A hot air balloon is rising at a speed of 10 km/hr. One hour later, the balloon
is still rising at 10 km/hr. What is its acceleration?

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude y at time t is

\(y(t)=50\,\mathrm m-\dfrac12gt^2\)

where g = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when y = 0:

\(0 = 50\,\mathrm m-\dfrac12gt^2\)

\(t^2=\dfrac{100\,\mathrm m}g\)

\(t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}\)

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

B. The force of gravity that acts on the kitten

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The mass of the child is 33.26 kg.

Mass can be defined the quantity of matter a body contained.

The S.I unit of mass is kilogram (kg)

To calculate the mass of the  child, we use the formula below.

Formula:

Where:

Make m the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the mass of the child is 33.26 kg.

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The Sun appears smaller than the Earth from here on Earth, but that is only because the Earth is considerably closer to you than the Sun is. Jupiter due to its rapid revolution, which increases its diameter in the midsection.

Our solar system consists of the star, Sun, planets: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, and small planets such as Pluto.

While the Sun is 150 million kilometers away from where you are, you are on the surface of the Earth.

The planet is an oblate spheroid due to its rapid revolution, which increases its diameter in the midsection.

Therefore, Jupiter due to its rapid revolution increases its diameter in the midsection making it bigger as compared to the world, so it is believed small compared to the Sun and Jupiter.

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Answer:

true. b, c and d

Explanation:

Let's review each statement separately  

a) False. The kinematics studies the position, speed and acceleration of the bodies, but not what causes these changes

b) True. Velocity is the displacement between time, displacement is a vector, and time is a scalar, so the division between them gives a vector

c) True. speed is the displacement that is a length between time, so its unit is length / time

d) true  desaceleration = - aceleration

The net torque on the object is 8 N·m

We can use the equation:

Net torque = (change in angular momentum) / (time interval)

An object's angular momentum is determined by:

L = I * ω

where is the angular velocity and I is the moment of inertia.

So, the change in angular momentum is:

ΔL = I * Δω

where Δω is the change in angular velocity.

Substituting the given values, we get:

ΔL = 2.0 kg·m² * (60 rad/s - 20 rad/s) = 80 N·m·s

The time interval is given as 10 seconds.

So, the net torque is:

Net torque = ΔL / Δt = 80 N·m·s / 10 s = 8 N·m

Therefore, the net torque on the object is 8 N·m.

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Answer:

For eintein's frame of reference, both beam travel at the same speed.

For my own frame of reference, both beams travel at the same speed.

Explanation:

According to special relativity, the speed of light is the same in all direction on all reference frame. If not for this law we will assume the from beam will have a relative speed that will be the speed of light plus the speed of the fright car. This is not so and it violates the speed limit of light which according to the first law is the highest speed possible and nothing can go beyond that.

Answer:

  -0.011176 m/s²

Explanation:

You want the acceleration in m/s² of a train that comes to rest from 30 mi/h after 20 minutes.

The acceleration is the change in velocity divided by the change in time.

  \(-\dfrac{\dfrac{30\text{ mi}}{\text{h}}}{20\text{ min}}=\dfrac{30\text{ mi}}{20\text{ h$\cdot$min}}\times\dfrac{1609.344\text{ m}}{1\text{ mi}}\times\dfrac{1\text{ h}}{60\text{ min}}\times\left(\dfrac{1\text{ min}}{60\text{ s}}\right)^2\\\\=-\dfrac{30\cdot1609.344\text{ m}}{20\cdot60^3\text{ s}^2}=\boxed{-0.011176\text{ m/s}^2}\)

equal in magnitude but opposite in direction

We have that the values for F north, F east, F up are

From the Question we are told that

electric force \(F_1 = 1.2 x 10^{-3} N(N)\)

electric force , \(F_2=5.7 x 10^{-4} N(E)\)

electric force , \(F_3=2.2 x 10^{-4} N (U)\)

charge on this ball one \(q_1= 110 nC.\)

charge on this ball two \(q_2= -50 nC.\)

Generally the equation for the F north  is mathematically given as

\(F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}\)

\(F_N=1.09090909*10^{-5}\)

For F East

\(F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}\)

\(F_E=5.18181818*10^{-6}\)

For F UP

\(F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}\)

\(F_E=2*10^{-6}\)

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Answer:

those are all correct. The arrows are matched correctly

Earthquakes are the vibrations inside the earth and they are seismic waves.

They differ from sound waves in terms of frequency.

Earthquakes cause destruction to building as they originate inside the earth and these waves produce vibrations to the lower part of the building first, which causes an imbalance in the building and the building collapses.

The potential energy stored inside the rocks provides energy to the seismic waves produced due to earthquakes.

Due to this huge potential energy large ocean waves are formed.

According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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The mass of MnO₂ required by 4 g of NaCl in the chemical reaction is 1.487 g.

The balanced chemical reaction of NaCl, MnO₂ and H₂SO₄ is given as follows;

4NaCl + MnO₂ + 4H₂SO₄ → MnCl₂ +  4NaHSO₄ + Cl₂ + 2H₂O

From the chemical equation given above, we can calculate the mass of 4NaCl  and MnO₂  as follows;

where;

4NaCl = 4 ( 23 + 35.5 ) = 234 g

MnO₂  = ( 55 + 32 ) = 87 g

The mass of MnO₂ required by 4 g of NaCl in the chemical reaction is calculated as;

4NaCl + MnO₂ + 4H₂SO₄ → MnCl₂ +  4NaHSO₄ + Cl₂ + 2H₂O

in this equation, 234 g of NaCl ---------> 87 g of MnO₂

                           4 g of NaCl -------------> ? MnO₂

= ( 4 x 87 ) / ( 234 )

= 1.487 g

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The things that should be held constant are the amount of water given to the plant each day, the length of time each plant is exposed to light and the temperature where the plants are stored.

Using a pH scale, acids and bases can be determined. The scale has a 0 to 14 range. In order to detect whether a chemical is an acid or a basic, Litmus paper is employed as an indication. The color of the paper, which corresponds to the numbers on the pH scale, indicates the type of chemical being tested. For instance, vinegar, which has a pH of 2.4, is an acid.

Now, according to the question,

The concentration of carbon dioxide in water affect the pH of the plant, so it depends on that how much water is given to the plant. The temperature also affect the pH of the plant  so, the length of time each plant is exposed to light and the temperature where the plants are stored will also affect the pH on plant growth that's why these things should be held constant.

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Answer: DADDY

Explanation:

Answer:

Potential energy of the ball would increase

Explanation:

The formula for potential energy of an object is:

Potential Energy (object) = mass x gravity x height

In your question, the value for height is increased when the object (ball) is placed in a higher position. This creates a net positive change in the right-hand side of the formula and since the value of mass and gravity doesn't change because gravity is a constant (meaning it's always 9.8N/kg) and the mass is said to be kept the same, the ball's potential energy would increase.

Answer:

Therefore the friction Force is 65 N.

Explanation:

Look at the image above.

The frictional force of the rubber block is 63.7N.

Friction is defined as a force that opposes the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are many types of friction such as dry friction which is defined as the force that opposes the relative lateral motion of two solid surfaces in contact.

This friction force is directed in the opposite direction to the motion of the object itself because the friction described so far between surfaces in relative motion is called kinetic friction.

For above given information,

mass of the block, m =10kg

coefficient of friction, µ=0.65

f=coefficient of the friction ×normal= µ*R

R= normal =mg = 9.8×10=98N

So, f =0.65×98=63.70N

≈65N(when g is taken as 10m/s²)

Thus, the frictional force of the rubber block is 63.7N.

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Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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Answer:

The width is  \(Z = 0.0424 \ m\)

Explanation:

From the question we are told that

    The width of the slit is \(d = 77.7 \mu m = 77.7 *10^{-6} \ m\)

    The wavelength of the light is  \(\lambda = 721 \ nm\)

      The position of the screen is  \(D = 2.83 \ m\)

Generally angle at which the first minimum  of the interference pattern the  light occurs  is mathematically  represented as

        \(\theta = sin ^{-1}[\frac{m \lambda}{d} ]\)

Where m which is the order of the interference is 1

substituting values

       \(\theta = sin ^{-1}[\frac{1 *721*10^{-9}}{ 77.7*10^{-6}} ]\)

      \(\theta = 0.5317 ^o\)

 Now the width of first minimum  of the interference pattern is mathematically evaluated as

       \(Y = D sin \theta\)

substituting values

       \(Y = 2.283 * sin (0.5317)\)

       \(Y = 0.02 12 \ m\)

 Now the width of  the  pattern's central maximum is mathematically evaluated as

        \(Z = 2 * Y\)

substituting values

      \(Z = 2 * 0.0212\)

     \(Z = 0.0424 \ m\)

Answer:

Impulse = \(206.28 * 10 = 2062.8\) g.m/s

Explanation:

Impulse is equal to the product of force and time

Here

Density of car =  \(0.54\)  g/mL

Volume of car \(= 38.2\) mL

Mass of the car is equal to the product of density and volume of car

Mass of the car \(= 0.54 * 38.2\) \(= 20.628\) grams

Acceleration of the car is \(10\) m/s^2

Force is equal to product of mass and acceleration

F = \(20.628 * 10 = 206.28\) g .m/s^2

Impulse = F * t

Impulse = \(206.28 * 10 = 2062.8\) g.m/s

Answer:

It should be C

Explanation:

It depends on the mass of each ball

Remember the formula for momentum, mass X velocity

Momentum depends on the mass of the object

The momentum of the billiard balls after the collision is 3 Kgm/s.

Given the following data:

To find the momentum of the balls after the collision:

Momentum is simply a multiplication (product) of the mass of an object with its velocity.  Also, momentum is a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

\(Momentum = Mass\) × \(Velocity\)

\(Total \; momentum = Momentum \; B + Momentum \;of \;the \;other\; balls.\)

Since the other billiard balls were at rest (not experience any motion), there velocities would be zero (0) m/s.

Substituting the values, we have:

\(Total \; Momentum = 3 + 0\)

Total momentum = 3 Kgm/s.

Therefore, the momentum of the billiard balls after the collision is 3 Kgm/s.

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Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms