A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to reach thermal equilibrium. What is the final temperature of the iron and water, given that the specific heat of iron is 0.449 J/(g·°C)? Assume no heat is lost to surroundings.
final= _______ degrees Celsius

Answer:

When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.

Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.

Answer:

2.8 m

Explanation:

:)

Chlorine gas occupies a volume of 25 mL at 300 K, 46 ml volume will it occupy at 600 K.

Initial volume V₁ = 25 mL

Final volume V₂ = ?

Initial temperature T₁ = 300 K

Final temperature T₂ = 600 K

To find out the final volume we will use the following equation.

V₁/T₁ = V₂/T₂

Rearrange it for V₂

Final volume V₂ = V₁/T₁ × T₂

Final volume V₂ = 23 ml / 300 ml × 600 K

Final volume V₂ = 0.0767

Final volume V₂ = 46 ml

46 ml volume will it occupy at 600 K.

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1.39 × 10²³ particles CuCr₂O₇

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 64.5 g CuCr₂O₇

[Solve] particles CuCr₂O₇

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of Cr - 52.00 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CuCr₂O₇ - 63.55 + 2(52.00) + 7(16.00) = 279.55 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.38944 × 10²³ particles CuCr₂O₇ ≈ 1.39 × 10²³ particles CuCr₂O₇

H2Se(g) + 402F2(g) ⇒SeF6(g) + 2HF(g) + 4O2(g) is true regarding following points ;

B. the oxidation number of H changes from -1 to +1 we can see as in H2Se changes to 2F.

C. the oxidation number of F changes from -1 to +1 we can see in O2F2 to        

     4O2.

D. the oxidation number of Se changes from -2 to +6 as we can see in H2Se to SeF6.

oxidation number also called oxidation state, is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

disproportionation reaction is the type of reaction when the compound is converted into 2 oxidation states one of higher and one of lower oxidation state.

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Answer:

Magnetism

Explanation:

iron filings are metallic and they can easily be attracted to magnets while sand cannot be attracted to magnets

Answer:b

Explanation:

i took the test

Because hydrogen and oxygen are combining to create a single product, the formation of water from these two elements is a combination reaction. The following happens as a result: 2H2(g)+O2(g)→2H2O(l)

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To balance the equation HNO3 + BA(OH)2 -> H2O + BA(NO3)2, we need to ensure that the number of atoms of each element is equal on both sides of the equation.

Looking at the left side, we have one nitrogen atom (N) in HNO3 and one nitrogen atom in BA(NO3)2. So, we don't need to adjust the nitrogen atoms.

Now let's balance the hydrogen (H) atoms. On the left side, we have one hydrogen atom in HNO3, and on the right side, we have two hydrogen atoms in H2O. To balance the hydrogen atoms, we need to put a coefficient of 2 in front of HNO3: 2HNO3 + BA(OH)2 -> H2O + BA(NO3)2.

Finally, let's balance the oxygen (O) atoms. On the left side, we have three oxygen atoms in HNO3, and on the right side, we have one oxygen atom in H2O and six oxygen atoms in BA(NO3)2. To balance the oxygen atoms, we need to put a coefficient of 3 in front of H2O: 2HNO3 + BA(OH)2 -> 3H2O + BA(NO3)2.

Therefore, the coefficient of H2O in the balanced equation is 3. So, the correct answer is option D. 3.

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To balance the equation HNO3 + BA(OH)2 -> H2O + BA(NO3)2, we need to ensure that the number of atoms of each element is equal on both sides of the equation.

Looking at the left side, we have one nitrogen atom (N) in HNO3 and one nitrogen atom in BA(NO3)2. So, we don't need to adjust the nitrogen atoms.

Now let's balance the hydrogen (H) atoms. On the left side, we have one hydrogen atom in HNO3, and on the right side, we have two hydrogen atoms in H2O. To balance the hydrogen atoms, we need to put a coefficient of 2 in front of HNO3: 2HNO3 + BA(OH)2 -> H2O + BA(NO3)2.

Finally, let's balance the oxygen (O) atoms. On the left side, we have three oxygen atoms in HNO3, and on the right side, we have one oxygen atom in H2O and six oxygen atoms in BA(NO3)2. To balance the oxygen atoms, we need to put a coefficient of 3 in front of H2O: 2HNO3 + BA(OH)2 -> 3H2O + BA(NO3)2.

Therefore, the coefficient of H2O in the balanced equation is 3. So, the correct answer is option D. 3.

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Answer:

A. 1 = 3 - 2

Explanation:

What defines an expression?

expression - An expression is a sentence with a minimum of two numbers and at least one math operation. This math operation can be addition, subtraction, multiplication, and division.

So if we look at the letter options we can see that A is the best choice.

Answer:

C

Explanation:

Answer:

I am pretty sure the correct answer is a reproductive system

The diastereomer (b) gives the E alkene.

The E and Z isomers are used to characterize the stereo features of carbons that have double bonds connected to them. In the case of the Z isomer, the substituted groups are located on the same side of the double bonds as in the E isomer; however, in the case of the E isomer, the substituted groups are located on the opposite side of the double bonds.

Find out where each of the two groups of higher importance sits in relation to one another. If they are located on the same side, then the molecule in question is a (Z)-alkene. It is an (E)-alkene if the two groups are on different ends of the molecule.

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In general, solids become more soluble as the temperature increases. This is why sugar dissolves better in hot water than in cold water. The table shows three examples of the solubility (g of solute per 100 g water) of substances at different temperatures.

The positions on the N-phenylacetamide ring that could undergo bromination are the ortho, meta, and para positions.

Bromination is an electrophilic aromatic substitution reaction, where a bromine atom is introduced to the aromatic ring. N-phenylacetamide has an amide group attached to the phenyl ring. The amide group is a weakly electron-withdrawing group due to resonance and inductive effects, making it a meta-directing group. However, it is not strong enough to completely prevent bromination at ortho and para positions.

Therefore, N-phenylacetamide can undergo bromination at all three positions, but the meta position is more likely due to the amide group's influence. It is important to note that the presence of a catalyst that can enhance the reactivity of bromine and influence the selectivity of the reaction. The positions on the N-phenylacetamide ring that could undergo bromination are the ortho, meta, and para positions.

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Non-combustible

eg:-glass,water,stone, Portland cement etc ...

Answer:

Noncombustible

Explanation:

So

Some examples are ,glass ,stone

0.99 moles of oxygen are added in a flask .

To calculate the number of moles of oxygen added to the flask, we need to use the ideal gas law equation. The ideal gas law is defined by PV = nRT.

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant and T is the temperature of the gas.

Considering the first scenario where only neon is present in the flask

Pressure \(P_1\) = 1.50 atm

Number of moles \(n_1\) = 3.00 mol

The temperature and volume remain constant during the process. Therefore, we can equate the first scenario with the second scenario to get the number of moles of oxygen added in the flask. So, the equation becomes:

\(P_1\)V = \(n_1\) R \(T_1\)  \(V_2\)

V = (n1 + n2)RT2

Where P2 = 4.50 atm, n1 = 3.00 mol, n2 = Number of moles of oxygen, T1 = T2 (the temperature is constant), R is the gas constant.

\(P_1\) V / T = ( \(n_1\)  +  \(n_2\) )R... (1)

\(P_2\) V / T = ( \(n_1\)  +  \(P_2\) )R... (2)

Dividing equation 1 by equation 2, we get:

( \(P_1\) V / T) / ( \(P_2\) V / T) =  \(n_1\)  +  \(n_2\)  /  \(n_1\) +  \(n_2\)

\(n_2\)  = ( \(P_2\) V / T -  \(P_1\) V / T) / R = (4.50 x V - 1.50 x V) / R = 3.00V / R

For neon, the molecular weight is 20.18 g/mol. Therefore, the mass of neon in the flask is 3.00 x 20.18 g = 60.54 g.

For hydrogen, the molecular weight is 2.02 g/mol. Therefore, the mass of hydrogen added to the flask is 1.00 x 2.02 g = 2.02 g.

The mass of oxygen added to the flask can be calculated by mass balance.

Mass of neon + Mass of hydrogen + Mass of oxygen = Total mass of gas in the flask

60.54 g + 2.02 g + Mass of oxygen = (3.00 + 1.00 + n2) x (2.02 + 32.00 + 20.18) g

Using the above equation, we can calculate the mass of oxygen as follows:

Mass of oxygen = 94.24 - 62.56 g = 31.68 g

Moles of oxygen = 31.68 g / 32.00 g/mol = 0.99 mol

Therefore, 0.99 moles of oxygen are added.

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The sigma bond between C2 and C3 in propylene (CH2CHCH3) is formed by a hybrid orbital of carbon atom and a hybrid orbital of a neighboring carbon atom. The hybridization of carbon atoms is sp2. Hybrid orbitals are formed when atomic orbitals mix to form new orbitals that result from bonding.

This hybridization provides a basis for the building of the σ bonding framework in propylene. In propylene, each carbon atom is connected to two other atoms. The carbon atom in the center of the molecule, C2, is bonded to two other carbon atoms and one hydrogen atom. It has an sp2 hybridization. The sigma bond between C2 and C3 is formed between an sp2 hybrid orbital of C2 and an sp2 hybrid orbital of C3.

The third carbon atom, C1, is also sp2 hybridized, but the shape of the orbitals is different. The orbitals of C1 and C2 have a planar structure, but the orbital shape of C3 is distorted due to the presence of the methyl group on C3. The hybridization of the methyl group's carbon atom is sp3, which results in the formation of a tetrahedral shape around the carbon atom. Therefore, the σ bond between C2 and C3 is formed by the overlap of two sp2 hybrid orbitals.

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The question is not scientific as it measures weight with a unit of mass.

Mass of water filling the flask =268.92 g - 93.667 g = 175.25 g . Molecular weight of the flask = 175.25 g / (1.00 g/cm^3) = 284.4 cm^3.

A given molecule's mass, expressed in daltons, is known as its molecular mass. Because different isotopes of an element are present in different molecules of the same compound, their molecular masses can vary. The mass of a substance per mole is its molecular weight. Typically, grams per mole are used to measure this. Molecular weight, also known as molecular mass, is the mass of a substance's molecules, based on 12 as the carbon-12 atom's atomic weight. In real life, it is calculated by adding the atomic weights of the atoms in the compound's molecular formula. The properties of a polymer are inversely correlated with its molecular weight. Mechanical properties typically increase as the molecular weight does.

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Answer:

Oxygen was discovered independently by two chemists in the late 18th century: Carl Wilhelm Scheele and Joseph Priestley.

Carl Wilhelm Scheele was a Swedish chemist who is credited with the discovery of several elements, including oxygen, chlorine, and molybdenum. He was born on December 9, 1742, in Stralsund, Sweden, and showed an early interest in chemistry. In the 1770s, he made several important discoveries related to oxygen, including the fact that it is a gas and that it is necessary for combustion. However, he did not publish his findings until after Priestley had published his own work on oxygen. Scheele died on May 21, 1786, at the age of 43.

Joseph Priestley was an English scientist, philosopher, and theologian who is best known for his discovery of oxygen. He was born on March 13, 1733, in Birstall, England, and studied theology and science at the University of Leeds. In the 1770s, he conducted a series of experiments in which he isolated and described oxygen. He published his findings in 1774, in a book called "Experiments and Observations on Different Kinds of Air." Priestley's work on oxygen helped to lay the foundations for modern chemistry and the understanding of combustion and respiration. He died on February 6, 1804, at the age of 70.

The form of transportation that accounts for the majority of greenhouse gas (GHG) emissions in Canada is passenger transport, including cars, trucks, and motorcycles.

Specifically, these modes of transportation emit carbon dioxide (\(CO_2\)) and contribute significantly to climate change.Several modes of transportation contribute to greenhouse gas emissions in Canada. However, according to the graph titled "Transportation GHG Emissions by mode, Canada,"

passenger transport such as cars, trucks, and motorcycles account for a significant percentage of total emissions. The data in the chart is presented below:- Passenger transport (Cars, trucks, and motorcycles):

44%- Light trucks (SUVs, vans, and pickups): 10%- Aviation: 9%- Heavy trucks: 8%- Rail: 3%- Electric vehicles: 1%- Transit buses: 1%- Walk/bike: 1%- Light rail transit (LRT): <1%

Therefore, passenger transport, including cars, trucks, and motorcycles, accounts for the majority of GHG emissions in Canada.

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Answer:

In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Showing that Mass cannot be created nor destroyed in a chemical reaction

Explanation:

The acid that is the best choice for preparing a pH = 2.00 buffer is HC2H3O2.

Let's understand this in detail:

A buffer is a chemical solution that can resist changes in pH when an acid or base is added. A pH buffer is a solution containing a weak acid and its conjugate base or a weak base and its conjugate acid.

A pH is a scale that measures the acidity or basicity of a solution. On a scale of 1 to 14, the pH range is from acid to base. Acidic solutions have a pH of less than 7, neutral solutions have a pH of 7, and basic solutions have a pH of more than 7.

An acid is a chemical that has a sour taste and reacts with a base or metal to form salt and water. The acid that is the best choice for preparing a pH = 2.00 buffer is HC2H3O2. This is because the dissociation constant Ka of HC2H3O2 is low, and pH value of 4.76. This means that its pKa value is 4.76. Hence, at pH 2, HC2H3O2 will behave as a weak acid, and its conjugate base will be its conjugate base, C2H3O2–.

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A–]/[HA])

where pKa is the dissociation constant, and [A–] and [HA] are the conjugate base and acid concentrations, respectively.

Answer:

Hydrocarbon combustion refers to the chemical reaction where a hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat. Hydrocarbons are molecules consisting of both hydrogen and carbon. ... Methane combining with 2 oxygen to form carbon dioxide, water and heat.

In a TLC experiment, the compound with the larger Rf value will elute faster. In the case of naphthalene and 1-bromonaphthalene, the 1-bromonaphthalene will elute faster and have a larger Rf value.

This is because 1-bromonaphthalene is more polar than naphthalene. Polar compounds have a stronger attraction to the polar stationary phase (such as the silica gel in TLC plates) and will interact more with it, resulting in a lower Rf value.

Naphthalene, on the other hand, is less polar and will have a weaker interaction with the stationary phase, allowing it to travel further and have a higher Rf value.

The polarity of a compound is determined by the presence of functional groups or atoms that create an uneven distribution of charge or electronegativity. In this case, the bromine atom in 1-bromonaphthalene increases its polarity compared to naphthalene, leading to a stronger interaction with the stationary phase.

In summary, the 1-bromonaphthalene will elute faster in a TLC experiment and have a larger Rf value compared to naphthalene due to its higher polarity resulting from the presence of a bromine atom.

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The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the

Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.

James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.

This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.

Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.

Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.

In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.

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Answer:

the correct answer is air.

Answer:

water

Explanation:

the medium an electromagnetic wave travel the fastest is in water