A line passes through the points (-5, 2) and (10,-1). Which is the equation of the line?
o y=-3x+1
O y-zx=3
O y = -5x – 23
O y = 5x + 27
HURRY

To discover the t-value for testing a person parameter at the 1% level, we ought to isolate the coefficient appraise by its standard deviation and compare it to the t-distribution with suitable degrees of flexibility.

For case, to test the parameter gauge for x1, we would calculate the t-value as: t = (-3.682) / 2.630 ≈ -1.4

At that point compare this t-value to the t-distribution with 485 degrees of flexibility (which compares to the leftover degrees of opportunity), and decide on the off chance that it surpasses the basic esteem at the 1% level (which is around 2.977).

In any case, the given yield does not demonstrate which parameter appraise is being tried, so we cannot decide the comparing t-value. Hence, none of the reply choices are rectified.

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The general solution to the differential equation y''-8y'+20y=0 is y = c₁e^(4x)cos(2x) + c₂e^(4x)sin(2x).

To find the general solution to y''-8y'+20y=0, we can assume a solution of the form y=e^(rt), where r is a constant. Substituting this into the differential equation, we get:

r^2e^(rt) - 8re^(rt) + 20e^(rt) = 0

We can factor out e^(rt) and simplify to get:

(e^(rt))(r^2 - 8r + 20) = 0

Since e^(rt) is never zero, we can focus on solving the quadratic equation r^2 - 8r + 20 = 0. Using the quadratic formula, we get:

r = (8 ± √(8^2 - 4(1)(20))) / 2

r = 4 ± 2i

Thus, the general solution is a linear combination of the two solutions:

y = c₁e^(4x)cos(2x) + c₂e^(4x)sin(2x)

where c₁ and c₂ are arbitrary constants determined by the initial conditions of the problem.

This is the general solution to the differential equation y''-8y'+20y=0. The solution consists of two parts, each containing an exponential term with a constant factor and a trigonometric function with a different phase shift.

The constants c1 and c2 are determined by the initial conditions, such as the value of y and its derivative at a certain point. The solution represents all possible solutions to the differential equation, and any specific solution can be obtained by setting appropriate initial conditions.

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To calculate the gain on the sale of the office furniture, we need to determine the asset's book value and compare it to the sale price.

First, let's calculate the accumulated depreciation on the furniture. The furniture was purchased on January 1, 2014, and the straight-line depreciation method is used over 10 years with a salvage value of $80,200.

Depreciation per year = (Cost - Salvage Value) / Useful Life

Depreciation per year = ($746,800 - $80,200) / 10 years

Depreciation per year = $66,160

Next, we need to calculate the accumulated depreciation for the period from January 1, 2014, to May 1, 2021 (the date of the sale). This is approximately 7.33 years.

Accumulated Depreciation = Depreciation per year × Years

Accumulated Depreciation = $66,160 × 7.33 years

Accumulated Depreciation = $484,444.80

Now, we can calculate the book value of the furniture:

Book Value = Cost - Accumulated Depreciation

Book Value = $746,800 - $484,444.80

Book Value = $262,355.20

Finally, we can calculate the gain on the sale:

Gain on Sale = Sale Price - Book Value

Gain on Sale = $300,000 - $262,355.20

Gain on Sale = $37,644.80

Therefore, the gain that should be recognized on the sale of the office furniture is approximately $37,644.80.

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The gain that should be recognized on the sale of the office furniture is $84,080.

The gain is calculated by subtracting the equipment's book value from the sale price. This gain will be reported on the company's income statement. Here is how to calculate the gain:First, find the equipment's book value using the straight-line method of depreciation.

Straight-line depreciation is calculated by taking the difference between the equipment's original cost and its salvage value, and then dividing it by the number of years the equipment is used. The annual depreciation expense is then multiplied by the number of years the equipment is used to find the equipment's book value at the end of its useful life.

For this question, the book value of the equipment at the time of sale is:Cost of equipment: $746,800Salvage value: $80,200Depreciable cost: $746,800 - $80,200 = $666,600Annual depreciation: $666,600 ÷ 10 years = $66,660Book value at the end of 2020: $666,600 - ($66,660 x 7) = $156,420

Next, subtract the equipment's book value from the sale price to find the gain:Sale price: $300,000Book value: $156,420Gain: $143,580Finally, round the gain to the nearest dollar:$143,580 ≈ $143,580.00So the gain that should be recognized on the sale of the office furniture is $84,080.

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Answer:

5/3 is the slope

Step-by-step explanation:

The length c of the right angle triangle is 9 units.

A right angle triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a right angle triangle is 180 degrees.

The sides of a right angle triangle can be found using trigonometric ratios as follows:

Therefore,

sin 60° = opposite / hypotenuse

where

opposite side = c

hypotenuse side = 6√3 ft

Hence,

sin 60° = c / 6 √3

cross multiply

c = 6√3 × sin 60

c  = 6√3 × √3 / 2

c = 6 × 3 / 2

c = 18 / 2

Therefore,

c = 9 units

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Answer:

Step-by-step explanation:

a line is 180° so we subtract 109 from 180 to find mLUE

180-109=

71

a triangle is also 180° so we add up the angles we have so far and subtract that from 180°

180-(71+49)

180-(120)

mULE = 60°

Answer:

x=\(\frac{m}{k-n}\)

Step-by-step explanation:

First you subtract nx from both side getting kx-nx=m.

Then you factor out x getting x(k-n)=m

and now you divide both sides from (k-n) and you will get the answer.

The system of equations that matches the given graph is:

A. 3x - 6y = 12

9x - 18y = 36

To determine which system of equations matches a given graph, we need to analyze the slope and intercepts of the lines in the graph.

Looking at the options provided:

A. 3x - 6y = 12

9x - 18y = 36

B. 3x + 6y = 12

9x + 18y = 36

Let's analyze the equations in each option:

For option A:

The first equation, 3x - 6y = 12, can be rearranged to slope-intercept form: y = (1/2)x - 2.

The second equation, 9x - 18y = 36, can be simplified to 3x - 6y = 12, which is the same as the first equation.

In option A, both equations represent the same line, as they are equivalent. Therefore, option A does not match the given graph.

For option B:

The first equation, 3x + 6y = 12, can be rearranged to slope-intercept form: y = (-1/2)x + 2.

The second equation, 9x + 18y = 36, can be simplified to 3x + 6y = 12, which is the same as the first equation.

In option B, both equations also represent the same line, as they are equivalent. Therefore, option B does not match the given graph.

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Percent represents the time Joey spent on his homework from Monday to Wednesday is 0.0114 % .

Given :-

On Monday Joe finished his homework in 32 mins

On Wednesday joe finished his homework in 2 mins .

Divide the number of hours John spent doing math homework by the number of hours John spent doing homework to obtain the fraction

n of his total time spent doing homework did he spend .

To find the percentage that how much it represents the time Joey spent on his homework from Monday to Wednesday will be

= 32 / 28

=  1.1428 %

To find the percentage we have to divide it by 100 which means

1.14 X  1 / 100

= 0.0114 %

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Answer:

1800

Step-by-step explanation:

75 mL x 24 hours =1800mL

Answer:

im not really good at drawing but Can I ask a question can I help you with other questions?

Step-by-step explanation:

The probability that is true is P(D or E) = 0.72.

Option D is the correct answer.

We have,

We can start by using the formula:

P(D and E) = P(D) x P(E)

Since D and E are independent events, their probabilities multiply to give the probability of both events happening together.

Plugging in the given values.

0.18 = 0.6 x P(E)

Solving for P(E).

P(E) = 0.18 / 0.6 = 0.3

So option (A) is not correct.

To find P(D or E), we can use the formula:

P(D or E) = P(D) + P(E) - P(D and E)

Plugging in the given values.

P(D or E) = 0.6 + 0.3 - 0.18 = 0.72

Thus,

P(D or E) = 0.72 is true.

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Answer: 5

Step-by-step explanation:

Therefore, the annual annuity payment can be approximately $6,069,727.

To calculate the size of the annual annuity payment, we can use the present value formula for an ordinary annuity. The formula is given by:

PMT = PV / [(1 - (1 + r)⁻ⁿ) / r]

Where:

PMT = Annual annuity payment

PV = Present value of the annuity

r = Annual interest rate

n = Number of periods

Given:

PV = $230 million

r = 8% = 0.08

n = 40 years

Using the formula, we can calculate the annual annuity payment:

PMT = 230,000,000 / [(1 - (1 + 0.08)⁻⁴⁰) / 0.08]

PMT ≈ $6,069,727

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Answer:

y=0.25x^2−2x

Step-by-step explanation:

You have to use the disruptive property.

The term that describes jellyfish skeletons formed by fluid-filled compartments is hydrostatic skeletons.

Hydrostatic skeletons are a type of skeletal system found in certain invertebrates, including jellyfish. These skeletons rely on the pressure of fluid within the body to provide support and maintain the body structure. In jellyfish, the fluid-filled compartments act as a hydrostatic skeleton, resisting compression and preventing the body from collapsing or deforming. This enables jellyfish to maintain their shape and move through the water with flexibility. By adjusting the internal pressure of the fluid-filled compartments, jellyfish can control their buoyancy and movement. Hydrostatic skeletons are advantageous for organisms that live in aquatic environments, allowing for efficient locomotion and adaptation to varying water conditions.

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Answer:

Solution given:

\(4\frac{2}{3}÷7\)

=\( \frac{4*3+2}{3}×\frac{1}{7}\)

=\(\frac{14}{3*7}\)

=\(\frac{2}{3}\) is a required answer.

Answer:

Step-by-step explanation:

Given question is incomplete; here is the complete question.

The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with 10-meter sides. The heights of the pyramids are the same.

The volume of pyramid A is ____ the volume of pyramid B. If the height of pyramid B increases to twice that of pyramid A, the new volume of pyramid B is ______the volume of pyramid A.

Since, volume of pyramid = \(\frac{1}{3}(\text{Area of the base})(\text{Height})\)

Volume of the pyramid A = \(\frac{1}{3}(\text{length}\times \text{Width})(\text{height})\)

                                          = \(\frac{1}{3}(10\times 20)(h)\)

                                          = \(\frac{200h}{3}\)

Volume of pyramid B = \(\frac{1}{3}(10)^2(h)\)

                                    = \(\frac{100h}{3}\)

Ratio of the volumes of the pyramids = \(\frac{\text{Volume of pyramid A}}{\text{Volume of pyramid B}}\)

                                                              = \(\frac{\frac{200h}{3}}{\frac{100h}{3} }\)

                                                              = 2

Therefore, volume of pyramid A is TWICE the volume of pyramid B.

If If height of the pyramid B increases twice of pyramid A,

Then the volume of pyramid B = \(\frac{1}{3}(100)(2h)\)

                                                   = \(\frac{200h}{3}\)

Ratio of volumes of pyramid B and pyramid A = \(\frac{\text{Volume of pyramid B}}{\text{Volume of pyramid A}}\)

                                                                            = \(\frac{\frac{200h}{3}}{\frac{200h}{3}}\)

                                                                            = 1

Therefore, new volume of pyramid B is EQUAL to the volume of pyramid A.  

Answer:

Step-by-step explanation:

I can't think of many ratios, but here are two:

Ashanti sored:

(9 points)/(1 game), and

(1 game)/(9 points)

If she maintains an average of (9 points)/(1 game), after 14 games we would predict:

(9 points)/(1 game)*(14 games) = 126 points total

The number of fruits sold on the first day is 18.125 kg

Let

= 27 × ( x + x - 25)

= 27 × (2x - 25)

= 54x - 675

315 = x + (x - 25) + (54x-675)

315 = x + x - 25 + 54x - 675

315 = 56x - 700

315 + 700 = 56x

1015 = 56x

x = 1015 / 56

= 18.125 kg

Number of fruits sold on the second day = x

= 18.125kg

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The amount in kilogram of fruit the grocer sold each day is as follows:

First day sales(kg) = 110 kg

Second day sales(kg) = 135 kg

Third day sales(kg)  = 70 kg

Let

the amount he sold on the second day = x

He sold 25 fewer kilograms of fruit on the first day of operation than he did on the second day. Therefore, the first day sales will be as follows;

On the third day, the grocer sold 2 / 7 of the fruit he had sold on the first and second days combined. Therefore, the third day sales will be as follows:

If he sold 315 kg in total the amount he sold each day can be calculated as follows:

2x - 25 + 4x / 7 - 50 / 7 = 315

2x + 4x / 7 = 315 + 25 + 50 / 7

14x + 4x / 7 = 340 + 50 / 7

18x / 7 = 2380 + 50 / 7

18x / 7 = 2430 / 7

18x = 2430

x = 2430 / 18

x = 135

Therefore,

First day sales(kg) = 135 - 25 = 110 kg

Second day sales(kg) = 135 kg

Third day sales(kg) = 315 - 135 - 110 = 70 kg

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a. All collections on the preceding page and its content are well-defined.

b. The difficulty in deciding whether a given collection is a set or not usually arises when the criteria for membership in the collection are ambiguous or subjective.

c. A collection of happy people can be considered a set, depending on how it is defined and the context in which it is used.

d. Collections of people with pretty faces are not well-defined because the notion of beauty or prettiness is subjective and can vary from person to person.

The preceding page and its content.

The collection is based on personal preferences or opinions, it becomes challenging to determine whether an item belongs to the collection. Another challenge is when the collection includes elements that are themselves collections or have complex properties.

If the criteria for membership in the collection are well-defined and objective, such as people who exhibit certain behaviors or express happiness in a measurable way, then it can be considered a set.

If the criteria are subjective or vague, such as being perceived as happy by others, it becomes difficult to determine membership and the collection may not be well-defined.

One person finds attractive, another may not.

Beauty is influenced by cultural, societal and personal preferences, making it difficult to establish clear and objective criteria for determining membership in such a collection.

collections of people with pretty faces are not well-defined sets.

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1. The minor |M₁2| of matrix A is -18. 2. The cofactor C32 of matrix A is 4. 3. The cofactor C22 of matrix A is -2. 4. Using cofactor expansion about the 2nd row, the determinant of matrix A is (-4)(-9)-(-1)(-1)+(2)(15) = -67.

1. To find the minor |M₁2|, we need to take the determinant of the submatrix formed by removing the 1st row and the 2nd column of matrix A. The submatrix is just a scalar, which is 1. Therefore, the minor |M₁2| is -18.

2. The cofactor C32 can be found by multiplying the minor |M₃2| by (-1)^(3+2). Since |M₃2| is equal to -18, we have C32 = -18 * (-1)^(3+2) = 4.

3. Similarly, the cofactor C22 can be found by multiplying the minor |M₂2| by (-1)^(2+2). Since |M₂2| is equal to 1, we have C22 = 1 * (-1)^(2+2) = -2.

4. The determinant of matrix A can be calculated using cofactor expansion about the 2nd row. We multiply each element of the 2nd row by its corresponding cofactor and sum them up. The determinant is given by det A = (-4)(-9)-(-1)(-1)+(2)(15) = -36+1+30 = -5+30 = -67.

Therefore, the minor |M₁2| is -18, the cofactor C32 is 4, the cofactor C22 is -2, and the determinant of matrix A is -67.

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so we know the equation to get the total forces is

\(\cfrac{Kg\cdot m}{s^2} ~~ \begin{cases} Kg=kilograms\\ m=meters\\ s=seconds \end{cases}\implies Kg\cdot \cfrac{m}{s^2}\implies Kg\cdot (acceleration)\)

the idea being, well, we have to do unit conversion, we know the object has a mass of 80 grams, hmmm that's not Kilograms, however since there are 1000 grams in a Kg, we can just convert that, and the acceleration of it is 20 m/s², so

\(\stackrel{ Kilograms }{\cfrac{80}{1000}}\cdot \stackrel{ accelaration }{20}\qquad \impliedby \textit{sum of the forces}\)

Answer:

Solution Given:

let pitcher which is small be S medium be M and large be L and barrel be B.

By question

6S+3M+1L= 1B...... eq. 1

2S+1M+3L=1B.......eq. 2

The difference in 2L from the first to the second is 4S and 2M

Therefore, each L=2S+M

In equation 2

2S+1M+3L=1B

replacing 2S +1M by L,we get

L+3L=1B

4L=1B

Therefore, 4 large pitcher is required

Answer:

4 large pitchers

Step-by-step explanation:

Define the variables:

Create two equations with the given information and the defined variables.

Equation 1

If the barrel can be filled with 6 small pitchers, 3 medium pitchers and 1 large pitchers:

⇒ 6x + 3y + z = b

Equation 2

If the barrel can be filled with 2 small pitchers, 1 medium pitcher and 3 large pitchers:

⇒ 2x + y + 3z = b

Substitute Equation 2 into Equation 1

⇒ 6x + 3y + z = 2x + y + 3z

Subtract 6x from both sides:

⇒ 3y + z = -4x + y + 3z

Subtract y from both sides:

⇒ 2y + z = -4x + 3z

Subtract z from both sides:

⇒ 2y = -4x + 2z

Divide both sides by 2:

⇒ y = -2x + z

Substitute the found expression for y into Equation 1:

⇒ 6x + 3(-2x + z) + z = b

⇒ 6x - 6x + 3z + z = b

⇒ 4z = b

Therefore, 4 large pitchers are needed to fill the barrel.

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Answer: C. \(\sqrt{9} * \sqrt{4}\)

Step-by-step explanation:

There is a square root rule that states \(\sqrt{x*y} = \sqrt{x} * \sqrt{y} \\\)

We can apply this rule to this problem.

Given \(\sqrt{9*4}\)

We can use the rule to make it equal to \(\sqrt{9} * \sqrt{4}\)

This is answer choice C.

Answer: c

Step-by-step explanation: 9*4=36          36* 36 = 1296

9 * 9 = 81      4 * 4 = 16       81 * 16 =  1296    hope this helps

Answer:

f(1) = 257

Step-by-step explanation:

x-variable: 1 (time is the independent variable)

y-variable: 257 (number of visitors is the dependent variable)

When the time is at 1 (1pm), there are 257 visitors

Answer:

Step-by-step explanation: