A linear function graph has a dotted diagonal line passing through the x-axis at (3, 0), and the y-axis at (0, minus 2) In the function above, the slope will be multiplied by -4, and the y-value of the y-intercept will be decreased by 1 unit. Which of the following graphs best represents the new function? A linear function graph has a diagonal line passing through the x-axis at (1.5, 0), and the y-axis at (0, minus 3) W. A linear function graph has a diagonal line passing through the x-axis at (0.5, 0), and the y-axis at (0, minus 1) X. A linear function graph has a dotted diagonal line passing through the x-axis at (minus 0.5, 0), and the y-axis at (0, minus 1) Y. A linear function graph has a diagonal line passing through the x-axis at (minus 1.5, 0), and the y-axis at (0, minus 3)

Answer:

  b > 1

Step-by-step explanation:

You want to know the conditions on an exponential function that represents growth.

The value of 'b' in the exponential function y = a·b^x is called the "growth factor." Each time x increases by 1 unit, the value of y is multiplied by 'b'. If that product is increasing, the value of 'b' must be greater than 1.

The relation represents growth when b > 1.

An exponential function in the form \(y = ab^x\) represents growth when the base (b) is greater than 1.

In an exponential function of the form y = ab^x, the base (b) is a crucial component. The behavior of the function depends on the value of the base.

When the base (b) is greater than 1, it means that b is a positive number larger than 1. In this scenario, as the value of x increases, the value of \(b^x\) also increases exponentially. This results in the function \(y = ab^x\) exhibiting growth.

To better understand this growth behavior, let's consider an example. Suppose we have an exponential function \(y = 2^x\). As x increases from 0, the values of \(2^x\) will be as follows:

For x = 0, \(2^0\) = 1

For x = 1, \(2^1\) = 2

For x = 2, \(2^2\) = 4

For x = 3, \(2^3\) = 8

For x = 4, \(2^4\) = 16

As you can see, as x increases, the values of \(2^x\) grow exponentially. This demonstrates the growth behavior of exponential functions when the base is greater than 1.

It's important to note that when the base (b) is between 0 and 1 (exclusive), the exponential function will exhibit decay or decreasing behavior rather than growth.

In summary, an exponential function of the form \(y = ab^x\) represents growth when the base (b) is greater than 1. As x increases, the function values increase exponentially, indicating a growth pattern.

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The volume of the box is given by:

V = lwh

where l = 10 cm, w = 16 cm, and h = 5 cm.

The differential of V with respect to l is:

dV = (wh)dl + (lh)dw + (lw)dh

The differential of V with respect to w is:

dV = (lh)dw + (lw)dh + (wh)dl

The differential of V with respect to h is:

dV = (lw)dh + (wh)dl + (lh)dw

Using the maximum error of 1 mm for each measurement, we have:

dl = 0.1 cm

dw = 0.1 cm

dh = 0.1 cm

Substituting these values into the differentials above, we get:

dV ≈ (wh)(0.1) + (lh)(0.1) + (lw)(0.1)

dV ≈ (16 cm x 5 cm)(0.1) + (10 cm x 5 cm)(0.1) + (10 cm x 16 cm)(0.1)

dV ≈ 8 cm^2 + 5 cm^2 + 16 cm^2

dV ≈ 29 cm^2

Therefore, the maximum error in the calculated volume of the box is approximately 29 cm^3.

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X= 1 , X= –7

I hope I helped you^_^

Answer:

15 miles

Step-by-step explanation:

8.80-2.80=6

6/0.40=15 miles

m = miles traveled.

$2.80 + $0.40m = $8.80

Subtract $2.80 from both sides.

$0.40m = $6.00

Divide both sides by $0.40

m = 15

Carmen traveled a total of 15 miles.

Answer:

This might get confusing but bear with me.

The top two are correct, leave them where they are. The 6th one down is step three, the 8th one down is step four, the 3rd one down is step five, the 4th one down is step six, the 7th ne down is step seven so leave it alone, and the 5th one down is step 8.

Answer:

I think 11

Step-by-step explanation:

11 goes in to 33 88 and 110 evenly

Answer:

11x

Step-by-step explanation:

Each term has 'x' so we know that we can factor out the 'x'. Then we are left with

x(33+88+110)

All three of the numbers inside the parenthesis are divisible by 11. So we will get

11x(3+8+10)

There are no more common factors so 11x is the GCF.

According to the model, the minimum cost per unit is obtained for an order of 8 units.

Since the total cost is modeled by;

C(x)=7x²+252

Then;

1 unit costs; C(x)=7(1)²+252= 259

cost per unit 259/1 = 259

8 units costs; C(x)=7(8)²+252 = 700

cost per unit = 700/8 = 87.5

80 units costs; C(x)=7(80)²+252 = 45052

Cost per unit = 45052/80 = 563.15

The minimum cost per unit is obtained for an order of 8 units.

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Answer:

40, 48, 56

Step-by-step explanation:

8x5 is 40

8x6 is 48

8x7 is 56

I hope this helps have a good day

Answer:59280

Step-by-step explanation: Permutation of (40,3)

Answer:

85.2

Step-by-step explanation:

add all scores (98+78+84+75+91)

then with that answer (426)

divide by how many scores there are (5)

Answer:

85.2

Step-by-step explanation:

Answer:

10.6

Step-by-step explanation

i just divided 2.65 and 0.25 and got 10.6(: hoped it helped

a) The values of q that result in a dictator (list all possible values) are: q=13.

b) The smallest value of q that results in exactly one player with veto power who is not a dictator is q=7.

c) The smallest value of q that results in exactly two players with veto power is 16.

Consider the weighted voting system [q: 13, 7, 3].

a)

Which values of q result in a dictator (list all possible values)?

The given voting system is a dictator if one player has enough weight to decide the outcome of every vote.

It's also a dictator if one player has enough weight to outvote every other combination of players.

As a result, in a weighted voting system of [q: 13, 7, 3], the possible values of q that result in a dictator are: q = 13

b)

What is the smallest value for q that results in exactly one player with veto power who is not a dictator?

If one player has veto power, he or she can prevent any coalition of players from winning a vote.

In other words, the other players must band together to form a winning coalition.

In a weighted voting system with n players, one player has veto power if and only if n-1 < qi.

In a weighted voting system of [q: 13, 7, 3], the smallest value of q that results in exactly one player with veto power who is not a dictator is q=7.

c)

What is the smallest value for q that results in exactly two players with veto power?

Two players have veto power in a weighted voting system when they have enough combined weight to outvote every other combination of players.

In a weighted voting system of [q: 13, 7, 3], the possible combinations of players who could have veto power are: {13,7}, {13,3}, and {7,3}.

If two players have veto power, they must also have enough weight to outvote every other combination of players.

As a result, the smallest value of q that results in exactly two players with veto power is 16, which is the combined weight of {13,3}.

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Answer:fixed cost=10

Independent variable=months paid

Dependent=hours on support

month=x,h=hour,10x+35h=total cost

97.50=10+35h

87.50=35h

h=2.5 hours

Step-by-step explanation:

showed work

Answer:

20m

Step-by-step explanation:

write a equation duh

x * 4x = 100

u can split 100 into 5 x 20

x * 4x = 5 * 20

x = 5

and 4x = 20

Answer:

1. B

2. B

3. A

4. B

5. A

6. C

Step-by-step explanation:

i hoped it helped

Answer:

3 pieces of strawberry cake

Step-by-step explanation:

Given data shows they took six pieces and then 9 more.

2/6 or 1/3 were strawberry cake.

1/3 of 9 = 3 pieces of strawberry cake

Answer:

4 strawberry, 5 coconut !!

Step-by-step explanation:

Well, out of the 6 that have been taken so far. 2 were strawberry and 4 were coconut. If this trend in the data continues you can assume that out of the next 9

4 will be strawberry and 5 will be coconut.

Answer:

x = - 11

Step-by-step explanation:

u and v are parallel if you  have equal alternate interior angles .

that is ,

x + 111 = 100

x = 100 - 111

x = - 11

Answer:

1/3 is the slope of the line

the yellow one is correct

For the estimated regression equation determined to predict salary based on years of experience, the estimated salary for an employee with 19 years of experience is $79,283.68.

For the estimated salary for an employee with 19 years of experience, we can substitute the value of 19 into the regression equation:

Estimated Salary = 27,709.94 + 2712.46(Years of experience)

Estimated Salary = 27,709.94 + 2712.46(19)

Calculating this expression:

Estimated Salary = 27,709.94 + 51,573.74

Estimated Salary = 79,283.68

Therefore, the estimated salary for an employee with 19 years of experience is $79,283.68.

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The probability of drawing a seven and then a four when randomly drawing two cards without replacement is 0.0045 or approximately 0.45%.

The probability of drawing a seven and then a four when randomly drawing two cards without replacement can be calculated using the following steps:

First, we need to determine the total number of possible outcomes when drawing two cards from a standard deck of 52 cards without replacement. This can be found using the combination formula:

C(52,2) = 52! / (2! * (52-2)!) = 1,326

Next, we need to determine the number of favorable outcomes where we draw a seven and then a four.

There are four sevens and four fours in a deck of 52 cards, so the probability of drawing a seven on the first draw is 4/52. Since we are not replacing the card, there are now 51 cards left in the deck, and three of them are fours. Therefore, the probability of drawing a four on the second draw is 3/51.

The probability of drawing a seven and then a four is the product of the probabilities of drawing a seven on the first draw and a four on the second draw:

P(seven and then four) = (4/52) * (3/51) = 0.0045 or approximately 0.45%.

Therefore, the probability of drawing a seven and then a four when without replacement is 0.0045 or approximately 0.45%.

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Answer:

11.5

Step-by-step explanation:

the mean of a set of numbers is the sum divided by the number of terms

(15+4+6+12+16+20+16+3)/8

The required mean of the data for the sample of Dr. Frank's dentist office is  11.5.

Given that,
The number of patients treated at Dr. Frank's dentist's office each day was recorded for eight days: 15, 4, 6, 12, 16, 20, 16, 3. Using the given data, find the mean for this sample is to be determined.

The average of the values is the ratio of the total sum of values to the number of values.

Here,
The number of patients treated was recorded for eight days,
Sample space =  15, 4, 6, 12, 16, 20, 16, 3
n(s) = 8
Mean = (15 + 4 + 6 + 16 + 20 + 16 + 3) / 8
Mean = 92 / 8
Mean = 11.5

The required mean of the data for the sample of Dr. Frank's dentist office is  11.5.

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Answer:

15 x -5y -6 -2y

-75y -6 -2y

-77-6

An example of two nonlinear functions that don't dominate each other is the sin function (f(x) = sin(x)) and the exponential function (g(x) = e^x).

For any given value of x, the sin function oscillates between -1 and 1, taking on both positive and negative values. It has a periodic nature and does not grow or decay exponentially as x increases or decreases.

On the other hand, the exponential function grows or decays exponentially as x increases or decreases. It is characterized by a constant positive growth rate. The exponential function increases rapidly when x is positive and approaches zero as x approaches negative infinity.

The key characteristic here is that the sine function oscillates while the exponential function grows or decays exponentially.

Due to their fundamentally different natures, neither function dominates the other over their entire domains.

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Answer:

Step-by-step explanation:

The y-intercept corresponds to number of gallons at zero minutes, this is the initial point (0, 480), so 480 is the y-intercept.

Take one more pair of values (5, 320) and find the slope.

Since probabilities cannot be negative, we can conclude that the given probabilities are inconsistent or there might be an error in the information provided. Please verify the values and provide correct probabilities so that we can accurately calculate P(B|A), the probability of the flight being delayed when it is raining.

Let's denote the events as follows:

A: It will rain

B: The flight will be delayed

We are given the following probabilities:

P(A) = 0.11 (probability of rain)

P(B) = 0.14 (probability of flight delay)

P(A'∩B') = 0.76 (probability of no rain and on-time departure)

We can use the probability formula to calculate the probability of the flight being delayed when it is raining, P(B|A), which is the probability of B given A.

We know that:

P(B|A) = P(A∩B) / P(A)

To find P(A∩B), we can use the formula:

P(A∩B) = P(A) - P(A'∩B')

Substituting the given values:

P(A∩B) = P(A) - P(A'∩B')

P(A∩B) = 0.11 - 0.76

P(A∩B) = -0.65

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The first 3 terms of the sequence are 21, 24 and 29

From the question, we have the following parameters that can be used in our computation:

n² + 20

This means that

f(n) = n² + 20

The first 3 terms of the sequence is when n = 1, 2 and 3

So, we have

f(1) = 1² + 20 = 21

f(2) = 2² + 20 = 24

f(3) = 3² + 20 = 29

Hence, the first 3 terms of the sequence are 21, 24 and 29

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Answer:

Step-by-step explanation:

Complementary          Supplementary

40°,50°                          90°,90°

45°,45°                          80°, 100°

60°,30°                         60°,120°

Answer: the answer is b . negative Infinity infinity and positive 8

The probability that an arriving student will find at least one other student waiting in line is approximately 0.167.

To solve this problem, we'll use the M/M/1 queueing model with Poisson arrivals and exponential service times. Let's calculate the required values: (a) Percentage of time Judy is idle: The utilization of the system (ρ) is the ratio of the average service time to the average interarrival time. In this case, the average service time is 10 minutes, and the average interarrival time is 12 minutes. Utilization (ρ) = Average service time / Average interarrival time = 10 / 12 = 5/6 ≈ 0.8333

The percentage of time Judy is idle is given by (1 - ρ) multiplied by 100: Idle percentage = (1 - 0.8333) * 100 ≈ 16.67%. Therefore, Judy is idle approximately 16.67% of the time. (b) Average waiting time for a student:

The average waiting time in a queue (Wq) can be calculated using Little's Law: Wq = Lq / λ, where Lq is the average number of customers in the queue and λ is the arrival rate. In this case, λ (arrival rate) = 1 customer per 12 minutes, and Lq can be calculated using the queuing formula: Lq = ρ^2 / (1 - ρ). Plugging in the values: Lq = (5/6)^2 / (1 - 5/6) = 25/6 ≈ 4.17 customers Wq = Lq / λ = 4.17 / (1/12) = 50 minutes. Therefore, on average, a student spends approximately 50 minutes waiting in line.

(c) Average length of the line: The average number of customers in the system (L) can be calculated using Little's Law: L = λ * W, where W is the average time a customer spends in the system. In this case, λ (arrival rate) = 1 customer per 12 minutes, and W can be calculated as W = Wq + 1/μ, where μ is the service rate (1/10 customers per minute). Plugging in the values: W = 50 + 1/ (1/10) = 50 + 10 = 60 minutes. L = λ * W = (1/12) * 60 = 5 customers. Therefore, on average, the line consists of approximately 5 customers.

(d) Probability of finding at least one student waiting in line: The probability that an arriving student finds at least one other student waiting in line is equal to the probability that the system is not empty. The probability that the system is not empty (P0) can be calculated using the formula: P0 = 1 - ρ, where ρ is the utilization. Plugging in the values:

P0 = 1 - 0.8333 ≈ 0.1667. Therefore, the probability that an arriving student will find at least one other student waiting in line is approximately 0.167.

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