Approximately 2.5 billion electrons were transferred when a glass rod with a charge of 12.0 nC touches a metal sphere and its charge decreases to 8.0 nC.
To determine the number of electrons transferred, we need to calculate the difference in charge before and after the rod touches the metal sphere.
The charge transferred can be calculated using the formula:
ΔQ = Qfinal - Qinitial
where:
ΔQ is the charge transferred,
Qfinal is the final charge of the rod (8.0 nC), and
Qinitial is the initial charge of the rod (12.0 nC).
Substituting the given values into the formula:
ΔQ = 8.0 nC - 12.0 nC
= -4.0 nC
The negative sign indicates that electrons were transferred from the rod to the metal sphere.
To calculate the number of electrons transferred, we can use the elementary charge (e) which is approximately equal to 1.6 × 10^(-19) C.
The number of electrons transferred (N) can be calculated as:
N = ΔQ / e
Substituting the values:
N = (-4.0 nC) / (1.6 × 10^(-19) C)
= -2.5 × 10^10 electrons
The negative sign indicates that electrons were transferred from the rod to the metal sphere.
Therefore, approximately 2.5 billion (2.5 × 10^9) electrons were transferred.
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Dos carritos se colocan en una mesa sobre la que pueden moverse sin rozamiento y se sujetan comprimiendo un resorte entre ellos. El carrito 1 tiene doble masa que el 2. De pronto se sueltan. A) Compara las velocidades, cantidades de movimiento y energías cinéticas que adquieren, b) ¿Cómo serían las respuestas si la masa del carrito 1 fuese mucho mayor que la del 2?
Answer:
a) v₁ = - ½ v₂, K₁ / K ₂ = ½,)
Explanation:
A) Let's use the conservation of the moment, for this we define the system formed by the spring and the two cars, so the force during the separation is internal, therefore the moment is conserved
initial instant. Before releasing the carts
p₀ = 0
final instant. After jumping the cars
p_f = M v₁ + m v₂₂
how the moment was preserved
p₀ = p_f
0 = M v₁ + m v₂
v₁ = - m / M v₂
indicate that M = 2m
v₁ = - ½ v₂
the kinetic energy of each car is
K₁ = ½ M v₁²
K₁ = ½ 2m (v₂/ 2) ²
K₁ = m ₂v₂² / 4
K₂ = ½ m v₂²
the relationship between the kinetic energies is
K₁ / K₂ = ½
B) If the much greater than the mass of car 1 is mass of car 2
v = - m / M v₂
In this case, the speed of car 1 is very small, so the car 1 practitioner does not backtrack and car 2 leaves with a lot of speed.
The energy is still conserved, where almost all the energy has it is car 2
a boy on a bike covers 300 meters in a minute and 420 metres in the following minutes minute. calculate his average speed during the: a: first minute b: second minute c: two minutes together
ya'll help me pls
the answer is two minutes together which is c
A student measures her height with a meter stick and finds that she is about 1.5 m tall. How can she measure her height with greater accuracy and precision?
Answer:
She should use a measuring tape
Explanation:
A student measures her height with a meter stick and gets a result of 1.5 m tall. This may not be as accurate as possible due to the fact that a meter stick has a maximum length of 1m which means an error could have occurred when she had to mark a point and then measure the remaining 0.5m.
She can however measure her height with greater accuracy and precision with a meter tape which has a wider measurement range and there won’t be any need to measure twice.
What are some some examples of estimator variables (forensics)
Answer:
Estimator variables are those that cannot be controlled by the criminal justice system. They include simple factors like the lighting when the crime took place or the distance from which the witness saw the perpetrator.
Explanation:
you are at the grand canyon standing at the edge of a ledge 1857 m high you have a mass of 61 kg. you decide to take a selfie to share with your science teacher when you get home which causes you to wonder how much gravitational potential energy do you have standing at the edge of this cliff
Answer:
1,110,114.6 J
Explanation:
The height is 1857m, the mass is 61 kg, and the accelaration is 9.8 m/s^2. Plug in the equation GPE=h*m*a and you get 1,110,114.6.
h= height
m= mass
a= accelaration
GPE= gravitational potential energy
If you are at the grand canyon standing at the edge of a ledge 1857 meters high you have a mass of 61 kilograms, then your gravitational potential energy at the edge of the cliff would be 1111247.37 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.
ME = KE + PE
The total gravitational potential energy at the edge of the cliff would be
PE = m × g × h
PE =61 × 9.81 × 1857
PE =1111247.37 Joules
Thus, the total gravitational potential energy at the edge of the cliff would be 1111247.37 Joules.
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A beam of monochromatic light is aimed at a slit of width and forms a diffraction pattern. In which case is the width of the central band greater
When the incident light is yellow the width of the central band greater. Single-wavelength light sources are known as monochromatic lights, where mono stands for one and chroma for color. Monochromatic lights are defined as visible light that falls inside a specific range of wavelengths. It has a wavelength that falls within a constrained wavelength range.
A laser beam is the ideal illustration of monochromatic light. A monochromatic light beam produced by a single atomic transition with a particular single wavelength is what makes up a laser. A color scheme that consists solely of different shades of one color is referred to as monochromatic.
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A scientist heats a red powder. Upon heating, a liquid and a gas form.
Which type of substance is the red powder?
O A. anion
B. an isotope
O c. an element
O D. a compound
Answer:
Compound
Explanation:
A train travels 190km in 3.0 hours and then 120 km in 2.0 hours. What is it’s average speed ?
Answer:
60 km/h
Explanation:
Simplify the speed:
120÷2=60
Hence, the average speed is 60 km/h.
mass of a body is 210g and its density is 7.981g/cm^3 what will be its volume with regard to significant figures
those who tell right answer i will make brainliest please fast
Density is mass per unit volume,
\(\rho=\dfrac mV\)
so to get the volume, divide the mass by the density,
\(V=\dfrac m\rho\)
So the volume is
\(\dfrac{210\,\mathrm g}{7.981\frac{\rm g}{\mathrm{cm}^3}}\approx26.312\,\mathrm{cm}^3\approx\boxed{26\,\mathrm{cm}^3}\)
can someone write and short summary on how to hula hoop
Answer:
First you take a hula hoop and hold it around your waist then you start moving your hips in a circle and let the hula hoop go off your hands and you keep moving your hips. You keep moving your hips until you want to stop but it might fall. Just keep trying and you should get the hang of it in a few minutes.
Explanation:
The Sackur-Tetrode equation for the entropy of an ideal gas is given by (Blundell and Blundell ch 21): S = NkB [2 3 [2 - In (pX³h)], where p = N/V is the (number) density of the gas, and Ath = h/√2πmkBT is the thermal wavelength. a) [5 marks] Show that S is an extensive quantity. b) [5 marks] Show that the entropy of a gas of distinguishable particles is instead given by 3 S = NKB Nkw [-In ()] hint: use the relationship S = where F is the Helmholtz free energy. c) [5 marks] Show that the quantity in b) is not extensive
a. The Sackur-Tetrode equation has the entropy to be S = NkB [2 + 3[2 - ln(pX³h)]
b. 3S = NkB ln(V / Nλ³ shows the entropy of a gas with distinguishable particles
c. The quantity 3S = NkB ln(V / Nλ³) is not an extensive quantity because it does not scale linearly with the size of the system.
How do we calculate?a)
Entropy in the Sackur-Tetrode equation is denoted by S = NkB [2 + 3[2 - ln(pX3h)],
N = particle count,
kB = Boltzmann constant,
p = gas's number density,
X = thermal wavelength,
h = Planck's factor.
When we consider two systems, each with a different number of particles and volume, the entropy of the combined system is equal to the sum of the entropies of the individual systems.
b) The entropy is given by 3S = NkB ln(V / Nλ³),
where V = volume,
N= total number of particles,
λ= thermal wavelength.
The Helmholtz free energy (F) is defined as
F_ = U - TS.
IF we differentiate the Helmholtz free energy with respect to temperature (T), we can obtain the entropy expression 3S = NkB ln(V / Nλ³).
c)
Because it does not increase linearly with system size, the amount 3S = NkB ln(V / N3) is not a large quantity. In a large quantity, doubling the system's size would also double the quantity's value.
In this our scenario, doubling the system size would not result in a doubling of the entropy. As a result, it is not regarded as a large number.
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in a house 6 bulbs each of 100 watt runs for 8 hours daily and 3 heaters of 1500 watt runs 5 hours daily, how much unit of electricity is consumed in 30 days
Answer:
Explanation:
all bulbs = 100*6=600 for 8 hrs
heaters= 1500*3=4500 for 5 hrs
so 600+4500=5100watts
Solution is in the attachment!! :)
An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
The wavelength of the radio waves is 3.04 cm.
Calculation:λf = c
λ = c/f
where,
λ = wavelength
c = speed of light
f = frequency
Given,
f = 98.6 MHz = 98.6 × 10⁶
c = 3 × 10⁸
To find,
λ =?
Put the values in the formula,
λ = c/f
λ = 3 × 10⁸/98.6 × 10⁶
= 0.0304 × 10² m
= 3.04 cm
Therefore, the wavelength of the radio waves is 3.04 cm.
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El Sol radia energía electromagnética a un tasa de P = 3. 85×1026 W. A) ¿A qué distancia del Sol la intensidad disminuye hasta 1000 W/m2
Sabiendo la tasa de energía electromagnética que el sol radi, la distancia a la cual la intensidad disminuye a 1000 W/m² es de 6.96×10¹⁰ m metros o 69.6 millones de kilómetros.
La intensidad de la energía electromagnética emitida por el Sol disminuye a medida que se aleja del Sol. Esta disminución está dada por la ley del cuadrado inverso, que establece que la intensidad es inversamente proporcional al cuadrado de la distancia desde la fuente.
La intensidad de la energía electromagnética se puede calcular mediante la siguiente fórmula:
I = P / 4πr²
Donde I es la intensidad, P es la potencia del Sol, y r es la distancia desde el Sol.
Si queremos encontrar la distancia a la cual la intensidad disminuye a 1000 W/m², podemos despejar r de la fórmula y sustituir los valores conocidos:
1000 = 3.85×10²⁶ / 4πr²
r² = 3.85×10²⁶ / (1000 × 4π)
r = √(3.85×10²⁶ / (1000 × 4π))
r = 6.96×10¹⁰ m
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20
All electromagnetic waves travel at the speed of light (300,000,000 m/s). However, even at this speed, if a radio
transmission is sent to astronauts on the Moon, there is a delay between the time that the message was sent
and the time that the astronauts receive it. Why?
0/1
Radio waves travel at a slower speed through a vacuum than they do through air.
The Moon is very far away from the Earth and it takes time for radio messages to travel.
Ο Ο Ο Ο
Asteroids and other space debris interfere with radio transmissions from Earth.
Radio waves are delayed as they pass through Earth's atmosphere.
Answer:
t = S / V = 3.8E8 / 3E8 = 1.3 sec
It takes over 1 second for a radio signal to travel between the earth and the moon.
a school bus uses petroleum as chemical potential energy. this energy is transferred through the engine, which in turn moves the bus. the movement of the bus is an example of what type of energy?
Kinetic
Radiational
Thermal
Potential
The movement of the school bus that is powered by petroleum as chemical potential energy is an example of Kinetic energy. This is because the chemical potential energy from the petroleum is transferred through the engine, converting it into kinetic energy which then moves the bus.
Kinetic energy refers to the energy of an object in motion. It is defined as the work required to bring a body of a given mass from a state of rest to a state of motion. It is measured as the amount of work needed to accelerate a body of a given mass to a given speed. Kinetic energy is proportional to the square of the object's speed, which means that as the object's speed increases, so does its kinetic energy. Therefore, the movement of the bus, which is an object in motion, is an example of kinetic energy.
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How much work must be done to stop a 925-kg car
traveling at 95 km/h?
The vertical line above represents the reflecting surface of a flat mirror while the dot on the left represents the local of a small bug. Using a straight edge and being concerned for the correct scale: Draw the location of the image of the bug in the mirror. Draw four light rays that come from the bug and that are reflected from the mirror. Show the relation between these light rays and the location of the image of the bug. Also show the relation between the angle of incidence and the angle of reflection in the reflected ray.
Drawing the location of the image of the bug in the mirror and the reflected rays from the bug allows us to visualize how flat mirrors reflect light and form images, and how the angles of incidence and reflection are related.
To draw the location of the image of the bug in the mirror, we first draw a perpendicular line to the reflecting surface of the flat mirror at the location of the bug. This perpendicular line represents the normal to the surface of the mirror.
Then we draw a line from the bug to the mirror, making sure that the angle of incidence is equal to the angle of reflection. This line represents the incident ray. We extend this line behind the mirror, and where it intersects the normal line, we draw a dashed line representing the reflected ray. We repeat this process for a few more rays coming from different points on the bug.
To be more specific, we draw four light rays coming from the bug, such that two of the rays are parallel to each other and pass through the top and bottom of the bug, while the other two rays are also parallel to each other and pass through the left and right sides of the bug.
The image of the bug will be located at the point where these reflected rays intersect. This point will be behind the mirror, as the image is virtual, meaning it appears to be behind the mirror but is not a physical object.
The angle of incidence and the angle of reflection will be equal for each of the reflected rays, and these angles will be measured with respect to the normal to the surface of the mirror at the point of incidence. Therefore, the angle of incidence and the angle of reflection will be equal and opposite for each of the reflected rays.
Overall, drawing the location of the image of the bug in the mirror and the reflected rays from the bug allows us to visualize how flat mirrors reflect light and form images, and how the angles of incidence and reflection are related.
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Work, Power, and Energy
A 3 kg ball falls from a height of 45 meters to a height of 32 meters. Calculate the amount of work done by gravity.
When writing your answer, please include the formula you used! Thank you!
Answer:
383.2
Explanation:
W=m×g(9.8)×(change in height)
=3×9.8× (45-32)
=3×9.8×13
=383.2
The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be
The exact same. gravity has no effect on mass.
Answer:
The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be LessExplanation:
A property of matter by which it remains at rest or in uniform motion in the same straight line unless acted upon by some external force.
Answer:
Inertia.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
For example, the inertia of an object such as a shopping cart is greatly dependent or influenced by its mass; the higher quantity of matter in a shopping cart, the greater will be its tendency to continuously remain at rest.
Suppose a manufacturing plant has an average sound intensity level of 97.0 dB created by 25 identical machines.
(a) Find the total intensity created by all the machines.
intensityall =
(b) Find the sound intensity created by one such machine.
intensityIndv =
(c) What's the sound decibel level if five such machines are running?
intensity =
(a) Total intensity is given by the equation:$$I_t = I_1 + I_2 + ... + I_n$$where $I_1$, $I_2$ and $I_n$ are intensities of individual machines in watts per square meter.
The intensity created by one machine, $I_{indv}$, is given by the formula:$$I_{indv} = 10^{(dB/10)}I_0$$where $I_0$ is the threshold of hearing $10^{-12}$ W/m² and $dB$ is the intensity of the machine in decibels, so to find $I_{indv}$ from the given $97.0$ dB, we have:$$I_{indv} = 10^{(97.0/10)}10^{-12} = 1.12 \times 10^{-3} W/m^2$$Now we can find the total intensity by all machines as follows:$$intensityall = I_{indv} \times 25$$$$intensityall = 1.12 \times 10^{-3} \times 25 = 2.8 \times 10^{-2} W/m^2$$Thus, the total intensity created by all machines is $2.8 \times 10^{-2} W/m^2$.
(b) Find the sound intensity created by one such machine.
Since we have already found $I_{indv}$ in part a, we just have to substitute it into the formula:$$intensityIndv = 1.12 \times 10^{-3} W/m^2$$Thus, the sound intensity created by one such machine is $1.12 \times 10^{-3} W/m^2$.
(c) To find the sound decibel level when five such machines are running, we use the formula:$$I_1 = I_2 + I_3 + ... + I_n$$where $I_1$ is the intensity of the 5 machines running together, and $I_2$, $I_3$, and $I_n$ are intensities of the individual machines. Since we know the intensity of one machine, we can find the total intensity of five machines by multiplying by 5:$$I_1 = 5 \times 1.12 \times 10^{-3} = 5.6 \times 10^{-3} W/m^2$$To find the sound decibel level of this intensity, we use the formula for decibels in terms of intensity:$$dB = 10\log_{10}\frac{I}{I_0}$$where $I$ is the intensity in watts per square meter and $I_0$ is the threshold of hearing $10^{-12}$ W/m². Substituting $I = 5.6 \times 10^{-3} W/m^2$ and $I_0 = 10^{-12} W/m^2$ gives:$$dB = 10\log_{10}\frac{5.6 \times 10^{-3}}{10^{-12}} \approx 101.8$$Thus, the sound decibel level when five such machines are running is approximately $101.8$ dB.
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A 1.5 kg frictionless pendulum is released from point A at an angle θ of 35 degrees. The speed of the pendulum at point C is 3.4 m/s. What is the length of the pendulum?
A) 3.3m
B) 0.72m
C) 0.59m
D) 8.7m
The length of the pendulum is 3.3 m.
The given parameters:
Mass, m = 1.5 kgAngle, θ = 35⁰Speed, v = 3.4 m/sWhat is principle of conservation of energy?The principle of conservation of energy states that, the total energy of a system is always conserved.P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
g(L - Lcosθ) = ¹/₂v²
gL(1 - cosθ) = ¹/₂v²
\(L = \frac{v^2}{2g(1- cos\theta)} \\\\L = \frac{(3.4)^2}{2\times 9.8(1 - cos35)} \\\\L = 3.28 \ m\\\\L = 3.3 \ m\)
Thus, the length of the pendulum is 3.3 m.
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which statement best describes balancing equations and the law of conservation of mass?
Balancing equations is the process of ensuring that the number of atoms of each element is the same on both sides of a chemical equation. This is done by adjusting the coefficients (numbers in front of the chemical formulas) to achieve balance. The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction.
When a chemical reaction occurs, the atoms of the reactants rearrange to form new compounds, known as the products. The law of conservation of mass states that the total mass of the reactants must be equal to the total mass of the products. This means that the number of atoms of each element must be the same on both sides of the equation.
To balance an equation, you need to adjust the coefficients in front of the chemical formulas. You can change the coefficients, but not the subscripts within the formulas, as this would change the identity of the compounds. By adding coefficients, you ensure that the number of atoms of each element is the same on both sides of the equation.
For example, let's consider the equation:
2H₂ + O₂ → 2H₂O
In this equation, we have 2 hydrogen (H) atoms on the left side, but only 2 hydrogen atoms on the right side. To balance the equation, we add a coefficient of 2 in front of the H₂O on the right side, resulting in:
2H₂ + O₂ → 4H₂O
Now we have 4 hydrogen atoms on both sides, fulfilling the law of conservation of mass.
In summary, balancing equations ensures that the number of atoms of each element is the same on both sides of the equation, in accordance with the law of conservation of mass. This is achieved by adjusting the coefficients in front of the chemical formulas.
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La velocidad de la luz es de 300 000 km/s, convertir a m/s.
ayudenme porfa
If you could repeat the lab and make it better, what would you do differently and why? There are always ways that labs can be improved. Now that you are a veteran of this lab and have experience with the procedure, offer some advice to the next scientist about what you suggest and why. Your answer should be at least two to three sentences in length.
Answer:
I suggest that you recheck your answers multiple times and make sure that they are making sense. Also I think that you should Study the organisms very well and you should be careful when making observations so that you really are sure that the organism has 4 wings and not only 2 wings(for example).
Explanation:
I hope this answers your question
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How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?
Answer:
Power = 20 Watts
Explanation:
Given the following data;
Voltage = 100 V
Resistance = 500 Ohms
To find the power that is required to light a lightbulb;
Mathematically, power can be calculated using the formula;
\( Power = \frac {Voltage^{2}}{resistance} \)
Substituting into the formula, we have;
\( Power = \frac {100^{2}}{500} \)
\( Power = \frac {10000}{500} \)
Power = 20 Watts
A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?
The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d
The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.
Therefore,
using Newtons third law
F - f = ma
a = v/t
t = d/v
F - f = m × v / t
F- f = m × \(\frac{v}{\frac{d}{v} }\)
F- f = m × v²/d
Therefore,
F- f = mv² / d
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Meeta used an elastic tape to measure the length of her window to stitch a curtain. Do you think she will be able to stitch a curtain of correct measurement? Yes/No . Give scientific reason in detail, also explain the correct method to measure the length of her window.
Answer:
No
Explanation:
She will not be able to measure the length of her window accurately due to instrumental error from her choice of instrument. The elastic nature of her tape would alter the measurement because it will stretch as she is taking her readings, thus reducing the true measurement of the length of her window.
To measure the length of her window, she could use an inelastic tape rule or a metre rule. These instruments would eliminate instrumental error.
what is the scientific method
Answer:
Step 7- Communicate. Present/share your results. Replicate.
Step 1- Question.
Step 2-Research.
Step 3-Hypothesis.
Step 4-Experiment.
Step 5-Observations.
Step 6-Results/Conclusion
Explanation: