a lapidary cuts a diamond so that the light will refract at an angle of 17.0° to the normal. what is the index of refraction of the diamond when the angle of incidence is 45.0°?

Answer:

I'm not that busy solving but I'll tell you the formula that Force x distance is equal to work done

The work is done on a pumpkin when we lift it by 15 m with 24 N is 360 J

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J).  

i.e. Work(W) is force(F) times displacement(s).

W=F× s

When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.

Writing for it's dimension,

W=F× s

Force has dimension [L¹ M¹ T²]

Displacement has dimension [L¹]

multiplying both the dimensions Force and Displacement  

we get,

dimension of Work [L² M¹ T²]

According to newton's second law of motion,

Force(F) is mass(M) times acceleration(a).

i.e. F=ma

Given,

Force = 24 N

Displacement = 15 m

W=F.s= 24*15 = 360 J

Hence work done on pumpkin is 360 J

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Answer:

Acceleration =13.63m/s^2

initial velocity = v = 45

final velocity = u = 0

acceleration = v-u/t

Answer:

F = M a    and  a = (V2 - V1) / t

If a equals zero (constant velocity) then no external forces are present

Answer:

2000g

Explanation:

volume=mass/density

=2000/2.5

=800cm³

mass=density×volume

=800×2.5

=2000g

The required net electric field in unit-vector notation when the charge on the particles is specified is calculated to be -6.39 × 10⁵ N/C i.

The charge on the particle 1 is given as -2× 10⁻⁷ c.

The charge on the particle 2 is given as 2× 10⁻⁷ c.

x₁ is given as 6 cm and x₂ is given as 21 cm.

Let x be the point midway of the two positions.

x = 13.5 cm

The magnitude and direction of individual electric fields is calculated as,

E₁ = -q₁/(4πε₀)(x - x₁)² = 9 × 10⁹|(-2× 10⁻⁷)|/(0.135 - 0.06) = -3.196 × 10⁵ N/C i

E₂ = -q₂/(4πε₀)(x - x₂)² = 9 × 10⁹|(2× 10⁻⁷)|/(0.135 - 0.21) = -3.196 × 10⁵ N/C i

The net electric field is given as,

E net = E₁ + E₂ = -6.39 × 10⁵ N/C i

The given question is inappropriate. The complete question is 'Two charged particles are attached to an x axis: particle 1 of charge -2 × 10⁻⁷ c is at position x = 6 cm and particle 2 of charge 2× 10⁻⁷ c is at position x = 21.0 cm. midway between the particles, what is their net electric field in unit-vector notation?'

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Answer:

8.37757

Explanation:

may i have brainliest

so the answer is easy it's air

Answer:

The reasons behind it include the environmental cost of manufacturing and how many miles per gallon a car gets.

a study reveals that fully 75 percent of a car's lifetime carbon emissions stem from the fuel it burns, not its production. A further 19 percent of that is production and transportation of the fuel, leaving just six percent for the car's manufacture.

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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The estimated age of the Universe can be calculated using the Hubble constant. If the Hubble constant is 80 km/s/Mpc, the estimated age of the Universe is approximately 13.8 billion years. Given that the star created at the beginning of the Universe has a lifespan of 11 billion years (tsun = 11 billion years), it would still be around today.

The Hubble constant is a measure of the rate at which the Universe is expanding. By using the Hubble constant, the age of the Universe can be estimated using the reciprocal of the Hubble constant. If the Hubble constant is 80 km/s/Mpc, the estimated age of the Universe is approximately 1 / (80 km/s/Mpc) = 13.8 billion years.

Considering the estimated age of the Universe as 13.8 billion years and the lifespan of a star with the same mass as our Sun as 11 billion years, it is evident that the star created at the beginning of the Universe would still be around today. Since the estimated age of the Universe is greater than the lifespan of the star, it indicates that the star would not have reached the end of its life yet and would still exist in the present time. Therefore, the answer is yes, a star created at the beginning of the Universe with the same mass as our Sun could still be around today.

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Answer:

Design 2

Explanation:

I had this same question

My answer:

"Design 2 is the well-designed one, because the air molecules are the most compact and could protect the individual better than 1,3,and no air bag."

X-rays are electromagnetic radiation with a high frequency and energy. They have frequencies between 3 and 1016 Hz and wavelengths between 0.01 to 10 nanometers. They are discovered to exist in the electromagnetic spectrum's region between ultraviolet and gamma rays.

What distinguishes X-rays from other electromagnetic waves?

X-rays are a part of the electromagnetic spectrum. Light waves get more energetic as their wavelengths shorten. X-rays are more energetic because they have shorter wavelengths. When discussing X-rays, we frequently refer to their energy rather than its wavelength.

Compared to ultraviolet light, x-rays have far higher energies and shorter wavelengths; therefore, scientists normally talk about x-rays in terms.

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Answer:

I think its because of the way our eyes see colors

Explanation:

yellow is between green and orange on the spectrum of visible light. that is why it is called the ' yellow ' light

The magnitude of the acceleration is  −0.50 m/s² of the block of mass 290kg that slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 .

The resulting motion is

2. up the plane, since the acceleration is negative.

Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an object or point moving straight ahead.

Due to the constant change in direction, motion on a circle accelerates even when the speed is constant. Both effects help to accelerate all other types of motion.

We have given that,

m = 290 kg

θ = 39◦

F = 1643 N

g = 9.8 m/s²

The force due to gravity

F₁ = m × g × sinθ

F₁ = 290 × 9.8 × sin 39°

F₁ = 1790.46 N

Lets take acceleration is a m/s²

Form Newtons second law

F - F₁ = m × a

1643 - 1790.46 = 290 x a

a = −0.50 m/s²

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The Amway Center is a multi-purpose arena located in downtown Orlando, Florida, United States. It is primarily used for basketball games, ice hockey matches, concerts, and other events.

The basketball floor is put into place following a rock concert by dismantling the concert stage and equipment and then removing the temporary flooring that was laid down for the concert.

The basketball floor is then transported into the arena on trucks and assembled piece by piece.

The Amway Center is a multi-purpose arena located in downtown Orlando, Florida, United States.

The basketball floor is put into place following a rock concert by dismantling the concert stage and equipment and then removing the temporary flooring that was laid down for the concert.

The basketball floor is then transported into the arena on trucks and assembled piece by piece.

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Integrating the given acceleration function twice, we find that the the position of the particle at time t = 14 is 10039 units.

Acceleration function: a(t) = 18t+18

To find the velocity function, we integrate the acceleration function with respect to time:

v(t) = ∫ a(t)dt = ∫(18t+18)dt=9t2 + 18t + C1

We know that the velocity at time t = 0 is v(0) = 3, , so we substitute these values into the velocity equation to find the constant C1 :

v(0) = 9(0)2 + 18(0) + C1 = C1 =3

Therefore, the velocity function is: v(t) = 9t2 + 18t + 3

To find the position function, we integrate the velocity function with respect to time:

s(t) = ∫v(t)dt = ∫( 9t2 + 18t + 3) dt = 3t3 + 9t2 + 3t + C2

We know that the position at time t = 0 is s (0) = 1, so we substitute these values into the position equation to find the constant C2 :

s(0) = 3(0)3 + 9(0)2 + 3(0) + C2 = C2 = 1

Therefore, the position function is: s(t) = 3t3 + 9t2 + 3t + 1

To find the position at time t = 14, we substitute t = 14  into the position equation:

s(14) = 3(14)3 + 9(14)2 + 3(14) + 1

s(14) = 3(2744) + 9(196) + 42 + 1

s(14) = 8232 + 1764 + 42 + 1

s(14) = 10039

Therefore, the position of the particle at time t = 14 is 10039 units.

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Answer:

The strength of gravity decreases.

An example of that would be if you were in space; you float around because there's no gravity.

(1) The time does pilot take the weight to hit the ground = 2.4 s

(2) The pilot travel before land = 400 m

Because fall time is proportional to fall height and acceleration due to gravity (g) is constant,

t₁ = t₂  

s₁ = initial distance

s₂ = final distance

t₁ = initial time

t₂ = final time

Hence, the time does it take the weight to hit the ground = 2.4 s

The initial distance (s₁) = 200 m, and the pilot does a run at the same height but twice the speed.

So, the  pilot travel before land:

s₂ = 2 x s₁

= 2 x 200 m

= 400 m

The question is incomplete, it should be:

There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. A pilot flying low and slow drops a weight; it takes 2.4 s to hit the ground, during which it travels a horizontal distance of 200 m. Now the pilot does a run at the same height but twice the speed. How much time does it take the weight to hit the ground? How far does it travel before it lands?

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If the plane is moving blank 120 km/h, the velocity used to complete the statement is 1. west at 120km/h. and 3. North at 120km/h.

The assertion "A plane is moving at 120km/h" gives data about the speed of the plane. Notwithstanding, to completely depict the movement of an article, both speed and course are required, which together make up speed. In this manner, choices 1 and 3 give guidance alongside the speed, making them reasonable choices to finish the assertion. Choice 2 just gives a subjective depiction of the speed, which isn't adequate to portray speed. Choice 4 just gives data about the sort of speed however provides no data about the guidance. In this manner, choices 1 and 3 are the ones in particular that make a legitimate speed esteem when used to finish the assertion.

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The complete question is:

A plane is moving blank 120km/h.

Which of the following options make a velocity value if used to complete the statement

Select all that apply

1. West at 120km/h.

2. At a low velocity of 120km/h.

3. North at 120km/h.

4. At a cruising velocity of 120km/h.

The statement that describes at t =5 second is is the object speed up.

According to Newton's second law of motion, the acceleration of a body is equal to the net force acting on the body divided by its mass, a = Fm. This acceleration equation can be used to calculate the acceleration of an object if the mass of the object and the net force acting on it are known. The only acceleration of the projectile is the downward acceleration due to gravity.

The projectile has a vertical acceleration of 9.8 m/s/s throughout its trajectory. This acceleration value is constant. This means that the vertical velocity changes by the same amount every second. Instantaneous velocity is the speed of an object at a particular point in time. If the velocity is constant the average velocity for any time interval will not differ from the instantaneous velocity at that point in time.

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Answer:

Explanation:

Oxide ion I think.

Answer: about 1,100,000,000 to 1,500,000,000 Joules/second

Explanation:

1 MW (megawatt) = 1,000,000.00 J/s (joules per second)

1100(1,000,000) = 1,100,000,000

1500(1,000,000) = 1,500,000,000

The solubility of silver carbonate in water at 25°C is approximately

1.28 x 10⁻⁴ g/L

To calculate the solubility of silver carbonate (in water at 25°C, we need to use the solubility product constant (Ksp) and the balanced chemical equation for the dissociation of silver carbonate.

The balanced chemical equation for the dissociation of Ag2CO3 is

Ag₂CO₃(s) ⇌ 2Ag+(aq) + CO₃²-(aq)

Using the Ksp expression for Ag₂CO₃

Ksp = [Ag+]² [CO3²-]

substituting the equilibrium concentrations:

8.4 x 10⁻¹² = (2x)² * x

Simplifying the equation

8.4 x 10⁻¹² = 4x³

2.1 x 10⁻¹²  = x³

taking the cube root of both sides

x ≈ 1.28 x 10⁻⁴ g/L

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