A living thing that has a irregular shape is

A disk rotates about a fixed axis that is perpendicular to the disk and passes through its center. At any instant, every point on the disk has the same angular velocity. So, option e. is correct.

Angular velocity is a measurement of the rate of change of the angular position of an object over a duration of time. The symbol used for angular velocity is usually a lowercase Greek symbol omega. Angular velocity is depicted in units of radians per time or degrees per minute (usually radians in physics), with somewhat straightforward conversions letting the scientist or student use radians per second or degrees per minute or whatever arrangement is required in a given rotational situation, whether it be a large Ferris wheel or a yo-yo.

Angular velocity is less common than linear velocity because it only refers to objects that are moving along a circular path.

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Answer:

h = 0.288m

Explanation:

Assume

\(v_1\) = Speed of Sue

\(v_2\) = Speed of Chris immediately after the push

Sue's KE = \(\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2\)

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65  

= 331.24

\(26v_{1}\ ^2\) = 331.24

So, \(v_1 = 3.569\)

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

\(m_1v_1 = m_2v_2\)

\(52 \times 3.569 = 78 \times v_2\)

\(v_2 = 2.380\)

Chris kt = \(\frac{1}{2} \times 78 \times 2.380^2\)

= 220.827

220.827 = mgh

So, h = 0.288m

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

\(tan \ \theta = \dfrac{12}{100} \\ \\ tan \ \theta = 0.12 \\ \\ \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0\)

The drag force D = Wsinθ

\(\dfrac{1}{2}C_v \rho AV^2 = W sin \theta\)

where;

\(\rho = 1.23 \ kg/m^3\)

A = 0.9 m²

V = 15 m/s

∴

Drag coefficient \(C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}\)

\(C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}\)

\(C_D =0.9378\)

The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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In the figure below, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

Periodic or oscillatory motion is defined as a motion that repeats itself. Due to a restoring force or torque, an object in such motion oscillates around an equilibrium position.

Energy is conserved in oscillation.

So, the maximum loss in Potential Energy = Maximum gain in Kinetic energy

5 J - 1 J = Maximum gain in Kinetic energy

Maximum gain in Kinetic energy = 4 J

\(0.5 \times m \times vmax^2 = 4\\0.5 \times 2.0 \times 10^-3\; Kg \times vmax^2 = 4 J\\vmax^2 = 4 \times 10^3 m^2/s^2\\vmax = 63.2 m/s\)

Therefore, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

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An example of a physical change of matter is (c) Melting ice.

Explanation: Melting ice is an example of a physical change of matter. When ice melts, it undergoes a change in state from a solid to a liquid, but its chemical composition remains the same. The water molecules in ice rearrange themselves to form liquid water, but no new substances are formed. This change can be reversed by cooling the liquid water to below its freezing point, causing it to solidify back into ice. Physical changes do not involve a change in the chemical identity of the substance, only a change in its physical properties, such as shape, size, or state.

In contrast, options a) Burning wood, b) Digesting food, and d) Rusting iron involve chemical changes. Burning wood involves a chemical reaction where wood reacts with oxygen to produce carbon dioxide, water vapor, and ash. Digesting food involves the breakdown of complex molecules into simpler ones through chemical reactions in the body. Rusting iron is a chemical reaction where iron reacts with oxygen and moisture in the air to form iron oxide.

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Note: The complete question is:

Which of the following is an example of a physical change of matter?

a) Burning wood

b) Digesting food

c) Melting ice

d) Rusting iron

The runner who reaches their maximum speed more quickly has the larger maximum speed. In a 100-meter dash, reaching maximum speed more quickly generally indicates a higher level of acceleration, which is related to maximum speed.

The runner who reaches their maximum speed more slowly may have a longer time to build up speed, but once both runners have reached their maximum speed, they are both running at the same speed.

So, the runner who reached maximum speed more quickly will have had a higher maximum speed.

Speed is known as the rate of change of position of an object in any direction. Speed is calculated as the ratio of distance to the time in which the distance was covered.

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Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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When placed in glycerin of specific gravity 1.35, the block projects 0.25m in above the liquid surface. The specific gravity of the wood is 1.35, and the density of the wood is 1350 kg/m³.

Specific gravity is a measure of the density of a substance relative to the density of a reference substance. It is a dimensionless quantity and is often expressed as a ratio. In the context of liquids and solids, the reference substance is typically water at a specific temperature. Specific gravity indicates how much denser or lighter a substance is compared to water.

Density is a measure of how much mass is contained in a given volume of a substance. It is defined as the mass of a substance per unit volume. Density is usually expressed in units such as kilograms per cubic meter (kg/m³) or grams per cubic centimeter (g/cm³).

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A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours. The average speed of the car is 80 km/hour.

To find the average speed of the car, we need to calculate the total distance traveled and the total time taken.

In the first 2.5 hours, the car travels 200 km.

Then, it stops for half an hour.

After that, the car travels another 200 km in 2 hours.

So the total distance traveled is 200 km + 200 km = 400 km.

The total time taken is 2.5 hours + 0.5 hours + 2 hours = 5 hours.

Therefore, the average speed of the car is:

Average speed = total distance / total time

= 400 km / 5 hours

= 80 km/hour.

So the average speed of the car is 80 km/hour.

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Given that the mass of the object is m = 5kg.

The force on the object is F = 100 N.

The radius of the circle is r = 6 m

We have to find velocity.

Velocity can be calculated by the formula

Substituting the values, the velocity will be

Thus, the velocity is 10.95 m/s

Answer: B. 1m/s^2

Explanation:

Answer:

D Constant velocity

Explanation:

if it has forces moving on it it has constant velocity

Answer:

The maximum speed of the stone without breaking the rope is 4.33 m/s.

Explanation:

Given;

maximum tension the rope can withstand, T = 75 N

mass of the rock, m = 6 kg

radius of the circle, r = 1.5 m

As the stone spin in a vertical circle, it performs circular motion with centripetal acceleration directed inwards. The maximum centripetal force during this motion will be equal to maximum tension on the rope.

\(F_c,_m_a_x = T = \frac{MV_m_a_x^{2} }{r}\\\\V_m_a_x^{2} = \frac{Tr}{M}\\\\V_m_a_x = \sqrt{\frac{75*1.5}{6}}\\\\V_m_a_x = 4.33 \ m/s\)

Therefore, the maximum speed of the stone without breaking the rope is 4.33 m/s.

60 kg m/s is the answer because you gave it and I thought you are telling ruth also you are a big questioner and also you should check with your doctor and go out and go touch the grass.

(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Answer: the answer is 6kg.

Explanation:

Mass= force divided by acceleration, which would be 12 divided by 2.

Answer:

a is the answer I think so

When a car is traveling north, its acceleration vector can point south when it is slowing down.

A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.

If the car is travelling north, the direction of the acceleration vector will continue to point northwards.

However, when the car slows down, the direction of the accelerating vector will now point southwards.

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3) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4) 90 J work has been done by her

5) 51 J work was done

6) He have done  \(10^{4}\) J  of work

7) no work is done

8) no work is done

9) 700 J is the work done on the car

10) 10.68 N  force is applied

3 ) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4 ) work done = force * displacement

                       = 75 * 1.2 = 90 J

5 )  work done = force * displacement  

                        = 15 * 3.4 = 51 J

6 ) work done = force * displacement  

                        = 100 * 100 = \(10^{4}\) J

7) no work is done because no displacement occurred

8)  no work is done because no displacement took place

9) work done = force * displacement

                        = 12.5 * 56 = 700 J

10)  force = work done / displacement

                = 142 / 13.3 = 10.68 N

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Answer:

97 s

Explanation:

Given:

Δx = 9600 m

v₀ = 198 m/s

v = 0 m/s

Find: t

Δx = ½ (v + v₀) t

9600 m = ½ (0 m/s + 198 m/s) t

t = 97 s

Answer:

Δx = ½ (v + v₀) t

9600 m = ½ (0 m/s + 198 m/s) t

t = 97 s

Explanation:

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

a precision instrument for taking extremely precise measurements. It's the newest advancement in caliper technology.

Explanation:

Answer:

Because the temperature Would Most likey increase And same with the Beans! :D <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3

Explanation:

Im pretty sure the answer is A and B

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.

The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.

To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².

Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².

Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m

The time taken, t = 38 ms = 0.038 s.

Now, we know that acceleration, a = (v - u) / t.

We can rearrange the above equation to find the final velocity, v. We get,v = u + at

Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s

Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.

Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

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In a roller coaster, the highest point on the track is generally where it has the most potential energy.

Option A.

At position A, the coaster has the most potential energy because it is at its highest point above the ground, and thus has the greatest amount of gravitational potential energy. As the coaster descends from this point, it begins to convert this potential energy into kinetic energy, which allows it to accelerate down the track and reach high speeds at various points throughout the ride.

On the other hand, position B is typically the lowest point in the coaster's track, where the coaster would have the least potential energy and the most kinetic energy. At this point, the coaster is moving at its fastest speed and has the greatest amount of kinetic energy, which it acquired by converting its potential energy into kinetic energy as it descended from position A.

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