The work done in pulling the rope up 20 ft is 2598 J.
To calculate the work done in pulling the rope up 20 ft, we need to determine the change in potential energy of the rope.
The potential energy of an object near the surface of the earth is given by the equation: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above some reference level.
In this problem, the rope has a length of 30 ft and a weight of 15 lbs, which is equivalent to a mass of 15/32 slugs (since 1 slug is the mass that accelerates at 1 ft/s^2 when a force of 1 lb is applied). Therefore, the initial potential energy of the rope when it is hanging over the edge of the building is:
PE_initial = (15/32) * 30 * 32.2 * 100 = 14475 J
where we have converted the units of mass and acceleration to the SI system (kg and m/s^2) and used 1 ft = 0.3048 m.
When the rope is pulled up 20 ft, its height above the reference level changes by 20 ft. Therefore, its final potential energy is:
PE_final = (15/32) * 30 * 32.2 * (100 + 20) = 17073 J
The work done in pulling the rope up 20 ft is equal to the change in potential energy:
W = PE_final - PE_initial = 17073 J - 14475 J = 2598 J
Therefore, the work done in pulling the rope up 20 ft is 2598 J.
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You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N
Answer:
85.2 N
Explanation:
You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.
WeightYour weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...
W = k(M/r²) = 710 N
W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N
Your weight would be 82.5 N.
hermodynamic properties and theoretical rocket performance of hydrogen to 100000 k and 1.01325x10^8 n/m^2
At extremely high temperatures of 100,000 K and a pressure of \(1.01325x10^8 N/m^2\), hydrogen exhibits unique thermodynamic properties and theoretical rocket performance.
When hydrogen is subjected to such extreme conditions, its thermodynamic properties undergo significant changes. At 100,000 K, hydrogen is in a highly excited state, with its molecules dissociating into individual atoms. The high temperature leads to increased kinetic energy and molecular collisions, resulting in a highly energetic and reactive gas.
Regarding theoretical rocket performance, hydrogen is often used as a propellant in rocket engines due to its high specific impulse and efficient combustion properties. At 100,000 K and a pressure of \(1.01325x10^8 N/m^2,\) the high temperature and pressure conditions allow for rapid expansion and exhaust velocity in a rocket nozzle, resulting in a higher thrust generation.
It is important to note that these extreme conditions are far beyond what can be practically achieved in real-world scenarios. The values mentioned represent theoretical limits for understanding the behavior of hydrogen under such extreme circumstances. In practical rocket applications, hydrogen is typically used at lower temperatures and pressures, offering still impressive performance characteristics.
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Rosa pours a cup of boiling water into a pot of room temperature water. According to the second law of
thermodynamics, what will occur?
O Thermal energy from the room temperature water will continuously flow to the boiling water.
O Thermal energy from the room temperature water will flow to the boiling water until all of the water in the pot is at
a single temperature.
Thermal energy from the boiling water will continuously flow to the room temperature water.
Thermal energy from the boiling water will flow to the room temperature water until all of the water in the pot is at
a single temperature.
Answer: D. Thermal energy from the boiling water will flow to the room-temperature water until all of the water in the pot is at a single temperature.
Explanation:
This is because thermal energy moves from warmer objects to cooler objects, until they are at the same level of thermal energy or temperature.
Answer:
Answer is D
Explanation:
Edge 2020
a strong lightning bolt transfers about 25 C to earth. how many electrons are transferred?
Answer:
\(n = 1.563x {10}^{20} \)
The center of ?
is the point at which the entire
weight of a body may be considered to be concentrated.
Answer:
Gravity
Explanation:
Thats the answer bucko. Gives the brainliest or I die
Select the correct answer. when do sea breezes occur? a. daytime b. nighttime
c. both day and night d. at thermal equilibrium
The sea breezes occur during the day when land surfaces heats up faster than water surfaces.
The cooler air above the water is moving across the surface of the land to replace the rising heated air as it rises over the land is called sea breezes.
Sea breezes mostly occur during hot days i.e., summer time as there is unequal heating of land and water surfaces. The land surface get heat up first and during the day the land get heat up faster than water surfaces due to which there is high temperature and low pressure.
The winds always blows from the high pressure to low pressure or low temperature to high temperature i.e., from water to land surfaces durning day time and in night time it happens opposite the wind flows from land surfaces to water surfaces
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The sea breeze occurs during the daytime as the land masses heat up faster than water.
The breeze blowing towards the land from the sea is known as sea breeze.
Due to the differences in pressure, the air flows from high pressure areas over the sea to the low pressure areas on the land. In summer there is unequal heating of land and water masses. This results in the formation of sea breeze.
The winds always blows from the high pressure to low pressure or low temperature to high temperature i.e., from water to land surfaces durning day time and in night time it happens opposite the wind flows from land surfaces to water surfaces.
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A radioactive chemical has a decay rate of approximately 5% per year. Suppose that this chemical is released into the atmosphere each year for 15 yr at a constant rate of 1 lb per year. How much of this chemical will remain in the atmosphere after 15 yr? The amount of chemical remaining in the atmosphere is lbs.
After 15 years, approximately 0.319 lb (or 0.319 pounds) of the radioactive chemical will remain in the atmosphere.
The decay rate of the chemical is approximately 5% per year, which means that each year, 95% of the chemical will remain after decay. This can be expressed as a decay factor of 0.95.
Since the chemical is released into the atmosphere at a constant rate of 1 lb per year for 15 years, we can calculate the amount remaining using the formula:
Remaining amount = Initial amount * Decay factor^Number of years
In this case, the initial amount is 1 lb, the decay factor is 0.95, and the number of years is 15. Plugging these values into the formula, we get:
Remaining amount = 1 lb * (0.95)^15
Calculating this expression, we find:
Remaining amount ≈ 0.319 lb
After 15 years, approximately 0.319 lb of the radioactive chemical will remain in the atmosphere. The decay rate of 5% per year gradually reduces the amount of chemical present, resulting in a relatively small fraction remaining after 15 years.
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William Herschel thought he had found a comet when he spotted the green disk of: Neptune. Oberon. Uranus. Titania. Triton.
William Herschel thought he had found a comet when he spotted the green disk of Uranus.
Uranus is the seventh planet located far away from the Sun. It is a gaseous planet which was discovered in 1781, mistaken by a comet but after two years it was accepted as a planet. After decades of observations and only one close visit by a spacecraft, which shows us that Uranus has unique atmosphere.
Atmosphere of Uranus is mostly made up of hydrogen and helium as well as a small amount of methane and traces of water and ammonia. The presence of methane gas gives blue colour to Uranus so we can conclude that Uranus is the planet which was thought first a comet by William Herschel.
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the motion(s) that occur at the radioulnar joint?
The radioulnar joint is a synovial joint located at the elbow that connects the radius and the ulna, enabling rotational motion.
The radioulnar joint allows for pronation and supination. Pronation refers to the motion of rotating the forearm so that the palm faces downwards, while supination refers to the motion of rotating the forearm so that the palm faces upwards. The radioulnar joint allows the radius and ulna to move relative to each other, resulting in rotational motion.
When the forearm is pronated, the radius rotates over the ulna and crosses it, while the ulna remains stationary. When the forearm is supinated, the radius rotates back to its original position, and the two bones are parallel to each other.The radioulnar joint is important in many activities, including writing, typing, playing musical instruments, and sports like tennis and golf. Any damage to this joint can result in a loss of pronation and supination, making daily activities challenging.
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is a solar energy technology that uses unique properties of semiconductors to turn light into electricity
Solar energy technology utilizes the unique properties of semiconductors to convert sunlight into electricity. This process is called photovoltaic (PV) effect, where semiconductors, such as silicon, absorb photons from sunlight and release electrons.
These electrons are captured by an electric field, creating a flow of electricity. PV cells are grouped together to form solar panels, which can be installed on rooftops or large solar farms.
Solar energy is a clean, renewable, and sustainable source of power, reducing greenhouse gas emissions and reliance on fossil fuels.
Moreover, advancements in semiconductor materials and manufacturing techniques have improved the efficiency and affordability of solar technology, making it more accessible for a wide range of applications.
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What are the three properties about gravitational force ?
what causes the boat in (figure 1) to move forward? what causes the boat in to move forward? the motion of the water itself. the force the man exerts on the paddle. the force the water exerts on the paddle. the force the paddle exerts on the water.
The man exerts a force on the paddle to move the paddle, and he is not pushing the water directly.
The boat moves forward when the paddle exerts a force on the water, and the water exerts the same amount of reaction force on the paddle.
Due to the reaction force on the paddle by the water, the boat moves forward.
The boatman applies a force pushing the water backward (the action).
The water exerts an equal force along the pole in the opposite direction (this is the reaction).The horizontal component of this reaction is a force that makes the boat move forward into the water.
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--Incomplete Question, The complete Question is- what causes the boat in (figure 1) to move forward? what causes the boat in to move forward? the motion of the water itself. the force the man exerts on the paddle. the force the water exerts on the paddle. the force the paddle exerts on the water.--
A penguin swimming underwater goes 20 meters in 5 seconds. What is its average speed?
Answer:
4 meters per second
Explanation:
The length of a simple pendulum is reduced to half. What will be its new time period?
Explanation:
Period of a pendulum is 2pi sqrt (l/g) now reduce l to 1/2 l
period = 2pi sqrt ( 1/2l / g) = 2 pi * .707 sqrt ( l/g) <===== this is .707 the original
the time period is less by a factor of sqrt (1/2) = .707
g a 50 kg mass is resting on a plane that is inclined at 15 degrees above the horizontal. a 250 n forces is applied to the mass, up the inclined plane, but the mass does not move. determine the coefficient of static friction between he mass and the plane.
The coefficient of static friction between the mass and the plane is 0.52.
Then coefficient of static friction is the value that must be overcomed when two surfaces are in contact. This value depends on the nature of the surfaces in contact.
In the given question, since the two surfaces are rough, frictional force will act in opposite direction of the motion.
Given that;
F = μR
where F is the force applied to the mass and R is its reaction.
F = 250 N
R = mgCos θ
= 50 x 10 Cos 15
= 483 N
So that;
μ = F/R
= 250/483
μ = 0.52
The coefficient of static friction between the mass and the plane is 0.52.
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how does earths magnetic field compare to other planets?
No, magnetic fields do not exist on every planet. The magnetic fields of the four gas giants are extremely strong, while those of the Earth and Mercury are fairly strong and Venus and Mars have essentially no detectable magnetic fields.
Mars and Venus don't have much of a magnetic field, according to probes. The magnetic fields of Jupiter, Saturn, Uranus, and Neptune are all far stronger than those of the Earth. Jupiter is the winner since it has the biggest magnetic field. The magnetosphere grows in size as the magnetic field gets stronger. Jupiter's magnetic field, which is around 20,000 times stronger than Earth's magnetic field, generates a magnetosphere that extends over 3 million kilometers from Jupiter before it starts to deflect solar wind.
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matlab questions help
QUESTION 5 Which of the following methods is used to repeat the same sound clip, one after another? O Add the sound sample arrays O Multiply the sound sample arrays by a scalar value less than 1 O Con
To repeat the same sound clip one after another, the method used is to concatenate the sound sample arrays. By concatenating the sound sample arrays, you create a new array that contains multiple copies of the original sound clip, effectively repeating it one after another. Therefore the correct option is b. Multiply the sound sample arrays by a scalar value less than 1.
When you want to repeat the same sound clip, one after another, you can achieve this by concatenating the sound sample arrays. Here's a step-by-step explanation:
1. Load the sound clip into MATLAB and convert it into a sound sample array.
2. Determine the number of times you want to repeat the sound clip.
3. Use the concatenation operator `[ ]` to join the sound sample arrays together.
4. Repeat the sound sample array as many times as desired by appending it to itself using the concatenation operator. For example, if you want to repeat the sound clip three times, you would write `[soundClip, soundClip, soundClip]`.
5. Store the concatenated sound sample array in a new variable.
6. If needed, you can then play the repeated sound clip using the `sound()` function in MATLAB.
By concatenating the sound sample arrays, you create a new array that contains multiple copies of the original sound clip, effectively repeating it one after another.
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a ball is thrown striaght up in the air and then falls back to earth. if the downward fall takes 2.2s, how fast is the ball traveling when it striker the ground
The velocity of the ball when it strikes the ground, given the data is 21.56 m/s
Data obtained from the questionFrom the question given above, the following data were obtained:
Time to reach ground from maximum height (t) = 2.2 sInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) =? How to determine the velocity when the ball strikes the groundThe velocity of the ball when it strikes the ground can be obtained as illustrated below:
v = u + gt
v = 0 + (9.8 × 2.2)
v = 0 + 21.56
v = 21.56 m/s
Thus, the velocity of the ball when it strikes the ground is 21.56 m/s
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A person takes a ride to the top of a building in an elevator. If the elevator starts with
electrical energy, what types of energy does the electrical energy transform into during
this process? Put at least four answers.
Answer:
mechanical energy
Explanation:
What is the hypothesis for Lift an Ice Cube.
Answer:
When we sprinkle salt onto the ice cube, the state of equilibrium is disrupted. The salt molecules dissolve and join the water molecules thus changing the water's rate of freezing. The rate of melting is now much faster than freezing hence causing the ice to melt.
Explanation: Hope this helps
Which is an example of transforming potential energy to kinetic energy? Select two options
changing thermal energy to electrical energy
changing chemical energy to thermal energy
changing nuclear energy to radiant energy
changing radiant energy to electrical energy
changing mechanical energy to chemical energ
Answer :
.changing chemical energy to thermal energy
.changing nuclear energy to radiant energy
Explanation :
Hope it helps you mate ))Answer:
.changing chemical energy to thermal energy
.changing nuclear energy to radiant energy
Explanation:
The magnetic striping patterns on each side of a mid-oceanic ridge are each other. Each stripe in the pattern is a measure of.
As a result, the magnetic stripes on either side of the mid-ocean ridges develop in a symmetrical pattern with opposite polarity.
On each side of the oceanic ridge, are the magnetic stripe patterns equal?Along the Oceanic Ridge, the stripes are symmetrical. A mirror image is made by them. It implies that new seafloor is created in the center (at the Ridge), and some of the new seafloor is transported to each of the Ridge's sides, generating a symmetric pattern.
On which direction does the oceanic ridge's magnetic stripe pattern run?Pictures for Each side of a mid-oceanic ridge has a different magnetic striping pattern, although they are identical.
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Glucose is first broken down in the cytoplasm and then converted to cellular energy in the mitochondria during cellular respiration.
True
False
Answer:
True
Explanation:
Mitochondria is the power-house of almost every cell due to the fact that the cytoplasm stores energy, then sends it to the mitochondria. (at the needed times, of course.)
How to find the force.
If mass and acceleration are given use F =ma.
when distances were carefully measured from earth to globular clusters above and below the milky way plane (where the view of them is not obscured by interstellar dust and gas), the distribution of the clusters was found to be
The distribution of globular clusters above and below the Milky Way plane appears to be roughly spherical and symmetric, indicating their presence in a halo structure surrounding the galactic center.
When distances were measured from Earth to globular clusters located above and below the Milky Way plane, astronomers found that the distribution of these clusters appeared to be roughly spherical or symmetric. This observation provides valuable insights into the structure and formation of our galaxy.
Globular clusters are densely packed groups of stars that typically contain hundreds of thousands to millions of stars. They are gravitationally bound and orbit around the galactic center. The distribution of these clusters is crucial for understanding the overall shape and dynamics of the Milky Way.
The spherical distribution of globular clusters suggests that they form a halo surrounding the central disk of the galaxy. This halo extends in all directions and is more pronounced in the regions above and below the Milky Way plane where the view is less obstructed by interstellar dust and gas.
The symmetric distribution indicates that the clusters are uniformly distributed around the galactic center. This symmetry implies that the formation and evolution of globular clusters are influenced by the overall gravitational potential of the galaxy. The clusters are believed to have formed early in the history of the Milky Way, potentially during the initial stages of galaxy formation. Their distribution has remained relatively stable over billions of years, despite the complex gravitational interactions within the galaxy.
By studying the distribution of globular clusters, astronomers can gain insights into the formation and evolution of galaxies, including the Milky Way. The properties of these clusters, such as their ages and chemical compositions, provide valuable information about the conditions and processes that were present during the early stages of galaxy formation.
In summary, the spherical and symmetric distribution of globular clusters above and below the Milky Way plane indicates their presence in a halo structure surrounding the galactic center. This observation enhances our understanding of the overall structure and formation of the Milky Way galaxy and contributes to our broader knowledge of galactic dynamics and evolution.
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A solenoid of radius 2. 30 cm has 640 turns and a length of 25. 0 cm. (a) Find its inductance. MH (b) Find the rate at which current must change through it to produce an emf of 70. 0 mV. (Enter the magnitude. ) A/s
To find the inductance (L) of the solenoid, we can use the formula:L = (μ₀ * N² * A) / l, where μ₀ is the permeability of free space (4π × 10^(-7) T·m/A), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.
Given:
Radius of the solenoid, r = 2.30 cm = 0.023 m,
Number of turns, N = 640,
Length of the solenoid, l = 25.0 cm = 0.25 m.
The cross-sectional area of the solenoid, A, can be calculated as:
A = π * r²
= π * (0.023)²
≈ 0.001663 m².
Now we can calculate the inductance:
L = (μ₀ * N² * A) / l
= (4π × 10^(-7) * 640² * 0.001663) / 0.25
≈ 0.133 mH.
Therefore, the inductance of the solenoid is approximately 0.133 mH.
To find the rate at which the current must change through the solenoid to produce an emf (ε) of 70.0 mV, we can use Faraday's law of electromagnetic induction:ε = -L * (dI/dt), where ε is the induced emf, L is the inductance, and (dI/dt) is the rate of change of current.
Given:
Inductance, L = 0.133 mH = 0.133 × 10^(-3) H,
Induced emf, ε = 70.0 mV = 70.0 × 10^(-3) V.
Rearranging the equation, we can solve for (dI/dt):
(dI/dt) = -ε / L
= -(70.0 × 10^(-3)) / (0.133 × 10^(-3))
= -70.0 / 0.133
≈ -526.32 A/s.
Since the question asks for the magnitude of the rate of change of current, the answer is approximately 526.32 A/s.
Therefore, the magnitude of the rate at which the current must change through the solenoid to produce an emf of 70.0 mV is approximately 526.32 A/s.
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PLS HELP ME Which object has the greatest kinetic energy?
A: a truck with a mass of 3,500 kg moving at 30 m/s
B: a person with a mass of 73 kg running 6 m/s
C: a locomotive engine with a mass of 205,000 kg moving 5 m/s
D: a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
A locomotive engine with a mad of 205000kg moving with 5m/s
Explanation:
\(from \: the \: options \: substitute \: the \: formulars \: for \: kinetic \: energy \\ for \: opton \: a \: ke = \frac{1}{2} mv {}^{2} = \frac{1}{2} \times 3500 \times 30 {}^{2} = 1575000 \\ for \: option \: b \: ke = \frac{1}{2} mv {}^{2} = \frac{1}{2} \times 73 \times 6 {}^{2} = 1314 \\ for \: option \: \: c = \frac{1}{2}mv {}^{2} = \frac{1}{2} \times 205000 \times 5 {}^{2} = 2562500 \\ for \: option \: d \: = \frac{1}{2}mv {}^{2} = \frac{1}{2} \times 0.5 \times(46.9) {}^{2} = 549.9025 \\ from \: the \: analysis \: above \: the \: options \: that \: has \: the \: highest \: kinetic \: energy \: is \: a \: locomotive \: engine \: with \: a \: mass \: of \: 205000kg \: moving \: with \: a \: velocity \: of \: 5 \frac{m}{s} \)
Muscular Strength exercises focus on high______and low___
A) Intervals, Rest
B)Repetitions, Weight
C)Strength, Power
D) Weight, Repetitions
The Answer Is D, Weight, Repetitions
The muscular strength exercises focus on high weight and low repetitions. Hence, option D is correct.
What is Muscular strength?Two crucial components of your body's capacity to move, lift objects, and perform daily activities are muscular strength and endurance. The force you can exert or the weight you can lift is a measure of your muscular strength. How many times you can lift that weight before becoming exhausted is a measure of muscular endurance (very tired).
There are many benefits of Muscular strength, few of them are :
Increase the endurance with which you can carry out tasks like opening doors, lifting boxes, or chopping wood.Gain self-assurance and feel better about yourself.Permit you to diversify and add new exercises to your routine.Lessen the chance of damage.Hence, muscular strength exercises focus on high weight and low repetitions.
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input source of a curling iron?
Answer:
depends if it is wireless
Explanation:
if not a socket in a wall or surface. if not then it will probably use batteries.
Calculate the power required of a 1400kg car under the following circumstances a) The car climbs a 10° hill at a steady 80km/h and b) The car accelerates from 90 to 110km/h in 6.0s to pass another car on a level road. Assume the force of friction on the car is 700N in both parts of the problem.
(a) The power required for the car to climb the hill at a steady speed is 15.56 kW.
(b) The power required for the car to climb the hill at a changing speed is 19.44 kW.
What is the power required for the car to climb the hill?The power required for the car the move the incline is calculated as follows;
When the speed is steady, the average speed is calculated as;
v = ( 80km/h + 80 km/h) / 2 = 80 km/h = 22.22 m/s
P = Fv
where;
F is the applied forcev is average speedP = ( 700 N x 22.22 m/s )
P = 15,555.56 W = 15.56 kW
When the speed changes from 90 km/h to 110 km/h, the average speed is calculated as;
v = ( 90 km/h + 110 km/h ) / 2 = 100 km/h = 27.78 m/s
P = ( 700 N x 27,78 m/s )
P = 19,444.44 W = 19.44 kW
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