The charged particles that transferred between the glass rod and the metal sphere were electrons.
The rod has lost some of the charges it had earlier as the remaining count of charges is less than the previous one.Before analysing the type of the charge it is worthy to know about the conductive properties of both the materials.Glass is insulative while metal is conductive. Conductive materials in the sense have free electrons in abundance compared to insulative materials that conduct electricity within them. Glass, in comparison, does not conduct charges dynamically but rather keeps them stationary where those were originated. Electrons are more dynamic than protons.In this case, the metal sphere is neutral at the beginning that contained equal amounts of negative(electrons) and positive(protons) within it. Once the rod is taken close and eventually touched the sphere the more dynamic electrons flow into the rod nullifying the charges the rod had earlier.Therefore, it can be concluded that the type of charges the rod had were positive ones(protons) and the charges moved between them were electrons from the sphere to the rod.Otherway around is impossible.Finally, the sphere contains an amount of positive 7.0 nC charge while the rod contains the remainder of 7.0 nC on the parts which did not touch the sphere.
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an object is located inside the focal point of a concave mirror. will the image of the objectr be nearer or farther from the observer than the object tiself? explain
When an object is placed inside the focal point of a concave mirror, the image formed will be virtual, upright, and magnified.
This occurs because the light rays reflecting off the mirror diverge and never intersect on the real side of the mirror. Instead, they appear to converge on the virtual side, behind the mirror.
As a result, the image of the object will be farther from the observer than the object itself. The observer will see the image behind the mirror, which is not the actual position of the object, making it appear more distant than it truly is.
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Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
List two specific daily activities or movements that require you to have flexibility and identify the muscle groups and joints that need have a good range of motion (ROM) for you to perform these activities
Ankle mobility. Good ankle mobility contributes to better balance, fewer falls, and better performance during activities like squats and deadlifts.
Range of motion (ROM) exercises are done to preserve flexibility and mobility of the joints on which they are performed.
What is meant by Ankle mobility ?
The flexibility of the ankle joint and the muscles and tendons that surround it is referred to as ankle mobility.You can move more freely throughout activities when your ankle is flexible.Mobility work is crucial for carrying out daily tasks safely and lowering our risk of injury.Exercises for improving joint mobility are intended to strengthen a joint and get it ready for movements that may be performed outside of your "comfort" or "safe" range.Over the past few years, these kinds of ankle mobility drills have gained popularity and are frequently crucial elements of corrective exercise and movement preparation programs.To learn more about Ankle mobility refer to
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A garden hose of inner radius 1.00 cm carries water at 3.84 m/s. The nozzle at the end has inner radius 0.200 cm. How fast does the water move through the nozzle? m/s
We would apply the equation of continuity. Recall, it states that in case of flow of an incompressible fluid, the rate of flow at any time is constant at all points. The volume of fluid entering a section of flow in a period of time equals the volume of fluid that leaves at that same period of time. This means that
A1V1 = A2V2
where
A1 and A2 are the areas of the inlet and outlet
V1 and V2 are the velocities at inlet and outlet
AV is the volume flow rate in m^3/s
From the information given,
radius of inlet = 1 cm
Recall,
1 cm = 0.01 m
thus, radius of inlet = 0.01
Also,
Area of circle = pi x radius^2
Area of inlet = 3.14 x 0.01^2 = 0.000314
V1 = 3.84
A1V1 = 0.000314 x 3.84 = 0.00121
inner radius of outlet = 0.2 cm
Converting to meters, inner radius = 0.2 x 0.01 = 0.002
Area = 3.14 x 0.002^2 = 0.00001256
A2V2 = 0.00001256V2
Thus,
0.00121 = 0.00001256V2
V2 = 0.00121/0.00001256 = 96.33
The outlet velocity is 96.33 m/s
Compare the values for index of refraction of glass for each trial (values in last column) Is there good agreement between them? Would you conclude that index of refraction is constant for & given medium? Compare your calculated nz with the given index of refraction, nglass. Do they agree? Explain why it does or doesn't"
The calculated average n2 does not agree with the given index of refraction, indicating a potential discrepancy that may be attributed to experimental limitations or errors.
To analyze the agreement between the values for the index of refraction (n2) of glass in each trial, we can observe the trend and variation in the data. From the table, it appears that the values for n2 increase as the angles θ1 and θ2 increase. However, it is difficult to determine the level of agreement between the values without further statistical analysis or calculation of uncertainties.
The conclusion regarding whether the index of refraction is constant for a given medium depends on the level of agreement observed. If the values for n2 in each trial are close to each other and do not deviate significantly, it suggests good agreement and supports the hypothesis of a constant index of refraction.
On the other hand, if there is significant variation and inconsistency among the values, it indicates that the index of refraction may not be constant for the given medium.
To determine the average value of n2 from the provided results, we can calculate the mean of the n2 values:
Average n2 = (1.46 + 1.61 + 1.73 + 1.96 + 2.08 + 2.13) / 6 ≈ 1.85
Comparing the calculated average n2 (1.85) with the given index of refraction of the glass (1.50), we can see that they do not agree. The calculated average n2 is higher than the given value of 1.50. This suggests that there might be some systematic error or uncertainties in the measurements or calculations.
The difference between the calculated and given values could be due to factors such as experimental errors, instrumental limitations, or other sources of uncertainty in the measurement process.
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Complete question is:
Calculate sinθ1, sinθ2 and n2 for each of your results and add them to table 1. Keep your results to 2 or 3 significant figures.
Compare the values for index of refraction of glass for each trial (values in last column). Is there good agreement between them? Would you conclude that index of refraction is a constant for a given medium?
Determine the average value of n2 from your results.
Compare your calculated n2 with the given index of refraction of the glass (1.50). Do they agree? Explain why it does or doesn’t.
The type of remote sensing which penetrates clouds at night for accurate terrain representation is ___.a. sonarb. thermal infraredc. passive microwaved. Landsate. radar
The type of remote sensing which penetrates clouds at night for accurate terrain representation is radar.
Radar uses radio waves to detect objects and their properties, and can penetrate clouds and other obstacles that might obscure the view.
By bouncing radio waves off of the surface and measuring the time it takes for them to return, radar can create accurate representations of terrain and objects, including those hidden from view by clouds or darkness.
This makes radar an invaluable tool for a wide range of applications, including military, meteorological, and scientific uses.
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The charged particles in the beams at Thompson study came from atoms as these particles moved away from their original atoms they formed a visible beam the current model of the atom includes protons neutrons and electrons.
Answer:
The answer to the question is:
An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to remove.
Explanation:
-Atoms are mainly comprised of a nucleus consisting of protons (red) and neutrons (blue). The number of orbiting electrons is the same as the number of protons and is termed the "atomic number" of the element.J.J. Thomson discovered the electron. Atoms are neutral overall, therefore in Thomson’s ‘plum pudding model:
- atoms are spheres of positive charge
- electrons are dotted around inside
Thus the answer to your questions is, An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to remove.
9. A speedboat engine exerts 90000 W of power in moving the boat through the water. The velocity of the boat is 1P = 5 m/s. What force does the engine apply to do this?
P = F x V
Answer:
it g hope it helps you out
What is the force on an object that 1 point has a mass of 150 kg and an acceleration of 3. 7 m/s
Answer:
555N
Explanation:
Force = mass × acceleration
F=150×3.7
F=555
Can I have help with this please- thank you!!!
A child is pulling a toy train along the floor by pulling a piece of string state one contact force and one non contact force that acts on the toy
Answer:
I would say there is friction against the floor, air resistance, and gravity.
Explanation:
The contact force acting on the toy is the frictional force, and the non-contact force acting on the toy is the gravitational force.
Forces acting on the toy:According to the question, a toy train is being pulled by a string along the floor.
The gravitational force acting on the toy train is the weight of the toy train, which is a non-contact force given by:
F = mg
where m is the mass of the toy, and g is the acceleration due to gravity.
Now, the floor will exert a normal force against the toy, equal to the weight of the toy. Let the normal force be N.
Since the toy is in contact with the floor, there is a frictional force acting against the motion of the toy trains, which is a contact force and is given by:
f = μN = μmg
where μ is the coefficient of friction between the toy and the floor.
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how can I use theory and law in the same sentence in a scientific way and in every day use
Answer:
Explanation:
There are many laws in physics, that started out as theories and became scientific truths only after an experiment was performed that confirmed that the theory was true.
One of the most famous theories was the guess that the gravitational Force was a constant amount that depended on mass and distance. It was incredibly difficult to prove because the with large masses and small distances, the force is quite small.
Newton proposed the existence of the gravitational force in 1687 and Cavendish found its precise truth in 1798 -- 111 years after Newton said it was so.
Newton proposed a theory. Cavendish proved it to be a law later. Even then, Einstein proposed the modern law.
Which path would the laser take when entering the water from air?
brown or black
How do you find the average speed of three speeds?
Answer:
Assess what information you are given. Use this method if you know:
the total distance covered by one person or vehicle; and
the total time it took that person or vehicle to cover the distance.
Explanation:
Hope this helps! I might be wrong, so tell me if I am
Answer:
Average speed can be calculated by dividing the total distance the object travels by the total amount of time it takes to travel that distance.
Explanation:
This is as much as I can help you, i don't know much else on how to do that ;w; sorry
4 Applications of named material with high specific heat capacity
Water has the highest specific heat capacity.
The specific heat capacity is measured in J/(kg K) or J/(kg °C), and it is the amount of heat (J) absorbed per unit mass (kg) of the material when its temperature rises by 1 K (or 1 °C).
Applications of water with highest specific heat capacity are:
Fomentation: Hot water bottles are employed for this process because, despite producing a lot of heat, the water stays hot for a long period inside the bottle. Water is utilized as a coolant in automobile radiators. It can absorb a lot of heat energy from the car's engine thanks to its high specific heat capacity, but its temperature doesn't get too hot.Bottled Wines: Wine bottles are stored submerged in water in colder areas. The time it takes for the temperature to drop to 0 C is due to the large specific heat capacity of water.To know more about specific heat visit the link:
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Your neighbor is riding her bike around the block. When she slows down and turns a corner, what changes about her?.
Answer:
nothing
Explanation:If you ride a bike around the block and return to the exact point where you started, your displacement is zero.
By definition, displacement involves changing an object from its original position. No matter how far or for how long a body moves, if it returns to the position it started from, it has not been displaced at all. This means that the body has zero displacements.
A bike accelerates uniformly from rest to a speed of 3.55 m/s over 17.7m . what is the acceleration of the bike
Answer:4.9mph per meter
Explanation:
How fast, (vfx)q, will the quarterback be moving backward just after releasing the ball?
mlAn 80- quarterback jumps straight up in the air right before throwing a 0.43- football horizontally at 15 . How fast will he be moving backward just after releasing the ball?Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far will he move horizontally, assuming his speed is constant?
The quarterback will be moving backward at a speed of approximately 2.97 m/s just after releasing the ball.
To determine the speed at which the quarterback moves backward, we can use the principle of conservation of momentum. Before releasing the ball, the quarterback and the ball form a system with zero net external forces acting on them. This means that the momentum of the system is conserved.
When the quarterback jumps straight up in the air, his horizontal velocity component remains unchanged. Therefore, the momentum of the system before the throw is solely due to the horizontal velocity of the ball. We can calculate the initial momentum of the system using the formula:
Initial momentum = mass of the ball × horizontal velocity of the ball
Given that the mass of the ball is 0.43 kg and the horizontal velocity of the ball is 15 m/s, we can calculate the initial momentum as:
Initial momentum = 0.43 kg × 15 m/s = 6.45 kg·m/s
After the ball is released, the quarterback experiences an equal and opposite momentum to maintain the conservation of momentum. This momentum causes the quarterback to move backward. To find the speed at which the quarterback moves backward, we divide the momentum by the mass of the quarterback. Assuming an 80 kg quarterback, we can calculate the speed as:
Speed = momentum / mass of the quarterback = 6.45 kg·m/s / 80 kg = 0.0806 m/s ≈ 2.97 m/s
Therefore, the quarterback will be moving backward at a speed of approximately 2.97 m/s just after releasing the ball.
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a system takes 550 j of heat while it does 840 j of work on the surroundings. what is the change in internal energy of the system?
The change in internal energy of the system is -290 J (or -290 joules). The negative sign indicates that the internal energy of the system has decreased by 290 J.
The change in internal energy of a system can be calculated using the first law of thermodynamics, which states that the change in internal energy (∆U) is equal to the heat added to the system (Q) minus the work done by the system (W):
∆U = Q - W
Given that the system takes 550 J of heat (Q = 550 J) and does 840 J of work on the surroundings (W = 840 J), we can substitute these values into the equation:
∆U = 550 J - 840 J
∆U = -290 J
The negative sign indicates that the internal energy of the system has decreased by 290 J. the system has lost energy to the surroundings as both heat and work.
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under what condition is the angular momentum of an object conserved? under what condition is the angular momentum of an object conserved? if there is no net torque acting on it. if it is a point particle. if there is no net force acting on it. if there are no torques acting on it.
The angular momentum of an object conserved A. if there is no net torque acting on it.
Angular momentum is defined as the rotational analog of linear momentum, which is a measure of the amount of rotation an object has. The law of conservation of angular momentum states that the angular momentum of an object is conserved when there is no external torque acting on the object.
Mathematically, it can be expressed as, L = IωWhere L is the angular momentum of an object, I is its moment of inertia, and ω is its angular velocity. The angular momentum of an object is conserved when there is no net torque acting on it. This means that the total external torque acting on an object must be zero. If there is no external torque acting on an object, its angular momentum will be conserved, meaning that it will remain constant in magnitude and direction over time.
If an object experiences a torque, its angular momentum will change, and the rate of change of angular momentum will be equal to the magnitude of the torque acting on the object. Hence, if there is no net torque acting on an object, the angular momentum of that object will be conserved. An object that has no net force acting on it is not necessarily conserved, since it may still experience a torque that will cause its angular momentum to change.
However, if an object is a point particle, it can be treated as having zero moments of inertia, and its angular momentum will be conserved if there is no net torque acting on it. Therefore the correct option is A
The Question was Incomplete, Find the full content below :
under what condition is the angular momentum of an object conserved?
a. if there is no net torque acting on it.
b. if it is a point particle.
c. if there is no net force acting on it.
d. if there are no torques acting on it
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HELP IM REALLY STRUGGLING WITH THIS!!1
Different isotopes of an element can exist. For example, Carbon can have a mass number of 12 or a mass number of 14. Carbon always has an atomic number of 6.
Describe the difference between these two isotopes of Carbon.
In your answer, compare the number of protons, neutrons and electrons.
Answer:
Carbon 14 has 2 more neutrons than Carbon 12
same number of protons and electrons if they are both neutral atoms (that is the + or - aspect)
Explanation:
Answer:
The difference is the number of neutrons they have.
Explanation:
The atomic number is the number of protons. The number of protons is what differentiates elements. The isotope number is the total weight of the atom, that is the protons plus the neutrons. Therefore the number of neutrons is equal to the atomic mass minus the atomic number. Electrons are generally equal to the number of protons, to balance the charge of the atom.
In short: the difference between the two isotopes is that one has more neutrons.
A 50 kg crate is at rest on a horizontal floor. The coefficient of static friction between crate and floor is 0.75. The coefficient of kinetic friction is 0.60. What is the minimum horizontal force that is required (magnitude only) in order to start the crate moving across the floor?
A horizontal floor is the resting place for a 50 kg crate. The static friction coefficient between the floor and the crate is 0.75. Kinetic friction has a coefficient of 0.60. The minimum horizontal force required to start the crate moving is 367.5 N
To find the minimum horizontal force required to start the crate moving across the floor, we need to consider the static friction between the crate and the floor. The formula to calculate the maximum static friction is Fs = μs × N
where Fs is the maximum static friction, μs is the coefficient of static friction, and N is the normal force.
The normal force N is equal to the weight of the crate, which is given by:
N = m × g
where m is the mass of the crate and g is the acceleration due to gravity.
Substituting the values, we have:
N = 50 kg × 9.8 m/s² = 490 N
Now we can calculate the maximum static friction:
Fs = 0.75 × 490 N = 367.5 N
Therefore, the minimum horizontal force required to start the crate moving is 367.5 N (magnitude only).
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A 5 Kg bucket is being lifted by Sue straight up. A)If Sue is lifting the bucket up with constant velocity with what force is she lifting the bucket with? B) If Sue uses the same force and lifted the bucket on the moon which has a gravitational pull of 1.6 m/s2, with what acceleration will the bucket rise?
Answer:
A) Sue is lifting the bucket by a force of 49.035 newtons.
B) The bucket has an acceleration of 8.207 meters per square second on the Moon.
Explanation:
A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:
\(\Sigma F = F - m\cdot g = 0\) (1)
Where:
\(F\) - Lifting force, measured in newtons.
\(m\) - Mass of the bucket, measured in kilograms.
\(g\) - Gravitational acceleration, measured in meters per square second.
If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:
\(F = m\cdot g\)
\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)
\(F = 49.035\,N\)
Sue is lifting the bucket by a force of 49.035 newtons.
B) By the Second Newton's Law, we have the following model:
\(\Sigma F = F-m\cdot g = m\cdot a\) (2)
Where \(a\) is the net acceleration of the bucket, measured in meters per square second.
If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:
\(a = \frac{F}{m} -g\)
\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)
\(a = 8.207\,\frac{m}{s^{2}}\)
The bucket has an acceleration of 8.207 meters per square second on the Moon.
(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.
(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².
The given parameters;
mass of the bucket, m = 5 kgThe force applied by Sue in lifting the bucket at a constant velocity is calculated as;
\(F = m(a + g)\)
at constant velocity, a = 0\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)
The acceleration of the bucket when lifted on the moon with the calculated force is;
\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)
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Q3. A space probe is traveling in outer space with a momentum that has a magnitude
of . A retrorocket is fired to slow down the probe. It applies a force to
the probe that has a magnitude of and a direction opposite to the probe’s
motion. It fires for a period of 12 s. Determine the momentum of the probe after the
retrorocket ceases to fire
The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s
What is the momentum?We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.
According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.
We know that;
\(F_{t}\) = \(p_{f}\) -\(p_{i}\)
F = force
t = time taken
\(p_{f}\)= final velocity
\(p_{i}\) = initial velocity
\(p_{f}\) = \(F_{t}\) + -\(p_{i}\)
\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7
\(p_{f}\) = 2.4 * 10^7 + 7.5 * 10^7
\(p_{f}\) = 9.9 * 10^7 Kg m/s
Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.
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Missing parts;
A space probe is traveling in outer space with a momentum that has a magnitude of 7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0 * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.
Question 7 Points 2
The bicycle lamp glows when the bicycle's generator touches the wheel. This is because
Answer:
The dynamo has a wheel that touches the back tyre. As the bicycle moves, the wheel turns a magnet inside a coil. This induces enough electricity to run the bicycle's lights. The faster the bicycle moves, the greater the induced voltage - and the brighter the lights.
Because of the bicycle's actions, the wheel turns a magnet internal a coil. This induces enough strength to run the bicycle's lighting fixtures. The faster the bicycle movements, the greater the caused voltage - and the brighter the lights.
What type of modern is produced with the aid of a bicycle dynamo?A trendy dynamo creates an instantaneous modern-day (DC) – a one-directional waft of electrical rate. A bicycle dynamo creates an alternating current (AC), which reverses course from time to time.
A dynamo is a tool normally positioned inside the hub of a motorcycle's wheel that converts the energy generated by means of the wheel spinning to electric power. That energy is then used to run front and rear dynamo lights at the bike, offering constantly-on illumination without the want to change the lighting.
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Problem Set #2
work! Units requiring conversion should also be shown with
30 AM, Wednesday, September 28th,
1. A biker travels 500 meters in 25 seconds. What is the biker's
speed in m/s and km/h?
Answer: 20 m/s and 72km/h
Explanation:
500/25 = 20m/s (difference in place/difference in time)
20*3.6 = 72km/h (m/s*3.6=km/h and km/h/3.6=m/s)
Convert the normal temperature of human body from Celcius to Kelvin
and Fahrenheit scale.
Answer:
the normal human body temperature in Celcius is 37°C, in Fahrenheit is 98.6°F, in Kelvin is 310°K
a plano-convex lens has a front surface that is flat. its back surface has a radius curvature of -20cm. it is made of glass with n=1.5. what is the focal length (in cm) of this lens?
The focal length of the plano-convex lens is 40 cm.
To find the focal length of the plano-convex lens, we can use the lens maker's formula:
1/f = (n-1) * (1/R1 - 1/R2)
where f is the focal length of the lens, n is the refractive index of the glass, R1 is the radius of curvature of the front surface (which is infinite for a flat surface), and R2 is the radius of curvature of the back surface.
In this case, R1 is infinite, so we can simplify the formula to:
1/f = (n-1) * (-1/R2)
Plugging in the values, we get:
1/f = (1.5-1) * (-1/(-20cm))
= 0.5 * 0.05
= 0.025
Therefore, the focal length of the lens is:
f = 1/0.025
= 40 cm
So the focal length of the plano-convex lens is 40 cm.
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a block of known mass m is at rest at the base of a ramp. a second identical block of mass m travels at a known, constant velocity v0 , as shown in figure 1. the block that travels at a constant speed collides with and sticks to the first block. both blocks slide up the ramp and travel with an unknown velocity vr at the top of the ramp, as shown in figure 2. all frictional forces are considered to be negligible. which quantity should the student measure, if any, to determine whether the conservation of momentum applies to the two-block system from immediately before the collision to immediately after the blocks have reached the top of the ramp while stuck together? justify your selection. responses the force due to gravity exerted on both blocks as they travel up the ramp, because the force due to gravity does work on the system as it travels up the ramp.
The velocity of the two-block system at the top of the ramp is half the initial velocity of the second block. However, the force due to gravity exerted on both blocks as they travel up the ramp is not relevant to the conservation of momentum because it is a conservative force that does not affect the total momentum of the system.
Velocity of th two blocks systemThe total momentum of the system before the collision is equal to the momentum of the second block, which is given by:
p = mv0
where m is the mass of each block, and v0 is the initial velocity of the second block.
After the collision, the two blocks move together with an unknown velocity vr. The total momentum of the system after the collision is:
p' = (2m)vr
where 2m is the total mass of the two blocks, and vr is the final velocity of the system.
The conservation of momentum states that the total momentum of an isolated system remains constant, provided no external forces act on it. Therefore, the total momentum of the system before the collision is equal to the total momentum of the system after the collision:
p = p'
Substituting the expressions for p and p' gives:
mv0 = (2m)vr
Simplifying gives:
vr = v0/2
The velocity of the system can be measured to confirm that the conservation of momentum applies to the system.
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When would force lines connect two charges?
if the charges were both negative
if the charges were neutral
if the charges were opposite
if the charges were both positive
Answer: If the charges were opposite
Explanation:
Opposite charges attract, same charges repel (negative repels negative, positive repels negative), neutral charges have no charge
Force lines, also known as electric field lines, connect two charges when they are opposite in sign. Option C is correct.
What is charge?Charge is a fundamental property of matter that determines how it interacts with electromagnetic fields. Electric charge is a property of subatomic particles such as electrons and protons. It can be either positive or negative, and like charges repel each other while opposite charges attract each other.
Here,
Force lines, also known as electric field lines, connect two charges when they are opposite in sign. If the charges are both positive or both negative, the electric field lines will diverge away from each other, indicating a repulsive force between them. If the charges are opposite in sign, the electric field lines will converge toward each other, indicating an attractive force between them.
If the charges are neutral, there is no net electric field and thus no electric field lines connecting the charges. However, electric dipoles can still be formed between neutral charges, which can create a non-zero electric field in their surroundings.
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Approximately how long does it take the uterus lining to build up again after menstruation
The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.
The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.
The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.
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