Answer:
The magnetic field is \(B = 3 mT\)
Explanation:
From the question we are told that
The inner radius is \(r_i = 1.00 mm =1*10^{-3} \ m\)
The outer radius is \(r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m\)
The distance from the axis of the conductor is \(d =2.0 \ mm = 2.0 *10^{-3} \ m\)
The current carried by the conductor is \(I = 80 A\)
According to Ampere's circuital law , the magnetic field at a point that is \(r_3\) from the axis of the conductor
\(B = \frac{\mu_oI}{2 \pi d } [\frac{d - r_1}{r_2 -r_1} ]\)
Where \(\mu_o\) is the permeability of free space with a value of \(\mu_o = 4 \pi *10^{-7} N/A^2\)
substituting values
\(B = \frac{(4 \pi *10^{-7})(80)}{2 * 3.142 * 2 *10^{=3} } [\frac{(2^2 - 1 ^2 )*10^{-3}}{(3^2 - 1^2) *10^{-3}} ]\)
\(B = 3 mT\)
A car traveling initially at 5.47 m/s accelerates at the rate of 1.65 m/s/s
for a time of 9.06 s. What is its velocity at the end of the acceleration?
At the end of the acceleration, its speed is 81.77 m/s.
A description of an object's speed and direction of motion is comparable to the term "speed." Meter per second (m/s) is the metric measurement of speed. Centimeters per second (cm/s) can also be used to describe the velocity magnitude.
What is an example of velocity?The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car traveling north on a highway or a rocket taking flight.
Calculation:V = u + at
V = 5.47 + 1.65 × 9.06 s
V = 81.77m/s
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EXPLAIN CONSERVATION OF MOMEMTUM WITH THE HELP OF COLLISION OF TWO OBJECT.
i hate this question.
Conservation of momentum - is when the total momentum before and after collision is equal.
Here is the formula darling,
p = p
mv = mv
See the pic for example. HmpH
Costal residents must do many things to prepare for hurricanes
What's the kinetic energy of the roller coaster at the top and bottom of the hill? Use KE
mu
A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it's moving at a speed of 3 meters/second. After reaching the bottom
of the hill, its speed doubles. The car's kinetic energy at the bottom is
v its kinetic energy at the top. The car has
joules of kinetic energy at the bottom of the hill.
Reset
Next
The kinetic energy of the car is four times greater at the bottom than it is at the top. At the base of the hill, the car's kinetic energy is 1800 joules.
Describe kinetic energy.The momentum an object has as a result of motion is known as kinetic energy. We must exert force on an object if we desire to accelerate it. To apply a force, we must exert effort. Once the work is finished, the objects will be moving because energy has now been transferred to it.
What elements influence the kinetic energy?Describe that a travelling internal force and speed are major factors that impact the amount of kinetic energy it will possess. Partially particles can result in the loss of kinetic energy through frictional, sound, and heat.
k = 1 /2 mv²
K = 1 /2 (100 kg) (3 m/s)²
= 450 J
K = 1 /2 (100 kg) (6 m/s)²
k = 1800 J
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What does ceteris paribus mean?
A. other things remain unequal
B. other things remain constant
C. other things remain irregular
D. other things remain unbalanced
Answer:
other things remain constant
Explanation:
Answer:
B) Other things remain constant.
Explanation:
For edmentum users.
A person has a choice of either pushing or pulling a book of ice with a mass of 50kg at a constant velocity. Assuming a coefficient of friction on 0.2 and pushing or pulling at the angle depicted, calculate the applied force needed for situations (a) and (b).
The applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.
How to determine the applied forceWe have that the force for situation 'a' is on an angle of inclination of 25° with the book of ice.
Thus,
Applied force = mg × sine of angle of inclination
Where mass, m = 50kg
g = acceleration due to gravity = 10m/s^2
Applied force = 50 × 10 × sin 25
Applied force = 50 × 10 × 0. 4226
Applied force = 211. 31 Newton
For situation 'b', the mass of block is adjacent to the book of ice, thus
Applied force = mg × cos of angle of inclination
Applied force = 50 × 10 × cos 25
Applied force = 50 × 10 × 0. 9063
Applied force = 453. 15 Newton
Thus, the applied force needed for situation a and b are 211. 31 Newton and 453. 15 Newton respectively.
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The Witness Experimenter configure options include a Skip field. What does the skip value do? a. Increases the simulation run speed b. Resets the statistics for the warm up period c. Sets the length of the warm up period d. Misses out a different number of random numbers for each replication e. Changes the random number streams for each replication
The Witness Experimenter configure options include a Skip field that misses out on a different number of random numbers for each replication (Option D).
What are the Experimenter configure options?Experimenter configure options are some basic settings of a Witness experiment. These settings influence how the experiment would behave and what output is produced. With the help of configure options, you can set the value of random number streams and skip replication.
The skip value misses out on a different number of random numbers for each replication. As a result, this provides some level of control over the replication. By changing the value of the skip, you can control which random numbers should be missed and which should not be missed. In addition, by using the skip field, you can increase the simulation run speed. As a result, you get better output in less time.
Thus, the correct option is D.
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Juanita studies several free-body diagrams in which a normal force is shown. What is always true about a normal force in a free-body diagram?
Answer: B
Explanation: it is perpendicular to a surface
Answer:
it is perpendicular to a surface
Explanation:
A rectangular loop of wire with a cross-sectional area of 2.936 m2 carries a current of 6.488 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 1.108 T. The plane of the loop is initially at an angle of 59.914o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?
ANSWER:
10.58 Nm
STEP-BY-STEP EXPLANATION:
Given:
Area (A) = 2.936 m²
Current (i) = 6.488 A
Magnetic field (B) = 1.108 T
Angle (θ)= 59.914°
To calculate the torque we must resort to the following formula:
\(\begin{gathered} \tau=MB\sin\alpha \\ \\ \alpha=90\degree-\theta=90-59.914\degree \\ \\ \alpha=30.086\degree \end{gathered}\)We need to know the magnetic moment, as follows:
\(\begin{gathered} M=NIA \\ \\ M=1\cdot6.488\cdot2.936 \\ \\ M=19.05\text{ A}\cdot m^2 \end{gathered}\)In this way we can calculate the torque:
\(\begin{gathered} \tau=19.05\cdot1.108\cdot\sin(30.086\degree) \\ \\ \tau=10.58\text{ Nm} \end{gathered}\)Therefore, the magnitude of the torque on the loop is 10.58 Nm
A box is lifted to a height of 6 meters in 3 seconds. If the lift required 400 watts of power, what was the weight of the box?200 N250 N300 N350 N
Given:
The height through which the box was lifted, h=6 m
The time it took to lift the box, t=3 s
The power dissipated in lifting the box, P=400 W
To find:
The weight of the box.
Explanation:
The power is described as the time rate of transfer of energy.
Thus the power is given by,
\(P=\frac{W}{t}\)Where W is the work done in lifting the box.
The work done is given by,
\(W=F\times h\)Where F is the weight of the box.
Thus the power dissipated in lifting the box is given by,
\(P=\frac{Fh}{t}\)On substituting the known values,
\(\begin{gathered} 400=\frac{F\times6}{3} \\ \Rightarrow F=\frac{400\times3}{6} \\ =200\text{ N} \end{gathered}\)Final answer:
The weight of the box is 200 N
Thus the correct answer is option A.
6) Magnetic flux density is per unit area
A) magnetic filed times
b) magnetic lines
C) electric field
D)NONE
Answer:
c electric field is the answer
For the waveform of quality of sound _______ is taken vertically.
(a).Length
(b).Mass
(c). Pressure
(d). Velocity
Which electrode is the anode and what is the cell potential in a standard lead-cobalt cell? a)The anode is the lead electrode and the cell potential is +0.15 V. b)The anode is the lead electrode and the cell potential is +0.39 V. c)The anode is the cobalt electrode and the cell potential is +0.15 V. d)The anode is the cobalt electrode and the cell potential is +0.39 V.
The correct answer is d) The anode is the cobalt electrode and the cell potential is +0.39 V. In a standard lead-cobalt cell, the anode is the cobalt electrode and the cell potential is +0.39 V.
This is because the cobalt electrode has a higher reduction potential than the lead electrode, meaning that electrons will flow from the cobalt to the lead electrode. The cell potential is the difference in the reduction potentials of the two electrodes, and since the cobalt electrode has a higher reduction potential, the cell potential is positive. The cell potential is measured in volts, and in this case it is +0.39 V.
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A spring of k=500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
c. Determine the speed
e. What would the speed at the top of the hill be with 2m of initial compression if 15% of the energy is
dissipated through friction?
d. What is the minimum compression of the spring necessary to get to the top of the hill? (v=0 at top, no
friction)
Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
What is energy?The capacity or power to do work, such as the capacity to move an object by application of force is called energy.
Initial potential energy of compressed spring is:
Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J
k is spring constant, x is compression of the spring, and J is unit of energy in joules.
Final potential energy of the bricks is:
Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = Ep
1/2 kx^2 = mgh
v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s
Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.
c. Initial potential energy of compressed spring is: 1000 J
Ek = Ep = 1000 J
Kinetic energy of the bricks is given by:
Ek = 1/2 mv^2
1000 J = 1/2 * 100 N * v^2
v = sqrt(200 / 1) = 14.14 m/s
Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.
d. As, Ep = m g h
where m is mass of the bricks, g is acceleration due to gravity, and h is height of the hill.
Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = 1/2 kx^2 = 1962 J
1/2 * 500 N/m * x^2 = 1962 J
x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m
Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.
e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,
0.85 * 1000 J = 1/2 mv^2
v = sqrt(170 / 1) = 13.04 m/s
Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
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The noble gas neon is used for filling neon signs. Like other noble elements, it has a full octet (complete outer energy level) of electrons, which makes the gas A. freeze at room temperature. B. react with other gases in the air. C. unlikely to combine with other elements. D. solidify at standard pressure and temperature, chiny pray-colored solid at room
Answer:
C. unlikely to combine with other elements.
Explanation:
In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.
Noble gases are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.
Hence, the full octet makes the gas (neon) unlikely to combine with other elements.
What do you ocean waves and sound waves have in common?
Answer:
They are both mechanical waves
How can a standing wave be formed with the help of a tuning fork and a closed-end tube of appropriate lengt
At this point, the frequency of the tuning fork and the fundamental frequency of the standing wave in the tube match.
A standing wave can be formed with the help of a tuning fork and a closed-end tube of appropriate length by following the steps given below:
Step 1: Take a closed-end tube of suitable length and place the tuning fork over its mouth. The fork should not touch the mouth of the tube.
Step 2: Strike the tuning fork to set it in vibration.
Step 3: Bring the fork over the mouth of the tube and adjust the length of the tube by pushing it in or pulling it out until a loud sound is heard.
Step 4: This loud sound is caused by the formation of a standing wave in the tube. At this point, the frequency of the tuning fork and the fundamental frequency of the standing wave in the tube match.
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the seasons on earth are caused by its elliptical orbit around the sun.
t
f
False.The seasons on earth are Not caused by its elliptical orbit around the sun.
The seasons on Earth are not caused by its elliptical orbit around the Sun. The seasons are primarily caused by the tilt of Earth's axis relative to its orbit around the Sun. Earth's axis is tilted at an angle of approximately 23.5 degrees, and as Earth orbits the Sun, different parts of the planet receive varying amounts of sunlight throughout the year.
During summer in a particular hemisphere, that hemisphere is tilted towards the Sun, resulting in longer days, more direct sunlight, and warmer temperatures. In contrast, during winter, that hemisphere is tilted away from the Sun, leading to shorter days, less direct sunlight, and cooler temperatures. The equinoxes, which occur in spring and autumn, are the times when the tilt of Earth's axis is neither towards nor away from the Sun, resulting in roughly equal lengths of day and night.
While Earth's elliptical orbit does contribute to slight variations in the intensity of sunlight received throughout the year, it is the axial tilt that is the primary cause of the seasons.
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Predicting low-latitude scintillation is a difficult problem
that has been researched for several decades. Give a reason why it
is difficult to predict scintillation and suggest how it could be
addres
Predicting low-latitude scintillation is difficult due to its complex nature, influenced by a combination of factors such as ionospheric irregularities, solar activity, and geomagnetic disturbances.
Low-latitude scintillation refers to the rapid fluctuations in the amplitude and phase of radio signals passing through the Earth's ionosphere in regions closer to the equator. It is challenging to predict scintillation accurately because it involves a complex interplay of various factors.
One of the main reasons for the difficulty is the presence of ionospheric irregularities. These irregularities are caused by the interaction between the solar wind and the Earth's magnetosphere, leading to the formation of plasma density structures in the ionosphere. These structures can cause signal distortions and scintillation. However, these irregularities are highly dynamic and difficult to model accurately, making it challenging to predict their occurrence and characteristics.
To address the difficulty of predicting low-latitude scintillation, a multi-disciplinary approach is required. This involves combining data from various sources such as ground-based and satellite observations, ionospheric modeling, and space weather monitoring. By improving our understanding of ionospheric physics, developing advanced modeling techniques, and integrating real-time observations, scientists can work towards improving the prediction of low-latitude scintillation events.
In summary, predicting low-latitude scintillation is challenging due to the complex nature of ionospheric irregularities and the influence of solar activity and geomagnetic disturbances. Addressing this challenge requires a multi-disciplinary approach and advancements in observational techniques and modeling methods.
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What waves are transverse waves that disturb electromagnetic fields?
Radio waves are transverse waves that disturb electromagnetic fields.
What is electromagnetic fields?Electromagnetic field, a feature of space brought on by the movement of an electric charge. Only an electric field will be generated by a stationary charge in the surrounding area. A magnetic field is also created if the charge is in motion.
A changing magnetic field can also create an electric field. An electromagnetic field is created by the mutual interaction of electric and magnetic fields. This field is thought to exist independently of any charges or currents (a stream of moving charges) to which it may be related. It is possible to think of this electromagnetic field in some situations as an electromagnetic energy-transporting wave.
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For the following, determine the final volume in ml (V2) of a gas when it is heated to 373K (T2) when it's starting temperature was 273K (T1) and its starting volume was 100 ml (V1)?
136.63 ml
136.63 K
73.19 ml
73.19 K
For the previous question, how are volume and temperature related?
temperature and volume are not related
temperature and volume are inversely proportional
temperature and volume are directly proportional
only pressure and volume are related
Answer:
136.63 ml
Explanation:
Two forces oppose each other while a star is stable. The first is gravity pulling inward. What is the
other force?
Answer:
the radiation pressure that has to push the star
Explanation:
In the stars there are two forces that act in the opposite direction.
- On the one hand there is the force of gravity that the star has to collapse
- On the other is the radiation pressure that has to push the star. This pressure comes from the radiation and velocity of the particles involved in nuclear reactions.
In materials such as metals, the outer shell electrons are loosely bound to the nuclei of their atoms and are free to move from one atom to another. These materials are good conductors. Is this true or false?
In materials such as metals the outer most electrons are loosely bound and therefore their movement is chaotic, this allows for the transportation of energy in form of electricity therefore, this materials are good conductors. The statement is true.
A wire is wrapped around in a circular loop with a radius of 10 centimeters 25 times, what is the magnetic moment of the wire when there are 4 amps of current running through the wire?
The magnetic moment of a current loop can be defined as the product of the current and the area of the loop. In this case, we have a wire wrapped in a circular loop with a radius of 10 centimeters 25 times, carrying a current of 4 amps.
Therefore, the area of the loop can be calculated as follows:Area of a single loop = πr²= π(10 cm)²= 100π cm²Area of 25 loops = 25(100π) cm²= 2500π cm²The magnetic moment of the wire can then be calculated as the product of the current and the area of the loop:Magnetic moment = current × area= 4 amps × 2500π cm²= 10000π A cm²This means that the magnetic moment of the wire is 10000π A cm² when there are 4 amps of current running through it.
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825 kg car outputs 36,181 watts, going at 13 m/s. going up a 2.85 meter hill, how long does the acceleration take
It takes approximately 20.09 seconds for the car to accelerate up the 2.85 meter hill.
potential energy =\(m * g * h\)
where m = 825 kg (mass of the car), g = 9.81 m/s^2 (acceleration due to gravity), and h = 2.85 m (height of the hill)
potential energy = 825 kg * 9.81 m/s^2 * 2.85 m
potential energy = 22,571 J
work = kinetic energy + potential energy
where kinetic energy = 1/2 * m * v^2
and v = 13 m/s (velocity of the car)
kinetic energy = 1/2 * 825 kg * (13 m/s)^2
kinetic energy = 703,612 J
work = 703,612 J + 22,571 J
work = 726,183 J
power = work / time
where power = 36,181 watts (output power of the car's engine)
time = work / power
time = 726,183 J / 36,181 W
time = 20.09 seconds
Acceleration can be caused by various forces, such as gravity, friction, or a pushing or pulling force. For example, when a car accelerates, the engine produces a force that propels the car forward, increasing its speed. When a skydiver jumps out of a plane, gravity causes the diver to accelerate towards the ground.
In addition to its use in physics, the term "accelerate" is also used in a broader sense to describe the process of speeding up or increasing the pace of something. For example, a company may accelerate its production schedule to meet a deadline, or an athlete may accelerate their training to improve their performance. In these contexts, acceleration refers to an increase in the rate or intensity of a process, rather than a change in velocity.
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the speed of a wave depends on the ________.
a. crest
b.pitch
c.medium
d.amplitude
Answer:
C. Medium
Explanation:
The speed of the wave depends on the medium in which it is traveling. ... The wavelength of a wave does not affect the speed at which the wave travels. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.
Hope it helps!
A boat sailed 560 km in 8 hrs. It took three hours to travel the first 150 km. What was it’s average speed for the remaining journey?
Answer:
82 km/h
Explanation:
Given that A boat sailed 560 km in 8 hrs. It took three hours to travel the first 150 km. That is,
The remaining distance will be:
560 - 150 = 410 km
the remaining time will be:
8 - 3 = 5 hours
For the remaining Journey, average speed will be:
Speed = distance/time
Speed = 410/5
Speed = 82 km/h
Therefore, the average speed for the remaining journey will be 82 km/h
calculate the force of gravity between earth and the moon
The force of gravity between the Earth and the Moon is approximately 1.982 x 10²⁰ Newtons.
The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is:
F = (G x m1 x m2) / r²
Where:
F is the force of gravity,
G is the gravitational constant (approximately 6.674 x 10⁻¹¹ Nm²/kg²),
m1 and m2 are the masses of the two objects,
r is the distance between the centers of the two objects.
For the case of the Earth and the Moon, the mass of the Earth is approximately 5.972 x 10²⁴ kg, the mass of the Moon is approximately 7.348 x 10²² kg, and the average distance between them is approximately 384,400 km (or 3.844 x 10⁸ meters).
Substituting these values into the formula:
F = (6.674 x 10⁻¹¹ Nm²/kg² x 5.972 x 10²⁴ kg x 7.348 x 10²² kg) / (3.844 x 10⁸ meters)²
Simplifying the calculation yields:
F ≈ 1.982 x 10²⁰ N
Therefore, the force of gravity between the Earth and the Moon is approximately 1.982 x 10²⁰ Newtons.
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How wood helps in home insulating?
Please answer fast
Answer:
Wood helps in home insulating because logs have both a proper structure and insulation. Since the log has so much heat storage, its huge mass will have a lot more thermal energy than other materials for insulating.
A 54\,\text {kg}54kg54, start text, k, g, end text pig runs at a speed of 1.0\, \dfrac{\text m}{\text s}1.0 s m 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
Answer:
Following are the solution to this question:
Explanation:
In this question, some of the information is missing that's why its solution can be defined as follows:
\(v= 0\\\\u= 1.0 \frac{m}{s} \\\\s= 1\\\\m= 54 \ kg\\\)
Using formula:
\(\to v^2-u^2=2\cdot a\cdot s \\\\\to 0^2 - 1.0^2= 2 \cdot a \cdot 1\\\\\to - 1=2a\\\\\to a= -\frac{1}{2} \ \frac{m}{s^2}\\\\ \to \bold{F= m\cdot a}\\\\\)
\(=54 \times - \frac{1}{2}\\\\= -27\ N\)