0.0414 T
Therefore, the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is approximately 0.0414 Tesla (T).
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what is the velocity between 0s & 5s. (picture is given) Please assist (will give branliest)
Answer: the velocity is -2
Explanation: good luck don't think its wrong everyone calls me the human calculator
So if any of ya got like, screenshots of all the answers for Edge, 2020. Lab-Kinetic Energy-student guide, That would be really helpful. If you could help me, then I will mark you brainliest. And for you trollers out there who just want the points, could you not steal them for this one? Anyways, thanks ya'll!
Answer:
has any one finished the lab yet?????
Explanation:
Predict how monarch butterfly populations may compare over time in two locations with very different temperatures.
Answer:
they will increase why because they go from warm cold warm meaning they have to adapt back to the previous location
Explanation:
A car drives 90 meters north, then turns around and drives 120 meters south. What was its displacement and distance?
Answer:
displacement= 30 m towards south, distance= 210m
Explanation:
Distance (scalar quantity) how much ground an object has covered.
Displacement (vector quantity) refers to how far out of place an object is it is the object's overall change in position.
Basically meaning for displacement the directions will be very key
D for Displacement
D= D1+D2
D= 120 (S) + 90 m (N)
Must be in same direction
D= 120 (S) + (-90 m) (S)
D= 30 m (S)
and for distance you are simply just adding how much distance they have covered
so d= d1+d2
d= 90m + 120m
d= 210m
A spherical glass ornament is 6 cm in diameter. If an object is placed 10.5 cm away from the ornament, where will its image form? What is the magnification?
The magnification is mathematically given as
M= 0.125
Lens magnificationQuestion Parameters:
A spherical glass ornament is 6 cm in diameter.
If an object is placed 10.5 cm away from the ornament, where will its image form
Generally, the mirror equation for ornament is mathematically given as\
1/q = 2 / r - 1/p
Therefore
1/q = 2 / (-3 cm) - 1/(10.5 cm)
q = -1.31 cm
Therefore, the magnification
M = -q/p
M= -(-1.31 m)/ (10.5 cm)
M= 0.125
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when two cars collide in real life they come to a stop. does this prove that conservation of momentum is not true in real life? explain
Some of the velocity from a collision between two vehicles crumples their bodies. A purposeful loss of kinetic energy occurs.
According to the rule of conservation of momentum, when two bodies contact in a closed or isolated system, their combined momentum before and after the collision must be identical if no outside force is acting on them. In other words, the system momentum is unchanged.
Momentum is defined as p = mv (in kg/s).
Where V is a body's speed, m = the body's mass, In order to maintain momentum
mv = unchanging
This is,
m1v1 = m2v2
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When is the average velocity of an object equal to the instantaneous velocity? a. This is always true. b. This is never true. c. This is the case only when the velocity is constant. d. This is the case only when the acceleration is constant. e. This is the case only when the velocity is decreasing at a constant rate.
When is the average velocity of an object equal to the instantaneous velocity is C. This is the case only when the velocity is constant.
The instantaneous velocity of an object is equal to the average velocity of an object when the velocity is constant or when the acceleration is zero, this is the case only when the velocity is constant. When an object has a constant velocity, the instantaneous velocity of the object is equivalent to the average velocity of the object. This is true because the velocity of the object remains constant over time.
For example, if an object travels at a speed of 20 meters per second for a time period of 5 seconds, then the instantaneous velocity at the end of the 5 seconds is 20 meters per second, and the average velocity of the object over the 5 seconds is also 20 meters per second. This is because the velocity remained constant throughout the entire time period. Therefore, option c is correct, this is the case only when the velocity is constant.
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Write a set of turtle instructions to draw an AND gate.
The turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
To draw an AND gate using turtle graphics, you can use the following set of instructions:
Set up the turtle:
a. Set the turtle's initial position.
b. Set the turtle's pen color and size.
Draw the first input line:
a. Move the turtle forward to the starting point of the line.
b. Draw a straight line segment to represent the first input.
Draw the second input line:
a. Move the turtle to the starting point of the second line.
b. Draw a straight line segment to represent the second input.
Draw the output line:
a. Move the turtle to the starting point of the output line.
b. Draw a straight line segment to represent the output.
Draw the logic gate shape:
a. Move the turtle to the starting point of the gate.
b. Draw a rectangle to represent the gate.
c. Add any necessary labels or symbols to indicate it as an AND gate.
Add connections between lines and gate:
a. Move the turtle to the intersection point of the first input line and the gate.
b. Draw a small line segment to connect the input line to the gate.
c. Repeat the above step for the second input line and the gate.
d. Draw a small line segment to connect the output line to the gate.
Repeat the above steps as necessary to draw multiple AND gates or any additional components.
Remember to adjust the turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
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assuming that there is sufficient friction between the barrel and the clothes to keep the clothes from slipping down the side of the barrel, what is the maximum angular speed a washer with barrel radius r can have such that the clothes will tumble?
The maximum angular speed a washer with a barrel radius r can have such that the clothes will tumble is determined by the centripetal force required to keep the clothes from slipping down the side of the barrel. The centripetal force is provided by the friction between the barrel and the clothes.
1. To find the maximum angular speed, we need to consider the forces acting on the clothes. The main force is the gravitational force pulling the clothes downward.
2. To counteract this downward force and prevent the clothes from slipping, the frictional force between the barrel and the clothes must provide an equal and opposite force.
3. The maximum angular speed occurs when the frictional force reaches its maximum value, which is the maximum static friction.
Therefore, the maximum angular speed can be calculated by equating the centripetal force to the maximum static friction force:
Centripetal force = Maximum static friction force
The centripetal force is given by:
Centripetal force = m * ω^2 * r
Where m is the mass of the clothes, ω is the angular speed, and r is the radius of the barrel.
The maximum static friction force is given by:
Maximum static friction force = μ_s * N
Where μ_s is the coefficient of static friction and N is the normal force.
By equating these two forces, we can solve for the maximum angular speed (ω) as follows:
m * ω^2 * r = μ_s * N
Since the normal force is equal to the weight of the clothes (mg), we can substitute this into the equation:
m * ω^2 * r = μ_s * mg
Simplifying the equation, we get:
ω^2 = μ_s * g / r
Taking the square root of both sides, we find:
ω = sqrt(μ_s * g / r)
So, the maximum angular speed a washer with barrel radius r can have such that the clothes will tumble is ω = sqrt(μ_s * g / r), where μ_s is the coefficient of static friction and g is the acceleration due to gravity.
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It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration?
Given:
The angular displacement, θ=89.5°
Initial angular velocity, ω₀=47.8 rpm
Final angular velocity, ω=0 rad/s
To find:
The angular acceleration of the wheel.
Explanation:
The angular velocity can be converted to rad/s as,
\(\begin{gathered} \omega_0=\frac{47.8\times2\pi}{60} \\ =5\text{ rad/s} \end{gathered}\)The angle is converted into the radians as,
\(\begin{gathered} \theta=\frac{89.5\times\pi}{180} \\ =1.56\text{ rad} \end{gathered}\)From the equation of motion,
\(\omega^2-\omega^2=2\alpha\theta\)Where α is the angular acceleration of the wheel.
On substituting the known values,
\(\begin{gathered} 0^2-5^2=2\times\alpha\times1.56 \\ \implies\alpha=\frac{-5^2}{2\times1.56} \\ =-8.01\text{ rad/s}^2 \end{gathered}\)Final answer:
Thus the angular acceleration of the wheel is -8.01 rad/s²
why doesn't earth have as many craters as the moon
The Earth doesn't have as many craters as the Moon because its geological processes, such as erosion and plate tectonics, have been more active in reshaping its surface over time.
The Moon's surface is covered in craters because it lacks significant geological processes that could erase or modify them. The Moon has a thin atmosphere and no active tectonic activity, which means that craters formed by impacts with asteroids or comets remain preserved for long periods.
In contrast, Earth has a dynamic geology with processes like erosion, weathering, and plate tectonics.
These processes continually reshape the Earth's surface, gradually erasing or modifying impact craters. Erosion caused by wind, water, and glaciers can wear down craters, while tectonic activity, such as the movement of Earth's crustal plates, can uplift or subside regions, altering the original crater morphology.
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Earth doesn't have as many craters as the Moon due to its active geology, erosion, tectonic activity, and the protective role of its atmosphere.
The number of craters on Earth is significantly lower compared to the Moon due to several factors. Firstly, Earth's active geology, erosion, and tectonic activity constantly reshape its surface, erasing or modifying older craters over time. This process, known as geological activity, is absent on the Moon, allowing craters to remain preserved for billions of years.
Secondly, Earth's atmosphere plays a crucial role in protecting the planet's surface from smaller meteoroids. When these meteoroids enter Earth's atmosphere, they experience friction and heat, causing them to burn up before reaching the surface. This phenomenon, known as atmospheric entry, prevents many smaller meteoroids from creating craters on Earth.
On the other hand, the Moon lacks an atmosphere, which means that meteoroids can directly impact its surface without burning up. As a result, the Moon has accumulated a significantly higher number of craters over billions of years.
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A uniform solid sphere rolls down an incline. a) What must be the incline angle (in degrees) if the linear acceleration of the center of the sphere is to have a magnitude of 0.23g? b) If a frictionless block were to slide down the incline at that angle, would its acceleration magnitude be more than, less than, or equal to 0.23g?
The incline angle should be about 4.7 degrees and the block's acceleration would be greater than that of the rolling sphere.
a) Let M be the mass of the sphere, R be its radius, and θ be the incline angle. When the sphere rolls down the incline without slipping, the friction force acting on it causes a torque about its center of mass, which results in a rotational acceleration. If a is the linear acceleration of the center of mass, and α is the angular acceleration, then we have:
a = α R
Also, the torque τ caused by the friction force is given by:
\(τ = I α\)
where I is the moment of inertia of the sphere about its center of mass. For a solid sphere, I is given by:
\(I = (2/5) M R^2\)
Since the sphere rolls without slipping, the friction force is related to the normal force N by:
\(f = μ N\)
where f is the friction force, and μ is the coefficient of static friction. The normal force is related to the weight of the sphere by:
N = M g cos θ
where g is the acceleration due to gravity.
The net force acting on the sphere down the incline is given by:
\(Fnet = M g sin θ - f\)
The linear acceleration of the center of mass is given by:
\(a = Fnet / M\)
Substituting for f and N, we get:
\(a = g (sin θ - μ cos θ)\)
Equating this to α R, we get:
g (sin θ - μ cos θ) = α R
Substituting for α using the expression for I and τ, we get:
\(g (sin θ - μ cos θ) = τ / (2/5 M R)\)
Substituting for τ using the expression for f and N, we get:
\(g (sin θ - μ cos θ) = (μ M g cos θ) R / (2/5)\)
Simplifying, we get:
\(tan θ = (5/7) μ\)
Substituting the given values, we get:
tan θ = (5/7) (0.23)
\(θ = arctan(0.082)\)
θ = 4.7 degrees (approximately)
Therefore, the incline angle should be about 4.7 degrees
b) Since the block is frictionless, its acceleration down the incline is given by:
a' = g sin θ
Substituting the value of θ obtained in part a), we get:
a' = g sin(4.7) ≈ 0.41 g
Since this is greater than 0.23g, the block's acceleration would be greater than that of the rolling sphere.
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In beams with circular cross sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.
a. true
b. false
The given statement is that in beams with circular cross-sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.
The tension that develops as a result of the internal shearing of a beam as a result of a shear force applied to the beam is known as shearing stress.
One-half of the difference between the primary stresses is the maximum shear stress. It should be noticed that the primary planes equation, 2p, results in two angles between 0° and 360°.
The primary stresses brought on by bending are typical tension and compression stresses. However, the state of stress within the beam also includes large normal stresses caused by bending in addition to shear stresses caused by the shear force, even though the former is often of a lesser order than the latter.
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the solar spectrum is a good example of what kind of spectrum?
HELP ASAP PLZ
Carbon-11 undergoes radioactive decay. Which particle correctly completes
the equation to show that the numbers of nucleons on each side of the
equation are equal?
IPC 'B+ ?
O A. Le
O B. He
O c. He
Doe
Answer:
d
Explanation:
the atomic number and the mass number must not change. so you're just looking for the particle that makes the numbers on both sides the same
Answer:
D
Explanation:
Ap3x
An incline plane is 12-m long and 4-m high. A block is pulled up the ramp with a spring scale. The reading on the spring scale is 70-N. How many Newtons would the block actually weigh if you had to lift it the 4-m height?
Answer:
W = 210 N
Explanation:
For an ideal machine:
\(Work\ In = Work\ Out\\(P)(L)=(W)(H)\)
where,
P = Effort = Spring Scale Reading = 70 N
L = Effort Arm = Length of inclined plane = 12 m
W = Actual Load (Weight) to be lifted = ?
H = Load Arm = Height = 4 m
Therefore,
\((70\ N)(12\ m) = (W)(4\ m)\\\\W = \frac{(70\ N)(12\ m)}{4\ m}\)
W = 210 N
Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science. Complete the Venn Diagram below.(10 pts) Scientific Method in Philosophy Scientific Method in Science