A load of 50 N attached to a spring that is hanging vertically stretches the spring 0.20 m. What is the spring constant?

What is depolarizer?

Depolarizer is the substance added to the electrolyte of an electric cell or battery to remove the gas collected on the electrodes.

It is an optical device used to scramble the polarization of light.

The reason why the stationary object is more difficult to move is the law of inertia.

We know that according to the Newton first law, an object that is at rest would continue to be at rest unless the object has been acted upon by an external force. Also, the object that is in a state of constant motion would continue in the state of constant motion unless the object has been acted upon by an external force.

The law that I have just described above is called the law of inertia. The concept of the law has to do with a reluctance towards motion. The object does not move easily. We would have to apply a lot of force to the  object which would enable us to over come this force of inertia and get the object to start moving in the first place. A little force can now maintain the motion of the object in a straight path.

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(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.

The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.

You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.

Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

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The minimum amount of work required to make the enemy satellite inoperative and push it out of its circular orbit is 6.972 × 10^9 joules.

To calculate the minimum amount of work required to knock the satellite out of its circular orbit, we need to determine the change in kinetic energy required to change the satellite's velocity. This change in kinetic energy can be calculated using the conservation of energy, which states that the total energy in a closed system remains constant.

The kinetic energy of an object in motion can be expressed as:

K = (1/2)mv^2

Where:

K = Kinetic energy

m = Mass of the object

v = Velocity of the object

To determine the velocity of the satellite, we can use the following formula:

v = sqrt(GM/r)

Where:

G = Universal gravitational constant = 6.6743 × 10^-11 N m^2/kg^2

M = Mass of the Earth = 5.98×10^24 kg

r = Altitude of the satellite above the Earth's surface + radius of the Earth = 6,997 km

v = sqrt(6.6743 × 10^-11 × 5.98×10^24 / 6,997×10^3) = 7,650 m/s

To change the satellite's velocity, we need to calculate the new velocity required to push the satellite out of its circular orbit. We can use the following formula to calculate the escape velocity required to leave the Earth's gravitational field:

Ve = sqrt(2GM/r)

Ve = sqrt(2 × 6.6743 × 10^-11 × 5.98×10^24 / 6,997×10^3) = 11,186 m/s

To calculate the change in kinetic energy required to change the satellite's velocity from its initial velocity to the escape velocity, we can use the following formula:

ΔK = (1/2)m(Δv)^2

Where:

ΔK = Change in kinetic energy

m = Mass of the satellite

Δv = Change in velocity required to reach escape velocity = Ve - v

Δv = 11,186 m/s - 7,650 m/s = 3,536 m/s

ΔK = (1/2) × 993 kg × (3,536 m/s)^2 = 6.972 × 10^9 J

Therefore, The adversary spacecraft must be rendered inoperable and forced out of its elliptical orbit with a minimum of 6.972 × 10^9 joules of work.

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The velocity of the bus after 6.8 secs later will be ; 16.7 m/s

Given data:

Initial speed = 8 m/s

Increment speed = 1.5 m/s

Total time travelled = 6.8 s

Determine the final velocity after 6.8 secs

After 1 sec : speed = 8 m/s

After 2 secs : speed = 8 + 1.5

After 3 secs :  speed = 8 + 1.5 + 1.5

After 4 secs : speed = 8 + 1.5 + 1.5 + 1.5

After 5 secs : speed = 8 + 1.5 + 1.5 + 1.5 + 1.5

After 6 secs : speed = 8 + 1.5 + 1.5 + 1.5 + 1.5 + 1.5 =  15.5 m/s

∴ After 6.8 secs : speed = 15.5 + [ ( 1.5 / 10 ) * 8 ] = 16.7 m/s

Hence we can conclude that the velocity of the bus after 6.8 secs is 16.7m/s

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a ) The normal force on the crate in terms of the F = 921.2 - 0.5 F N

b ) The minimum force the man would have to apply to pull the crate up the ramp = 533.44 N

W = m g

m = 100 kg

g = 9.8 m / s²

W = 100 * 9.8

W = 980 N

Resolving the force of gravity into its horizontal and vertical components,

Wx = W sin θ

Wx = 980 * sin 20°

Wx = 333.2 N

Wy = W cos θ

Wy = 980 * cos 20°

Wy = 921.2 N

Resolving F into its vertical and horizontal components,

Fx = F cos θ

Fx = F cos 30°

Fx = 0.87 F N

Fy = F sin θ

Fy = F sin 30°

Fy = 0.5 F N

Since there is no acceleration in y-direction,

N - Wy + Fy = 0

N = 921.2 - 0.5 F

Ff = μ N

If the crate is being pulled with the minimum force, velocity would be constant. So acceleration will be zero.

∑ \(F_{x}\) = 0

Fx - Ff - Wx = 0

0.87 F - 0.2 ( 921.2 - 0.5 F ) - 333.2 = 0

0.87 F - 184.24 + 0.1 F - 333.2 = 0

0.97 F = 517.44

F = 533.44 N

Therefore,

a ) The normal force on the crate in terms of the F = 921.2 - 0.5 F N

b ) The minimum force the man would have to apply to pull the crate up the ramp = 533.44 N

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Answer:

The answer is within the picture.

Explanation:

Answer: D. 6.1 m/s^2

Explanation:

Answer:

233.33°F

Explanation:

(385K - 273.15) * 9/5 + 32 = 233.33°F

Answer:

.

Explanation:

Answer:

R = 19.36  ohms

Explanation:

Given that,

The power of an electric motor, P = 2500 Watts

The voltage of the circuit, V = 220 V

We need to find the resistance of the motor. We can find it as follows :

\(P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(220)^2}{2500}\\R=19.36\ \Omega\)

So, the resistance of the motor is 19.36  ohms.

I don't think the provided solution is correct because it's not dimensionally consistent. The quantity \(8h-1\) in particular doesn't make sense since it's mixing a distance with a dimensionless constant.

Here's how I think the proper answer should look:

The net force on the box acting perpendicular to the ramp is

\(\sum F_\perp = F_{\rm normal} - mg \cos(\theta) = 0\)

where \(F_{\rm normal}\) is the magnitude of the normal force due to contact with the ramp and \(mg\cos(\theta)\) is the magnitude of the box's weight acting in this direction. The net force is zero since the box doesn't move up or down relative to the plane of motion.

The net force acting parallel the ramp is

\(\sum F_\| = mg\sin(\theta) - F_{\rm friction} = ma\)

where \(mg\sin(\theta)\) is the magnitude of the parallel component of the box's weight, \(F_{\rm friction}\) is the magnitude of kinetic friction, and \(a\) is the acceleration of the box.

From the first equation, we find

\(F_{\rm normal} = mg \cos(\theta)\)

and since \(F_{\rm friction} = \mu F_{\rm normal}\), we get from the second equation

\(mg\sin(\theta) - \mu mg\cos(\theta) = ma\)

and with \(\mu = 0.25\) and \(\theta=60^\circ\), we get

\(a = g\sin(60^\circ) - 0.25g \cos(60^\circ) = \left(\dfrac{\sqrt3}2 - \dfrac18\right) g\)

Let \(x\) be the length of the ramp, i.e. the distance that the box covers as it slides down it. Then the box attains a final velocity \(v\) such that

\(v^2 = 2ax\)

From the diagram, we see that

\(\sin(\theta) = \dfrac hx \implies x = \dfrac h{\sin(60^\circ)} = \dfrac{2h}{\sqrt3}\)

and so

\(v^2 = \dfrac{4ah}{\sqrt3} = \left(2 - \dfrac1{2\sqrt3}\right) hg = \dfrac14 \left(8 - \dfrac2{\sqrt3}\right) hg\)

\(\implies v = \dfrac12 \sqrt{\left(8 - \dfrac2{\sqrt3}\right) hg}\)

Answer: Magnetic Fields

Explanation: A Compass works by detecting the earth's magnetic fields. The earth has a iron core that is part liquid and part solid crystal due to gravitational pressure.

The ball will strike the ground after 8.04 seconds.

Using the kinematic equation for displacement:

y = y0 + v0t - 1/2g*t^2

where:

We want to findt, let's substitute the values:

0 = 58.52 + 19.50t - 1/2(9.81)*t^2

4.905t^2 - 19.50t - 58.52 = 0

Using the quadratic formula:

t = (-b ± sqrt(b^2 - 4ac)) / 2a

where:

t = (-(-19.50) ± sqrt((-19.50)^2 - 4(4.905)(-58.52))) / 2(4.905)

t = (19.50 ± 31.37) / 9.81

The two possible solutions are:

t1 = 5.61 s (ball on the way up)

t2 = 8.04 s (ball on the way down)

Since the question is asking for when the ball strikes the ground, we take the larger solution, which is:

t = 8.04 s

In other words, the ball will strike the ground after 8.04 seconds.

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

a refractor telescope

Explanation:

Answer:

a. refractor telescope

Electromagnetic radiation of a specific wavelength or energy is called a photon.

Electromagnetic radiation of a specific wavelength or energy is called a photon. A photon is a fundamental particle of light and is the smallest unit of electromagnetic radiation. It has no mass, but carries energy and momentum. Photons travel through space at the speed of light and can exhibit both wave-like and particle-like behaviors.The energy of a photon is directly proportional to its frequency or inversely proportional to its wavelength. This relationship is known as the Planck-Einstein equation and can be expressed as E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the radiation.When a photon interacts with matter, it can be absorbed, reflected, or scattered. The energy of the photon is transferred to the absorbing material, causing an excitation or ionization of the atoms or molecules. This process is the basis for many scientific techniques, such as spectroscopy, where the absorption or emission of photons by a material is used to identify its chemical composition and structure. Understanding the properties of photons and their interactions with matter is essential for many fields of science, including optics, physics, and chemistry.

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Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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Answer:

Below

Explanation:

You can use this formula to find the velocity of an object

     velocity = displacement / change in time

For this problem, we need to find displacement first

To find displacement all you need to do is find the difference between the two distances!

So our displacement here would be

     73 - 62 = 11 m

Now that we have displacement we can find velocity

      velocity = 11 / 15

                    = 0.733333....

                    = 0.73 m/s

Hope this helps! Best of luck <3

The velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.

When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time.

If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.

Given:

The distance of the object = 73 m to 62 m,

The time taken by the object, t = 15 s,

Calculate the displacement of the object = 73 - 62 = 11 m

Calculate the velocity by the formula given below,

\(v = d /t\)

v = 11 / 15

v = 0.73 m / s

Therefore, the velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.

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Answer:

acceleration = change in velocity / change in time

acceleration = 14/10

acceleration = 1.4/s^2

Matching the government activities to the different fiscal policies.

Contractionary Fiscal Policy:

budget indicates a surplus

government is spending less than what it earns

Expansionary Fiscal Policy:

government is spending more on infrastructure development

budget indicates a deficit

government is spending more than what it earns

When the government is spending less than what it earns, it has a budget surplus. This indicates that the government is collecting more revenue than it is spending. This is an example of a contractionary fiscal policy because it reduces the amount of money circulating in the economy, which can help control inflation.

When the government is spending more than what it earns, it has a budget deficit. This indicates that the government is spending more money than it is collecting in revenue. This is an example of an expansionary fiscal policy because it injects more money into the economy, which can stimulate economic growth.

When the government is spending more on infrastructure development, it is an example of an expansionary fiscal policy because it increases government spending and stimulates economic growth.

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Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

The mechanical advantage of the crowbar is 3.1667.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane.

The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Input force by you= 12 N.

Output force from the crowbar = 38 N.

Then, the mechanical advantage of the crowbar = Output force from the crowbar / input force by you.

= 38N/12N.

=3.1667.

Hence, the mechanical advantage of the crowbar is 3.1667.

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Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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The net electric field at point P is 3.2×10^6 N/C, directed towards the left.

To calculate the net electric field at point P due to charges A and B, we need to consider the vector sum of the electric fields produced by each charge individually.

Given:

Electric field due to charge A: E_A = 8.7×10^6 N/C

Electric field due to charge B: E_B = 5.5×10^6 N/C

Since electric field is a vector quantity, we need to consider both magnitude and direction. Let's assume that the electric field due to charge A points to the left and the electric field due to charge B points to the right.

To find the net electric field at point P, we can subtract the magnitudes of the electric fields since they are acting in opposite directions:

Net electric field at point P = |E_A| - |E_B|

Substituting the given values, we get:

Net electric field at point P = 8.7×10^6 N/C - 5.5×10^6 N/C

                           = 3.2×10^6 N/C

Therefore, the net electric field at point P is 3.2×10^6 N/C, directed towards the left.

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The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.

(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)

Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)

(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.

Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.

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